Answer:
2.5m/s
Explanation:
a = \(\frac{(vf - vi)}{t}\)
vf = final velocity = 20m/s
vi = initial velocity = 0m/s (alex is starting "at rest")
a = acceleration =
t = time = 8s
a = \(\frac{(20-0)}{8 }\) = 2.5m/s
Question 68 Marks: 1 The Department of Energy regulations require solidification of high-level radioactive wastes within ______ of their production.Choose one answer. a. 1 year b. 5 years c. 10 years d. 20 years
The Department of Energy regulations require solidification of high-level radioactive wastes within 10 years of their production.
Therefore the answer is c) 10 years.
High-level radioactive wastes are generated from the production of nuclear power and the reprocessing of spent nuclear fuel. These wastes contain a significant amount of radioactive material and pose a potential hazard to human health and the environment if not managed properly.
The Department of Energy (DOE) is responsible for managing high-level radioactive wastes generated by its facilities and has established regulations to ensure their safe handling and disposal. One of these regulations requires that high-level radioactive wastes be solidified within 10 years of their production.
Solidification involves mixing the liquid wastes with materials such as cement or glass to form a solid, stable form that can be safely stored or disposed of. By solidifying the wastes, the risk of accidental spills or leaks is reduced, and the wastes can be more easily transported and stored.
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A bicyclist travels the first 700 m of a trip at an average speed of 8 m/s, travels
the next 600 m in 90 s and the last 50s at a speed of 21 m/s. Find the average speed
of the bicyclist for this trip
Answer:
500
Explanation: its 500 because you can also just search for it
How much energy does a 50kg rock have if it sitting on the edge of a 15m cliff
Answer:
14715 joules
Explanation:
What is the change in gravitational potential energy of the apple if it falls the amount shown? Estimate g to 9.81m/s2 and keep 3 significant figures.
Answer: 1.72J
Just figured this out a while ago
2. At 6:00 AM a hopital ued it cyclotron to make 1 milligram of the iotope fluorine-18 for ue a a diagnotic tool with it PET canner. The half-life of F-18 i 1. 8 hour. How much F-18 i left at 3:00 PM? At midnight? Should the hopital plan to make more F-18 the next morning?
Cyclotron to make 1 milligram of the isotope fluorine-18 for use a a diagnostic tool with it PET scanner. It seems that the hospital should plan to make more F-18 the next morning, as the amount remaining at midnight is very small.
The half-life of F-18 is 1.8 hours, so after 1.8 hours, half of the original amount of F-18 will remain. After 3.6 hours, a quarter of the original amount will remain, and so on.
At 3:00 PM (9 hours after the F-18 was made), the hospital will have
= 1/2^(9/1.8)
= 1/2^5
= 1/32
= approximately 0.03125 milligrams of F-18 remaining.
At midnight (18 hours after the F-18 was made), the hospital will have
= 1/2^(18/1.8)
= 1/2^10
= 1/1024
= approximately 0.0009765625 milligrams of F-18 remaining.
While using cyclotron, based on these calculations, it seems that the hospital should plan to make more F-18 the next morning, as the amount remaining at midnight is very small.
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Why does sound increase in pitch as a sound source approaches, as demonstrated by the Doppler effect?
1.Objects vibrate faster when they move forward.
2.Objects vibrate slower when they move forward.
3.The waves are closer together because the object is approaching.
4.The waves are farther apart because the object is approaching.
The fact that the item is approaching you explains why the waves are closer together.
What is meant by doppler effect?The Doppler Effect can be used to both sound and light sources. For instance, the sound waves' frequency rises when a sound object approaches you, raising their pitch. The frequency of the sound waves increases as it moves toward you, but the pitch falls as it moves away from you.
The difference in PITCH between a sound's source and listener due to motional interaction. The perceived pitch changes depending on how close or far the listener and sound source are to one another. As they draw closer, it is higher than the source's stationary pitch.
The fact that the item is approaching you explains why the waves are closer together.
Therefore, the correct answer is option 3.The waves are closer together because the object is approaching.
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The waves become closer together because the thing is coming towards you. Hence option 3 is correct.
