A series circuit consists of 4 resistors connected in series: 1202, 180, 320, and a 3802 to
a battery. What is the total equivalent resistance?

ANSWER:

5 kcal

STEP-BY-STEP EXPLANATION:

We have the following:

Mass of water = 0.5 kg

Change in temperature of water: 30° C - 20°C = 10°C

Specific heat of water = 1 kcal/kg*°C

The amount of heat added to the water is calculated as:

Answer:

Vi = 32 [m/s]

Explanation:

In order to solve this problem we must use the following the two following kinematics equations.

\(v_{f} =v_{i} - (a*t)\\\)

The negative sign of the second term of the equation means that the velocity decreases, as indicated in the problem.

where:

Vf = final velocity = 8[m/s]

Vi = initial velocity [m/s]

a = acceleration = [m/s^2]

t = time = 5 [s]

Now replacing:

8 = Vi - 5*a

Vi = (8 + 5*a)

As we can see we have two unknowns the initial velocity and the acceleration, so we must use a second kinematics equation.

\(v_{f}^{2} = v_{i}^{2} - (2*a*d)\)

where:

d = distance = 100[m]

(8^2) = (8 + 5*a)^2 - (2*a*100)

64 = (64 + 80*a + 25*a^2) - 200*a

0 = 80*a - 200*a + 25*a^2

0 = - 120*a + 25*a^2

0 = 25*a(a - 4.8)

therefore:

a = 0 or a = 4.8 [m/s^2]

We choose the value of 4.8 as the acceleration value, since the zero value would not apply.

Returning to the first equation:

8 = Vi - (4.8*5)

Vi = 32 [m/s]

OD

Explanation:

both gravitational force and speed will increase

The gravitational force will increase and speed will decrease. So, the correct option is c.

Any two objects in the universe are attracted towards each other by the gravitational force, regardless of whether their masses are equal or not.

Here,

Newton's universal law of gravitation states that the force of attraction between any two bodies is inversely proportional to the square of the distance between them and directly proportional to the product of their masses.

So, the gravitational force of the satellite,

F ∝ 1/R²

where R is the radius of the circular orbit.

The equation for speed of the satellite is given by,

v = √Rg

where g is the acceleration due to gravity.

So, the speed is directly proportional to the square root of the radius of the orbit.

v ∝ √R

Therefore, as a result of the decrease in the radius of the orbit, the gravitational force of the satellite will increase, and its speed will decrease.

Hence,

The gravitational force will increase and speed will decrease.

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The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.

Given:

Object height (h) = 5 cm

Focal length of the convex lens (f) = 10 cm

Object distance (u) = 15 cm (positive since it's on the same side as the incident light)

To determine the nature, position, and size of the image, we can use the lens formula:

1/f = 1/v - 1/u

Substituting the given values:

1/10 = 1/v - 1/15

To simplify the equation, we find the common denominator:

3v - 2v = 2v/3

Simplifying further:

v = 30 cm

The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.

To find the magnification (M), we use the formula:

M = -v/u

Substituting the values:

M = -30 / 15 = -2

The magnification is -2, indicating that the image is inverted and twice the size of the object.

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Horizontal force will be there but angular force is zero because it is dependent on angle and angular velocity is constant.

\(\tau = rF\sin\theta\)

T= torque

r= radius

In mechanics, every action that tries to preserve, alter, or change a body's motion is referred to as a force. Isaac Newton's Principia Mathematica has three principles of motion that are usually used to explain the concept of force (1687).

Newton's first law states that in the absence of an external force, a body will continue to be in either its resting or evenly moving condition along a straight path. According to the second law, any time an outside force acts on a body, the body accelerates (changing velocity) in the force's direction.

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Answer:

50 Hz

Explanation:

Frequency is oscillations per second.

