A radio station tower was built in two sections. From a point 87 feet from the base of the tower, the angle of elevation of the top of the first section is 25 degrees, and the angle of the top of the second section is 40 degrees. to the nearest foot, what is the height of the top section of the tower?

Answer:

The answer is "\(5.53 \ \frac{m}{s}\)"

Explanation:

apply the formula for calculating the average velocity to the relative air

\(V_{PG} =V_{PA}+V_{AG}\)

\(\Rightarrow V_{PA} = V_{PG} -V_{AG}\)

Given value:

\(V_{AG} = -2 \ \frac{m}{s}\)

\(V_{PG} =3.53\)

\(\Rightarrow V_{PA} = 3.53 - (-2) \\\\\Rightarrow V_{PA} = 3.53 +2 \\\\\Rightarrow V_{PA} = 5.53 \\\\\)

The final answer is "\(5.53 \ \frac{m}{s}\)" in the south-east direction.

A source travelling in the direction of the observer causes Doppler blueshift.

When an object is moving towards us, the light from the object is known as blueshift.

The phrase refers to any relative motion, that causes a decrease in the wavelength and rise in frequency, including those that take place outside of the visible spectrum.

During the motion of the object towards us, blueshift will happen, thus shifting light to shorter wavelengths on the blue side of the spectrum.

This causes the color to shift from the red to the blue end of the spectrum in visible light.

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Given

Rope at second harmoic frequency is 8hz

Procedure

The fundamental vibrational mode of a stretched string is such that the wavelength is twice the length of the string.

f1 = Fundamental frequency

f2 = 2f1

f1 = f2/2

f1 = 8 Hz/2

f1 = 4 Hz

Now, for the fifth harmonic

f5 = 32f1

f5 = 32*4

f5 = 128 Hz

The fifth harmonic would be 128 hz

Answer:

1. A =3i - 9j

B = -4i + 2j

A.B = -12 - 18 = -30

2. A = 5i + 5j

B = 2i - 4j

A.B = 10 - 20 = -10

3. A = 8i + 4j

B = 41 - 8j

A.B = 32 - 32 = 0

Answer:

C

Explanation:

PV=nRT

Here

P=Pressure

V=Volume

n=Molarity

R=universal gas constant

T=Temperature.

LHS

\(\\ \tt\bull\leadsto PV\)

\(\\ \tt\bull\leadsto [ML^2T^{-2}][M^0L^3T^0]\)

\(\\ \tt\bull\leadsto [ML^5T^{-2}]\)

RHS

\(\\ \tt\bull\leadsto nRT\)

\(\\ \tt\bull\leadsto [M^0L^{3}T^0][M^1 L^2 T^{-2}K^{-1}][M^0L^0T^0K^1]\)

\(\\ \tt\bull\leadsto [ML^5T^{-2}]\)

LHS=RHS

hence verified

The rise in temperature of the body as determined from the specific heat capacity, mass, and heat change of the body is 12.24 °C.

The rise in temperature of the body is determined from the specific heat capacity, mass, and heat change of the body.

The formula relating the temperature rise of the body, the specific heat capacity, mass, and heat change of the body is given below:

Heat change = mass * specific heat capacity * temperature rise

Temperature rise = Heat change / mass * specific heat capacity

Temperature rise = 3.6 * 10⁶ J / 84 kg * 3,500 J/kg/°C

Temepartaure rise = 12.24 °C

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The observation that electromagnetic radiation with energy above a certain value can eject electrons out of a metal is a piece of evidence that they have particle-like properties.

The observation that electromagnetic radiation with energy above a certain value can eject electrons out of a metal is a piece of evidence that they have particle-like properties.

This observation that electromagnetic radiation behaves like particles is known as the photoelectric effect.

It provides evidence that electromagnetic radiation exhibits particle-like properties. When EMR with sufficient energy (above a certain threshold) interacts with a metal surface, it can cause the ejection of electrons from the metal.

This behavior indicates that EMR behaves as discrete packets of energy called photons, which transfer their energy to the electrons and cause their release. The photoelectric effect supports the particle nature of EMR and is a fundamental concept in the field of quantum mechanics.

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The description that tells two processes that scientists think move Earth's lithospheric plates is convection in the mantle and pressure of magma on the edge of the plate.

The Earth's lithosphere is the rocky outer part of Earth which is made up of the brittle crust and the top part of the upper mantle.

The Earth's lithosphere deflects the convections and as the convections churn clockwise of anticlockwise, they drag the  lithosphere with it via friction an this is what is stipulated to cause tectonic plate movements.  

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Answer: convection in the mantle and pressure of magma on the edge of the plate

Explanation: I took the unit test

The wavelength of light that should be used to obtain fringes that are 0.0045 m wide after reducing the distance between the screen and the slit by half is 2.25 * 10^7 Å.

Huygens's Principle states that every point on a wavefront can be considered as a source of secondary spherical wavelets that spread out in all directions with the same speed as the original wave. The new wavefront is formed by the envelope of these secondary wavelets at a later time.

