A spring is stretched 5 mm by a force of 125 N. How much will the spring stretch
when 250 N force is applied?

Answer:

PLS MARK ME AS BRAINLIEST

Explanation:

The people in ancient times realize the need for some fixed quantity of measurement because the length of the various body parts differs from person to person.

Answer:

Explanation:

In ancient times, people realized the need for fixed quantity of measurement because it helped them in various aspects of their daily lives. By having standardized measurements, they could ensure fairness in trade and commerce, build structures with stability and accuracy, and establish systems for agriculture, timekeeping, and other important activities. Having fixed measurements made it easier for people to communicate and collaborate effectively, leading to better understanding and progress in their societies.

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The angular velocity in radians per second, given that Microwave ovens rotate at a rate of about 5 revolutions per minute (rpm) is 0.50 radians per second

The angular velocity (in radians per second) can be obtained by simply converting 0.08 revolution per second to radians per second. This is obtained as illustrated below:

1 revolution per second = 2π radians per second

Therefore,

0.08 revolution per second = 0.08 × 2π

Recall

Pi (π) = 3.14

Thus,

0.08 revolution per second = 0.08 × 2 × 3.14

0.08 revolution per second = 0.50 radians per second

Thus, we can conclude that the angular velocity (in radians per second) is 0.50 radians per second

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The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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If the cloud is transparent, milky, thin layers, rain within the next 2 hours, then the cloud you are seeing is most likely a type of altocumulus cloud.

Altocumulus clouds are generally characterized by their white or gray color, and can sometimes appear milky or translucent. They often form in layers, and can be thin or thick depending on the conditions.

Altocumulus clouds are typically found at medium altitudes, between 6,500 and 20,000 feet and are often associated with unsettled weather conditions.

While they don't necessarily indicate that rain is imminent, altocumulus clouds can be a sign that a change in the weather is on the way.

Thus, if it is likely to rain in the next 2 hours, then the cloud must be altocumulus clouds.

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Answer:  C.  5V

Explanation:

Since P = VI, power is directly proportional to voltage

If current is constant, then the lower the voltage, the lower the power. The lowest voltage shown is 5 Volts.

The magnitude of the forces acting at the top are;

\(\mathbf{F_{Top, \ x}}\) = 132.95 N

\(\mathbf{F_{Top, \ y}}\) = 0

The magnitude of the forces acting at the bottom are;

\(\mathbf{F_{Bottom, \ x}}\) = \(\mathbf{ F_f}\) = -132.95 N

\(\mathbf{F_{Bottom, \ y}}\) = 784.8 N

The known parameters in the question are;

The mass of the person, m₁ = 70.0 kg

The length of the ladder, l = 6.00 m

The mass of the ladder, m₂ = 10.0 kg

The distance of the base of the ladder from the house, d = 2.00 m

The point on the roof the ladder rests = A frictionless plastic rain gutter

The location of the center of mass of the ladder, C.M. = 2 m from the bottom of the ladder

The location of the point the person is standing = 3 meters from the bottom

g = The acceleration due to gravity ≈ 9.81 m/s²

The required parameters are;

The magnitudes of the forces on the ladder at the top and bottom

The strategy to be used;

Find the angle of inclination of the ladder, θ

At equilibrium, the sum of the moments about a point is zero

The angle of inclination of the ladder, θ = arccos(2/6) ≈ 70.53 °C

Taking moment about the point of contact of the ladder with the ground, B gives;

\(\sum M_B\) = 0

Therefore;

\(\sum M_{BCW}\) = \(\sum M_{BCCW}\)

Where;

\(\sum M_{BCW}\) = The sum of clockwise moments about B

\(\sum M_{BCCW}\) = The sum of counterclockwise moments about B

Therefore, we have;

\(\sum M_{BCW}\) = 2  × (2/6) × 10.0 × 9.81 + 3.0 × (2/6) × 70 × 9.81

\(\sum M_{BCCW}\) = \(F_R\) × √(6² - 2²)

Therefore, we get;

