a star of apparent magnitude 1 appears a star of apparent magnitude 1 appears either brighter or fainter than a star of apparent magnitude 2, depending on the distance to the stars. brighter than a star of apparent magnitude 2. fainter than a star of apparent magnitude 2. farther away than a star of apparent magnitude 2.

Answer:

V = 50 volts

Explanation:

Given that,

Resistance, R = 10 ohms

Current, I = 5 A

We need to find the potential difference across the circuit. We know that,

V = IR

Put all the values,

V = 5 × 10

V = 50 volts

Hence, the potential difference is equal to 50 volts.

Answer:

8 meters

Explanation:

40/ 5 = 8

The wavelength of an electron moving at 3.94 x 10^7 m/s is 1.67 × 10^-10 m.

The de Broglie wavelength formula is λ = h / mv where λ is the wavelength of the particle, h is Planck's constant, m is the mass of the particle, and v is its velocity.

To calculate the wavelength of an electron moving at 3.94 x 10^7 m/s, we need to know the mass of the electron and Planck's constant. The mass of an electron is 9.10938356 × 10^-31 kilograms. Planck's constant is 6.62607015 × 10^-34 Joule seconds. Using these values, we can calculate the wavelength of an electron moving at 3.94 x 10^7 m/s as follows:λ = h / mvλ = 6.62607015 × 10^-34 J.s / (9.10938356 × 10^-31 kg) × (3.94 × 10^7 m/s)λ = 1.67 × 10^-10 m

Therefore, the wavelength of an electron moving at 3.94 x 10^7 m/s is 1.67 × 10^-10 m.

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With a temperature change of 31°C, the mercury column's height changes by 0.0106 cm.

As the temperature rises, the mercury will expand in the capillary tube, increasing its volume. V = VT = (1.8*10-4 (oC)-1)(0.100 cm3)(20 oC) = 3.6*10-4 cm3 = 0.36 mm3, or the formula V = VT.

\(A1 * h1 = A2 * h2\)

\(A1 = πr1^2 = π(0.005 cm/2)^2 = 7.85 × 10^-5 cm^2\)

The cross-sectional area of the bulb is:

\(A2 = πr2^2 = π(0.31 cm/2)^2 = 0.0755 cm^2\)

\(ΔV = V0 * β * ΔT\)

\(V0 = A1 * h1\)

\(h2 = (A1/A2) * h1 + (ΔV/A2)\)

\(h2 = (7.85 × 10^-5 cm^2)/(0.0755 cm^2) * h1 + (0.000182 (°C)^-1 * 31°C *\) 7.85 × \(10^-5 cm^2)/(0.0755 cm^2)\)

\(h2 = 0.0106 h1 + 0.00000122 cm\)

\(Δh = h2 - h1 = 0.0106 h1 + 0.00000122 cm - h1 = 0.0106 cm\)

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Answer:

Correct options are C. As food is digested, molecule bonds are broken, allowing new molecules to form that can be used by our bodies.

D. Energy stored in organic fuels are used for heat and electricity/ When batteries are connected to a circuit, a reaction occurs inside the cell producing electrical energy.

Explanation:

The breakdown of food leads to the release of chemical energy which was first stored in food. This energy is used to drive necessary functions of the body. A series of chemical reactions are involved in the breakdown of food and changing them into useful components for the cell.

Chemical energy is stored in circuits. When the battery is connected to a circuit, the chemical energy gets transferred into electrical energy.

Answer:

change, combine

Answer:the specific heat is the measure of how much heat per unfit mass required to raise the temperature by 1 degrees Celsius.the formula is given as Q= cm T where

Q= the amount of heat added

C= specific heat of a substance

T= change in temperature in degrees Celsius

Q=(4186 j/kg degrees Celsius (.109 kg) (8.93- degrees Celsius)=4974.53J

Explanation:

The mass of the copper coin placed in 101g of water is 135.3g.

