A shell is shot with an initial velocity v
0
​
of 13 m/s, at an angle of θ 0
​
=63 ∘
with the horizontal. At the top of the trajectory, the shell explodes into two fragments of equal mass (see the figure). One fragment, whose speed immediately after the explosion is zero, falls vertically. How far from the gun does the other fragment land, assuming that the terrain is level and that air drag is negligible? Number Units The figure shows an arrangement with an air track, in which a cart is connected by a cord to a hanging block. The cart has mass m 1
​
= 0.640 kg, and its center is initially at xy coordinates (−0.480 m,0 m); the block has mass m 2
​
=0.220 kg, and its center is initially at xy coordinates (0,−0.250 m). The mass of the cord and pulley are negligible. The cart is released from rest, and both cart and block move until the cart hits the pulley. The friction between the cart and the air track and between the pulley and its axle is negligible. (a) In unitvector notation, what is the acceleration of the center of mass of the cart-block system? (b) What is the velocity of the com as a function of time t, in unit-vector notation? (a) ( i- j) (b) ( i j)t The figure gives an overhead view of the path taken by a 0.162 kg cue ball as it bounces from a rail of a pool table. The ball's initial speed is 1.96 m/s, and the angle θ 1
​
is 59.3 ∘
. The bounce reverses the y component of the ball's velocity but does not alter the x component. What are (a) angle θ 2
​
and (b) the magnitude of the change in the ball's linear momentum? (The fact that the ball rolls is irrelevant to the problem.) (a) Number Units (b) Number Units A 5.0 kg toy car can move along an x axis. The figure gives F x
​
of the force acting on the car, which begins at rest at time t=0. The scale on the F x
​
axis is set by F xs
​
=6.0 N. In unit-vector notation, what is P
at (a)t=8.0 s and (b)t=5.0 s,(c) what is v
at t=3.0 s ?

Answer:

Oblique

Explanation:

I think that's the answer I was told this but forgot if this is the right answer if not then sorry

The net force is in the direction of the larger force. If we take that direction to be positive, then the net force has a magnitude of

68.8 N - 26.5 N = 42.3 N

Use Newton's second law to solve for the acceleration:

F = m a

42.3 N = (21.2 kg) a

a = (42.3 N) / (21.2 kg)

a ≈ 2.00 m/s²

(you might also try 1.99 or 2.01 in case that doesn't get accepted)

The number is closest to the frequency of a photon with a wavelength of 5.0* 10⁻⁷ m is 6* 10¹⁴ s⁻¹. ( option B)

Given that,

Wavelength of a photon = 5* 10⁻⁷ m

We know the relation between wavelength and frequency as,

v = c/λ

where,

c is the velocity of light (3* 10⁸ m/s)

λ is the wavelength in m

v is frequency in Hz

Substituting the values, we have

v = c/λ = (3* 10⁸)/(5* 10⁻⁷) = 0.6 * 10¹⁵ hz = 6* 10¹⁴ hz

The units for frequency can also be 1/second as frequency is nothing but the inverse of time period.

So, the answer is 6* 10¹⁴ s⁻¹.

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Explanation:

The reason time zones are 15 degrees wide is because there are 24 hours and 360/24 = 15. As you move east by 15 degrees the sun’s position in the sky changes relative to us and it looks an hour later in the day, so we advance our clocks to match the sun’s position.

So every 15° eastward one hour ahead.

Answer:

Number of Significant Figures: 3

The Significant Figures are 2 3 5

Explanation:

Answer:

Explanation:

static friction = 0.34

Acting force = 50N

mass = 12 kg

g = 9.81

a = acceleration after box moves against friction.

Acting force - Frictional Force = m * a

Frictional Force = mu*Normal

Normal = m * g

Normal = 12 * 9.81 = 117.72

Frictional Force = Normal * 0.34

Frictional Force = 117.72 * 0,34

Frictional Force = 40.02

50 - 40.02 = 12 *a

9.98 = 12*a

a = 0.8317 m/s^2

The x-component of the net force on q2 is -1.439 × 10^-10 N.

The given charges are Q1 = -4.60 * 10^-6 C, q2 = +3.75 * 10^-5 C, and q3 = -5.30 * 10^-6 C. We need to find the x-component of the net force on q2.

The formula for force is F = K(q1 * q2) / r^2, where K is Coulomb's constant = 8.99 × 10^9 Nm^2/C^2, q1 and q2 are the charges in Coulombs, and r is the separation distance in meters.

The force between q2 and Q1 on the x-axis can be calculated as:

F1 = K(Q1 * q2) / r^2 ... (i)

Here, K = 8.99 × 10^9 Nm^2/C^2, Q1 = -4.60 × 10^-6 C, q2 = 3.75 × 10^-5 C, and r = 0.05 m.

Calculating F1:

F1 = (8.99 × 10^9) * (-4.60 × 10^-6) * (3.75 × 10^-5) / (0.05)^2

F1 = -1.242 × 10^-10 N

Similarly, the force between q2 and q3 on the x-axis can be calculated as:

F2 = K(q2 * q3) / r^2 ... (ii)

Here, K = 8.99 × 10^9 Nm^2/C^2, q2 = 3.75 × 10^-5 C, q3 = -5.30 × 10^-6 C, and r = 0.06 m.

