A) The magnitude of the magnetic field these two segments produce at point P is 1.95 nT B) Direction of the magnetic field is into the page.
What is Biot - Savart's law?An equation that describes the magnetic field generated by a constant electric current is called Biot –Savart law.
A) Given; A0 and B0 = 3cm
I= 30 A and l= 2mm
Bio Savart's law;
dB= μIdl sinФ/4πr
Ф = 45° as ΔAOB is an isosceles triangle and Q is the angle between I dL and r.
dB at point P due to 2mm is;
dB= [μIdl sin45°/4πr][1/(AP)² + 1/(BP)²]
= [μIdl sin45°/4πr] [1/(1/2 AB)²+ 1/(1/2 AB)²]
dB= [μIdl sin45°/4πr] [ 8/ (AB)²]
=[(4π * 10^-7 * 30 *2 *10^-3*1/√2)/ 4π] * 8/18
= 1.948 * 10^-9 T
dB = 1.95 nT
B) Direction of the magnetic field is into the page.
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How much power is produced by flashlight that has a voltage of 12 volts and a current of 6.5 x 10^-2 amps? A. 0.78 watts B. 78 watts C. 190 watts D. 0.0054 watts E. 1.9 watts
Answer:
the powar produced is 0.7 watts
A. Obtain the following: microwave, ruler, something meltable (e.g. candy bar, marshmallows) B. A microwave works by setting up a standing electromagnetic wave inside of a box made of conducting materials. What is the value of an electric field inside a conductor
Answer:
E = 124.7 N / C
Explanation:
Let's analyze the exercise: the microwave creates an electromagnetic wave of frequency F = 2.45 GHz, this wave is introduced into the microwave cavity and is reflected on the metal walls, which is why one or more standing waves are formed.
The electric field of the standing wave is
I = E²
E =√I
where I is the intensity of the radiation.
What is it
I = P / A
where P is the effective emission power, almost all the power of the microwave and A is the area of the cavity, in the most used microwaves
P = 700 W and the area is A = 25 x 18 cm² = 0.045 m²
I = 700 / 0.045
I = 15555.56 W/m²
let's calculate the electric field
E = √15555.56
E = 124.7 N / C
Object 1 with mass 1=3.25 kg
is held in place on an inclined plane that makes an angle
of 40.0∘
with the horizontal. The coefficient of kinetic friction between the plane and the object is 0.535.
Object 2 with mass 2=4.75 kg
is connected to object 1 with a massless string over a massless, frictionless pulley. The objects are then released.
Calculate the magnitude
of the initial acceleration.
Calculate the magnitude
of the tension in the string once the objects are released.
The magnitude of the initial acceleration of the object is 4.2 m/s².
The tension in the string once the object starts moving is 13.65 N.
What is the magnitude of the initial acceleration?The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;
F(net) = ma
m₂g - μm₁g cosθ = a(m₁ + m₂)
where;
m₁ and m₂ are the masses of the blocksg is acceleration due to gravityμ is coefficient of frictionθ is the angle of inclinationa is the acceleration(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)
33.5 = 8a
a = 33.5/8
a = 4.2 m/s²
The tension in the string once the object starts moving is calculated as;
T = m₁a
T = 3.25 x 4.2
T = 13.65 N
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Two atoms of the same element only differ because one of the atoms has more electrons, making it an ion. Which statement is true? They have the same A-number and the same Z-number. They have the same A-number but different Z-number. They have a different A-number but the same Z-number. They have different A-numbers and different Z-numbers.
The correct answer is Option B. The statement "they have the same A-number but different Z-number" is true .
Atoms of the same element only differ because one of the atoms has more electrons, making it an ion.
This difference does not affect the mass of the atom, which is determined by the sum of its protons and neutrons, represented by the atomic mass or A-number.
The number of protons in an atom is called the atomic number or Z-number.
The Z-number of an element is unique to it. All the atoms of a given element have the same number of protons.
Thus, for example, all carbon atoms have six protons, making the Z-number of carbon 6.
However, different isotopes of an element can have different numbers of neutrons.
This means that they have a different atomic mass or A-number.
Therefore, they have the same A-number but different Z-number.
Therefore the correct Option is B.
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6. The radius of a ball is (5.2 + 0.2) cm. The percentage
error in the volume of the ball is;
Explanation:
It is given that, the radius of a ball is \((5.2\pm 0.2)\ cm\).