50/1 = 50

A. The average speed you can use to pull the safe is 1.02 m/s

B. The time needed to pull the safe up is 17.65 s

First, we shall obtain the force. This is shown below:

F = mg

F = 60 × 9.8

F = 588 N

Finally, we shall obtain the average speed. Details below:

Power = force × average speed

600 = 588 × average speed

Divide both sides by 588

Average speed = 600 / 588

Average speed = 1.02 m/s

The time needed to pull the safe up can be obtained as follow:

Time = Total distance / average speed

Time = 18 / 1.02

Time = 17.65 s

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Complete question:

You know you can provide 600 W

of power to move large objects. You need to move a 60-kg

safe up to a storage loft, 18 m

above the floor.

Part A

With what average speed can you pull the safe straight up?

Part B

What is the time needed to pull the safe up?

Answer:

Periodic.

Explanation:

Electromagnetic waves is a propagating medium used in all communications device to transmit data (messages) from the device of the sender to the device of the receiver.

Generally, the most commonly used electromagnetic wave technology in telecommunications is radio waves.

Radio waves can be defined as an electromagnetic wave that has its frequency ranging from 30 GHz to 300 GHz and its wavelength between 1mm and 3000m. Therefore, radio waves are a series of repetitive valleys and peaks that are typically characterized of having the longest wavelength in the electromagnetic spectrum.

Basically, as a result of radio waves having long wavelengths, they are mainly used in long-distance communications such as the carriage and transmission of data.

Generally, a fixed speed is used for the propagation of traveling waves and this speed is usually denoted with the variable "v" or sometimes "c."

Furthermore, if the waveform of a traveling wave is repeated every time at specific intervals T, it is referred to as periodic wave.

Mathematically, the period of a traveling wave is given by the formula;

\( Period = \frac {1}{T} \)

Where;

T is the time measured in seconds.

Using SOH,CAH,TOA, we can calculate the height of the building by taking the sine of the launch angle (60°) and the distance traveled (65 m). The height of the building is 56.9 m.

SOH,CAH,TOA stands for Sine = Opposite/Hypotenuse, Cosine = Adjacent/Hypotenuse and Tangent = Opposite/Adjacent. This is a set of trigonometric ratios that can be used to solve for angles and lengths of sides of a right triangle. It is used when the angle and length of two sides of a right triangle are known, but the length of the third side needs to be calculated.

Calculation using SOH, CAH, TOA

The distance from the ground to the top of the building is 65 m and the angle is 60 degrees. the height (h) of the building.has to be found

Using the trigonometric ratio of Sine,  calculate the height of the building:

Sin(60°) = Opposite/Hypotenuse

h/65 = sin(60°)

h = 65sin(60°)

h = 65(0.866)

h = 56.59 m

Therefore, the height of the building the projectile was launched to from the ground is 56.59 m.

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Hi there!

\(\Phi _B = \int B \cdot dA\)

φ = Magnetic Flux (Wb or Tm²)
B = Magnetic field strength (T)
A = Area (m²)

This equation includes a dot product, so this can be rewritten as:

\(\Phi _B = B A cos\theta\)

In this instance, the field is parallel to the area, so cos(0) = 1.

Calculate the magnetic flux by plugging in the given values.

\(\Phi _B = BA = 0.114 * 0.065 = \boxed{0.00741 Wb}\)

Answer:

Thermal energy is directly proportional to particle movement.

Explanation:

Thermal energy is a form of energy from heat. When applied to a given substance, it increases the kinetic energy of the particles. Thus the average rate of motion of the particles of the substance increases, likewise its temperature.

Therefore, an increase in thermal energy increases particle movement of a substance. And a decrease in thermal energy decreases the particle movement of a substance. Thus, thermal energy is directly proportional to the particle movement of a given substance.

Answer:7.5. 10^4 J

Explanation:

Answer:

The Kinetic Energy of the car at that instant will be 123,210 Joules.

Explanation:

Given:

Mass=500 Kg

\(Speed= 80 km/h=\frac{80*1000}{3600}\ m/s =22.2 m/s\)

Required:

Kinetic energy (K.E)=?

Formula:

\(K.E=\frac{1}{2}mv^{2}\)

Where:

m is the mass.

v is the speed.

Solution:

\(K.E=\frac{1}{2}mv^{2}\\K.E=\frac{1}{2} *500* (22.2)^{2} \\K.E=123,210 J\)

The Kinetic Energy of the car at that instant will be 123,210 Joules.

