A point charge Q1+ 6.0 nC is a point (0.30 m, 0.00 m); a charge Q2 = -10 nC is at (0.00m , 0.10m), and a charge Q3 = + 5.0 nC is at (0.00m , 0.00m). what are the magnatude and direction of the net force on the +5.0 -nC charge due to the other two charges?

The event that marks the end of a star's evolutionary life before becoming a white dwarf is a planetary nebula. So, option E is correct.

A planetary nebula is characterized by cosmic rays of gas and dust surrounding a dying star. This dying star becomes a white dwarf after the complete depletion of hydrogen in the core.

It gets its name from a scientist who described the gases to be looking like two planets around a dying star. Thus, it's called planetary nebulae. This marks the final stage of a dying star that becomes a white dwarf. It consists of the outer layers of the star.

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The value of resistivity and conductivity are mentioned below.

What is resistivity ?

A conductor with a unit cross-sectional area and unit length and its electrical resistance. Resistivity, a distinctive quality of any material, is helpful in comparing different materials based on their capacity to conduct electric currents. Poor conductors are identified by high resistance.

What is conductivity ?

A substance or material that permits electricity to flow through it is referred to as an electrical conductor. When voltage is given to a conductor, electrical charge carriers, often electrons or ions, travel easily from atom to atom.

Part a is explained by using the concept of diffusion current density and Einstein's relation

from semiconductor we have

T mobility

V= μE

Drift velocity

I = ncAvl

J also equal to E

σE= nevd

σ= nevd/E

σ= neμ

resistivity is reciprocal of conductivity

S= 1/σ=1/neμ

from Einstein's equation

∫= KT/ ne²Dn

Therefore, value of resistivity and conductivity are mentioned below.

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At time t = 15/16, the object reaches a state of zero velocity, indicating a momentary pause in its motion. Prior to this time, the object moves in one direction, while after this time, it changes direction and moves in the opposite direction. The value t = 15/16 represents the specific moment when the object transitions from one direction to another and experiences a brief period of rest.

To find the velocity v(t) of the object at any time t, we differentiate the given distance function s(t) = 9 - 15t + 8t² with respect to time:

v(t) = d/dt (9 - 15t + 8t²)

Applying the power rule of differentiation, we obtain:

v(t) = -15 + 16t

Therefore, the velocity v(t) of the object at any time t is given by v(t) = -15 + 16t.

To determine when the object is at rest, we set the velocity v(t) equal to zero and solve for t:

-15 + 16t = 0

Adding 15 to both sides of the equation, we have:

16t = 15

Finally, dividing both sides by 16, we find

t = 15/16

Hence, the object is at rest when t = 15/16.

This means that at time t = 15/16, the object's velocity is zero, indicating that it is momentarily stationary. Before this time, the object is moving in one direction, and after this time, it is moving in the opposite direction. The value t = 15/16 represents the specific point in time when the direction of motion changes, and the object is at rest for an instant.

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To find the electric field between the two points, we can use the formula. So, the electric field between the two points is approximately 10.57 V/m.

Electric field = Potential difference / Distance between the points
Plugging in the given values, we get:
Electric field = 44.4 V / 4.2 m
Electric field = 10.57 V/m
Therefore, the electric field between the two points is 10.57 V/m.

To find the electric field between two points with a potential difference, you can use the formula:
Electric Field (E) = Potential Difference (V) / Distance (d)
In this case, the two points are 4.2 meters apart and the potential difference between them is 44.4 V. Plugging these values into the formula, we get:
E = 44.4 V / 4.2 m
E ≈ 10.57 V/m
So, the electric field between the two points is approximately 10.57 V/m.

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The equation that shows the relationship between X₁ and X₂ in the springs is X₁ = 4X₂.

From the complete question, for case I, the two springs stretch up to the distance of X₁. Therefore, f = mg = kx₁.

For case 2, f = mg = kx₂.

Therefore, we'll equate the equations. This will be:

Kx₁ = Kx₂

(K/2)x₁ = (2k)x₂

K(x₁/2) = k(2x₂)

X₁/2 = 2x₂

X1 = 2 × 2x₂

X₁ = 4X₂.

In conclusion, X₁ = 4X₂.