We need to find the percentage error in the volume of the ball. The volume of a sphere is : \(V=\dfrac{4}{3}\pi r^2\)
The percentage error is given by :
\(\dfrac{\Delta V}{V}=3\dfrac{\Delta r}{r}\times 100\)
We have, \(\Delta r=0.2\) and r = 5.2
So,
\(\dfrac{\Delta V}{V}=3\times \dfrac{0.2}{5.2}\times 100\\\\\%=11\%\)
So, the percentage error in the volume of the ball is 11%
A yo‑yo with a mass of 0.0600 kg and a rolling radius of =1.60 cm rolls down a string with a linear acceleration of 5.20 m/s2.
Calculate the tension magnitude in the string and the angular acceleration magnitude of the yo‑yo.
What is the moment of inertia of this yo‑yo?
The tension magnitude in the string is 0.312 N.
The angular acceleration magnitude of the yo‑yo is 325 rad/s².
The moment of inertia of the yo-yo is 7.68 x 10⁻⁶ kgm².
What is the moment of inertia of the yo-yo?
The moment of inertia of the yo-yo is calculated by applying the following equation as shown below;
I = ¹/₂MR²
where;
M is the mass of the yo-yoR is the radius of the yo-yoI = ¹/₂(0.06 kg)(0.016)²
I = 7.68 x 10⁻⁶ kgm²
The angular acceleration of the yo-yo is calculated as follows;
α = a/R
where;
a is the linear accelerationα = 5.2/0.016
α = 325 rad/s²
The tension in the string is calculated as follows;
T = ma
where;
m is the mass of the yo-yoa is the linear acceleration of the yo-yoT = 0.06 kg x 5.2 m/s²
T = 0.312 N
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Plot a graph of the pendulum period, T, vs. mass, m, using LabQuest App or graph paper. Scale each axis from the origin (0,0). Does the period appear to depend on mass? Do you have enough data to answer this conclusively?
Given a graph of the period versus the mass.
From the graph, the plot of the period versus mass is almost a horizontal line. That is as the mass of the pendulum increases, its period remains constant. The period of the pendulum is unaffected by the change in the mass. Thus the period of the pendulum does not depend on its mass.
This is also consistent with the formula of the period which is,
\(T=2\pi\sqrt[]{\frac{L}{g}}\)Where L is the length of the pendulum and g is the acceleration due to gravity.
As seen from the formula the period of the pendulum does not depend on the mass of the pendulum.
Therefore the period of the pendulum does not depend on its mass, this is conclusive from the given data.
Common Misconceptions about the Consumer Price Index [CPI]: Questions and
Answers
When the cost of food rises, does the CPI assume that consumers switch to less
desired foods, such as substituting hamburger for steak?
No. In January 1999, the BLS [Bureau of Labor Statistics] began using a geometric
mean formula in the CPI that reflects the fact that consumers shift their purchases
toward products that have fallen in relative price.... The CPI's objective is to calculate
the change in the amount consumers need to spend to maintain a constant level of
satisfaction.... The BLS is not assuming that consumers substitute hamburgers for
steak... Furthermore, the CPI doesn't implicitly assume that consumers always
substitute toward the less desirable good. Within the beef steaks item category, for
example, the assumption is that consumers on average would move up from flank
steak to filet mignon if the price of flank steak rose by a greater amount (or fell by less)
than filet mignon prices.
"Consumer Price Index," U.S. Bureau of Labor Statistics
Based on the text, how does the Consumer Price Index vary over the course of a
business cycle? E.2.1
O It changes according to the number of goods produced by a business.
O It changes according to availability of items, depending upon which items are priced the highest.
O It changes according to the desires of the consumers and access to lower-priced goods.
() It changes according to availability of ponds in the market hased on consumer needs
Consumer Price Index vary over the course of a business cycle It changes according to the desires of the consumers and access to lower-priced goods.
Based on the provided text, the Consumer Price Index (CPI) changes according to the desires of the consumers and access to lower-priced goods. The text mentions that consumers shift their purchases toward products that have fallen in relative price. The objective of the CPI is to calculate the change in the amount consumers need to spend to maintain a constant level of satisfaction.
