A sound signal traveling underwater has a frequency of 230 hertz. The speed of sound under water is 1. 45 × 103 meters/second. What is the wavelength of the sound signal? A. 6. 3 meters B. 2. 3 meters C. 3. 0 meters D. 1. 2 meters E. 9. 3 meters.

Assume that the electric field between two points that are 4 meters apart has a 14 volt/m potential. The electric potential between the two points is 460 w (in volts).

V =Er

= 67 X 13

V =871 volts

I =q/t=8/2

I=4 Amp

P=VI

230 X 2

P=460 W

A unit of electric charge must be moved from a reference point to a specific point in an electric field, and this amount of work energy is known as the electric potential. Against an electric field, the amount of work required to move a unit charge from one point to another is known as electric potential. Although any location outside the range of the electric field charge can be used, Earth is typically used as the reference point. The external effort required to move a charge from one location to another in an electric field is known as an electric potential difference, or voltage. A test charge that has an electric potential difference of +1 will experience a change in potential energy.

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If an air parcel is given a small push upward and it falls back to its original position, the atmosphere is said to be stable.

What happens to an air parcel as it descends?

The potential energy of the air molecules is similarly transferred back to kinetic energy as the air parcel decelerates. Rise in air temperature. A change is referred to as adiabatic if it occurs when a substance changes its state (pressure, volume, or temperature) without any heat being added to or removed from it.

What happens to a parcel of air as it rises up through the atmosphere?

The temperature of the air parcel decreases as it climbs due to the air parcel's expansion, or work. The parcel's humidity grows as it ascends until it reaches 100%. When this happens, extra water vapor condenses on the biggest aerosol particles, which leads to the formation of cloud droplets.

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Answer:

i donk know

Explanation:

The weight of the second object is 4.8 N.

Weight of first object, W₁ = 24 N

Weight of second object, W₂ = W

Distance of first object to center of mass, r₁ = 0.8 m

Distance of second object to center of mass, r₂ = 4 m

When a system exhibits no tendency to change further on its own, the forces on it are considered to be in equilibrium. External means must be used to bring about any additional change. If all forces operating on a body are added up, and is said to be zero, which is what translational equilibrium means.

The equation for equilibrium of force, is given by,

W₁r₁ = W₂r₂

Therefore, the weight of the second object,

W₂ = W = W₁r₁/r₂

W = 24 x 0.8/4

W = 4.8 N

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Answer:

ʕ •ᴥ•ʔ

Explanation:

Answer:

It depends on the model but these are the watts of each motor

Explanation:

Un motor: 258 HP (262 CV) Dual motor: 154 kW (209 CV) y 197 kW (268 CV). Performance: 154 kW (209 CV) y 225 kW (306 CV).

Answer:

40.90 mph if I did the math right

A trait shared by dolphins and bats  will be the need to move quickly through dark environments.

Our understanding of the evolution of echolocation in bats has shifted as a result of recent molecular phylogenies. These phylogenies imply that bats with advanced echolocation

According to one interpretation of these trees, laryngeal echolocation originated in the ancestor of all living bats. Echolocation may have been lost in Old World fruit bats

The vast adaptive radiation in echolocation call design is substantially controlled by ecology, demonstrating how environmental perceptual problems influence call design.

A trait shared by dolphins and bats that possibly led to the evolution of echolocation in these two animal groups will be the need to move quickly through dark environments.

Hence option A is correct.

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Answer:

D

Explanation:

Answer:

The correct answer is H ÷ ¹/₂T

Explanation:

The formula for velocity is distance covered ÷ time.

Neglecting air resistance;

If the ball's time of overall time flight is T, the time it will take for the second half/return trip is ¹/₂T.

If the ball's maximum height above its released point is H, the height will also be the distance it covered for the second part of the trip since the student caught the ball in the exact same place the ball was thrown. Hence, the distance for the second half of the trip will be H.

Since velocity = distance/time

The average velocity during the second half of the trip will be = H ÷ ¹/₂T

Cell membrane - It acts as a barrier for the inner and out environments of the cell and it controls what goes in and what comes out of the cell.

