The rate of the vacuum's air flow is approximately 99.149 L/s. The thickness of the layer of iron surrounding the hole is approximately 7.18 cm.
To convert the rate of air flow from cubic feet per minute (ft³/min) to liters per second (L/s), we need to use the following conversion factors:
1 ft³ = 28.3168466 liters
1 min = 60 s
Given that the rate of air flow is 210 ft³/min, we can calculate the rate in L/s as follows:
Rate in L/s = (210 ft³/min) * (28.3168466 L/ft³) * (1 min/60 s)
Simplifying the equation:
Rate in L/s ≈ 99.149 L/s
Therefore, the rate of the vacuum's air flow is approximately 99.149 L/s.
Regarding the second question about the thickness of the layer of iron surrounding the hole, the provided answer of 5.306 cm is incorrect. I apologize for the mistake, and I will provide the correct solution:
The inner radius of the hole (r₁) can be found using the formula:
r₁ = (r³ - V_hole)^(1/3)
where r is the radius of the hollow spherical iron ball and V_hole is the volume of the hole.
Given that the diameter of the hollow spherical iron ball is 15.3 cm, the radius (r) is half of that:
r = 15.3 cm / 2 = 7.65 cm
The volume of the hole (V_hole) can be calculated by subtracting the volume of the hollow spherical iron ball from the total volume of the sphere:
V_hole = (4/3)πr³ - (4/3)πr₁³
The mass of the hollow spherical iron ball is given as 10.1 kilograms, which can be converted to grams:
mass = 10.1 kg * 1000 g/kg = 10100
Using the density of iron (7.86 g/cm³), we can calculate the volume of the hollow spherical iron ball:
V_ball = mass / density = 10100 g / 7.86 g/cm³ ≈ 1285.56 cm³
Now, we can calculate the volume of the hole:
V_hole = (4/3)πr³ - V_ball ≈ (4/3)π(7.65 cm)³ - 1285.56 cm³ ≈ 1473.93 cm³
Substituting the values into the equation for r₁:
r₁ = (7.65 cm)³ - 1473.93 cm³ ≈ 7.18 cm
Therefore, the thickness of the layer of iron surrounding the hole is approximately 7.18 cm.
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Evaluate 4x+13 when x=-3
4x + 13
4 * -3 + 13
-12 + 13
1
How many moles of H2 can be made from complete reaction of 3.0 moles of Al?
Given: 2 Al + 6 HCI - 2 AlCl3 + 3 H2
Answer: 4.5 moles of \(H_{2}\) can be made from complete reaction of 3.0 moles of Al.
Explanation:
The given reaction equation is as follows.
\(2Al + 6HCl \rightarrow 2AlCl_{3} + 3H_{2}\)
This shows that 2 moles of Al reacts with 6 moles of HCl. So, the amount of HCl required to react with 1 mole Al is three times the amount of HCl.
Therefore, 3 moles of Al will react with 9 moles of HCl to give 3 moles of \(AlCl_{3}\) and \(\frac{9}{2}\) moles of \(H_{2}\).
The reaction equation now will be as follows.
\(3Al + 9HCl \rightarrow 3AlCl_{3} + \frac{9}{2}H_{2}\)
The moles \(\frac{9}{2}\) can also be written as 4.5 moles.
Thus, we can conclude that 4.5 moles of \(H_{2}\) can be made from complete reaction of 3.0 moles of Al.
4.5 moles of H2 can be made from complete reaction of 3.0 moles of Al with hydrogen chloride.
STOICHIOMETRY:
According to this question, aluminum reacts with hydrogen chloride to form aluminum chloride and hydrogen gas as follows:2Al + 6HCI → 2AlCl3 + 3H2Based on this equation, 2 moles of aluminum (Al) reacts to produce 3 moles of hydrogen gas. Hence, 3 moles of aluminum will produce (3 × 3)/2 = 4.5 moles of hydrogen gas. Therefore, 4.5 moles of H2 can be made from complete reaction of 3.0 moles of Al with hydrogen chloride.Learn more about stoichiometry at: https://brainly.com/question/22288091?referrer=searchResults
A solution is prepared by dissolving 23.7 g of CaCl2 in 375 g of water. The density of the resulting solution is 1.05 g/mL. The concentration of Cl- in this solution is
If a solution is prepared by dissolving 23.7 g of CaCl₂ in 375 g of water and the density of the resulting solution is 1.05 then the concentration of Cl⁻ in this solution is 1.196 M.
