a standing wave is formed by waves of frequency 256hz.the speed of the wave is 128m/s.what is the distance between the nodes​

Answer:

2.5 seconds

Explanation:

Time is equal to distance over speed

300 divide by 120 u get 2.5 seconds

a. The Inverse Square Law states that the intensity or strength of a physical quantity decreases with the square of the distance from its source.

b. The values of E and r in the given circuit are: E = 4V (e.m.f. of the cell) and r = ∞

a. In the context of electrostatics, the Inverse Square Law describes the relationship between the electric field strength and the distance from a charged particle.

b. For the first scenario (V = 4V and I = 1A), we have:

4V = 1A * R1,

R1 = 4Ω.

For the second scenario (V = 2V and I = 2.5A), we have:

2V = 2.5A * R2,

R2 = 0.8Ω.

Total resistance in the circuit (when ammeter reads zero current) is given by:

= R1 + R2 + r.

Since the ammeter reads zero current, we have:

E = I * R_total,

4V = 0A * R_total,

R_total = ∞ (infinity).

Therefore, we can conclude that the internal resistance r of the cell is infinite (or very high compared to the resistances in the circuit).

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Answer:

Explanation:

F = mv²/R

F = 11.0(3.50²)/0.600 = 225 N

We are given the following information

Energy of bulb = 100 W = 100 Joules/second

Area of fingertip = 1 cm² = 0.0001 m²

Wavelength of light = 588×10⁻⁹ m

Number of photons per second = ?

Let us first convert the wavelength into energy

Where h is the plank's constant (6.626x10⁻³⁴J.s), c is the speed of light (3×10⁸ m/s) and λ is the wavelength.

In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.

This relationship is described by the equation for the generated emf in a DC generator:

Emf = Φ * N * A * Z / 60

Where:

Emf is the generated electromotive force (in volts),

Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),

N is the number of turns in the armature winding,

A is the effective area of the armature coil (in square meters),

Z is the total number of armature conductors, and

60 is a constant representing the conversion from seconds to minutes.

From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.

The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.

The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.

Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.

By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.

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Answer:

LIKE Hmm

Explanation:

I CAN"T

Answer: I don't know exactly, but series circuits have an alternating current, while parallel has direct

Explanation:

Answer:

d: the speed of a character at the moment of contact

Explanation:

did the quick check

The measure which would be an initial condition in one of these games is

speed of a character at the moment of contact.

The speed of the character at the point of contact is the most suitable

option which tells the exact speed and position of the character in the

video game.

The moment of contact will determine the type of movement and position

exhibited by the players which can then be immediately updated when the

game is being played.

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Answer:

E

Explanation:

I me and my friends did a project on this

Answer:

9

Explanation:

d/dx (x² - x + 3)

= 2x - 1

when x = 5,

2x-1

= 2(5) - 1

= 10 - 1

= 9

The net force of the object using the free body diagram above is 12N, right (option D).

Net force is defined as the sum of all the forces acting on an object. Net force can accelerate a mass. Some other force acts on a body either at rest or motion.

The net force is a term used in a system when there is a significant number of forces.

Fnet = F¹+ F² + F³….+ Fn

Where;

F¹, F², F³…Fn are the forces acting on a body

According to this question, a stationary object is given with forces 8N and 10N acting rightward, then force 6N acting leftward.

Fnet = (8 + 10) - 6

Fnet = 18 - 6 = 12N

Therefore, the net force is 12N to the right because it is an unbalanced force.

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The electric potential supplied to a circuit is driven by electromagnetic induction through the relative motion of the conductor.

It is process through which an emf is produced in a conductor placed in a magnetic field when there is a relative motion of the conductor cutting across the flux of the field.

The motion of loop of wire through a magnetic field induces a voltage in the coil and the magnitude of the induced voltage is proportional to the speed or velocity of the movement of the loop.

Thus, the electric potential supplied to a circuit is driven by electromagnetic induction through the relative motion of the conductor.

