A rocket accelerates vertically upwards from rest with a net acceleration of 5.4 ms −2
. How long (in s) will it take to reach an altitude of 116.7 km ?

Answer:

Encounter multiple hazards from any direction

Explanation:

The chemical energy that Product Z contains is 205.5 J.

Given that the chemical energy of Reactant X is 199.3 J, the chemical energy of Reactant Y is 272.3 J, and the chemical energy of Product W is 41.9 J, we need to find the chemical energy of Product Z. If the reaction loses 111.6 J of chemical energy as it proceeds, we can apply the Law of Conservation of Energy:

Initial Energy of Reactant = Final Energy of Product

Mathematically, it can be written as:

Reactant X + Reactant Y - Energy lost in the reaction = Product W + Product Z

Substituting the given values:

199.3 J + 272.3 J - 111.6 J = 41.9 J + Product Z

Simplifying:

359 J - 111.6 J - 41.9 J = Product Z

Product Z = 205.5 J.

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Answer: 34

Explanation:

34

Answer:

Potential

Explanation:

hope this helps

Electricity can be produced by the relative motion of coil and a magnet.

We know that it is possible that we can be able to generate electricity by the alteration of a magnetic field. This is what we call the generation of electricity by electromagnetic induction. This was well discussed by Michael Faraday.

We have to note that the relative motion between the coils and the magnetic field is able to cause the fact that current would be induced in the coils as stated by the principle.

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If i1/i0=4/5, the ratio of i2/i0 is 0.667 when applied across the resistor.

Resistor is defined as a two-terminal passive electrical device that uses electrical resistance as a circuit component. High resistance resistors will withstand a lot of electric current.

We can say that I1 / I0 = 4/5 , I1 = 4 and I0 = 5.

We know that V = IR So, I = V / R

Thus I0 = 5 V /1 so, V = 5

V = IR

5 = 4 x (Ru +Rr)

5 = 4 x (1 + Rr)

Rr = 0.25

So, for I2

V = I2 x R

V = I2 (Rr + Rr + Ru)

5 = I2 x (1.5)

I2 = 3.333

So, the ratio is I2 / I0 = 3.333 / 5 = 0.667

Thus, if i1/i0=4/5, the ratio of i2/i0 is 0.667 when applied across the resistor.

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The change in relative humidity throughout the day and night is primarily influenced by two factors: temperature and the diurnal cycle of atmospheric moisture.

The relative humidity refers to the amount of water vapor present in the air compared to the maximum amount of water vapor the air can hold at a particular temperature. The change in relative humidity throughout the day and night is primarily influenced by two factors: temperature and the diurnal cycle of atmospheric moisture.

During the day, as the Sun heats the Earth's surface, the temperature rises. Warmer air can hold more water vapor, so the air's capacity to hold moisture increases. However, this does not necessarily mean that the actual amount of water vapor in the air increases proportionally. As the air warms up, it becomes less dense and can rise, leading to vertical mixing and dispersion of moisture. Additionally, the warmer air can enhance the evaporation of water from surfaces, including bodies of water and vegetation. These processes tend to result in a decrease in relative humidity during the day.

At night, the opposite occurs. As the Sun sets and the temperature drops, the air cools down. Cooler air has a lower capacity to hold moisture, so the relative humidity tends to increase. The cooler air reduces the rate of evaporation and allows moisture to condense, leading to an accumulation of water vapor in the air. The reduced temperature also lowers the air's ability to disperse moisture through vertical mixing. As a result, relative humidity tends to be higher during the night.

It's important to note that local geographic and meteorological conditions can also influence relative humidity patterns, so variations may occur depending on the specific location and climate.

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The final speeds of the spheres are 3.47 m/s and 3.08 m/s.

We can use conservation of momentum to solve this problem since there are no external forces acting on the system.

The initial momentum of the system is:

p_initial = m₁ * v₁ + m₂ * v₂

where m₁ and m₂ are the masses of the spheres, and v₁ and v₂ are their initial velocities (4.00 m/s and 0 m/s, respectively).

