A solution with a pOH of 4.3 has a [H+] of ??
please help

The solid commonly used as an inactive electrode in electrochemical cells is Graphite. So option b is the correct answer.

Graphite is often chosen as an electrode material because it is chemically inert, highly conductive, and has a stable structure. This makes it suitable for various electrochemical applications without affecting the overall cell reactions.

An inactive electrode, also known as an inert electrode, is an electrode that does not participate in the chemical reaction occurring in the cell but serves as a conductor for the flow of electrons.

The graphite working electrode, which can be employed as an anode or a cathode in various electrochemical applications, is renowned for its chemical stability, superior electrical conductivity, and high melting point.

So the correct answer is option b. Graphite.

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Answer:

The bag of skin that holds and helps to protect the testicles. The testicles make sperm

Explanation:

Answer:

V ≈ 16,662.63 L

Explanation:

The data given in the question includes;

The pressure in the medium, P = 1.23 mmHg

The number of moles of the substance present in the medium, n = 0.773 mol

The temperature of the substance in the medium, T = 152 °C = 425.15 K

The unknown quantity, V = The volume filled by the substance

The ideal gas law equation that can be used to find the unknown volume is given here as follows;

P × V = n × R × T

Where;

R = The Universal Gas Constant = 62.363 mmHg·L·mol⁻¹·K⁻¹

From the ideal gas law equation, we get;

V = n × R × T/P

Plugging in the values, gives;

V = 0.773 mol × 62.363 mmHg·L·mol⁻¹·K⁻¹ × 425.15 K/(1.23 mmHg) = 16,662.6305405 L

The volume occupied, which is the unknown quantity, V ≈ 16,662.63 L.

Answer:

a. 5 8/100 is equivalent to $ 5.08.

Explanation:

i hope this helps :)

Answer:

2H2S + 3O2 --> 2H2O + 2SO2

2 mol H2S/8 mol H2O = 0.25 mol

Explanation:

Reactants: H is 2; S is 1; O is 2

Products: H is 2; S is 1; O is 3

There are 3 oxygens so add a 2 to the H2O e and 3 to the reactants side.

H2S + 3O2 → 2H2O + SO2

Reactant side: H is 2; S is 1; O is 6

Product side: H is 4; S is 1; O is 4

Hydrogen is now out of balance, so a coefficient of 2 can be placed in front of H2S to give:

2H2S + 3O2 → 2H2O + SO2

Reactant side: H is 4; S is 2; O is 6

Product side: H is 4; S is 1; O is 4

Sulfur is unbalanced, so a coefficient of 2 can be placed in front of SO2 to give:

2H2S + 3O2 → 2H2O + 2SO2

Answer:

\(\boxed {\boxed {\sf 1290 \ g \ PI_3}}\)

Explanation:

We want to convert from moles to grams, so we must use the molar mass.

The molar mass is the mass of 1 mole of a substance. It is the same as the atomic masses on the Periodic Table, but the units are grams per mole (g/mol) instead of atomic mass units (amu).

We are given the compound PI₃ or phosphorus triiodide. Look up the molar masses of the individual elements.

Note that there is a subscript of 3 after the I in the formula. This means there are 3 moles of iodine in 1 mole of the compound PI₃. We should multiply iodine's molar mass by 3, then add phosphorus's molar mass.

Use the molar mass as a ratio.

\(\frac {411.687262 \ g \ PI_3}{ 1 \ mol \ PI_3}\)

We want to convert 3.14 moles to grams, so we multiply by that value.

\(3.14 \ mol \ PI_3 *\frac {411.687262 \ g \ PI_3}{ 1 \ mol \ PI_3}\)

The units of moles of PI₃ cancel.

\(3.14 *\frac {411.687262 \ g \ PI_3}{ 1 }\)

\(1292.698 \ g\ PI_3\)

The original measurement of moles has 3 significant figures, so our answer must have the same. For the number we calculated, that is the tens place.

The 2 in the ones place tells us to leave the 9.

\(1290 \ g \ PI_3\)

3.14 moles of phosphorous triiodide is approximately equal to 1290 grams of phosphorus triodide.

Answer: A! The soup will become saltier because evaporation removes the water and leaves the salt behind.

Explanation:

Just finished the test and got a 90%! <3

Answer:

A

Explanation:

The enthalpy of the reaction is 14 J/mol.

