A pulley is mounted on a frictionless axis and then the pulley is attached to the higher end of the inclined surface as shown in the figure. A massless cord is wrapped around the pulley while its other end is tied to a 1.0 kg object. The pulley has a radius of 20 cm and moment of inertia of 0.4 kg m2 . The angle of the surface is 37° and the coefficient of kinetic friction is 0.2. The object is released from rest. The pulley starts to rotate as the object moves and the cord unwinds. Determine the acceleration of the object and the tension in the cord.
Answers
Answer:
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Explanation:
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Newton's second law we can find the answers for the block system with a pulley are
a) The acceleration is 0.39 m / s² descending the inclined plane
b) The tension of the rope is 3.9 N
Newton's Second Law gives the relationship between the net external force is proportional to the mass and the acceleration of the body
∑ F = m a
Where bold letters indicate vectors, F is force, m is mass, and a is the acceleration.
Reference systems are coordinate systems with respect to which to perform vector decomposition measurements. In this case we take a system with the x axis parallel to the plane and the positive direction the direction of movement, the ej y is perpendicular to the plane,
The free body diagram is a diagram of the forces in the system without the physical body details, in the attached we have a free body diagram. Let's write the equation for each axis
y-axis
N - \(W_y\) = 0
N = \(W_y\)
x-axis
Wₓ -fr -T = m a
Let's use trigonometric to break down the weight
cos 37 =\(\frac{W_y}{W}\)
sin 37 = \(\fracW_{x}{W}\)
W_y = W cos 37
Wₓ = W sin 37
The friction force is the macroscopic manifestation of the interaction between the two bodies, it has the formula
fr =μ N
fr = μ W sin 37
We substitute
W sin 37 - μ W cos 37 - T = m a
Now let's use Newton's second law for rotational motion in the pulley
Σ τ = I α
Where τ is the torque, I the moment of inertia and α is the angular acceleration of the pulley.
Torque is the product of the force times the perpendicular distance to the axis of rotation, let's take the clockwise direction as positive
The weight forces in the y axis and normal are on the axis, their distance is zero, so they do not create torque
T R = I α
Let's use the relationship between linear and angular variables
a = α R
α = \(\frac{a}{R}\)
TR = I a / R
Let's write our equations
W sin 37 - μ W cos 37 - T = m a
T = I \(\frac{a}{R^2 }\)
We have two equation es and two unknowns, let's solve the system
m g sin 37 - μ mg cos 37 - I a / Rr² = m a
m (g sin 37 - μ g cos 37) =m a ( 1 + \(\frac{I}{mR^2}\))
a = g \(g \ \frac{sin 37 - \mu \ cos 37}{ 1 + \frac{I }{mR^2 } }\)
Let's calculate
a = \(9.8 \ \frac{sin 37 - 0.2 cos 37 }{ 1 + \frac{0.4}{1.0 \ 0.2^2 } }\)
a = 0.39 m / s²
We look for the tension of the rope
T = I \(\frac{a}{R^2 }\)
T = 0.4 0.39 / 0.2²
T = 3.9 N
In conclusion using Newton's second law we can find the answers for the block system with a pulley are
a) The acceleration is 0.39 m / s² descending the inclined plane
b) The tension of the rope is 3.9 N
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Related Questions
how does mass relates to latent heat?
Answers
The mass of a substance is not directly related to latent heat. Instead, latent heat is a parameter that describes the amount of energy required or released during a phase shift of a substance.
What is latent heat?Latent heat can be thought of as hidden energy that is supplied or extracted to change the state of a substance without changing its temperature or pressure.
Latent heat is energy released or absorbed, by a body or a thermodynamic system, during a constant-temperature process—typically a first-order phase transition.
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Physics Question!!!!!