What is meant by doppler effect?The Doppler Effect can be used to both sound and light sources. For instance, the sound waves' frequency rises when a sound object approaches you, raising their pitch. The frequency of the sound waves increases as it moves toward you, but the pitch falls as it moves away from you.
The difference in PITCH between a sound's source and listener due to motional interaction. The perceived pitch changes depending on how close or far the listener and sound source are to one another. As they draw closer, it is higher than the source's stationary pitch.
The fact that the item is approaching you explains why the waves are closer together.
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1. interpret data- based on the data, describe what alicia did.
2. draw conclusions- what conclusions can you draw? what does stirring do in terms of heat transfer?
help :(
Will give correct answer brainliest
Momentum is never created or destroyed. It's conserved. The total amount after a collision is the same as it was before the collision.
In this scenario, the total is 10 kg-m/s before the collision, so it's going to be 10 kg-m/s after.
Ball 2 has 4 kg-m/s, so Ball 1 has the other 6 kg-m/s of momentum.
The voltage in a battery is 9 volts. The resistance is 3 ohms.
What is the current?
6 amps
3 amps
12 amps
27 amps
Answer:
3 amps
Explanation:
easily
PLEASE HELP!!
A pendulum swings back and forth 24 times in 8 seconds. What is its period? What is its frequency? Make sure to include your work and units on your answers.
The time period is 0.3 s and frequency is 3 Hz
Step 1 :
Given:
No. of cycles N = 24
Total time take t = 8 s
Step 1 : Calculating the frequency:
The frequency of a wave or oscillation is defined as the number of cycles or completed alternations per unit time.
f = N/t
f = 24/8
f = 3 Hz
Step 2: Calculating the time period:
Frequency and time period are inversely proportional.
The amount of time it takes for something to complete one oscillation is called its time period.
Time period = 1/Frequency
Time period = 1/3 = 0.3 s
So, the time period is 0.3 s and frequency is 3 Hz.
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I’m think 3 or 1.. am I right?
Answer:
C-3 I beleive it is three!!!!
Explanation:
Hope this helps!
Have a grreat day!
-Hailey
Answer:
it is n2+3
Explanation:
(IT) A 1. 0 x 10^3 kg Toyota collides into the rear end of a 2. 2 x 10^3-kg Cadillac stopped at a red light. The bumpers lock, the brakes are locked, and the two cars skid forward 2. 8 m before stopping. The police officer, knowing that the coefticient of kinetic fric- tion between tires and road 1s 0. 40, calculates the speed of the Toyota at impact. What was that speed?
The speed of the Toyota at impact can be calculated using kinetic friction which is equal to 7.9 m/s
The speed of the Toyota at impact can be calculated using the coefficient of kinetic friction.
The equation for the speed is: speed = √(2fμd), where f is the force of the impact, μ is the coefficient of kinetic friction, and d is the distance that the cars skid.
In this case, the force of the impact can be calculated by multiplying the masses of the two cars together, which comes to
4.4 x 10³ kg. With μ = 0.4 and d = 2.8 m
The speed of the Toyota at impact can be calculated to be 7.9 m/s.
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a 100 kg crate,sliding on a floor, is brought to a stop by 25 N force what is the deceleration of the crate
Explanation:
a = ?
m = 100kg
Force = 25N
F = ma
a = F/m
a = 25/100
a = ¼
a = 0.25ms—²
deceleration = negative acceleration
deceleration = —0.25ms—²
Answer:
25neuton+100kg =125kg floor sliding
Got stuck on question 3 need help please
An Olympic sprinter runs towards you while holding a green glow stick. Assuming you had sensitive enough equipment, the light from the glow stick will appear: Blueshifted Greenshifted As a blackbody O Redshifted
The light from the green glow stick held by the Olympic sprinter will appear redshifted.
The phenomenon of redshift occurs when the source of light is moving away from the observer. In this case, as the sprinter is running towards you, the distance between you and the glow stick is decreasing over time. This decrease in distance causes a Doppler shift in the frequency of the light emitted by the glow stick.
Since the light is redshifted, its wavelength increases and the frequency decreases compared to its original emitted frequency. As a result, the light that reaches your eyes appears more towards the red end of the visible spectrum.