2  × (2/6) × 10.0 × 9.81 + 3.0 × (2/6) × 70 × 9.81  = \(F_R\) × √(6² - 2²)

\(F_R\)  = (2  × (2/6) × 10.0 × 9.81 + 3.0 × (2/6) × 70 × 9.81)/(√(6² - 2²)) ≈ 132.95

The reaction force on the wall, \(F_R\) ≈ 132.95 N

We note that the magnitude of the reaction force at the roof, \(F_R\) = The magnitude of the frictional force of bottom of the ladder on the floor, \(F_f\) but opposite in direction

Therefore;

\(F_R\) = \(-F_f\)

\(F_f\) = - \(F_R\) ≈ -132.95 N

Similarly, at equilibrium, we have;

∑Fₓ = \(\sum F_y\) = 0

The vertical component of the forces acting on the ladder are, (taking forces acting upward as positive;

\(\sum F_y\) = -70.0 × 9.81 - 10 × 9.81 + \(F_{By}\)

∴ The upward force acting at the bottom, \(F_{By}\) = 784.8 N

Therefore;

The magnitudes of the forces at the ladder top and bottom are;

At the top;

\(\mathbf{F_{Top, \ x}}\) = \(F_R\) ≈ 132.95 N←

\(\mathbf{F_{Top, \ y}}\) = 0 (The surface upon which the ladder rest at the top is frictionless)

At the bottom;

\(\mathbf{F_{Bottom, \ x}}\) = \(F_f\) ≈ -132.95 N →

\(\mathbf{F_{Bottom, \ y}}\) = \(F_{By}\) = 784.8 N ↑

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Answer:

The mechanical advantage of a hydraulic system is given by the ratio of the output force to the input force. In this case, the input force is 15.8 lb and the output force is 93 lb.

So, the mechanical advantage of the hydraulic system is:

MA = Output force / Input force

MA = 93 lb / 15.8 lb

MA = 5.89

Therefore, the mechanical advantage of the hydraulic system is 5.89. This means that the system can lift a weight that is almost 6 times greater than the input force applied to the other piston.

Answer:

23.51 m/s

Explanation:

Parameters given:

Kinetic energy, K = 295 J

Momentum, p = 25.1 kgm/s

a) The kinetic energy of a body is given as:

where m = mass of the body and v = speed of the body

Answer:

Explanation:

Where,

\(\to\:\:\sf\red{K.E. = \dfrac{1}{2}mv^{2}}\)

\(\to\:\:\sf\orange{5000 = \dfrac{1}{2} \times 100 \times v^{2}}\)

\(\to\:\:\sf\green{5000 = 50 \times v^{2}}\)

\(\to\:\:\sf\blue{\dfrac{5000}{50} = v^{2}}\)

\(\to\:\:\sf\purple{100 = v^{2}}\)

\(\to\:\:\sf\red{\sqrt{100} = v}\)

\(\to\:\:\sf\orange{ 10 = v}\)

\(\to\:\:\bf\pink{v = 10\:m/s}\)

The equivalent resistance of the circuit shown  is 23 ohms.

Option A is correct.

Resistance is  described as the opposition that a substance offers to the flow of electric current.

In a series circuit, all components are connected end-to-end to form a single path for current flow.

In a parallel circuit, all components are connected across each other with exactly two electrically common nodes with the same volt.

We then 1/R = 1/100 + 1/100 + 1 /(50+ 50) +  1 /(50+ 50)

I/R = 0.04

R = 25 ohms.

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Answer:

5 g/per cm3

Explanation:

3 times 5 times 2 = 30 150/30 = 5

The final vertical velocity of the skydiver at 50.8 m of fall is 31.56 m/s.

The time of motion of the girl is calculated as follows;

h = vt + ¹/₂gt²

where;

Substitute the given parameters and solve for time of motion;

50.8 = 0 + ¹/₂(9.8)t²

2(50.8) = 9.8t²

101.6 = 9.8t²

t² = 101.6/9.8

t² = 10.367

t = √10.367

t = 3.22 seconds

vf = vi + gt

where;

vi is the initial vertical velocity = 0

vf = 0 + 9.8(3.22)

vf = 31.56 m/s

Thus, the final vertical velocity of the skydiver at 50.8 m of fall is 31.56 m/s.