Now, let's consider a Young's double-slit experiment. In this experiment, when light passes through two narrow slits, it creates an interference pattern on a screen behind the slits. The fringe width is the distance between two consecutive bright or dark fringes in the pattern.

Given that the fringe width obtained is 0.6 cm and the wavelength of light used is 4500 Å (Angstroms), we can calculate the wavelength of light required to obtain fringes that are 0.0045 m wide.

We can use the formula for fringe width in Young's double-slit experiment:

w = (λ * D) / d

Where:

w is the fringe width,

λ is the wavelength of light,

D is the distance between the screen and the double slits, and

d is the distance between the two slits.

Let's calculate the value of D/d using the given information:

D/d = w / λ

= 0.006 m / 4500 Å (1 m = 10^10 Å)

= 0.006 * 10^10 / 4500 m^-1

Now, if the distance between the screen and the slit is reduced by half, the new value of D/d would be:

(D'/d) = (0.006/2) * 10^10 / 4500 m^-1

Now, we can rearrange the equation to solve for the new wavelength (λ'):

(λ' * D') / d = (D/d)

λ' = (D/d) * d / D

= [(0.006/2) * 10^10 / 4500] * (4500 / 0.006) Å

= 0.0045 m * 10^10 / 2 Å

= \(0.00225 * 10^{10\) Å

=\(2.25 * 10^7\)Å

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It takes 0.1311 seconds to hear the echo of the stone.

First we need to determine the time it takes for the sound wave to travel from the stone to the bottom of the mine shaft and back up to our ears.

Let's start by finding the time it takes for the sound wave to reach the bottom of the mine shaft. We can use the formula:

time = distance / speed

The distance is the depth of the mine shaft, which is 15 meters. The speed of sound is 343 m/s, as given in the problem. Therefore, the time it takes for the sound wave to reach the bottom of the mine shaft is:

time = 15 m / 343 m/s

time = 0.0437 s

Now, we need to find the time it takes for the sound wave to travel back up to our ears. Since the sound wave travels at the same speed, 343 m/s, the distance it needs to cover is twice the depth of the mine shaft, or 30 meters. Therefore, the time it takes for the sound wave to travel back up to our ears is:

time = 30 m / 343 m/s

time = 0.0874 s

Finally, to find the total time it takes to hear the echo, we add the time it takes for the sound wave to reach the bottom of the mine shaft to the time it takes to travel back up to our ears:

total time = 0.0437 s + 0.0874 s

total time = 0.1311 s

Therefore, it takes 0.1311 seconds to hear the echo of the stone.

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Explanation:

\(\theta=1.22 \frac{\lambda}{D}\)

And, from equation ( 2 ), we get

\(\theta=\frac{x}{d}\)

Thus,

\(\frac{x}{d} &=1.22 \frac{\lambda}{D}\)

\(D &=1.22 \frac{\lambda d}{x}\)

\(=1.22 \frac{550 \times 10^{-9} 3.84 \times 10^{8}}{5 \times 10^{3}}\)

\(=0.0515 \mathrm{m}\)

Thus, the diameter of the telescope's mirror that would allow us to see details as small as is

The magnitude of the charge of the given moveable beads is 9.33 nC.

The tension in the string is calculated as follows;

Tcos45 = mg

where;

F = Tsin45

\(\frac{kq^2}{r^2} = Tsin(45)\\\\\frac{kq^2}{r^2} = \frac{mg}{cos45} \times sin(45)\\\\\frac{kq^2}{r^2} = mg\\\\q = \sqrt{\frac{mgr^2}{k} }\)

\(q = \sqrt{\frac{(0.032 \times 10^{-3})(9.8)(0.05)^2}{9\times 10^9} } \\\\q = 9.33\times 10^{-9} \ C\\\\q = 9.33 \ nC\)

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Given the mass of the cell is 1 * 10⁻¹⁴ kg, the number of cells in the 65 kg person is  6.5 * 10¹⁵  cells.

The number of cells in a human is calculated as follows:

The mass of an average cell is ten times the mass of a bacterium.

The mass of a bacterium = 1 * 10⁻¹⁵ kg

mass of an average cell = 10 *  1 * 10⁻¹⁵ kg =  1 * 10⁻¹⁴ kg

Number of cells = mass of person/mass of cell

Number of cells = 65 kg/1 * 10⁻¹⁴ kg

Number of cells = 6.5 * 10¹⁵  cells.

In conclusion, the number of cells is obtained by dividing the mass of the person by the mass of a average cell.

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Note that the complete question is given below:

Assuming the mass of an average cell is ten times the mass of a bacterium (which is 10⁻¹⁵ kg): Calculate the number of cells in a human assuming the mass of the person is 10² kg.

Answer:

25 m

Explanation:

Let's assume that its acceleration is constant. We can determine the acceleration of the object by its definition

\(a= \frac{\Delta v}{\Delta t} = \frac{10-0(\frac ms)}{5 s} = 2 \frac m{s^2}\)

Now we can write the equation of motion

\(s(t)= s_0 + v_0t + \frac12at^2\)

where, the two terms \(s_0\ v_0\) represent the initial position and velocity respectively. Replacing the values we have ("from rest" means that initial velocity is 0)

\(s(5) = 0+0(5)+\frac12 2 (5)^2 = 25 m\)

We can deduce here that the maximum horizontal force that you can apply to the box is 150 pounds. Thus, the heaviest box that you can push up the ramp at a constant speed is 75 pounds.