The passage specifically states that the CPI does not assume that consumers substitute less desirable goods for more expensive ones. Instead, it acknowledges that consumers may move up within a category if the price of a lower-priced item rises more than that of a higher-priced item.
For example, within the beef steaks category, consumers are assumed to move up from flank steak to filet mignon if the price of flank steak rises by a greater amount or falls by less than filet mignon prices.
Therefore, the CPI takes into account consumer preferences and the availability of lower-priced goods. It reflects changes in prices and consumer behavior over the course of a business cycle, considering how consumers adjust their purchasing decisions based on price fluctuations and their desire for maintaining a constant level of satisfaction.
In summary, the CPI varies over the course of a business cycle based on consumer desires and access to lower-priced goods, rather than the availability of goods produced by businesses or the availability of specific items priced the highest.
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The spring in the figure has a spring constant of 1400 N/m . It is compressed 17.0 cm , then launches a 200 g block. The horizontal surface is frictionless, but the block's coefficient of kinetic friction on the incline is 0.210.
What distance d does the block sail through the air?
Use the work-energy theorem to find the velocity of the block when it's released by the spring. The work done by the spring on the block as it's restored to equilibrium is
W = 1/2 kx ²
where k is the spring constant and x is the compression of the spring. So
W = 1/2 (1400 N/m) (0.170 m)² = 20.23 J
This is equal to the block's change in kinetic energy ∆K,
W = ∆K
and since it starts from rest, the initial K is zero, leaving us with
W = 1/2 mv ²
where m is the mass of the block and v is its speed, so that
20.23 J = 1/2 (0.200 kg) v ²
==> v ≈ 14.2 m/s
The block slides at this speed across the frictionless surface until it hits the incline which introduces friction.
First, you need to find the length of the incline. It forms a 45° angle, and the underlying 45°-45°-90° triangle has a hypotenuse of length √2 (2.0 m) ≈ 2.83 m.
Next, you need to find the total work done on the block as it slides up the incline. Use Newton's second law to examine the forces acting on the block during this phase:
• the net force acting on the block in the direction perpendicular to the incline is
∑ F = n - mg cos(45°) = 0
where n = mg cos(45°) ≈ 1.39 N is the magnitude of the normal force and mg cos(45°) ≈ 1.39 N is the perpendicular component of the block's weight;
• the net force acting on the block parallel to the surface is
∑ F = -f - mg sin(45°) = ma
where f = µn = 0.210n ≈ 0.291 N is the magnitude of kinetic friction, mg sin(45°) ≈ 1.39 N is the parallel component of the weight, and a is the acceleration of the block.
Only the parallel forces do work on the block, and this work is negative because friction and weight oppose the block's sliding up the incline. The total work done on the block is then
W = (-0.291 N - 1.39 N) (2.83 m) ≈ -4.74 J
Use the work-energy theorem again to find the block's new speed v at the top of the incline:
W = ∆K
==> -4.74 J = 1/2 (0.200 kg) v ² - 1/2 (0.200 kg) (14.2 m/s)²
==> v ≈ 12.4 m/s
And now this becomes a projectile problem. The block travels a horizontal distance x after being launched at an angle of 45° with initial speed 12.4 m/s after time t according to
x = (12.4 m/s) cos(45°) t
Its height y from the 2.0 m-high surface at time t is given by
y = (12.4 m/s) sin(45°) t - 1/2 gt ²
The block lands on the surface when y = 0, which occurs after t ≈ 1.79 s, at which point the block has covered a distance d ≈ 15.7 m.
The block sail through the air at the distance of "15.8 m"
Given:
Spring constant,
1400 N/mMass,
200 gBlock's coefficient,
0.210By using Work energy theorem, we get
→ \(W_{spring}+W_g+W_f = KE_f-KE_i\)
By substituting the values, we get
→ \(\frac{1}{2}\times 1400\times (0.17)^2- (0.2\times 9.8\times 2)-(0.21\times 0.2\times \frac{9.8}{\sqrt{2} }\times \sqrt{2}\times 2 )= \frac{1}{2}\times 0.2\times V_f^2\)
here,
\(V_f = 12.44 \ m/s\)
→ \(d = \frac{V_f^2 Sin 2 \Theta}{g}\)
\(= \frac{(12.44)^2 Sin 90^{\circ}}{9.8}\)
\(= 15.8 \ m\)
Thus the answer above is right.
