A right triangle and some of its measurements are shown in this diagram. Based on the measurements shown in the diagram, what is the value of T? HELP HELP GOD IMMA FAIL PLZ THIS IS URGENT

Answer: The two numerical expressions that correctly represent the phrase "twice the sum of nine and four" are:

2 * (9 + 4) = 2 * 13 = 26

2(9 + 4) = 2(13) = 26

Both expressions use the correct mathematical operations to represent the phrase "twice the sum of nine and four" and both will yield the same result of 26.

Step-by-step explanation:

Answer:

1. 48

2. 45

3. 32

4. B

Step-by-step explanation: Hope this help :D

I HOPE IT WILL HELP YOU.

Thank you.

^ - ^

Answer:

7/1

Step-by-step explanation:

The smallest positive integer n such that t \($\sqrt[4]{56 \cdot n}$\)  is an integer is 686.

We have to find the smallest positive integer n such that \($\sqrt[4]{56 \cdot n}$\) is an integer

To find the smallest positive integer n such that  \($\sqrt[4]{56 \cdot n}$\)   is an integer, we need to determine the factors of 56 and find the smallest value of n that, when multiplied by 56, results in a perfect fourth power.

The prime factorization of 56 is:

56 = 2³ × 7

The prime factors of 56 need to be raised to multiples of 4.

Therefore, we need to determine the smallest value of n that includes additional factors of 2 and 7.

To make the expression a perfect fourth power, we need to raise 2 and 7 to the power of 4, which is 2⁴ × 7⁴

The smallest value of n that satisfies this condition is:

n = 2 × 7³ = 2× 343 = 686

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To find the polar equation of a conic with focus at the pole, directrix y=3, and eccentricity of 2, we can use the definition of a conic in polar coordinates.

The general form of the polar equation for a conic with focus at the pole is given by:

r = \(\frac{ed}{1+e\cos(\theta-\theta_0)}\)

Where:

- r is the distance from the origin (pole) to a point on the conic.

- e is the eccentricity.

- d is the distance from the pole to the directrix.

- θ is the angle between the polar axis and the line connecting the pole to a point on the conic.

- θ_0 is the angle between the polar axis and the line connecting the pole to the focus.

In this case, the focus is at the pole, so θ_0 = 0. The directrix is y = 3, which means its distance from the pole is d = 3. The eccentricity is given as 2, so e = 2.

Substituting these values into the general equation, we get:

r =\(\frac{2\cdot3}{1+2\cos(\theta-0)}\)

Simplifying further:

r =\(\frac{6}{1+2\cos(\theta)}\)

Therefore, the polar equation of the conic with focus at the pole, directrix y=3, and eccentricity of 2 is:

r =\(\frac{6}{1+2\cos(\theta)}.\)

This equation describes the shape of the conic in polar coordinates, where r represents the distance from the origin to a point on the conic, and θ represents the angle between the polar axis and the line connecting the origin to the point.

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Answer:

Solving the system of equations using elimination method, we get x=2, y=0

The ordered pair is: (2,0)

Step-by-step explanation:

We need to solve the system of equations using elimination method.

\(5x-2y = 10\\4x + 2y = 8\)

Let:

\(5x-2y = 10--eq(1)\\4x + 2y = 8--eq(2)\)

Add both equations to eliminate y and find value of x

\(5x-2y = 10\\4x + 2y = 8\\------\\9x=18\\x=\frac{18}{9}\\x=2\)

We get value of x=2

Now, finding value of y by putting value of x in eq(1)

\(5x-2y=10\\Put\:x=2\\5(2)-2y=10\\10-2y=10\\-2y=10-10\\-2y=0\\y=0\)

We get value of y= 0

Solving the system of equations using elimination method, we get x=2, y=0

The ordered pair is: (2,0)

Answer:

the answer is C

Step-by-step explanation:

The probability of occurrence for the events A, B and C is; 1/4.

For the first event A in which case, there's no odd number on the first two rolls, the possible events are; EEE and EEO. Consequently, the required probability is;

Event A = 2/8 = 1/4.