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The concept of relative velocity can be found the speed of the bird respecting susan v = -12 m / s. The negative sign indicates that the bird is approaching susan

given parameter

to find

Velocity is a vector unit, therefore, in addition to magnitude, it has direction and sense, therefore, to make the sum of the same quantities, vector relations must be used

         v₁ = v₂ + v₃

where v₁, v₂ and v₃ are velocity and the bold letters indicate vectors

in this case Susan and the bird go on the x axis therefore the algebra is reduced to the algebraic sum. We will assume that the positive direction is to the right of the x-axis, consequently the velocities are:

Susan       v_{st} = 2 m / s

Bird          v_{bt} = - 10 m / s

The relative velocity is the vector sum of the velocities of the bodies, one way to perform this sum is by using subscripts

           v_{pt} =   v_{ps} + v_{st}

Where  v_{ps} is the speed of the bird relative to susan, v_{st} is the speed of susan relative to the ground, and v_{pt} is the speed of the bird relative to the ground.

            v_{ps} = v_{pt} - v_{st}

            v_{ps} = -10 - 2

            v_{ps} = - 12 m / s

Using the concept of relative velocity, the velocity of the bird respecting susan v = -12 m/s can be found. The negative sign indicates that the bird is approaching susab.

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Answer:

1. Dheere Dheere (slowly slowly)

2. Har (every)

3. Kal (tomorrow)

4. Mat (don't)

5. Andar (inside)

sorry I wasn't able to write in hindi

Answer and Explanation:

A. We have temperature t = 32

Speed of sound, s = 1087.5

As t increases by 1⁰f speed increases by 1.2

So that

S = 1088.6

T= 33⁰f

We have 2 equations

1087.5 = k(32) + c

1088.6 = k(33) + c

Subtracting both equations

(33-32)k = 1088.6-1087.5

K = 1.1

b.). S = kT + c

1087.5 = 32(1.1) + c

Such that

C = 1052.3

Therefore

S = 1.1(t) + 1052.3

C.). S = 1.1t + 1052.3

We make t subject of the formula

T = s/1.1 - 1052.3/1.1

T = 0.90(s) - 956.3

D. This means that We have temperature to rise by 0.90 whenever speed is increased

A person in an airplane in the sky has the greatest potential energy, while a person standing on the ground has the least potential energy.

Gravitational potential energy is the energy that an object possesses due to its position above the ground.

Mathematically, the formula for gravitational potential energy is given as;

PE = mgh

Where;

The greater the height or distance of an object above the ground, the greater the gravitational potential energy.

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Answer:

45.8

Explanation:

becuse 9.8+36=45.8 simple

Answer:

Force applied to stop the car = 1,250 N

Explanation:

Given:

Mass of car (M) = 1,000 kg

Initial velocity (U) = 20 m/s

Final velocity (V) = 0 m/s

Distance (S) = 160 m

Find:

Force applied to stop the car.

Computation:

\(v^2 = u^2 + 2as\\\\0^2=20^2+2(a)(160)\\\\0=400+320(a)\\\\Acceleration = a = -1.25m/s^2\\\\Force = ma \\\\Force= 1,000(1.25)\\\\Force = 1,250 N\)

Force applied to stop the car = 1,250 N

The speed of the ball rebounding from the plate is approximately 13.2 m/s.

According to the graph, the greatest force exerted by the football on the force plate during impact is around 1900 N. The ball comes to a halt on the force plate before rebounding.

The kinetic energy of the ball before impact equals the kinetic energy of the ball after the rebound, according to the law of conservation of energy.

The speed of the ball rebounding can be calculated using the formula:

(1/2)mv²= (1/2)mv_0²

where m is the mass of the ball (0.43 kg), v is the speed of the ball rebounding, and v_0 is the initial speed of the ball (15 m/s).

Solving for v, we get:

v = sqrt(v_0² - (2F/m))

where F is the maximum force exerted on the force plate (1900 N).

Plugging in the values, we get:

v = sqrt(15² - (2*1900/0.43)) ≈ 13.2 m/s

Therefore, the speed of the ball rebounding from the plate is approximately 13.2 m/s.