The mass of the copper coin can be calculated using the following expression:

Since; Q = mc∆T

Where;

mc∆T (water) = mc∆T (copper)

According to this question;

COPPER METAL:

WATER:

101 × 4.18 × 8.39 = (0.385 × m × 68)

3542.09 = 26.18m

m = 3542.09 ÷ 26.18

m = 135.3g

Therefore, the mass of the copper coin placed in 101g of water is 135.3g.

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Answer:

The answer is Muscular endurance

Explanation:

It is this because your seeing how long your muscles can with stand. I answered by guessing lol.

Answer:

The magnification produced by a plane mirror is +1

means then the size of the image is equal to the size of the object. If m has a magnitude greater than 1 the image is larger than the object, and an m with a magnitude less than 1 means the image is smaller than the object.

Scenario 1:

a. The operating frequency of the system before the switch (load 2) is closed is approximately 50.2 Hz.

b. The operating frequency of the system after the switch (load 2) is closed remains approximately 50.2 Hz.

c. Increase the mechanical input power to the generator and Decrease the loads

Scenario 2:

a. The operating frequency of the system before the switch (load 2) is closed is approximately 50.2 Hz.

b. The operating frequency of the system after the switch (load 2) is closed remains approximately 50.2 Hz.

c. Increase the mechanical input power to the generator and Decrease the loads.

Scenario 1: Generator directly connected to the loads

a. To find the operating frequency of the system before the switch (load 2) is closed, we need to consider the power balance equation:

Total power supplied by the generator = Power consumed by Load 1 + Power consumed by Load 2

The total power supplied by the generator can be calculated using the formula:

Total power = No-load frequency (f0) * Slope (Sp)

Total power = 51.0 Hz * Y MW/Hz = 51Y MW

The power consumed by Load 1 can be calculated using the formula:

Power consumed by Load 1 = Load 1 (Y MW) * Power factor (0.8 lagging)

Power consumed by Load 1 = Y MW * 0.8 = 0.8Y MW

To find the power consumed by Load 2, we'll convert it to apparent power since we're given the power factor in terms of lagging.

Apparent power consumed by Load 2 = Load 2 (0.8 MVA) * Power factor (0.8 lagging)

Apparent power consumed by Load 2 = 0.8 MVA * 0.8 = 0.64 MVA

To convert the apparent power to real power, we'll use the formula:

Real power consumed by Load 2 = Apparent power * Power factor

Real power consumed by Load 2 = 0.64 MVA * 0.8 = 0.512 MW

Now, we can set up the power balance equation:

51Y MW = 0.8Y MW + 0.512 MW

Simplifying the equation:

50.2Y MW = 0.512 MW

Y ≈ 0.0102 MW

Therefore, the operating frequency of the system before the switch (load 2) is closed is approximately 50.2 Hz.

b. After the switch (load 2) is closed, the total power consumed by the system will increase to Y MW + 0.512 MW.

The new power balance equation will be:

51Y MW = 0.8Y MW + 0.512 MW

Simplifying the equation:

50.2Y MW = 0.512 MW

Y ≈ 0.0102 MW

The operating frequency of the system after the switch (load 2) is closed remains approximately 50.2 Hz.

c. To restore the system frequency to 50 Hz after both loads are connected to the generator, the operator can take the following action:

1. Increase the mechanical input power to the generator: By increasing the mechanical input power, the generator will produce more electrical power and help restore the system frequency to 50 Hz.

2. Decrease the loads: If the loads can be reduced, the total power consumed by the system will decrease, which will help bring the frequency back to 50 Hz.