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X₁ = 4X₂ is the equation that shows the connection between X₁ and X₂ in the springs.

The force required to extend or compress a spring by some distance scales linearly with respect to that distance is known as the spring force. Its formula is

F = kx

For case 1;

f=mg=kx₁

For case 2;

f=mg=kx₂

After equating the equation we get;

\(\rm Kx_1 = Kx_2 \\\\ \frac{K}{2}x_1 = (2k)x_2 = k(2x_2) \\\\ \frac{x_1}{2} =2x_2\\\\ x_1 = 4x_2\)

Hence  X₁ = 4X₂ is the equation that shows the connection between X₁ and X₂ in the springs.

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\( \large \mathfrak{Solution : }\)

Distance = 150 meters

Time = 18 seconds

Speed :

The thermal energy from nuclear reactions is first converted to mechanical energy and finally to electrical energy for use by the community.

Nuclear energy is the energy produced as a result of changes that occur in the nucleus of atoms of elements. These changes are known as nuclear reactions.

Electrical energy can be generated from nuclear reactions.

The steps in the generation of electrical energy from nuclear reactions is as follows:

Therefore, the thermal energy from nuclear reactions is converted to electrical energy for use by the community.

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The angular speed of the soccer ball is approximately 0.197 radians per second.

To find the angular speed of the soccer ball, we need to convert the linear speed (distance over time) into angular speed (radians per second).

Radius of the soccer ball (r) = 11 cm = 0.11 m

Distance rolled (d) = 10 m

Time taken (t) = 3.50 s

First, let's calculate the circumference of the soccer ball:

Circumference (C) = 2 * π * r

Next, we can calculate the angular speed (ω) using the formula:

Angular speed (ω) = (Distance traveled) / (Time taken) = (C / t)

Substituting the values, we have:

Circumference (C) = 2 * π * 0.11 m

Angular speed (ω) = (10 m) / (3.50 s)

Calculating the circumference:

C = 2 * 3.1416 * 0.11 m = 0.689 m

Now, we can find the angular speed:

ω = (0.689 m) / (3.50 s) ≈ 0.197 radians per second

Therefore, the angular speed of the soccer ball is approximately 0.197 radians per second.

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Answer:

La densidad del tetracloruro de carbono es 1.990 gramos por centímetro cúbico.

Explanation:

La masa de agua contenida dentro de la botella es igual a la diferencia entre la masa pesada totalmente llena y la masa pesada totalmente vacía, es decir:

\(m_{w} = 86.55\,g-24.25\,g\)

\(m_{w} = 62.3\,g\)

Ahora, de acuerdo con la definición de densidad, la masa es directamente proporcional a la densidad, entonces, podemos calcular la densidad del solvente mediante la siguiente relación:

\(\frac{m_{x}}{m_{w}} = \frac{\rho_{x}}{\rho_{w}}\) (1)

Donde:

\(m_{x}\) - Masa del tetracloruro de carbono, en gramos.

\(m_{w}\) - Masa del agua, en gramos.

\(\rho_{x}\) - Densidad del tetracloruro de carbono, en gramos por centímetro cúbico.

\(\rho_{w}\) - Densidad del agua, en gramos por centímetro cúbico.

Si sabemos que \(m_{x} = 123.95\,g\), \(m_{w} = 62.3\,g\) y \(\rho_{w} = 1\,\frac{g}{cm^{3}}\), entonces la densidad del tetracloruro de carbono es:

\(\rho_{x} = \left(\frac{m_{x}}{m_{w}} \right)\cdot \rho_{w}\)

\(\rho_{x} = 1.990\,\frac{g}{cm^{3}}\)

La densidad del tetracloruro de carbono es 1.990 gramos por centímetro cúbico.

Answer:Electricity works by getting a bunch of conductor elements together and creating a flow of electron-stealing patterns through them. This flow is called a current. ... Once you can control the direction the electrons are going, you can use them to power or charge anything from a light bulb to your TV to your electric car.

Explanation:trust

Given that the progressive wave equation is represented by y=Asin2π(0.15t-0.1x). Let's find the period, amplitude, frequency, wavelength, and velocity.