The enthalpy of a reaction (ΔH) is the amount of energy transferred between a system and its surroundings during a chemical reaction at constant pressure, measured in joules per mole (J/mol). This value is important because it can tell us whether a reaction is exothermic or endothermic, as well as give us information about the strength of chemical bonds within the reactants and products.To calculate the enthalpy of a reaction, we need to know the amount of energy released or absorbed (Q) and the number of moles of the compound involved in the reaction (n). We can use the equation:
ΔH = Q/n
Given that 6 moles of a compound produce 84 J of energy, we can calculate the enthalpy of the reaction as follows:
ΔH = Q/n
ΔH = 84 J / 6 mol
ΔH = 14 J/mol
This means that for every mole of the compound involved in the reaction, 14 J of energy is transferred between the system and the surroundings. Since the value is positive, we can conclude that the reaction is endothermic, meaning that it requires an input of energy to occur.It is worth noting that the enthalpy of a reaction can depend on a number of factors, such as temperature, pressure, and the specific conditions under which the reaction occurs. As such, it is important to take these factors into account when calculating or predicting enthalpy values.

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0.0174 M is the calculated [H₃O+] for 0.0087 M H₂SO₄.  Molarity is an important concept in chemistry.

Molarity, which is defined as the number of moles of solute dissolved per liter of solution, is a measure of a solution's concentration. It is often written with the symbol "M" and is measured in moles per liter (mol/L) units.

The molarity of a solution is determined by dividing the volume of the solution in liters by the number of moles of the solute present in that volume. because it allows us to quantify the amount of substance present in a solution. It is frequently used in stoichiometric calculations to determine the amounts of a chemical reaction's reactant and product that should be known. For instance, if a solution contains 2 moles of solute dissolved in 1 liter of solution, the molarity of the solution is 2 mol/L.

Because it fully dissociates in water, H₂SO₄ is a powerful acid that produces two H+ ions for every molecule that dissociates. As a result, the [H₃O+] in a solution of 0.0087 M H₂SO₄ is twice as molten as the H₂SO₄ solution: [H₃O+] = 2 x [H+] = 2 x 0.0087 M = 0.0174 M.

Accordingly, the [H₃O+] of a H₂SO₄ solution containing 0.0087 M is 0.0174 M.

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Answer:

Water, Ethonal, Ammonia, Sulfur Dioxide, and hydrogen sulfide.

The oxidation state of Ca in CaSO₄ is +2. The charge of the whole group SO₄ is -2. The charge of S is +6 and that of O is -2.

The oxidation state of a species is the numerical charge it possess. Thus, it is the number of electrons the element lost or gained. The total charge of a compound will be zero and every compound tends to exist as neutral.

The total charge of the compound CaSO₄ is zero and that of SO₄ is -2. Hence, to neutralize that Ca lose 2 electrons and form in +2 oxidation state.

The charge of one oxygen is -2. Here we have 4 oxygens and the total charge of all oxygens is -8 in the group SO₄.

Now, the charge of S = (-2) - (-8) = +6. Hence, the oxidation state of sulphur is +6.

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Answer

449.4 grams

Explanation

The balanced chemical equation of the reaction is;

From the balanced chemical equation;

3 moles of H₂ reacted with 1 mole of N₂ to produce 2 moles of NH₃

Molar mass of H₂ = 2.016 g/mol

Molar mass of N₂ = 28.0134 g/mol

Molar mass of NH₃ = 17.031 g/mol

Convert mole to gram using the formula;

For 1 mole N₂

For 3 moles H₂

For 2 moles NH₃

We can now calculate, the mass of NH₃ that can be produced from 79.8 grams of H₂ as follows:

From the balanced equation we can say;

6.048 grams H₂ → 34.062 grams NH₃

∴ 79.8 grams H₂ → x grams NH₃

Therefore, 449.4 grams of Ammonia is produced if you started with 79.8 grams of Hydrogen.

The melting point of 4-cyclohexene-cis-1,2-dicarboxylic anhydride (often abbreviated as "4-cylohexene-1,2-dicarboxylic anhydride") is approximately 102-103 °C.

The typical definition of the melting point is the temperature at which a substance transforms from a solid to a liquid. The melting point of a liquid is the temperature at which the liquid transforms from a solid to a liquid under atmospheric pressure. This is the location where the liquid and solid phases are equally present.

