A small model car with mass m travels at constant speed on the inside of a track that is a vertical circle with radius r = 11.0 m (Figure 1). The normal force exerted by the track on the car when it is at the bottom of the track (point A ) is equal to 2.50mg .

The principal stresses and corresponding principal directions for the stresses in a problem can be found using various methods, one of which is Mohr's circle.

What is Mohr's circle?

Mohr's circle is a graphical representation of a two-dimensional stress state. Given the stress tensor components, the Mohr's circle can be used to visualize and determine the maximum and minimum normal stresses (i.e., the principal stresses) and the orientation of the planes on which they act (i.e., the principal directions).

It is important to note that finding the principal stresses and directions requires a thorough understanding of stress analysis, including stress transformation and the use of Mohr's circle. If you have access to the full problem statement, I would be happy to help you work through the solution.

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ANSWER

122.5N per hand

EXPLANATION

First, we have to draw a free body diagram,

A wheelbarrow is an example of a lever but in this case, both forces are on the same side of the pivot - which is the wheel. To keep the wheelbarrow in balance, the output force, Fo, must be equal to the weight of the wheelbarrow,

Using the mechanical advantage relation between the input and output forces and the lever arms,

We have to find Fi. To solve for Fi, first raise both sides to the exponent of -1 - in other words, flip both fractions,

And multiply both sides by Fo,

The output force is the one found before, 980N. Then, the length of the lever arm of the output force is the distance from the center of gravity to the wheel, 0.5m, and the length of the lever arm of the input force is the distance from the man's hands to the wheel, 2m,

The total force the man has to make is 245N. Assuming each hand can support the same weight, then each hand should be doing 122.5N of force to keep the wheelbarrow in balance.

Average velocity of man is 2 m/s

Given that;

Distance between tree and house = 16 m

Time taken = 8 seconds

Find:

Average velocity

Computation:

Average velocity = Total distance cover / Time taken

Average velocity = Distance between tree and house / Time taken

Average velocity = 16 / 8

Average velocity = 2 m/s

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Answer:

The Answer is C. the student changed too many variables.

Explanation:

For the quiz in K12

a)The speed of the ball at the time of impact will be 8.1 m/sec.

b)The time taken by the ball impacts the surface of trampoline will be 1.1 second.

Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. Its SI unit is m/sec.

Given data;

g( gravitational acceleration) = 9.81 m/s2

u (initial velocity of ball) = 2.5 m/s

h₁(initial height of the ball) = 3.0 m

v (speed of the ball at the time of impact ) ?

The time taken by ball for upward journey = u / g

t₁ = u / g

t₁  = (2.5 m/s) / (9.81 m/s2) =

t₁  =0.2548 s

From second equation of motion,upward vertical distance covered by ball is;

\(\rm h_2= \frac{1}{2} gt^2\\\\ h_2=\frac{1}{2} \times 9.81 \times (0.2548)^2\\\\ h_2=0.3184\)

The total distance in the downward direction travelled;

\(\rm h_3=h_1+h_2 \\\\ h_3=3.0+0.3184 \\\\ h_3=3.3184 \ m\)

The time taken for the downward motion is;

\(\rm t_2 = (\frac{2 \times h_3 }{g} )^\frac{1}{2}\\\\ t_2 = 0.825 \ m/sec\)

The speed of the ball at the time of impact is found as;

\(\rm V=gt_2 \\\\ V= 9.81 \times 0.8225 \\\\ V= 8.07 \ m/sec\)

The total time of the flight of ball is;

\(\rm t_3 = t_1+t_2 \\\\ t_3=0.2548+0.8225 \\\\ t_3=1.0774 \ sec\)

Hence,the speed of the ball at the time of impact will be 8.1 m/sec and time taken by the ball impacts the surface of trampoline will be 1.1 second.

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(a) When you apply a force of 40 N, the magnitude of the horizontal component of the force that the floor exerts on the block is 51 N.

(b) When you apply a force of 59 N, the magnitude of the horizontal component of the force that the floor exerts on the block is 51 N.

The horizontal component of the force that the floor exerts on the block is determined by applying Newton's second law of motion;

\(F = ma\)

\(\Sigma F = 0\\\\F - F_f = 0\\\\F = F_f\)

\(F_f = F\\\\F_f = 51 \ N\)

where;

Since the surface (floor) is constant, the frictional force (horizontal component of the force that the floor exerts on the block ) will be the same on the cases.

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Based on the definition of limiting frictional force;

Force is any push or pull effect which tends to cause a change in the motion or shape of an object.

Based on Newton's third law, every force produces an equal and opposite reaction.