Given the following:

Maximum horizontal force = 150 pounds

Coefficient of kinetic friction = 0.50

Weight of the box = 150 pounds

Angle of the ramp = 60°

Normal force = Weight of the box * Cosine of the angle of the ramp

= 150 pounds × Cos(60°)

= 75 pounds.

Force of friction = Coefficient of kinetic friction × Normal force

= 0.50 × 75 pounds

= 37.5 pounds

Maximum force that can be applied to the box = Weight of the box × Cosine of the angle of the ramp - Force of friction

= 150 pounds × Cos(60°) - 37.5 pounds

= 75 pounds

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Answer:

The force is  \(F = 3920 \ N\)

Explanation:

The diagram for this question is shown on the first uploaded image

   From the question we are told that

          The weight of the gate is \(G = 100\ kg\)

The vertical component of F is  \(F_y = F\ sin \theta\)

   From the diagram , taking moment about the pivot we have  

                \(W_g * 2 - F_y * 1 = 0\)

Where \(W_g\)  is the weight of the gate evaluated as

             \(W_g = m_g * g = 100 * 9.8 = 980 \ N\)

=>        \(980 * 2 - Fsin(30) * 1 = 0\)

=>         \(F = \frac{1960}{sin(30)}\)

=>      \(F = 3920 \ N\)

Answer:

Kilogram

Explanation:

A rock is thrown horizontally from a bridge with a velocity of 5 m/s and hits the water below in 2.2 seconds therefore the height of the bridge is 11m.

This is referred to as a scalar quantity that refers to "how much ground an object has covered" during its motion. Height on the other hand is the measurement of an item in the vertical direction,

We should also note that velocity = distance/time

Velocity = 5m/s

time = 2.2s

Therefore 5m/s = d/2.2s

d = 5m/s × 2.2s = 11m

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Answer:

C

Explanation:

From the question we are told that a vector on the x and y plane face their negative axis

Generally  in the x and y plane thr negative y axis is made to face down opposite the positive y axis

Whilst the negative x axis faces the left which is also alternate to the positive x axis

Generally A vector pointing towards the x and y negative axis fro  the origin (0) will definitely be in the third quadrant

Answer: 1 > 3 > 2

Explanation: The range will increase with the velocity. If they are all launched at the same time the ones that are launched the hardest or with the most velocity will go the furthest horizontally. But because they are all launched from the same height and the force of gravity on all three projectiles is constant (the same for all three) they will all hit the ground at the same time but different distances from the starting point.

Answer:

Explanation:

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Answer:The powder of Kool Aid crystals are the solute. The water is the solvent and the delicious Kool Aid is the solution.... .-.

Explanation:

A Stone Is Dropped Into a Deep Water Well. The Sound of The Stone Hitting The Water Is Heard After 3.4 Seconds. then The Depth of The Water Well is 56.6 m.

In terms of physics, sound is a vibration that travels through a transmission medium like a gas, liquid, or solid as an acoustic wave. Sound is the receipt of these waves and the brain's perception of them in terms of human physiology and psychology. Only acoustic waves with frequencies between about 20 Hz and 20 kHz, or the audio frequency range, may cause a human to have an auditory sensation. These correspond to sound waves in air with an atmospheric pressure of 17 metres (56 ft) to 1.7 centimetres (0.67 in) in wavelength. Ultrasounds are sound waves with a frequency higher than 20 kHz that are inaudible to humans. Infrasound refers to sound frequencies below 20 Hz. Animals of different species have different hearing ranges. Acceleration of the stone is 9.8 m/s²

according to kinematics,

s = ut + 1/2 at²

s =  1/2 ×9.8×3.4²

s = 56.6 m

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Explanation:

The light bulb is connected across the circuit along with the battery.

A light bulb acts as a load or resistance in the circuit.

It can be used to determine the current flow in the circuit.

The light bulb will glow if electricity flows through the circuit.

They use electrical energy to generate light energy through the heating property of filament.

Answer:

uniformly accelerated motion

Explanation:

The motion of the body where the acceleration is constant is known as uniformly accelerated motion. The value of the acceleration does not change with the function of time.

The box accelerates to the right due to the applied force of 35 N in the +x direction.

Newton's second law states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass. In this case, the net force acting on the box is 35 N in the +x direction, and its mass is 15 kg. Therefore, we can calculate the acceleration using the formula:

acceleration = net force / mass

acceleration = 35 N / 15 kg = 2.33 m/s² (rounded to two decimal places)

Since the box is not accelerating up or down, we can conclude that the force applied is only causing the box to accelerate in the horizontal direction.

Other forces such as gravity and friction are not considered in this scenario. Thus, the 15 kg box will experience an acceleration of approximately 2.33 m/s² in the +x direction due to the applied force of 35 N.

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Answer:

UMMMMMMMMMMMMMMM ]

Explanation:

WHAT

Answer:

dang, he should go see a doctor