Scenario 2: Generator connected to the loads through a transformer

a. Before the switch (load 2) is closed, the operating frequency of the system can be calculated using the same power balance equation as in Scenario 1:

Total power = No-load frequency (f0) * Slope (Sp)

Total power = 51.0 Hz * Y MW/Hz = 51Y MW

Power consumed by Load 1 = Y MW * 0.8 = 0.8Y MW

Real power consumed by Load 2 = 0.8 MVA * 0.8 = 0.64 MVA *

0.8 = 0.512 MW

Setting up the power balance equation:

51Y MW = 0.8Y MW + 0.512 MW

Simplifying the equation:

50.2Y MW = 0.512 MW

Y ≈ 0.0102 MW

Therefore, the operating frequency of the system before the switch (load 2) is closed is approximately 50.2 Hz.

b. After the switch (load 2) is closed, the total power consumed by the system will increase to Y MW + 0.512 MW.

The new power balance equation will be:

51Y MW = 0.8Y MW + 0.512 MW

Simplifying the equation:

50.2Y MW = 0.512 MW

Y ≈ 0.0102 MW

The operating frequency of the system after the switch (load 2) is closed remains approximately 50.2 Hz.

c. To restore the system frequency to 50 Hz after both loads are connected to the generator, the operator can take the same actions mentioned in Scenario 1:

1. Increase the mechanical input power to the generator.

2. Decrease the loads.

These actions will help bring the frequency back to the desired 50 Hz.

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The tension does no (zero) work

F· S = W

Since the tension is perpendicular to the direction of motion, and there is no change in S the work done is zero.

The pressure tendency would likely be growing if "good" weather was on the horizon.

The forecast calls for fair to good weather when the pressure tendency is rising. It is common to expect stormy or inclement weather while the pressure tendency is declining. Clouds and precipitation are linked to low pressure systems because warm air (which holds a lot of water vapour) rises because it is denser than the air above.

High-pressure regions are linked to calmer winds and sunny sky, while low-pressure regions are frequently connected with unfavourable weather (such as gloomy, windy, with potential for rain or storms).

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Answer:

The best explanation is that the first person is grounded to the earth, and his/her body either draws up negative charges from the earth, or tend to conducts negative charges to the earth, depending on the charge on the balloon.

Explanation:

The earth is an infinite store for charges. In the first case where the second person brings a negatively charged balloon towards the first person, the negative charges on the balloon induces the first person's body to tend to attract the negative charges on the balloon through the first person's body to the positive charges within the earth. In the second case when again a positively charged balloon is brought near the first person's hair, the positive charges on the balloon induce the first person's body into drawing up negative charges from within the earth. This charges, and their opposite induced charges, create an attractive force between the hair strands and the balloons.

Answer:

multiply them together and get ur answer

Explanation:

Since the force is perpendicular to the displacement of the ball, the total work done by the force is 50 Nm.

Given the following data:

To find the total work done by the force:

The work done by an object is the product of the perpendicular force acting on the object and the distance it covers.

Mathematically, work done is given by the formula:

\(Work\;done = Force\) × \(distance\)

Substituting the given parameters into the formula, we have;

\(Work\;done = 10\) × \(5\)

Work done = 50 Nm.

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Answer:

the advantage gained by the use of a mechanism in transmitting force specifically : the ratio of the force that performs the useful work of a machine to the force that is applied to the machine.

Explanation:

Mechanical advantage is a measure of the force amplification achieved by using a tool, mechanical device or machine system. The device trades off input forces against movement to obtain a desired amplification in the output force. The model for this is the law of the lever.

A proton with kinetic energy T=10 MeV flies past a stationary free electron at a distance b=10 pm. The energy acquired by the electron is 286 eV, assuming the proton's trajectory to be rectilinear and the electron to be practically motionless as the proton flies by.

To find the energy acquired by the electron, we can use the concept of Coulomb scattering. In this process, the proton and the electron interact via the electrostatic force, which transfers energy from the proton to the electron.

The maximum energy transferred to the electron (ΔE) can be found using the following formula:

ΔE = (2 * k * q1 * q2) / b

where k is the Coulomb constant (approximately 8.99 × 10^9 N m^2 C^−2), q1 and q2 are the charges of the proton and electron (1.6 × 10^-19 C each), and b is the impact parameter (10 pm or 10 × 10^-12 m).

