A single-turn current loop, carrying a current of 3.66 A, is in the shape of a right triangle with sides 50.0,101. and 113 cm. The loop is in a uniform magnetic field of magnitude 65.9mT whose direction is paraliel to the current in the 113 cm side of the loop. What is the magnitude of the magnetic force on (a) the 113 cm side, (b) the 50.0 cm side. and (c) the 101 cm side? (d) What is the magnitude of the net force on the loop?
Answers
a. The force on the 113 cm side is 0N. b. The force on the 50.0 cm side is 0.120N. c. The 101 cm side force is 0.234N . d. The magnitude of the net force on the loop is 0.354 N
The magnitude of the magnetic force on each side of the loop can be determined using the formula F = I * L * B * sin(θ), where I is the current, L is the length of the side, B is the magnetic field magnitude, and θ is the angle between the magnetic field and the side of the loop. The net force on the loop can be obtained by summing the individual forces acting on each side.
(a) To calculate the magnitude of the magnetic force on the 113 cm side, we use the formula F = I * L * B * sin(θ). The current (I) is 3.66 A, the length (L) is 113 cm, the magnetic field magnitude (B) is 65.9 mT (converted to Tesla by dividing by 1000), and the angle (θ) is 0 degrees since the magnetic field is parallel to this side. Therefore, the force on the 113 cm side is F = 3.66 * 1.13 * 0.0659 * sin(0°) = 0 N.
(b) Similarly, for the 50.0 cm side, the force can be calculated using the same formula, but the length is 50.0 cm and the angle θ is 90 degrees since the magnetic field is perpendicular to this side. Thus, the force on the 50.0 cm side is F = 3.66 * 0.5 * 0.0659 * sin(90°) = 0.120 N.
(c) For the 101 cm side, the angle θ is also 90 degrees, so the force is F = 3.66 * 1.01 * 0.0659 * sin(90°) = 0.234 N.
(d) To find the net force on the loop, we sum the individual forces: 0 + 0.120 + 0.234 = 0.354 N.
Therefore, the magnitude of the net force on the loop is 0.354 N.
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Related Questions
A student moves a box across the floor by exerting 56.7 N of force and doing 195 J of
work on the box. How far does the student move the box?
A.3.4 m
B. 11,056 m
C.138 m
D.0.29 m
Answers
Answer:
A. 3.4 m
Explanation:
Given the following data;
Force = 56.7N
Workdone = 195J
To find the distance
Workdone is given by the formula;
\( Workdone = force * distance\)
Making "distance" the subject of formula, we have;
\( Distance = \frac {workdone}{force} \)
Substituting into the equation, we have;
\( Distance = \frac {195}{56.7} \)
Distance = 3.4 meters.
a coil with a self-inductance of 1.5 mh will show a rate of current change of what value when inducing an emf of 0.30 v?
Answers
The rate of change of current in the coil induced by the EMF of 0.30 V is -200 A/s.
The rate of change of current in a coil induced by an EMF is given by the equation:
EMF = -L * dI/dt
where EMF is the induced electromotive force, L is the self-inductance of the coil, and dI/dt is the rate of change of current.
Rearranging the equation, we get:
dI/dt = -EMF / L
Substituting the given values, we have:
dI/dt = -0.30 V / 1.5 mH
= -(0.30 V / 0.0015 H)
= -200 A/s
The negative sign indicates that the current is decreasing.
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A 5,000 kg truck moving at 8 m/s has the same momentum as a 2,500 kg car. What is the velocity of
the car?
Answers
Answer:
16m/s
Explanation:
Mv=mv
5000x8=2500x v
V=5000x8/2500
V=40000/2500
= 16m/s
Find the solution to the 1D wave problem: Utt - 4Uxx , u(0,t) = uz(1,t) = 0, u(x,0) = x2 – 2x , Ut(x,0) = 0, 0 < x <1,t> 0, t>0, 0 < x <1, 0 < x <1. = = Show the details of your work.
Answers
The solution to the 1D wave problem: Utt - 4Uxx , u(0,t) = uz(1,t) = 0, u(x,0) = x2 – 2x , Ut(x,0) = 0, 0 < x <1,t> 0, t>0, 0 < x <1, 0 < x <1. C_1 = ∫ [0] sin(πx) dx and D_1 = ∫ [0] cos(πx) dx
To solve the 1D wave problem with the given conditions, we will use the method of separation of variables. We assume that the solution can be written as a product of two functions: U(x, t) = X(x)T(t).
