According to a report for veterinarians in the united states, 36. 5 percent of households in the united states own dogs and 30. 4 percent of households in the united states own cats. If one household in the united states is selected at random, what is the probability that the selected household will own a dog or a cat?.

The triangle and its image are added as attachment

From the question, we have the following parameters that can be used in our computation:

A(1, 2) , B(3, 1) and C(1,- 1)

Also, we have

The translation ( x - 2 . y + 3 )

To perform a translation on a figure, we need to add -2 to the x-coordinate and 3 to the y-coordinate of each point.

i.e.

(x, y) = ( x - 2 . y + 3 )

So, we have

A(1 - 2, 2 + 3) , B(3 - 2, 1 + 3) and C(1 - 2,- 1 + 3)

This gives

A'(-1, 5), B'(1, 4), and  C'(-1, 2).

See attachment for the figure

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Answer:

A.  9.4 mi

Step-by-step explanation:

Sketch a right triangle with legs of 8 and 5.  Shortest distance back to the starting point is the hypotenuse (h) of the triangle:

h² = 8² + 5² = 89

h = √89 = 9.43 mi

Answer:

n = infinite amount of solutions

General Formulas and Concepts:

Pre-Alg

Step-by-step explanation:

Step 1: Define equation

14n + 34 = 2(17 + 7n)

Step 2: Solve for n

Here we see that n can be any number. Therefore, n has an infinite amount of solutions.

Let \(\(a\)\) and \(\(b\)\) be integers such that \(\(ab = 4\)\). We want to prove that \(\((a - b)^3 - 9(a - b) = 0\).\)

Starting with the left side of the equation, we have:

\(\((a - b)^3 - 9(a - b)\)\)

Using the identity \(\((x - y)^3 = x^3 - 3x^2y + 3xy^2 - y^3\)\), we can expand the cube of the binomial \((a - b)\):

\(\(a^3 - 3a^2b + 3ab^2 - b^3 - 9(a - b)\)\)

Rearranging the terms, we have:

\(\(a^3 - b^3 - 3a^2b + 3ab^2 - 9a + 9b\)\)

Since \(\(ab = 4\)\), we can substitute \(\(4\)\) for \(\(ab\)\) in the equation:

\(\(a^3 - b^3 - 3a^2(4) + 3a(4^2) - 9a + 9b\)\)

Simplifying further, we get:

\(\(a^3 - b^3 - 12a^2 + 48a - 9a + 9b\)\)

Now, notice that \(\(a^3 - b^3\)\) can be factored as \(\((a - b)(a^2 + ab + b^2)\):\)

\(\((a - b)(a^2 + ab + b^2) - 12a^2 + 48a - 9a + 9b\)\)

Since \(\(ab = 4\)\), we can substitute \(\(4\)\) for \(\(ab\)\) in the equation:

\(\((a - b)(a^2 + 4 + b^2) - 12a^2 + 48a - 9a + 9b\)\)

Simplifying further, we get:

\(\((a - b)(a^2 + 4 + b^2) - 12a^2 + 39a + 9b\)\)

Now, we can observe that \(\(a^2 + 4 + b^2\)\) is always greater than or equal to \(\(0\)\) since it involves the sum of squares, which is non-negative.

Therefore, \(\((a - b)(a^2 + 4 + b^2) - 12a^2 + 39a + 9b\)\) will be equal to \(\(0\)\) if and only if \(\(a - b = 0\)\) since the expression \(\((a - b)(a^2 + 4 + b^2)\)\) will be equal to \(\(0\)\) only when \(\(a - b = 0\).\)

Hence, we have proved that if \(\(ab = 4\)\), then \(\((a - b)^3 - 9(a - b) = 0\).\)

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Answer:

Umm Where's The Answer?

Answer: The second r10

Step-by-step explanation:

Answer: 3 years

Step-by-step explanation:

Interest = 1740 - 1200 = 540

SI = prt / 100

540 = 1200 x 0.15 x t

540 = 180t

t = 540 / 180 = 3

Find the interest amount.

\(I=1740-1200=540\)

Use the formula for simple interest.

\(I=prt/100\)

Solve for t.

\(540=1200 \times 15\% \times t\)

\(540=1200 \times \frac{15}{100} \times t\)

\(540=180t\)

\(t=\frac{540}{180}\)

\(t=3\)

Answer:the coefficient of the 2nd term is : 24

Step-by-step explanation:(6p + 2)^2 =

(6p + 2)(6p + 2) =

36p^2 + 12p + 12p + 4 =

36p^2 + 24p + 4

Answer: You switch the point in the x-axis to the negative/positive of the number.

Step-by-step explanation:

So for example if you have the point (3,7), you would switch the 3 to -3 and you would keep the y the same.

Hope this helps!

The probability that the weight limit will be exceeded when there are exactly 40 passengers and 3 crew members on board is 0.031.