Nucleus - It stores genetic code or the instructions on how the cell should work. It also controls the metabolic reactions inside the cell.

Answer:

Fractional error = 0.17

Percent error = 17%

F = 112 ± 19 N

Explanation:

Plug in the values to find the force:

F = (3.5 kg) (20 m/s)² / (12.5 m) = 112 N

Find the fractional error:

ΔF/F = Δm/m + 2Δv/v + Δr/r

ΔF/F = 0.1/3.5 + 2(1/20) + 0.5/12.5

ΔF/F = 0.17

Multiply by 100% to find the percent error:

ΔF/F × 100% = 17%

Solve for the absolute error:

ΔF = 0.17 × 112 N = 19 N

Therefore, the force is:

F = 112 ± 19 N

Answer:

a wedge.

Explanation:

it moves when you apply force to one end of the wedge.

Answer:

what data table?

i can help if you attach a picture of the data :)

Answer:

equation average velocity = total distance

equation average velocity = total distance

Explanation:

Force = mass × acceleration

Now, keeping this formula in mind you can find the mass as follows;

= 35 = m × 3

= 35/3 = m

= 11.6 kg = m

And yeah its done!:)

The primary indicator of an object's position and speed is its velocity.It is the distance that an object travels in one unit of time.The displacement of the item in one unit of time is the definition of velocity.

Smax = 400 feet.

c) v = 32 ft/s

c) v = - 32 ft/s

(a)

The following is the function provided for ball height:

s = 160 t - 16 t²

Therefore, we must take the derivative with respect to t and make it equal to zero in order to get the time to reach maximum height (in-flexion point):

So, 160 - 32 t = 0, 32 t = 160 t, and 160/32 t = 5 sec.

As a result, the maximum distance is covered every 5 seconds.

Smax = (160)(5) - (16)(5)²

Smax = 800 - 400

Smax=400 feet

b)First, we determine the speed at which the ball travels 384 feet.

384 = 160 t - 16 t

16 t² - 160 t + 384 = 0

Quadratic Equation Solving:

Either:

t = 6 sec

or t = 4 seconds

Since it takes 5 seconds to reach the highest point,

t then equals 5 seconds.

t then equals 4 seconds.

Now, by taking a derivative of ods with respect to t at 4 sec, we can find velocity:

v = 160 - 32 t

v = 160 - (32)(4)

v = 32 ft/s

c,Because t = 6 s > 5 s

The second number of t = 6 sec must represent the point in the ball's downward motion when it is 384 feet above the earth.

So, at that moment, velocity will be:

v = 160 - (32)(6)

v = -32 ft/s

downward motion is a bad sign.

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The induced emf in the loop is  -1500 μ V or  - 0.0015 V  .

According to the question

A conducting loop in the form of a circle is placed perpendicular to a magnetic field of 0. 50 t.  

i.e

Magnetic field (B) = 0. 50 T

Area of circle or loop = \(\pi r^{2}\)  

Now,

The area of the loop decreases at a rate of 3. 0 × 10⁻³ m/s

i.e

dA = 3. 0 × 10⁻³ meter²

dt = 1 sec  

As per the formula of Induced e.m.f in the loop

emf is dependent on number of turns of coil, shape of the coil, strength of magnet and speed with which magnet is moved. Emf is independent of resistivity of wire of the coil.

\(e=-B*\frac{dA}{dt}\)

where A is the area of the loop.

Now ,

Substituting the values in the formula

\(e=-B*\frac{dA}{dt}\)

\(e= - 0.50 *\frac{ 3 * 10^{-3}}{1}\)    

e = - 0.0015 V

OR

e = -1500 * 10⁻⁶ V

e =  -1500 μ V

Negative just signifies emf will such be induced that current induced will oppose change in magnetic field though it

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Answer:

D

Explanation:

their octet is complete they don't react with any thing

Argon and krypton have similar properties, and they have a complete octet, which means that they do not react with anyone. Hence, option D is correct.

The phrase "inert gas" is a bit misleading because, in some circumstances, these gases can really be reactive. As a result, these gases are typically referred to as noble gases in the context of chemistry and materials science.