Answers
Answer:
bbibinononobyvtcrxrxextcyvubuvububububububbu
Answer:
im just gettin these points babbbyyyyyy
Explanation:
A hollow cast-iron cylinder 4m long, 300mm outer diameter, and thickness of metal 50mm is subjected to a central load on the top when standing straight. The stress produced is 75000kN/m2. Assume Young's modulus for cast iron as 1.5x 108 kN/m^2 and find (i) magnitude of the load, (ii) longitudinal strain produced, and (iii) total decrease in length.
Answers
Here, the calculated Magnitude of the load P is 2945.2 kN, the Longitudinal strain produced is 0.0005 and the decrease in length is 2 mm.
Given,
Length, L = 4 m
Outer diameter, D = 300mm, D= 0.3 m
Thickness, t = 50 mm, t = 0.05 m
Stress produced, σ = 75000 kN/m²
Young's modulus for cast iron, E = 1.5 x 10⁸ kN/m²
Calculating the diameter of the cylinder,
Diameter of cylinder, d = (D) – (2t) = 0.3 –( 2 × 0.05)
d= 0.2 m
(i) Magnitude of the load P:
Using the relation, σ =P/A
P = σ × A = 75000 × π /4 (D² – d² )
P= 75000 × π/4 (0.3² – 0.2²)
P= 75000 × π/4 (0.09 – 0.04)
P = 2945.2 kN
Hence, Magnitude of the load P is 2945.2 kN.
(ii) Longitudinal strain produced, e :
Using the relation, Strain, (e) = stress/E
e= 75000/(1.5 x 10⁸)= 0.0005
Hence, the Longitudinal strain produced is 0.0005.
(iii)Total decrease in length, dL:
The total decrease in length can be calculated using the strain as the ratio of change in length to the original length is known as Strain.
Strain = change in length/original length
e= dL/L
0.0005 = dL/4
dL = 0.0005 × 4m = 0.002m=2mm
Hence,the decrease in length is 2 mm.
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Without actually calculating any logarithms, determine which of the following intervals the sound intensity level of a sound with intensity 3.66×10^−4W/m^2 falls within?
a. 30 and 40
b. 40 and 50
c. 50 and 60
d. 60 and 70
e. 70 and 80
f. 80 and 90
g. 90 and 100
Answers
Answer:
f. 80 and 90
Explanation:
1 x 10⁻¹² W/m² sound intensity falls within 0 sound level
1 x 10⁻¹¹ W/m² sound intensity falls within 10 sound level
1 x 10⁻¹⁰ W/m² sound intensity falls within 20 sound level
1 x 10⁻⁹ W/m² sound intensity falls within 30 sound level
1 x 10⁻⁸ W/m² sound intensity falls within 40 sound level
1 x 10⁻⁷ W/m² sound intensity falls within 50 sound level
1 x 10⁻⁶ W/m² sound intensity falls within 60 sound level
1 x 10⁻⁵ W/m² sound intensity falls within 70 sound level
1 x 10⁻⁴ W/m² sound intensity falls within 80 sound level
1 x 10⁻³ W/m² sound intensity falls within 90 sound level
Given sound intensity (3.66 x 10⁻⁴ W/m²) falls with 1 x 10⁻⁴ W/m² of intensity which is within 80 and 90 sound level.
f. 80 and 90
how much work is done to a 2.0 kg cart that moves 10.0 m/s to 15 m/s
Answers
The cart has undergone work done is 125 Joules of labor.
A finished job is what?To move an object, it must be transformed into energy. Force can be used to transmit energy. The work done is the amount of energy that a force used to move an object.
We must apply the following formula to determine the amount of work done on the cart:
W = K = (1/2)mvf2 - (1/2)mvi2 where m is the cart's mass, vf is the end velocity, and vi is the beginning velocity. K is a symbol for kinetic energy change.
By entering the specified values, we obtain:
\(W = (1/2) x 2.0 kg x (15 m/s)^2 - (1/2) x 2.0 kg x (10 m/s)^2\)
\(W = (1/2) x 2.0 kg x 225 m^2/s^2 - (1/2) x 2.0 kg x 100 m^2/s^2\)\(W = (1/2) x 2.0 kg x 225 m^2/s^2 - (1/2) x 2.0 kg x 100 m^2/s^2\)
\(W = 125 J\)
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Select the correct answer.