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two particles with equal charge experiences a force of 12 nN where they are 30 cm apart. what is the magnitude of the charge on each particle
Considering the Coulomb's Law, the magnitude of the charge on each particle is 4.2426 C.
Definition of Coulomb's LawCoulomb's law or law of electrostatics is the relationship between the interactions of electric charges, that is, it explains the force experienced by two electric charges at rest.
This law says that the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them, expressed mathematically as:
\(F=k\frac{Qq}{d^{2} }\)
where:
F is the electrical force of attraction or repulsion. It is measured in Newtons (N).Q and q are the values of the two point charges. They are measured in Coulombs (C).d is the value of the distance that separates them. It is measured in meters (m).k is a constant of proportionality called the Coulomb's law constant. It depends on the medium in which the charges are located. Specifically for vacuum k is approximately 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\).The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.
Magnitude of the charge on each particleIn this case, you know that:
F= 12 nN= 1.8×10⁻⁸ N (being 1 nN= 1×10⁻⁹ N)k= 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\)Q= qd= 30 cm= 0.3 m (being 100 cm= 1 m)Replacing in the Coulomb's Law:
\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{Qq}{(0.3 m)^{2} }\)
Being Q=q:
\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{q^{2} }{(0.3 m)^{2} }\)
Solving:
1.8×10⁻⁸ N÷ 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\)= q²÷ (0.3 m)²
2×10⁻¹⁸ C²/m²= q²÷ (0.3 m)²
2×10⁻¹⁸ C²/m²= q²÷ 0.09 m²
2×10⁻¹⁸ C²/m² ×0.09 m²= q²
1.8×10⁻¹⁹ C²= q²
√1.8×10⁻¹⁹ C²= q
4.2426 C= q= Q
Finally, each charge has a value of 4.2426 C.
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you made $100,000 this year. you have $0 in adjustments, $11,500 in deductions and $7,300 in exemptions. What is your taxable increase?
The tax rate you will pay is displayed in tax brackets for each category of taxable income.
Thus, For instance, in 2022, the first $10,275 of your taxable income is subject to the lowest tax rate of 10% if you are single.
Up until the maximum amount of your taxable income, the following portion of your income is taxed at a rate of 12%.
As taxable income rises, the tax rate rises under the progressive tax system. Overall, this has the result that taxpayers with higher incomes often pay a greater rate of income tax than taxpayers with lower incomes.
Thus, The tax rate you will pay is displayed in tax brackets for each category of taxable income.
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Question 81 point)
Ms. Vetter has not worked out in a long time. She is trying to lift her pet bunny cage off the ground to put into her car for their trip to Bunnyville
to visit some of her pet bunnies ancestors. If Ms. Vetter does not have enough _____ _____ she can use a simple machine to help her lift the cage off the ground and into her car.
A.craft supplies
B.big muscles
C.mechanical force
D.mechanical advantage
Answer:
(C) Mechanical Force
Explanation:
Three tiny charged metal balls are arranged on a straight line. The middle ball is positively charged and the two outside balls are negatively charged. The two outside balls are separated by 20 cm and the middle ball is exactly halfway in between. (HINT: Draw a picture; in your picture, the distance between the two outermost balls should be 20 cm.) The absolute value of the charge on each ball is the same, 1.45 μCoulombs (the meaning of μ, which is read as "micro", is 10-6). Give your answers in newtons.
a) What is the magnitude of the attractive force on either outside ball due ONLY to the positively-charged middle ball?
(b) What is the magnitude of the repulsive force on either outside ball due ONLY to the other outside ball?
(c) What is the magnitude of the net force on the outside of the ball
Answer:
\((a) 189.23 N\), \((b) 47.31 N\) and \((c) 141.92 N\).
Explanation:
Three balls are shown in figure having charge \(q=1.45 \mu C\). The middle ball, \(B\), is positively charged having charge \(+q\), and the remaining two outside balls, \(A\) and \(C\), are negatively charged having charged \(-q\) as shown.
\(AC=20 cm\) and \(AB=BC=10\) cm as B is the mid-point of AC.
