A un paciente se le toma la temperatura a las 7 am, 9 am, 2 pm y a las 4 pm. La primera segunda y cuarta lecturas son de 66 grados F, 90 grados F, y 94 grados F, respectivamente. Si el promedio de las 4 lecturas fue 86 grados F, cual fue su tercera lectura?

The weighted average length of a nail from the carpenter's box whose distribution is give in image is: 3.5cm.

What is weighted average ?

Weighted average is a type of average that takes into account the relative importance or weight of each data point. In a weighted average, each data point is multiplied by a corresponding weight, which reflects its relative importance, and the products are then summed and divided by the sum of the weights.

To find the weighted average length of a nail, we need to multiply each nail length by its percent abundance, then add up all the products and divide by the total percent abundance.

Let's start by calculating the product of each nail length and its percent abundance:

Short nail: (2.5 cm) x (70.5%) = 1.7625 cm

Medium nail: (5.0 cm) x (19%) = 0.95 cm

Long nail: (7.5 cm) x (10.5%) = 0.7875 cm

Now, we add up all the products:

1.7625 cm + 0.95 cm + 0.7875 cm = 3.5 cm

Finally, we divide by the total percent abundance:

70.5% + 19.0% + 10.5% = 100%

Therefore, the weighted average length of a nail from the carpenter's box is: 3.5 cm ÷ 100% = 3.5cm

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Answer:

5%

Step-by-step explanation:

Answer:

0.9

Step-by-step explanation:

The equivalent value of the expression 1.8-0.9 = 0.9

Given data:

The first decimal number is represented as p.

The value of p = 1.8

The second decimal number is represented as q.

The value of q = 0.9

The expression A = p - q

On simplifying the equation:

A = 1.8 - 0.9

On subtracting both the decimals:

A = 0.9

Therefore, the value of A is 0.9

Hence, the expression is A = 0.9

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The solution to the quadratic equation 2x² - 7x - 4x is x = 0 and x = 11/2.

A quadratic equation is an algebraic expression in the form of variables and constants.

A quadratic equation has two roots as its degree is two.

Given, y = 2x² - 7x - 4x.

y = 2x² - 11x.

y = x(2x - 11).

Or,

x(2x - 11) = 0.

x = 0 Or 2x - 11 = 0 ⇒ 2x = 11 ⇒ x = 11/2.

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Answer:

You bought 5 books for $60 and 2 movies for $30

Step-by-step explanation:

Answer:

63

Step-by-step explanation:

Answer: 1. 6,341

2. 634.1

3. 63.41

Step-by-step explanation:

Answer:

the are so many numbers but here's one of them

Step-by-step explanation:

Since the number is less than 700, it cannot begin with a 7 or an 8.

So the hundreds digit can only be a 2 or a 5.

Now the tens digit can be any digit not occupying the hudreds digit. So there would be 3 possibilities, and there remain two possibilities for the units digit.

Hence, the number of such numbers is 2x3x2 which is 12.

The number of two-digit or three-digit numbers that can be made using the digits 1, 7, 8, 5, and 2 will be 150.

A sample is a group of clearly specified components. The number of items in a finite set is denoted by a curly bracket.

The number of two-digit numbers that can be made using the digits 1, 7, 8, 5, and 2 is calculated as,

⇒ 5 x 5

⇒ 25

The number of three-digit numbers that can be made using the digits 1, 7, 8, 5, and 2 is calculated as,

⇒ 5 x 5 x 3

⇒ 125

The number of two-digit or three-digit numbers that can be made using the digits 1, 7, 8, 5, and 2 is calculated as,

⇒ 125 + 25

⇒ 150

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Answer:

\(\displaystyle \frac{75}{2}\) or \(37.5\)

Step-by-step explanation:

We can answer this problem geometrically:

\(\displaystyle \int^6_{-4}f(x)\,dx=\int^1_{-4}f(x)\,dx+\int^3_1f(x)\,dx+\int^6_3f(x)\,dx\\\\\int^6_{-4}f(x)\,dx=(5*5)+\frac{1}{2}(2*5)+\frac{1}{2}(3*5)\\\\\int^6_{-4}f(x)\,dx=25+5+7.5\\\\\int^6_{-4}f(x)\,dx=37.5=\frac{75}{2}\)

Notice that we found the area of the rectangular region between -4 and 1, and then the two triangular areas from 1 to 3 and 3 to 6. We then found the sum of these areas to get the total area under the curve of f(x) from -4 to 6.

