A series LCR circuit is connected to an ac voltage source. When L is removed from the circuit, the phase difference between current and voltage is π/3. If instead C is removed from the circuit, the phase difference is again π/3 between current and voltage. The power factor of the circuit is :
Azero
B0.5
C1.0
D-1.0

Given the weight of the car, W = 8707 N, and the car moves a distance, s= 16.73 m, and final velocity, v = 5.84 m/s

Let the mass of the car be m and acceleration due to gravity g = 9.8 m/s^2

Also, weight is given by the formula,

Then, the mass of the car will be

The acceleration, a can be calculated by the formula

Here, u is the initial velocity, u=0.

The force will be

Thus, the force is 905.34 N

The current flowing through the resistor if the resistance is 2.0 ohms is 25 A.

option B.

The current flowing through the resistor if the resistance is 2.0 ohms is calculated by applying ohms law.

The law states that the voltage across a circuit is directly proportional to the current flowing in the circuit.

V = IR

where;

The current flowing through the resistor if the resistance is 2.0 ohms is calculated as;

I = V/R

I = 50 V / 2 ohms

I = 25 A

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A scale which reads 0 in the vacuum of space is placed on the surface of planet Physica. On the planet's surface, the scale indicates a force of 10,000 Newtons. The surface area of the scale is 0.125 square meters.

To calculate the surface area of the scale, we can use the formula:

P = F/A

where P is the pressure, F is the force, and A is the surface area.

Given that the atmospheric pressure on the surface of Physica is 80,000 Pascals and the scale indicates a force of 10,000 Newtons, we can plug in these values into the equation:

80,000 Pa = 10,000 N / A

To solve for A, we can rearrange the equation:

A = 10,000 N / 80,000 Pa

A = 0.125 m²

In summary, based on the given information, the surface area of the scale on the surface of planet Physica is calculated to be 0.125 square meters.

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We know

\(\boxed{\sf m=-\dfrac{v}{u}}\)

\(\\ \sf\longmapsto 3=-\dfrac{-40}{u}\)

\(\\ \sf\longmapsto 3=\dfrac{40}{u}\)

\(\\ \sf\longmapsto u=\dfrac{40}{3}\)

\(\\ \sf\longmapsto u=13.3cm\)

A scalar quantity, speed is defined as the size of the change in an object's location over time or the size of the change in an object's position per unit of time.

How far is the motorcycle from the car when it reaches this speed?

When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time.

Acceleration is the rate at which an object's velocity with respect to time changes. They are vector quantities, accelerations. The direction of the net force acting on an object determines the direction of its acceleration.

Given,

Speed = 86 km/h

= 86000m/3600 s = 23.89m/s

v = a t

so,

23.89 = 7.1 * t

Therefore, t = 3.36 seconds

Distance car went = 23.89*3.36 = 80.38m

Distance motorcycle went = (23.89/2)* 3.36 = 40.14m

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Answer:

Control groups let the one who is expermenting compare  the effect of the varibles in the expermental group.

Explanation:

Question :-

Answer :-

Explanation :-

As per the provided information in the given question, we have been given that the Velocity of the ball is 12 m/s . Time is given as 36 sec . And, we have been asked to calculate the Acceleration .

For calculating the Acceleration , we will use the Formula :-

\( \bigstar \: \: \boxed{ \sf{ \: Acceleration \: = \: \dfrac{v \: - \: u}{t} \: }} \)

Where ,

Therefore , by Substituting the given values in the above Formula :-

\( \dag \: \: \: \sf { Acceleration \: = \: \dfrac{Final \: Velocity \: - \: Initial \: Velocity}{Time} } \)

\( \longmapsto \: \: \sf { Acceleration \: = \: \dfrac{0 \: - \: 12}{36}} \)

\(\longmapsto \: \: \sf {Acceleration \: = \: \dfrac{ \: 12 \: }{36}}\)

\(\longmapsto \: \: \sf {Acceleration \: = \: \dfrac{ \: 1 \: }{3}}\)

\( \longmapsto \: \bf {Acceleration \: = \: 0.33 \: m/s^{2}} \)

Hence :-

\( \underline {\rule {212pt} {4pt}} \)

The ions are;

S^2- Gained 2 electrons

Li^+ - Lost one electron

Al^3+ - Lost 3 electrons

Cl^- gained one electron

Sr^2+ Lost two electrons

P^3- gained 3 electrons

As an atom or molecule acquires or loses one or more electrons, ions are created. Protons and neutrons make up the positively charged nucleus of an atom, which is encircled by negatively charged electrons. An atom typically has a neutral charge because the amount of electrons and protons in it equals one.

The balance between the negatively charged electrons and positively charged protons is upset when an atom receives or loses an electron, creating an ion with a positive or negative charge.

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Answer: The angle at the curve should be banked to prevent skidding by 12.68⁰.