To calculate the concentration of Cl⁻ in a solution prepared by dissolving 23.7 g of CaCl₂ in 375 g of water, we need to first calculate the moles of Cl- present in the solution.
1: Calculate the moles of CaCl₂ present in the solution.
Molar mass of CaCl₂ = 40.08 + (2 × 35.45) = 110.98 g/mol. Number of moles of CaCl₂ = mass / molar mass = 23.7 g / 110.98 g/mol = 0.2133 mol
2: Since 1 mole of CaCl₂ contains 2 moles of Cl⁻, the number of moles of Cl- present in the solution is 2 × 0.2133 = 0.4266 mol
3: Calculate the volume of the solution using its density.
Volume = mass / density = 375 g / 1.05 g/mL = 357.14 mL = 0.35714 L
4: Calculate the concentration of Cl-.
The concentration of Cl⁻ = number of moles/volume of solution
= 0.4266 mol / 0.35714 L= 1.196 M.
The concentration of Cl⁻ in this solution is 1.196 M.
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The concentration of Cl- in a solution can be found by determining the number of moles of Cl-, calculating the volume of the solution, and dividing the moles of Cl- by the volume.
Explanation:In order to find the concentration of Cl-, we first need to determine the number of moles of Cl-. Given that the molar mass of CaCl2 is roughly 110.98 g/mol, we can find this by dividing the mass of CaCl2 (23.7 g) by the molar mass (110.98 g/mol). Since there are two moles of Cl- for each mole of CaCl2, this gives us the number of moles of Cl-.
The density of the solution is given as 1.05 g/mL, from which the volume can be determined by dividing the total mass of the solution (375 g + 23.7 g) by the density. The concentration of Cl-, in moles per liter, is then calculated by dividing the number of moles of Cl- by the volume of the solution in liters.
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Sugar is added to iced tea and the contents are stirred until all of the sugar dissolves. How would the tea now be classified?
A. It is a solution
B. It is an element. C. It is a compound D. It is a pure substance
a. the vapor pressure of bromobenzene at 40°c is 10 mm hg. determine the phase of bromobenzene at 40°c, 1 atm. b. the normal boiling point of fluorobenzene is 84.7°c. what is the phase of fluorobenzene at 25°c, 1 atm?
A. The phase of bromobenzene at 40°C and 1 atm is a *liquid*.
b. The phase of fluorobenzene at 25°C and 1 atm is a *liquid*.
A- According to the given information, the vapor pressure of bromobenzene at 40°C is 10 mm Hg. Vapor pressure is the pressure exerted by the vapor of a substance in equilibrium with its liquid phase at a given temperature. When the vapor pressure of a substance equals the external pressure (1 atm in this case), the substance boils and transitions from the liquid phase to the gas phase.
Since the vapor pressure of bromobenzene at 40°C (10 mm Hg) is lower than the external pressure of 1 atm, bromobenzene does not reach its boiling point and remains in the liquid phase.
B- The normal boiling point of a substance is the temperature at which its vapor pressure equals the external pressure of 1 atm. In this case, the normal boiling point of fluorobenzene is given as 84.7°C.
Since the temperature of 25°C is below the normal boiling point of fluorobenzene, it does not reach its boiling point and remains in the liquid phase. At 25°C and 1 atm, the vapor pressure of fluorobenzene is lower than the external pressure, indicating that it will not undergo a phase change to the gas phase. Therefore, fluorobenzene exists as a liquid at 25°C and 1 atm.
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What is the IMA of the following pulley system?
2
4
5
3
Draw the Lewis dot structure for RbF
There are several steps to draw lewis dot structure of any chemical compound. Here, we taking RbF. Structure is given below with the image.
1. Start by writing the chemical symbol for the element at the center of the structure. In this case, it is Rb for Rubidium.
2. Draw dots around the symbol to represent the valence electrons. Rb has one valence electron, so you would put one dot around the Rb.
3. Next, write the chemical symbol for the other element in the compound, in this case F for Fluorine.
4. Draw dots around the symbol to represent the valence electrons. Fluorine has 7 valence electrons, so you would put 7 dots around the F.
5. To create the bond between the two elements, use a pair of dots to connect the Rb and F. This represents the sharing of electrons between the two elements.
