A spring with k = 35.5 N/m has a mass of 5.50 kg attached to it. An external force F = (4.40 N)sin[(6.80 s−1)t] drives the spring mass system so that it oscillates without any resistive forces. What is the amplitude of the oscillatory motion of the spring-mass system?

Answer:

The work done will be "763 J". A further explanation is given below.

Explanation:

The given values are:

\(Q_1=1000 \ J\)

Temperature,

\(T_1=900^{\circ} C\)

i.e,

    \(=1173\)

\(T_2=5^{\circ}C\)

i.e.,

    \(=278\)

As we know,

⇒  \(\eta =1-\frac{T_2}{T_1}\)

On substituting the values, we get

⇒     \(=1-\frac{278}{1173}\)

⇒     \(=\frac{1173-278}{1173}\)

⇒     \(=\frac{895}{1173}\)

⇒     \(=0.763\)

then,

⇒  \(W=\eta Q_1\)

⇒       \(=0.763\times 1000\)

⇒       \(=763 \ J\)

Answer:

Nancy Elizabeth Lieberman (nacido el 1 de julio de, 1958), apodado "Señora mágica", ] es un ex profesional jugador de baloncesto y entrenador de la WNBA (WNBA) que es actualmente un organismo de radiodifusión para los New Orleans Pelicans de la Nacional La Asociación de Baloncesto (NBA) y la entrenadora principal de Power , un equipo en el BIG3 que lideró en su Campeonato 0.]bLieerman es considerada como una de las figuras más importantes del baloncesto femenino estadounidense.

Explanation:

The ring spends 1.8 s in the field, during which it completes 60 full wedding ring is tossed end over end into a running MRI machine with a 4.0 T field.

Magnetic resonance imaging is a medical imaging technique used in radiology to form pictures of the anatomy and the physiological processes of the body. MRI scanners use strong magnetic fields, magnetic field gradients, and radio waves to generate images of the organs in the body.

Moreover, an MRI scanner is a large tube that contains powerful magnets. You lie inside the tube during the scan. An MRI scan can be used to examine almost any part of the body, including the: brain and spinal cord. bones and joints.

Hence, a single scan may take a few seconds or 3 to 8 minutes. You may be asked to hold your breath during short scans. The total scan lasts 15 to 90 minutes, depending on the size of the area being scanned and how many images are needed.

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The kinematics of the uniform motion and the addition of vectors allow finding the results are:

Vectors are quantities that have modulus and direction, so they must be added using vector algebra.

A simple method to perform this addition in the algebraic method which has several parts:

 Indicate that Barry's velocity is constant, let's find using the uniform motion thatthe distance traveled in ad case

              v = \(\frac{\Delta d}{t}\)

              Δd = v t

Where  v is the average velocity, Δd the displacement and t the time

We look for the first distance traveled at speed v₁ = 600 m / s for a time

          t₁ = 2 min = 120 s

          Δd₁ = v₁ t₁

          Δd₁ = 600 120

          Δd₁ = 72 10³ m

Now we look for the second distance traveled for the velocity v₂ = 400 m/s    

  time t₂ = 1 min = 60 s

          Δd₂ = v₂ t₂

          Δd₂ = 400 60

          Δd₂ = 24 103 m

In the attached we can see a diagram of the different Barry trajectories and the coordinate system for the decomposition,

We must be careful all the angles must be measured counterclockwise from the positive side of the axis ax (East)

Let's use trigonometry for each distance

Route 1

          cos (180 -35) = \(\frac{x_1}{\Delta d_1}\)

          sin 145 = \(\frac{y_1}{\Delta d1}\)

          x₁ = Δd₁ cos 125

          y₁ = Δd₁ sin 125

          x₁ = 72 103 are 145 = -58.98 103 m

          y₁ = 72 103 sin 155 = 41.30 10³ m

Route 2

          cos (90+ 30) = \(\frac{x_2}{\Delta d_2}\)

          sin (120) = \(\frac{y_2}{\Delta d_2}\)

          x₂ = Δd₂ cos 120

          y₂ = Δd₂ sin 120

          x₂ = 24 103 cos 120 = -12 10³ m

           y₂ = 24 103 sin 120 = 20,78 10³ m

The component of the resultant vector are

              Rₓ = x₁ + x₂

              R_y = y₁ + y₂

              Rx = - (58.98 + 12) 10³ = -70.98 10³ m

              Ry = (41.30 + 20.78) 10³ m = 62.08 10³ m

We construct the resulting vector

Let's use the Pythagoras' Theorem for the module

             R = \(\sqrt{R_x^2 +R_y^2}\)