For the event B in which case, there's an even number on both the first and last rolls; the possible events are; EEE and EOE. Consequently, the required probability is;

Event B = 2/8 = 1/4.

For the event C in which case, there's an odd number on each of the first two rolls; the possible events are; OOO and OOE. Consequently, the required probability is;

Event C = 2/8 = 1/4.

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Answer:

56 units

Step-by-step explanation:

add all numbers then divide by 5

30+45+50+75+80 = 280

280/5 = 56

Answer:

False. The product of two negative integers is a positive integer.

Answer:

I also believe it is -4.9 but I may be mistaken

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Answer:

2x2 - 5x - 12 = 0.

(2x + 3)(x - 4) = 0.

2x + 3 = 0 or x - 4 = 0.

x = -3/2, or x = 4. I hope this helps

Step-by-step explanation:

Answer:

13

Step-by-step explanation:

The velocity is given by:

\(\displaystyle v(t)= -2t + 8\)

And the total distance given the velocity is given by:

\(\displaystyle \int_{a}^{b}|v(t)|\, dt\)

So, the total distance traveled by the particle from t = 1 to t = 6 will be:

\(\displaystyle d=\int_{1}^{6}|-2t+8|\, dt\)

The absolute value tells us that:

\(\displaystyle |-2t+8| = \left\{ \begin{array}{ll} -2t+8 & \quad x \leq 4 \\ -(-2t+8) & \quad x > 4\\ \end{array} \right\)

So, split the integral into two parts:

\(\displaystyle d=\int_{1}^{4} (-2t+8)\, dt+\int_{4}^{6}(-(-2t+8))\, dt\)

Integrate:

\(\displaystyle d=(-t^2+8t)\Big|_{1}^{4}+(t^2-8t)\Big|_{4}^{6}\)

Evaluate:

\(\begin{aligned} d&=[(-4^2+8(4))-(-1^2+8)]+[(6^2-8(6))-(4^2-8(4)]\\ &= [16-7]+[-12-(-16)]\\ &=9+4 \\ &=13 \end{aligned}\)

Answer:

Y = 4

Step-by-step explanation:

5x-y=54

50-y=54

circle y and subtract 50 from itself then subtract 50 from 54.

after subtracting you should have y=4

The mean absolute deviation is 0.75

To calculate the mean absolute deviation (M.A.D.), you need to find the average of the absolute differences between each data point and the mean of the data set

From the information given, we have that the data set is;

8 9 9 7 8 6 9 8

Let's calculate the mean, we get;

Mean = (8 + 9 + 9 + 7 + 8 + 6 + 9 + 8) / 8

Mean = 64 / 8

Divide the values

Mean = 8

Let's determine the absolute difference, we get;

Absolute differences=

|8 - 8| = 0

|9 - 8| = 1

|9 - 8| = 1

|7 - 8| = 1

|8 - 8| = 0

|6 - 8| = 2

|9 - 8| = 1

|8 - 8| = 0

Find the mean of the absolute differences:

Average of absolute differences = (0 + 1 + 1 + 1 + 0 + 2 + 1 + 0) / 8

Absolute difference = 6 / 8 = 0.75

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Answer:

Now plot those points in graph and find intersection hope it helps you.......

Answer:

Inequality Form:

x<4

1<4

3<4

-1004<4

Interval Notation:

(−∞,4)

(-1004,4)

(3,4)

(1,4)

Step-by-step explanation:

Answer:

6pi

Step-by-step explanation:

Area of a circle = 2pi*r

d = 12

r = d/2

r=6

Area of semicircle = (2pi *r)/2 = pi*r

pi*6 = 6pi

Answer:18π cm^2

Step-by-step explanation:

diameter=12

Radius=diameter ➗ 2

Radius=12 ➗ 2

Radius=6

Area of semicircle=0.5 x π x radius x radius

Area of semicircle=0.5xπx6x6

Area of semicircle=18π cm^2

Answer:

no

Step-by-step explanation:

6^2+7^2=9^2

36+49=81

no its not a right triangle

Answer:

B

Step-by-step explanation:

B

x - 4 squared provides 2 real zeros that are the same. These two are not distinct.