The temperature at which molecules in a solid can pass one another and transform into a liquid is known as the melting point. On the other hand, liquids and gases are involved in the boiling point.

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Answer:

fractional distillation

In order to answer the question first we must write the atomic number of each element:

Zirconium (Zr): 40

Cadmium (Cd): 48

Iridium (Ir): 77

Iron (Fe): 26

Then, we have to complete the distribution of electrons in each orbital for each atom:

The first 4 levels have the following distribution:

Level1: 1s

Number of electrones: 2

Level 2: 2s, 2p

Number of electrones 8 (2 in the s orbital and 6 in the p orbitals).

Level3: 3s, 3p, 3d

Number of electrones 18 (2 in the s orbital, 6 in the p orbital and 10 in the d orbitals)

Level 4: 4s, 4p, 4d, 4f

Number of electrones 32 (2 in the s orbital, 6 in the p orbitals, 10 in the d orbitals and 14 in the f orbitals)

The order in which the orbitlas are completed depends on the energy of each level. For example the 4s orbitals will be completed before the 3d orbitals because their energy is lower.

The order is as follows:

1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p...

Now, knowing the atomic number we can answer the question:

For Zirconium (total 40 electrones):

2 electrones are predicted in the 4d orbital

For Cadmium (total 48 electrones):

10 electrones are predicted in the 4d orbital

For iridium, as it has an atomic number higher than Cadmium we can predict tha it also complets the 4d orbital, then it has also 10 electrones in it.

For iron (total 26 electrones)

Iron has no electrones in the 4d orbitals

2 moles of solute dissolved in 1 liter of solution has the greatest concentration.

Concentration refers to the quantity of solute that is dissolved in a specific amount of solution, and it is commonly measured in units such as moles per liter or grams per liter.

To determine which solution has the greatest concentration, we need to calculate the number of moles of solute present in each solution and then compare the values.

a. Concentration = 2 moles / 1 liter = 2 M

b. Concentration = 0.3 moles / 0.6 liters = 0.5 M

c. Concentration = 2 moles / 10 liters = 0.2 M

d. Concentration = 0.1 moles / 0.5 liters = 0.2 M

Comparing the concentrations, we see that solution (a) has the greatest concentration of 2 M, while the other solutions have concentrations of 0.5 M or lower.

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The force exerted by the gas on the piston in newtons (N) is 38503.5N.

Pressure is the amount of force that is applied over a given area divided by the size of this area.

This means that the pressure can be calculated as follows:

P = F/A

Where;

According to this question, in a car piston, the pressure of the compressed gas (red) is 5.00 atm. If the area of the piston is 0.0760 m², the force exerted can be calculated as follows:

506625N/m² = F/0.0760m²

F = 38503.5N

Therefore, the force in Newtons is 38503.5N.

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Answer:

yes

Explanation:

please take to 8 glasses of water everyday

Heat transfers from object A to object B, because molecules from A collide with those from B. Option 1.

Heat always flows from an object at a higher temperature to an object at a lower temperature. When two objects at different temperatures are in contact with each other, their molecules collide, and this collision transfers energy from the hotter object to the colder object.

As a result, the hotter object loses heat, and the colder object gains heat. This process will continue until the two objects reach thermal equilibrium, meaning that they have the same temperature and there is no more net heat transfer between them.

Therefore, in the given scenario, object A, which is hotter, will transfer heat to object B, which is colder, as the molecules from object A collide with those from object B.

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Answer:

Heat transfers from object A to object B, because molecules from A collide with those from B.

Explanation:

A total of 12,552 joules of heat energy will be given off when 120 grams of water are cooled from 0°C to -25°C.

The specific heat capacity of water is 4.184 J/g·°C.

To calculate the amount of heat energy released, we can use the formula:Q = mcΔTwhere Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

ΔT = (0 - (-25)) = 25°CQ

= (120 g)(4.184 J/g·°C)(25°C)Q

= 12,552 J

The formula for calculating the amount of heat energy released during the cooling process of water is Q = mcΔT. Here, Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. We are given the mass of water and the initial and final temperatures.

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because of its milk-like appearance. ... Since the dissociation of this small amount of dissolved magnesium hydroxide is complete, magnesium hydroxide is considered a strong electrolyte. Its low solubility makes it a weak base.