Answer:

\(\dfrac{75}{2}\)

Step-by-step explanation:

The value of a definite integral represents the area between the x-axis and the graph of the function you’re integrating between two limits.

\(\boxed{\begin{minipage}{8.5 cm}\underline{De\:\!finite integration}\\\\$\displaystyle \int^b_a f(x)\:\:\text{d}x$\\\\\\where $a$ is the lower limit and $b$ is the upper limit.\\\end{minipage}}\)

The given definite integral is:

\(\displaystyle \int^6_{-4} f(x)\; \;\text{d}x\)

This means we need to find the area between the x-axis and the function between the limits x = -4 and x = 6.

Notice that the function touches the x-axis at x = 3.

Therefore, we can separate the integral into two areas and add them together:

\(\displaystyle \int^6_{-4} f(x)\; \;\text{d}x=\int^3_{-4} f(x)\; \;\text{d}x+\int^6_{3} f(x)\; \;\text{d}x\)

The area between the x-axis and the function between the limits x = -4 and x = 3 is a trapezoid with bases of 5 and 7 units, and a height of 5 units.

The area between the x-axis and the function between the limits x = 3 and x = 6 is a triangle with base of 3 units and height of 5 units.

Using the formulas for the area of a trapezoid and the area of a triangle, the definite integral can be calculated as follows:

\(\begin{aligned}\displaystyle \int^6_{-4} f(x)\; \;\text{d}x & =\int^3_{-4} f(x)\; \;\text{d}x+\int^6_{3} f(x)\; \;\text{d}x\\\\& =\dfrac{1}{2}(5+7)(5)+\dfrac{1}{2}(3)(5)\\\\& =30+\dfrac{15}{2}\\\\& =\dfrac{75}{2}\end{aligned}\)

The completed sequence is: 3/k, 3/k, 3/k, 9/2k.To complete the sequence of numbers with a constant difference between adjacent numbers, we can calculate the common difference by subtracting the first term from the second term.

Let's denote the missing terms as A and B.

The given sequence is: 3/k, A, B, 9/2k.

The common difference can be found by subtracting 3/k from A or B. Therefore:

A - 3/k = B - A = 9/2k - B.

To simplify, we can equate the two expressions for the                     common difference:

A - 3/k = 9/2k - B.

Next, we can solve for A and B using this equation.

Adding 3/k to both sides gives:

A = 3/k + 9/2k - B.

Now, we can substitute the value of A into the equation:

3/k + 9/2k - B - 3/k = 9/2k - B.

Simplifying further, we have:

9/2k - 3/k = 9/2k - B.

Cancelling out the common terms, we find:

-3/k = -B.

Multiplying both sides by -1, we get:

3/k = B.

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In the 6th grade, he read = 15 books

In the 7th grade, he read = 21 books

The difference between the books he read = 21-15 =6 books

Total number of books from 6th to 7th grade = 15+21 = 36 books

So, the percentage of change in the number of books

Percentage in the number of books Miguel read from 6th to 7th grade? is 16.66%

Answer: 1.To find the mean, we sum up all the scores and divide by the number of scores:

Mean = (5 + 12 + 8 + 14 + 11) / 5 = 50 / 5 = 10

To find the variance, we first find the deviation of each score from the mean:

5 - 10 = -5

12 - 10 = 2

8 - 10 = -2

14 - 10 = 4

11 - 10 = 1

We square each deviation and sum them up:

(-5)^2 + 2^2 + (-2)^2 + 4^2 + 1^2 = 26

Then, we divide by the number of scores to find the variance:

Variance = 26 / 5 = 5.2

Finally, we find the standard deviation by taking the square root of the variance:

Standard deviation = √5.2 = 2.28

2. To construct a simple random sample of size 2, we can choose any two scores from the population. The number of ways to do this is given by the combination formula:

C(5,2) = 5! / (2! * (5 - 2)!) = 10

Therefore, there are 10 simple random samples of size 2 that can be constructed.