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For a single slit illuminated with a 500 nm light gives a diffraction pattern on a far screen,the angle  is mathematically given as

theta=25.3

Option A is correct

Generally, the equation for the the angle   is mathematically given as

\(\theta=n(\lambda/d)\)

Therefore

\(\theta 1/ \theta 2=n1(\lambda/d)/ n2(\lambda/d)\)

In conclusion

theta/7=16/5

theta=10*7/5

theta=25.3

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Answer:

.54 grams = .054 dekagrams

Explanation:

The specific latent heat of fusion of ice obtained from this experiment is approximately 583.33 J/g.

To determine the specific latent heat of fusion of ice using the given experiment, we need to consider the energy transferred during the process.First, we need to calculate the energy lost by the water to cool down from 25 °C to 0 °C. The energy lost is given by:

Q1 = m1 * c * ΔT1

Where:

m1 = mass of water = 100 g

c = specific heat capacity of water = 4.2 J/g °C

ΔT1 = change in temperature = (0 °C - 25 °C) = -25 °C

Q1 = 100 g * 4.2 J/g °C * (-25 °C) = -10,500 J

Next, we calculate the energy released by the water to freeze and cool the remaining ice. The energy released is given by:

Q2 = m2 * Lf

Where:

m2 = mass of ice = 18 g

Lf = specific latent heat of fusion of ice (to be determined)

Q2 = 18 g * Lf

Since energy is conserved in the system, the energy lost by the water (Q1) is equal to the energy released by the water (Q2):

-10,500 J = 18 g * Lf

Solving for Lf:

Lf = -10,500 J / 18 g = -583.33 J/g

The negative sign indicates that energy is being released during the process of freezing.

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The instantaneous current at the same moment in the RL circuit can be expressed as I = Imaxsin(150), where Imax represents the maximum current.

1. Given that the instantaneous voltage at a specific moment in the RL circuit is V = Vmaxsin(150).

2. We can express the current at the same moment using Ohm's Law, which states that V = IR, where V is voltage, I is current, and R is resistance.

3. In an RL circuit, the resistance is represented by the symbol R, and it is typically associated with the resistance of the wire or any resistors in the circuit.

4. However, the given equation does not explicitly mention resistance.

5. Since we are considering an RL circuit, it suggests the presence of inductance (L) along with resistance (R).

6. In an RL circuit, the voltage across the inductor (VL) can be expressed as VL = L(di/dt), where L is the inductance and di/dt represents the rate of change of current.

7. At any given instant, the total voltage across the circuit (V) can be expressed as the sum of the voltage across the resistor (VR) and the voltage across the inductor (VL).

8. Therefore, V = VR + VL.

9. Since the given equation represents the instantaneous voltage (V), we can deduce that V = VR.

10. By comparing V = VR with Ohm's Law (V = IR), we can conclude that I = Imaxsin(150), where Imax represents the maximum current.

The specific values of Vmax, Imax, and the phase angle have not been provided in the question, so we are working with the general expression.

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The net force on particle q₁ is approximately +25.6 N.

The electrostatic forces between particle q1 and the other two particles, q2 and q3, must be taken into account in order to determine the net force on particle q1. Coulomb's Law describes the electrostatic force between two charged particles:

F = k * |q₁ * q₂| / r²

F is the force, k is the electrostatic constant (9 x 109 N m2/C2), q1 and q2 are the charges' magnitudes, and r is the distance separating them.

Let's first determine the force between q1 and q2:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9 x 10^9 N m²/C²) * |(-29.6 μC) * (+37.7 μC)| / (0.630 m)²

F₁₂ = (9 x 10^9 N m²/C²) * (29.6 x 10^-6 C) * (37.7 x 10^-6 C) / (0.630 m)²

F₁₂ ≈ -7.45 N

The absence of a positive sign suggests an attractive force between q1 and q2.

Let's next determine the force between q2 and q3:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9 x 10^9 N m²/C²) * |(+37.7 μC) * (-10.8 μC)| / (0.315 m)²

F₂₃ = (9 x 10^9 N m²/C²) * (37.7 x 10^-6 C) * (10.8 x 10^-6 C) / (0.315 m)²

F₂₃ ≈ +33.05 N

The presence of a positive sign suggests a repulsive force between q2 and q3.