Explanation:

At a banked road curve

Horizontal factor = mgsinθ

And the factor of centrifugal force = mv²/r*cosθ

In absence of friction, a car can travel without skid if:

mv^2/r*cosθ = mgsinθ or tanθ = mv²/(g*r)

Given, radius of curve, r = 900ft = 900*0.305 = 274.5m

v = 55 mph = 55*0.447 = 24.585 m/s

and g = 9.81 m/s^2

So, tanθ = (24.585)²/(9.8*274.5) = 0.225

θ = 12.68⁰

Therefore, The angle at the curve should be banked to prevent skidding by 12.68⁰.

The heaviest liquid is mercury. In order to equalize the air pressure, it only climbs 76 cm. Water will rise to a 13.6 because it is 13.6 times lighter than mercury. By a factor of 13.6, mercury is 13.6 times denser than water.

Therefore, the barometer's height would be 13.6 times higher if water were employed in place of mercury. Since water expands when it freezes, the glass tube would be broken.

Because of its high density, mercury is frequently employed in barometers, allowing for a column height that is appropriate for measuring atmospheric pressure. For example, a mercury barometer would need to be 13.6 times taller than a water barometer to measure the same change in pressure.

This is the primary justification for using mercury in thermometers. Mercury will provide accurate readings in comparison to water since it lacks the condensation property that water possesses. Mercury can be used to measure both negative and positive temperatures, whereas water cannot be used to measure either.

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Answer:

3525.19 kg

Explanation:

The computation of the mass of the car is shown below:

As we know that

Fc = m × V^2 ÷ R

m = Fc × R ÷ V^2

Provided that:

Fc = 34.652 kN = 34652 N

R = Radius = 24.98 m

V = speed = 15.67 m/s

So,

m = 34652 × 24.98 ÷ 15.67^2

 = 3525.19 kg

A photon is a tiny energy packet of electromagnetic radiation, also referred to as a light quantum.

1) Ultraviolet radiation is commonly used in sanitizing hospitals because, viruses, methicillin-resistant Staphylococcus aureus, and vancomycin-resistant enterococci are all susceptible to the germicidal effects of UV-C.

2) According to the photon theory, electrons that have been stimulated return to the ground state to create atomic emission spectra. Light or the photon is the energy that is released when electrons drop to a lower energy level.

3) To characterise the atomic characteristics of light, Albert Einstein used Planck's quantum theory.

Planck's hypothesis is supported by Einstein's demonstration that electromagnetic radiation, such as light, has both wave-like and particle-like properties.

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Given,

The distance covered, d=30 m

The time interval, t=8 s

As there is no initial velocity is given, we assume that the initial velocity is u=0 m/s

Acceleration of the can be calculated from one of the equations of motion,

Where a is the acceleration of the body.

On substituting the known values ,

Thus the acceleration of the body is 0.94 m/s²

Answer:Magnetic fields from two sources add up as vectors at each point, so the strength of the field is not necessarily the sum of the strengths1. Magnetic fields are vectors, which means they have direction as well as size. Therefore, the sum of two magnetic fields is not simply the sum of their magnitudes2.

Explanation:

Answer:

Q = 3877 KJ

Explanation:

Since, the system is closed and isolated. Therefore, the law of conservation of energy can be written as:

Heat Absorbed By Water (Q) = Heat required to raise the temperature of water (Q₁) + Heat required to convert water to steam (Q₂)

Q = Q₁ + Q₂   ----- equation (1)

Now, for Q₁:

Q₁ = m C ΔT

where,

m = Mass of Water = 1.5 kg

C = Specific Heat of Water = 4187 J/kg.°C

ΔT = Change in Temperature of Water = T₂ - T₁ = 100°C - 22°C = 78°C

Therefore,

Q₁ = (1.5 kg)(4187 J/kg.°C)(78°C)

Q₁ = 490 x 10³ J =490 KJ

Now, for Q₂:

Q₂ = m H

where,

m = Mass of Water = 1.5 kg

H = Heat of Vaporization of Water = 2258 KJ/kg

Therefore,

Q₂ = (1.5 kg)(2258 KJ/kg)

Q₂ = 3387 KJ

Substituting the values in equation (1), we get:

Q = Q₁ + Q₂

Q = 490 KJ + 3387 KJ

Q = 3877 KJ

Answer:

(B) {u}= [T/(du / dy)] = (F/L^2) / (L/T) / L = FT / L^2

Explanation:

Answer:

6 km is the right answer

hope it helps you

Explanation:

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The magnitude of the force exerted on the 300 kg bumper car is 500 N.

option B.

Newton's third law of motion states that for every action force, there is an equal and opposite reaction force. That is action force and reaction force are equal in magnitude but opposite in direction.