Calculating F2:

F2 = (8.99 × 10^9) * (3.75 × 10^-5) * (-5.30 × 10^-6) / (0.06)^2

F2 = -1.971 × 10^-11 N

The net force can be calculated by adding F1 and F2, considering their x-components:

Fnet = F1 + F2

Fnet = (-1.242 × 10^-10) + (-1.971 × 10^-11)

Fnet = -1.439 × 10^-10 N

As both forces act in opposite directions along the x-axis, the net force is in the negative x-direction.

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The longest-wavelength EM radiation that can eject a photoelectron from osmium is 209 nm. This is not in the visible range, as the visible range for humans is approximately 400-700 nm.

The energy of a photon is given by the equation E = hc/λ, where E is energy, h is Planck's constant, c is the speed of light, and λ is wavelength. To eject a photoelectron, the energy of the photon must be greater than or equal to the binding energy of the electron. The binding energy for osmium is given as 5.93 eV.

Using the equation E = hc/λ and converting electron volts to joules, we can solve for the maximum wavelength as follows:

5.93 eV * 1.602 x 10^-19 J/eV = 9.51 x 10^-19 J (binding energy)

h = 6.626 x 10^-34 J s (Planck's constant)

c = 2.998 x 10^8 m/s (speed of light)

λ = hc/E = (6.626 x 10^-34 J s)(2.998 x 10^8 m/s)/(9.51 x 10^-19 J) = 209 nm.

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Answer:

3 m/s^2

Explanation:

acceleration = vf-vi/t = (30 m/s-0 m/s)/10 s = 3 m/s^2

Answer:

b.mountain the correct answer

Explanation:

what type of ladform ids depicted here? a.a b. mountain b. a depression c. avaley

Answer:

The first option, energy is transferred.

Explanation:

The velocity of blood flow in capillaries can vary depending on various factors, including blood pressure, viscosity, and the specific characteristics of the capillary bed.

The velocity of blood molecules flowing through a capillary can be explained by the principles of fluid dynamics. In a capillary, blood flow is characterized by laminar flow, which means that the blood flows in smooth, parallel layers.

The velocity of blood molecules can be affected by various factors, including the radius of the capillary. According to the principle of continuity, which states that the volume flow rate of an incompressible fluid remains constant along a tube, the velocity of blood molecules is inversely proportional to the cross-sectional area of the capillary.

As the radius of the capillary decreases, the cross-sectional area decreases as well. This leads to an increase in the velocity of blood molecules. This relationship can be explained by the equation of continuity:

A1V1 = A2V2

Where A1 and A2 are the cross-sectional areas at two different points along the capillary, and V1 and V2 are the corresponding velocities at those points.

Since the radius is inversely proportional to the cross-sectional area (A), we can rewrite the equation as:

r1^2 * V1 = r2^2 * V2

Where r1 and r2 are the radii at two different points along the capillary.

From this equation, we can observe that as the radius (r) decreases, the velocity (V) increases to maintain the constant flow rate. This means that blood molecules flow faster through narrower capillaries compared to wider ones.

To express the velocity in centimeters per second, it is important to consider the units of the radius. If the radius is given in centimeters, then the velocity will also be in centimeters per second. However, if the radius is given in another unit such as millimeters, the velocity would need to be converted accordingly.

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Answer:

photons      

E = h ν          where h is Planck's constant and ν = frequency of packet

Answer:-20.m/s,drum

Explanation:

Answer:

3.07 kilometres per second

Answer:

wave w is a sound wave

wave x and y are light waves

Answer:

D

Explanation:

The masses amount of a proton and neutron are 1.0087 and 1.0073 amu respectively.

This is defined as  sub atomic particle which is positively charged and is present in the nucleus while the neutron is also a particle present in the nucleus but has a neutral charge.

Electrons on the other hand are found outside the nucleus and are negatively charged. It is the sub atomic particle which is actively involved in a chemical reaction.

The masses of neutron and proton are 1.0087 and 1.0073 amu respectively and was discovered by scientists thereby making it the most appropriate choice.

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Answer:

47 mW

Explanation:

The average value of the Poynting vector, S = 0.939 W/m² = Intensity of wave, I

S = I S

Also, I = P/A where P = Et, P = power of electromagnetic wave, E = energy of electromagnetic wave in time t and t = time = 1 min = 60 s and A = area = lb since the electromagnetic waves falls on area equal to that of a rectangle.

So, S = Et/A

E = SA/t

= Slb/t

= 0.939 W/m² × 1.5 m × 2.0 m/60 s

= 2.817 W/60 s

= 0.047 W

= 47 mW

So, 47 mW of electromagnetic energy falls on the area in 1.0 minute.

The strong nuclear force, leptons do not interact with this force and include particles like electrons and muons.

