a summer speeds up from 1.1m/s to 1.3m/s during the last 20 s of the workout. what is the acceleration during this interval?

i don't Know

Explanation:

learn from yourself.

Answer: The Earth is an oblate spheroid, meaning it is roughly spherical in shape but flattened at the poles and bulges at the equator. This shape has been scientifically proven through centuries of evidence and observations. While some people may claim that the Earth is flat, this idea is not supported by scientific evidence.

In decreasing order, the ranking is as follows:

What is displacement?

Displacement can simply be defined as the difference in the position of the two objects and is independent of the path taken when traveling between the two objects.

Displacement is a vector quantity that has both a direction and magnitude.

The displacement of a hiker with a constant acceleration is equal to the average velocity during a time interval multiplied by the time interval.

The reason is because the time intervals are equal, the displacements are in the same order as decreasing average velocities. So therefore, the average velocity decreases in the order CD, DE, EF, and FG.

In conclusion, displacement depends on two positions which is the initial position and the final position.

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Answer:

Explanation:

For refraction , the formula is

sin i / sin r = μ₂ / μ₁

where light is travelling from medium 1 to 2 having refractive index of μ₁ and μ₂ . Angle of incidence in medium 1 is i and angle of refraction in medium 2 is r .

Here i = 70°, r = 37°

μ₁ = 1.8 ,μ₂ = ?

sin70 / sin 37 = μ₂ / 1.8

.939 / .602 = μ₂ / 1.8

1.56 =  μ₂ / 1.8

μ₂ = 2.81 .

The value of refraction index for the second medium will be  \(\mu_2=2.16\)

Every material has a different refractive index. The refracted index of any material shows that the light is refracted by how much angle.

So like for water its value will be different also for glass its value will be different.

Now it is given in the question that

Angle of incidence \(i=70^o\)

Refractive index of the first medium \(\mu_1=1.8\)

Angle of refraction \(r=37^o\)

Now from snells law

\(\dfrac{Sin \ i}{Sin \ r} = \dfrac{\mu_2}{\mu_1}\)

\(\dfrac{Sin70}{Sin37} = \dfrac{\mu_2}{1.8}\)

\(\mu_2= \dfrac{Sin70\times1.8}{Sin37}\)

\(\mu_2=2.16\)

Thus the value of the refraction index for the second medium will be  \(\mu_2=2.16\)

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Answer:

r=2√2rp

Explanation:

khan

To find the tangential and normal components of acceleration, we need to differentiate the given position vector twice with respect to time (t) to obtain the acceleration vector.

Then, we can decompose the acceleration vector into its tangential and normal components.

Given position vector: \(r(t) = t^2i + (t^2 - 1)j + 2t^2k\)

First, let's differentiate the position vector with respect to time to find the velocity vector:

\(v(t) = dr(t)/dt = 2ti + (2t)j + 4tk\)

Now, let's differentiate the velocity vector with respect to time to find the acceleration vector:

\(a(t) = dv(t)/dt = d^2r(t)/dt^2 = d^2r(t)/dt^2 = 2i + 2j + 4k\)

The acceleration vector is a(t) = 2i + 2j + 4k.

Now, let's decompose the acceleration vector into its tangential and normal components.

The tangential component of acceleration (a_T) is the component of acceleration parallel to the velocity vector. It can be calculated by taking the dot product of the acceleration vector (a) and the unit vector in the direction of the velocity vector (v/|v|):

\(a_T\) = (a · v/|v|) * (v/|v|)

To find the unit vector in the direction of v, we divide the velocity vector (v) by its magnitude:

v = 2ti + 2tj + 4tk

\(|v| = sqrt((2t)^2 + (2t)^2 + (4t)^2) = sqrt(4t^2 + 4t^2 + 16t^2) = sqrt(24t^2) = 2sqrt(6)t\)

v/|v| = (2ti + 2tj + 4tk) / (2sqrt(6)t) = (i + j + 2k) / sqrt(6)

Now, let's calculate the dot product of a and v/|v|:

a · v/|v| = (2i + 2j + 4k) · (i + j + 2k) / sqrt(6)

          = 2 + 2 + 8 / sqrt(6)

          = 12 / sqrt(6)

          = 2sqrt(6)

Finally, we can calculate the tangential component of acceleration (a_T):

\(a_T\)= (a · v/|v|) * (v/|v|)

   = (2sqrt(6)) * ((i + j + 2k) / sqrt(6))

   = 2(i + j + 2k)

Therefore, the tangential component of acceleration \((a_T)\) is 2(i + j + 2k).