Let \(d_1=AC=20\times 10^{-3}m\) and \(d_2=AB=BC=10\times 10^{-3}m\)
From Coulomb's law, the magnitude of the force, \(F\), between two point charges having magnitudes \(q_1 \& q_2\), separated by distance, \(d\), is
\(F=\frac {1}{4\pi\epsilon_0}\frac {q_1q_2}{d^2}\;\cdots (i)\)
where, \(\epsilon_0\) is the permittivity of free space and
\(\frac {1}{4\pi\epsilon_0}=9\times 10^9\) in SI units.
This force is repulsive for the same nature of charges and attractive for the different nature of charges.
Now, Using equations(i),
(a) The magnitude of attraction force between balls A and B is
\(F_{AB}=F_{BC}= \frac {1}{4\pi\epsilon_0}\frac {qq}{(d_2)^2}\)
\(\Rightarrow F_{AB}= 9\times 10^9}\frac {1.45\times 10^{-6}\times1.45\times 10^{-6}}{\left(10\times 10^{-3}\right)^2}\)
\(\Rightarrow F_{AB}=189.23 N\)
(a) The magnitude of the repulsive force between balls A and C is
\(F_{AC}= \frac {1}{4\pi\epsilon_0}\frac {qq}{(d_1)^2}\)
\(\Rightarrow F_{AC}= 9\times 10^9}\frac {1.45\times 10^{-6}\times1.45\times 10^{-6}}{\left(20\times 10^{-3}\right)^2}\)
\(\Rightarrow F_{AC}=47.31 N\)
(c) The magnitude of the net force, \(F_{net}\), on the outside of the ball is,
\(F_{net}=189.23-47.31 N\)
\(\Rightarrow F_{net}=141.92 N\)
figure left shows a standard cmos inverter. however, during manufacturing, the circuit was contaminated
I'm sorry, I'm not able to see the figure you mentioned. Can you please provide more information or context about the figure and the question you have related to it?
A rocket is fired from the earth to the moon at a speed of 0.930c. Let two events be "rocket leaves earth" and "rocket hits moon"
A. In the earth's reference frame, calculate Δx for these events.
B. In the earth's reference frame, calculate Δt for these events.
C. In the earth's reference frame, calculate the spacetime interval s for these events.
D. In the earth's reference frame, calculate Δx' for these events.
E. In the earth's reference frame, calculate Δt' for these events.
F. In the earth's reference frame, calculate the spacetime interval s' for these events.
G. In the earth's reference frame, calculate Δx if a rocket is replaced with a laser beam.
H. In the earth's reference frame, calculate Δt if a rocket is replaced with a laser beam.
I. In the earth's reference frame, calculate the spacetime interval s if a rocket is replaced with a laser beam.
Express ALL parts with appropriate units
A. Δx = 384,400 km (distance between Earth and Moon)
How to solveB. Δt = 384,400 km / (0.930 * 299,792 km/s) ≈ 1.421 s
C. s² ≈ (-2.781 * 10^10) km² (imaginary number, time-like separated events)
D, E, F. Cannot answer without specified primed frame.
G. Δx for laser beam = 384,400 km
H. Δt for laser beam = 384,400 km / 299,792 km/s ≈ 1.282 s
I. s² for laser beam ≈ 0 km² (light-like separated events)
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Uri looks through a telescope for two stars. He knows that both stars have the same absolute brightness and that the second star is twice as far from Earth as the first star. How bright will the second star appear compared to the first star? SC.8.E.5.5
A. It will appear brighter than the first star.
B. It will appear dimmer than the first star.
C. It will appear as bright as the first star.
D. It will appear redder then the first star.
Answer:
b
Explanation:
"Part B? Question
The total resistance in a circuit with two parallel resistors is 2 ohms and $R_1$ is 6 ohms. Using the equation for R₂, in terms of Rt and R₁, what is R₂ ?
R₂ is ohms."
The value of R₂, given that the total resistance in a circuit with two parallel resistor is 2 ohms, is 3 ohms
How do I determine the value of R₂?The formula to obtain the total resistance in a parallel connection for two resistors is given as folllow:
Rₜ = (R₁ × R₂) / (R₁ + R₂)
With the above formula, we can obtain the value of R₂. Details below:
Total resistance (Rₜ) = 2 ohmsResistor 1 (R₁) = 6 ohms Resistor 2 (R₂) = ?Rₜ = (R₁ × R₂) / (R₁ + R₂)
2 = (6 × R₂) / (6 + R₂)
2 = 6R₂ / (6 + R₂)
Cross multiply
2 × (6 + R₂) = 6R₂
Clear bracket
12 + 2R₂ = 6R₂
Collect like terms
12 = 6R₂ - 2R₂
12 = 4R₂
Divide both sides by 4
R₂ = 12 / 4
R₂ = 3 ohms
Thus, we can conclude that the value of R₂ is 3 ohms
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Doubling the potential across a given capacitor causes the energy stored in that capacitor to reduce to:_______
a. one-half.
b. double.
c. reduce to one-fourth.
d. quadruple.
