a person threw a small bundle toward their friend on a balcony 10 meters above them. how fast did they throw it up?

A tug-of-war that results in one team pulling the other across the line is an example of reaction force.

A reaction force  can be described as the consequence of an action force which is opposite in direction.

It should be noted that the  Newton's third law of motion is the one that deals with these two forces, which  can be considered as the action and reaction forces however the Newton's third law made us to understand that for every action, there is an equal and opposite reaction, hence the case above can be seen as an example of reaction force.

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The kangaroo's horizontal speed will be 9.7 m/s and its departure speed will indeed be 10.65 m/s.

By observing the pace at which this compressed region moves through the medium, we may determine the sound speed. The sound wave travels at a speed of around 343 meters per second in low humidity at 20 degrees Celsius.

The following equation relates the distance to the direction and initial velocity:

d = [v₀²sin2θ]/g, where θ – the angle of the jump.

Thus, v₀² = gd / (sin2θ) = (9.8×8)/0.69 = 113.62

v₀ = 10.65 m/s ( the take off speed).

The horizontal velocity equals:

vₓ = v₀cos 22° = 10.65 m/s × 0.92 = 9.7 m/s

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Physical effects refer to the changes or alterations that occur in the physical properties of an object or system, as a result of a physical force or interaction.

Physical effects are the modifications or changes that take place in an object's or system's physical characteristics as a result of a physical force or interaction.

These effects can be observed and measured through various physical phenomena, such as temperature, pressure, density, electric fields, and magnetic fields, among others.

Examples of physical effects include the deformation of a material under stress, the heating or cooling of an object when it is exposed to a heat source or cold environment, the change in pressure of a gas when it is compressed or expanded, the flow of electric current through a conductor, and the generation of magnetic fields around a magnet or current-carrying wire.

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The correct answers are up, down, into the screen, and out of the screen.

When a charge is moving at an angle of 90 degrees to a magnetic field, it experiences no magnetic force. When a charge is moving parallel or anti-parallel to a magnetic field, it does not experience magnetic force.

Check all that apply in the following list: UpDownLeftRightInto the screenOut of the screen

A magnetic field is a field created by an electrical charge in motion, such as an electron or a current through a wire. A magnetic field's direction is determined by the direction of the current, with north and south poles corresponding to the direction of the current.

When a charged particle travels through a magnetic field, it experiences a magnetic force.The charge moves and experiences no magnetic force when it is perpendicular to the magnetic field.

Therefore, the correct answers are up, down, into the screen, and out of the screen.

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To answer this question, we need to use the formula that relates force, mass, and acceleration: F=ma. We can rearrange this formula to solve for acceleration: a=F/m.

In this case, we are given that the force applied by the motor is 13.9N, and we need to find the velocity at which it will pull a mass. We are not given the mass directly, but we can calculate it using the power of the motor (300W) and the velocity we are trying to find.

Power is defined as the rate at which work is done, or P=W/t, where W is the work done and t is the time it takes to do that work. In this case, we can assume that the work done is moving the mass a certain distance, and we can use the velocity to calculate the time it takes to do that work. So, we have:

P=Fv

where P=300W, F=13.9N, and v is the velocity we want to find. Rearranging this equation gives:

v=P/F

Now we can substitute in the values for P and F to get:

v=300/13.9

v≈21.6 m/s

So, at a velocity of 21.6 m/s, a 300.W motor applying a force of 13.9N can pull a mass.

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Answer:

Kinetic, Potential, and Chemical energy

Explanation:

If you want to know the six basic ones they are, chemical, electrical, radiant, mechanical, thermal and nuclear energy. Hope this helps!

Answer:

If talking about forms of energy, the answer would be:

Kinetic, potential, and chemical energy

If asking for types, the answer could be:

Nuclear, Electrical, and Thermal

The correct  option is D, A material in which electrons are able to move easily conductor.

A conductor is a material or substance that allows for the flow of electric charge. This is due to the presence of free electrons within the material, which are not bound to specific atoms and are able to move easily in response to an electric field. Conductors are widely used in electrical circuits, where they are used to transport electricity from one place to another with minimal loss of energy.

Conductors are typically characterized by their ability to conduct electricity, which is measured by their electrical conductivity. This property is determined by a number of factors, including the nature of the material, its temperature, and the strength of the electric field. Some common examples of conductors include metals such as copper, aluminum, and gold, as well as certain non-metallic materials like graphite.

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Answer:

First one is hyperopia, second is myopia

Explanation:

Hyperopia is when the image is formed behind the retina.