After the collision, the momentum of the system is:

p_final = m₁ * v1' + m₂ * v₂'

where v₁' and v₂' are the final velocities of the spheres. We also know that the angle between the first sphere's final path and its initial path is 60 degrees, which means that the angle between the two spheres after the collision is 150 degrees (90 + 60).

Using conservation of momentum, we can set the initial and final momenta equal to each other:

m₁ * v₁ + m₂ * v₂ = m₁ * v₁' + m₂ * v₂'

We can also break down the final velocities into their x and y components using trigonometry. Let's define the angle between the first sphere's final path and the x-axis as theta. Now we can use conservation of momentum to solve for the final velocities:

m₁ * v₁ + m₂ * v₂ = m₁ * v₁' * cos(theta) + m₂ * v₂' * cos(150 degrees)

0 = m₁ * v₁' * sin(theta) + m₂ * v₂' * sin(150 degrees)

Solving the first equation for v₂', we get:

v₂' = (m₁ * v₁ + m₂ * v₂ - m₁ * v₁' * cos(theta)) / (m₂ * cos(150 degrees))

Substituting this expression into the second equation and solving for v₁', we get:

v₁' = (m₂ * sin(150 degrees) * v₁ + m₂ * sin(150 degrees) * v₂ + m₁ * sin(theta) * v₁' - m₁ * sin(theta) * m₂ * v₁ * cos(theta) / cos(150 degrees)) / (m₁ * sin(theta))

Plugging in the given values and solving, we get:

v₁' = 3.47 m/s

v₂' = 3.08 m/s

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Given that two electrons are transferred from a neutral atom A to another neutral atom B to create a positive ion A+ and a negative ion B−. If the magnitude of the electrostatic force between two ions is 5.67E-12 N, we need to find the separation distance between the ions. We can solve this problem using Coulomb's law.Coulomb's law states that the magnitude of the electrostatic force of attraction or repulsion between two point charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them. Mathematically,F = kq1q2 / r²Here, F is the force of attraction or repulsion between two point chargesq1 and q2 are the magnitudes of the chargesk is Coulomb's constantr is the distance between two chargesLet's substitute the given values in the formula and solve for r.F = 5.67E-12 Nk = 9 x 10^9 Nm²/C²q1 = q2 = e (charge on one electron) = 1.6 x 10⁻¹⁹ C Rearranging the formula to solve for r,r = sqrt(kq1q2/F) Substituting the given values in the above equation, r = sqrt((9 x 10^9 Nm²/C²) x (1.6 x 10⁻¹⁹ C)² / (5.67 x 10⁻¹² N))r = 2.04 x 10⁻¹⁰ mThe separation distance between the ions is 2.04 x 10⁻¹⁰ m. Therefore, option D is the correct answer.

Atom is taken from the Greek word 'atomos' which means indivisible. Atom is a basic unit of matter, which consists of an atomic nucleus and a cloud of negatively charged electrons that surround it. The atomic nucleus consists of positively charged protons and neutral charged neutrons. The electrons in an atom are bound to the nucleus by electromagnetic forces.

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Answer:

0.63m/s²

Explanation:

The average acceleration can be derived from using the formula:

V = u + at

Where v = final velocity (m/s)

u = initial velocity (m/s)

a = acceleration (m/s²)

t = time (s)

V = u + at

V - u = at

a = v - u/t

a = ∆V/t

According to the provided information; v = 5.8m/s, u = 0m/s, t = 9.25s

a = ∆V/t

a = (5.8-0)/9.25

a = 5.8/9.25

a = 0.627

a = 0.63m/s²

Hence, the average acceleration is 0.63m/s²

The average acceleration of the ferry which leaves Guemes Island and heads back  toward Anacortes is 0.627m/s².

Given the data in the question;

To determine the average acceleration, we use the first equation of motion:

\(v = u + at\)

Where v is final speed, u is initial speed, a is acceleration and t is time taken.

We substitute our given values into the equation

\(5.8m/s = 0 + [ a * 9.25s ]\\\\5.8m/s = a * 9.25s\\\\a = \frac{5.8m/s}{9.25s}\\\\a = 0.627m/s^2\)

Therefore, the average acceleration of the ferry which leaves Guemes Island and heads back  toward Anacortes is 0.627m/s².