The wave equation is represented by y=Asin2π(0.15t-0.1x). The standard wave equation can be written asy = Asin(kx-ωt + Φ)Where,k = wave numberω = angular frequencyΦ = phase angle for the given equation, k = 0.1 and ω = 0.15.Amplitude:

Amplitude = A = maximum displacement from the mean position.A = 1Frequency: Frequency is the number of complete oscillations made by a point on the wave in one second. It is denoted by f.f = ω/2πFrequency, f = 0.15/2π = 0.0238 HzPeriod: Period is the time taken by one complete oscillation.

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Answer:

100 meters

Explanation:

To determine the mass of oxygen that is in 87.7g of magnesium nitrate, we can use the following steps:

Step 1: Find the molecular weight of magnesium nitrate (Mg(NO3)2)Mg(NO3)2 has a molecular weight of:1 magnesium atom (Mg) = 24.31 g/mol2 nitrogen atoms (N) = 2 x 14.01 g/mol = 28.02 g/mol6 oxygen atoms (O) = 6 x 16.00 g/mol = 96.00 g/molTotal molecular weight = 24.31 + 28.02 + 96.00 = 148.33 g/mol. Therefore, the molecular weight of magnesium nitrate (Mg(NO3)2) is 148.33 g/mol. Step 2: Calculate the moles of magnesium nitrate (Mg(NO3)2) in 87.7 g.Moles of Mg(NO3)2 = Mass / Molecular weight= 87.7 g / 148.33 g/mol= 0.590 molStep 3: Determine the number of moles of oxygen (O) in Mg(NO3)2Moles of O = 6 x Moles of Mg(NO3)2= 6 x 0.590= 3.54 molStep 4: Calculate the mass of oxygen (O) in Mg(NO3)2Mass of O = Moles of O x Molecular weight of O= 3.54 mol x 16.00 g/mol= 56.64 g.

Therefore, the mass of oxygen that is in 87.7 g of magnesium nitrate (Mg(NO3)2) is 56.64 g.

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Estimating the number of apples that is the energy equivalent of 1 gallon of gasoline is difficult, as the energy content of both substances is different. However, we can calculate the energy content of one gallon of gasoline and compare it to the energy content of one apple. So, approximately 1,045,454 medium-sized apples will be the energy equivalent of one gallon of gasoline.

Explanation:

What is the energy content of 1 gallon of gasoline?

The energy content of gasoline is measured in British Thermal Units (BTUs). According to the US Energy Information Administration, one gallon of gasoline contains approximately 115,000 BTUs.Therefore, to calculate the number of apples that are the energy equivalent of one gallon of gasoline, we need to determine the energy content of one apple.

Calculating the energy content of apples:

The energy content of an apple varies depending on its size and type, but on average, one medium-sized apple contains about 95 calories or 0.00011 BTUs.To calculate how many apples are equivalent to one gallon of gasoline, divide the BTU content of gasoline by the BTU content of one apple:115,000 BTUs ÷ 0.00011 BTUs/apple ≈ 1,045,454 applesTherefore, approximately 1,045,454 medium-sized apples are the energy equivalent of one gallon of gasoline.

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Answer:

Whale is the largest mammal in the world

Explanation:

you you know that the DNA of parent depend upon her babies.

so due to the DNA characteristics will get big one to another

Answer:

For example, in the North Atlantic and North Pacific, blue whales can grow up to about 90 feet, but in the Antarctic, they can reach up to about 110 feet and weigh more than 330,000 pounds. Like other baleen whales, female blue whales are generally larger than male    Blue whales are the largest animals ever known to have lived on Earth. These magnificent marine mammals rule the oceans at up to 100 feet long and upwards of 200 tons.

Explanation:

Answer:

1666.7 ETB (birr)

833.3 ETB (birr)

2083.3 ETB (birr)

Explanation:

The first worker

5000*1/3=1666.7

The second worker

5000*1/6=833.3

The third worker

5000*5/12=2083.3

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Answer:

v = 40 m/s

Explanation:

Given that,

A man stands 80m in front of a cliff face.  He makes aloud bang and listens for the  echo. He makes a loud bong once every second.

He hears an echo exactly half way between  the bang that caused it and the next hang.

Distance = 40 m, t = 1 s

The speed of sound is given by :

\(v=\dfrac{d}{t}\\\\v=\dfrac{40\ m}{1\ s}\\\\v=40\ m/s\)

Hence, the speed of sound is equal to 40 m/s.

