A) What is the resistance (in Ω) of seventeen 330 Ω resistors connected in series?
b) What is the resistance (in Ω) of seventeen 330 Ω resistors connected in parallel?

Answer: true

Explanation:

Wavelength affects a wave's energy; the longer its wavelengths, the lesser the energy. Gamma rays therefore have the maximum energy and long radio waves the lowest in the electromagnetic spectrum.

The slowest seismic waves are surface waves. They move at a speed of 1.5 miles per second, or 2.5 km. Surface waves come in two different varieties. Love waves slither from side to side like a snake.

Low-energy photons make up radio waves; microwave photons contain a little more energy as radio waves; infrared photons have much more energy; and the most energetic photons of them are gamma rays.

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Explanation:

1st- states that when two bodies interact, they apply forces to one another that are equal in magnitude and opposite in direction. 

2nd- states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it. (most important law)

3rd- states that when two bodies interact, they apply forces to one another that are equal in magnitude and opposite in direction. (law of action/reaction)

Answer: A.

Explanation: If you move it from A to D look closely its a straight line.

Calculation of the angular separation between the fourth-order bright fringe and the center of the central bright fringeHere, the distance between the two slits = d = 1.30 × 10⁻⁵ m Wavelength of light = λ = 550 nm = 550 × 10⁻⁹ m.

Distance between the slit and the screen = D = 2.00 mThe distance between the central maxima and the fourth-order maxima is given by;y = (nλD) / d = (4 x 550 x 10⁻⁹ x 2) / (1.30 x 10⁻⁵) = 0.000036 = 3.6 x 10⁻⁵ mThe fringe width, w = λD / d = (550 x 10⁻⁹ x 2) / (1.30 x 10⁻⁵) = 0.000090 = 9 x 10⁻⁵ m.

Let the distance between the central maximum and the fourth-order maximum be x radians. Then, for small values of x, tan(x) = xThe angle subtended by the fringe is given by;θ = y / D = (3.6 x 10⁻⁵) / 2.00 = 1.8 x 10⁻⁵ radiansx = θ = 1.8 x 10⁻⁵ radiansTherefore, the angular separation between the fourth-order bright fringe and the center of the central bright fringe is 1.8 x 10⁻⁵ radians.

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The two cars will meet at a distance of 50 km from city A, and the meeting will occur 2 hours after they start moving.

To determine when and where the two cars meet, we need to calculate the time it takes for them to meet and then use that time to find the meeting location.

In this case:

Distance between cities A and B = 180 km

Velocity of the car starting from city A = 25 km/hr

Velocity of the car starting from city B = 65 km/hr

Let's assume the meeting point is at a distance of x km from city A. Since the total distance between the two cities is 180 km, the distance traveled by the car starting from city A is x km, and the distance traveled by the car starting from city B is (180 - x) km.

Using the formula:

Time = Distance / Velocity

The time taken by the car starting from city A to reach the meeting point is:

Time for car from A = x km / 25 km/hr = x/25 hr

The time taken by the car starting from city B to reach the meeting point is:

Time for car from B = (180 - x) km / 65 km/hr = (180 - x)/65 hr

Since the two cars meet at the same time, we can set their time equations equal to each other:

x/25 = (180 - x)/65

Now, we can solve this equation to find the value of x:

65x = 25(180 - x)

65x = 4500 - 25x

90x = 4500

x = 50

Therefore, the meeting point is 50 km from city A.

To find the time it takes for the cars to meet, we can substitute this value of x back into either of the time equations:

Time = Distance / Velocity

Time = 50 km / 25 km/hr

Time = 2 hours

So, the two cars will meet after 2 hours.

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Answer:

Wtens = (20 N) * (5 m) * cos (0 deg) = +100 Joules

Wgrav = (20 N) * (5 m) * cos (180 deg) = -100 Joules

Wapp= (10 N) * (5 m) *cos (0 degrees) = +50 Joules

Wfrict =(10 N) * (5 m) * cos (180 degrees) = -50 Joules

Wapp = (10 N) * (5 m) * cos (0 deg) = +50 Joules

Wfrict = (10 N) * (5 m) * cos (180 deg) = -50 Joules

Explanation:

Apply the work equation to determine the amount of work done by the applied force in each of the three situations described below.

Answer: A

Explanation:

Pulmonary - is lungs

Systemic - is body system

With a world-record leap with a maximum height of 58.7 cm above the ground. By the given launch angle of 58.0° and assuming a takeoff speed of 4.00 m/s, the horizontal distance covered is calculated.

To determine the horizontal distance covered by the froghopper, we can use the equations of projectile motion. Given the launch angle and takeoff speed, we can break down the initial velocity into its horizontal and vertical components.

The initial vertical velocity (v0y) can be found using the takeoff speed and the launch angle:

v0y = v * sin(θ),

v0y = 4.00 m/s * sin(58.0°),

v0y ≈ 3.36 m/s.

Next, we can calculate the time it takes for the froghopper to reach its maximum height. At the peak of the trajectory, the vertical component of the velocity becomes zero.