It is important to note that the color of the glow stick itself remains the same, but due to the relative motion between the source (the sprinter) and the observer (you), the light undergoes a change in frequency and appears redshifted.
This phenomenon is similar to the redshift observed in cosmology, where the light from distant galaxies appears to be redshifted due to the expansion of the universe.
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Who is farther from home at 4 minutes?
Answer:
lil's sister
hope this helps pls mark brainliest
how many molecules are in 3 moles of CO2
Answer:
1.806 x 10^24 molecules
Explanation:
1 mole of CO2 has 6.02 x 10^23 molecules
3 mole of CO2 has 3x6.02x10^23 molecuels = 1.806 x 10^24 molecules
The 3 mole of \(CO_{2}\) contains \(1.8066*10^{24}\) molecules.
One mole of \(CO_{2}\) contains \(6.022*10^{23}\) molecules.
In 3 moles of \(CO_{2}\) ,
\(=3*6.022*10^{23}=1.8066*10^{24}\) molecules.
Hence, the 3 mole of \(CO_{2}\) contains \(1.8066*10^{24}\) molecules.
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There is a 5mA flowing through an 18k register. What is the voltage drop?
The voltage drop across the 18 kΩ resistor is 90 volts. This means that when a current of 5 mA flows through an 18 kΩ resistor, there is a potential difference of 90 volts across the resistor.
To calculate the voltage drop across a resistor, Ohm's Law can be applied. Ohm's Law states that the voltage (V) across a resistor is equal to the product of the current (I) flowing through it and the resistance (R) of the resistor. The formula for Ohm's Law is V = I * R.
Given:
Current (I) = 5 mA = 5 * 10^(-3) A
Resistance (R) = 18 kΩ = 18 * 10^(3) Ω
Using Ohm's Law, we can calculate the voltage drop (V):
V = I * R
= (5 * 10^(-3) A) * (18 * 10^(3) Ω)
= 90 V
Therefore, the voltage drop across the 18 kΩ resistor is 90 volts. This means that when a current of 5 mA flows through an 18 kΩ resistor, there is a potential difference of 90 volts across the resistor.
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doppler radar is replacing conventional radar in weather forecasting because
Doppler radar enhances the capabilities of weather forecasting by providing real-time, quantitative data on the movement and behavior of precipitation.
Doppler radar is replacing conventional radar in weather forecasting because it provides additional information about the movement and velocity of precipitation particles. Unlike conventional radar, which can only detect the presence of precipitation, Doppler radar can measure the Doppler shift in the frequency of the radar waves caused by the motion of the precipitation particles.
This ability to measure the Doppler shift allows meteorologists to determine the speed and direction of the precipitation, providing valuable insights into the intensity, rotation, and potential for severe weather phenomena such as tornadoes and thunderstorms. Doppler radar can also detect the presence of wind shear and turbulence, which are crucial factors in aviation weather forecasting.
Additionally, Doppler radar provides more accurate and detailed information about the structure and characteristics of precipitation, such as the size and shape of raindrops or hailstones. This helps meteorologists analyze and predict the type of precipitation (rain, snow, sleet) and estimate its intensity.
Overall, Doppler radar enhances the capabilities of weather forecasting by providing real-time, quantitative data on the movement and behavior of precipitation. It allows meteorologists to make more precise predictions and issue timely warnings for severe weather events, improving public safety and preparedness.
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a if your speedometer has an uncertainty of 20 kmh at a speed of 90 kmh what is the percent uncertai
As per the given values, and uncertainty of the speedometer the actual speed could be 61.33 km/h.
Uncertainty = 2.0 km/h
Measured value = 90 km/h
Calculating the Percent uncertainty -
= (Uncertainty / Measured value) x 100
= (2.0 / 90 ) x 100
= 2.22%
Now, assuming the speedometer has the same percent uncertainty at 60 km/h, this percent uncertainty can be used to determine the range of speeds.
