A town has a population of 13,000 and grows at 5% every year what will the population be after 11 years to the nearest whole number

Answer:

(0,5)

(5/6,35/9)

Step-by-step explanation:

Step-by-step explanation:

x = devaughn age

y = sydney age

x = y - 9

x + y = 61

y-9 + y = 61

2y= 61+9

2y = 70

y = 35

x = 35 - 9 = 26

check

35 + 26 = 61

35- 26 = 9

Hope this helps!

Answer:

1.5

Step-by-step explanation

Answer:

they can help by finding answers faster like a calculator.

Step-by-step explanation:

The expected value of that Poisson distribution is 12.96. So, correct option is A.

The expected value of a Poisson distribution is given by lambda, where lambda is the mean or average number of occurrences in the given interval. In a Poisson distribution, the variance is equal to the mean, so the standard deviation is the square root of the mean.

Thus, if the standard deviation is known to be 3.60, we can find the mean as follows:

Standard deviation = √(mean)

Squaring both sides, we get:

Variance = mean

Substituting the given standard deviation, we have:

3.60 = √(mean)

Squaring both sides again, we get:

12.96 = mean

Therefore, correct option is A.

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Answer:

$6.25 for 1 shirt ,$11.75 for 1 pants

Step-by-step explanation:

3s +4p = 63.50

6s +8p = 127

2s+3p = 46.25

6s+9p = 138.75

9p-8p = 138.75-127

1p = 11.75

2s + 3(11.75) =46.25

2s= 12.5

1s= 6.25

The slope of a logarithmic graph depends on the type of logarithm used.

For a logarithmic function in the form y = log(b,x) where b is the base of the logarithm, the slope of the graph is undefined for x=0 and for x<0 because logarithmic functions are not defined in those cases.

For a natural logarithm, the slope is negative infinity at x=0 and positive for x > 0. As x increases, the slope becomes closer to zero.

For a common logarithm, the slope is negative infinity at x=0 and positive for x > 0. As x increases, the slope becomes closer to zero.

It's important to note that logarithmic functions are not linear functions, and therefore they do not have a constant slope, the slope of a logarithmic graph will change throughout the graph.

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Answer:

-0.4........................

Answer:

\(\displaystyle \angle A=30^\circ\)

Step-by-step explanation:

We are given that in Circle O, Arc BAC measures 300°.

Recall that arc lengths will always total 360°. Therefore:

\(\stackrel{\frown}{BAC}+\stackrel{\frown}{CB}=360^\circ\)

By substitution:

\(300+\stackrel{\frown}{CB}=360\)

Thus:

\(\stackrel{\frown}{CB}=60^\circ\)

∠A intercepts Arc CB. Since it is an inscribed angle, it will be half of its intercepted arc. In other words:

\(\angle A=\displaystyle \frac{1}{2}\stackrel{\frown}{CB}\)

Therefore:

\(\displaystyle \angle A=\frac{1}{2}(60)=30^\circ\)

Given the points:

We need to reflect the points over the line y = x

The rule of reflection is as follows:

So, the points after reflection will be:

Volume =  

1  πr2h

3

=  

1 ×π×42×7

3

=  117.28612573402 centimeters^3

The value of the composite function (g o f)(6) is 3

From the question, we have the following parameters that can be used in our computation:

f(x) = 2x + 3

g(x) = 1/5x

A. Find f(6)

substitute the known values in the above equation, so, we have the following representation

f(6) = 2 * 6 + 3

So, we have

f(6) = 15

For the function (gof)(6), we have

g(x) = 1/5x

This gives

(g o f)(6) = 1/5 * 15

Evaluate

(g o f)(6) = 3

Hence, the composite function has a solution of 3

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Complete question

Given that f(x) = 2x + 3 and g(x) = 1/5x

Compute (gof)(6)

A. Find f(6)

B. substitute the value of g(x) into the function f(x) in place of x

Step-by-step explanation:

3x+2y = 7

3x +2(-3x+11) = 7

3x-6x +11 = 7

-3x+11 =7

-3x = 7-11

-3x =-4

x =-4/-3

x = 4/3.

bro u r option has wrong

The probability that the digit that is received (after having been transmitted across the 4 channels) is 0.3645

In communication systems, it is common to face the challenge of transmitting information accurately over a noisy channel. In this scenario, errors can occur during transmission, and it is essential to quantify the probability of receiving the correct information at the end of the channel.

In this problem, we are asked to calculate the probability that the digit received after transmitting a 0 across four channels is also a 0. We know that each channel can either transmit the digit correctly with probability 0.9 or incorrectly with probability 0.1. Therefore, we can use the concept of conditional probability to solve this problem.