Therefore, the force that the floor exerts on the block is oppositely direction to the force exerted by the horizontal force acting on the block.

Since a horizontal force of 51 N applied to the block is required to keep the block moving across the floor at a constant speed, this is the limiting frictional force.

a) when a force of 40 N is applied to the block, the magnitude of the horizontal component of the force that the floor exerts on the block is equal to 40 N

b) when a force of 59 N is applied to the block, the magnitude of the horizontal component of the force that the floor exerts on the block is equal to 51 N, the limiting frictional force.

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A father and son push a 500 kg car for 5 minutes using a force of 50 N, but the car does not move.

Hence, the correct option is A.

The work done is equal to the force applied multiplied by the distance moved in the direction of the force.

In this case, the car does not move, so the distance moved is zero. Therefore, the work done by the father and son pushing the car is

Work = Force x Distance

Work = 50 N x 0 m

Work = 0 Joules (J)

Work = 0 J

Hence, the correct option is A.

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Answer:

Force (P) : Positive

Normal Force (Fn) : Zero

Weight (mg) : Zero

Kinetic Frictional Force (fk) : Negative

Explanation:

The work done by a force on an object is given by the following formula:

W = F.d

W = F d Cosθ

where,

W = Work Done

f = Force Applied

d = displacement

θ = Angle between force and displacement

FOR FORCE (P):

Since, force P is parallel to the motion of the box. Therefore, θ = 0°

Hence,

W = P d Cos 0°

W = P d(1)

W = Pd

Therefore, work done by force (P) is Positive.

FOR NORMAL FORCE (Fn) AND WEIGHT (W):

Since, normal force and weight are perpendicular to the motion of the box. Therefore, θ = 90°

Hence,

W = Fn d Cos 90°= mg d Cos 90°

W = Fn d(0) = mg d (0)

W = 0

Therefore, work done by Normal Force (Fn) and Weight (mg) is Zero.

FOR KINETIC FRICTIONAL FORCE (fk):

Since, kinetic frictional force acts in the opposite direction of motion of the box. Therefore, θ = 180°

Hence,

W = fk d Cos 180°

W = fk d(-1)

W = -fk d

Therefore, work done by Kinetic Frictional Force (fk) is Negative.

Answer:

B:A

Explanation:

because the alphabet goes

A B C D E F G

Answer: B.) A

This was a little complicated because of the answer letters LOL

Answer:

visualizing

Explanation:

You are imagining yourself doing it, using the image in your head and the steps you read to figure out what to do first, next, last.

Answer:

Brakes unevenly adjusted: Brakes pulling in one direction or the other can lead to a skid. Tires with worn tread: Tread is necessary for traction in wet weather

Explanation:

Answer: exhaust pipe

Explanation: It doesn't really control anything so I'm assuming this is the answer

A rectangular container measuring 19 cm x 51 cm x 62 cm is filled with water. The mass of this volume of water in kilograms is  60.4 kilograms (kg).

To calculate the mass of water in the rectangular container, we need to multiply the volume of water by the density of water.

1. Volume of water:

The volume of the rectangular container is given as:

Length (L) = 19 cm

Width (W) = 51 cm

Height (H) = 62 cm

The volume of water (V) is calculated as:

V = L × W × H

Converting the dimensions to meters:

L = 19 cm = 0.19 m

W = 51 cm = 0.51 m

H = 62 cm = 0.62 m

V = 0.19 m × 0.51 m × 0.62 m

V ≈ 0.0604 cubic meters (\(m^3\))

2. Density of water:

The density of water (ρ) is approximately 1000 kilograms per cubic meter (kg/\(m^3\)).

3. Mass of water:

Mass (m) = Volume × Density

m = 0.0604 m^3 × 1000 kg/\(m^3\)

m = 60.4 kilograms (kg)

Therefore, the mass of the volume of water in the rectangular container is approximately 60.4 kilograms (kg).

It's important to note that the density of water can vary slightly depending on temperature and impurities, but for most practical purposes, a density of 1000 kg/\(m^3\)is commonly used.

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Answer:

Iron or steel

Explanation:

because both metals show permanent magnetic properties

Answer:

strongest are at the points of the north pole and the south pole, specifically between the red box and the letter of each pole.

Explanation:

The lines of magnetic force are drawn so that the density of lines is proportional to the intensity of the magnetic field.

Therefore, the sections where the magnetic field is strongest are at the points of the north pole and the south pole, specifically between the red box and the letter of each pole.

Answer:

Not quite

Explanation:

The frequency of a wave is inversely proportional to its wavelength. That means that waves with a high frequency have a short wavelength, while waves with a low frequency have a longer wavelength

What determines the strength of a wave?