The normal component of acceleration (a_N) is the component of acceleration perpendicular to the velocity vector. It can be calculated by subtracting the tangential component of acceleration from the total acceleration vector:

\(a_N = a - a_T\)

   = (2i + 2j + 4k) - 2(i + j + 2k)

   = 2i + 2j + 4k - 2i - 2j - 4k

   = 0i + 0j + 0k

   = 0

Therefore, the normal component of acceleration \((a_N)\) is 0.

In summary, at any time t > 0, the tangential component of acceleration \((a_T)\) is 2(i + j + 2k), and the normal component of acceleration \((a_N)\) is 0.

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Answer: 480 N is required to maintain the arrangement .

Explanation:

Given, 320 N  force is required to hold 2 protons in a particular arrangement .

Then the force required to keep 1 proton in a particular arrangement = 320/2

= 160 N

Then if  a proton is replaced by an alpha particle , it is given that a alpha contains 2 protons , then we conclude that after replcament , the arrangement has 1 alpha and 1 proton = 3 protons

Then , the force exerted by 3 protons = 3×160 = 480 N

The force exerted by the arrangement , if one of the protons is replaced with alpha is 480 N

The oscillating frequency of the LC circuit with a capacitor of 2 Farads and an inductor of 2 Henrys is approximately 0.03979 Hertz or 39.79 millihertz.

the oscillating frequency of an LC circuit can be calculated using the formula:

f = 1 / (2π√(LC))

where f is the frequency in hertz (Hz), L is the inductance in henries (H), and C is the capacitance in farads (F).

Given that the capacitor has a capacitance of 2 Farads (F) and the inductor has an inductance of 2 Henrys (H), we can substitute these values into the formula:

f = 1 / (2π√(2 H * 2 F))

Simplifying further:

f = 1 / (2π√(4 H*F))

f = 1 / (2π * 2 H*F)

f = 1 / (4π H*F)

Using the approximation of π as 3.14159:

f ≈ 1 / (4 * 3.14159 * 2 H * 2 F)

f ≈ 1 / (25.13272 H*F)

f ≈ 0.03979 H*F

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Answer:

The point at which the electrical potential is zero is x = +0.33 m.

Explanation:

By definition the electrical potential is:

\( V_{E} = \frac{K*q}{r} \)

Where:

K: is Coulomb's constant = 9x10⁹ N*m²/C²

q: is the charge

r: is the distance

The point at which the electrical potential is zero can be calculated as follows:

\( V_{1} + V_{2} = 0 \)

\( K(\frac{q_{1}}{r_{1}} + \frac{q_{2}}{r_{2}}) = 0 \)    (1)

q₁ is the first charge = +3 mC

r₁ is the distance from the point to the first charge  

q₂ is the first charge = -6 mC

r₂ is the distance from the point to the second charge    

By replacing r₁ = 1 - r₂ into equation (1) we have:

\(K(\frac{q_{1}}{1 - r_{2}} + \frac{q_{2}}{r_{2}}) = 0\)   (2)

By solving equation (2) for r₂:

\(r_{2} = \frac{q_{1}}{q_{1} - q_{2}} = \frac{3 mC}{3 mC - (-6 mC)} = +0.33 m\)

Therefore, the point at which the electrical potential is zero is x = +0.33 m.

I hope it helps you!  

Since the two charges are placed on the x-axis. Then, the electric potential is zero at the distance of 0.66 m from the second point charge on the x-axis.

The electric potential at any point is the amount of work needed to move a unit positive charge from infinity to that point.

Given data-

The magnitude of a point charge is, Q = + 3 C.

The magnitude of the second point charge is, Q' = -6 C.

The distance between the two charges is, x = 1.0 m.

The expression for the net electric potential due to both the charges is,

\(V = \dfrac{k \times Q}{x} +\dfrac{k \times Q'}{x-y}\)

here,

k is the Coulomb's constant.

y is the distance from the second point charge on the x-axis, where the net potential is zero.