Using Bayes' theorem, we can rewrite this as:

P(CCCC | 0 received) x P(0 received) / P(CCCC)

Here, P(CCCC | 0 received) represents the probability that all four channels transmitted the 0 correctly, given that a 0 was received. This probability can be calculated as:

P(CCCC | 0 received) = P(C) x P(C | C) x P(C | C | C) x P(C | C | C | C)

Substituting the given probabilities, we get:

P(CCCC | 0 received) = 0.9 * 0.9 * 0.9 * 0.9 = 0.6561

Similarly, we can calculate the probability of receiving a 0 in general as:

P(0 received) = P(CCCC | 0 received) x P(0) + P(IIII | 0 received) x P(1)

where P(IIII | 0 received) represents the probability that all four channels transmitted the digit incorrectly, given that a 0 was received. This probability can be calculated similarly as:

P(IIII | 0 received) = P(I) * P(I | I) x P(I | I | I) x P(I | I | I | I) = 0.1 x 0.1 x 0.1 x 0.1 = 0.0001

Substituting the given probabilities, we get:

P(0 received) = 0.6561 x 0.5 + 0.0001 x 0.5 = 0.3281

Finally, we can calculate the denominator P(CCCC) as:

P(CCCC) = P(CCCC | 0 received) x P(0) + P(CCCC | 1 received) x P(1)

where P(CCCC | 1 received) represents the probability that all four channels transmitted the digit correctly, given that a 1 was received. This probability can be calculated similarly as:

P(CCCC | 1 received) = P(I) x P(I | C) x P(I | C | C) x P(I | C | C | C) = 0.1 x 0.9 x 0.9 x 0.9 = 0.0729

Substituting the given probabilities, we get:

P(CCCC) = 0.6561 * 0.5 + 0.0729 * 0.5 = 0.3645

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Option A

your just multiplying the 2 to what's in parentheses

The magnitude of the resultant vector is 27 miles

Resultant vector = Distance of A - Distance of B

This is so because of the opposite direction of the car's movement

A = 87 miles

B = 114 miles

Resultant vector = 114 - 87

Resultant vector = 27 miles

Thus, the magnitude of the resultant vector is 27 miles

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There is only one child in the park who does not like to play either cricket or football or soccer.

Additionally, you should ignore any typos or irrelevant parts of the question .Here's how you can solve the given problem :Given that ,In a park, 25 children play every day in the evening.

12 children like to play cricket.8 children like to play football.4 children like to play soccer.Total children who like to play either of these three sports = \(12 + 8 + 4 = 24.\)

Therefore, the number of children who do not like to play any of these sports = Total number of children - Number of children who like to play any of these sports= \(25 - 24= 1\).

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Answer:48 dollars

32 divided by 8= 4 dollars each.

12 books multiply by 4 dollars a book to get 48 dollar.

Answer:

$48

Step-by-step explanation:

You take 32 divided by 8 and get 4. Now take that 4 times 12 and get 48. Which makes it so you get 12 books for $48 dollars.

Answer:

5.7, 6.9, 5, 7.1

Step-by-step explanation:

The absolute value of a number shows its distance from 0 on the number line, meaning it must always be positive since distance is positive. You have to perform the operations indicated on each expression to the left and match it to the correct value on the right. I got 5.7, 6.9, 5, 7.1 in order from top to bottom after adding and subtracting the numbers to the left.

Answer:

the first one on the left, goes to the third one on the right. the second one on the left goes to the first one on the right. the third one on the left goes to the fourth one on the right. the first one on the left goes to the second one on the right. Sorry if this is confusing :(

Answer:

-6

Step-by-step explanation:

Answer:

-4 + -2 = -6

Step-by-step explanation:

So this is a rhyme that helps me remember how to add and subtract positive and negative numbers...

(To the tune of Row Row Row Your Boat)

Same sign add and keep

Different sign subtract

Keep the sign of the bigger number

Then you'll be exact

I know it sounds silly but it helped me :)

The statement "NOT(MyAge > YourAge)" is true if MyAge is not greater than YourAge, which is not the case in this scenario because 30 is less than 40.

Therefore, option (a) is false.

The statement "MyAge >= YourAge" is also false because MyAge (30) is less than YourAge (40). Therefore, option (b) is also false.

Option (c) states that none of the above statements are true, which is also false because statement (a) is false.

Option (d) is irrelevant because it compares the values of MyAge and YourAge with string values, which is not the correct way to compare integers. Therefore, option (d) is also false.

The correct answer is (c) None of the above are a true statement.

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Answer: 725 as a decimal is 7.25

725 as a fraction is 725/1

725 as a percent is 7250%

Step-by-step explanation:

725 as a decimal is 7.25

725 as a fraction is 725/1

725 as a percent is 7250%

The vendor sold 172 sodas and 58 hotdogs at the hockey game.