A boat moves 60 kilometers east from point A to point B. There, it reverses direction and travels another 45 kilometers toward point A. What are the total
distance and total displacement of the boat?
O A.
OB.
O C.
O D.
The total distance is 105 kilometers and the total displacement is 45 kilometers east.
The total distance is 60 kilometers and the total displacement is 60 kilometers east.
The total distance is 105 kilometers and the total displacement is 15 kilometers east.
The total distance is 60 kilometers and the total displacement is 45 kilometers east.
Answers
The total distance is 105 kilometers and the total displacement is 15 kilometers east. Option C
How to solve for the total distanceTo calculate the total distance, we add the distances traveled in each leg of the journey: 60 kilometers (from A to B) + 45 kilometers (from B back to A) = 105 kilometers.
However, displacement refers to the change in position of an object in a straight line from its starting point to its ending point. In this case, since the boat starts and ends at the same point (A), the total displacement is zero.
Hence The total distance is 105 kilometers and the total displacement is 15 kilometers east.
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YOU HAVE 5 MINUTES!!!!
Design an easy do-it-yourself compost bin that can be put (exnfe ffpao)
together at home. You can describe it, draw and label it, or both!
Include the following in your design:
• drawing or description of design
• materials used for the bin
• size of the bin
• substances used to fill it
• household items that can go in it
• how long it takes before it is ready
• how you use the compost
2)
Compost bin design: Add these household items to
your compost bin:
Compost is ready to use in this
much time:
Use your compost this way:
Answers
The finished compost can be used to enrich soil for planting and gardening. Mix the compost into the soil or use it as a top dressing around plants.
Substances Used to Fill It:
A mixture of "brown" and "green" organic materials such as leaves, grass clippings, fruit and vegetable scraps, coffee grounds, and shredded paper can be used to fill the bin.
Household Items That Can Go in It:
Most fruit and vegetable scraps, eggshells, tea bags, coffee grounds, yard waste such as grass clippings and leaves, and shredded paper can be added to the compost bin. Meat, dairy, and fatty foods should be avoided.
How Long It Takes Before It Is Ready:
The compost should be ready to use in approximately 6 to 12 months, depending on the environmental conditions and the frequency of turning and mixing the compost.
How You Use the Compost:
The finished compost can be used as a nutrient-rich soil amendment for planting and gardening.
Compost Bin Design:
To add household items to your compost bin, simply add any of the following organic materials to the bin: fruit and vegetable scraps, coffee grounds and filters, tea bags, eggshells, yard waste such as leaves and grass clippings, and shredded paper.
Compost is ready to use in this much time:
The compost should be ready to use in approximately 6 to 12 months, depending on the environmental conditions and the frequency of turning and mixing the compost.
Use your compost this way:
The finished compost can be used to enrich soil for planting and gardening. Mix the compost into the soil or use it as a top dressing around plants.
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You lift a 5 kg object 3 m above the ground.
How much GPE does it have?
How much work was done lifting it?
• How much KE does the object have just before hitting the ground
• if it is dropped?
Answers
(a) The amount of gravitational potential energy possessed by the object at the given height is 147.
(b) The kinetic energy, KE the object have just before hitting the ground is 147 J.
How much GPE does it have?The amount of gravitational potential energy possessed by the object at the given height is calculated as follows;
GPE = mgh
where;
m is the mass of the objectg is acceleration due to gravityh is heightGPE = 5 kg x 9.8 m/s² x 3 m
GPE = 147 J
Based on the law of conservation of energy, the amount of kinetic energy possessed by the object just before hitting the ground will the same as the gravitational potential energy at the initial height.
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Marsha's car accelerates at an average rate of 3 m/s2. How long does it take for her car to speed up from 10 m/s to 15 m/s?
