a plano-convex lens is to have a focal length of 18.7 cm. if made from fused quartz (n = 1.46), what must be the radius of curvature of the convex surface?

Answer:

Gravity is what holds the planets in orbit around the sun and what keeps the moon in orbit around Earth. The gravitational pull of the moon pulls the seas towards it, causing the ocean tides. Gravity creates stars and planets by pulling together the material from which they are made.

Explanation: Hope it helps you :))))

Have a good day

The photon energy corresponding to the peak frequency of the cosmic microwave background radiation is approximately 6.626 x 10^-24 Joules.

The cosmic microwave background (CMB) radiation is a remnant of the Big Bang and is characterized by a blackbody spectrum.

The peak frequency of the CMB radiation occurs in the microwave region of the electromagnetic spectrum.

To determine the photon energy corresponding to the peak frequency, we can use Planck's equation,
E = hf,
where E is the energy,
h is Planck's constant (approximately 6.626 x 10^-34 Joule-seconds), and
f is the frequency.

The peak frequency of the CMB radiation is around 160.2 GHz or 1.602 x 10^11 Hz. By substituting this value into the equation, we get:

E = (6.626 x 10^-34 J s) * (1.602 x 10^11 Hz) ≈ 6.626 x 10^-24 Joules.

Therefore, the photon energy corresponding to the peak frequency of the CMB radiation is approximately 6.626 x 10^-24 Joules.

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Answer:D

Explanation:

:)

The item has no energy at its greatest point since all of it's kinetic energy has been transformed into potential energy; as a result, the velocity is null and the object is not accelerating.

The best engine in the cosmos is the speed of light. A study that was earlier this month published in the scientific journal Nature revealed that it was an illusion.

The formula for gravitational force is P.E. Equals mgh, where g is the deceleration caused by gravity (9.8 m/s2 at the earth's surface) when h is the elevation in meters. The units for gravitational potential energy are kg m2/s2, which are the same as those for kinetic energy.

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Answer:

False

Explanation:

To determine the point at which a spaceship is beyond the pull of Earth's gravity, we need to calculate the gravitational potential energy at that point. The equation for gravitational potential energy is:

\(\[ Ep = - \frac{G \times m_{1}m_{2}}{r} \]\)

where Ep is the gravitational potential energy, G is the gravitational constant (approximately 6.67430 × \(10^{(-11)} N m^2/kg^2)\), m1 is the mass of the spaceship, m2 is the mass of the Earth, and r is the distance between the spaceship and the center of the Earth.

When the spaceship is beyond the pull of Earth's gravity, the gravitational potential energy will be zero or negligible. Therefore, we can set Ep equal to zero and solve for the distance (r) at that point.

Given:

Mass of the spaceship (m1) = Assume a value (let's say 1 kg)

Mass of the Earth (m2) = 5.972 × \(10^{24\) kg (approximately)

Gravitational constant (G) = \(6.67430 × 10^(-11) N m^2/kg^2\)

Let's plug in the values and solve for r:

\(\[ 0 = - \frac{G \times m_{1}m_{2}}{r} \]\)

\(\[ 0 = - \frac{(6.67430 × 10^(-11) \, \text{N m}^2/\text{kg}^2) \times (1 \, \text{kg}) \times (5.972 × 10^24 \, \text{kg})}{r} \]\)

Simplifying the equation:

\(\[ 0 = - \frac{6.67430 × 10^(-11) \times 5.972 × 10^24}{r} \]\)

\(\[ 0 = - \frac{39.82144 × 10^{13}}{r} \]\)

To solve for r, we can multiply both sides by r:

\(\[ 0 = -39.82144 × 10^{13} \]\)

Since the left side of the equation is zero, we have:

\(\[ 0 = 0 \]\)

This means that the equation is true for any value of r. In other words, the spaceship is never beyond the pull of Earth's gravity.