Percent uncertainty = 2.22%
Measured value = 60 km/h
Calculating the range -
= (Percent uncertainty / 100) x Measured value
= (2.22% / 100) x 60
= 1.33
Calculating the Total speed -
= 60 + 1.33
= 61.33
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Complete Question:
If your speedometer has an uncertainty of 2.0 km/h at a speed of 90 km/h ,what is the percent uncertainty? (b) If it has the same percent uncertainty when it reads 60 km/h , what is the range of speeds you could be going?
A 22Na source is labeled 2. 50 mCi, but its present activity is found to be 2. 31 ✕ 107 Bq.
(a) What is the present activity in mCi?
(b) How long ago did it actually have a 2. 50-mCi activity?
For a 22Na source which is labeled 2. 50 mCi, but its present activity is found to be 2. 31 ✕ 107 Bq (a) the present activity in mCi is 0. 623 mCi and (b) the time it actually had a 2. 50-mCi activity is 19 years ago.
(a) Given, 1 mCi = 3. 7 ✕ 10^10 Bq
Therefore, 2. 50 mCi = 2. 50 × 3. 7 ✕ 10^10 = 9. 25 ✕ 10^10 Bq
So, Present activity in mCi = 2. 31 ✕ 10^7 / 3. 7 ✕ 10^10 = 0. 623 mCi
(b) Let's assume, after time t, the activity of the source is 2. 50 mCi. Then, at present, the activity of the source = 2. 31 ✕ 10^7 Bq
Let, λ be the decay constant and A₀ be the initial activity of the source at time t = 0.
The activity of a radioactive substance at any time t can be represented by the formula,
A = A₀ e^(-λt)
Given, A₀ = 2. 50 mCi = 2. 50 × 3. 7 ✕ 10^10 = 9. 25 ✕ 10^10 Bq
A = 2. 31 ✕ 10^7 Bqe^(-λt)
∴ λ = ln(A₀/A) / t = ln(9. 25 ✕ 10^10 / (2. 31 ✕ 10^7)) / t ≈ 2. 27 ✕ 10^-9 s^-1
Therefore, the time taken for the activity to reduce from 2. 50 mCi to 0. 623 mCi is given by
2. 50 e^(-2. 27 ✕ 10^-9 t) = 0. 623
e^(-2. 27 ✕ 10^-9 t) = 0. 623 / 2. 50 = 0. 2492
Taking natural logarithm on both sides, we get
-2. 27 ✕ 10^-9 t = ln(0. 2492)
t = - ln(0. 2492) / 2. 27 ✕ 10^-9≈ 0. 60 × 10^9 s ≈ 19 years
Therefore, the source actually had a 2.50-mCi activity about 19 years ago.
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Impulses are sudden and powerful urges. Where does their energy come from?
A. It comes from high-speed neurons in the brain.
B. It comes from being encouraged by peers.
C. It comes from bypassing the prefrontal cortex.
D. It comes from conscious repetition.
Answer:
From psychology
It comes from bypassing the prefrontal cortex
So yes, The answer will be C.
A student pushes a 50-N box across the floor a distance of 15 m. How much work was done to move the box?
1) 750 j
2) 75 J
3) no work was done
4) 7500 J
Answer:750
Explanation:
50 times 15
Answer:
750 j
Explanation:
I took the test in k12
Question 4 (2 points)
Your friend just challenged you to a race. You know in order to beat him, you must run 50 meters within 60 seconds in an eastern direction.
What does your average velocity need to be to win the race? (2 points)
5 meters per second, east
Оа
Ob
.83 meters per second, east
Ос
1.2 meters per second, east
Od
3000 meters per second, east
Answer:
0.83m/s,east
Explanation:
velocity=d/t
v=50/60
v=0.83m/s,east
A boulder rolls off a 100 meter cliff with a horizontal velocity of 2 m/s.
Make a sketch of the cliff and the boulder. Be sure to label the height of the cliff, the horizontal velocty of the
boulder, and the trajectory of the boulder
Explanation:
It is given that,
Height of the cliff is 100 m
Its horizontal velocity is 2 m/s
The attached figure shows the sketch of the cliff and the boulder. It will go in the form of parabola. Its trajectory is parabolic in nature. The horizontal distance is called the range of the parabola.