Mean = 196 × 43

Mean = 8428

Std. Dev. = 63 × √(43)

Std. Dev. = 63 × 6.56

Std. Dev. = 413.28

Here, μ = 8428, σ = 413.1186 and x = 9200. We must calculate P(X ≥ 9200).

he central limit theorem states that, for a sufficiently large sample size, the sample mean of all observations will be approximately normally distributed, regardless of the distribution of the population from which it was sampled.

The Central Limit Theorem is used to get the associated z-value.

z = (x - μ)/σ

z = (9200 - 8428)/413.28

z = 772/413.28

z = 1.87

Therefore,

P(X ≥ 9200) = P(z ≤ (9200 - 8428)/413.1186)

P(X ≥ 9200) = P(z ≤ 772/413.1186)

P(X ≥ 9200) = P(z ≥ 1.87)

P(X ≥ 9200) = 1 - 0.9693

P(X ≥ 9200) = 0.031

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The complete question is:

A small jet can carry up to 40 passengers and 3 crew members. There is a weight restriction of 9200 pounds on board. The combined weight of each passenger (or crew member) and his luggage has a mean of 196 pounds, with a standard deviation of 63 pounds. What is the probability that the weight limit will be exceeded when there are exactly 40 passengers and 3 crew members on board? Carry your intermediate computations to at least four decimal places. Report your result to at least three decimal places.

Answer:

I'm pretty sure it's a

Step-by-step explanation:

step by step

Answer:

below

Step-by-step explanation:

1. 35910 (190*189)

2. 343 possibilities

Answer:

1. 35910 (190*189)

2. 343 possibilities

Answer: y = 2(x + 2)² - 5

Step-by-step explanation:

          We are going to use the completing the square method to transform this quadratic equation from standard form to vertex form.

Given:

     y = 2x² + 8x + 3

Factor the 2 out of the first two terms:

     y = 2(x² + 4x) + 3

Add and subtract \(\frac{b}{2} ^2\):

     y = 2(x² + 4x + 4 - 4) + 3

Distribute the 2 into -4 and combine with the 3:

     y = 2(x² + 4x + 4) - 5

Factor (x² + 4x + 4):

     y = 2(x + 2)² - 5

Answer:

*inserting real answer*

The answer I think is A which is \(4r^{2}\)

Step-by-step explanation:

Hope this helps have a nice day!

Also to let you know I tried my best ok ;-;

The maximum amount you can earn is $540

a. y = 13.50x , 10 <= x <= 40
b. x = 10, y = 135; x = 20, y= 270; x = 30, y = 405; x = 40, y = 540
c. Domain: 10 <= x <= 40; Range: 0 <= y <= 540
d. The minimum amount you can earn in a week with this job is $135. The maximum amount you can earn is $540.

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Work Shown:

yz = y(x^2+2x-5)

yz = y(x^2) + y(2x) + y(-5)

yz = x^2( y ) + 2x( y ) - 5( y )

yz = x^2( 3x+5 ) + 2x( 3x+5 ) - 5( 3x+5 )

yz = x^2*3x + x^2*5 + 2x*3x + 2x*5 - 5*3x - 5*5

yz = 3x^3 + 5x^2 + 6x^2 + 10x - 15x - 25

yz = 3x^3 + 11x^2 - 5x - 25

The cumulative percent frequency for the class of 30 - 39 hours worked per week, among 400 statistics students, is 70%.

To find the cumulative percent frequency for the class of 30 - 39 hours worked per week, we need to calculate the cumulative frequency first. The cumulative frequency represents the sum of frequencies up to a certain class.

In this case, we start with the frequency of the first class, which is 20. Then we add the frequency of the second class, which is 80, to get a cumulative frequency of 100. Next, we add the frequency of the third class, which is 200, to get a cumulative frequency of 300. Finally, we add the frequency of the fourth class, which is 100, to get a cumulative frequency of 400.

To calculate the cumulative percent frequency, we divide the cumulative frequency for the class of 30 - 39 (which is 300) by the total number of observations (400) and multiply by 100. This gives us (300/400) * 100 = 75%. Therefore, the cumulative percent frequency for the class of 30 - 39 is 75%.

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Answer:

72° and 108°

Step-by-step explanation:

let one angle be x then the other angle is 1.5x

A linear pair sum to 180° , so

x + 1.5x = 180 , that is

2.5x = 180 ( divide both sides by 2.5 )

x = 72

1.5x = 1.5 × 72° = 108°

The two angles are 72° and 108°

Answer:

do you have wazapp I can send full pic of the answer here

Answer:118

Step-by-step explanation:

Y= mx-b ....substitute the values of m,x,b

Y=(5×6)-12

y= 30-12

Y=118

The point- slope form of the line is y-5 = -0.25(x+6).

What is line?

A line is an one-dimensional figure. It has length but no width. A line can be made of a set of points which is extended in opposite directions to infinity. There are straight line, horizontal, vertical lines or may be parallel lines perpendicular lines etc.