Substituting this into the wave equation, we get:
Utt - 4Uxx = X''(x)T(t) - 4X(x)T''(t) = 0
Dividing by X(x)T(t), we have:
(X''(x) / X(x)) = (T''(t) / (4T(t)))
The left side of the equation depends only on x, while the right side depends only on t. Since they are equal to a constant, we can write:
(X''(x) / X(x)) = -λ^2 (1)
(T''(t) / (4T(t))) = -λ^2 (2)
where λ is the separation constant.
Now let's solve the equation (1) for X(x):
X''(x) = -λ^2 X(x)
The general solution of this ordinary differential equation is of the form:
X(x) = A sin(λx) + B cos(λx)
To satisfy the boundary conditions u(0,t) = u(1,t) = 0, we have:
X(0) = A sin(0) + B cos(0) = 0
B = 0
X(1) = A sin(λ) = 0
sin(λ) = 0
From the condition sin(λ) = 0, we know that λ must be of the form:
λ = nπ, where n is a non-zero integer.
Therefore, the eigenfunctions X_n(x) corresponding to λ_n = nπ are:
X_n(x) = A_n sin(nπx)
Next, let's solve equation (2) for T(t):
T''(t) + 4λ^2 T(t) = 0
This is a simple harmonic oscillator equation with the general solution:
T_n(t) = C_n cos(2λ_n t) + D_n sin(2λ_n t)
Now, we can write the general solution for U(x, t) as a superposition of the eigenfunctions:
U(x, t) = Σ [A_n sin(nπx)] [C_n cos(2nπt) + D_n sin(2nπt)]
Applying the initial conditions U(x, 0) = x^2 – 2x and Ut(x, 0) = 0, we can find the coefficients A_n, C_n, and D_n by using the orthogonality property of sine functions.
U(x, 0) = x^2 – 2x = Σ [A_n sin(nπx)] [C_n cos(0) + D_n sin(0)]
Comparing coefficients of the sine functions on both sides, we obtain:
A_1 = ∫ [x^2 – 2x] sin(πx) dx
Similarly, using the condition Ut(x, 0) = 0, we find:
C_1 = ∫ [0] sin(πx) dx
D_1 = ∫ [0] cos(πx) dx
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SHORT ANSWER
Which of the balanced chemical equations below has a molar ratio
with the smallest difference between elemental sodium (Na) as a reac-
tant and the chemical formed as a product? Explain.
Use at least two sentences in your answer.
Word Count: (minimum - 10; maximum - 300)
a. 2Na + F2 = 2 NaF
b. 3Na + P = Na3P
c. Na + N2 2Na N
d. Na + 0 = 2 Na o
Answers
Answer:
A
Explanation:
the formula ,
From the given chemical equations,the one with molar ratio with smallest difference between elemental sodium (Na) as a reactant and the chemical formed as a product is equation 'a'.
What is chemical equation?Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.
A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .
The first chemical equation was put forth by Jean Beguin in 1615.By making use of chemical equations the direction of reaction ,state of reactants and products can be stated. In the chemical equations even the temperature to be maintained and catalyst can be mentioned.
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3. Since Aspeon is not expected togrow, Emily believes that the following equations can be used in the valuation analysis: (1) S=[EBIT−kd(D)](1−ks)
(2) V=S+D
(3) P=(V−D0)/n0
(4) n1=n0−D/P
(5) VL=VU+TD
Answers
The equations mentioned by Emily in the valuation analysis for Aspeon are as follows:
1) Equation (1): This equation represents the value of equity (S) and calculates it based on the EBIT (earnings before interest and taxes), the tax shield provided by debt (D), and the required return on debt (kd) and equity (ks). It implies that the value of equity is equal to the adjusted EBIT after deducting the tax shield from debt.
2) Equation (2): This equation calculates the total enterprise value (V) by adding the value of equity (S) and debt (D). It represents the total worth of the company, considering both equity and debt.
3) Equation (3): This equation calculates the price per share (P) by dividing the total enterprise value (V) minus the initial debt (D0) by the number of shares (n0). It represents the price per share based on the valuation of the company.
4) Equation (4): This equation calculates the new number of shares (n1) by subtracting the dividend (D) from the initial number of shares (n0) divided by the price per share (P). It represents the adjusted number of shares after the payment of dividends.
5) Equation (5): This equation calculates the levered value (VL) by adding the unlevered value (VU) with the tax shield value (TD). It represents the value of the company after considering the tax advantages of debt.