Answers
Explanation:
We are going to use the following equation:
\(v = v_0 + at \Rightarrow t = \dfrac{v - v_0}{a}\)
\(t = \dfrac{15\:\text{m/s} - 10\:\text{m/s}}{3\:\text{m/s}^2}\)
\(\:\:\:\:=1.67\:\text{s}\)
A plane lands with a velocity of 120 m/s and accelerates at a maximum rate of -6.0 m/s/s.From the instant, the plane touches the runway, what is the minimum time needed before it can come to restCan this plane land in the school parking lot which is 800 meters long? please help with this problem
Answers
The minimum time needed for the plane to come to rest will happen if the maximum acceleration is the same throughout the landing; this means that for this situation we can look at the motion as an uniform accelerated motion and then we will be able to use the equations describing this type of motion.
For this kind of motion we know that:
\(a=\frac{v_f-v_0}{t}\)we want the plane to stop, this means that we want the final velocity to be zero; plugging this value in the equation above and the values given by the problem we have that:
\(\begin{gathered} -6=\frac{0-120}{t} \\ t=\frac{-120}{-6} \\ t=20 \end{gathered}\)Therefore the plane will need a minimum of 20 seconds to stop.
To determine the minimum distance needed for the plane to stop safely we have to remember that for this kind of motion:
\(v^2_f-v^2_0=2ax\)Plugging the values we have that:
\(\begin{gathered} 0^2-120^2=2(-6)x \\ -120^2=-12x \\ x_{}_{}=\frac{-120^2}{-12} \\ x_{}=1200 \end{gathered}\)Hence, we need at least 1200 m for the plane to safely land and therefore the plan can't land in the school parking lot.
When converting chemical potential energy to kinetic energy some of the energy is lost as heat.
Answers
Answer:
When converting chemical potential energy to kinetic energy some of the energy is lost as heat.
Why is it important to observe the necessary precautions in dancing??
Answers
Answer:
To Avoid accidents and injuries
Explanation:
Safety measures are vital dancing as this may prevent bad things like accidents and injuries from happening.
When dancing,the safety of dancers is a must to be observed and considered.
Dancers are also most likely to exert their full potential if they know that they are safe no matter what happen....
HAVE A GOOD DAY....
A runner of mass 59.5 kg initially moves at a speed of 9.50 m/s. How long must an average external force of 1.90 102 N act to bring the runner to rest
Answers
Hi there!
We can use the Impulse-Momentum Theorem to solve.
Recall:
Impulse = Change in momentum = Δp = mΔv
The change in momentum is equivalent to:
Δp = m(vf - vi) = (59.5)(0 - 9.5) = -565.25 kgm/s ⇒ 565.25 kgm/s (+ b/c change)
This is also equal to the impulse, which is:
I = Ft (Force × time)
Thus:
565.25 = (1.9 × 10²)t
565.25/190 = 2.975 sec
Some dragonflies splash down onto the surface of a lake to clean themselves. After this dunking, the dragonflies gain altitude, and then spin rapidly at about 1100 rpm to spray the water off their bodies. When the dragonflies do this "spin-dry," they tuck themselves into a "ball" with a moment of inertia of 2.0×10−7kg⋅m2 . How much energy must the dragonfly generate to spin itself at this rate?
Answers
The dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.
Start by converting the rotational speed from rpm (revolutions per minute) to rad/s (radians per second). Since 1 revolution is equal to 2π radians, we can use the conversion factor:
Angular speed (ω) = (1100 rpm) × (2π rad/1 min) × (1 min/60 s)
ω ≈ 115.28 rad/s
The moment of inertia (I) is given as 2.0 × 10^-7 kg⋅m².
Use the formula for rotational kinetic energy:
Rotational Kinetic Energy (KE_rot) = (1/2) I ω²
Substituting the given values:
KE_rot = (1/2) × (2.0 × 10^-7 kg⋅m²) × (115.28 rad/s)²
Calculate the value inside the parentheses:
KE_rot ≈ (1/2) × (2.0 × 10^-7 kg⋅m²) × (13274.28 rad²/s²)
KE_rot ≈ 1.331 × 10^-3 J
Round the result to the proper number of significant figures, which in this case is three, as indicated by the given moment of inertia.