3.The mean of the sampling distribution of the sample means is equal to the population mean, which we found to be 10. The variance of the sampling distribution is equal to the population variance divided by the sample size:

Variance of sampling distribution = Variance / Sample size = 5.2 / 2 = 2.6

The standard error of the sampling distribution is the square root of the variance:

Standard error = √2.6 = 1.61

4.The variance of the sampling distribution is 2.6, as we found in part

5. Since this is considered to be data from a simple random sample, we can use the sample mean as a point estimate of the population mean. Therefore, the point estimate of the population mean is 10.

Similarly, we can use the sample variance as a point estimate of the population variance. However, we need to correct for the bias in the sample variance by dividing by (n-1) instead of n:

Point estimate of population variance = Variance * (n / (n-1)) = 5.2 * (5 / 4) = 6.5

Step-by-step explanation:

Answer:

(Below)

Step-by-step explanation:

First, solve for  \(y\)

\(y=-5+\frac{5x}{4}\)

\(y=\frac{5}{4}x-5\)

\(\mathrm{Slope}: \frac{5}{4} \\\mathrm{y-intercept}: (0,-5)\)

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Answer:

The answer is letter A.....

Answer: C: 43

Step-by-step explanation:

As we are calling the function with 2 for x, we can substitute 2 for every x we see in the function and solve.

\(f(2)=2(2)^3-19(2)^2+28(2)+47\\=2(8)-19(4)+28(2)+47\\=16-76+56+47\\=43\)

Hence, f(2) is 43.

They collected $134.45 and we can find this using percentage.

Travis = $43

Jessica = 43 - (43 × 20%) = $34.4

Robin = 43 + (43 × 35%) = $58.05

Percentage (%):

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The radio will cost $21.32 during a 1/3 off sale.

What is selling price?

The selling price of a product or service is the seller’s final price, i.e., how much the customer pays for something. The exchange can be for a product or service in a certain quantity, weight, or measure.

If the radio is on sale for 1/3 off, it means the customer will pay only 2/3 of the original price.

So, the sale price of the radio can be calculated as follows:

Sale price = (1 - 1/3) * Original price

Sale price = (2/3) * $31.98

Sale price = $21.32

Therefore, the radio will cost $21.32 during a 1/3 off sale.

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Answer:

The probability is 0.58992 or simply 0.59

Step-by-step explanation:

We start by getting the z-scores of the diameter

we have this as follows;

Mathematically;

z-score = (x-mean)/SD

mean = 9.0 mm

SD = 1.5 mm

For 8.00 mm, we have

z = (8-9)/1.5 = -0.67

For 10.5 mm, we have

z = (10.5-9)/1.5 = 1

So the probability we want to calculate is;

P( 1 < x < -0.67)

we can calculate this using the standard normal distribution table

We have this as ;

P( x < -0.67) - P( x > 1) = 0.58992

Based on the information given, the price of the zero coupon bond is $692.04.

To calculate the price of a zero coupon bond, we need to use the following formula:

\(\sf P =\dfrac{F}{1+r\div n}^{(nt)\)

Where:

Also, the annual interest rate is 7.50%, which is the market interest rate, and the compounding is semiannual, which means n = 2. Finally, the time to maturity is 5 years.

Plugging in the values into the formula, we get:

\(\sf P = \dfrac{1000}{(1+0.075\div2)^{(2\times5)}}\)

\(\sf P = \dfrac{1000}{(1.0375)^{10}}\)

\(\sf P = \dfrac{1000}{1.4450}\)

\(\sf P = \$692.04 \ \ (rounded \ to \ the \ nearest \ cent)\)

Therefore, the price of the zero coupon bond is $692.04.

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The value of side length x in diagram a) is 4.3mm and side length x in diagram b) is 309.7 m.