These equations provide a framework for valuation analysis, considering factors such as earnings, taxes, debt, and equity. They help assess the value and financial implications of Aspeon's growth prospects.
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if jupiter was about the size of a basketball, which planet(s) would be about the size of a baseball?
Answers
If Jupiter was about the size of a basketball, Venus would be about the size of a baseball.
If Jupiter was about the size of a basketball (approximately 9.4 inches or 24 centimeters in diameter), then a planet about the size of a baseball (approximately 2.9 inches or 7.4 centimeters in diameter) would be roughly 1/3 the diameter of Jupiter.
There are four planets in our solar system that are smaller than Jupiter and roughly 1/3 its diameter: Saturn, Uranus, Neptune, and Venus. Of these, Venus is the closest in size to a baseball, with a diameter of approximately 7,520 miles (12,104 kilometers), making it slightly larger than a baseball but still in the same size range.
So, if Jupiter was the size of a basketball, Venus would be the planet in our solar system that is closest in size to a baseball. Saturn, Uranus, and Neptune would be slightly larger, but still much smaller than Jupiter.
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A cold air mass moves in and overtakes a warm front in the presence of a low-pressure system. Which weather is least likely to occur with these conditions?
A. thunderstorms
B. cloudy skies
C. hailstorms
D. Clear skies
Answers
The weather that is least likely to occur when a cold air mass moves in and overtakes a warm front in the presence of a low-pressure system is clear skies ( D ).
When a cold air mass moves in and overtakes a warm front in the presence of a low-pressure system, it is called as occluded front. During this the colder air is pushed beneath the warmer air. Depending on the direction of occlusion, it can be of two types of of occluded fronts such as
Cold occluded frontWarm occluded frontDuring occluded fronts the possible weather conditions are
ThunderstormsHailstormsTornadoesCloudy skiesTherefore, the weather that is least likely to occur with these conditions is clear skies ( D ).
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how did clair patterson determine the age of earth
Answers
Answer:
Patterson isolated lead from fragments of a meteorite that had struck Earth thousands of years ago, and determined the age of the fragments by analyzing proportions of the lead isotopes. The meteorite is assumed to have been formed at the same time as the rest of the solar system, including Earth
Explanation:
who made the first game
A William Shakespeare
B Horace Alexander
C Doris Twitchell Allen
D William higginbotham
Answers
Hope this helps
. By mistake, 1000.0 cm^3 of oil was dumped into a pond with a surface area of 850.0 m². The density of the oil was 0.850 g/cm². How thick was the resulting oil slick? Remember to use significant figures and scientific notation.
Answers
Answer:
First, convert 850.0 m^2 to cm^2 to match the volume of oil. It would come out to 8,500,000 cm^2. Now set up V=lwh (length times width times height). You are looking for thickness, which is height.
1000.0cm^3 = (8.500*10^6 cm^2)(h)
1000.0/(8.500*10^6) = h
Explanation: I hope this help :)
If the thickness of an absorber is 1.5 cm and 36.45% of a beam is attenuated by the absorber, what is the half-value layer?
Answers
If the thickness of an absorber is 1.5 cm and 36.45% of a beam is attenuated by the absorber, The half-value layer is 0.51 cm.
The half-value layer (HVL) is a measure of the thickness of an absorber required to reduce the intensity of a beam to half its initial value. In this case, we are given that the absorber attenuates 36.45% of the beam.
To find the HVL, we can use the relationship between the percent attenuation and the thickness of the absorber. The HVL is the thickness at which the beam is attenuated to 50% or 0.5 of its initial intensity.
Since 36.45% of the beam is attenuated by the absorber, the remaining intensity is 100% - 36.45% = 63.55% or 0.6355 of the initial intensity.
We can set up the following equation:
0.5 = 0.6355^x
Solving for x, we find x ≈ 0.51.
Therefore, the half-value layer is approximately 0.51 cm, indicating that a thickness of 0.51 cm of the absorber is required to reduce the beam intensity to half its initial value.
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Tariah is riding on her bike at 4m/s (North). If she accelerates at a rate of 1.5 m/s^2 for 2 s, what is her final velocity?