Plugging the values into the formula, we get:

ΔE = (2 * 8.99 × 10^9 N m^2 C^−2 * (1.6 × 10^-19 C)^2) / (10 × 10^-12 m)

ΔE ≈ 4.58 × 10^-17 J

Now, to convert the energy into electron volts (eV), we can use the following conversion:

1 eV = 1.6 × 10^-19 J

ΔE ≈ (4.58 × 10^-17 J) / (1.6 × 10^-19 J/eV) ≈ 286 eV

So, the energy acquired by the electron is approximately 286 eV. This value is much smaller than the initial kinetic energy of the proton (10 MeV), confirming the assumption that the electron is practically motionless as the proton flies by.

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Answer:

Simply put: the grounding wire is a way of electrical protection. Its function is to quickly connect the current to the earth through the grounding wire when your electrical equipment is leaking or inductively charged, so that the equipment shell is no longer charged, thereby ensuring the safety of the equipment behind the personnel.

Explanation:

For example, due to poor insulation performance of household appliances or humid environment, the shell will be charged with static electricity, and electric shock accidents may occur in serious cases. In order to avoid accidents, a wire can be connected to the metal shell of the electrical appliance, and the other end of the wire can be connected to the ground. Once the electrical leakage occurs, the grounding wire will bring static electricity into the ground and release it. In addition, it is more important for electrical maintenance personnel to use electric soldering irons to solder circuits, sometimes because the electric soldering irons are charged and break down and damage the integrated circuits in the electrical appliances. Friends who use computers sometimes ignore the grounding of the mainframe. In fact, connecting a ground wire to the mainframe of the computer can prevent the occurrence of crashes to a certain extent.

i hope it help you out ο(=•ω＜=)ρ⌒☆

Answer:

What is most widely accepted today is a the giant-impact theory. It proposes that the Moon formed during a collision between the Earth and another small planet, about the size of Mars. The debris from this impact collected in an orbit around Earth to form the Moon.

For the same amount of heat added, the change in entropy will be the same regardless of the initial conditions in an isothermal process. The change in entropy will be the same regardless of the initial conditions in case of isobaric process. For isochoric process, the change in entropy will be the same regardless of the initial conditions.

1, In an isothermal process, the temperature of the gas remains constant.

So, the change in entropy (ΔS) for an isothermal process can be calculated as below,

ΔS = Q / T, where Q is the heat added to the system and T is the temperature in Kelvin.

2, In an isobaric process, the pressure of the gas remains constant. The change in entropy (ΔS) for an isobaric process can be calculated as,  ΔS = Q / T, here Q is the heat added to the system and T is the temperature in Kelvin.

3, Isochoric Process: In an isochoric process, the volume of the gas remains constant.

The change in entropy (ΔS) for an isochoric process can be calculated using the formula:

ΔS = Q / T, where Q is the heat added to the system and T is the temperature in Kelvin.

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The freezing method works by exploiting the difference in freezing points between engine oil and water. However, its effectiveness may vary depending on the properties and composition of the mixture.

The freezing method for separating engine oil from water is based on the difference in freezing points between the two substances. Water has a higher freezing point than most engine oils, which means that when a mixture of oil and water is cooled to a temperature below the freezing point of water, the water will freeze while the oil remains in liquid form.

To use this method, the mixture is first placed in a container and then put in a freezer or other cooling device. As the temperature drops, the water in the mixture will begin to freeze, forming ice crystals. These can then be removed by either skimming them off the surface or pouring off the liquid oil, which should be separated from the frozen water.

It's worth noting that this method is not always effective, as some engine oils may have a higher freezing point than water, making it difficult to separate them using this technique. Additionally, it may not be suitable for larger quantities of oil and water or for more complex mixtures containing other substances.

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Answer:

\( \infty \infty \)

Answer:

Distance

Explanation:

Because each path you take will have a different distance. Each path will be different, leading to a different distance. Hope this helped :D

Yes, the sound wave with a frequency of 540 Hz will diffract while passing through an opening of 80 cm.