Answer:

\(\boxed {\boxed {\sf 400 \ J}}\)

Explanation:

Work is a force that causes the displacement of an object. It is the product of force and displacement.

\(W=Fd\)

The force is 40 Newtons and the displacement is 10 meters.

Substitute the values into the formula.

\(W= 40 \ N * 10 \ m\)

Multiply.

\(W= 400 \ N*m\)

Convert the units. 1 Newton meter is equal to 1 Joule, so our answer is equal to 400 Joules.

\(W= 400 \ J\)

400 Joules of work was done to move the block.

Answer:

400 J

Explanation:

This is the correct answer for k12

Answer:

The answer is Current.

We have that for the Question "" it can be said that how long will it take the car to come to a full stop and the car lengths before a stop is

From the question we are told

Your car can brake with a deceleration of 6 m/s2. The car is initially going at 40 m/s.

a) How long will it take the car to come to a full stop?  

b) If the car is 5 meters long, about how many car lengths should be kept between you and the car in front of you (assume the car in front of you comes to a stop immediately).

Generally the equation for the Velocity is mathematically given as

\(v=u+at\\\\Therefore\\\\40=0+6t\\\\t=6.667s\\\\\)

b)

s=ut+1/2at^2

Therefore

\(S=0+1/2(6)(6.7)^2\\\\S=134.67m\)

Therefore

The car lengths before a stop is

L=134.67m/5

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(a)The pressure at B is 0.1248 atm.

(b)The temperature at C is 727.1 K.

(c)The total work done by the gas in one cycle is -1979J

General calculation:

We can use the First Law of Thermodynamics to analyze the heat engine cycle:

ΔU = Q - W

where ΔU is the change in internal energy, Q is the heat added to the system, and W is the work done by the system. For a complete cycle, ΔU = 0, so:

Q = W

We can also use the ideal gas law to relate the pressure, volume, and temperature of the gas:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the absolute temperature.

(a)How to find the pressure at B segment?

To find the pressure at B, we can use the fact that the segment AB is an isothermal expansion. This means that the temperature remains constant, so:

PV = nRT

PB = (nRT)/(2V) = (2.00 mol)(0.0821 L·atm/mol·K)(600 K)/(2V) = (0.0821 L·atm/mol)(600 K)/V

Since the pressure at A is 5.00 atm, we can use the fact that the temperature is constant to find the volume at A:

PV = nRT

VA = (nRT)/P = (2.00 mol)(0.0821 L·atm/mol·K)(600 K)/5.00 atm = 197.76 L

Since the volume at B is twice the volume at A, we have:

VB = 2VA = 395.52 L

Substituting into the expression for PB, we get:

PB = (0.0821 L·atm/mol)(600 K)/395.52 L = 0.1248 atm

Therefore, the pressure at B is 0.1248 atm.

To find the temperature at C, we can use the fact that the segment BC is an adiabatic expansion. This means that no heat is added or removed from the system, so:

\(PV^\gamma\)= constant

where γ is the ratio of specific heats (for a monoatomic gas, γ = 5/3). We can use the fact that the volume at C is equal to the volume at A to find the pressure at C:

\(PAV^\gamma = PCV^\gamma\)

PC =  \(PA(V/A)^\gamma\) = 5.00 atm\((1/2)^(^5^/^3^)\) = 1.556 atm

Since the segment BC is adiabatic, the temperature changes but no heat is added or removed from the system. Using the ideal gas law, we can relate the pressure, volume, and temperature:

PV = nRT

TC = (PCVC)/(nR) = (1.556 atm)(197.76 L)/(2.00 mol)(0.0821 L·atm/mol·K) = 727.1 K

Therefore, the temperature at C is 727.1 K.

