According to Newton’s second law of motion,how much force will be required to accelerate an object at the same rate if it mass is reduced by half ?

We can see here that the diagram that reveals the absorption of photons and production of electrons (photoelectric effect) used in solar PV systems is seen below.

A photon is a fundamental particle or quantum of light.

It is the smallest indivisible unit of electromagnetic radiation, which also includes radio waves, microwaves, X-rays, visible light, ultraviolet light, and infrared radiation. In scientific calculations, photons are represented by the symbol "c" and move at the speed of light in a vacuum while carrying energy.

Wave-particle duality is the idea that photons are both particles and have wave-like characteristics. This means that they can exhibit wave-like properties like interference and diffraction as well as discrete particle behavior, each with a distinct energy and momentum.

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Answer:

\(initial \: veloity = 2\frac{m}{ {s} } \\ accelaration = - 1 \frac{m}{ {s}^{2} } \\ v = u + at \\ 0 = 2 + - 1 \times t \\ 0 = 2 - t \\ 2 = t \\ thank \: you\)

Answer: 1.348 meters

Explanation: Although the sign is missing from the location of the 4.00 kg object, it is assumed to be positive. The net moment of all the objects about the center of mass must be zero. Let the center of mass be on the y axis at a point  c . Adding the four moments together, we get:

(2.00)(3.00−c)+(3.00)(2.50−c)+(2.50)(0−c)+(4.00)(0.500−c)=0

6.00−2.00c+7.50−3.00c+0−2.50c+2.00−4.00c=0

11.5c=15.50

c=  1.348 metres

The center of mass is on the y axis at  y  = 1.348 metres.

Answer: B

Explanation: because x is 19.4 and then the y is m/s north

Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe.

Galileo Galilei played a crucial role in challenging the prevailing geocentric model of the universe proposed by Aristotle and supported by Ptolemy. He provided several lines of evidence that effectively disproved their theories and supported the heliocentric model proposed by Nicolaus Copernicus. Some of the key evidence used by Galileo includes:

1. Observations through a telescope: Galileo was one of the first astronomers to use a telescope to observe the heavens. His telescopic observations revealed several important discoveries that contradicted the Aristotelian-Ptolemaic worldview. He observed the phases of Venus, which demonstrated that Venus orbits the Sun and not Earth. He also observed the four largest moons of Jupiter, now known as the Galilean moons, which provided evidence for celestial bodies orbiting a planet other than Earth.

2. Sunspots: Galileo's observations of sunspots provided evidence that the Sun is not a perfect celestial body, as suggested by Aristotle. Sunspots indicated that the Sun has imperfections and undergoes changes, challenging the notion of celestial perfection.

3. Mountains on the Moon: Galileo observed the rugged and uneven surface of the Moon, which contradicted Aristotle's belief in celestial spheres made of perfect, unchanging material. The presence of mountains on the Moon suggested that celestial bodies are subject to the same physical laws as Earth.

4. Phases of Venus: Galileo's observations of the phases of Venus provided direct evidence for the heliocentric model. As Venus orbits the Sun, it goes through phases similar to the Moon, ranging from crescent to full. This observation strongly supported the idea that Venus revolves around the Sun.

These lines of evidence presented by Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe. His work marked a significant turning point in the history of science and laid the foundation for modern astronomy.

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The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

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Answer:

Lunar and solar eclipses occur with about equal frequency. Lunar eclipses are more widely visible because Earth casts a much larger shadow on the Moon during a lunar eclipse than the Moon casts on Earth during a solar eclipse. As a result, you are more likely to see a lunar eclipse than a solar eclipse.

For a total eclipse to take place, the sun, moon and Earth must be in a direct line. The second type of solar eclipse is a partial solar eclipse. This happens when the sun, moon and Earth are not exactly lined up. The sun appears to have a dark shadow on only a small part of its surface.

For a lunar eclipse to occur, the Sun, Earth, and Moon must be roughly aligned in a line

The average density of a planet is given by:

where m is the mass of the planet and V is its volume. We know the mass of the planet but we don't know its volume, to find it we will need find its radius.