Answer:

decomposition

Explanation:

the reactants turn into two different products, thus the reaction is decomposition.

AB -> A + B

Answer:

A: a decomposition reaction in which a metal is reduced

Explanation:

HgO is actually the metal Mercury and in the equation Mercury is being decomposed into the elements Hg and O. (the element for Mercury and Oxygen) So the equation they give you is a decomposition.

Determine the basis's mass (1 litre of solution) Mass = d V; d = mass / V mass = 1,000 ml/litre x 1,000 g/liter x 1 litre = 1006 g

Acetic acid makes up 3.26% of vinegar. Step 1: Information is provided Sample weight: 5.54 grammes. NaOH volume: 30.10 m. NaOH has a molarity of 0.100M. Step 2: The equation with a balance. NaOH + CH3COOH = CH3COONa + H2O. Step 3: Determine the moles of NaOH/. Volume * Molarity = Moles of NaOH. NaOH moles = 0.03010 L * 0.100M. Moles of NaOH equal 0.00301 moles of NaOH. Step 4: Determine the moles of CH3COOH. For 1 mol NaOH, 1 mol CH3COOH is required. For 0.00301 moles of NaOH, 0.00301 moles of CH3COOH are required. Step 5: Determine the mass CH3COOH. Mass CH3COOH is equal to the sum of its moles and molar masses. The mass of CH3COOH is 0.00301 moles times 60.05 g/mol.m CH3COOH mass equals 0.1808 grammes. Calculate the acetic acid percentage by weight. Mass % = (0.1808 / 5.54 ) *100% Mass % = 3.26 %.

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Answer:

Approximately \(1.92\).

Explanation:

The \({\rm pH}\) of a solution is the opposite of the base-\(10\) logarithm of that solution's \({\rm H^{+}}\) concentration measured in \({\rm mol \cdot L^{-1}}\). In other words:

\({\rm pH} = - \log_{10} ([{\rm H^{+}])\).

Using properties of logarithms:

\(\begin{aligned}{\rm pH} &= - \log_{10} ([{\rm H^{+}]) \\ &= -\left(\frac{\ln([{\rm H^{+}]})}{\ln(10)}\right)\end{aligned}\).

In this question, \([{\rm H^{+}}] = 1.2 \times 10^{-2}\; {\rm mol \cdot L^{-1}}\). Therefore:

\(\begin{aligned}{\rm pH} &= - \log_{10} ([{\rm H^{+}]) \\ &= -\left(\frac{\ln([{\rm H^{+}]})}{\ln(10)}\right) \\ &= - \frac{\ln(1.2 \times 10^{-2})}{\ln(10)} \\ &\approx 1.92\end{aligned}\).

By convention, the number of decimal values in the \({\rm pH}\) should be equal to the number of significant figures in the \({\rm H^{+}}\) concentration of the solution.

In this question, there are two significant figures in the measurement\([{\rm H^{+}}] = 1.2 \times 10^{-2}\; {\rm mol \cdot L^{-1}}\). Thus, the \({\rm pH}\) result should be rounded to two decimal places.

Answer:

its B

Explanation:

The experimental value for the enthalpy of combustion will be lower than the true value.

There may be other causes, but the calorimeter itself is the most frequent one. The calorimeter is typically not completely insulated, unless it is an industrial model, allowing some heat to escape. The heat of combustion is subsequently underestimated because this heat is not recorded as a rise in temperature.

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The standard enthalpy change for reaction (3) is 117.1 kJ.

The standard enthalpy change for reaction (3) can be calculated by using the enthalpy changes of reactions (1) and (2) and applying Hess's Law.

To do this, we need to manipulate the given equations so that the desired reaction (3) can be obtained.

First, we reverse reaction (1) to get the formation of C2H4(g) from C2H6(g):

C2H4(g)C2H6(g) ΔH° = -52.3 kJ

Next, we multiply reaction (2) by 2 and reverse it to obtain 2 moles of C2H6(g) reacting to form 3 moles of H2(g):

2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

Now, we add the two modified equations together:

C2H4(g)C2H6(g) ΔH° = -52.3 kJ
2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

When adding these equations, the C2H6(g) on the left side cancels out with the C2H6(g) on the right side, leaving us with the desired reaction (3):

C2H4(g) + H2(g)C2H6(g) ΔH° = -52.3 kJ + 169.4 kJ = 117.1 kJ

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