The figures in the image are right triangles.

A)

angle D = 17 degree

Adjacent to angle D = 14 mm

Opposite to angle D = x

To solve for the missing side length x, we use the trigonometric ratio.

Note that: tangent = opposite / adjacent

Hence:

tan( 17 ) = x/14

x = tan( 17 ) × 14

x = 4.3mm

B)

angle Z = 82 degree

Adjacent to angle Z = 43.1 m

Hypotenuse = x

Using trigonometric ratio,

cosine = adjacent / hypotenuse

cos( 82 ) = 43.1 / x

x = 43.1 / cos( 82 )

x = 309.7 m

Therefore, the measure of x is 309.7 meters.

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The amount of cars you need to break even is 5.

To determine the number of cars you need to break even, we can set up an equation where the revenue equals the total cost.

Let's denote the number of cars as x.

Revenue = Number of cars × Price per wash

= x × $10

Total cost = Cost per car × Number of cars + One-time cost

= $3x + $35

To break even, the revenue should be equal to the total cost:

x × $10 = $3x + $35

Now, let's solve this equation to find the value of x:

10x = 3x + 35

Subtract 3x from both sides:

10x - 3x = 3x + 35 - 3x

7x = 35

Divide both sides by 7:

x = 35 / 7

x = 5

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The method of counting seeds by touching each can be more effective in enhancing strong number sense in children as it allows them to experience each number physically and helps them in developing a strong sense of numbers.

In order to enhance strong number sense in children, there are various methods that can be used.

In the given scenario, Mme Potatana asked the children to count as a whole class from 1 to 20 while Ntate Mafodi asked the children in his class to count seeds from the school's ground in a pile by touching each as they count.

Both methods have their own benefits, but the method of counting seeds by touching each can be more effective in enhancing strong number sense in children.

The method of counting seeds by touching each can be more effective in enhancing strong number sense in children because it allows them to experience each number physically.

This helps them in developing a strong sense of numbers. By touching each seed as they count, children can feel and see each number, which helps them in understanding numbers better. Additionally, it helps in developing the concept of one-to-one correspondence and counting by rote.

Here are some appropriate examples for enhancing strong number sense using the method of counting seeds by touching each:

1. Use counters: Provide children with counters such as small objects, blocks, or toys. Ask them to count the number of counters by touching each as they count.

2. Counting on fingers: Encourage children to count on their fingers. This helps them in developing a strong sense of numbers and helps them in understanding the concept of one-to-one correspondence.

3. Counting objects in a pile: Ask children to count objects in a pile by touching each as they count. This helps in developing the concept of counting by rote and helps in enhancing strong number sense.

Overall, the method of counting seeds by touching each can be more effective in enhancing strong number sense in children as it allows them to experience each number physically and helps them in developing a strong sense of numbers.

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A set of numbers that can represent the side lengths, in centimeters, of a right triangle is any set that satisfies the Pythagorean theorem, where the square of the hypotenuse's length is equal to the sum of the squares of the other two sides.

A right triangle is a type of triangle that contains a 90-degree angle. According to the Pythagorean theorem, in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

Let's consider a set of numbers that could represent the side lengths of a right triangle in centimeters.

One possible set could be 3 cm, 4 cm, and 5 cm.

To verify if this set forms a right triangle, we can apply the Pythagorean theorem.

Squaring the length of the shortest side, 3 cm, gives us 9. Squaring the length of the other side, 4 cm, gives us 16.

Adding these two values together gives us 25.

Finally, squaring the length of the hypotenuse, 5 cm, also gives us 25. Since both values are equal, this set of side lengths satisfies the Pythagorean theorem, and hence forms a right triangle.

It's worth mentioning that the set of side lengths forming a right triangle is not limited to just 3 cm, 4 cm, and 5 cm.

There are infinitely many such sets that can be generated by using different combinations of positive integers that satisfy the Pythagorean theorem.

These sets are known as Pythagorean triples.

Some other examples include 5 cm, 12 cm, and 13 cm, or 8 cm, 15 cm, and 17 cm.