The total work done by the gas in one cycle is the sum of the work done in each segment of the cycle:

W = WAB + WBC + WCD + WDA

For segment AB, the work done is:

WAB = -QAB = -∫PdV = -nRT∫(1/V)dV = -nRT ln(VB/VA) = -(2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2) = -602 J

For segment BC, the work done is:

WBC = -QBC = -∫PdV = -nγRT∫(1/V)dV = -nγRT

We know that VB = 2VA and VC = 2VD, so we can express the ratio VB/VC in terms of VA/VD:

VB/VC = (2VA)/(2VD) = VA/VD

Substituting into the expression for WBC, we get:

WBC = -nγRT ln(VA/VD)

For segment CD, the work done is:

WCD = -QCD + PCDΔV = -nCpΔT + PCDΔV

where Cp is the specific heat at constant pressure, ΔT is the change in temperature, and ΔV is the change in volume. We know that the segment CD is isobaric, so ΔV = VB - VA = (2VA) - VA = VA. We can also use the ideal gas law to relate the pressure, volume, and temperature:

Substituting into the expression for WCD, we get:

WCD = -nCpΔT + (nRT/VD)VA = -nCp(TC - TD) + (nRT/VD)VA

For segment DA, the work done is:

WDA = -QDA + ΔU = -nCvΔT

where Cv is the specific heat at constant volume. We know that the segment DA is isovolumetric, so ΔV = 0. Using the First Law of Thermodynamics, we know that ΔU = 0 for a complete cycle, so:

QDA = -WDA = nCvΔT

Substituting into the expression for WDA, we get:

WDA = -nCvΔT

Adding up the work done in each segment, we get:

W = WAB + WBC + WCD + WDA

= -(2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2)- (2.00 mol)(5/3)(0.0821 L·atm/mol·K)(727.1 K) ln(VA/VD)- (2.00 mol)(Cp)(TC - TD) + (2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2)- (2.00 mol)(Cv)(TC - TA)

We know that Cp and Cv for a monoatomic gas are related by Cp = Cv + R, so we can express Cp in terms of Cv:

Cp = Cv + R = (3/2)R + R = (5/2)R

Substituting and simplifying, we get:

W = (2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2)- (2.00 mol)(5/3)(0.0821 L·atm/mol·K)(727.1 K) ln(VA/VD)- (2.00 mol)(5/2)(0.0821 L·atm/mol·K)(727.1 K)+ (2.00 mol)(5/2)(0.0821 L·atm/mol·K)(600 K)

W = -966.2 J - 4957 J - 7476 J + 5154 J

    = -1979 J

Therefore, the total work done by the gas in one cycle is -1979 J

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Answer:

The magnification produced by a plane mirror is +1

means then the size of the image is equal to the size of the object. If m has a magnitude greater than 1 the image is larger than the object, and an m with a magnitude less than 1 means the image is smaller than the object.

Answer:

75 volt

Explanation:

Current (I) = 5 A

Resistance (R) = 15 Ω

Voltage (V) = ?

We know

R = V/I

15 = v / 5

v = 75 Volt

Answer:

I think its radiation

Explanation:

Conduction is the transfer of heat through solids (A)

Convection is the transfer of heat through liquids or gasses (B)

Radiation is the transfer of heat through em waves (C)

The angular magnification of the refracting telescope is approximately -0.0215. Note that the negative sign indicates that the image is inverted.

The angular magnification of a telescope is defined as the ratio of the angle subtended by the image seen through the eyepiece to the angle subtended by the object as viewed by the unaided eye. In order to find the angular magnification of this refracting telescope, we need to use the formula:
M = \frac{-fe }{ fo}
where M is the angular magnification, fe is the focal length of the eyepiece, and fo is the focal length of the objective.
Since we know the refractive powers of the objective and eyepiece, we can calculate their focal lengths using the formula:
f = \frac{1}{ P}
where f is the focal length and P is the refractive power in diopters.
Thus, the focal length of the objective is fo = \frac{1 }{ 1.25} = 0.8 meters, and the focal length of the eyepiece is

fe =\frac{ 1 }{230 }= 0.0043 meters.
Substituting these values into the formula for angular magnification, we get:
M = - (\frac{0.0043 }{ 0.8}) = -0.0215

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The shear modulus is approximately 46 GPa.

The shear modulus which is also known as the modulus of rigidity is a material property that measures the ability of a material to resist shear deformation. It is denoted by G and typically measured in Pascals(Pa). It measures the ratio of shear stress to shear strain in a material.

The shear modulus is an important property in the study of material science and engineering.