Answer:
D. quadrupleExplanation:
The stored energy varies with the square of the electric charge stored in the capacitor. If you double the charge, the stored energy in the capacitor will quadruple or increase by a factor of 4.
Doubling the potential across a given capacitor causes the energy stored in that capacitor to reduce to :
D. Quadruple
"Energy"Doubling the potential across a given capacitor causes the energy stored in that capacitor to reduce to Quadruple.
The stored energy shifts with the square of the electric charge put away within the capacitor.
In case you twofold the charge, the put away vitality within the capacitor will fourfold or increment by a calculate of 4.
Thus, the correct answer is D.
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1. A ball is at rest on the top of a hill (see the figure).
At the top of the hill, the ball will have [the maximum value of its, no, the minimum value of its] gravitational potential energy and [no, the maximum value of its] kinetic energy. If the ball rolls down the hill then, its [gravitational potential energy, kinetic energy] is converted to [gravitational potential energy, kinetic energy] when it gets to the ground.
2. Get your stopwatch ready and prepare to drop the object from the height h you selected in the previous step. You should drop the object so its [bottom, top, middle] part is initially at the height h. The initial speed of the ball [zero, 9.8 m/s, 9.8 m/s^2, depends on the height h] You'll need to measure the time from when the ball leaves your hand to exactly when it hits the ground [ for the first time it bounces, after it bounces and then comes to rest, both the first time and then after it bounces; then average the two times]
.
As magma rises through the cracks of a spreading seafloor, it cools and adds new rock to the ocean floor.
The ribbon of magma causing the spreading is most similar to which structure?
A volcano
A sinkhole
A valley
A glacier
Answer:
zd its c
Explanation:
i know
Two identical strings making an angle of = 26.3° with respect to the vertical support a block of mass m = 14.7 kg (see the figure below). What is the tension in each of the strings? (Enter your answer in N.)
HINT
An illustration shows a block of mass m suspended from a ceiling by two strings of equal length. The lower ends of the strings share a single anchor point at the center of the block's upper surface while their upper ends have separate anchor points along the ceiling. Each string forms an angle with the vertical.
As a result, each string is under about 71.3 N of tension.
How tight are the strings on each one?The forces tugging on the rope from either end cause a certain strand of string or rope to be under strain. Recall that force equals mass times acceleration. Every change in acceleration or mass of the objects the rope is supporting will result in a change in tension in the rope, assuming the rope is stretched firmly.
The strain in the strings balances the block's weight in the vertical direction, giving us: 2T cos θ = mg
Therefore, we have: 2T sin θ = 0
since sin θ = 0 when θ = 26.3°.
Solving the first equation for T, we get:
T = mg / (2cos θ)
Substituting the given values, we get:
T = (14.7 kg)(9.81 m/s²) / (2cos 26.3°)
T ≈ 71.3 N
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What is the equivalent resistance of a circuit that contains three 10.0 Ω
resistors connected in parallel with a 6.0 V battery?
Ο Α. 3.33 Ω
Ο Β. 0.300 Ω
Ο C. 30,0 Ω
Ο D. 60.0 Ω
Answer:
A
Explanation:
Formula for Equivalent Resistance :
\(\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}\)
Solving :
\(\frac{1}{R} = \frac{1}{10} +\frac{1}{10} +\frac{1}{10}\)
\(\frac{1}{R} = \frac{3}{10}\)
\(R = \frac{10}{3}\)
R = 3.33 Ω
The equivalent resistance of a circuit that contains three 10.0 Ω
resistors connected in parallel is 33.33 Ω. Hence option A is correct.