Earth's gravitational pull extends indefinitely, even though it becomes weaker as you move farther away from the Earth.

Therefore, the spaceship will always experience the gravitational pull of Earth throughout its journey to the Moon and beyond.

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Answer:

a.149 °F into °C

149 - 32 = 117

117 x 5 = 585

585 / 9 = 65

149 °F = 65 °C

b.149 °F into Kelvin

(149°F − 32) × 5/9 + 273.15 = 338.15K

Frequency or wavelength-based distribution of all electromagnetic radiation is known as electromagnetic spectrum.

The majority of celestial bodies emit many forms of electromagnetic radiation simultaneously. What they emit depends on a variety of factors, including how hot they are and what materials they are made of.

Different telescopes are used by astronomers to find various electromagnetic spectrum components. Only one region of the electromagnetic spectrum can be detected by each type of telescope.

At radio frequencies, light pollution is more severe than at visible wavelengths.

Light pollution, often known as artificial nighttime light, is the improper or excessive use of artificial outdoor light.

Different energies of photons have a range of wavelengths, some of which are inaccessible from the Earth's surface and need different methods of collection.

As the atmosphere distorts more strongly at shorter wavelengths, telescopes must adjust.

Modern telescopes use new technologies to work more effectively and making innovative telescope designs is a task that engineers and astronomers relish.

That’s why astronomers need different telescopes at different locations to observe across the electromagnetic spectrum.

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Answer:A Ed 2020

Explanation:

In order to use the Pythagorean theorem to find the magnitude of a resultant vector, two initial vectors must form a 90 degree angle.

The Pythagorean theorem, sometimes known as Pythagoras' theorem, is a basic relationship between a right triangle's three sides in Euclidean geometry.

In a right-angled triangle, the square of the hypotenuse side is equal to the sum of the squares of the other two sides, according to Pythagoras's Theorem. These triangle's three sides are known as the Perpendicular, Base, and Hypotenuse.

Due to its position opposite the 90° angle, the hypotenuse in this case is the longest side. When the positive integer sides of a right triangle (let's say sides a, b, and c) are squared, the result is an equation known as a Pythagorean triple.

Hence,  two initial vectors must form a 90 degree angle.

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Cost of operating a 200-W lamp continuously for 1 week when the power Utility rate is 20 cents/kWh is $6.72.

The energy consumed by the lamp in one week is:

1 week = 7 days = 24 hours/day = 7 x 24 = 168 hours

Energy = Power x Time

Energy = 200 W x 168 hours = 33,600 Wh

To convert watt-hours (Wh) to kilowatt-hours (kWh), we divide by 1000:

33,600 Wh ÷ 1000 = 33.6 kWh

The cost of using the lamp for 1 week is:

Cost = Energy x Rate

Cost = 33.6 kWh x $0.20/kWh = $6.72

Therefore, the cost of operating a 200-W lamp continuously for 1 week when the power Utility rate is 20 cents/kWh is $6.72.

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this question is centered around newtons second law f=ma

First you need to find the acceleration

\( acceleration = \frac{8 - 0}{22} \)

that gives you 0.36 recurring(on both numbers) m/s²

mass= force ÷ acceleration

\( mass = \frac{31}{0.36recurring} \)

mass= 85.25 kg

if you want to check

f=ma

85.25 × 0.36 recurring (remember its on both numbers not just 6) = 31 N

Answer:

Explanation:

Givens

F = 31 N

vi = 0

vf = 8 m/s

t = 22 seconds

m = ?

Formula

F = m ( vf - vi)/t

Solution

31 = m (8 - 0) / 22             Multiply both sides by 22

31 * 22 = 8 * m

8m = 682                          Divide by 8

m = 682 / 8

m = 85.25

Explanation:

he is very keen on taking up and is the age

another answer for acellus is 143 m/s it worked for me

The speed of the charge is approximately 2.857 m/s.

To find the speed of the charge, we can use the formula for the magnetic force on a charged particle moving through a magnetic field:

Force (F) = q * v * B * sin(θ)

Where:

F is the force on the charge (given as 2.14 x \(10^-8\)  N),

q is the charge of the particle (given as 2.99  x \(10^-6\)C),

v is the speed of the charge (what we want to find),

B is the magnitude of the magnetic field (given as 5.00 x \(10^-5\) T),

θ is the angle between the direction of motion and the magnetic field (given as 10.0°).

First, we need to convert the angle from degrees to radians:

θ (in radians) = 10.0° * (π / 180°) ≈ 0.174532925 radians

Now, we can rearrange the formula to solve for the speed (v):

v = F / (q * B * sin(θ))

Substitute the given values into the equation:

v = 2.14 x \(10^-8\) N / (2.99 x \(10^-6\) C * 5.00  x \(10^-5\)  T * sin(0.174532925))

v ≈ 2.857143 m/s

Therefore, the speed of the charge is approximately 2.857 m/s.

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Answer:

Kepler refined the Copernican model. Orbits are not circles along which planets move at a constant speed, but ellipses, in the central focus of which is the Sun. The planet moves in an ellipse with a variable speed depending on the distance to the Sun. On this basis, Kepler significantly simplified the Copernican model and formulated the laws of planetary motion in their orbits.

The three workers that use technologies that apply the Doppler effect are;

The term Doppler effect has to do with an increase or decrease in the frequency of sound as the observer moves towards or away from the source of the sound.

We know that;

fo = (v + vo/v + vs) fs

fo = frequency of the observer

v = velocity of sound

vs = velocity of source of sound

vo = velocity of observer

fs = true velocity of sound

The three workers that use technologies that apply the Doppler effect are;

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Answer:

The answer is the third one.

C.

Hope this helps!

A photon is a quantum of light is the correct answer.

A photon is tiny packets of energy of electromagnetic radiation. This concept is presented by Albert Einstein in order to explain the photoelectric effect. Photon is also known as light quantum because it is related to light.

So we can conclude that photon is a quantum of light is the correct answer.

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Answer:

a quantum of light

Explanation:

I got it right on the test.

Using the free body diagram, let's determine the scenario the diagram illustrates.

From the free body diagram, we can see that the weight is acting on the object while the tension will be the force which supports the object.

The tension in this case, helps hang the object while the weight is the product of the mass of the object and the force of gravity acting on the object.

Tension can be defined as the pulling force transmitted through a rope or string.

Therefore, the best scenario which is represented by the free body diagram is a sign board supported by two strings.

ANSWER:

A signboard supported by

Answer: If the charges were opposite

Explanation:

Opposite charges attract, same charges repel (negative repels negative, positive repels negative), neutral charges have no charge

Force lines, also known as electric field lines, connect two charges when they are opposite in sign. Option C is correct.

Charge is a fundamental property of matter that determines how it interacts with electromagnetic fields. Electric charge is a property of subatomic particles such as electrons and protons. It can be either positive or negative, and like charges repel each other while opposite charges attract each other.

Here,
Force lines, also known as electric field lines, connect two charges when they are opposite in sign. If the charges are both positive or both negative, the electric field lines will diverge away from each other, indicating a repulsive force between them. If the charges are opposite in sign, the electric field lines will converge toward each other, indicating an attractive force between them.

If the charges are neutral, there is no net electric field and thus no electric field lines connecting the charges. However, electric dipoles can still be formed between neutral charges, which can create a non-zero electric field in their surroundings.

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According to the Question:

\(\footnotesize\implies F \propto [m]^x [v]^y [r]^z\)

\(\footnotesize\implies F =k [m]^x [v]^y [r]^z \:...(i)\)

Now, substituting Dimensions of each physical quantity in equation (I):

\(\footnotesize\implies [M^1L^1T^{-2}] =[M^1L^0T^0]^x [M^0L^1T^{-1}]^y [M^0L^1T^0]^z\)

\(\footnotesize\implies [M^1L^1T^{-2}] =[M]^x [L]^{y + z} [T]^{ - y}\)

On comparing the powers of LHS and RHS:

\(\implies \bf x = 1\)

\(\implies - y = - 2\)

\( \implies \bf y = 2\)

\(\implies y + z = 1\)

\(\implies z = 1 - 2\)

\(\implies \bf z = - 1\)

\(\footnotesize\implies F = [m]^x [v]^y [r]^z\)

\(\footnotesize\implies F = [m]^1 [v]^2 [r]^{ - 1}\)

\(\implies\footnotesize \underline{ \boxed{ \bf \red{ F = \frac{m {v}^{2} }{r} }}}\)

The direction of the angular momentum of the hoop depends on the orientation of the hoop and the direction of its rotation. A hoop that rolls without slipping on a horizontal surface has both translational and rotational motion. The linear speed of the hoop is constant and in the due east direction, but the hoop is also rotating about its center. The direction of the angular momentum of the hoop is perpendicular to the plane of rotation and is given by the right-hand rule. If the hoop is rotating clockwise when viewed from above, then the direction of the angular momentum is upward, perpendicular to the plane of rotation and pointing north. If the hoop is rotating counterclockwise, then the direction of the angular momentum is downward, perpendicular to the plane of rotation and pointing south. The angular momentum of a rotating object is a vector quantity that describes the quantity of rotation and is an important concept in the study of rotational motion in physics.

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The direction of the angular momentum of a hoop rolling without slipping on a horizontal surface, moving east at a constant linear speed, is clockwise.

This is because the angular momentum is defined as the product of the moment of inertia and the angular velocity. Since the hoop is moving in a straight line, the angular velocity is zero, and the angular momentum is equal to the moment of inertia multiplied by zero.

Since the moment of inertia is a positive quantity, the angular momentum is also positive, and thus it is clockwise. This direction is determined by the right-hand rule, which states that if your right hand is placed in the direction of motion, the thumb points in the direction of the angular momentum.

It is important to note that the direction of the angular momentum does not change as the hoop moves along the surface. This is because angular momentum is a conserved quantity and is not affected by any external forces or torques.

Furthermore, the magnitude of the angular momentum is also constant since the linear speed is constant and the moment of inertia remains the same.

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Here's the Answer :

=》A) It will move towards the weaker force.

because, the stronger force will overcome the weaker one and hence make the object move towards the other side.

The magnifying power of an astronomical telescope will be:

"0.095".

Telescope: Focal length and Power

According to the question,

Radius of curvature, R = 5.5 mm

Focal length of eyepiece,  = 2.9 cm

We know that,

→ Focal length of mirror,

F₀ =

By substituting the values,

   = 2.75 mm or,

   = 0.278 cm

hence,

The telescope's magnification be:

= 0.095

Thus the above approach is correct.

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The magnifying power of the astronomical telescope using a reflecting mirror is approximately 108.62.

To determine the magnifying power of an astronomical telescope, we can use the formula:

Magnifying power (M) = Focal length of the objective / Focal length of the eyepiece

For a reflecting mirror, the focal length is half of the radius of curvature. In this case, the focal length of the objective (mirror) is:

Focal length of the objective = Radius of curvature / 2 = 6.3m / 2 = 3.15m

Now, convert the eyepiece's focal length to meters:

Focal length of the eyepiece = 2.9cm = 0.029m

Using the formula for magnifying power:

M = 3.15m / 0.029m = 108.62

Therefore, the magnifying power of the astronomical telescope is approximately 108.62.

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Answer:

B is the answer

Explanation:

Here, the black color may be dominant trait in the kittens  and trait for white color is hidden in the kittens.

The genetic codes that creates a particular characteristics in a species is called a gene trait.  Most of common characteristics will be inherited from the parents to the offsprings.

The B gene regulates the synthesis of eumelanin, the pigment that gives cats their black fur. It has three different alleles, or kinds. It just takes one B allele from one parent for a cat to have black fur since the B gene, which causes black fur, is dominant.

Either parent's color or a mixed color is getting for the kittens. Sometimes the one color trait will be hidden in them and in that case they show the color one parent that is dominant.

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Answer:

7 Seconds

Explanation:

P=W/t

t=W/P

t=875,000/125,000

t=7 seconds

The lowest frequency at which the circuit can operate can be determined using the formula:
f = (1 / (2π√(L3 * C)))
The lowest frequency at which the circuit can operate is not limited by the given parameters.

Given that L3 is 24 mH (millihenries), we can convert it to henries by dividing it by 1000:
L3 = 24 mH = 0.024 H
Assuming the circuit operates at the resonant frequency, the inductive reactance (XL) and capacitive reactance (XC) cancel each other out, resulting in a purely resistive circuit. This means that the impedance (Z) of the circuit is equal to the resistance (R). In this case, the impedance is given by:
Z = Vrms / Irms = 7.0 V / 1.0 A = 7.0 Ω
Since Z = R, we can consider R as the effective resistance of the circuit.
Using the impedance and inductance values, we can calculate the capacitance (C) required for the circuit:
Z = √(R² + (XL - XC)²)
7.0 Ω = √(R² + (2πfL3 - 1 / (2πfC))²)
Since we want to find the lowest frequency, we can assume that the capacitive reactance is at its maximum value, which occurs when XC = 1 / (2πfC) is at its minimum. This happens when the denominator is at its maximum value, which occurs when fC is at its minimum.
Therefore, the lowest frequency (f) occurs when fC = 1 / (2πfC) is at its minimum.
Simplifying the equation, we have:
1 / (2πfC) = 2πfC
1 = (2πfC)²
1 = 4π²f²C²
f²C² = 1 / (4π²)
Now we can substitute the given values and solve for the lowest frequency (f):
(1 / (4π²)) * C² = 1 / (4π²)
C² = 1
Since C is the capacitance, its value cannot be negative. Therefore, the equation C² = 1 has a valid solution, which means that the lowest frequency (f) is not restricted by the given constraints.
In conclusion, the lowest frequency at which the circuit can operate is not limited by the given parameters.

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A motive, when restated at a different pitch, results in a transposition or sequence.

In music, a motive refers to a short melodic or rhythmic fragment that serves as a building block for a larger musical composition. Motives can be restated or repeated at different pitches, leading to variations in the musical material.

When a motive is restated at a different pitch, it undergoes a process called transposition. Transposition involves shifting the entire motive up or down in pitch while maintaining the same intervals and relationships between the notes.

This allows the motive to be presented in a different tonal context or to explore different musical possibilities while still retaining its recognizable characteristics.

Transposition is a common technique used in music composition and arrangement to create variation, explore different tonalities, or adapt a musical idea to different instruments or vocal ranges. It provides composers and performers with a way to manipulate and develop musical material while maintaining a cohesive musical structure.

Therefore, Restating a motive at a different pitch result in either a transposition or a sequence of the musical fragment.

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Answer:

the anwser is atp

Explanation:

To move substances against a concentration or an electrochemical gradient the cell must use energy. This energy is harvested from ATP that is generated through cellular metabolism. Active transport mechanisms, collectively called pumps or carrier proteins work against electrochemical gradients.

The energy for passive transport comes from the gradient itself, in which transfer of a solute from high electrochemical potential to low take place.

The passive transport is the shifting or transfer of a solute from a place where the electrochemical potential is high to a place where the electrochemical potential is low.

Energy require for passive transport-

Thus, the energy for passive transport comes from the gradient itself, in which transfer of a solute from high electrochemical potential to low take place.

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