A line with a slope of –1/4 passes through the point (–6,5)

Any line in point - slope form can be written as

y - y₁= m(x -x₁) -------(1)

where,

y= y coordinate of second point

y₁ = y coordinate of first point

m= slope of the line

x= x coordinate of second point

x₁ = x coordinate of first point

In the given problem (x₁ , y₁) = (-6,5) and m= -1/4

Putting all these values in equation (1) we get,

y-5= (-1/4) (x- (-6))

⇒ y-5 = -0.25(x+6)

Hence, the point- slope form of the line is y-5 = -0.25(x+6).

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Answer: 20%

Step-by-step explanation:

Answer:

To calculate the interest earned on the R9000 invested at 8%p.a simple interest for 3 years, you'll need to use the formula I = Prt.

I = Interest earned

P = Principal amount (R9000)

r = Rate of interest (8% = 0.08)

t = Time (3 years)

Plugging in the values, we get: I = 9000 x 0.08 x 3 = R2160.

Therefore, the interest earned on the R9000 invested at 8%p.a simple interest for 3 years is R2160.

Solving the fraction negative four and one fifth ÷ two and one fourth gives; negative one and 39 over 45

We want to divide the fraction negative four and one fifth ÷ two and one fourth. This can be expressed as;

-4¹/₅ ÷ 2¹/₄

Converting to improper fraction gives;

-21/5 ÷ 9/4

= -21/5 * 4/9

= -84/45

3 is a common factor that both numerator and denominator can be divided by to get; -28/15

Expressing the answer as a mixed fraction is; -1 ³⁹/₄₅

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There are 25,053,600 different tests of 5 questions each that can be made from Ms. Wood's collection of 25 questions.

To find the number of different tests of 5 questions each that can be made from a set of 25 questions, you can use the combination formula. The combination formula is:

n! / (r! * (n-r)!)

Where n is the total number of items and r is the number of items being chosen at a time.

In this case, n is 25 (the total number of questions) and r is 5 (the number of questions per test). Plugging these values into the formula gives:

25! / (5! * (25-5)!) = 25! / (5! * 20!) = 25 * 24 * 23 * 22 * 21 / (5 * 4 * 3 * 2 * 1) = 25,!053,!600

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The probability of the intersection of the two diagonals chosen lying inside the nonagon is 2/3.

What is the probability?

Probability is a measure of the likelihood of an event occurring. It is a number between 0 and 1, with 0 representing an impossible event and 1 representing a certain event.

In this problem, the event of interest is the intersection of the two diagonals lying inside the nonagon. A nonagon is a 9-sided polygon, so there are 9 total corners, each of which can be one end of a diagonal. Therefore, there are 9 choose 2 = 36 total ways to choose two diagonals.

To find the number of favorable outcomes, we need to find the number of ways to choose two diagonals such that their intersection is inside the nonagon. To do this, we can notice that the diagonals that have an intersection inside the nonagon are the diagonals that connect non-adjacent corners of the nonagon. There are 8 non-adjacent corners, so there are 8 choose 2 = 28 ways to choose two non-adjacent corners.

So the probability of the intersection of the two diagonals lying inside the nonagon is:

P(intersection inside nonagon) = favorable outcomes / total outcomes = 28/36 = 2/3

Hence, the probability of the intersection of the two diagonals chosen lying inside the nonagon is 2/3.

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The probability of the intersection of the two diagonals chosen lying inside the nonagon is 2/3.

What is the probability?

Probability is a measure of the likelihood of an event occurring. It is a number between 0 and 1, with 0 representing an impossible event and 1 representing a certain event.

In this problem, the event of interest is the intersection of the two diagonals lying inside the nonagon. A nonagon is a 9-sided polygon, so there are 9 total corners, each of which can be one end of a diagonal. Therefore, there are 9 choose 2 = 36 total ways to choose two diagonals.

To find the number of favorable outcomes, we need to find the number of ways to choose two diagonals such that their intersection is inside the nonagon. To do this, we can notice that the diagonals that have an intersection inside the nonagon are the diagonals that connect non-adjacent corners of the nonagon. There are 8 non-adjacent corners, so there are 8 choose 2 = 28 ways to choose two non-adjacent corners.

So the probability of the intersection of the two diagonals lying inside the nonagon is:

P(intersection inside nonagon) = favorable outcomes / total outcomes = 28/36 = 2/3

Hence, the probability of the intersection of the two diagonals chosen lying inside the nonagon is 2/3.

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You can treat x and 2x+1 just as though they are real numbers.

So f(2x+1) = 3(2x+1) - 5 = 6x + 3 - 5 = 6x - 2

In the above, I made use of something called the distributive law which says that if a,b and c are real numbers, then a(b+c) = ab + ac.

Answer:

Step-by-step explanation:

k = xy

Putting values of x and y in the equation

k = (5)(-3.5)

= - 17.5

Finding value of x when y = 10

k = xy

- 17.5 = x10

Bringing like terms on one side

- 17.5 - 10 = x

-27.5 = x