The other two come from x^2 - 7x + 10 which has a discriminate of

sqrt(7^2 - 4*1*10) = sqrt(9) = +/- 3 leading to something real and different.

Answer:

B. The function has three distinct real zeros.

Step-by-step explanation:

For all Plato users

Based on the given assumptions and calculations, the net present value (NPV) of the investment in the new piece of equipment is -$27,045.76, indicating that the investment is not favorable.

To calculate the after-tax cash flows for each year and evaluate the investment decision, let's use the following information:

Assumptions:

Tax depreciation is straight-line over five years.

Pre-tax salvage value is $10,000 in Year 5 and $15,000 if the asset is scrapped in Year 4.

Tax on salvage value is 30% of the difference between salvage value and book value of the investment.

The cost of capital is 12%.

Given:

Initial investment cost = $50,000

Useful life of the equipment = 5 years

To calculate the depreciation expense each year, we divide the initial investment by the useful life:

Depreciation expense per year = Initial investment / Useful life

Depreciation expense per year = $50,000 / 5 = $10,000

Now, let's calculate the book value at the end of each year:

Year 1:

Book value = Initial investment - Depreciation expense per year

Book value \(= $50,000 - $10,000 = $40,000\)

Year 2:

Book value = Initial investment - (2 \(\times\) Depreciation expense per year)

Book value \(= $50,000 - (2 \times$10,000) = $30,000\)

Year 3:

Book value = Initial investment - (3 \(\times\) Depreciation expense per year)

Book value = $50,000 - (3 \(\times\) $10,000) = $20,000

Year 4:

Book value = Initial investment - (4 \(\times\) Depreciation expense per year)

Book value \(= $50,000 - (4 \times $10,000) = $10,000\)

Year 5:

Book value = Initial investment - (5 \(\times\) Depreciation expense per year)

Book value \(= $50,000 - (5 \times $10,000) = $0\)

Based on the assumptions, the salvage value is $10,000 in Year 5.

If the asset is scrapped in Year 4, the salvage value is $15,000.

To calculate the tax on salvage value, we need to find the difference between the salvage value and the book value and then multiply it by the tax rate:

Tax on salvage value = Tax rate \(\times\) (Salvage value - Book value)

For Year 5:

Tax on salvage value\(= 0.30 \times ($10,000 - $0) = $3,000\)

For Year 4 (if scrapped):

Tax on salvage value\(= 0.30 \times ($15,000 - $10,000) = $1,500\)

Now, let's calculate the after-tax cash flows for each year:

Year 1:

After-tax cash flow = Depreciation expense per year - Tax on salvage value

After-tax cash flow = $10,000 - $0 = $10,000

Year 2:

After-tax cash flow = Salvage value - Tax on salvage value

After-tax cash flow = $0 - $0 = $0

Year 3:

After-tax cash flow = Salvage value - Tax on salvage value

After-tax cash flow = $0 - $0 = $0

Year 4 (if scrapped):

After-tax cash flow = Salvage value - Tax on salvage value

After-tax cash flow = $15,000 - $1,500 = $13,500

Year 5:

After-tax cash flow = Salvage value - Tax on salvage value

After-tax cash flow = $10,000 - $3,000 = $7,000

Now, let's calculate the net present value (NPV) using the cost of capital of 12%.

We will discount each year's after-tax cash flow to its present value using the formula:

\(PV = CF / (1 + r)^t\)

Where:

PV = Present value

CF = Cash flow

r = Discount rate (cost of capital)

t = Time period (year)

NPV = PV Year 1 + PV Year 2 + PV Year 3 + PV Year 4 + PV Year 5 - Initial investment

Let's calculate the NPV:

PV Year 1 \(= $10,000 / (1 + 0.12)^1 = $8,928.57\)

PV Year 2 \(= $0 / (1 + 0.12)^2 = $0\)

PV Year 3 \(= $0 / (1 + 0.12)^3 = $0\)

PV Year 4 \(= $13,500 / (1 + 0.12)^4 = $9,551.28\)

PV Year 5 \(= $7,000 / (1 + 0.12)^5 = $4,474.39\)

NPV = $8,928.57 + $0 + $0 + $9,551.28 + $4,474.39 - $50,000

NPV = $22,954.24 - $50,000

NPV = -$27,045.76

The NPV is negative, which means that based on the given assumptions and cost of capital, the investment in the new piece of equipment would result in a net loss.