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The two sentences that best state the central ideas of Wiesel's speech are:

Elie Wiesel's speech focuses primarily on the Holocaust and the atrocities that were committed during that time, particularly at Auschwitz. The central ideas of his speech are:

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Answer:

yor welcome

Explanation:

hi

Answer:

Option "C": "4.5 g"

Explanation:

N0 = 36 g, Let half-life is T.

t = 3 T, n is number of half lives = t / T = 3

By using the decay law of radioactivity

N / N0 = (1 / 2)^n

where

"N0" be the "initial amount"

"N" be the "amount left"

"n" be the "number of half-lives"

N / 36 = (1/2)^3

N / 36 = 1 / 8

N = 36 / 8 = 4.5 g

The engine that provides twice more power will make it first

The car with the twice more power does more work

When a vertical force acts on an object moving horizontally, the work done by the force depends on the angle between the force and the displacement of the object. If the force is perpendicular to the displacement, no work is done, since the force does not contribute to the displacement of the object.

The work done is the same as the gravitational potential energy and this is;

W = F h

F  = Force

h = height of the object

Thus;

W = 25 * 1.5

= 37.5 J

Then;

Power = Work done/Time

= 100 J/ 2 s

= 50 W

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The kinetic energy of the book after it is slids a distance of 2 meters will be 10 Joules.

The work-energy theorem states that "the work done on an object is the change in its kinetic energy".

Hence;

Kinetic energy = work done

Note that: work-done is expressed as:

Work done = f × d

Where f is force applied and d is distance traveled.

Given that:

Force applied f = 5 newton

Distance d = 2 meters

Work done = ?

Plug these values into the above formula and solve for the workdone.

Work done = f × d

Work done = 5N × 2m

Work done = 10Nm

Work done = 10 Joules

Therefore, the kinetic energy is 10 Joules.

Option B) 10 J is the correct answer.

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Answer:

0.001 A

Explanation:

Applying,

V = IR.............. Equation 1

Where V = Voltage of the motor, I = current, R = resistance

make I the subject of the equation

I = V/R.............. Equation 2

From the question,

Given: V = 1000 V, R = 1 MΩ = 10⁶ Ω

Substitute these values into equation 2

I = 1000/10⁶

I = 10⁻³ A

I = 0.001 A

In your business plan, the target market section should clearly identify both your primary and secondary market(s). The market analysis is basically the target market section of your business plan. It is a thorough examination of the ideal people to whom you intend to sell your products or services.

Answer:  Part A:

The period of a simple pendulum is given by the formula: T = 2π√(L/g), where L is the length of the pendulum and g is the acceleration due to gravity. If the mass of the bob is doubled, the period of the pendulum will change. To see how much it changes, we can use the fact that the period depends only on the length of the pendulum and the acceleration due to gravity, and not on the mass of the bob. Therefore, the new period of the pendulum will be the same as the old period: T.

Part B:

If the pendulum is brought to the moon, where the acceleration due to gravity is about g/6, the new period of the pendulum can be found using the same formula as before: T = 2π√(L/g). However, now we need to use the value of the acceleration due to gravity on the moon, which is g/6. Therefore, the new period of the pendulum is T' = 2π√(L/(g/6)) = 2π√(6L/g) = √6T.

Therefore, the answer is: T/√6.

Part C:

If the pendulum is taken into an orbiting space station, the bob will continue to oscillate in a vertical plane with the same period as it did on the surface of the Earth. This is because the period of the pendulum depends only on the length of the pendulum and the acceleration due to gravity, and not on the location of the pendulum. In the space station, both the pendulum and the point to which it is attached are in free fall, but they are falling together and maintaining their relative positions, so the pendulum will continue to oscillate as before.