For maximum power generation, it is ideal if the water rebounds off of the turbine blades. If the water bounces back, it has undergone a greater shift in momentum than if it had simply stopped. Additionally, the blades will spin quicker if there is a greater momentum change for the water than there is for the blades.

The momentum of a body's center of mass can only be changed by the application of an external force, according to the laws of motion. However, due to the force of friction created by the car's tires in contact with the ground, it can be accelerated by applying an internal engine force.

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"What Is It and What Are Some Differences Between High and Low Specific Heat Capacity?"

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Hello! Today, let's begin with discussing what specific heat capacity is.

"What is Specific Heat Capacity?"

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"What is High and Low Specific Heat Capacity?"

______________________________________________________

Hopefully this sort of helps you have a better understanding of what specific heat is, as well as the differences between that of high and low specific heat capacity. Also, if this is a write your answer response, it is better to dive further into your studies and notes regarding this topic so you can properly answer the question and follow the guidelines. Anyways, I wish you the best of luck on your assignment. Thanks for reading!

Based on the measurements, the maximum height reached by the puck in trial 6 is determined as 5.1 m.

The maximum height reached by the puck is calculated by applying the principle of conservation of energy as shown below;

From the trials, the puck was thrown upwards with initial velocity of 10 m/s and the mass of the puck is given as 400 g.

With these values we can predict the maximum height the puck will reach by applying the principle of conservation of energy.

Potential energy of the puck at maximum height = Kinetic energy of the puck at minimum height

P.E = K.E

mgh = ¹/₂ mv²

h = ¹/₂ (v² / g )

where;

The maximum height reached by the puck is calculated as follows;

h =  ¹/₂ (10² / 9.8 )

h = 5.1 m

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Answer: 0

Explanation:

Given

Shaneil hold the 20 N box for 40 s

Since there is no movement of the box, so velocity associated with it is zero and the workdone by the shaniel is also zero.

Power is the rate of doing work. Therefore, it is also zero.

The size of the electric current is 155 Amperes.

Calculation:

I = Q / t

I = 93.0 C / 0.601 s

I = 155 C/s

I = 155 A

Electric current is the flow of charged particles such as electrons and ions, that travel through a conductor or space. It is measured as the net flux of charge to the surface or control volume. Electricity starts with atoms.

Atoms are made up of protons neutrons and electrons. Electricity is generated when electrons are moved from atom to atom by an external force. The flow of electrons is called current. Current refers to the flow of current in an electronic circuit and the amount of current that flows through the circuit.

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Answer:   PbBr4 is covalent

The net force on particle 92 is approximately 8.10 × 10¹¹ N to the right.

The net force on particle 92 due to particles 91 and 93 can be calculated using Coulomb's law:

F = k * |q₁| * |q₂| / r² where k is the Coulomb constant (9.0 × 10⁹ N·m²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them. The direction of the force is given by the signs of the charges.

The force on particle 92 due to particle 91 is:

F₁ = k * |91| * |92| / r² = k * 66.3 * 108 / (0.550)²

≈ 4.90 × 10^11 N

Since particle 91 has a negative charge and is to the left of particle 92, the force it exerts on particle 92 is to the right (positive).

The force on particle 92 due to particle 93 is:

F₃ = k * |93| * |92| / r² = k * 43.2 * 108 / (0.550)²

≈ 3.20 × 10¹¹ N

Since particle 93 has a negative charge and is to the right of particle 92, the force it exerts on particle 92 is also to the right (positive).

The net force on particle 92 is the vector sum of F₁ and F₃:

Fnet = F₁ + F₃ ≈ 8.10 × 10¹¹ N to the right.

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The ratio of the mass density of girder a to the mass density of girder b is 1/2.

It is possible to measure a materials density by how closely it is packed. The mass per unit volume is how it is formally defined. The density is expressed as follows: = m/V, where m is the object's mass and V is its volume.

A material substance's density is defined as its mass per unit volume. D is density, M is mass, and V is volume, and the formula for density is d = M/V. Most often, grammes per cubic centimetre are used to express density.

Since they are made of same material, their mass density is same. Their mass is different but not mass density.