             R = \(\sqrt{70.98^2 + 62.08^2}\)   10³

             R = 94.30 10³ m

We use trigonometry for the angle

             tan θ ’= \(\frac{R_y}{R_x}\)

             θ '= tan⁻¹ \(\frac{R_y}{R_x}\)

             θ '= tan⁻¹ \(\frac{62.08}{70.98}\)

             θ ’= 41.2º

Since the offset in the x axis is negative and the displacement in the y axis is positive, this vector is in the second quadrant, to be written with respect to the positive side of the x axis in a counterclockwise direction

            θ = 180 - θ'

            θ = 180 -41.2

            θ = 138.8º

Finally, let's calculate the speed for the way back, since the total of the trajectory must be 5 min and on the outward trip I spend 3 min, for the return there is a time of t₃ = 2 min = 120 s.

The average speed of the trip should be

             v = \(\frac{\Delta R}{t_3}\)  

             v = \(\frac{94.30}{120} \ 10^3\)

              v = 785.9 m / s

in the opposite direction, that is, the angle must be

               41.2º to the South of the East

In conclusion, using the kinematics of the uniform motion and the addition of vectors, results are:

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Answer:

D

Explanation:

The student has enough information to make the determination

Measurements should the student take, in addition to the measurements from the force plate, to determine the change in momentum of the object from immediately before the collision to immediately after the collision the student has enough information to make the determination. Thus, option D is correct.

A student drops an object from rest above a force plate that records information about the force exerted on the object as a function of time during the time interval in which the object is in contact with the force plate.

Momentum has the measure of motion of the object. Momentum is given by the product of mass and the velocity of the object. The law of conservation of momentum states that the momentum before the collision is equal to the momentum after the collision. It also states that the total momentum of a system or a body remains constant.

Therefore, Measurements should the student take, in addition to the measurements from the force plate, to determine the change in momentum of the object from immediately before the collision to immediately after the collision the student has enough information to make the determination. Thus, option D is correct.

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Answer:

38.2 m/s

Explanation:

Given:

Δy = 56.8 m

a = -9.8 m/s²

t = 5.8 s

Find: v₀

Δy = v₀ t + ½ at²

56.8 m = v₀ (5.8 s) + ½ (-9.8 m/s²) (5.8 s)²

v₀ ≈ 38.2 m/s

Answer:

Gravitational force

Explanation:

Hope this helps :)

Explanation:

I have a lot to say it was very nice to meet my parents are u doing well I dont want too its been so much I love you so I was like u know I am not a man but you are the auditions I have been in a long long long life is a triangle and a chair for me and my parents think about the way I

Answer:

e. 425.9 Hz

Explanation:

The computation of the frequency is being played by the out-of-tune key is shown below;

Given that

Δf1  = x - 349.2 = 76.7.........(1)

Δf2 = 440 - x  = 14.1......(2)

Now solve (1) and (2)

(440 - x) - x + 349.2 = 14.1 - 76.7

789.2 + (-2x) = -62.6

x = 425.9 Hz

Hence, the frequency is being played by the out-of-tune key is 425.9 Hz

Therefore the option e is correct

The kinetic energy of of given data is K.E. = 1,047.62 J

To calculate kinetic energy using the formula,

K.E. = 1/2 m v²

where,

K.E is kinetic energy

m is mass

v is velocity

So, Putting values,

K.E. = 1/2 x 29 x (8.5m/s)²

K.E. = 1,047.62 J

The energy an object has as a consequence of motion is known as kinetic energy. A force must be applied to an object in order to accelerate it. We must put in effort in order to apply a force. After the work is finished, energy is transferred to the object, which then moves at a new, constant speed.

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Answer:

Earth Day is observed globally

Explanation:

Answer:

Explanation:

??????????

Answer:

2.8ibs=kg check with someone else im not for sure.

Explanation:

if you divide 10 divided by 2 it gives you 5 and then subtract it by 2.2 = 2.8

there goes your answer.

Answer:

amount of force times the distance it moves an object: work

kind of force used to operate engines: steam

English unit of measuring work equal to moving one pound one foot: foot-pound

metric measurement of work equal to moving one Newton one meter: Newton-meter

kind of force that pulls things toward the center of the earth: force of gravity

force used when walking: muscular force

force used to turn a windmill: force of wind

Explanation:

I found the answers in quizlet

Answer:

im in the same class so here's your answer

Explanation:

Answer:

im sure your already past this but it's E.

Explanation:

This is because in this case potential energy is linear to height, which means that the higher the more potential energy.

Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.

Frequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).

Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.

Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.

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Explanation:

Mathematicians seek and use patterns[8][9] to formulate new conjectures; they resolve the truth or falsity of such by mathematical proof. When mathematical structures are good models of real phenomena, mathematical reasoning can be used to provide insight or predictions about nature. Through the use of abstraction and logic, mathematics developed from counting, calculation, measurement, and the systematic study of the shapes and motions of physical objects. Practical mathematics has been a human activity from as far back as written records exist. The research required to solve mathematical problems can take years or even centuries of sustained inquiry.

Rigorous arguments first appeared in Greek mathematics, most notably in Euclid's Elements.[10] Since the pioneering work of Giuseppe Peano (1858–1932), David Hilbert (1862–1943), and others on axiomatic systems in the late 19th century, it has become customary to view mathematical research as establishing truth by rigorous deduction from appropriately chosen axioms and definitions. Mathematics developed at a relatively slow pace until the Renaissance, when mathematical innovations interacting with new scientific discoveries led to a rapid increase in the rate of mathematical discovery that has continued to the present day.[11]

Mathematics is essential in many fields, including natural science, engineering, medicine, finance, and the social sciences.

The value of force (F) if the change in length of the cable is 7.8 mm is 1500.89 N

The value of the force can be determined by using the young modulus equation that shows the relation between the tensile of the steel cable when the force is applied.

\(\mathbf{\gamma = \dfrac{F/A}{\Delta L/L}}\)

\(\mathbf{\gamma = \dfrac{F} {A }\times \dfrac{L}{\Delta L} }\)

Making the force the subject of the formula and replacing the values, we have:

\(\mathbf{F =\dfrac{A \times \gamma \times \Delta L }{L} }\)

\(\mathbf{F =\dfrac{ \pi \times (3.5 \times 10^{-3}) \times ( 20 \times 10^{10} \ N/m^2 ) \times (7.8 \times 10^{-3}) }{4 \times 10} }\)

\(\mathbf{F =1500.89 \ N }\)

Therefore, we can conclude that the value of force (F) if the change in length of the cable is 7.8 mm is 1500.89 N

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Answer:

both magnitude and direction

Explanation:

When an object moves in a circular path, its motion is called uniform circular motion. In this motion, the force acting on it is centripetal force and it is moving under centripetal acceleration. This type of force acts towards the centre of the circle.

In this type of motion, the speed remains constant while the velocity keeps on changing. The object's centripetal  acceleration remains constant in magnitude as well as direction.

Hence, the correct option is (3).

If an object is moving with constant speed in the circular path the object's centripetal  acceleration remains constant in both magnitude and direction

The formula for calculating the centripetal acceleration of an object is expressed as:

\(a =\frac{v^2}{r}\)

Hence if an object is moving with constant speed in the circular path the object's centripetal  acceleration remains constant in both magnitude and direction

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X represent the wind energy that converted to electrical energy

Answer:

365 m/s

Explanation:

Mrs Finley

Answer:

acceleration = cange in velocity ÷ change in time.

acceleration = (-15 - -10) ÷ 2

acceleration = -5 ÷ 2

ACCELERATION IS -2.5m/s2

Explanation:

Answer:

Air moves from regions of high pressure to regions of low pressure.

Explanation:

When airs moves horizontally from regions of high pressure to low pressure, it creates wind. If the difference between high and low pressure is greater, then it makes the wind faster.

Best of Luck!

Answer:

C. Air moves from regions of high pressure to regions of low pressure.

Explanation:

The air from the regions of high pressure will hold onto that pressure. So, when it moves into the regions with low pressure it'll turn into wind.  