An equation of degree one is known as a linear equation.

A linear equation of two variables can be represented by ax + by = c.

let, the number of soda cans be 'x' and the number of hot dogs be 'y'.

So, From the given information x = 3y and the vendor sold a total of 232.

Therefore, x + y = 232.

3y + y = 232.

4y = 232.

y = 232/4.

y = 58.

So, He sold 58 hot dogs and 3×58 = 172 soda cans.

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2(2x+7)-7(x+1)=28

4x+14-7x-7=28

4x-7x=28+7-14

-3x=28-7

-3x=21

pls mark mine as brainliest :D

x=-7

In conclusion: (a) The linear transformation f: M₂x₂ → R₃ given by f(a b; c d) = (b+d, a+b, d-a) is injective (one-to-one). (b) The linear transformation f is surjective (onto) if and only if every value of z can be expressed as the difference d - a for some real numbers d and a.

To determine whether the linear transformation f: M₂x₂ → R₃ is injective (one-to-one) and surjective (onto), we need to analyze its properties and conditions.

Let's define the linear transformation f as:

f(a b; c d) = (b+d, a+b, d-a)

(a) Injective (One-to-One):

A linear transformation f is injective if every distinct input vector in the domain corresponds to a distinct output vector in the codomain. In other words, if f(a₁ b₁; c₁ d₁) = f(a₂ b₂; c₂ d₂), then (a₁ b₁; c₁ d₁) = (a₂ b₂; c₂ d₂).

To test injectivity, we need to compare the outputs of f for two different input matrices and see if they are equal.

Let's assume two different input matrices: A₁ = (a₁ b₁; c₁ d₁) and A₂ = (a₂ b₂; c₂ d₂).

If f(A₁) = f(A₂), then we have:

(b₁+d₁, a₁+b₁, d₁-a₁) = (b₂+d₂, a₂+b₂, d₂-a₂)

Comparing the corresponding elements, we get the following system of equations:

b₁ + d₁ = b₂ + d₂ (1)

a₁ + b₁ = a₂ + b₂ (2)

d₁ - a₁ = d₂ - a₂ (3)

From equation (1), we can deduce that b₁ - b₂ = d₂ - d₁. Let's call this equation (4).

Similarly, equation (2) can be rewritten as a₁ - a₂ = b₂ - b₁. Let's call this equation (5).

Now, subtracting equation (3) from equation (4), we have:

(b₁ - b₂) - (d₁ - d₂) = (d₂ - d₁) - (a₂ - a₁)

(b₁ - b₂) - (d₁ - d₂) = (d₂ - d₁) - (b₂ - b₁)

Simplifying further, we get:

2(b₁ - b₂) = 2(d₂ - d₁)

b₁ - b₂ = d₂ - d₁

Using equation (5), we can substitute b₁ - b₂ = d₂ - d₁:

a₁ - a₂ = b₂ - b₁ = d₂ - d₁

This implies that a₁ = a₂, b₁ = b₂, and d₁ = d₂.

Therefore, we have shown that if f(A₁) = f(A₂), then A₁ = A₂. This confirms that f is an injective (one-to-one) linear transformation.

(b) Surjective (Onto):

A linear transformation f is surjective if every vector in the codomain has at least one corresponding input vector in the domain. In other words, for every vector (x, y, z) in the codomain R₃, there exists an input matrix A = (a b; c d) such that f(A) = (x, y, z).

To test surjectivity, we need to check if every vector (x, y, z) in R₃ can be expressed as f(A) for some matrix A = (a b; c d).

The codomain R₃ consists of 3-dimensional vectors, and the range of f is determined by the values of b, d, and the differences between b and d (b - d).

From the transformation equation f(a b; c d) = (b+d, a+b, d-a), we can observe that the third component z in R₃ is given by z = d - a. Therefore, any vector in R₃ can be expressed as f(A) if and only if z = d - a.

Since a and d are the diagonal elements of the input matrix A, we can conclude that for every vector (x, y, z) in R₃, there exists a matrix A = (a b; c d) such that f(A) = (x, y, z) if and only if z = d - a.

Therefore, f is surjective (onto) if and only if every value of z can be expressed as the difference d - a for some real numbers d and a.

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The number of red balls Luke has at the start is 47.

blue ball per day = 2

red ball per day = -3 ('-' ve sign as he is loosing them)

let the number of red balls be represented by r

let the number of blue balls be represented by b

after 5 days

b+ 10 = r -15 -(i)

After 9 days

b + 18 =2(r-27)-(ii)

subtracting (i) from (ii)

b + 18 - b - 10 = 2r - r - 54 +15

8 = r - 39

r = 39 + 8

r = 47

The number of red balls Luke has at the start is 47

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