So the Lewis dot structure for RbF would be represented as:
. .
Rb+ [:F:]
. .
This representation shows that Rb and F share one pair of electrons, forming a bond between them, and the dots around Rb and F represent the remaining number of valence electrons that are not involved in the bond.
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How might water high specific heat capacity affect energy distribution and temperature on earth
Answer:
Water can hold a lot of heat inside it and as the climate starts getting cold, the water releases the heat which heats up the climate
Due to the fact that water has a high heat capacity, its temperature has a very limited range, which causes the coastal areas close to having a similar small daily and seasonal temperature range.
What is specific heat capacity?"When the temperature of a material rises 1 K (or 1 °C), the amount of heat (J) absorbed per unit mass (kg)".
When the weather begins to grow chilly, water releases the heat it has stored inside, warming the environment.
High specific heat of the water makes it temperature resistant, and it helps the earth to maintain its temperature and helps organisms to maintain their functions at a constant temperature of the earth.
Thus, the normal temperature is necessary for maintaining the temperature of the earth and the water bodies maintain the temperature of the earth.
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You are ordered to administer 20 mg of Medication A. The vial shows a concentrationof 0.5%. How many mL will you need to administer in order to deliver the correctdose?
The concentration of the vial is 0.5 %. We will suppose that it is % w/v. The concentrarion % w/v is defined as:
% w/v = mass of solute in g/volume of solution in mL * 100
We have to find the mL that we have to administer to deliver 20 mg. Let's convert those mg into g. We know that there are 1000 mg in 1 g.
1000 mg = 1 g
mass of solute in g = 20 mg * 1 g/(1000 mg)
mass of solute in g = 0.020 g
Now that we know the concentration of the solution and the mass in grams of the medication, we can find the volume in mL.
% w/v = mass of solute in g/volume of solution in mL * 100
0.5 = 0.020 / volume of solution in mL * 100
volume of solution in mL = 0.5/(100 * 0.020)
volume of solution in mL = 0.25 mL
Answer: we need to administer 0.25 ml
When you walk at an average speed of 5km/h for 30 minutes, how far will you walk?
Answer:
150
Explanation:
i think that was the answer
A given mass of oxygen is 0.15dm³ at 60°c and 1.01 × 105 nm-² .find its pressure at the same temperature if it's volume is charged to 0.39 dm³
The pressure of the oxygen at 60°C and a volume of 0.39 dm³ is 3.5 × 104 nm-².
To solve this problem, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas:
(P1 x V1) / T1 = (P2 x V2) / T2
where P1, V1, and T1 are the initial pressure, volume, and temperature of the gas, and P2, V2, and T2 are the final/absolute pressure, volume, and temperature.
We are given the following:
Initial pressure P1 = 1.01 × 105 nm-² (nanometers squared)
Initial volume V1 = 0.15 dm³
Initial temperature T1 = 60°C = 333 K
Final volume V2 = 0.39 dm³
Final temperature T2 = 60°C = 333 K
We need to find the final pressure P2.
Plugging these values into the combined gas law, we get:
(P1 x V1) / T1 = (P2 x V2) / T2
(1.01 × 105 nm-² x 0.15 dm³) / 333 K = (P2 x 0.39 dm³) / 333 K
Simplifying this equation, we get the following:
P2 = (1.01 × 105 nm-² x 0.15 dm³ x 333 K) / (0.39 dm³ x 333 K)
P2 = 3.5 × 104 nm-²
Therefore, the pressure of the oxygen at 60°C and a volume of 0.39 dm³ is 3.5 × 104 nm-².
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How many grams are there in 9.4 x 1025 molecules of H2?
Answer:
Mass = 312 g
Explanation:
Given data:
Number of molecules of H₂ = 9.4 × 10²⁵
Mass in gram = ?
Solution:
First of all we will calculate the number of moles of H₂.
1 mole of H₂ contain 6.022× 10²³ molecules
9.4 × 10²⁵ molecules × 1 mol / 6.022× 10²³ molecules
1.56× 10² mol
156 moles of H₂:
Mass in gram:
Mass = number of mole × molar mass
Mass = 156 mol × 2 g/mol
Mass = 312 g
Chemical analysis shows that citric acid contains 37.51% C, 4.20% H, and 58.29% O. What is the empirical formula for citric acid?