KE_rot ≈ 4.8 × 10^-4 J
Therefore, the dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.
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What is the difference between a wave and energy?
Answers
Answer:
The higher the amplitude, the higher the energy. To summarise, waves carry energy. The amount of energy they carry is related to their frequency and their amplitude. The higher the frequency, the more energy, and the higher the amplitude, the more energy
Explanation:
The main difference between a wave and energy is: wave is oscillation of energy whereas energy is ability of doing work.
What is wave?A wave is an energetic disturbance in a medium that doesn't include any net particle motion. Elastic deformation, a change in pressure, an electric or magnetic intensity, an electric potential, or a change in temperature are a few examples.
What is energy?The capacity to do work is energy. Energy can only be changed from one form to another; it cannot be created or destroyed. Energy is measured in Joules, the same unit used to measure work. There are several sorts of energy since it is present in many different things.
There are two types of energy: kinetic and potential. Kinetic energy is the energy that is in motion, whereas potential energy is the energy that is stored in an object and is determined by the amount of work that is required.
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An object falls freely from rest on a planet
where the acceleration due to gravity is
29 m/s ^2
After 3.8 s, what will be its speed?
Answer in units of m/s.
Answers
Answer:
v=u+gt , initially u=0 and g acting in the direction of movement of body.
v=0+9.8×2
v=19.6m/s
Explanation:
sorry i dont have exact answer but hope this above equation will help you ....♡
Is frictional force the only example of non-conservative force?
Answers
Answer: NO, there are many examples of non-conservative forces.
Explanation: Conservatives forces are special forces whose work is zero in a closed path.
Magnetic and Electric fields are Non- Conservative.How are reflectivity and solubility related?
Answers
Answer:
they are related because..
Explanation:
Physical properties can be observed or measured without changing the composition of matter. Physical properties include: appearance, texture, color, odor, melting point, boiling point, density, solubility, polarity, and many others
The relation is ; Reflectivity and solubility are both physical properties of substances and are measured in relation to given variable ( i.e. incident ray for reflectivity and solvent for solubility )
Reflectivity ( aka optical property ) and solubility are both physical properties of any substance. while reflectivity of an object is measured as the amount of light an object reflects in relation to the light incident on it ( incident ray ), solubility is the amount of a substance that will dissolve in a given solvent at a given temperature. a
Hence we can conclude that the relation between reflectivity and solubility is that they are both physical properties of substances and are measured in relation to given variable ( i.e. incident ray for reflectivity and solvent for solubility ).
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Which factor is related to seat belt use in teens?
A.Speed limit on roadways
B.Type of vehicle
C.Alcohol use
D.Weather conditions
Answers
Answer:
Explanation:
C
Answer:
Explanation:
Alcohol use C
In the Daytona 500 auto race, a Ford Thunderbird and a Mercedes Benz are moving side by side down a straightaway at 73.5 m/s. The driver of the Thunderbird realizes that she must make a pit stop, and she smoothly slows to a stop over a distance of 250 m. She spends 5.00 s in the pit and then accelerates out, reaching her previous speed of 73.5 m/s after a distance of 400 m. At this point how far has the Thunderbird fallen behind the Mercedes Benz, which has continued at a constant speed
Answers
Answer:
Thunderbird has fallen behind the Mercedes Benz by 1017.49 m
Explanation:
Given the data in question;
initial speed of the ford u1 = 73.5 m/s
distance d1 = 250 m
t1 = 5.00 s
d2 = 400 m
Now, let the time taken to stop be t2 and deceleration is a1
so,
a1 = u1² / (2 × d1)
a1 = (73.5)² / (2 × 250)
a1 = 10.8045 m/s²
Now , for acceleration is a2
a2 = v² / (2 × d2)
a2 = (73.5)² / (2 × 400)
a2 = 6.7528 m/s²
total time spend = 5 + u/a1 + u/a2
total time spend = 5 + (73.5/10.8045) + (73.5/6.7528)
total time spend = 22.687 sec
Now, distance Mercedes is ahead = 22.687 × 73.5 - 400 - 250
= 1667.4945 - 400 - 250
= 1017.49 m
Therefore, Thunderbird has fallen behind the Mercedes Benz by 1017.49 m
is it true or false if a force is a push or a pull on a object
Answers
Answer: true
Explanation: a force can be anything that effects an object, as long as the object moves
Explanation:Because anything that is being pushed of pulled is called force.