Mathematically, the formula for Newton's third law of motion is given as;

Fa = - Fb

where;

Fb = - 500 N

| Fb | = 500 N

Thus, the force exerted by 200 kg bumper is to the force exerted by 300 kg bumper.

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This question is incomplete, the missing image uploaded along this answer below;

Answer:

a) frequency is 2.381 Hz

b) the angular frequency/speed is 14.96 rad/s

c) the magnitude of the magnetic field is 0.5199 T

Explanation:

Given that;

cross sectional Area A = 0.018 m²

Number of turns N = 200

from the diagram. maximum time T = 0.42 sec

a) the frequency f of the generator in hertz

frequency = 1 / T

we substitute

frequency = 1 / 0.42 = 2.381 Hz

Therefore, frequency is 2.381 Hz

b)  the angular frequency in rad/s

angular speed ω = 2πf

we substitute

ω = 2π × 2.381

ω = 14.96 rad/s

Therefore, the angular frequency/speed is 14.96 rad/s

c) the magnitude of the magnetic field.

to determine the magnitude of the magnetic field, we use the following expression;

e = NBAω

from the diagram, e = 28.0 V

so we substitute

28.0 V = 200 × B × 0.018 × 14.96

28 = 53.856B

B = 28 / 53.856

B = 0.5199 T

Therefore, the magnitude of the magnetic field is 0.5199 T

The time will be the same for both horizontal and vertical component. The initial speed is 10.7 m/s

Speed is a distance travel per time taken. It is a scalar quantity and it is measured in m/s

Given that a person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a height of 52 m and it lands a distance of 35 m from the base of the cliff.

The rock will move vertically downward with initial velocity = 0. The time taken will be constant. That is, same horizontally.

Let us first calculate the time by using the formula

h = ut + 1/2gt²

Where

Substitute all the necessary parameters into the formula

52 = 0 + 1/2 × 9.8 × t²

52 = 4.9t²

t² = 52/4.9

t² = 10.6

t = √10.6

t = 3.26 s

The speed at which the rock was initially kicked can be found by

R = Ut

35 = U × 3.26

U = 35/3.26

U = 10.7 m/s

Therefore, rock was initially kicked at a speed of 10.7 m/s

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Answer: KE=.5mv^2

KE=.5(7.62)(7.5)^2

KE=.5(7.62)(56.25)

KE=.5(428.625)

KE=214.3125 J of KE

Explanation:

Given:

As we know,

→ \(K.E = \frac{1}{2} mv^2\)

By substituting the values, we get

          \(= \frac{1}{2}\times 762\times (7.5)^2\)

          \(= \frac{1}{2}\times 7.62\times 56.25\)

          \(= \frac{1}{2}\times 428.625\)

          \(= 214.32 \ J\)

Thus the response above is appropriate.

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Answer:

7 mL

Explanation:

Given that:

mass of an oral solution = 500 mg

solution in mL = 5mL

Thus, the ratio = 5 mL/500 mg

= 0.01 mL/mg

since 1000 mg = 1g

∴

= 0.01 mL/mg × 1000 mg/1g

= 10 mL/g

Now, suppose the amount of 0.7 g dosage is required:

∴

the needed amount of mL will be:

= 10 mL/g × 0.7 g

= 7 mL

The net force on particle q₁ is approximately +25.6 N.

The electrostatic forces between particle q1 and the other two particles, q2 and q3, must be taken into account in order to determine the net force on particle q1. Coulomb's Law describes the electrostatic force between two charged particles:

F = k * |q₁ * q₂| / r²

F is the force, k is the electrostatic constant (9 x 109 N m2/C2), q1 and q2 are the charges' magnitudes, and r is the distance separating them.

Let's first determine the force between q1 and q2:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9 x 10^9 N m²/C²) * |(-29.6 μC) * (+37.7 μC)| / (0.630 m)²

F₁₂ = (9 x 10^9 N m²/C²) * (29.6 x 10^-6 C) * (37.7 x 10^-6 C) / (0.630 m)²

F₁₂ ≈ -7.45 N

The absence of a positive sign suggests an attractive force between q1 and q2.

Let's next determine the force between q2 and q3:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9 x 10^9 N m²/C²) * |(+37.7 μC) * (-10.8 μC)| / (0.315 m)²

F₂₃ = (9 x 10^9 N m²/C²) * (37.7 x 10^-6 C) * (10.8 x 10^-6 C) / (0.315 m)²

F₂₃ ≈ +33.05 N

The presence of a positive sign suggests a repulsive force between q2 and q3.

We must now add all the forces in order to determine the net force on q1:

Net force = F₁₂ + F₂₃

Net force ≈ -7.45 N + 33.05 N

Net force ≈ +25.6 N

The presence of a positive sign implies that the net force is pointing to the right, in the same direction as particle q2.