Answers
ANSWER:
7 m/s
STEP-BY-STEP EXPLANATION:
Given:
Initial velocity (u) = 4 m/s
Acceleration (a) = 1.5 m/s^2
Time (t) = 2 s
We can calculate the final velocity using the following formula:
\(v=u+a\cdot t\)We replace and calculate the value of the final velocity:
\(\begin{gathered} v=4+2\cdot1.5 \\ v=4+3 \\ v=7\text{ m/s} \end{gathered}\)The final velocity is equal to 7 m/s.
a pure resistance or 14.0 ohms is connected to an ac voltage source of 184 v (max) that oscillates at a linear frequency of 40.9 hz. determine the current in the circuit after 5.12 s. g
Answers
The current in the circuit is 9.31 A after 5.12 s.
Since the circuit contains only a pure resistance, the current in the circuit can be determined using Ohm's law, which states that the current in a circuit is equal to the voltage divided by the resistance:
I = V/R
where I is the current, V is the voltage, and R is the resistance.
In this case, the resistance is 14.0 ohms, and the voltage is given as 184 V (max).
However, we need to find the root-mean-square (rms) voltage to use in the formula, since the voltage given is the maximum voltage, not the rms voltage.
The relationship between the maximum voltage and the rms voltage is:
\(V_{rms}\) = \(V_{max}\) / √2
\(V_{rms}\) = 184 V / √2 = 130.3 V
Substituting the values into the formula, we get:
I = V/R = 130.3 V / 14.0 ohms = 9.31 A
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Select the correct answer.
Which of the following social events are often centered around sporting events?
A. Tailgate Parties
B. Parades
C. Pep Rallies
D. All of the above
Answers
what is the speed of a wave frequency of 300hz and a wavelength of 25M
I NEED AN EXPLANATION AS WELL
PLEAAASE HELP ASAP
Answers
Answer:
7500 m/s
Explanation:
We can use the equation velocity of a wave equals wavelength times frequency. Therefore, v = wavelength*f = (25 m)(300 Hz) = m/s7,500
write the functio of the following
1.Eardrum
2.Middle
3.Conknea
4.Pina
Answers
The eardrum is the thin piece of tissue which is present between the outer and middle ear. This is responsible for the hearing capacity of an individual.
What are the different parts of Ear?The eardrum, middle ear, cochlea, and pinna are important parts of the Ear. The eardrum is a thin piece of tissue which separates the outer and middle ear. Damage to this eardrum may harm hearing capacity. Mastoiditis is an infection of the bony air cells which are present in the mastoid bone, that is located just behind the ear.
Middle ear has three tiny bones including the malleus, incus and stapes. These bones transfer sound vibrations from eardrum to the inner ear.
The cochlea is a hollow, spiral-shaped bone which is found in the inner ear that plays a key role in the sense of hearing and it also participates in the process of auditory transduction. Sound waves are transduced into electrical impulses which the brain can interpret as individual frequencies of sound.
The auricle or pinna is the visible portion of the outer ear. It is responsible for collecting the sound waves and channels them into the ear canal, where the sound is amplified.
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Circle the letter of each sentence that is true about calculating the
acceleration of a moving object.
A.) If an object is moving without changing direction, then its acceleration is the change in its speed during one unit of time.
B.) If an object's speed changes by the same amount during each unit of
time, then the acceleration of the object at any time is the same.
C.) To determine the acceleration of an object, you must calculate the
change in velocity during only one unit of time.
D.) If an object's acceleration varies, then you can describe only average
acceleration.
Answers
Answer: D
Explanation:
The A string of a violin is a little too tightly stretched. Beats at 4.00 per second are heard when the string is sounded together with a tuning fork that is oscillating accurately at a concert A (400Hz). What is the period of the violin string oscillations
Answers
Answer:
\(T=2.5*10^{-3}s\)
Explanation:
From the question we are told that:
Beat frequency \(F_b=4\)
Frequency \(F=400Hz\)
Generally the equation for Frequency of the violin is mathematically given by
\(f_v=F_b+F\)
\(f_v=4+400Hz\)
\(f_v=404Hz\)
Therefore the period of the violin string oscillations is
\(T=\frac{1}{f_v}\)
\(T=\frac{1}{404}\)
\(T=2.5*10^{-3}s\)
Thirteen resistors are connected across points A and B as shown in the figure. If all the resistors are
accurate to 2 significant figures, what is the equivalent resistance between points A and B?