HOPE IT HELPED :)
The speed of a 500 g cricket ball changes from 10m/s to 30m/s in just 7 seconds. What is the force acting on the cart?
Answers
The force acting on the cart is 1.43 N.
What is force?Force can be defined as the product of mass and acceleration.
To calculate the force acting on the cart, we use the formula below.
Formula:
F = m(v-u)/t................. Equation 1Where:
F = Force acting on the cartm = mass of the cartv = Final velocityu = initial velocityt = timeFrom the question,
Given:
m = 500 g = 0.5 kgv = 30 m/su = 10 m/st = 7 secondsSubstitute these values into equation 1
F = 0.5(30-10)/7F = 10/7F = 1.43 N.Hence, the force acting on the cart is 1.43 N.
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What kinds of materials generally have the lowest specific heats?
Answers
Answer:
Iron and lead generally have low specific heats.
A ball is thrown straight up with a launch of 3 m/s.
what is the acceleration as it moves towards the top of the path and what is the acceleration as the ball returns to the throwers hand? please help me, thank you.
Answers
Explanation:
The ball is in free fall (gravity is the only force acting on the ball), so its acceleration is 9.8 m/s² down during the entire path.
A stationary 0.750kg ball is thrown up by doing 2.50J of work on it. What is the velocity of the ball?
Answers
When a ball is thrown up by doing work, the velocity of the ball will be 2.6 m/s.
What is Work energy theorem?It states that the Work done in moving a body is equal to the change in kinetic energy of the body
Kinetic energy = 1/2 mv²
Given is a ball of mass m = 0.750 kg and the work done on ball W = 2.50 J
The ball is initially at rest. So, initial velocity is zero. Then, change in kinetic energy will be
W= ΔK.E = K.Ef - K.Ei
According to work energy theorem, work done is
W = 2.5J = 1/2 x 0.750 x (v)² -0
v =2.6 m/s
Thus, the velocity of the ball is 2.6 m/s
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a place-kicker must kick a football from a point 36.0 m (about 40 yards) from the goal. half the crowd hopes the ball will clear the crossbar, which is 3.05 m high. when kicked, the ball leaves the ground with a speed of 23.9 m/s at an angle of 51.5 degrees to the horizontal. (a) by how much does the ball clear or fall short of clearing the crossbar?
(b) does the ball approach the crossbar while still rising or while falling?
Answers
Explanation:
Let's calculate the components of the football's velocity:
\(v_{0x} = (23.9\:\text{m/s})\cos{51.5°} = 14.9\:\text{m/s}\)
\(v_{0y} = (23.9\:\text{m/s})\sin{51.5°} = 18.7\:\text{m/s}\)
a) The time it takes for the football to travel 36.0 m horizontally is
\(t = \dfrac{x}{v_{0x}} = \dfrac{36.0\:\text{m}}{14.9\:\text{m/s}} = 2.4\:\text{s}\)
During this time, the y-displacement of the football is
\(y = v_{0x}t - \frac{1}{2}gt^2\)
\(\:\:\:\:= (18.7\:\text{m/s})(2.4\:\text{s}) - \frac{1}{2}(9.8\:\text{m/s}^2)(2.4\:\text{s})^2\)
\(\:\:\:\:= 16.7\:\text{m}\)
This means that the football cleared the crossbar by 16.7 m - 3.05 m = 13.7 m
b) To determine whether the football was rising or falling while clearing the crossbar, let's look at the y-component of its velocity after 2.4 s:
\(v_y = v_{0y} - gt = 18.7\:\text{m/s} - (9.8\:\text{m/s}^2)(2.4\:\text{s})\)
\(\:\:\:\:\:\:= -4.82\:\text{s}\)
Since its sign is negative, this means that the football was already on its way down.