We must now add all the forces in order to determine the net force on q1:

Net force = F₁₂ + F₂₃

Net force ≈ -7.45 N + 33.05 N

Net force ≈ +25.6 N

The presence of a positive sign implies that the net force is pointing to the right, in the same direction as particle q2.

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An additional 83.2 micro C of charge will flow into the capacitor.

A 3.2 micro F capacitor has a potential difference of 21.0 V between its plates. An additional 83.2 micro C of charge will flow into the capacitor. The formula for the charge Q on a capacitor with capacitance C that is connected to a voltage V is given by:

Q = CV

where C is the capacitance of the capacitor in Farads, V is the potential difference across the capacitor in volts, and Q is the charge on the capacitor in coulombs. Thus, if the potential difference across the capacitor is increased from 21.0 V to 47.0 V, an additional 83.2 micro C of charge will flow into the capacitor. Capacitor is the entity that used to store the electricity in it, it is also used to generate an electricity spark in the gap between the wires of the circuit and the project just to make an gap and it is used to jump an electricity phase like wise in any circuit, it is used to provide the power and potential to make the charge jump from one place to another.

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An additional 83.2 microC of charge will flow into the capacitor.

The formula for the charge Q on a capacitor with capacitance C that is connected to a voltage V is given by:

Q = CV

where C is the capacitance of the capacitor in Farads,

V is the potential difference across the capacitor in volts, and Q is the charge on the capacitor in coulombs.

The initial charge on the capacitor is given by:Q1 = C1V1 = (3.2 microF)(21.0 V) = 67.2 microC

The final charge on the capacitor when the potential difference is increased to 47.0 V is given by:

Q2 = C2V2 = (3.2 microF)(47.0 V) = 150.4 microC

The additional charge that flows into the capacitor is equal to the difference between the final and initial charges:

ΔQ = Q2 - Q1 = 150.4 microC - 67.2 microC = 83.2 microC

Thus, if the potential difference across the capacitor is increased from 21.0 V to 47.0 V, an additional 83.2 microC of charge will flow into the capacitor.

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Answer:

range selection lock feature

Explanation:

This feature locks  the meter at a particular range. The range selection lock defeats the

meter’s normal autoranging function, which can become confused if

electrical noise or other signal pulses are present on nearby circuits or

conductors.

Range selection lock feature is  used to override or defeat the autoranging function on a Digital Multimeter (DMM).

Instruments called digital multimeters are used to measure things like voltage, current, and resistance. Digital displays make it possible for even novice users to read measured values quickly and easily.

Some digital multimeters automatically choose the measurement range, removing the need for manual selection. As a result, even for beginners, these instruments are rather simple to use. Naturally, analogue testers have advantages as well. For instance, it is simple to read variations in the measured value during measurement, and a needle may be seen intuitively in places where a digital reading might be challenging to notice.

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Given:

Mass of skater, m = 75 kg

Height, h = 5 meters

Let's find the potential energy of the skater.

To find the potential energy, since the skater is in motion, apply the formula below:

Where:

m is the mass in kg = 75 kg

g is acceleration due to gravity = 9.8 m/s^2

h is the height in meters = 5 m

Hence, to find the potentila energy, (PE), we have:

Therefore, the potential energy of the skater is 3675 Joules.

ANSWER:

3675 J

Answer:

( About ) 6.8nC

Explanation:

We are given the equation |Q2| = mgd^2 / kQ1. Let us substitute known values into this equation, but first list the given,

Charge Q2 = +45nC = (45 × 10⁻⁹) C

mass of charge Q2 = 4.5 μg, force of gravity = 4.5 μg × 9.8 m/s² = ( 4.41 × 10^-5 ) N,

Distance between charges = 25 cm = 0.25 m,

k = Coulomb's constant = 9 × 10^9

_______________________________________________________

And of course, we have to solve for the magnitude of Q2, represented by the charge magnitude of the charge on Q2 -

(4.41 × 10^-5) = [(9.0 × 10⁹) × (45 × 10⁻⁹) × Q₂] / 0.25²

_______________________________________________________

Solution = ( About ) 6.8nC