This is because the diffraction of a wave is directly proportional to the wavelength of the wave and inversely proportional to the size of the opening. As the wavelength of a sound wave with a frequency of 540 Hz is approximately 0.63 meters, which is much larger than the size of the opening, it will diffract around the edges of the opening.
Hi! A sound wave with a frequency of 540 Hz will indeed diffract while passing through an opening of 80 cm. The extent of diffraction depends on the wavelength of the sound wave and the size of the opening. In this case, the wavelength is longer compared to the size of the opening, which allows for significant diffraction to occur.

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Answer:

Stars become the main sequence as they move through a galaxy. During this stage, it will fuse hydrogen atoms and form helium molecules in its core for 90 percent of its life. We are currently in the main sequence of our sun's life cycle.

Explanation:

Answer:

D I'm pretty sure :)

Explanation:

hope this helps

Answer:

vmbjjbhvmnbchkbchkjfmbbfkjmhcmnbfnmcbim ghjmbgi

Answer:

Explanation:

a.

b.Rtđ= R1.R2/R1+R2= 6 ôm

U=U1 = I1.R1= 0,5.15= 7,5 V

c.

1/Rtđ'= 1/R1+1/R2+1/R3= 7/30

=> Rtđ' = 4,29 ôm

I= U/Rtđ' = 7,5/4,29= 1,75 A

The upward force the water will exert on the duct is 3.463kN.

Here we have to find the buoyancy force:

Buoyancy force:

The buoyant force is the upward force exerted on an object wholly or partly immersed in a fluid. This upward force is also called Upthrust. Due to the buoyant force, a body submerged partially or fully in a fluid appears to lose its weight, i.e. appears to be lighter.

Formula to calculate buoyancy forces:

B = ρgV

ρ= fluid density

g = acceleration due to gravity

V = fluid volume

V = πr²L

So;

B = ρgπr²L

Given data:

g = 9.8 m/s²

r = 15 cm = 0.15m

L = 20m

ρ = 1000

B = 1000× 9.8 × 22/7 ( 0.15/2)² × 20

  = 3.465kN

Therefore the upward force is 3.465kN.

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Answer:

B. speed

Explanation:

im not sure hahahaha

Answer:

This question is incomplete, the options are:

A) The object absorbs most white light and refracts most green light.

B) The object refracts most white light and absorbs most green light.

C) More green light is absorbed while more red and blue light is reflected.

D) More green light is reflected while more red and blue light is absorbed.

The answer is D.

Explanation:

Light is an electromagnetic wave that contains different colours at different wavelength. The colour of light that is seen depends on the wavelength of light that is REFLECTED, while other wavelengths of light are ABSORBED. This feature is dependent on the properties of each object that received the sunlight.

For example, an object will appear GREEN because it has properties that enables it to REFLECT most of the GREEN LIGHT but absorbs most of the RED AND BLUE LIGHT in the sunlight passing through the object.

Answer:

D

Explanation:

More green light is reflected while more red and blue light is absorbed.

Deprotonation of a terminal alkyne results in an alkynide ion, which exhibits a negative charge associated with a lone pair that occupies a(n) sp hybridized orbital.

When a terminal alkyne undergoes deprotonation, the removal of a proton from the terminal carbon atom results in the formation of an alkynide ion. The alkynide ion contains a negative charge that is associated with a lone pair of electrons, which occupies a p-orbital. This p-orbital is perpendicular to the plane of the molecule and lies along the axis of the carbon-carbon triple bond.

The alkynide ion is a very strong base due to the stability of the resulting anion. This base can be used in various reactions to form new carbon-carbon bonds or as a nucleophile in substitution reactions. Additionally, alkynide ions can be used as ligands in organometallic chemistry due to their ability to donate electrons to metal centers. In summary, deprotonation of a terminal alkyne leads to the formation of an alkynide ion that has a negative charge associated with a lone pair of electrons occupying a p-orbital.

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