Car P travels due East along a straight highway at a constant speed of 30 m/s. At 9:00
a.m., P passes Exit 17. At precisely the same moment, car Q passes Exit 16, traveling due
West at a constant 26 m/s. Slightly later, car P and car Q pass the same point. Knowing
the exits are exactly 7 km apart, determine how many minutes past 9:00 a.m. the cars pass
each other.
Answers
Knowing the exits are exactly 7 km apart, the cars pass each other at 9:29 and 15 seconds a.m.
How to calculate time?The relative velocity of the cars is 30 m/s - 26 m/s = 4 m/s.
The distance between the cars is 7 km = 7000 m.
The time it takes for the cars to pass each other is 7000 m / 4 m/s = 1750 seconds.
1750 seconds is 29 minutes and 15 seconds.
To calculate the time in minutes;
Let:
v_p = the speed of car P (m/s)
v_q = the speed of car Q (m/s)
d = the distance between the cars (m)
t = the time it takes for the cars to pass each other (s)
Given that:
v_p = 30 m/s
v_q = 26 m/s
d = 7000 m
Use the equation for relative velocity to find the velocity of the cars relative to each other:
v_r = v_p - v_q
v_r = 30 m/s - 26 m/s = 4 m/s
Use the equation for distance to find the time it takes for the cars to pass each other:
d = v_r × t
7000 m = 4 m/s × t
t = 7000 m / 4 m/s = 1750 s
Convert 1750 seconds to minutes and seconds:
1750 s = 29 minutes and 15 seconds
Therefore, the cars pass each other at 9:29 and 15 seconds a.m.
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calculate the electric potential energy in a capacitor that stores 9.40 x 10 to the negative 10 C of charge at 50.0 V
Answers
The electric potential energy stored in the capacitor is 4.70 x 10^-8 Joules.
The electric potential energy stored in a capacitor is given by the formula:
U = (1/2) * C * V^2
where U is the potential energy in Joules, C is the capacitance in Farads, and V is the voltage across the capacitor in Volts.
In this case, we are given that the capacitor stores 9.40 x 10^-10 C of charge at 50.0 V. However, we are not given the capacitance value. Therefore, we cannot calculate the potential energy directly using the above formula.
To find the capacitance value, we can use the formula:
C = Q / V
where Q is the charge stored in the capacitor and V is the voltage across the capacitor.
Substituting the given values, we get:
C = 9.40 x 10^-10 / 50.0
= 1.88 x 10^-11 F
Now we can use the formula for electric potential energy to find the energy stored in the capacitor:
U = (1/2) * 1.88 x 10^-11 * (50.0)^2
= 4.70 x 10^-8 J
Therefore, the electric potential energy stored in the capacitor is 4.70 x 10^-8 Joules.
Know more about electric potential energy here:
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Explain why the atomic mass of an element is weighted average mass
Answers
Explanation:
The mass written on the periodic table is an average atomic mass taken from all known isotopes of an element. This average is a weighted average, meaning the isotope's relative abundance changes its impact on the final average. The reason this is done is because there is no set mass for an element.
Describing the Motion of an Object
SARE
Use the information from the graph to answer the
question.
What is the acceleration of the object?
m/s2
Velocity vs. Time
Velocity (m/s)
45
40
35
30
25
20
10
5
0
0
2
10
12
4. 6 8
Time (s)
Answers
Answer:
i actually dont know im so sorry but i will keep trying to find the answerr