Fundamental particles are the building blocks of matter and can be grouped into two categories based on their intrinsic properties and interactions with other particles: fermions and bosons. Fermions are the particles that make up matter and are divided into two subcategories: quarks and leptons. Leptons are fundamental particles that do not participate in the strong nuclear force, while quarks are particles that do participate in the strong nuclear force and are always found within hadrons, which are particles made up of quarks.

Hadrons are subdivided into two categories: baryons and mesons. Baryons are hadrons made up of three quarks, while mesons are hadrons made up of one quark and one antiquark. Some examples of baryons include the proton and the neutron, which are both made up of up and down quarks. Mesons include particles like the pion, kaon, and eta meson.

Leptons, on the other hand, are particles that do not interact with the strong nuclear force and include electrons, muons, and taus, as well as their corresponding neutrinos. Electrons are negatively charged particles that orbit the nucleus of atoms, while muons are similar in many ways to electrons, but are about 200 times more massive. Taus are even more massive than muons.

Overall, the categorization of fundamental particles into hadrons and leptons is based on their interactions with other particles, particularly with respect to the strong nuclear force. While hadrons are made up of quarks and are subject to the strong nuclear force, leptons do not interact with this force and include particles like electrons and muons.

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Answer:

I am pretty sure it is A!

:D

The air is warmer near Earth's surface because warm air is denser and sits on top of the Earth's surface. The correct option is B.

The mass of the air per unit volume is known as the air density. Its unit is kg/m³.

Due to the lower pressures in the air above, air expands when it rises. cooling air expands.

The hottest temperatures in the troposphere are often found at the earth's surface because the sun heats the atmosphere predominantly from the surface and because the air cools as it ascends.

Because warm air is denser and lies on top of the surface of the Earth, it is warmer near the surface of the earth.

Hence, the correct option is B.

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The speed of the plane and pilot before the pilot jumps is 17.8 m/s.

We know that the principle of conservation of linear momentum states that the total momentum of a system is constant. This means that the momentum "before" and "after" must be equal.

Thus;

Momentum before = (114 Kg + 60.0 kg) v

Momentum after = (60.0 kg × -5.32 m/s) + (114 Kg × 3.40 m/s)

Hence;

(114 Kg + 60.0 kg) v = 3100.8

v = 3100.8/(114 + 60.0)

v = 17.8 m/s

The speed of the plane and pilot before the pilot jumps is 17.8 m/s.

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The thermodynamic values for water that are used constantly during a unit. Some key thermodynamic values for water are:1. Specific heat capacity (Cp);2. Latent heat of vaporization;3. Latent heat of fusion (L_f).

1. Specific heat capacity (Cp): The amount of heat required to raise the temperature of 1 gram of water by 1 degree Celsius. For water, Cp is approximately 4.18 J/g·°C.
2. Latent heat of vaporization (L_v): The amount of heat required to convert 1 gram of liquid water to water vapor at a constant temperature. For water, L_v is approximately 2260 J/g
3. Latent heat of fusion (L_f): The amount of heat required to convert 1 gram of solid ice to liquid water at a constant temperature. For water, L_f is approximately 334 J/g.
These thermodynamic values are used constantly when studying and analyzing water's behavior in various processes, as they help determine the energy transfer that occurs during phase changes and temperature changes.

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Answer:

d

Explanation:

Answer:

I'M SORRY I CAN'T SEE THE PICTURE BUT IT WILL MOST LIKELY BE THE DIFFERENCE BETWEEN THE NUMBERS

Explanation:

for instance if there was someone pushing a desk with a net force of 9 towards the right, the net force would come to a total of 9 since there is no one on the other side pushing the desk. Meaning the desk would go right. I'm sorry if this isn't what you needed D:

Explanation:

Using kinematics,

t = 4s

u = 0m/s

a = 9.8m/s^2

Therefore v = u + at = 0 + (4)(9.8) = 39.2m/s.

Answer: Limiting reactant

Explanation:

The limiting reactant is a reactant will get completely consumed up in the reaction. This reactant being in low concentration will lead to the formation of limited amount of product.

In the given situation, since the butter cakes are required to be 3 sticks for making 3 cakes but only 2 cakes are available thus the butter stick is the limiting reactant.

The crane uses a heavy concrete block as a counterweight to balance itself when lifting and moving heavy loads.

The counterweight is attached to one end of the crane's arm to prevent it from tipping over due to uneven weight distribution. Additionally, concrete blocks are placed around the crane's base to further enhance its stability and prevent tipping. These measures ensure the safe and efficient operation of the crane.

These blocks act as a foundation and further enhance the crane's overall balance and resistance to tipping over. By distributing the weight across a wider base, the crane becomes more stable and secure during operation.

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Answer:

The correct option is;

3. The total mechanical energy is constant as the block moves back and forth

Explanation:

The total mechanical energy is the sum of the potential and kinetic energies of the system

For a system that is isolated from the effects of external forces, but being acted upon by the internal conservative forces within the system, the total mechanical energy is constant

For a black and spring system, we have total mechanical energy, E = 1/2×K×A².

Where;

K = Constant

A = The amplitude of motion

Therefore, where there is no loss to friction, with A, remaining constant, the total mechanical energy will be constant.