To find the radius of the planet we can use Newton's Law of gravitation:

where G is the gravitational constant, m is the mass of the object, M is the mass of the planet and d is the distance between the planet and the object. Let r be the radius of the planet, and x be the distance from the surface of the planet to the object (x=13660 in this case); then we have:

Plugging the values given we have:

Since the radius of the planet has to be positive we choose the positive solution.

Now, that we know the radius of the planet we can calculate its volume; assuming the planet is spherical we have that:

then we have:

Finally we can calculate the density:

Therefore, the average density is 11398 kg/m^3

A miniature quadcopter is located at xi = −1.75 m and yi = 2.70 m at t = 0, so the x-coordinate of the quadcopter's position at t = 2.10 s is -0.185 m, and the y-coordinate is -3.175 m.

The equation that is used here is the kinematic equations to find the position of the quadcopter at time t,

x = xi + vav, x × t

y = yi + vav, y × t

Substituting the given values, one can get:

x = -1.75 m + 1.70 m/s × 2.10 s = -0.185 m

y = 2.70 m - 2.50 m/s × 2.10 s = -3.175 m

Hence, the x-coordinate of the quadcopter's position at t = 2.10 s is -0.185 m, and the y-coordinate is -3.175 m.

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Answer:

Getting a good rest

Explanation:

Answer:

Explanation:

b) light

Answer:

15 m/s

Explanation:

m₁ = 9 kg, before collision: v₁ = 5 m/s, after collision: v₁' = 0

m₂ = 3 kg,  before collision: v₂ = 0, after collision: v₂' = ? (x)

Momentum conservation:

9 * 5 + 3 * 0 = 9 * 0 + 3 * x

45 = 3x

x = 45/3 = 15 m/s

If the dog walked at a constant speed the whole way, the graph of the dog's position versus time would be a straight line. This is because the dog's velocity (which is the derivative of position with respect to time) would be constant, and the acceleration (which is the derivative of velocity with respect to time) would be zero.

A straight line on a position-time graph indicates that the object is moving at a constant velocity. The slope of the line would be equal to the velocity of the dog.

If the graph is a horizontal line, it would indicate that the dog is at rest. If the line slopes upward, the dog is moving in the positive direction (for example, to the right in a position-time graph), and if the line slopes downward, the dog is moving in the negative direction.

In all, A constant speed means a constant velocity and the line is a straight line with a particular slope.

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Answer:

the ans is D.... good luck

Answer:

Explanation:

The Workdone is the product of force and distance, Hence, the Workdone on the box from distance x = 0 meters and x = 16 meters is 0 Joules.

Using the graph given :

The work done from x = 0 to x = 16 metres ;

The distance can be split evenly into :

(x = 0 to x = 8) and (x = 8 to x = 16)

Workdone = Force × distance

Workdone from ; x = 0 to x = 8 ;

Force at a distance of 8 meters = - 40N

Workdone = - 40N × 8 m = -320 Nm

Workdone from ; x = 8 to x = 16 ;

Force at a distance of 16 meters = 40 N

Workdone = 40 N × 8 m = 320 Nm

The total workdone :

(-320 + 320) Nm = 0 J

.

Therefore, the Workdone ls 0 Joules.

The amount of matter or stuff a thing contains essentially determines its mass. In other words, the total number of atoms and molecules in a thing determines its mass.

Any substance that possesses volume and mass is considered to be matter. Every one of the many-particle kinds has a distinct mass and size.

Atoms are the minuscule constituent parts of matter. Matter exists in three different states. Gas, liquid, and solid.

The electron, proton, and neutron are the three types of material particles that are most well-known.

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Answer:

Explanation:

Using the formula for calculating range expressed as;

R = U√2H/g

U is the speed = 300m/s

H is the maximum height = 78.4m

g is the acceleration due to gravity = 9.8m/s²

Substitute into the fromula;

R = 300√2(78.4)/9.8

R = 300 √(16)

R = 300*4

R = 1200m

Hence the projectile travelled 1200m before hitting the ground

When developing an experimental design, the action that would improve the quality of the results is to ensure that it answers a question about cause and effect.

Experimental design is a concept used to organize, conduct, and interpret results of experiments in an efficient way, making sure that as much useful information as possible is obtained by performing a small number of trials.