If an isotropic material has Young's modulus of 120 GPa and a Poisson's ratio of 0.3, you can calculate its shear modulus using the following formula:

G = E / [2 * (1 + (ν))]

Here,

E is Young's modulus of the material

ν is the Poisson's ratio of the material

Plugging the values,

G = 120 GPa / [2 * (1 + 0.3)]

G = 120 GPa / 2.6

G ≈ 46.15 GPa

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\(I = (1/12)M(L^2 + 12d^2)\)

The moment of inertia for a thin rod of mass M and length L about an axis located distance d from one end can be calculated using direct integration.

The formula for the moment of inertia of a rod about an axis perpendicular to its length and passing through one of its ends is given by:

\(I = (1/3)ML^2\)

To find the moment of inertia for a rod about an axis located distance d from one end, we need to use the parallel axis theorem.

The parallel axis theorem states that the moment of inertia of a body about any axis parallel to its center of mass axis is equal to the moment of inertia about the center of mass axis plus the product of the mass of the body and the square of the distance between the two axes.

In this case, the center of mass axis is located at the center of the rod. The distance between the center of mass axis and the axis located distance d from one end is (L/2) - d.

Therefore, we can use the parallel axis theorem to find the moment of inertia about the axis located distance d from one end:

\(I = Icm + Md^2\)

where Icm is the moment of inertia about the center of mass axis, and M is the mass of the rod.

To find the moment of inertia about the center of mass axis, we can divide the rod into small segments of length dx, each with mass dm. The mass of each segment is given by:

\(dm = M/L dx\)

The moment of inertia of each segment about the center of mass axis is given by:

\(dIcm = (1/12)dm dx^2\)

Substituting the value of dm, we get:

\(dIcm = (1/12)(M/L) dx (dx)^2\)

Simplifying, we get:

\(dIcm = (1/12)M/L dx^3\)

Integrating both sides from 0 to L, we get:

\(Icm = ∫(0 to L) (1/12)M/L x^3 dx\)

Solving the integral, we get:

\(Icm = (1/12)ML^2\)

Now, we can substitute the value of Icm and Md^2 in the equation for the moment of inertia about the axis located distance d from one end:

\(I = Icm + Md^2I = (1/12)ML^2 + Md^2\)

Simplifying, we get:

\(I = (1/12)M(L^2 + 12d^2)\)

Therefore, the moment of inertia for a thin rod of mass M and length L about an axis located distance d from one end is given by the formula:

\(I = (1/12)M(L^2 + 12d^2)\)

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a)

Answer:

Using Pythagorean Theorem.

\(F_{R} = \sqrt{Fn^{2} + Fe^{2} } \\\\ F_{R} = \sqrt{52.7^{2} + 91^{2} }\\\\ F_{R} = 105.16N\)

b)

Answer:

\(tan^{-1} \frac{opp}{adj} \\ \\ tan^{-1} \frac{52.7}{91} \\ \\ = 30.08^{o}\)

The resultant force of the two forces which are acting perpendicular to each other is 105.15 N and the direction is 59.91 ° from east.

Force is an external agent acting on a body to change it from the state of motion or rest. If two forces acting on a body and both are applied in the same direction, the resultant force will be the sum of two forces in magnitude.

If the two forces are in opposite directions, then the resultant force will be the substracted value of their magnitude. If one force is to the north and other is to the east, then they are perpendicular to each other.

Hence, to find the resultant force we can use the Pythagoras theorem for right angled triangle. The hypotenuse will be the resultant force.

Resultant force = √ (52.7² + 91² )

                          = 105. 15 N.

The direction of the force = Tan ⁻¹ (91 / 52.7 )

                                           = 59.91 ° from east to north.

Hence, the resultant force is 105.15 N with a direction of 59.91 ° from east.

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Answer:

If the sun's mass were to double without pushing or pulling on the Earth, then the Earth's orbit will change to an ellipse which brings it out to our current radius but spends most of its time closer to the sun. The tides would probably get even stronger then, particularly when our orbit takes us closer to the sun.

Explanation:

Answer:

3.

Force(f) =2000N

Distance (d) =10m

Time(t)=50 sec

We know,

P=W/t

=f×d/t

=2000×10/50

=400 watt

4.

Force(f) =30N

Distance (d) =10 m

Time(t) =5 sec

We know,

P=w/t

=f×d/t

=30×10/5

=60 watt