The empirical formula for the citric acid is C₆H₈O₇
Data obtained from the question Carbon (C) = 37.51%Hydrogen (H) = 4.20%Oxygen (O) = 58.29%Empirical formula =?Divide by their molar mass
C = 37.51 / 12 = 3.126
H = 4.2 / 1 = 4.2
O = 58.29 / 16 = 3.643
Divide by the smallest
C = 3.126 / 3.126 = 1
H = 4.2 / 3.126 = 1.34
O = 3.643 / 3.126 = 1.17
Multiply through by 6 to express in whole number
C = 1 × 6 = 6
H = 1.34 × 6 = 8
O = 1.17 × 6 = 7
Thus, the empirical formula for the citric acid is C₆H₈O₇
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Non-ferrous metal is NOT hardenable by heat treatment; it must
gain strength through a process such as tempering. Is this
statement TRUE or FALSE?
Group of answer choices
True
False
The statement is FALSE. Non-ferrous metals can be hardened by heat treatment, although the mechanisms and processes involved may differ from ferrous metals.
Heat treatment techniques such as precipitation hardening can be used to increase the strength of non-ferrous metals. Non-ferrous metals are metals or alloys that do not include iron (or iron allotropes, such as ferrite, etc.) in significant quantities. Non-ferrous metals are employed because they have desired qualities like reduced weight (for example, aluminium), greater conductivity (for example, copper), non-magnetic characteristics, or corrosion resistance (for example, zinc), even though they are often more expensive than ferrous metals. In the iron and steel sectors, several non-ferrous materials are also employed. Bauxite, for instance, is used as a flux in blast furnaces, whereas wolframite, pyrolusite, and chromite are utilised to create ferrous alloys.
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Look at the reaction below and state which direction the reaction would shift:
A closed container of water and its vapor at equilibrium. Vapor is added to the system.
Water + Energy <=> Vapor
A system's equilibrium will move to the right, or toward the side of the products, in accordance with Le Chatelier's principle, if more reactants are added. ... The equilibrium will move to the left if we add more product to a system, producing more reactants.
What causes the rightward tilting of equilibrium?Solution: By increasing the number of reactants, the equilibrium moves to the right and in the direction of the products.
What causes the balance to tilt to the left?Thus, if a reactant is added, equilibrium shifts to the right, away from the reactant. Equilibrium shifts to the left, away from the product, when a product is added. If we take away the product, equilibrium returns and produces the product. Reactant is created if reactant is removed, breaking the equilibrium.
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The car has a rechargeable battery to drive it’s motor. The rechargeable battery provided a potential difference of 330 volts and can store up to 64 mega Jules it takes 8 hours for the battery to receive a full charge assume that the charging process is 100% efficient calculate the total charge the flows while the battery is being charged
The total charge that flows while the battery is being charged is approximately 193,939.39 Coulombs.
To calculate the total charge that flows while the battery is being charged, we can use the relationship between electrical energy, potential difference, and charge.
The electrical energy (E) stored in the battery is given as 64 mega Jules (64 MJ). The potential difference (V) provided by the battery is 330 volts. We know that the energy (E) is equal to the product of the potential difference (V) and the charge (Q):
E = V * Q
Since the charging process is 100% efficient, all the electrical energy supplied is stored in the battery. Therefore, we can rearrange the equation to solve for the charge (Q):
Q = E / V
Substituting the given values, we have:
Q = 64 MJ / 330 V
To perform the calculation, we need to convert mega Jules (MJ) to joules (J) since the SI unit of energy is joules. One mega Joule is equal to 1 million joules:
Q = (64 * 10^6 J) / 330 V
Calculating the division:
Q ≈ 193,939.39 Coulombs
Therefore, the total charge that flows while the battery is being charged is approximately 193,939.39 Coulombs.
This value represents the quantity of electric charge transferred during the charging process, and it indicates the amount of electricity that enters the battery.
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ice added to a hot soup for the purpose must be made from what type of water
When adding ice to a hot soup, it is generally recommended to use ice made from potable or drinkable water.
The water used to make the ice should be clean and free from any contaminants that could affect the taste or safety of the soup.
It is advisable to use filtered or purify water to make the ice to ensure that it is of good quality. This helps prevent any unwanted flavors or impurities from transferring to the soup.
Using tap water can also be acceptable if it meets the drinking water standards in your area and is considered safe for consumption. However, if you have concerns about the quality of your tap water, using filtered water is a safer option.