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Answer:

a)40 meters

b)2 m/s

c)2 m/s

d)0 m/s

e)45 degrees northeast

Explanation:

a) The displacement from C to A is the distance directly across the river, which is 40 meters.

b) The speed of the boat as seen by people standing at A is the magnitude of the boat's velocity vector, which is equal to the displacement divided by the time taken:

Speed = displacement / time = 40 m / 20 s = 2 m/s.

c) Let v be the speed of the water in the river. The boat is moving at right angles to the flow of the river, so the water exerts a perpendicular force on the boat. The time taken for the boat to travel from A to C is 20 seconds, during which time the boat will have been carried downstream by the river by a distance equal to v times the time taken.

Distance carried downstream = v × time = v × 20 m.

Since the boat landed at C, which is directly across the river from A, the distance it traveled horizontally is 40 meters. Therefore:

40 m = (boat speed) × (time taken) = (boat speed) × 20 s.

Hence, the speed of the boat is:

Boat speed = 40 m / 20 s = 2 m/s.

So, we have two equations:

Distance carried downstream = v × 20 m

Boat speed = 2 m/s

From the first equation, we get:

v × 20 m = 40 m

Therefore, the speed of the water in the river is:

v = 40 m / 20 m = 2 m/s.

d) The speed of the boat as seen by a fish drifting with the river is the difference between the speed of the boat and the speed of the water in the river:

Boat speed - Water speed = 2 m/s - 2 m/s = 0 m/s.

So, the speed of the boat as seen by a fish drifting with the river is zero.

e) The boat should head in a direction that makes its velocity vector point directly from A to B. Since A and B are directly opposite each other, this means the velocity vector should be perpendicular to the line connecting A and B.

We know the boat's velocity vector has a magnitude of 2 m/s and is at right angles to the velocity vector of the water in the river, which has a magnitude of 2 m/s. So, we can draw a vector diagram with the velocity vector of the boat pointing straight up and the velocity vector of the water pointing straight to the right. The vector connecting the tail of the water velocity vector to the head of the boat velocity vector will then point directly from A to B.

The angle between the boat's velocity vector and the line connecting A and B can be found using trigonometry. Let θ be this angle. Then:

tan(θ) = (boat speed) / (water speed) = 2 m/s / 2 m/s = 1.

Taking the inverse tangent of both sides gives:

θ = tan^(-1)(1) = 45°.

So, the boat should head in a direction 45 degrees to the right of straight up, or northeast.

Por lo tanto, la pelota fue lanzada con una velocidad inicial de 14.7 m/s y alcanzó una altura máxima de 11.3 m.

Generally, Para resolver este problema, necesitamos conocer la relación entre la velocidad inicial con la que se lanza la pelota y la altura máxima que alcanza. Podemos usar las ecuaciones de movimiento para un objeto que se mueve verticalmente con aceleración constante.

Primero, consideremos el momento en que la pelota es lanzada. En ese momento, la velocidad inicial de la pelota es v0, que es lo que estamos buscando. Usando la ecuación de posición vertical:

y = v0t - 1/2gt^2

donde y es la altura alcanzada, t es el tiempo transcurrido, y g es la aceleración debido a la gravedad (-9.8 m/s^2), podemos despejar v0 en términos de y y t:

v0 = (y + 1/2gt^2) / t

Ahora, consideremos el momento en que la pelota es atrapada, 3.0 s después de ser lanzada. Sabemos que en ese momento, la velocidad vertical de la pelota es cero, ya que está en su punto más alto. Usando la misma ecuación de posición vertical, pero estableciendo y = 0 y v = 0, podemos encontrar el tiempo que tarda la pelota en llegar a su altura máxima:

0 = v0t - 1/2gt^2

t = 2v0/g

Sustituyendo este valor de t en la ecuación anterior, podemos encontrar la altura máxima que alcanza la pelota:

y = v0(2v0/g) - 1/2g(2v0/g)^2

y = v0^2/2g

Ahora podemos calcular los valores numéricos. Si asumimos que la altura a la que el jugador atrapa la pelota es la misma que la altura máxima alcanzada por la pelota, y tomamos g = -9.8 m/s^2, entonces:

v0 = (y + 1/2gt^2) / t = (0 + 1/2(-9.8 m/s^2)(3.0 s)^2) / 3.0 s = 14.7 m/s

y = v0^2/2g = (14.7 m/s)^2 / (2(-9.8 m/s^2)) = 11.3 m

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Element molecules consist of a single type of atom and are held together by covalent bonds. The model would have uniform-colored balls connected by sticks representing these bonds.

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Answer:

At elevated altitudes, any cooking that involves boiling or steaming generally requires compensation for lower temperatures because the boiling point of water is lower at higher altitudes due to the decreased atmospheric pressure.

Explanation:

Answer:

The Lower the air pressure the lower the boiling point.