Now, for zero net electric potential due to both the charges we have,

\(0 = \dfrac{k \times Q}{x-y} +\dfrac{k \times Q'}{y}\\\\\\-\dfrac{k \times Q'}{y}=\dfrac{k \times Q}{x-y}\)

Solving as,

\(-\dfrac{(-6)}{y}=\dfrac{3}{1-y}\\\\6-6y=3y\\\\y =0.66\;\rm m\)

Thus, we can conclude that the electric potential is zero at the distance of 0.66 m from the second point charge on the x-axis.

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Answer:

water pushes against the squid

According to the law of reflection, the light from the item cannot bounce off the mirror and reach his eye across his line of sight.

According to the law of reflection, the light from the item cannot bounce off the mirror and reach his eye across his line of sight. Ray is unable to see the object's reflection in the mirror because the object's light does not reach his eye.

The law of reflection, the angle of the reflected beam is equal to the angle of the incident ray while reflecting from a smooth surface. (In geometrical optics, all angles are usually measured in relation to the surface normal, or a line perpendicular to the surface.

In physics, the rule of reflection is used to locate an image that is reflected in a mirror. One effect of a law is that if you can see someone's eyes through a mirror (or the eyes of another species), you can assume that he may see your eyes as well because of how reflection function.

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Answer:

1. e

2. f

3. b

4. g

5. a

6. c

7. d

8. j

9. k

10. i

The points of Column A with Column B related to unit measurement, temperature and energy are matched with their appropriate option.

\(1-2-3-4-5-6-7-8-9-10\\ e-f-b-g-a-c-d-j-k-l\)

Energy is the capacity of a object to do a work. More the energy object posses, more the work it can do.

The main categories of energy

Let's match the point of Column A with Column B.

Thus, the points of Column A with Column B related to unit measurement, temperature and energy are matched with their appropriate option.

\(1-2-3-4-5-6-7-8-9-10\\ e-f-b-g-a-c-d-j-k-l\)

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Answer:

\(potential \: energy = mgh \\ m = 783 \\ g = 10 \\ h = 164 \\ pe = 783 \times 10 \times 164 \\ = 7830 \times 164 \\ = 1284120 \: joule \\ thank \: you\)

Explanation:

\( \sf \: Mass \: of \: the \: body: 783\: kg\)

\( \sf \: Acceleration \: due \: to \: gravity : 10\)

\( \sf \: Height : 164 \: metres\)

\(\sf\longmapsto \: 783 \times 10 \times 164\)

\(\sf\longmapsto 7830 \times 164\)

\(\sf\longmapsto 1284120\: \)

\(\sf\longmapsto 1284120 \:Joule\: \)

Answer:

The object accelerates downward at 4 m/s² since the tension on the rope is less than weight of the object.

Explanation:

Given;

mass of the object, m = 2 kg

weigh of the object, W = 20 N

tension on the rope, T = 12 N

The acceleration of the object is calculated by applying Newton's second law of motion as follows;

T = F + W

T = ma + W

ma = T - W

\(a = \frac{T-W}{m} \\\\a = \frac{12 - 20}{2} \\\\a = -4 \ m/s^2\) (the negative sign indicates deceleration of the object)

The object accelerates downward at 4 m/s² since the tension on the rope is less than weight of the object.

Here's the neat, cool way to convert units like this:

-- 1 kilogram  =  1,000 grams

-- 1 meter  =  100 centimeters

So . . . . .

(1000 kg/m³) x (1000 g/kg) x (1 m/100 cm)³ =

(1,000 kg/m³) x (1,000 g/kg) x (1 m³/1,000,000 cm³) =

(1,000 x 1,000 x 1 / 1,000,000) (kg-g-m³ / m³-kg-cm³)  =  1 g/cm³

Answer:

7...is mitochondria :- mitochondria are known as the power house of the cell.

Answer:

1) cell wall

you know cell wall is a made up cellulose

it's present in plant cell

it surface are very hard

it protects high temperature, moisture of air, pressure of air etc

Answer:

67%

Explanation:

In the absence of external forces, the total momentum of the system before the collision is equal to the total momentum after the collision. Since the second ball is initially at rest, the total momentum before the collision is simply m*v.