Ultimately, the goal is to add ice made from water that is safe and of good quality to avoid any negative impact on the taste or safety of the soup.
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CH3OH (g) = CO (g) + 2H2 (g) H= +91 kj/molrxn
The reaction represented above goes essentially to completion. The reaction takes place in a rigid, insulated vessel that is initially at 600K.
What can be inferred about delta S for the reaction at 600K?
Based on the given information, it can be inferred that delta S for the reaction at 600K is positive. The delta S for the reaction CH3OH (g) = CO (g) + 2H2 (g) at 600K can be inferred to be positive.
The fact that the reaction goes essentially to completion suggests that it is highly spontaneous, which indicates a large negative delta G. We can use the equation delta G = delta H - T delta S, where delta H is the enthalpy change and T is the temperature, to determine the sign of delta S.
The enthalpy change (Delta H) is given as +91 kJ/mol, which is a positive value, and the temperature is 600K. To make the Gibbs free energy change (Delta G) negative and ensure that the reaction is spontaneous, the entropy change (Delta S) must be positive. This is because a positive entropy change will result in a larger negative value when multiplied by the temperature, and will overcome the positive enthalpy change to make Delta G negative.
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A reaction between 1. 7 moles of zinc iodide and excess sodium
The percent yield of zinc carbonate is 5.91%. This suggests that the reaction did not go to completion, and there was likely some loss of product during the experiment.
To find the percent yield of zinc carbonate, we need to compare the actual yield (what was obtained in the experiment) to the theoretical yield (what would be obtained if the reaction went to completion).
First, let's calculate the theoretical yield of zinc carbonate:
From the balanced equation, we can see that 1 mole of ZnI2 reacts with 1 mole of \(Na_{2}CO_{3}\) to produce 1 mole of \(ZnCO_{3}\).Since we have 1.7 moles of ZnI2, we would need 1.7 moles of \(Na_{2}CO_{3}\) to react completely.The molar mass of \(ZnCO_{3}\) is 125.39 g/mol, so the theoretical yield of \(ZnCO_{3}\) would be:theoretical yield = 1.7 mol ZnCO3 x 125.39 g/mol = 213.07 gNow, let's calculate the percent yield:
The actual yield \(ZnCO_{3}\) is given as 12.6 g.
The percent yield is calculated as:
percent yield = (actual yield / theoretical yield) x 100%percent yield = (12.6 g / 213.07 g) x 100% = 5.91%Learn more about zinc carbonate
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Full Question: A reaction between 1.7 moles of zinc iodide and excess sodium carbonate yields 12.6 grams of zinc carbonate. This is the equation for the reaction: Na2CO3 + ZnI2 → 2NaI + ZnCO3. What is the percent yield of zinc carbonate? The percent yield of zinc carbonate is %
Which characteristics describe bacteria
Answer:
5 simple characteristics of bacteria-
Single-Celled.
Absent Organelles.
Plasma Membrane.
Cell Walls.
DNA.
Explanation:
when calculating losses and gains in the chemical composition of fresh rock vs. weathered rock, we chose to keep al2o3 constant between the samples. why do geochemists choose al2o3?
Al₂O₃ is used as an adsorbent, desiccating agent, and catalyst, and in the manufacture of dental cements and refractories.
Aluminium oxide is used for its hardness and strength. It is widely used as an abrasive, including as a much less expensive substitute for industrial diamond. Many types of sandpaper use aluminium oxide crystals.
Aluminium is a chemical element having the atomic number 13, and chemical symbol Al. Alumina is a chemical compound having the chemical formula Al₂O₃. Therefore, the key difference between aluminium and alumina is that the aluminum is a chemical element, and alumina is an aluminium containing compound.
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24. How many grams of NaCl are required to prepare 60ml of a 75% solution?
Considering the definition of mass volume percentage, a mass of NaCl of 45 grams is required to prepare 60ml of a 75% solution.
Definition of mass volume percentageA mass volume percentage is a ratio of the mass of a solute to the volume of the solution, expressed as a percentage. The mass/volume percentage is calculated as the mass of solute divided by the volume of solution:
mass volume percentage= (mass of solute÷ volume of solution)×100%
Mass of NaClIn this case, you know:
mass volume percentage= 75%mass of solute=?volume of solution= 60 mLReplacing in the definition of mass volume percentage:
75% grams/mL= (mass of solute÷ 60 mL)×100%
Solving:
75% grams/mL÷100%= mass of solute÷ 60 mL
0.75 grams/mL= mass of solute÷ 60 mL
0.75 grams/mL×60 mL= mass of solute
45 grams= mass of solute
Finally, a mass of NaCl of 45 grams is required.