Answer:

c

Explanation:

Answer:

the answer is c i just did it

Explanation:

Answer: λₑ = 123pm; λₚ = 286pm

Explanation:

λ= h/√2mE where E = Kinetic Energy.

λₑ = h/√2mₑE = 6.626 X 10^-33/√2 X 9.1 X 10⁻31 X 100 X 1.6 X 10^-19 = 123pm

λₚ = h/√2mₚE = 6.626 X 10^-33/√2 X 1.6 X 10⁻27 X 100 X 1.6 X 10^-19 = 286pm

Hope this helps!!!

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Answer:

The velocity & acceleration will be taken as negative when a ball is thrown upward because work is done against the gravity.

Explanation:

a = (dx / dt)²

Explanation:  Unit of distance is m (metres) and unit of time is s (seconds) speed v is  first derivative of distance x versus time:

  v = dx / dt, unit is m/s.    Acceleration is second derivative of

 speed versus time  a = (dx / dt)² = (dv/dt) , unit is m/s²

Answer:

Explanation:

Acceleration is derived unit because it has two fundamental units involved i.e. meter and second square.

Answer:

Emotional and Social Development

During the preschool years, your little one is learning to read emotional cues and is getting better at relating to other people, according to the New York University Child Study Center 1⭐

⭐This is a verified and trusted source

New York University Child Study Center: The Preschool Years: (Ages Four and Five) Expectations and Challenges

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. He can empathize with others and make friends with other children his own age. By his fifth birthday, your preschooler often seeks friends of the same gender and shows a preference for playing with other children, rather than adults. Your preschooler also engages in pretend play and can probably tell the difference between reality and fantasy, according to the American Academy of Pediatrics.

Physical Development

There's a big difference between a 2-year-old and a 5-year-old. During the preschool years, your child develops in many physical ways. She goes from toddling around unsteadily to being able to jump, stand on one foot, walk up and down stairs and walk backward, according to the New York University Child Study Center 1⭐

⭐This is a verified and trusted source

New York University Child Study Center: The Preschool Years: (Ages Four and Five) Expectations and Challenges

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. By the time she's 5, your little one should also be able to ride a tricycle, build a block tower, paint on paper, skip, throw a ball, dress and undress and begin drawing recognizable objects, adds the University of Illinois Extension.

Answer:

the tension in the cable is \(\mathbf{F = \frac{\pi E_o v^2r^2}{2d^2}}\)

the work done by the cable is \(\mathbf{W= \frac{\pi E_ov^2r^2}{4d}}\)

Explanation:

A)

If we have two circular plate supported by a cable at a fixed distance, then the electric field formed between the two plate of the capacitor can be represented by the equation.

\(\mathbf{E = \frac{voltage \ \ V}{distance \ \ d}}\)

However; the net electric field i.e the sum of the electric filed produced is represented as:

\(\mathbf{E' = \frac{E}{2}} \\ \\ \mathbf{E' = \frac{V}{2d}}\)

So, if we assume that the lower plate and the upper plate possess the charge +q and -q respectively. Then, the tension of the cable which is the same as Force F can be written as:

\(\mathbf{F = q* E'}\)

\(\mathbf{F = \frac{q*v}{2d}}\) -----    equation (1)

Also ; we know that

\(\mathbf{C = \frac{q}{v}= \frac{E_oA}{d}}\)

\(\mathbf{\frac{q}{v}= \frac{E_o \pi r^2}{d}} \ \ \ \ \ \mathbf{since \ A = \pi r^2}\)

\(\mathbf{{q}= \frac{\pi E_o {v} r^2}{d}}\)    -----   equation (2)

Replacing equation 3 into equation (2); we have:

\(\mathbf{F = \frac{\pi E_o vr^2}{d}* \frac{v}{2d}}\)

\(\mathbf{F = \frac{\pi E_o v^2r^2}{2d^2}}\)

Therefore,  the tension in the cable is \(\mathbf{F = \frac{\pi E_o v^2r^2}{2d^2}}\)

B)

Assume that the upper plate is displaced by dz in an upward direction ; Then we can express the workdone by the tension as :

\(\mathbf{dW = T *dz} \\ \\ \mathbf{dW = F*dz} \\ \\ \mathbf{dW = \frac{\pi E_o v^2r^2}{2z^2}dz }\)

The net workdone to raise the plate from separation d to 2d is:

\(\mathbf{W = \int\limits^{2d}_{2zd} {dw} = \frac{\pi E_ov^2r^2}{2} \int\limits^{2d}_d \frac{dz}{z^2} }\)

\(\mathbf{W= \frac{\pi E_ov^2r^2}{2} [-\frac{1}{z}]^{2d}_d }\)

\(\mathbf{W= - \frac{\pi E_ov^2r^2}{2} [\frac{1}{2d}-\frac{1}{d}]}\)

\(\mathbf{W= - \frac{\pi E_ov^2r^2}{2} [\frac{-1}{2d}]}\)

\(\mathbf{W= \frac{\pi E_ov^2r^2}{4d}}\)

the work done by the cable is \(\mathbf{W= \frac{\pi E_ov^2r^2}{4d}}\)

C) To calculate the energy stored in the Electrical energy Capacitor before the top plate is raised ; we have:

\(\mathbf{U_i = \frac{1}{2}Cv^2} \\ \\ \mathbf{U_i = \frac{1}{2}(\frac{E_oA}{d})v^2} \\ \\ \mathbf{U_i = \frac{1}{2}(\frac{E_o \pi r^2}{d})v^2} \\ \\ \mathbf{U_i = \frac{E_o \pi r^2 v^2}{2d}} }\)

D) The energy stored in the plate after the  the top plate was raised is as follows:  

\(\mathbf{U_f = \frac{1}{2}C'v^2} \\ \\ \mathbf{U_f = \frac{1}{2}(\frac{E_oA}{2d})v^2} \\ \\ \mathbf{U_f = \frac{1}{2}(\frac{E_o \pi r^2}{2d})v^2} \\ \\ \mathbf{U_f = \frac{E_o \pi r^2 v^2}{4d}} }\)

E) Yes,  work done by the cable equal to the change in the stored electrical energy. The Difference in energy stored before and after the top plate is raised:

\(\mathbf{U_i-U_f} = \mathbf{\frac{E_o \pi r^2 v^2}{2d}} }} - \mathbf {\frac{E_o \pi r^2 v^2}{4d}} }}\)

\(\mathbf{U_i-U_f}= \mathbf {\frac{E_o \pi r^2 v^2}{4d}} }}\)

Thus;

b)The work done in separating the plates is equal to the magnitude of the energy change in the plates. This does not mean that the work done is equal to the change in the energy stored in the plates.

Answer:

I'm pretty sure it's A

Explanation:

bc the crest is is the point on the wave

The mass of the planet is  5.98 × 10^24 kg.

To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.

First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.

Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.

Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.

Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2

Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2

Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.

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Answer:

violate violate

Explanation:

sjaknamakakakaksjjdksoaokzkv

The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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The time taken by the object to reach the ground from the upper story of the school is 1.314 seconds. The impact of  velocity of the object is   29.07 m/s. The greatest distance from the surface that the object can have is 55.07 meters.

Acceleration is the rate of change in velocity. It is a vector quantity. The velocity of the falling object is 25 m/s and the distance to the ground is 3.65 × 9 = 32.85 meters.

Now, the time of flight  = distance / velocity

                                      = 32.85 m / 25 m/s

                                      = 1.314 s

The impact of speed = √2gh

                                   = √ (2 × 12.87 × 32.85 m)

                                   = 29.07 m/s.

The acceleration due to gravity is 12.87 m/s² and the time is obtained as 1.314 seconds with initial velocity of 25 m/s. Therefore, the final velocity is

v = u + at

   = 25 m/s + 12.87 × 1.314 s

   = 41.911 m/s

Hence the maximum distance with this velocity is = 41.911 × 1.314 s

= 55.07 m. Therefore, the maximum distance above the surface that the object can occupy is 55.07 m.

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