Therefore, the investment may not be favorable.

Please note that the calculations above are based on the given assumptions, and additional factors or considerations specific to the business should also be taken into account when making investment decisions.

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The complete question may be like :

Assumptions: Tax depreciation is straight-line over five years. Pre-tax salvage value is $10,000 in Year 5 and $15,000 if the asset is scrapped in Year 4. Tax on salvage value is 30% of the difference between salvage value and book value of the investment. The cost of capital is 12%.

You are evaluating an investment in a new piece of equipment for your business. The initial investment cost is $50,000. The equipment is expected to have a useful life of five years.

Using the given assumptions, calculate the after-tax cash flows for each year and evaluate the investment decision by calculating the net present value (NPV) using the cost of capital of 12%.

Answer:

Area of Rectangle A

\(Area = 4x^2\)

Area of Rectangle B

\(Area = 2x^2\)

Fraction

\(Fraction =\frac{2}{3}\)

Step-by-step explanation:

From the attached, we understand that:

The dimension of rectangle A is 2x by 2x

The dimension of rectangle B is x by 2x

Area of rectangle is calculated as thus;

\(Area = Length * Breadth\)

Area of Rectangle A

\(Area = 2x * 2x\)

\(Area = 4x^2\)

Area of Rectangle B

\(Area = x * 2x\)

\(Area = 2x^2\)

Area of Big Rectangle

The largest rectangle is formed by merging the two rectangles together;

The dimension are 3x by 2x

The Area is as follows

\(Area = 2x * 3x\)

\(Area = 6x^2\)

The fraction of rectangle A in relation to the largest rectangle is calculated by dividing area of rectangle A by area of the largest rectangle;

\(Fraction = \frac{Rectangle\ A}{Biggest}\)

\(Fraction =\frac{4x^2}{6x^2}\)

Simplify

\(Fraction =\frac{2x^2 * 2}{2x^2 * 3}\)

\(Fraction =\frac{2}{3}\)

Answer:

C. μ = 3.60

Step-by-step explanation:

Two tables have been attached to this response.

One of the tables contains the given data and distribution with two columns: Houses Sold and Probability

The other table contains the analysis of the data with additional columns: Frequency and Fx

=> The Frequency(F) column is derived from the product of the probability of each item in the Houses sold column and the total number of houses sold (which is 28). For example,

When the number of houses sold = 0

F = P(0) x Total number of houses sold

F = 0.24 x 28 = 6.72

When the number of houses sold = 1

F = P(1) x Total number of houses sold

F = 0.01 x 28 = 0.28

=> The Fx column is found by multiplying the Frequency column by the Houses Sold column. For example,

When the number of houses sold = 0

Fx = F * x

F = 6.72 x 0 = 0

Now to get the mean, μ we use the relation;

μ = ∑Fx / ∑F

Where;

∑Fx = summation of the items in the Fx column = 100.8

∑F = summation of the items in the Frequency column = 28

μ = 100.8 / 28

μ = 3.60

Therefore, the mean of the given probability distribution is 3.60

The mean of the discrete probability distribution is given by:

C. μ = 3.60

The expected value of a discrete distribution is given by the sum of each outcome multiplied by it's respective probability.

In this problem, the table x - P(x) gives each outcome and their respective probabilities, hence, the mean is:

\(E(X) = 0(0.24) + 1(0.01) + 2(0.12) + 3(0.16) + 4(0.01) + 5(0.14) + 6(0.11) + 7(0.21) = 3.6\)

Hence option C is correct.