Using the equation for vertical velocity:

v = v0y - g * t,

0 = 3.36 m/s - 9.8 m/s^2 * t,

t ≈ 0.343 s.

Since the total time of flight is twice the time it takes to reach the maximum height, the total time is approximately 2 * 0.343 s = 0.686 s.

Finally, we can calculate the horizontal distance covered using the horizontal component of the initial velocity and the time of flight:

x = v0x * t,

x = v * cos(θ) * t,

x = 4.00 m/s * cos(58.0°) * 0.686 s,

x ≈ 1.64 m.

Therefore, for this world-record leap, the froghopper covered a horizontal distance of approximately 1.64 meters.

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Answer:

The right answer is. protons and neutrons

The cheetah's rate of acceleration is 10 m/s².Option A is correct.

The rate of velocity change concerning time is known as acceleration.

Given data;

Initial velocity, u= 0 m/s

Final velocity, v= 25 m/s

Time elapsed, t = 2.5 seconds.

To find ;

Acceleration, a

The acceleration when the change in velocity is observed by the formula as:

\(\rm a= \frac{v-u}{t}\)

Substitute the given values:

\(\rm a= \frac{25-0}{2.5} \\\\ a= 10 \ m/s^2\)

The cheetah's rate of acceleration is 10 m/s²

Hence option A is correct.

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Answer:

Systemic racism

Explanation:

Answer:

i dont know the answer sir !

Explanation:

Answer: The meter will read a negative voltage.

Explanation: If you're referring to a voltmeter, which measures the potential difference (voltage) between two points in an electrical circuit, if the positive lead is attached to the negatively charged area (lower potential) and the negative lead is attached to the positively charged area (higher potential), the meter will typically read a negative voltage.

This negative reading doesn't mean that the actual voltage is negative, but rather it indicates that the leads are reversed. The magnitude of the reading would still be the same, but the sign would be opposite.

For example, if there is a potential difference of 5 volts between the two points, with the point attached to the positive lead being at a lower potential, the voltmeter would read -5 volts. The negative sign is indicative of the direction in which current would flow if the two points were connected, which is from the point of higher potential to the point of lower potential.

Answer:

From the graph, at t = 5 seconds, the velocity = 50 m/s as shown also in the above table

Please find attached the graph

Explanation:

The initial velocity of the body =  m/s

The acceleration of the body = 8 m/s²

The velocity after 5 seconds can be determined graphically and by calculation as follows;

Graphically, we have the data points which can be found by the straight line relation  v = u + a×t,

Where ,

a = The slope = 8 m/s²

u = 10 m/s = The y-intercept

Which gives;

v = 10 + 8 × t

The following data can be calculated for various time t;

Time, t     Velocity , v

0,             10

1,              18

2,             26

3,             34

4,             42

5,             50

6,             58

From the graph, at t = 5 seconds, the velocity = 50 m/s as shown also in the above table

Please find attached the graph

By calculation, we have;

v = u + a×t

Where;

v = The final velocity

u = The initial velocity = 10 m/s

a = The acceleration = 8 m/s²

t = The time = 5 seconds

v = 10 + 5× 8 = 50 m/s.

Answer:

given that

V = 12.0 m/s

U = 0 m/s

s = 28 m

Explanation:

using the equation of motion

V^2 = U^2 + 2as

12^2 = 0 + 2(28)a

144 = 56a

a = 5.5 m/s^2

v = u +at

12 = 0 + 5.5t

12 = 5.5t

t = 2.2s

The temperature change is 75 degrees.

The specific heat capacity of a substance is the amount of heat added to a substance in order to make the temperature of 1 Kg of the substance to rise by 1 degree.

We know that;

H = mcdT

Where;

H = heat added

m = mass of water

c = heat capacity of water

dT = temperature change

So;

157.125 × 10^3 = 0.5 × 4,190 × dT

dT = 157.125 × 10^3/0.5 × 4,190

dT = 75 degrees

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If you weigh yourself at the equator of Earth, you would get a slightly smaller value than if you weigh yourself at one of the poles. This is due to two main factors: Earth's shape and its rotation.

Earth is not a perfect sphere; it is slightly flattened at the poles and bulging at the equator, known as an oblate spheroid. This shape causes the gravitational force to be slightly stronger at the poles than at the equator.

This difference in distance from the center of the Earth results in a slightly weaker gravitational pull at the equator compared to the poles, which causes you to weigh slightly less. However, the difference in weight is very small and would not be noticeable unless you have extremely sensitive equipment.

Additionally, Earth's rotation creates a centrifugal force that acts outward at the equator, counteracting some of the gravitational force. This causes objects at the equator to experience slightly less gravitational force than objects at the poles.

In summary, your weight would be slightly less at the equator than at the poles due to Earth's shape and its rotation.

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The width of the central maximum in the diffraction pattern on a screen 5.0 m away is 0.45 cm.

To find the width of the central maximum in the diffraction pattern, we can use the formula for single slit diffraction:

θ = λ / b

where θ is the angle to the first minimum, λ is the wavelength of the light, and b is the width of the single slit.