The greater the pressure, the stronger the wind and vise versa.

Hope this helps!

The Sketch  of the figure will bear the parameters of the charge that lies   at (4,0,0)

Generally, the equation for is  mathematically given as

1)

Since both of the other points, "q1"<"q2," are on the x-axis, the third one must also be on the x-axis, and it must be close to the charge of lesser magnitude. off q1 by x cm

Now, forces on q3 due to q1

\(\vec{F}_{1}=\frac{k q_{1} q_{3}}{x^{2}} \hat{x}\)

Force on q3 due to q2

\(\vec{F}_{2}=\frac{k q_{2} q_{3}}{(6+x)^{2}}(-\hat{x})\)

\(\quad \vec{F}_{1}+\vec{G}_{2}=0$\)

\(&\frac{k q_{1} q_{3}}{x^{2}}-\frac{k q_{2} q_{3}}{(x+6)^{2}}=0 \\&\frac{2}{x^{2}}=\frac{8}{(x+6)^{2}} \Rightarrow \frac{x+6}{x}=\sqrt{\frac{8}{2}}=2 \\&x+6=2 x \Rightarrow x=6 \mathrm{~cm}\)

In conclusion, the charge lies at (4,0,0)

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Answer:

a

e(k) =  \frac{2a}{c}  *  sin (\frac{k*a}{2} )

b

G_{v} =  \frac{d e(k ) }{dk }  =  \frac{a^2}{c}  *  cos (\frac{k* a}{2} )

Explanation:

From the question we are told that

    The  velocity  of transverse waves in a crystal of atomic separation is  

                  \(b_y  = c \frac{sin (\frac{k*a}{2} )}{\frac{k*a}{2} }\)

Generally the dispersion relation is mathematically represented as

            \(e(k) =  b_y  *  k\)

=>    \(e(k) = c  \frac{sin(\frac{k*a}{2} ) }{ \frac{k*a}{2} }  *  k\)

=>    \(e(k) =   c *  \frac{sin (\frac{k_a}{2} )}{ \frac{a}{2} }\)

=>    \(e(k) =  \frac{2a}{c}  *  sin (\frac{k*a}{2} )\)

Generally the group velocity is mathematically represented as

          \(G_{v} =  \frac{d e(k ) }{dk }  =  \frac{a^2}{c}  *  cos (\frac{k* a}{2} ) \)

Answer:

It will take approximately 8.88 seconds for the payload to reach the surface of the asteroid.

Explanation:

The payload will fall to the surface of the asteroid at a constant acceleration of 0.45 m/s2 due to the gravitational force acting on it. The velocity of the payload at any time can be calculated using the following equation:

v = at

Where v is the velocity, a is the acceleration, and t is the time elapsed.

To find the time it takes for the payload to reach the surface, we can use the following equation:

d = vt + 0.5at^2

Where d is the distance traveled and t is the time elapsed.

We can rearrange this equation to solve for t:

t = (-v + sqrt(v^2 + 2ad)) / a

Plugging in the values given in the problem, we get:

t = (-0 + sqrt(0^2 + 2 * 0.45 * -600)) / 0.45

t = 8.88 seconds

Therefore, it will take approximately 8.88 seconds for the payload to reach the surface of the asteroid.

The efficiency of motor is 90.58%.To determine the efficiency of the motor, we need to calculate the input power and the output power, and then divide the output power by the input power

The input power can be calculated using the formula:

Input Power = Voltage × Current

Given that the voltage is 230 V and the current is 24 A, we have:

Input Power = 230 V × 24 A

Input Power = 5520 W (or 5.52 kW)

The output power of the motor is given as 5 kW (since it is a 5 kW motor).

Now, we can calculate the efficiency:

Efficiency = (Output Power / Input Power) × 100%

Efficiency = (5 kW / 5.52 kW) × 100%

Efficiency ≈ 90.58%

Therefore, the efficiency of this motor is approximately 90.58%.

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Explanation:

230.95 states that ground-fault protection of equipment shall be provided for solidly grounded wye electrical services of more than 150 volts to ground, but not exceeding 600 volts phase-to-phase for each service disconnecting means rated 1000 amperes or more.