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Answer:

The question is incomplete

Answer:

It was 1/3 before

Step-by-step explanation:

Answer:

You first work out the radius, as below:

Area = pi x radius^2

=> radius = sqrt(Area/pi)

Then, you find out circumference C.

=> C = 2 x pi x radius

Hope this helps!

:)

Complete Question

Suppose that the random variable X represents the length of a punched part in

centimeters. Let Y be the length of the part in millimeters. If E(X) = 5 and V(X) = 0.25,

what are the mean and variance of Y?

Answer:

The mean

\(E(Y) =50 mm\)

The variance

\(V(Y) = 25 mm\)

Step-by-step explanation:

From the question we are told that  

   Length in cm is  X

   Length in mm is Y

  Generally  10 mm  =  1 cm

So

    \(Y = 10 X\)

Hence the expected mean of Y is  

  \(E(Y) = E (10 X)\)

=>    \(E(Y) = 10 E(X)\)

From the question \(E(X) = 5\)

So

      \(E(Y) = 10 * 5\)

=> \(E(Y) =50 mm\)

Gnerally the variance of  X is  

      \(V(X) = E [X^2] -E[X]^2\)

From the question we are told that \(V(X) = 0.25\)

=> \(0.25 = E [X^2] -E[X]^2\)

Gnerally the variance of Y

    \(V(Y) = E [Y^2] -E[Y]^2\)

=> \(V(Y) = E [10X^2] -E[X]^2\)

=> \(V(Y) = 10^2[ E [X^2] -E[X]^2]\)

=> \(V(Y) = 10^2* V(X)\)

=> \(V(Y) = 10^2* 0.25\)

=> \(V(Y) = 25 mm\)

The value of df, when x = π/4 and dx = 1/24, is (-5π - 5√2)/(96√2).

To find the derivative of the function f(x) = -5cos(x) + xtan(x), we'll use the sum and product rules of differentiation. Let's start by finding df/dx.

Apply the product rule:

Let u(x) = -5cos(x) and v(x) = xtan(x).

Then, the product rule states that (uv)' = u'v + uv'.

Derivative of u(x):

u'(x) = d/dx[-5cos(x)] = -5 * d/dx[cos(x)] = 5sin(x) [Using the chain rule]

Derivative of v(x):

v'(x) = d/dx[xtan(x)] = x * d/dx[tan(x)] + tan(x) * d/dx[x] [Using the product rule]

= x * sec^2(x) + tan(x) [Using the derivative of tan(x) = sec^2(x)]

Applying the product rule:

(uv)' = (5sin(x))(xtan(x)) + (-5cos(x))(x * sec^2(x) + tan(x))

= 5xsin(x)tan(x) - 5xcos(x)sec^2(x) - 5cos(x)tan(x)

Simplify the expression:

df/dx = 5xsin(x)tan(x) - 5xcos(x)sec^2(x) - 5cos(x)tan(x)

Now, we need to evaluate df/dx at x = π/4 and dx = 1/24.

Substitute x = π/4 into the derivative expression:

df/dx = 5(π/4)sin(π/4)tan(π/4) - 5(π/4)cos(π/4)sec^2(π/4) - 5cos(π/4)tan(π/4)

Simplify the trigonometric values:

sin(π/4) = cos(π/4) = 1/√2

tan(π/4) = 1

sec(π/4) = √2

Substituting these values:

df/dx = 5(π/4)(1/√2)(1)(1) - 5(π/4)(1/√2)(√2)^2 - 5(1/√2)(1)

Simplifying further:

df/dx = 5(π/4)(1/√2) - 5(π/4)(1/√2)(2) - 5(1/√2)

= (5π/4√2) - (10π/4√2) - (5/√2)

= (5π - 10π - 5√2)/(4√2)

= (-5π - 5√2)/(4√2)

= (-5π - 5√2)/(4√2)

Now, to evaluate df/dx when dx = 1/24, we'll multiply the derivative by the given value:

df = (-5π - 5√2)/(4√2) * (1/24)

= (-5π - 5√2)/(96√2)

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