Answers
The equivalent resistance between points A and B in the diagram is 22 Ω
How do I determine the equivalent resistance?We shall begin by obtaining the equivalent resistance in parallel (i,e the three 6 Ω resistor). Details below:
Resistor 1 (R₁) = 6 ΩResistor 2 (R₂) = 6 ΩResistor 3 (R₃) = 6 ΩEquivalent resistance (Rₜ) = ?1/Rₜ = 1/R₁ + 1/R₂ + 1/R₃
1/Rₜ = 1/6 + 1/6 + 1/6
1/Rₜ = 3/6
1/Rₜ = 1/2
Rₜ = 2 Ω
Finally, we shall determine the equivalent resistance between A and B (i.e series arrangement). Details below:
Resistor 1 (R₁) = Resistor 2 (R₂) = ... = Resistor (R₁₁) = 2 ΩEquivalent resistance (R) =?R = R₁ + R₂ + R₃ + R₄ + R₅ + R₆ + R₇ + R₈ + R₉ + R₁₀ + R₁₁
R = 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2
R = 22Ω
Thus, we can conclude that the equivalent resistance is 22 Ω
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I need help QUICK!! 20 points
Which of the following is/are formed as gravity pulls increasing amounts of dust and debris in a nebula together?
a. the solar wind
b. meteors
c. planetesimals
d. meteorites
Answers
6.
Ann is driving down a street at 15 m/s (about 35 mph). Suddenly a child runs into the street. It
takes Ann 0.75 seconds to react and apply the brakes.
A) how many meters will she have moved before she begins to slow down?
Answers
The distance in meters she would have moved before she begins to slow down is 11.25 m
LINEAR MOTIONA straight line movement is known as linear motion
Given that Ann is driving down a street at 15 m/s. Suddenly a child runs into the street. It takes Ann 0.75 seconds to react and apply the brakes.
To know how many meters will she have moved before she begins to slow down, we need to first list all the given parameters.
speed = 15 m/stime t = 0.75 sFrom definition of speed,
speed = distance / time
Make distance the subject of the formula
distance = speed x time
distance = 15 x 0.75
distance = 11.25m
Therefore, the distance in meters she would have moved before she begins to slow down is 11.25 m
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A car accelerates from rest to 90m/s in 3 seconds. What is the acceleration and how far did it travel?
Answers
Answer:
Explanation:
1.)acceleration= final velocity-initial velocity/time
90m/s-0m/s /3seconds
=30m/s^2
2.) distance= speed*time
90m/s*3seconds
=270m
Dan steps on the brakes in his toy car which causes a braking force of 700 N to the left.
a) If Dan’s car weighs 750 N, then what is the mass of Dan’s car?
b) What is the acceleration of Dan’s car?
Answers
Answer:
76.53 kg; 9.15 m/s² left.
Explanation:
Given the following data;
Weight of car = 750N
Applied force = 700N
a) To find mass
Weight can be defined as the force acting on a body or an object as a result of gravity.
Mathematically, \( Weight, W = mg\)
We know acceleration due to gravity is equal to 9.8 m/s²
Substituting into the equation;
\( 750 = m*9.8\)
\(Mass, m = \frac{750}{9.8}\)
Mass, m = 76.53kg
b) To find the acceleration;
Force is given by the multiplication of mass and acceleration.
Mathematically, Force is;
\( F = ma\)
Where;
F represents force.m represents the mass of an object.a represents acceleration.Making acceleration (a) the subject, we have;
\(Acceleration (a) = \frac{F}{m}\)
Substituting into the equation;
\(Acceleration (a) = \frac{700}{76.53}\)
Acceleration (a) = 9.15 m/s² left.
Find the electric field E⃗ (r⃗ )E→(r→)E_vec(r_vec) inside the sphere (for rrr< aaa) in terms of the position vector r⃗ r→r_vec. Express your answer in terms of r⃗ r→r_vec, rhorhorho (Greek letter rho), and ϵ0ϵ0epsilon_0.
Answers
Solution :
Using the Gauss law, the electric field intensity of a sphere is given by :
\($E. 4 \pi r^2 = \frac{Q_{enc}}{\epsilon_0}$\)
\($E = \frac{Q_{enc}}{4 \pi r^2 \epsilon_0}$\)
Now the enclosed charge inside the sphere (r<a) is
\($Q_{enc}= \rho V$\)
\($Q_{enc}= \rho \left( \frac{4}{3} \pi r^3 \right)$\)
Hence, the electric field intensity becomes as follows :
\($E= \frac{\rho \left(\frac{4}{3} \pi r^3\right)}{4 \pi \epsilon_0 r^2}$\)
\($E =\frac{\rho r}{3 \epsilon_0}$\)
Thus, the electric field inside the sphere is given by :
\($\vec {E} = \frac{\rho \vec{r}}{3 \epsilon_0}$\)
An astronaut is said to be weightlessness when he\she travels in a satellite. Does it mean that the earth does not attract him\her?