Myopia is when images are formed infront of the retina.

The minimum force of friction necessary to stop the car just before hitting the deer is 3,000N.

Friction is a force between two surfaces that opposes motion when they rub against each other. It is the force that allows us to walk without slipping, and it is also the force that makes it difficult to move a heavy object. Friction is a type of non-conservative force, which means that it takes energy to overcome it, and that energy is not stored or conserved.

The force of friction necessary to stop the car can be determined using the equation F = mv²/2d. In this equation, F is the force of friction, m is the mass of the car (2,000kg), v is the initial velocity of the car (30m/s), and d is the distance between the car and the deer (300m). Plugging in the values, we get F = 2,000 ×(30)² / (2 × 300) = 3,000N. Therefore, the minimum force of friction necessary to stop the car just before hitting the deer is 3,000N.

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In glycerine, the light ray is refracted at an angle of 15.8°.

According to Snell's law, the angle of incidence I and angle of refraction (r) for a light ray travelling from a medium having a refractive index of one to a media with a refractive index of two are related by the formula n one times sin I equals n two times sin r.

n1 sin(theta1) = n2 sin(theta2)

where n1 and n2 are the indices of refraction of the two media, theta1 is the angle of incidence, and theta2 is the angle of refraction.

First, we can use Snell's Law to find the angle of refraction of the ray of light in ice:

n1 sin(theta1) = n2 sin(theta2)

sin(theta2) = (n1/n2) sin(theta1)

sin(theta2) = (1.000/1.314) sin(23.7)

sin(theta2) = 0.4205

theta2 = sin⁻¹(0.4205)

theta2 = 25.9°

Next, we can use Snell's Law again to find the angle of refraction of the ray of light in glycerine:

n1 sin(theta1) = n2 sin(theta2)

sin(theta2) = (n1/n2) sin(theta1)

sin(theta2) = (1.314/1.477) sin(25.9)

sin(theta2) = 0.2961

theta2 = sin⁻¹(0.2961)

theta2 = 15.8°

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Answer:

It means that 400 J of heat is the required amount to raise or lower thh temperature of a 1kg piece of copper

Explanation:

390 J/Kg °C specific heat capacity of copper means, 390 J of energy is required to raise the temperature of 1 kg of copper by 1 °C

From the given information,

The specific heat capacity of copper is 390 J/Kg °C. To determine what this means, we will define the term specific heat capacity.

The specific heat capacity of a substance is the amount of energy required to raise the temperature of 1 kg of the substance by 1 °C.

Therefore, 390 J/Kg °C specific heat capacity of copper means, 390 J of energy is required to raise the temperature of 1 kg of copper by 1 °C.

Hence, 390 J/Kg °C specific heat capacity of copper means, 390 J of energy is required to raise the temperature of 1 kg of copper by 1 °C.

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Answer:

potential energy depends on position or shape

Answer:

13.7 J

Explanation:

In absence of air resistance, the mechanical energy of the object is conserved during the fall: this means that the initial gravitational potential energy that it has at the beginning of the fall will be entirely converted into kinetic energy when the book is just about the hit the ground.

Therefore, this also means that we can calculate the mechanical energy at the beginning of the fall, as this will be equal to the mechanical energy just before the book hits the ground.

At the beginning of the fall, the mechanical energy is all gravitational potential energy:

where

m = 0.5 kg is the mass of the book

is the acceleration of gravity

h = 2.8 m is the height above the ground

Substituting,

It could be observed that the number of electrons escaping the film is increased.

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Explanation:

The potential energy of an object has the following formula

         Potential energy = mgh

      where m = mass of the object

                   g = acceleration due to gravity

                   h = height of the object

This means that the potential energy of an object depends upon its mass, acceleration due to gravity, and height.

In the given situation we have a bucket full of water. If the mass and acceleration due to gravity are not changed, the only way the potential energy can be decreased is by reducing the height of the bucket full of water.

This can be done by: -

         (i) Lifting the bucket full of water in such a way that you

             decrease its height as compared to the bench.

        (ii) Put the bucket full of water on a stool whose height is

            lower than the bench.

Answer:

1.By decreasing it's contents- this decreases the weight of the bucket thus decreasing the potential energy of the bucket.

2.By decreasing the height of the bench we have decreased the amount of potential energy stored in the bucket

Answer:

Explanation:

The cars velocity is 14m/s. That means for every second, the car moves 14m. Now, if the car wants to reach 28m, going 14m/s, it will take 2 seconds for the car to reach 28m.