In summary, a right triangle can have various sets of side lengths in centimeters, as long as they satisfy the Pythagorean theorem, where the square of the hypotenuse's length is equal to the sum of the squares of the other two sides.

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Answer:

7 hours and 15 minutes

Step-by-step explanation:

8 - 3/4 = 7 1/4 hours

Triangle ADC also has a right angle at D, making it a right-angled triangle.

The exact value of x be 2.25.

The hypotenuse's square is equal to the sum of its two other side squares of a right-angled triangle, according to the Pythagoras theorem.

Triangle ADB exists even a right-angled triangle with right-angle at D.

Therefore, Base of Triangle ADB = BD = 4,

Height of Triangle ADB = AD = 3,

Hypotenuse of Triangle ADB = AB

Using the Pythagoras Theorem, we get,

\($\left[(A D)^2+(B D)^2\right]=(A B)^2$\)

substitute the values in the above equation, we get

or,\($(A B)^2=\left[(3)^2+(4)^2\right]$\)

simplifying the equation, we get

or, \($(A B)^2=[9+16]$\)

or, \($(A B)^2=25$\)

or, \($\sqrt{(A B)^2}=\sqrt{25}$\)

or, AB = 25

Triangle ADC is also a right-angled triangle with right-angle at D.

Therefore, Base of Triangle ADC = DC = x

Height of Triangle ADC = AD = 3,

And, Hypotenuse of Triangle ADC = AC

Using the Pythagoras Theorem, we get,

\(& {\left[(D C)^2+(A D)^2\right]=(A C)^2} \\\)

simplifying the equation, we get

\(& \text { or },(A C)^2=\left[(3)^2+(x)^2\right] \\\)

\(& \text { or },(A C)^2=\left[9+x^2\right]\)

Triangle ABC is also a right-angled triangle with right-angle at A. Therefore, Base of Triangle ABC = AC,

Height of Triangle ABC = AB = 5,

And, Hypotenuse of Triangle ABC =  BC = (4 + x)

Using the Pythagoras Theorem, we get,

\(& {\left[(A C)^2+(A B)^2\right]=(B C)^2} \\\)

\(& \text { or, }(B C)^2=\left[(A C)^2+(A B)^2\right] \\\)

substitute the values in the above equation, we get

\(& \text { or, }(4+x)^2=\left[\left(9+x^2\right)+(5)^2\right] \\\)

simplifying the equation, we get

\(& \text { or, }\left[4^2+(2 \times 4 \times x)+x^2\right]=\left[9+x^2+25\right] \\\)

\(& \text { or, }\left[16+8 x+x^2\right]=\left[(9+25)+x^2\right] \\\)

\(& \text { or, }\left[16+8 x+x^2\right]=\left[34+x^2\right] \\\)

\(& \text { or, }\left[16+8 x+x^2\right]-\left[34+x^2\right]=0 \\\)

\(& \text { or, },(16-34)+8 x+\left(x^2-x^2\right)=0 \\\)

8x - 18 = 0

8x = 18

\(& \text { or, } x=\frac{18}{8} \\\)

\(& \text { or, } x=\frac{9 \times 2}{4 \times 2} \\\)

\(& \text { or, } x=\frac{9}{4} \\\)

Therefore, the value of x be 2.25.

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The sentence that correctly uses commas to separate coordinate adjectives is D. Shannon signed up for the challenging, writing course at the local, community college.

Words that describe or provide details about a noun are called adjectives. Two or more adjectives are referred to as coordinate adjectives when they are used to describe the same noun. 'And' or a comma are used to separate them every time.  These must be properly used, else a reader can mistake adjectives for a single modifier rather than a pair of coordinates.

The comma should be placed between any two or more adjectives that equally modify the same noun, and their order doesn't have to change the meaning, according to the guideline for using commas to separate coordinate adjectives in sentences. Option D includes the coordinate adjectives "challenging" and "writing" that equally modify the noun "course," as well as the coordinating adjectives "local" and "community" that equally modify the noun "college."

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Answer:

9576

Step-by-step explanation:

Area of the triangle × height

(1/2×28×19)×36