Answers
Answer:
Explanation:
The sense of weightlessness in orbiting satellite is because of the lack of any contact-forces. ... Thus, both the astronaut and the satellite have the same value of g, which is again equal to the centripetal acceleration of the satellite. These two neutralize each other, causing everything to appear weightless.
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a balloon is rising at a rate of 3 meters per second from a point on the ground 53 meters from an observer. find the rate of change of the angle of elevation from the observer to the balloon when the balloon is 21 meters above the ground.
Answers
We need to find the rate of change of the angle of elevation from the observer to the balloon when the balloon is 21 meters above the ground. Let's use trigonometry to solve the problem. Let ABC be the right-angled triangle such that angle ABC is 90°, where AB represents the distance from the observer to the point on the ground from where the balloon rises and BC represents the height of the balloon at any instant t.
Let CD be the vertical height of the observer above the ground. Let x be the angle of elevation from the observer to the balloon at any time t (in radians). We want to find the rate of change of x with respect to time t. We know that `tan(x) = BC / AB`.
Taking derivative with respect to time `t`, we get: `sec^2(x) (dx/dt) = (d/dt) (BC/AB)`We know that AB is constant as it is the distance between the observer and the point on the ground from where the balloon rises. Let the distance AB be a.We also know that `BC = h(t)`, the height of the balloon at any time t.
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what happens to the displacement vector when the spring constant has a higher value and the applied force remains constant? It remains the same it increases magnitude it changes direction it decreases magnitude
Answers
1. Which example best describes a restoring force?
B) the force applied to restore a spring to its original length
2. A spring is compressed, resulting in its displacement to the right. What happens to the spring when it is released?
C) The spring exerts a restoring force to the left and returns to its equilibrium position.
3. A 2-N force is applied to a spring, and there is displacement of 0.4 m. How much would the spring be displaced if a 5-N force was applied?
D) 1 m
4. Hooke’s law is described mathematically using the formula Fsp=−kx. Which statement is correct about the spring force, Fsp?
D)It is a vector quantity.
5. What happens to the displacement vector when the spring constant has a higher value and the applied force remains constant?
A) It decreases in magnatude.
how was william parsons (lord rosse) in 1845 able to see spiral structure in some nebulae, whereas others had not noticed this spiral structure before?
Answers
William parsons (lord rose) 1845 was able to see spiral structures in some nebulae, whereas others had not noticed this spiral structure before, using his 72-inch-diameter telescope was the largest in the world.
A telescope is a device that astronomers use to see faraway objects. most telescopes, and all big telescopes, paintings via the usage of curved mirrors to gather and focus light from the night sky. the first telescopes targeted light by using portions of curved, clear glass, known as lenses.
Telescope, a tool used to shape magnified images of remote objects. The telescope is undoubtedly the most essential investigative device in astronomy. It gives a way of accumulating and analyzing radiation from celestial items, even those within the ways reaches of the universe.
William Parsons (1800-1867) became famed for his achievements in astronomy. within the 1840s he built the 54ft long Leviathan telescope, at the time the most important of its type inside the globe. The telescope now forms a part of the exhibitions at Birr castle historical science Centre.
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A 4000 kg truck traveling at 10 m/s collides with a 1000 kg car that is at rest. Answer the following questions concerning the collision. (Circle all that apply. Consider only the magnitude of the values, ignore the fact that some are negative numbers. )
A) Which experiences a larger force? truck or car or neither
B) Which experiences a larger impulse? truck or car or neither
C) Which experiences a larger change in momentum? truck or car or neither
D) Which experiences a larger change in velocity? truck or car or neither
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Answers
Ignore the fact that some of the values are negative numbers and instead consider their magnitude.
A) Both are experience large force.
B) Both are experience large impulse.
C) Both are experience large momentum.
D) Car experience large change velocity.
What does the word collides mean?collision; collision To come together and have a strong or direct effect is an intransitive verb. The vehicle struck a tree. Hovercraft collision
According to the solving:Utilizing the rule of conservation of momentum, we can find a solution to this issue. If there are no outside forces, the truck-car system's total momentum must be preserved both before and after the collision.
Truck of mass m1 = 4000kg
velocity of truck V1 = 10m/s
Car of mass m2 = 1000kg
let
velocity of car V2
principle of conservation of momentum use
m1V1=m2V2
4000×10=1000×V2
V2=40000/1000
V2=40m/s
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