After the collision, the two balls stick together and move with a common velocity, which can be calculated using conservation of momentum:

m*v + 0 = (m+2m) * v_final

Solving for v_final, we get:

v_final = v/3

The initial kinetic energy of the system is:

K_i = 0.5mv^2

The final kinetic energy of the system is:

K_f = 0.5*(3m)v_final^2 = 0.5(3m)(v^2/9) = 0.5m*v^2/3

The fraction of the initial kinetic energy lost on impact is:

( K_i - K_f ) / K_i = ( 1 - 1/3 ) = 2/3 = 0.67

Therefore, 67% of the initial kinetic energy is lost on impact.

Given:

The length of the pipe is L.

The third harmonic has teh wavelength,

To find:

The type of the pipe

Explanation:

The wavelength of the harmonics for a pipe closed at one end is,

The wavelength of the harmonics for a pipe open at both the ends is,

Here,

The given wavelength is,

which resembles the form,

Hence, the pipe is open at the other end.

The kinetic energy of the bat which strikes the ball with the force of 2 x 10⁴ N is a) 1.0 x 10² J

The force at which the bat strikes the ball = 2 x 10⁴ N

The distance traveled by the ball = 5 x 10⁻³ m

The work done by the bat is the kinetic energy of the bat. Thus, the formula to find the kinetic energy of the bat is

                    K.E = F x d

where K.E is the kinetic energy of the bat

              F is the force of the bat

              d is the distance traveled by the ball.

Let us substitute the known values in the above equation, we get

                   K.E = 2 x 10⁴ x 5 x 10⁻³

                         = 10 x 10

                         = 1.0 x 10² J

Therefore, the kinetic energy of the bat is 1.0 x 10² J

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Answer:

15 units NE

Explanation:

Assuming the coordinate plane is a compass with N being the positive y-axis, we can use the Pythagorean theorem to find the magnitude of the vector. Since the vector is going up by 12 and right by 9 at the same time, it should form a diagonal line, aka the hypotenuse of a triangle. This triangle has both of its leg units as 12, and 9. Pythagorean theorem states that a^2 + b^2 = c^2, that is both of their legs squared is the hypotenuse of the triangle squared. 12^2 + 9^2 = c^2. c = 15. Now that we know the magnitude, let's go back to the quadrants as the compass. Since both units are positive, the vector goes in the positive direction on both sides, which is Quadrant 1. North and East would be the appropriate say for the vector's direction, thus the vector's direction will be 15 units North East.

Explanation:

The potential energy of an object has the following formula

         Potential energy = mgh

      where m = mass of the object

                   g = acceleration due to gravity

                   h = height of the object

This means that the potential energy of an object depends upon its mass, acceleration due to gravity, and height.

In the given situation we have a bucket full of water. If the mass and acceleration due to gravity are not changed, the only way the potential energy can be decreased is by reducing the height of the bucket full of water.

This can be done by: -

         (i) Lifting the bucket full of water in such a way that you

             decrease its height as compared to the bench.

        (ii) Put the bucket full of water on a stool whose height is

            lower than the bench.

Answer:

1.By decreasing it's contents- this decreases the weight of the bucket thus decreasing the potential energy of the bucket.

2.By decreasing the height of the bench we have decreased the amount of potential energy stored in the bucket

Answer: False

Explanation: The size of the observable cosmos has changed during the past few billion years. Since the Big Bang, which is thought to have happened approximately 13.8 billion years ago, the observable universe has been expanding. This indicates that the observable universe has been expanding together with the distance between galaxies. The cosmos has seen phases of acceleration and slowdown in its expansion, however the rate of expansion has not always been constant. The observable universe is therefore bigger than it was a few billion years ago.

Answer:

340 kg/m³

Explanation:

\(Relative density \: = \frac{density \: ofsubstance}{density \: of \: equal \: volume \: ofwater} \)

density of water = 1000 kg/m³

density of the liquid = 0.34 × 1000

= 340 kg/m³

The mass of an object that experiences a gravitational force of 685 N near earth's surface where g = 9.80 m/s² is 98.89 kg.

Any two mass-containing objects are attracted to one another by the gravitational force. Because it consistently attempts to pull masses together rather than pushing them apart, the gravitational force is known as attractive.

In reality, everything in the cosmos is tugging on everything else, including you!

According to the question,

The gravitational force of 685 N near earth's surface.

The acceleration due to gravity is  g = 9.80 m/s².

The formula for force acting of the body under the influence of gravitation is ;

Force = mass×acceleration

Substitute the given values;

685 = m×9.8

m = 685/9.8

m = 69.89 kg.

Therefore, mass of an object is 69.89 kg.

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The light travels through water and gets reflected off on the glass surface into the water. There had been a 180° phase change between the incident and the reflected wave. This is called Total internal reflection(TIR).

In total internal reflection, in physics, a ray of light in a medium such as water or glass is completely reflected back into the medium from the surrounding surfaces. This phenomenon occurs when the angle of incidence is greater than a certain critical angle called the critical angle. TIR only occurs when both of the following two conditions are met

Light is in a denser medium and is approaching a less dense medium.

The angle of incidence should be greater than the so-called critical angle.

Thus the phases of incident and reflected light are compared according to the the phenomenon called total internal reflection (TIR).

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Summary: The normal force at point C is 2 kN, the shear force is -10 kN (downward), and the moment is -12 kNm (clockwise).

In the given figure, the beam is subjected to a uniformly distributed load (w) of 10 kN/m and a point load (P) of 12 kN. To determine the normal force, shear force, and moment at point C, we consider equilibrium conditions.

First, let's calculate the normal force. At point C, there are no vertical loads acting, so the normal force is equal to zero.

Next, let's calculate the shear force at point C. Moving from left to right along the beam, the shear force will change due to the uniformly distributed load and the point load. At point C, the shear force is equal to the negative of the area under the uniformly distributed load curve between point B and point C. Hence, the shear force at point C is -10 kN (downward).

Finally, let's calculate the moment at point C. The moment at point C is the sum of the moments due to the distributed load and the point load. The moment caused by the distributed load can be calculated by taking the area under the load curve between point B and point C and multiplying it by the distance from point C. The moment caused by the point load P can be calculated by multiplying the point load by the distance from point C. Summing these two moments, we get a moment of -12 kNm (clockwise) at point C.

In conclusion, the normal force at point C is 2 kN, the shear force is -10 kN (downward), and the moment is -12 kNm (clockwise), following the sign convention.

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Answer:

part a)100 cm

Explanation:

i just did that as a lab

The net force of Alex is greater than net force of Sam.

The given parameters:

F = ma

The net force on each person is calculated as follows;

F = ma + mg

F = m(a + g)

Where;

a is acceleration

Acceleration is directly proportional to velocity

Thus, the person with greater speed will have greater net force.

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Answer:

1)  10 kg-m/s

2)  2 kg

3)  20 m/s

Explanation:

The momentum of an object can be calculated using the equation:

\(\large\boxed{p=mv}\)

where:

\(\hrulefill\)

For this question we need to find the momentum of a bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s.

Given values:

Substitute the given values into the momentum formula and solve for p:

\(p=4.0\;\text{kg} \cdot 2.5\;\text{m/s}\)

\(p=10\;\text{kg m/s}\)

Therefore, the momentum of the bowling ball is 10 kg-m/s.

\(\hrulefill\)

For this question we need to find the mass of a skateboard rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s.

Given values:

As we want to find mass, rearrange the momentum formula to isolate m:

\(\large\boxed{m=\dfrac{p}{v}}\)

Substitute the given values into the formula and solve for m:

\(m=\dfrac{6.0\; \text{kg m/s}}{3.0\; \text{m/s}}\)

\(m=2\;\text{kg}\)

Therefore, the mass of the skateboard is 2 kg.

\(\hrulefill\)

For this question we need to find the velocity of a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s.

Given values:

As we want to find velocity, rearrange the momentum formula to isolate v:

\(\large\boxed{v=\dfrac{p}{m}}\)

Substitute the given values into the formula and solve for v:

\(v=\dfrac{10\; \text{kg m/s}}{0.5\; \text{kg}}\)

\(v=20\;\text{m/s}\)

Therefore, the velocity of the baseball is 20 m/s.