What is a parallel combination of resistance?When two or more resistors are connected between two same points, they are said to be connected in parallel combination(as shown in fig). The equivalent resistance is the reciprocal and the sum of reciprocals of all resistance connected in parallel combination. In parallel combination, same potential difference exists across each resistor.
1/Rs= 1/R1+1/R2+1/R3……..1Rn where Rs is the equivalent or total resistance of the circuit.
1/Rs = R1+R2+R3............÷ RnR1R2R3.............Rn
Rs = R1R2R3.............÷RnR1+R2+R3.............Rn
Given,
R₁ = 10Ω
R₂ = 10Ω
R₃ = 10Ω
Equivalent resistance in parallel combination is,
Rs =R₁R₂R₃÷(R₁+R₂+R₃)
Rs = 1000÷(30)
Rs = 33.33 Ω
Hence option A is correct, there is typing mistake in the problem.
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Select the correct answer.
F₁ = 70 N
F₂ = 15 N
8
F₁
W = 80 N
Use this free body diagram to help you find the magnitude of the force F₁ needed to keep this block in static equilibrium.
Explanation:
F1 will have to have 65 N vertical up force to balance the net 65 N down on the body AND it will have to have 70 N horizontal to the right to balance the 70 N force that is acting to the left
Magnitude = sqrt ( 65^2 + 70^2) = 95.5 N
List the 6 questions you may apply to formulating a logical, reasonable perspective to any situation.
Steps to formulate a logical, reasonable perspective to any situation are: gather information, identify problem, analyze the situation, consider assumptions, generate solutions, evaluate options, consider your values, make decision and monitor and adjust
What are the 6 questions that may be applied to formulate logical, reasonable perspective to any situation?Here are the six questions that you can apply to formulating a logical, reasonable perspective to any situation:
What are the issues that should be addressed?
What are the relevant facts and data related to this problem or issue?
What assumptions am I making about the problem or issue?
What are the possible solutions or outcomes, and what are the pros and cons of each?
What are my values and priorities related to this problem or issue?
What additional information do I need to make an informed decision or come to a reasonable conclusion?
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A 55 kg skater spins with a speed of 7.2 m/s with her arms outstretched making a
radius of 0.6 m. Calculate the angular momentum of the skater. *
33 kg m^2/s
0 237.6 kg m^2/s
396 kg m^2/s
660 kg m^2/s
e xddd snoAnswer:n
E
xplanation:s no
All the questions are in the photos above. Thanks guys!
Answer:
right
Explanation:
Which change to this process would shift the equilibrium to produce the maximum possible amount of H20?
2H2 + 02 = 2H20 + energy
•A. Increasing the temperature
• B. Removing the Oz as it forms
•C. Decreasing the pressure
• D. Removing the H20 as it forms
Removing the H₂0 as it forms would shift the equilibrium to produce the most H₂0 possible. This is due to the reaction producing more water to replace the water that has been removed.
In chemistry, equilibrium refers to a state where the rate of the forward reaction is equal to the rate of the reverse reaction, resulting in no net change in the concentrations of the reactants and products. Equilibrium is an important concept in many chemical reactions, including acid-base reactions, redox reactions, and complex formation reactions.
Le Chatelier's principle can be used to predict how changes in conditions such as temperature, pressure, and concentration can affect the position of the equilibrium. For example, increasing the concentration of a reactant will shift the equilibrium towards the products, while decreasing the concentration of a reactant will shift the equilibrium towards the reactants.
In some cases, equilibrium can be used to achieve a desired product concentration. For example, the Haber process is used to produce ammonia by reacting nitrogen and hydrogen gases at high pressure and temperature. By controlling the reaction conditions, the equilibrium can be shifted to produce a high yield of ammonia.
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what is the velocity of the object 2.3 seconds after it is released from the top of the empire state building?
Explanation:
Object is under the effect of the acceleration of gravity
v = 1/2 a t^2 a = 9.81 m/s^2 t = 2.3
v = 25.9 m/s^2 = ~ 26 m/s ( two significant digits)
Use the picture to answer the following question. image Which of the following will predict what would happen if the scuba tank were to increase in temperature? A. The density of the gas in the tank would increase. B. The size of the gas particles in the tank would increase. C. The pressure exerted by the gas in the tank would increase. D. The number of particles in the tank would increase.
Answer:
c
Explanation:
Which is the load
Answer:
A is the load in the diagram
Answer:
i think the answer is A