Thus, when developing an experimental design, the action that would improve the quality of the results is to ensure that it answers a question about cause and effect.

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Answer:

Sound is produced when an object vibrates, creating a pressure wave. This pressure wave causes particles in the surrounding medium (air, water, or solid) to have vibrational motion. As the particles vibrate, they move nearby particles, transmitting the sound further through the medium.

D. produced a photograph that showed the creation of two particles when a particle of light was destroyed.

In 1933, Irène and Frédéric Joliot-Curie produced a photograph that showed the creation of two particles when a particle of light was destroyed, which was Einstein's prediction in the concept of pair production, which was a process in which two particles are created when a photon is absorbed. This photograph was the first experimental evidence of this process, which was a significant discovery in the field of nuclear physics.

Answer:

4.692m

Explanation:

The distance that this boy climbed = 12.0m

The velocity = 3.0m/s

We are to find how far forward this apple goes before it hits the ground.

We have y = 1/2gt²

X = v*t

T = 1.564 seconds

X = 3x1.564

X = 4.692m

Therefore the ball goes a distance of 4.692m forward before it then hits the ground.

The audience for the 9th grade physics MCAS is students in the 9th grade who are taking the Massachusetts Comprehensive Assessment System (MCAS) physics exam.

The exam is designed to assess students' knowledge and skills in physics, and it is used to make decisions about students' placement in courses, graduation requirements, and eligibility for college and career programs.

The 9th grade physics MCAS is a multiple-choice exam that consists of 50 questions. The questions are based on the Massachusetts Curriculum Framework for Science, which outlines the standards that students are expected to meet in physics.

Students who take the 9th grade physics MCAS must score at least proficient in order to meet the state's graduation requirements. Students who score below proficient may be required to take additional courses or remediation.

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Answer:

b

Explanation:

Answer:

There is no image

Explanation:

Answer: Send me image than I will be able to help

Explanation:

Answer:

Think in your Mind

Explanation:

if you do you will have a better understanding of what you're doing

you could study you could ask a parent or guardian

or maybe stop looking up answer and expect other people breaking thier heads doing this

Answer:

Q = 50.25 [J]

Explanation:

To solve this problem we must use the following equation that relates the temperature change with the mass and with the specific heat.

Q = m*Cp*(DT)

where:

Q = energy in form of heat [J]

m = mass = 5 [g] = 0.005 [kg]

Cp = specific heat = 1005 [J/kg*°C]

DT = temperature change = 10 [°C]

Now replacing:

Q = 0.005*1005*10

Q = 50.25 [J]

Answer:

B = 0.013(-j) T

Explanation:

Given that,

The speed of a proton, \(v=1.75\times 10^7\ m/s\)

Acceleration experienced by the proton,\(a=2.25\times 10^3\ m/s\)

We need to find the magnitude and the direction of the magnetic field. At equilibrium,

\(ma=qvB\\\\B=\dfrac{ma}{qv}\\\\B=\dfrac{1.67\times 10^{-27}\times 2.25\times 10^{13}}{1.6\times 10^{-19}\times 1.75\times 10^{7}}\\\\B=0.013\ T\)

The velocity is in +z direction, force in +x direction, then the field must be in -y direction.

Answer:

the Potential Energy is 2.304 × 10⁻¹⁶ J

Explanation:  

Given the data in the data in the question;

The expression for the electric potential energy between the charges can be expressed as follows;

PE = qV ------equ 1

where q is the charge and V is the electric potential

Also the formula for electric potential due to point a point in a field is;

V = kq /  r -------equ 2

where k is the electrostatic constant and r is the distance form the charged particle

input equation 2 into 1

PE = q × kq /  r

PE = kq²/r ------- equ 3

so we substitute into equation 3; 1.00×10⁻¹² for r, 9.00×10⁹ for k( constant ) and 1.60×10⁻¹⁹ for q( charge )

PE = ((9.00×10⁹) (1.60×10⁻¹⁹)²) / 1.00×10⁻¹²

PE = 2.304 × 10⁻²⁸ / 1.00×10⁻¹²

PE = 2.304 × 10⁻¹⁶ J

Therefore, the Potential Energy is 2.304 × 10⁻¹⁶ J