Wave height is affected by wind speed, wind duration (or how long the wind blows), and fetch, which is the distance over water that the wind blows in a single direction. If wind speed is slow, only small waves result, regardless of wind duration or fetch.

So,

As Wavelength increases, The energy of the wave spreads and it decreases

Answer:

B. carry a single circuit and are placed in individual cases.

Explanation:

An electric circuit can be defined as an interconnection of electrical components which creates a path for the flow of electric charge (electrons) due to a driving voltage.

Generally, an electric circuit consists of electrical components such as resistors, capacitors, battery, transistors, switches, inductors, etc.

Similarly, an integrated circuit (IC) also referred to as microchip can be defined as a semiconductor-based electronic component that comprises of many other tiny electronic components such as capacitors, resistors, transistors, and inductors.

Integrated circuits (ICs) are often used in virtually all modern electronic devices to carry out specific tasks or functions such as amplification, timer, oscillation, computer memory, microprocessor, etc.

A wafer can be defined as a thin slice of crystalline semiconductor such as silicon and germanium used typically for the construction of an integrated circuit.

In an integrated circuit, each wafer is cut into sections, which generally comprises of a single circuit that are placed in individual cases.

Additionally, a semiconductor can be defined as a crystalline solid substance that has its conductivity lying between that of a metal and an insulator, due to the effects of temperature or an addition of an impurity.

Answer: B got it right on the test just now

Explanation:

We are given the weight of two people, one on the moon and the other on earth. To determine the mass we will use the following formula:

Where:

Now, we solve for the mass "m" by dividing both sides by "g":

Now, for the case of the moon we have that the acceleration of gravity is:

Plugging in the values:

Solving the operations:

Now, for the case of the earth we have:

Plugging in the values:

Solving the operations:

Therefore, the greater mass is the mass of Bob.

Knowing the exits are exactly 7 km apart, the cars pass each other at 9:29 and 15 seconds a.m.

The relative velocity of the cars is 30 m/s - 26 m/s = 4 m/s.

The distance between the cars is 7 km = 7000 m.

The time it takes for the cars to pass each other is 7000 m / 4 m/s = 1750 seconds.

1750 seconds is 29 minutes and 15 seconds.

To calculate the time in minutes;

Let:

v_p = the speed of car P (m/s)

v_q = the speed of car Q (m/s)

d = the distance between the cars (m)

t = the time it takes for the cars to pass each other (s)

Given that:

v_p = 30 m/s

v_q = 26 m/s

d = 7000 m

Use the equation for relative velocity to find the velocity of the cars relative to each other:

v_r = v_p - v_q

v_r = 30 m/s - 26 m/s = 4 m/s

Use the equation for distance to find the time it takes for the cars to pass each other:

d = v_r × t

7000 m = 4 m/s × t

t = 7000 m / 4 m/s = 1750 s

Convert 1750 seconds to minutes and seconds:

1750 s = 29 minutes and 15 seconds

Therefore, the cars pass each other at 9:29 and 15 seconds a.m.

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That depends on the circle's radius, which you neglected to mention.

If the radius is 1 meter, then an arc of 3.05 degrees is 5.32 centimeters long.

If the radius is 1 kilometer, then an arc of 3.05 degrees is 53.2 meters long.

A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.

To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).

The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:

E_initial = KE_initial + PE_initial

The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:

E_final = KE_final + PE_final

The nonconservative work done on the boy is equal to the change in mechanical energy:

Work_nonconservative = E_final - E_initial

Let's calculate each term:

KE_initial = (1/2) * m * v_initial^2

= (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = m * g * h_initial

= 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * m * v_final^2

= (1/2) * 66.1 kg * (8.51 m/s)^2

PE_final = m * g * h_final

= 66.1 kg * 9.8 m/s^2 * 0

Since the boy ends at ground level, the final potential energy is zero.

Substituting the values into the equation for nonconservative work:

Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)

Simplifying:

Work_nonconservative = KE_final - KE_initial - PE_initial

Calculating the values:

KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2

Substituting the values:

Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]

Calculating the result:

Work_nonconservative ≈ -42.7 kJ

Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.

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Answer:

I'll try my utmost best to get the most out of life...I'd do the things have always wanted to do

Sometimes it might get to me knowing fully well that in two years time the world will end but i will shake it off because the time i spend thinking about it...It will be enough to make some memories.

Hope this help anyways

Answer:

In the taller, skinnier cylinder, each tick mark represents 2, while in the larger one, each tick mark represents 50.

Explanation:

If you count the tick marks between each big number, then you can divide, and figure out what amount each tick mark represents.