The term "noble" has historically been used in chemistry (and earlier in alchemy) to characterize the resistance of some metals to chemical reaction, and the term "noble gas" denotes the same resistance.

These are the inert gases which are mentioned in the periodic table.

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Answer:

3.6263736 * 10^-11 m

Explanation:

Considering the following equation,

λ = \(\frac{h}{mv}\)

where h = 6.6 * 10^-34 and m = mass, and v = velocity

λ = (6.6 * 10^-34)/(2 * 10^7 * 9.1 * 10^-31)

= 3.6263736 * 10^-11 m

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The maximum wind velocity for a 30° crosswind with a maximum crosswind component of 15 knots is 30 knots.

To determine the maximum wind velocity for a 30° crosswind when the maximum crosswind component for the airplane is 15 knots, follow these steps:

1. Identify the maximum crosswind component: 15 knots.
2. Determine the crosswind angle: 30°.
3. Use the formula: Wind velocity = Maximum crosswind component / sin(crosswind angle).

In this case:

Wind velocity = 15 knots / sin(30°)

The sine of 30° is 0.5, so:

Wind velocity = 15 knots / 0.5

Wind velocity = 30 knots

So, the maximum wind velocity for a 30° crosswind with a maximum crosswind component of 15 knots is 30 knots.

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the power of lens to see an object clearly that is 30.0 cm away is +1.67D.

This problem is known as hypermetropia the condition of the eyes where the image of a nearby object is formed behind the retina. Here, the light is focused behind the retina instead of focusing on the retina.

To treat hypermetropic eye, convex lens is used to focus the object in 30cm to the point 0.6m or 60cm.

which is near point in this case.

we have lens equation :- \((\frac{1}{v} ) - (\frac{1}{u} ) = \frac{1}{f}\)

where, v = lens to image distance = -60cm

           u = lens to object distance = -30cm

(cartesian sign convention is used for u and v )

by substituting value for u and v in lens equation we get ,

                                 \(\frac{1}{f} =-\frac{1}{60} +\frac{1}{30}\)

                                 \(\frac{1}{f} = 60cm\)

lens to be used is convex lens of focal length 60cm .

power of lens = \(\frac{1}{f}\)    ( put f in meter)

                         = \(\frac{1}{0.6}\)

                        =  + 1.67D

Thus from the above conclusion we can say that lens to be used is convex lens with power of  + 1.67D.

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The sun is Yellow, red, orange, and blue. Therefore option B is correct.

The star is moving toward an observer. Therefore option B is correct.

39. The type of radioactive decay represented by the equation provided Gamma. Therefore option A is correct.

40. The statement is completed correctly by the information which states that the coal in Alberta has a lower carbon content than coal in other parts of Canada, resulting in reduced greenhouse gas emissions.

29. graph B depicts the relationship between gravitational field strength and the mass of the International Space Station orbiting Earth.

30. The correct sequence of colors representing the changing temperature from the surface to the atmosphere of the sun is Yellow, red, orange, and blue. Therefore option B is correct.

1. When a star undergoes a blue shift, it indicates that the star is moving toward an observer. Therefore option B is correct.

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The equivalent resistance between points A and B in the diagram is 22 Ω

We shall begin by obtaining the equivalent resistance in parallel (i,e the three 6 Ω resistor). Details below:

1/Rₜ = 1/R₁ + 1/R₂ + 1/R₃

1/Rₜ = 1/6 + 1/6 + 1/6

1/Rₜ = 3/6

1/Rₜ = 1/2

Rₜ = 2 Ω

Finally, we shall determine the equivalent resistance between A and B (i.e series arrangement). Details below:

R = R₁ + R₂ + R₃ + R₄ + R₅ + R₆ + R₇ + R₈ + R₉ + R₁₀ + R₁₁

R = 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2

R = 22Ω

Thus, we can conclude that the equivalent resistance is 22 Ω

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(b) 0.10 m.The smallest amplitude occurs when there is destructive interference, which happens when two waves meet in anti-phase with each other.(a) 0.50 m.

The wave's highest displacement is its amplitude.Two waves that interfere with one another have a resultant amplitude that is equal to the sum of their respective displacements at the same point also as resultant wave's amplitude.

When two waves collide while moving across the same medium, wavelet is the result.The medium assumes a shape as a result of the net impact of the two distinct waves on the medium's particles due to wave interference.

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Answer:

In chaos theory , the butterfly effect is the sensetive dependence on initial conditions in which a small change in one state of a deterministic nonlinear can result in large difference in a letter state.

The velocity of a golf ball with a mass of 47 g and the kinetic energy of a golf ball is measured to be 143 J is 2.44 m/s.

The kinetic energy is the energy obtained when the body is in motion. The kinetic energy equals half of the product of mass and the square of the velocity of the object. The velocity is a vector quantity that defines the speed with a particular direction and the unit of velocity is m/s. The unit of kinetic energy is Joule (J).

From the given,

the mass of a golf ball = 47 g = 0.047 kg

the kinetic energy = 143 J

the velocity of a golf ball =?

K.E = 1/2 (mv²) where m is the mass and v is the velocity.

v² = 143×2 / 0.047

   = 286 / 0.047

  = 6085.10

v² = 6085.1

v = √6

  = 2.44

v = 2.44 m/s.

Thus, the velocity of a golf ball is 2.44 m/s.

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Answer:

Thermal energy can be transferred globally through various methods, including conduction, convection, and radiation.

Conduction is the transfer of thermal energy through direct contact between objects. When two objects with different temperatures are in direct contact, heat will flow from the warmer object to the cooler object until both objects reach thermal equilibrium.

Convection is the transfer of thermal energy through the movement of fluids or gases. When a fluid or gas is heated, it becomes less dense and rises, while cooler fluids or gases sink. This creates circulation patterns that can transfer heat from one location to another.

Radiation is the transfer of thermal energy through electromagnetic waves. All objects with a temperature above absolute zero emit electromagnetic radiation, and this radiation can be absorbed by other objects, transferring heat.

Thermal energy can also be transferred globally through the use of heat pumps, which use electricity to move heat from one location to another. Heat pumps can be used to heat buildings in cold climates and to cool buildings in hot climates.

Explanation:

There are three ways heat is transferred into and through the atmosphere:

Hi there!

We can use Newton's Second Law to solve:

\(\large\boxed{\Sigma F = ma}}\)

∑F = Net force (N)

m = mass (kg)

a = acceleration (m/s²)

Rearrange the equation to solve for acceleration:

\(\large\boxed{a = \frac{F}{m}}\)

Plug in the values given to solve for the magnitude of the force.

\(a = \frac{95.4}{16} = \boxed{5.96 m/s^2 \text{ To the left}}\)

**However, if we want to assign the left direction to be NEGATIVE, then the acceleration of the cart due to a leftward net force would be -5.96 m/s².

The final image is formed 30.0 cm (or 0.3 m) from the opposite end of the tube, where two thin lenses with 10.0-cm focal lengths are mounted at opposite ends of a 30.0-cm long tube and an object is located 45.0 cm from one end of the tube.

To solve this problem, we need to find the position of the final image using the lens formula and the given information. The lens formula is:

1/f = 1/do + 1/di

Where f is the focal length, do is the object distance, and di is the image distance. Since there are two lenses, we'll have to use this formula twice.

For the first lens (f1 = 10.0 cm), the object is located 45.0 cm away (do1 = 45.0 cm). Using the lens formula:

1/10 = 1/45 + 1/di1
Solving for di1, we get di1 = 18.0 cm.

Now, the second lens (f2 = 10.0 cm) is mounted at the opposite end of the 30.0 cm long tube, so the distance between the lenses is 30.0 cm. Since the image distance of the first lens is 18.0 cm, the object distance for the second lens (do2) is 30.0 - 18.0 = 12.0 cm.

Using the lens formula for the second lens:

1/10 = 1/12 + 1/di2
Solving for di2, we get di2 = 60.0 cm.

The final image is 60.0 cm from the second lens, which is at the opposite end of the 30.0 cm tube. Therefore, the final image is 60.0 - 30.0 = 30.0 cm from the opposite end of the tube.

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