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answer

so unit of velocity is m/s

displacement=600m

5minutes should be converted to seconds

5×60=300 seconds

so,

velocity= displacement÷time

= 600m ÷300s

=2m/s or 2ms^-1

Answer:

2 m/s

Explanation:

we have given

distance traveled by body =600m

time taken = 5*60 =300 sec( si unit of time is second)

velocity =?

we know that

velocity =distance traveled/ time taken

=600/300

= 2 m/s

The electric field strength inside the solenoid at a point on the axis is -7.45 x 10⁻³ V/m.

The electric field strength inside the solenoid can be found using Faraday's Law of Induction, which states that the induced electric field is proportional to the rate of change of magnetic flux.
Since the solenoid has a diameter of 5.0 cm, its radius is 2.5 cm or 0.025 m. The magnetic field inside the solenoid can be expressed as B = μ₀ * n * I, where μ₀ is the permeability of free space, n is the number of turns per unit length, and I is the current. Since the solenoid is not mentioned to have any current, we assume that there is no current and the magnetic field is solely due to the changing magnetic flux. Therefore, we can use the equation ε = -dΦ/dt to find the electric field strength, where ε is the induced electric field and dΦ/dt is the rate of change of magnetic flux.
The magnetic flux through the solenoid is given by Φ = B * A, where A is the area of the cross-section of the solenoid. Since the solenoid has a diameter of 5.0 cm, its cross-sectional area can be expressed as A = π * r² = π * (0.025 m)² = 1.96 x 10⁻³ m².
Substituting the given values into the equation, we have:
ε = -dΦ/dt = -d(B * A)/dt = -A * dB/dt
ε = -(1.96 x 10⁻³ m²) * (3.80 t/s) = -7.45 x 10⁻³ V/m
Therefore, the electric field strength inside the solenoid at a point on the axis is -7.45 x 10⁻³ V/m.

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Answer:

221.29 Watts

Explanation:

P=W/t

P=686/3.1

P=221.29 Watts

The angular velocity of Mars as it orbits the Sun is approximately \(1.03 * 10^{-7}\)  radians per second.

The angular velocity of an object in circular motion is defined as the rate at which it sweeps out angle per unit of time. In the case of Mars orbiting the Sun, its angular velocity represents the speed at which it moves along its orbital path.

To calculate the angular velocity of Mars, we need to know its orbital period and the radius of its orbit. The orbital period of Mars is approximately 687 Earth days, and the radius of its orbit is approximately 227.9 million kilometers.

Using the equation for angular velocity (ω = 2π / T), where ω is the angular velocity and T is the period, we can calculate the angular velocity of Mars.

ω = 2π / T = 2π / (687 days * 24 hours/day * 60 minutes/hour * 60 seconds/minute)

Substituting the values into the equation and performing the calculations, we find that the angular velocity of Mars as it orbits the Sun is approximately \(1.03 * 10^{-7}\)  radians per second.

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the fundamental frequency of this pipe is 273 Hz. The fundamental frequency of a pipe that is open at both ends is determined by the formula f = v/2L, where f is the frequency, v is the speed of sound, and L is the length of the pipe. However, since we are given the frequency of the standing wave (which is the third harmonic), we need to use the formula f = 3v/2L to solve for the speed of sound. Once we have the speed of sound, we can then use the formula f = v/2L to solve for the fundamental frequency.

First, we need to solve for the speed of sound. We know that the frequency of the standing wave is 182 Hz, which is the third harmonic since the pipe is open at both ends. This means that the third harmonic is produced when the wavelength of the sound wave is three times the length of the pipe. We can write this as:

λ = 3L

where λ is the wavelength and L is the length of the pipe.

We also know that the speed of sound is equal to the product of the frequency and wavelength, or:

v = fλ

Substituting 182 Hz for f and 3L for λ, we get:

v = (182 Hz)(3L) = 546L Hz

Now that we know the speed of sound, we can solve for the fundamental frequency using the formula f = v/2L. Substituting 546L Hz for v and L for L, we get:

f = (546L Hz)/(2L) = 273 Hz

Therefore, the fundamental frequency of this pipe is 273 Hz.