When two magnets are close to each other, the magnets experience a repulsive or attractive force. The magnetic field strength is affected by the orientation of the magnet.

The direction in which the bar magnet obtains its maximum magnetic property is called the orientation of the magnet. The magnetic field strength depends on the orientation of the magnet.

The magnetic field lines emerge from the north pole and end in the south pole. When the two bar magnets of opposite poles face each other, an attractive force will be produced and magnetic field strength increases.

When the bar magnet of the same poles faces each other, repulsive force will produce and magnetic field strength decreases. Hence from the orientation of the bar magnet,  the magnetic field strength gets affected.

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Answer:

Hope this helps ;) don't forget to rate this answer !

Explanation:

It is possible that identical rock formations can exist thousands of kilometers apart because of the rock cycle, a process that involves the continuous transformation of rocks through various stages such as weathering, erosion, deposition, and more.

To prove that the identical rock formations formed at the same time, geologists can look for clues such as the presence of the same type of minerals, the same layering or structure, and similar levels of weathering or erosion. This information can be incorporated into the model by including representations of these clues and explaining their significance in the rock cycle.

Processes that could have separated the rock formations over time include tectonic movement, erosion, and weathering. These processes can be incorporated into the model by including representations of tectonic plates and showing how they can move and collide, as well as by including examples of erosion and weathering and explaining their role in the rock cycle.

To determine how and when mountain ranges formed, geologists can study the rock formations, the types of minerals present, and the levels of weathering and erosion. This information can be incorporated into the model by including representations of different types of rock formations and explaining how they were formed through processes such as mountain building and erosion.

Weathering and erosion can cause both fast and slow changes to Earth's surface, and can affect both large and small areas. To include this information in the model, you could have two separate models to show different time and spatial scales. One model might show the slow weathering and erosion of a rock, while the second model might show the fast weathering and erosion of a mountainside during a landslide.

To model weathering and erosion, you could put rocks in a container and shake it many times to simulate weathering, or use water or a fan to model erosion by rivers or wind. You could also use a source of heat to model energy from Earth's interior, or a fan to model wind energy.

In your model, you should include processes that describe the cycling of Earth materials and the flow of energy that drives the cycling. These processes include weathering, erosion, deposition, compaction, cementation, melting, crystallization, pressure, deformation, subduction, and seafloor spreading.

In your article, you could start by introducing the rock cycle and explaining the various processes involved. You could then describe how these processes shape and change rocks on Earth's surface at different time and spatial scales, using examples to illustrate your points. You could also include information about the clues that geologists look for to determine the history of a rock formation, and how these clues can be used to understand the rock cycle. Finally, you could conclude by summarizing the key points and explaining the significance of the rock cycle in understanding the Earth's surface.

The density of the small spheres with a diameter of 1.05mm and a terminal velocity of 2.34 cm/s is 42.97m/s³.

Density is a measurement which compares the amount of matter occupied by an object with its volume. An object with much matter in a certain amount of volume has high density. Whereas, an object with a little matter in the same amount of volume has a low density.

We know that density of water,

σ = 1.00 × 10⁻³ kg/m³ and coefficient of viscosity for water, η = 10⁻³ Pa.s

Given,

Terminal speed, v = 2.34 cm/s = 0.0234 m/s

Radius of sphere, r = d/2 = 1.05/2 = 0.525mm = 0.0005m

Using the formula of terminal speed,

v = 2(ρ − σ)gr²/ 9η

0.0234 = 2(ρ - 1.00 × 10⁻³) × 9.8 × 0.0005²/ 9 × 10⁻³

0.0234 = 2(ρ - 1.00 × 10⁻³) × 9.8 × 0.00000025/ 9 × 10⁻³

0.0234 = 2(ρ - 1.00 × 10⁻³) × 0.00000245/ 9 × 10⁻³

0.0234 × 9 × 10⁻³/ 2 ×  0.00000245 = ρ - 1.00 × 10⁻³

0.2106× 10⁻³/ 0.0000049 = ρ - 1.00 × 10⁻³

0.0002106/ 0.0000049 = ρ - 1.00 × 10⁻³

42.97 = ρ - 1.00 × 10⁻³

ρ = 42.97m/s³

Therefore, the density of the small spheres is 42.97m/s³.

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Answer:

68000

Explanation:

1 MHz = 1000 Hz

just multiply by 1000 :)

Answer:

B. older than 50,000 years old

hope it helps you

Rocks older than 50,000 years old are objects in which geologists use carbon-14 dating to determine its age.

This is used to determine age by using the decay to nitrogen of radiocarbon (carbon-14).

Older rocks can have its age determined through the use of carbon-14 which is why option B was chosen.

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Hi there!

Given the values for α and β, we can plug these into the given equation:

\(v(t) = 4t - 2t^2\)

Begin by solving for the velocity at t = 0 and t = 3:

At t = 0:
\(v(0) = 4(0) - 2(0^2) = 0 \frac{m}{s}\)

At t = 3:
\(v(3) = 4(3) - 2(3^2) = 12 - 18 = -6 \frac{m}{s}\)

Acceleration is the SLOPE of the velocity graph (its derivative), so we can use the kinematic equation:

\(a = \frac{v_f - v_i}{\Delta t}\)

Plug in the knowns:

\(a = \frac{-6-0}{3 - 0} = \boxed{-2 \frac{m}{s^2}}\)

The velocity gradient across the 3.7 mm thick oil layer on the flat plate sliding on the horizontal table is 0.594 m/s/m.

Given:

Surface area of the plate (A) = 1.8 m^2

Thickness of the oil layer (h) = 3.7 mm = 0.0037 m

Force applied on the plate (F) = 2.2 N

Dynamic viscosity of the oil (η) = 0.89 x 10^-3 Ns/m^2

To calculate the velocity gradient across the oil layer, we can use the equation:

τ = η * du/dy

where τ is the shear stress, η is the dynamic viscosity, and du/dy is the velocity gradient.

Since the force (F) applied on the plate is responsible for the shear stress, we can write:

τ = F / A

Substituting the given values, we have:

F / A = η * du/dy

Solving for du/dy, we get:

du/dy = (F / A) / η

Substituting the values, we have:

du/dy = (2.2 N) / (1.8 m^2 * 0.89 x 10^-3 Ns/m^2)

du/dy = 0.594 m/s/m

Therefore, the velocity gradient across the oil layer is 0.594 m/s/m.

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Answer:

total distance travelled

Explanation:

The amount of load lifted by the pulley when the efficiency is 60% and effort is 50 N is determined as 30 N.

The amount of load lifted by the pulley is calculated by applying the formula for efficiency of a machine as follows;

E = L / E   x  100%

where;

The amount of load lifted by the pulley is calculated as;

60 = L / 50   x 100%

60 = 100L / 50

100L = 50 x 60

100 L = 3000

L = 3000 / 100

L = 30 N

Thus, the amount of load lifted by the pulley is 30 N.

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The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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Answer:

\(7.2 \times 10 {}^{11} newton\)

Explanation:

\(the \: magnitude \: of \: the \: forc \: e \: can \: be \: calculated \: using \: coulombs \: formular \\ f = \frac{k \times q1 \times q2}{d {}^{2} } \\ f = \frac{9 \times 10 {}^{9} \times 100 \times 20 }{5 {}^{2} } \\ f = \frac{18000 \times 10 {}^{9} }{25 } \\ f = \frac{18000000000000}{25} \\ f = 7.2 \times 10 {}^{11} newton\)

1. b. electrical potential energy.

2. a. True. For electric potential energy, a reference position must be defined.

3. a. -4 J. The potential energy between two charges is given by the equation U = k(q1q2)/r, where k is the electrostatic constant, q1 and q2 are the charges, and r is the separation between them. Since the potential energy is given as 2 J initially, and q2 is replaced by q3 (which is negative and twice the magnitude of q2), the potential energy becomes -4 J.

4. c. decreases. The potential energy between two charges decreases as they are moved closer together.