A star has right ascension of 3 hours. which of these statements is correct about the star?
it is 3 hours north of the celestial equator.
it is 3 hours south of the celestial equator.
it is 3 hours to the east of zero hours right ascension.
it is 3 hours to the west of zero hours right ascension.
Option C, it is 3 hours to the east of zero hours right ascension.
The angle of a specific location measured eastward along the celestial equator from the Sun at the March equinox to the (hour circle of the) point in question above the earth is known as right ascension (abbreviated RA; symbol ). These astronomical coordinates identify a point's location in the equatorial coordinate system on the celestial sphere when combined with declination.
Ascension, or the point on the celestial equator that rises with any celestial object as seen from Earth's equator, is referred to by the archaic phrase "right ascension" (Latin: ascensio rectal. This is where the celestial equator contacts the horizon at a right angle. It stands in contrast to oblique ascension, which is the point on the celestial equator that rises with every celestial object as seen from the majority of latitudes on Earth..
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A woman with mass 50 kg is standing on the rim of a large horizontal disk that is rotating at 0.80 rev/s about an axis through its center. The disk has mass 110 kg and radius 3.8 m.
The disk has mass 110 kg and radius 3.8 m is he value of the full angular momentum of the woman-disk machine is 9,759.7 kgm²/s.
The given parameters;
Mass of the woman, M = 50kg angular pace of the disk, w = 0.8rev/s
Mass of the disk, radius, r = 4.3m m = 110kg
The value of the full angular momentum of the woman-disk machine is calculated as follows;
I t =I disk omega+I woman
I t =(I disk +I woman )
\(I t =( 1/2 x m x r ^ 2 + M x r ^ 2I \\t = (1/2 x 110 x 4.3 ^ 2 + 50 x 4.3 ^ 2) *\)
\(I t = (1941.45kg x m ^ 2) x 5.0%I t =9, 759.7kg x m ^ 2\)/
Thus, the value of the full angular momentum of the woman- disk machine is 9,759.7 kgm²/s
\(t = 9.759 * 0.7ka m ^ 2.\)
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A truck was traveling at 24 m/s in came to a stop in 8 seconds. What was the truck's average acceleration over
that time period?
-3 m/s²
2 m/s²
3 m/s²
16 m/s²
Answer:
-3 m/sExplanation:
how I don't know I just guessed but now yall knowIn this experiment, you need to examine the idea of
thermal energy transfer. Using a controlled experiment,
what might a good question about the variables that
affect thermal energy transfer be? Thermal energy
transfer depends on many properties, but limit your
question to only two.
I
By examining the influence of surface area and material composition on thermal energy transfer in a controlled experiment, we can gain valuable insights into the fundamental factors that affect heat exchange. This knowledge can have practical applications in fields such as engineering, materials science, and energy efficiency.
A good question about the variables that affect thermal energy transfer in a controlled experiment could be: How does the surface area and material composition of an object influence the rate of thermal energy transfer?
By focusing on the surface area and material composition, we can investigate how these two variables affect the transfer of thermal energy. The surface area of an object determines the amount of area available for heat exchange, potentially affecting the rate of energy transfer. The material composition, on the other hand, can impact factors such as thermal conductivity, specific heat capacity, and emissivity, all of which play a role in how effectively heat is transferred.
To conduct the experiment, you can select objects of different materials and surface areas, such as metal plates or plastic blocks with varying dimensions. By exposing them to a controlled heat source and measuring the temperature change over time, you can analyze how the chosen variables affect thermal energy transfer.
This investigation would provide insights into the fundamental factors that influence heat exchange and can be used to inform practical applications in various fields such as engineering, materials science, and energy efficiency.
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A hollow circular pole 6 meters thick, with 300 mm outside diameter and the height of 3 m weighs 150 N/m. The pole is subjected to the following vertical load P-3N eccentricity of 100 mm from the centroid of the section, lateral force H -0. 45 KN at the top of the pole.
Determine the maximum tensile stress at the base due to vertical and lateral loads
O 3. 58 MP
O 3. 99 MPa
04. 73 MPa
O 431 MP3
Answer:d
Explanation:d