Who has so much time to measure the fμcking seeds?

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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The magnitude of the resulting angular acceleration about the pivot point is approximately 0.0021 rad/s^2.

To solve this problem, we need to use the equation for the torque on a rigid body:

τ = Iα

where τ is the torque, I is the moment of inertia, and α is the angular acceleration. We can also use the fact that the torque is given by:

τ = r × F

where r is the vector from the pivot point to the point of application of the force, and F is the force. The vector cross product r × F gives the torque about the pivot point.

First, we need to find the vector r. Since the force is acting at an angle of 95° to the horizontal, the vertical component of the force is given by:

Fy = F sin(95°) = 1.5 sin(95°) ≈ 0.15 N

The horizontal component of the force is given by:

Fx = F cos(95°) = 1.5 cos(95°) ≈ 0.04 N

The vector r points vertically downward from the pivot point and has a magnitude equal to half the length of the rod:

|r| = 0.5(1.9 m) = 0.95 m

Therefore, the vector r is given by:

r = -0.95j

where j is the unit vector in the vertical direction.

The torque about the pivot point is given by:

τ = r × F = (-0.95j) × (0.04i + 0.15j) = -0.15k

where i is the unit vector in the horizontal direction and k is the unit vector in the direction perpendicular to the plane of the rod and pointing out of the page.

Substituting the moment of inertia and torque into the equation for angular acceleration, we have:

α = τ/I = (-0.15k)/(930.02/12) ≈ -0.0021 rad/s^2

Therefore, the magnitude of the resulting angular acceleration about the pivot point is approximately 0.0021 rad/s^2.

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Answer:

Explanation:

To solve this problem, we will use vector addition. We can represent the dog's displacement as two vectors: one that points north of east, and another that points directly south. Let's call the first vector A and the second vector B.

a.) The distance from home is the magnitude of the total displacement vector, which we can find by adding vectors A and B using the Pythagorean theorem:

|A + B| = sqrt[(L cosθ + (-D))^2 + (L sinθ)^2]

Simplifying this expression gives:

|A + B| = sqrt[L^2 + D^2 - 2LD cosθ]

Therefore, the distance from home is sqrt[L^2 + D^2 - 2LD cosθ].

b.) To find the direction of the displacement, we need to find the angle between the displacement vector and the eastward direction. We can use trigonometry to do this:

tanθ = opposite/adjacent = L sinθ / (L cosθ - D)

Simplifying this expression gives:

tanθ = (sinθ)/(cosθ - D/L)

Taking the inverse tangent of both sides gives:

θ = tan^-1[(L sinθ)/(L cosθ - D)]

We can express this angle with respect to east by subtracting 90 degrees if θ is acute (i.e., θ < 90 degrees) or adding 90 degrees if θ is obtuse (i.e., θ > 90 degrees).

The correct answer of minimum wavelength Lambdamin of light radiated is 1.3777 x 10 ^-2 m.

What is bremsstrahlung radiation?

Bremsstrahlung, also known as "braking radiation" or "deceleration radiation," is electromagnetic radiation that is produced when a charged particle decelerates when it is deflected by another charged particle. This is commonly an electron by an atomic nucleus.

The energy of the photon is given by:

E=hν=hcλE=hν=hcλ

Here

• h=6.63⋅10^−34 J⋅s=6.63⋅10^−34 J⋅s is the Plank's constant and c is the speed of light and λ is the wavelength

λ= hc/E = 4.136×10−15 eV·s (2.998x10^8 m/s)/10^4 eV

= 4.136×10^−15 eV·s (2.998x10^8 m/s)/9^4 eV = 1.3777 x 10 ^ (8-15-4) = 1.3777 x 10 ^-11 m

= 1.3777 x 10 ^-2 m

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Answer:

\(8.1\:\mathrm{Ns}\)

Explanation:

The impulse-momentum theorem gives the impulse on an object to be equal to the change in momentum of that object. Since mass is maintained, the change in momentum of the basketball is:

\(\Delta p = m\Delta v\), where \(m\) is the mass of the basketball and \(\Delta v\) is the change in velocity.

Since the basketball is changing direction, its total change in velocity is:

\(\Delta v = 20-(-15)=35\:\mathrm{m/s}\).

Therefore, the basketball's change in momentum is:

\(\Delta p = m\Delta v = 0.23\cdot 35= 8.05=8.1\:\mathrm{kg\cdot m/s}\).

Thus, the impulse on the basketball is \(\fbox{$8.1\:\mathrm{Ns}$}\) (two significant figures).

Answer:

19

Explanation: