The third charge q should be placed at a distance of 6 meters from the origin in order to experience zero net force due to the fixed charges.
We can use Coulomb's law to calculate the force exerted by the two fixed charges on the third charge q. Coulomb's law states that the force F between two point charges q1 and q2, separated by a distance r, is given by:
F = k * q1 * q2 / r^2
where k is Coulomb's constant, with a value of approximately 9 x 10^9 N m^2 / C^2.
Let's denote the position of the third charge q as (x, 0), where x is the distance from the origin. Since the net force on q is zero, the forces exerted on it by the two fixed charges must be equal and opposite in direction.
The force exerted by the fixed charge q at the origin on q is given by:
F1 = k * q * q1 / x^2
where q1 is the charge on the fixed charge at the origin (q1 = q), and x is the distance between q and the fixed charge at the origin.
The force exerted by the fixed charge 9q at x = 2.0 m on q is given by:
F2 = k * q * (9q) / (2 - x)^2
where (2 - x) is the distance between q and the fixed charge at x = 2.0 m.
Since the forces are equal and opposite, we can set F1 = -F2 and solve for x:
k * q * q1 / x^2 = - k * q * (9q) / (2 - x)^2
Simplifying this equation, we get:
x^3 - 6x^2 + 36 = 0
This is a cubic equation that can be solved using numerical methods or by factoring. Factoring gives us:
(x - 6)(x^2 - 6x + 6^2) = 0
The only real root of this equation is x = 6. Therefore, the third charge q should be placed at a distance of 6 meters from the origin in order to experience zero net force due to the fixed charges.
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PLEASE HELP! I WILL MARK BRAINLIEST! tight guitar string has a frequency of 560 Hz as its third harmonic. What will be its fundamental frequency if it is fingered at a length of only 60% of its original length?
Answer:
Original fundamental frequency = 311.111 Hz (Approx)
Explanation:
Given:
Frequency (f) = 560 Hz
3rd harmonic
Used length = 60%
Find:
Original fundamental frequency.
Computation:
Fundamental frequency = Frequency (f) / 3rd harmonic
Fundamental frequency = 560 / 3
Original fundamental frequency = 560 / 3(60%)
Original fundamental frequency = 560 / 1.8
Original fundamental frequency = 311.111 Hz (Approx)
HEY CAN ANYONE PLS ANSWER DIS!!!!!!!!!!! IN YOUR OWN WORDS PLS!!!!!!
mass is conserved in a reaction if the of the initial reactant masses equals the of the masses of
Answer:
mass of the products
Explanation:
The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.
What happens to light when it travels from air into water?
Raul is riding on a train that is moving at a speed of 20.0 meters per second. Kirstin is sitting across from him, and there is a distance of 1.8 meters between them. If Raul and Kirstin do not leave their seats, which of the following graphs shows the distance from Raul to Kirstin over the first 6 seconds of the trip?
Answer:
C
Explanation: Study Island
Answer:
The Straight Line Graph
Explanation:
A 55 kg boy running at 2.0 m/s jumps onto a 2.0 kg skateboard. Calculate the
final velocity of the boy and the skateboard.
Answer:
The velocity of the boy and the skateboard is 24
Based on the law of conservation of energy, which statement is correct?
Answer:
You kinda left out the options you want us to choose from.
Resend the question with Full details
An archer shoots an arrow at a target. The arrow begins at the same height as the target. Which statement describes how the archer should aim the arrow
In order to hit the target, the archer should aim the arrow so that it follows a parabolic trajectory.
The archer should aim the arrow slightly higher than the target, so that the arrow will arc downward and reach the target. Additionally, the archer should take into account other factors such as wind speed and direction, as these can affect the trajectory of the arrow.
The parabolic trajectory is a curve created when an object is thrown or shot in the air at an angle, then follows the path of a parabola. The parabolic trajectory allows for the object to travel in an arc and reach a certain distance, such as a target.
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Find the work done when a constant force f = 13 lbs moves a chair from x = 2.4 to x = 4.1 ft. along the x -axis.
The work done in moving the chair from x = 2.4 to x = 4.1 ft using a force of F = 13 lbs is 29.98 J
What is work done?This is simply defined as the product of force and distance moved in the direction of the force. Mathematically, it can be expressed as
Workdone (Wd) = force (F) × distance (d)
Wd = Fd
How to convert lb to N1 lb = 4.45 N
Therefore,
13 lbs = 13 × 4.45
13 lbs = 57.85 N
How to determine the distance in mInitial distance = 2.4 ftFinal distance = 4.1 ftChange in distance = 4.1 -2.4 = 1.7 ft1 ft = 0.3048 m
Therefore,
1.7 ft = 1.7 × 0.3048
1.7 ft = 0.51816 m
How to determine the workdoneForce (F) = 57.85 NDistance (d) = 0.51816 mWorkdone (Wd) =?Wd = Fd
Wd = 57.85 × 0.51816
Workdone = 29.98 J
Thus, the workdone in moving the chair is 29.98 J
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Do you recommend the use of nuclear power as a main source of energy? explain your answer (PLEASE HELP WILL MARK BRAINLIEST!!)
Yes because;
i.Nuclear energy protects air quality
✓Nuclear is a zero-emission clean energy source.
It generates power through fission, which is the process of splitting uranium atoms to produce energy. The heat released by fission is used to create steam that spins a turbine to generate electricity without the harmful byproducts emitted by fossil fuels.
ii.Nuclear energy produces minimal waste
iii.Nuclear energy’s land footprint is small
✓Despite producing massive amounts of carbon-free power, nuclear energy produces more electricity on less land than any other clean-air source.
at the instant when the current in an inductor is increasing at a rate of the magnitude of the self-induced emf is 0.0160 v. (a) what is the inductance of the inductor? (b) if the inductor is a solenoid with 400 turns, what is the average magnetic flux through each turn when the current is 0.720 a?
When the current flowing through an inductor is increasing, the voltage across the inductor also increases, according to Faraday's law of electromagnetic induction.
This phenomenon occurs due to the inductor's inherent property of opposing changes in current. As the current increases, the magnetic field around the inductor expands and induces a voltage across the inductor that opposes the current change. This induced voltage can be visualized as a back EMF (electromotive force) that opposes the driving voltage. The magnitude of the induced voltage depends on the rate of current change, the inductance of the coil, and the number of turns of the coil.
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--The complete Question is,
What happens to the voltage across an inductor when the current flowing through it is increasing? --
Which of these is a good way to begin your personal helath plan for physical fitness A. An assessment B. An action plan C. A plan for measuring progress toward your goal D. An ambitious goal.
Answer: A. An Assessment
I hope this helps, and Happy Holidays! :)
ANSWER
A. An assessment
If you were in charge of designing a wire to carry electricity across your city, state or province, which of
the following properties would be most important for your wire to have?
Should it be thick or thin, aluminum or nichrome, buried underground or installed out in the sun
Pleaseeee I need this done I beg Ill give brainiest and make sure its at least on paragraph if not then at least as many sentences as you can please
Answer:
Thin, aluminium and buried underground.
Explanation:
When it comes to electrification of a state or province, some characteristics of the wire to use must be considered. This would help to minimize and avoid power loss and wire burns.
i. The wire to use should be thin, and a quite number can be twisted one against the other so as to increase the surface area for heat dissipation.
ii. Aluminium wire is more preferable for this project. It has a high melting point, and reduces energy loss.
iii. Burying the wire underground through an insulator is the best choice, though expensive but would preserve the wire from external influence.
A 500. Kg cat is driving with a speed of 4.00 m/s find the momentum of the car
A 500. Kg car is driving with a speed of 4.00 m/s, the momentum of car is 2000 kg.m/sec
What is momentum?Momentum is characterized as the intensity of a body's motion. As momentum relies on both velocity and the direction of the body's motion, it is quantified by "mass velocity". Because velocity is a vector, momentum is a also a vector quantity, whereas mass is a scalar number.
Given that,
mass of car (m) = 500 kg
velocity of car (v) = 4.00 m/sec
Thus, momentum (p) = m × v
p = 500 kg × 4.00 m/sec
p = 2000 kg.m/sec
Thus, momentum of car is 2000 kg.m/sec
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DUE TONIGHT 50 POINTS
An applied force of 13 N east acts on a 6.5-kg block that is moving east at 2.5 m/s on a level, frictionless surface. What is the final speed
of the block if the force is applied for 2.1 s?
A. 1.7 m/s
B. 4.2 m/s
C. 6.7 m/s
D. 7.2 m/s
Sample Response: Yes, the law of conservation of momentum is satisfied. The total momentum before the collision is 1.5 kg • m/s, and the total momentum after the collision is 1.5 kg • m/s. The momentum stays the same after the collision. What did you include in your response? Check all that apply. The law of conservation of momentum is satisfied. The momentum before the collision is 1.5 kg • . The momentum after the collision is 1.5 kg • . The momentum is the same after the collision as it was before the collision.
Answer:
All options presented were applied to the answer.
Explanation:
The sample response presented in the question above, refers to a closed system where two molecules after colliding satisfy the conservation of momentum law, which can also be called the conservation law of linear momentum. This law states that in a closed system the initial state of the components must be maintained and remain the same until the final state, that is, the two molecules maintain their ideal momentum before and after the collision. This means that if they had 1.5 kg • m/s before the collision, this value must be maintained after the collision. All these concepts are presented in the sample response.
Answer:
What did you include in your response? Check all that apply. The law of conservation of momentum is satisfied. The momentum before the collision is 1.5 kg • m/s. The momentum after the collision is 1.5 kg • m/s. The momentum before and after the collision is the same.
Explanation:
The sample response presented in the question above, refers to a closed system where two molecules after colliding satisfy the conservation of momentum law, which can also be called the conservation law of linear momentum. This law states that in a closed system the initial state of the components must be maintained and remain the same until the final state, that is, the two molecules maintain their ideal momentum before and after the collision. This means that if they had 1.5 kg • m/s before the collision, this value must be maintained after the collision. All these concepts are presented in the sample response.
A security incident is currently occurring on the company network. You discover that the attackinvolves a computer system that is attached to the network. You're unsure what kind of damage isbeing done to the network systems or data.Which of the following actions should you take FIRST?
The action which I should take first is a)Stop the attack and contain the damage by disconnecting the system from the network. So correct option is a.
Many people actually rely on the Internet for many of their professional, social and the personal activities. But there are many people who attempt to damage our Internet-connected computers, violate our privacy and render inoperable the Internet services.
Given the frequency and the variety of existing attacks as well as the threat of new and more dangerous future attacks, network security has become a central topic in the field of computer networking.
Hence, correct option is a.
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(Complete question) is:
A security incident is currently occurring on the company network. You discover that the attack involves the computer system that is attached to the network. You're unsure what kind of the damage is being done to the network systems or data. Which of the following actions should you take FIRST?
a)Stop the attack and contain the damage by disconnecting the system from the network.
b)Continuously remain the network system in running state.
c)Try to introduce malware in attacker network system.
d)All of the above.
Suppose a positive charge is brought near a neutral, conducting pieceof material. Is the positive charge attracted, repelled, or indifferent to the neutral object? Explain in other words, using a diagram
The positive charge is attracted to the neutral conducting piece of material.
When a positive charge is brought near a neutral conducting object, such as a metal, the electrons in the conducting material are free to move. The presence of the positive charge causes a redistribution of the electrons within the material. The electrons closest to the positive charge will be attracted towards it, creating an accumulation of negative charge on the side of the conducting material facing the positive charge. This accumulation of negative charge creates an induced positive charge on the opposite side of the material.
As a result, the positive charge is attracted to the neutral conducting piece of material due to the presence of the induced positive charge on the opposite side. This attraction occurs because opposite charges attract each other.
In other words, the positive charge induces a separation of charges within the conducting material, creating an electric field that attracts the positive charge towards the material. This can be visualized in a diagram by showing the redistribution of electrons and the resulting induced charges on the conducting material.
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in a piston which arrange the pressure from maximum pressure to minimum pressure
In a piston, the pressure is arranged from maximum pressure to minimum pressure in the following way:
Maximum pressure is at the top of the piston or the end that is opposite to the connecting rod, while minimum pressure is at the bottom of the end that is attached to the connecting rod. When the fuel-air mixture is ignited in the combustion chamber, it produces high-pressure gases that push the piston towards the connecting rod. This pressure decreases as the piston moves downwards, until it reaches the bottom of its stroke, where the pressure is at its lowest. The process then repeats itself as the piston moves back up towards the top of the cylinder. This movement is known as the piston's stroke. The pressure in the cylinder is controlled by various factors, including the size and shape of the combustion chamber, the fuel-air mixture ratio, and the timing of the ignition.
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compared to a coastal location of the same elevation and latitude, an inland location is likely to have:
A)warmer summers and cooler winters
B) warmer summers and warmer winters
C) cooler summers and cooler winters
D) cooler summers and warmer winters
Answer:
Explanation:
Compared to a coastal location of the same elevation and latitude, an inland location is likely to have **cooler summers and warmer winters** . Coastal climates tend to have wetter winters and drier summers, whereas inland climates have more humid summers and drier winters . Coastal climates are typically limited to narrow strips along the edges of continents, whereas inland climates tend to occur over broad swaths of continental interiors .
I hope this helps answer your question!
If a steady magnetic field exerts a force on a moving charge, that force is directed.
Answer:
F = q V X B = I L X B are descriptions of the force on a moving charge
Suppose that a battery terminal is + on the left connected by a wire to a - charge on the right, the X indicates a cross product so the force on the moving charge is perpendicular to both the magnetic field and the moving charge.
If one wraps the hand around the wire with the thumb pointing in the direction of the "conventional" current, the induced field will be in the direction of the fingers - V X B is the cross product of the moving charge and the magnetic field;
Note q V = q L / t = (q / t) * L = I L
6. What is the uncertainty in position of a proton with mass 1.673 x 10-27 kg and kinetic energy 1.2 keV?
According to Heisenberg's Uncertainty Principle, it is impossible to determine the position and momentum of a particle with absolute certainty at the same time. The Uncertainty Principle is defined as Δx * Δp ≥ h/4π, where Δx is the uncertainty in position, Δp is the uncertainty in momentum, and h is Planck's constant.
For the given problem, the uncertainty in position of a proton with mass 1.673 x 10-27 kg and kinetic energy 1.2 keV can be calculated as follows:
We know that the momentum p of a particle is given by p = mv, where m is the mass of the particle and v is its velocity.
The kinetic energy of the proton can be converted to momentum using the equation E = p²/2m, where E is the kinetic energy.
1.2 keV = (p²/2m) (1 eV = 1.6 x 10^-19 J)
p²/2m = 1.92 x 10^-16 J
The momentum p of the proton can be calculated by taking the square root of both sides:
p = √(2mE) = √(2 x 1.673 x 10^-27 x 1.6 x 10^-16) = 7.84 x 10^-22 kg m/s
Using Heisenberg's Uncertainty Principle, we can calculate the uncertainty in position as follows:
Δx * Δp ≥ h/4π
Δx ≥ h/4πΔp
Substituting the values of h, Δp, and solving for Δx:
Δx ≥ (6.626 x 10^-34)/(4π x 7.84 x 10^-22)
Δx ≥ 2.69 x 10^-12 m
Therefore, the uncertainty in position of the proton is 2.69 x 10^-12 m.
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In the school cafeteria, a trouble-making child blows a 12.0 g spitball through a 25.0 cm straw. The force (F) in Newtons, of his breath as a function of the distance along the straw (x) in meters, can be modeled as a linearly decreasing function for the first half of the straw, followed by a constant force through the rest of the straw. The force decreases by half along the first half of the straw. Assume there is negligible friction and the straw is held horizontally.
(a) Sketch a plot of the force of his breath as a function of position along the straw, labeling the force at x = 0 as F0.
(b) If the spitball begins from rest and leaves the straw with a speed of 16 m/s, how much work is done on the spitball?
(c) What is the maximum force F0, that acts on the spitball?
Answer:
A.) Find the attached file
B.) 1.536 J
C.) 123N
Explanation:
Given that the force (F) in Newtons, of his breath as a function of the distance along the straw (x) in meters, can be modeled as a linearly decreasing function for the first half of the straw,
Half of the straw = 12.5 cm
Let Force F = dependent variable
And distance x = independent variable
A.) Find the attached file for the graph.
Sinnce the force decreases by half along the first half of the straw. Assume there is negligible friction and the straw is held horizontally
B.) Given that the mass M = 12g = 12/1000 = 0.012kg
And Velocity V = 16m/s
The workdone = the kinetic energy of the split ball
WD = 1/2mv^2
Substitutes m and V into the formula
WD = 1/2 × 0.012 × 16^2
WD = 1.536 Joule
C.) The maximum force acts on the spit ball will be at maximum kinetic energy.
Since work done = force × distance
Where distance = 12.5 cm
F × S = 1/2mv^2
Substitutes all the parameters
F × 0.0125 = 1.536
Make F the subject of formula
F = 1.536/0.0125
F = 122.88 N
The maximum force F0, that acts on the spitball is therefore equal to 123 N approximately.
We have that for the Question "(a) Sketch a plot of the force of his breath as a function of position along the straw, labeling the force at x = 0 as F0.
(b) If the spitball begins from rest and leaves the straw with a speed of 16 m/s, how much work is done on the spitball?
(c) What is the maximum force F0, that acts on the spitball?"
It can be said that
a) The sketch is attachedb) The workdone = \(1.536J\)c) Maximum force = \(6.4N\)From the question we are told
mass of spitball = 12g through a 25.0 cm straw
Generally the equation for workdone is mathematically given as
\(= \frac{1}{2}mv^2 - 0\\\\= \frac{1}{2} * 12*10^{-3} * 16^2\\\\= 1.536J\)
Maximum force
\(w = \frac{1}{2}*\frac{x_0}{2}*\frac{F_0}{2} + x_0*\frac{F_0}{2}\\\\w = \frac{5}{8}x_0F_0\)
Therefore,
\(F_0 = \frac{8w}{5x_0}\\\\F_0 = \frac{8*1.536}{5*25*10^[-2]}\\\\F_0 = 6.4N\)
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About 50 000 years ago, in an area located outside Flagstaff, Arizona, a giant
4.5 x 107-kg meteor fell and struck the earth, leaving a 180-m-deep hole now
known as Barringer crater. If the meteor was traveling at 20 000 m/s upon
impact, with what average force did the meteor hit the earth?
Answer:
F_A =5.625*10^1^6N
Explanation:
From the question we are told that
50,000 years ago,
A giant 4.5 107-kg meteor
180-m-deep hole
20,000 m/s
Generally for this problem the energy change is given as
\triangle E=\frac{1}{2} mv^2 +mgd△E=
2
1
mv
2
+mgd
Having the potential and kinetic energy in place
Mathematically solving for Average forceF_AF
A
\triangle E=F_a*d△E=F
a
∗d
F_A =\frac{1/2* 4.5*10^7(20,000)^2-kg+4.5*10^7*9.81*160}{160}F
A
=
160
1/2∗4.5∗10
7
(20,000)
2
−kg+4.5∗10
7
∗9.81∗160
Therefore Average force F_AF
A
is given by
F_A =5.625*10^1^6N
Why we need football?
Answer:
bc we play when we are bored and some people use it as a tradition to play on thanksgiving
what is the magnitude of the vector described below? 13 m/s to the east a. east b. meters per second c. 13 m/s d. meters
Answer:
C
Explanation:
Magnitude of any quantity is the measurable value of the quantity. While the direction of the given quantity is the specific pointing direction of position or the angle at which it move.
The magnitude of the vector described below? 13 m/s to the east will be 13 m/s
While the direction will be eastward.
Therefore, the magnitude is 13 m/s
The correct answer is option C
Which of the following statements does NOT describe force?
A.Force causes objects to change direction.
B.Force causes objects to start moving.
C.Force causes objects to stop moving.
D.Force causes objects at rest to remain stationary.
Answer: D
Explanation: Force can do everything else.
Answer:
D. Force causes objects at rest to remain stationary.
Explanation:
Infrared telescopes are usually placed on high-flying airplanes or on satellites in space __________
Answer:
In order to improve visibility
Explanation:
Infrared telescopes are made using infrared cameras that contain infrared detectors which are solid-state and are maintained at very cold (cryogenic) temperatures
Infrared radiation is absorbed by water vapor which is present in the Earth's atmosphere, leading to the limitation of the use of infra red telescopes at high altitudes such as mountains, high flying planes or satellites
I can’t think of the answer for this question
The car started 15 ml west of Mulberry road.
Consider the East-West route as the x-axis, and place Mulberry Road's intersection at x = 0. This implies that, the west of the intersection is -ve and the east side will be represented positive.
Given the car ends up at 18 mi West to the intersection, implies that it ends at -18mi from x = 0. Also given the total displacement = - 33mi.
Hence, initial position = final position - displacement
= -18 - (- 33)
= -18 + 33
= 15 mi. So, the car started from 15mi from the Mulberry road and from the East of it.
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A light spring with force constant 3.70 N/m is compressed by 8.64 cm as it is held between a 0.261-kg block on the left and a 0.522-kg block on the right, both resting on a horizontal surface. The spring exerts a force on each block, tending to push them apart. The blocks are simultaneously released from rest. Find the acceleration with which each block starts to move, given that the coefficient of kinetic friction between each block and the surface is the following. (Let the coordinate system be positive to the right and negative to the left. Be sure to include the sign to indicate the direction of the acceleration.) (a) μ = 0 heavier block lighter block (b) μ = 0.110 heavier block lighter block (c) μ = 0.480 heavier block lighter block m/s² m/s² m/s² m/s² m/s² m/s²
The lighter block will also accelerate to the right with an acceleration of -0.82 m/s².
(a) μ = 0
The heavier block will accelerate to the right with an acceleration of:
a = F / m = k x / m = (3.70 N/m) (0.0864 m) / 0.261 kg = 1.22 m/s²
The lighter block will also accelerate to the right with an acceleration of 1.22 m/s².
(b) μ = 0.110
The heavier block will accelerate to the right with an acceleration of:
a = F - μk / m = k x / m - μk / m = (3.70 N/m) (0.0864 m) / 0.261 kg - (0.110)(0.261 kg)(9.80 m/s²) = 0.68 m/s²
The lighter block will not accelerate because the force of friction is greater than the force of the spring.
(c) μ = 0.480
The heavier block will accelerate to the right with an acceleration of:
a = F - μk / m = k x / m - μk / m = (3.70 N/m)(0.0864 m) / 0.261 kg - (0.480)(0.261 kg) (9.80 m/s²) = -0.82 m/s²
Therefore, the lighter block will also accelerate to the right with an acceleration of -0.82 m/s².
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