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Answer:

1025meter

Explanation:Distance is speed times time.so 3hx115km/h=345km

                                                                              5hx136km/h=680km

                                                                              345km+680km=1025km

Answer:

1025

Explanation:

Answer:

motion and forces

heat

waves

gravity

math

electricity and magnetism

conversation of energy and momentum

Answer:

pluto

Explanation:

Dwarf because it is very minut

Answer:

I think Saturn.

Explanation:

I think the inner planets are Mercury, Venus, Earth and Mars whereas the outer ones are Jupiter, Saturn, Uranus and Neptune.

Answ

— How can a small boy balance a big boy on a sea-saw? Show with a diagram. fast please...... Get the answers you need, now!

2 answers

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Explanation:

The center of mass of the thin plate is located at (x_cm, y_cm) = (0, 8/5) or (0, 1.6) units.

First, we need to find the total area A of the region bounded by the parabola and the line:

A = ∫[-2,2] (8 - 2x^2) dx

Integrating with respect to x:

A = [8x - (2/3)x^3] evaluated from -2 to 2

A = [8(2) - (2/3)(2^3)] - [8(-2) - (2/3)(-2^3)]

A = [16 - (2/3)(8)] - [-16 - (2/3)(-8)]

A = 16 - 16/3 + 16 + 16/3

A = 48/3

A = 16 square units

Now, let's calculate the center of mass coordinates:

x_cm = (1/M) ∫[-2,2] x * dm

y_cm = (1/M) ∫[-2,2] y * dm

Since the plate has constant density, we can express dm = ρ * dA, where ρ is the density and dA is the differential area element.

Let's substitute dm = ρ * dA into the center of mass formulas:

x_cm = (1/M) ∫[-2,2] x * (ρ * dA)

y_cm = (1/M) ∫[-2,2] y * (ρ * dA)

The density (ρ) cancels out in both equations, so we can write:

x_cm = (1/A) ∫[-2,2] x * dA

y_cm = (1/A) ∫[-2,2] y * dA

Now, we'll substitute the equations of the parabola and the line:

x_cm = (1/A) ∫[-2,2] x * dA

y_cm = (1/A) ∫[-2,2] y * dA

x_cm = (1/16) ∫[-2,2] x * dA

y_cm = (1/16) ∫[-2,2] y * dA

Density = 1 units

Recall the expressions for the center of mass coordinates:

x_cm = (1/A) ∫[-2,2] x * dA

y_cm = (1/A) ∫[-2,2] y * dA

Since the density is 1, we can simplify the expressions further:

x_cm = (1/16) ∫[-2,2] x * dA

y_cm = (1/16) ∫[-2,2] y * dA

We need to evaluate the integrals of x * dA and y * dA. Let's start with x * dA:

x_cm = (1/16) ∫[-2,2] x * dA

Substituting x = x and dA = y * dx:

x_cm = (1/16) ∫[-2,2] x * (y * dx)

x_cm = (1/16) ∫[-2,2] x * (2x^2 * dx)

Expanding and simplifying the expression:

x_cm = (1/8) ∫[-2,2] x^3 * dx

Integrating with respect to x:

x_cm = (1/8) * [ (1/4) * x^4 ] evaluated from -2 to 2

x_cm = (1/8) * [ (1/4) * (2^4) - (1/4) * (-2^4) ]

x_cm = (1/8) * [ 4 - 4 ]

x_cm = 0

Similarly, for y * dA:

y_cm = (1/16) ∫[-2,2] y * dA

Substituting y = 2x^2 and dA = y * dx:

y_cm = (1/16) ∫[-2,2] (2x^2) * (2x^2 * dx)

y_cm = (1/8) ∫[-2,2] x^4 * dx

Integrating with respect to x:

y_cm = (1/8) * [ (1/5) * x^5 ] evaluated from -2 to 2

y_cm = (1/8) * [ (1/5) * (2^5) - (1/5) * (-2^5) ]

y_cm = (1/8) * [ 32/5 - (-32/5) ]

y_cm = (1/8) * (64/5)

y_cm = 8/5

Therefore, the center of mass of the thin plate is located at (x_cm, y_cm) = (0, 8/5) or (0, 1.6) units.

The x-coordinate of the center of mass is at the centerline of the region bounded by the parabola and the line, while the y-coordinate is above the centerline but below the line y = 8.

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