λ = 450 nm (nanometers) = 450 ˣ 10⁻⁹ m (meters)
b = 1.0 mm (millimeters) = 1.0 ˣ 10\(^(-3)\) m (meters)

Now we can calculate θ:
θ = (450 ˣ 10\(^(-9)\)) / (1.0 ˣ 10\(^(-3)\))
θ = 4.5 ˣ 10\(^(-4)\) radians

The width of the central maximum is twice the distance from the center to the first minimum. We can use the small angle approximation to find this distance:

x = L ˣ tan(θ)

where x is the distance from the center to the first minimum, L is the distance to the screen, and θ is the angle to the first minimum.

Given that L = 5.0 m, we can find x:

x = 5.0 ˣ tan(4.5ˣ  10\(^(-4)\))
x ≈ 5.0 ˣ (4.5 ˣ 10\(^(-4)\))
x ≈ 0.00225 m

The width of the central maximum is twice this distance, so we have:

Width = 2 ˣ  x = 2 ˣ 0.00225 m

        = 0.0045 m

Width = 0.0045 m ˣ 100 = 0.45 cm

Therefore, the width of the central maximum in the diffraction pattern on a screen 5.0 m away is 0.45 cm.

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The chi-square test assumes that the variables being analyzed are measured at a nominal or ordinal level of measurement.

In statistics, the level of measurement refers to the nature and properties of the data being collected. There are four levels of measurement: nominal, ordinal, interval, and ratio. Nominal and ordinal levels are considered categorical, while interval and ratio levels are considered numerical. The chi-square test is specifically designed for analyzing categorical data, where the observations can be classified into distinct categories or groups. It is used to determine whether there is a significant association or relationship between two categorical variables.

The test calculates the difference between the observed frequencies and the expected frequencies under the assumption of independence between the variables. It compares the observed and expected frequencies using a chi-square statistic and determines the p-value to assess the statistical significance of the association. Therefore, the chi-square test assumes that the variables being analyzed are measured at a nominal or ordinal level because it deals with categorical data and evaluates the relationship between different categories or groups.

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The coefficient of friction between the soap and the tub is 0.1.

The coefficient of static friction is the ratio of the maximum static friction force between the surfaces in contact before movement commences to the normal force.

Mathematically, the coefficient of static friction is given as;

μ = F/N

where;

Before an object start moving, the static friction must be overcame since it resists the motion of the object.

The normal force on the soap is the vertical downward force on the soap applied by Alan, N = 500 N

The force of friction on the soap, F = 50 N

μ = F/N

μ = 50 / 500

μ =  0.1

Thus, the coefficient of friction increases with increase in the horizontal force of friction and decrease in the normal force on the object.

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The radius of a sphere is the distance between the centre point of the sphere to the surface of the sphere.

r = d / 2

A = 4 π r²

r = √ ( A / 4 π )

V = 4 / 3 π r³

r = ∛ ( 3 V / 4 π )

r = Radius of the sphere

d = Diameter of the sphere

A = Surface Area of the sphere

V = Volume of the sphere

A sphere is the 3-dimensional form of a circle. Since the radius of the sphere is a measure of length, its unit is usually meter.

Therefore, the radius of a sphere is the distance between the centre point of the sphere to the surface of the sphere.

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Answer:

Several cm of lead

Explanation:

It will need a force acceleration

4 Times. If the sun were moved 2 times further away, it would be 4 times fainter.

The relationship between fainting and the distance from the sun can be given as:

\(1/d^2\), where \(d\) is the distance from the sun.

This is called the Inverse Square Law.

According to the inverse square law, a phenomenon's intensity falls in proportion to the square of the distance as it gets further away from its source. Understanding the behavior of light and sound to develop systems that use or interact with these phenomena all depend on this idea, which is crucial in many fields of physics and engineering.

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Answer:

Put water at room temperature into a vacuum chamber and begin removing the air. Eventually, the boiling temperature will fall below the water temperature and boiling will begin without heating. Or if you want to be easy but messy, add dry ice to a bowl of water and watch how the water starts to boil.

Answer:

s orbital

Explanation:

that the answer

At time t = 0 a solid conducting sphere is given total charges q that is uniformly spread throughout its volume it is a stable distribution.

Student 1 : At time t = 0 a solid conducting sphere is given total charges q that is uniformly spread throughout its volume it is a stable distribution.

Student 2 : No its a unstable distribution.

Student 1 : But when the charges are equally given in the volume of sphere the charges will also be equal and when charges are equal it is said to be stable.

Student 2 : What about the resonance, because of it the stability may not exist.

Student 1 : When we talk about resonance here we just mean the charge distribution over two different atoms in a molecule.

Student 2 : As you know, resonance structures are considered to be more stable due to charge distribution.

Student 1 : If the charge is distributed between two atoms in the molecule, there is a gap between the charges and it is less repulsive and more stable than a molecule with no charge distribution.

Student 2 : In resonance , generally the negative charge goes on most electronegative atom.

Student 1 : Yes but on the other hand, the molecule gains stability because the positive charge is transferred to the less electronegative atom.

A stable distribution is when the charges are equally given in the volume of sphere the charges will also be equal .

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