Answer:

0.25N

Explanation:

k=0.5N/m

e=0.5m

f=?

were k=spring constant

e=extension

F=force

According to hooks law,

f=ke

f=0.5x0.5 =0.25 N

Answer:

The measurement of an object's motion with respect to any other object that is moving or stationary is called Relative Motion.

a) Force is: :F = 4849.7 + FB... b) force support B must exert on the beam in order for it to remain at rest is 7009.7 N c) At what distance x, in meters, from support A is the worker sitting now is 10.5 m. for the force.

The given figure and problem is shown below:Here,L = 14mmb = 405 kgmw = 79 kgFA = 2160 N

(a) We need to calculate the expression for the force support B must exert on the beam in order for it to remain at rest, in terms of defined quantities, x, and g.Force, F on a body of mass, m, on the earth due to the gravitational force of attraction, g is given by:F = m × gHere, for the rigid steel beam,F = mb × g

Thus, the force on the beam is given by:mg = 405 × 9.8 = 3970.5

Now, we consider the forces acting on the beam when the worker of mass, mw sits at a distance, x from support A. The forces acting on the beam are as follows:mg force acting downwards due to gravity mwg force acting downwards due to gravityF force acting upwards due to support AFB force acting upwards due to support BFrom the given problem, we know that the beam is at rest.

Therefore, the sum of the forces acting in the vertical direction will be zero. So we have:mg + mwg + F + FB = 0Now substituting the value of mg and multiplying both sides by -1, we get:FB = -mg - mwg - FFB = -(mb + mw)g - FFB = -4849.7 - FF = 4849.7 + FB

Thus, the force support B must exert on the beam in order for it to remain at rest, in terms of defined quantities, x, and g is given by:F = 4849.7 + FB...[Ans]

(b) The force, in newtons, that support B must exert on the beam in order for it to remain at rest when the worker sits at a distance x = 3.5 m from support A is given by:F = 4849.7 + FBThe force acting on the beam due to the gravitational force of attraction, g is given by:mg = 405 × 9.8 = 3970.5 Nmwg = 79 × 9.8 = 774.2 N

Now substituting the value of mg and mw and F = FA = 2160 N, we get:FB = -4849.7 - FFB = -4849.7 - FAFB = -4849.7 - 2160FB = -7009.7 NThus, the force support B must exert on the beam in order for it to remain at rest is 7009.7 N...[Ans]

(c) Let the distance from support A be y (as shown in the figure).Then, x + y = LSo, y = L - x

Substituting the value of L = 14m and x = 3.5m, we get:y = 14 - 3.5 = 10.5 m

Therefore, at what distance x, in meters, from support A is the worker sitting now is 10.5 m...[Ans]

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To calculate the standard free energy change of the reaction (ΔG°rxn), we can use the formula:ΔG°rxn = ΣnΔG°f(products) - ΣmΔG°f(reactants), where ΔG°f is the standard free energy of formation, n and m are the stoichiometric coefficients of the products and reactants, respectively.

Using the given data, we have:

ΔG°f(HNO3(aq)) = -207.0 kJ/mol

ΔG°f(NO(g)) = 91.3 kJ/mol

ΔG°f(NO2(g)) = 33.2 kJ/mol

ΔG°f(H2O(l)) = -285.8 kJ/mol

The stoichiometric coefficients of the balanced equation are:

2 HNO3(aq) → 3 NO2(g) + H2O(l)

So, we have:

ΔG°rxn = [3 × ΔG°f(NO2(g))] + [ΔG°f(H2O(l))] - [2 × ΔG°f(HNO3(aq))]

ΔG°rxn = [3 × 33.2 kJ/mol] + [-285.8 kJ/mol] - [2 × (-207.0 kJ/mol)]

ΔG°rxn = 99.6 kJ/mol - (-414.0 kJ/mol)

ΔG°rxn = 513.6 kJ/mol

Therefore, the standard free energy change of the reaction is approximately 513.6 kJ/mol.

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Answer:

Explanation:

You cant if the path is crooked then speed wont help but throw you off the track over and over.

Answer:

Depends.

Explanation:

It may be a bit harder because of the path's winding direction, but like the other question I answered, direction does not matter when calculating speed. So, you should be able to determine the speed using the formula per normal.

That is, if this path has railing of some form.

If not, then this answer is almost impossible.

No. Quite literally, it will be impossible, if not very difficult, to calculate an accurate speed.

(speed = distance ÷ time)

Hope this helped!

Source(s) used: My mind and a little bit of G*ogle as a refresher.

If acceleration, acceleration would be too fast in square metres. Therefore, this information equals the final minus initial divided by a, which is 15 m/s minus 5 m/s divided by 2 m/s squared. Five seconds are involved.

The three different forms of projectile motion are as follows: motion of a horizontal projectile. projectile motion that is oblique. Motion of a projectile on an incline

An item or particle that is thrown toward the surface of the Earth and moves along a curved route only under the influence of gravity is said to be experiencing projectile motion.

The movement of a falling item (projectile) after being assigned a forward beginning velocity The only forces affecting a projectile are gravity and air resistance. The ball travels along a curved route as a result of its initial forward velocity and the downward vertical pull of gravity.

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Answer:

b

Explanation:

there are 2 nitrogen and 1 oxygen, you can tell by the little number after the letter. if there is no number, then it's just one atom

Answer:

B.

Explanation:

I got it right on my test.

He travels a distance of 300 m in that time interval.

We know that we can be able to obtain the time that he travelled if we use the formula that applies to the average speed. In this case we are told in  a time of 30 seconds, he increases his speed steadily from 8.3 m/s to 11.7 m/s.

Thus;

distance = Average speed/Time

Distance = (8.3 + 11.7/2) * 30

Distance = 300 m

We can see that he would move through a distance of well about 300m as the velocity is increasing as shown here.

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The effective resistance of any circuit can be obtained by summing the individual resistance or taking the sum of their reciprocals.

The effective resistance of a circuit is calculated depending on the circuit arrangement.

For series circuit arrangement, the effective resistance is calculated as;

Re = R₁ + R₂ + R₃ + -----

Where;

For parallel circuit arrangement, the effective resistance is calculated as;

1/Re = 1/R₁ + 1/R₂ + 1/R₃

Where;

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A

Explanation:

The electrical signals were more accurate than optical semaphore signals.

The development of electrical signals sent through wires change communication as signals could be sent anywhere a wire could reach and no longer were restricted to line of sight.

Wired communication refers to the transmission of data over a wire-based communication technology.

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Correct option is:- C) Work is a measure of how much energy a force transfers.

Answer:A) 19.8 seconds

B) 467.5 metres

Explanation: 100km/hr = 27.78m/s

So, it covers 27.78 metres in one second

Take the time it would cover 550m as x

Therefore 27.78m = 1second

550m = x

Cross multiplying

27.78x = 550m

Divide both sides by the coefficient of x

x = 550÷27.78

x = 19.8seconds

B) distance = speed × time

Speed = 85km/hr = 23.61m/s

Time = 19.8seconds

Therefore,

Distance = 23.61 × 19.8

Distance = 467.5m

Cumulonimbus clouds often form along cold fronts, so heavy rain and thunderstorm is most likely to occur.

With the rise in the warm air above cold air and its fast condensation afterwards, is often why a lot of heavy rain is produced along a cold front. Also when the warm air keeps on rising in the atmosphere, the condensation process becomes more strong because the temperature drop becomes more significant and thunderstorms and hailstorms become more prominent with cold fronts.

Cumulonimbus clouds are formed due to the rise of the hot air above the cold air, by the means of convection. They also form due to forced convection along cold fronts, where milder air is forced to rise over the incoming cold air. Cumulonimbus clouds can be categorized into following 3 types :

Cumulonimbus calvus - the upper part of the cumulonimbus is puffy,

Cumulonimbus capillatus - the top part of the cloud is fibrous but relatively contained.

Cumulonimbus incus - the upper part of the cloud is fibrous and anvil-shaped.

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If the pressure gauge reads 31 psi and the atmospheric pressure is 15 psi, the real pressure of the air inside the tire is 16 psi. The pressure gauge measures the pressure inside the tire, so the reading of 31 psi represents the total pressure, which includes the atmospheric pressure.

The pressure gauge measures the pressure inside the tire, so the reading of 31 psi represents the total pressure, which includes the atmospheric pressure. To find the real pressure of the air inside the tire, we need to subtract the atmospheric pressure.
Given that the atmospheric pressure is 15 psi, we can subtract this value from the pressure gauge reading:
31 psi - 15 psi = 16 psi.
Therefore, the real pressure of the air inside the tire is 16 psi. This means that if the tire were removed from the gauge and measured independently, it would have a pressure of 16 psi.
It's important to note that the pressure gauge already accounts for the atmospheric pressure, so the reading on the gauge provides the total pressure inside the tire.
In summary, if the pressure gauge reads 31 psi and the atmospheric pressure is 15 psi, the real pressure of the air inside the tire is 16 psi.

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