5. b. -3.24 J. The electric potential energy between two point charges is given by the equation U = k(q1q2)/r, where k is the electrostatic constant, q1 and q2 are the charges, and r is the separation between them. Substituting the values into the equation, we get U = (9x10^(-6) C)(-4x10^(-6) C)/(0.1 m) = -3.24 J.

6. a. B or D. Electric potential energy can never be negative if the charges repel each other.

7. c. measures energy per unit charge.

8. 12 J. The potential energy is given by the equation U = qV, where U is the potential energy, q is the charge, and V is the potential. Substituting the values into the equation, we get U = (6 C)(2 V) = 12 J.

9. b. 10 V. The electric potential is given by the equation V = U/q, where V is the potential, U is the potential energy, and q is the charge. Substituting the values into the equation, we get V = 50 J/5 C = 10 V.

10. c. 14 V. The electric potential is inversely proportional to the distance from a point charge. When the distance is doubled, the potential is halved. Therefore, the electric potential at the new position of q2 is 28 V/2 = 14 V.

11. c. increases. The potential at the position of q2 due to q1 increases when a negative test charge is substituted with twice the magnitude of the positive test charge.

12. By convention, the direction of a current is taken to be the direction of motion of negative charges. In reality, it is actually electrons that move in wires.

13. c. 0.25 A. The current is defined as the rate of flow of charge. Given that 15 C flows through the wire each minute, the current is 15 C/60 s = 0.25 A.

14. b. 1.2x10^6 C. The charge flowing through the wire is given by the equation Q = It, where Q is the charge, I is the current, and t is the time. Substituting the values into the equation, we get Q = (3x10^(-3) A)(1 hour)(3600 s/hour) = 1.2x10^6 C.

15. d. current. An ampere is a unit of electric current.

16. electrons. As current flows through a wire, it is actually electrons that move. The flow of electrons constitutes the electric current.

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Answer:

24 mph

Explanation:

Speed = Distance / Time

Speed = 20 ÷ 5/6

Speed = 24 mph

NOTE: 5/6 is a fraction in this case and is equivalent to 50/60 and 60 minutes = 1 hour of course.

Hope this helped!

Answer:

\(\textsf {speed = 24 mph}\)

Explanation:

\(\textsf {Formula used :}\\\implies \textsf {speed = distance/time}\)

\(\mathsf {Given :}\)

\(\implies \textsf {distance = 20 miles}\)

\(\implies \textsf {time = 50 minutes = 5/6 hour}\)

\(\textsf {Solving :}\)

\(\implies \mathsf {speed = 20 \div 5/6 }\)

\(\implies \mathsf {speed = 20 \times 6/5}\)

\(\implies \mathsf {speed = 4 \times 6}\)

\(\implies \textsf {speed = 24 mph}\)

(a) The angular frequency is  2.7 Hz

(b) The maximum speed is  2.04 m/s

(c) The maximum value is occur at mean position

 so the dispalcement is zero

(d) The maximum acceleration is 34.68 m/s^2.

(e) The acceleartion should be maximum at extrem positions

  so the position  x = A = 12 cm

( f )  The force on the block  15.6 N

Calculation :

The mass of the block m = 0.45 kg

The dispalcement of the block

 x = 12cm cos [(17 rad/s) t + (π/2 rad)]

 (a) The angular frequency

                 ω = 17 rad/s

                  2πf = 17 rad/s

then the frequency

               f = 17 / 2π = 2.7 Hz

(b) The maximum speed

              v max = Aω  = (12 cm) (17 rad/s)

                                 = 2.04 m/s

(c) The maximum value is occur at mean position

 so the dispalcement is zero

(d) The maximum acceleration

     a max  = Aω^2

                = (0.12 m) (17)^2 = 34.68 m/s^2

(e) The acceleartion should be maximum at extrem positions

  so the position  x = A = 12 cm

(f)  The force on the block

           F = ma = (0.45 kg) (34.68 )

                        = 15.6 N

Force or Energy Exercised or Applied: Cause of Movement or Change: Active Force. force of nature

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Answer:

Let there be vectors A and B  where B = -A

Then A + B = 0