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A bottling plant has 126,515 bottles with a capacity of 335 mL, 108,500 caps and 48,775L of beverages
And let us address the bottle capacity....and this is given by the product. We know that, 1ml= 10⁻³ L
126,515 × 0.335 L = 42382 .525 L and it is the the bottle capacity.
The number of bottles you need is given by
33500/ 0.355= 9436 Bottles and there are enough caps . The limiting quantity is the beverage and there are reserve bottles and caps for the breakages and the failed seals that will undoubtedly occur.
Having brewed beer, ginger beer, or other beverages at home (and this is something that it is easy to do, and you get VERY good results). Most of the time, the bottles are the finite resource. You must gather, carefully clean, and disinfect each bottle.
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Which notation represents the largest atomic radius?
Cl
Cl^−
F
F^−
Answer:
Cl⁻ Or A
Explanation:
If I combine atoms then I must be performing which process?
A) Radiation Reaction
B) Strong Force
C) fission
D)Fusion
Answer:
D: fussion
Explanation:
The process called nuclear fussion.
for example, four hydrogen atoms combine in a nuclear fussion reaction to form one helium atom.
5. When 62.7 g of nitrogen and excess oxygen react they generate nitrogen dioxide. If the NO2 is collected at 620 K and 0.72 atm, what volume will it occupy?___ N2 (g) + ___O2 (g) → ___ NO2 (g)
answer and explanation
the first step is to balance the reaction equation
N₂ + 2O₂ > 2NO₂
now that we have balanced the equation we can calculate the number of moles of nitrogen
mols = mass / molar mass
= 62.7 g/ 14.00g/mol
= 4.48 mols
we see from the balanced equation that the mol ratio of nitrogen and nitrogen oxide is 1:2
therefor the number of mols of nitrogen oxide that will form will be
2 x 4.48 = 8.96 mol of nitrogen oxide.
now that we have the mols we can then calculate the volume using the ideal gas equation
PV =nRT
V = (nRT)/P
= (8.96 x 0.0821 x 620) / 0.72
= 633.5L
Se ard 25g de magneziu de puritate 90%. Ce volum de oxigen se consumă și câti moli dioxid de magneziu se formează
Answer:
10.5 dm3 O2
0.94 moles de MgO
Explanation:
La pregunta dice explícitamente que el magnesio es puro en un 90%.
Por lo tanto, masa de magnesio puro = 90/100 * 25G = 22,5 g
Número de moles de Mg = 22,5g / 24g/mol = 0,94 moles de Mg
La ecuación de reacción es;
2Mg (s) + O2 (g) ------> 2MgO (s)
Si 2 moles de Mg reaccionan con 1 moles de O2
0.94 moles de Mg reacciona con 0.94 * 1/2 = 0.47 moles de O2
Si 1 mol de O2 ocupa 22,4 dm3
0.47 moles de O2 ocupan 0.47 * 22.4 / 1 = 10.5 dm3
También;
2 moles de Mg producen 2 moles de MgO
Entonces, 0.94 moles de Mg producen 0.94 moles de MgO
A sonar device on a ship sends ultrasound waves under the water to locate a submarine. It takes
the ultrasound wave 5 seconds to travel from the device to the sunken submarine and back
again. How far below the surface is the sunken submarine? (Be sure to use the proper units of
measure) * 5
Answer:
3750 m
Explanation:
We must first know the speed of sound in water in order to solve this problem.
So, speed of sound in water = 1500 meters per second
Now time taken = 5 seconds
Given that;
v = 2x/t
where x is the distance below;
vt = 2x
x = vt/2
x = 1500 * 5/2
x = 3750 m
The area around the nucleus of an atom where an electron is moving
Answer: Negative electrons are attracted to the positive nucleus. This force of attraction keeps electrons constantly moving around the nucleus. The region where an electron is most likely to be found is called an orbital.
Compare the drops of wax that harden in hot water and Cold water.
Answer: They are are simular because when the wax cools down its not hot or it cools down it is the same with hot water it cools after along while.
Explanation: