A paper airplane is thrown horizontally with a velocity of 20 mph. The plane is in the air for 7.63 s before coming to a standstill on the ground. What is the acceleration of the plane?

To calculate the current in a circuit, we can use Ohm's Law, which states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R). So, in this case, the current would be:

I = V / R

I = 9.0V / 5.00 ohms

I = 1.8 A

So, 1.8 A of current would flow in a closed circuit that has a 9.0V battery and 5.00 total resistance.

Answer:

The horizontal range of the cannonball is 9180.4 meters.

Explanation:

The horizontal range of a cannonball can be calculated using the following formula:

range = (speed * speed * sin (2 * angle)) / acceleration due to gravity

In this case, we are given that the cannon is fired at an angle of 45 degrees and that the speed of the ball is 300 m/s. We can plug these values into the formula to calculate the horizontal range of the ball:

range = (300 * 300 * sin (2 * 45)) / 9.8

= (90000 * sin (90)) / 9.8

= (90000 * 1) / 9.8

= 9180.4 m

The energy of 25 kg object is moving at a velocity or 10 ml is 1250J.

KE = 1/2mv²

The mass is m = 25kg

The velocity is v = 10ms⁻¹

KE = 1/2 × 25 × 10²

⇒ KE = 1250J

Hence, Kinetic energy is 1250J

The energy an object has as a result of motion is known as kinetic energy. A force must be applied to an object in order to accelerate it. We must put in effort in order to apply a force. After the work is finished, energy is transferred to the item, which then moves at a new, constant speed.

The direction of a body or object's movement is defined by its velocity. In its basic form, speed is a scalar quantity. In essence, velocity is a vector quantity. It is the speed at which distance changes. It is the displacement change rate.

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Answer:

  74.7 m

Explanation:

You want the minimum radius of curvature of a vertical circular arc so that vehicles traveling 95 km/h making the transition from horizontal to an 18° down grade will not leave the road.

The acceleration due to gravity on the vehicle at the point it is traveling 18° down is ...

  g·cos(18°) ≈ (9.8 m/s²)·0.95106 ≈ 9.32 m/s²

The radius of an arc and the speed of travel are related to the normal acceleration by ...

  r = v²/a

where v is the speed along the arc, and 'a' is the normal acceleration required to make an object follow the circular curve.

The speed of 95 km/h can be translated to m/s by ...

  (95 km/h) · (1000 m/(1 km)) · (1 h)/(3600 s) = 95/3.6 m/s ≈ 26.389 m/s

Using the above relation to find the radius, we get ...

  r = (26.389 m/s)²/(9.32 m/s²) ≈ 74.72 m

The minimum radius of the vertical circular arc should be 74.7 meters to prevent vehicles from becoming airborne.

__

Additional comment

In actual roadway design, factors of sight distance and stopping distance come into play. Sight distance over this crest would be about 25 m. It would need to be more than 6 times that distance for the roadway to be safe at 95 km/h.

An 18° down grade is about 3 times the usual maximum for roadway design, which will severely increase stopping distance. The vertical arc described here would leave the car with no normal force on the roadway at the end of the arc, so braking would be impossible. Passengers would be feeling weightless, too.

Roadway curves are generally parabolic (not circular), so they have a constant rate of change of slope with horizontal distance.

Answer:

the principal energy level is d because electrons are 2 times more

A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.

To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).

The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:

E_initial = KE_initial + PE_initial

The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:

E_final = KE_final + PE_final

The nonconservative work done on the boy is equal to the change in mechanical energy:

Work_nonconservative = E_final - E_initial

Let's calculate each term:

KE_initial = (1/2) * m * v_initial^2

= (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = m * g * h_initial

= 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * m * v_final^2

= (1/2) * 66.1 kg * (8.51 m/s)^2

PE_final = m * g * h_final

= 66.1 kg * 9.8 m/s^2 * 0

Since the boy ends at ground level, the final potential energy is zero.

Substituting the values into the equation for nonconservative work:

Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)

Simplifying:

Work_nonconservative = KE_final - KE_initial - PE_initial

Calculating the values:

KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2

Substituting the values:

Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]

Calculating the result:

Work_nonconservative ≈ -42.7 kJ

Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.

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Answer:

C. The left wire attracts the right wire and exerts as much force as the right wire does.

Explanation:

To know what is the answer you first take into account the magnetic field generated by each current, for a distance of d:

\(B_1=\frac{\mu_oI_1}{2\pi d}=\frac{\mu_o}{2\pi d}(1A)\\\\B_2=\frac{\mu_oI_2}{2\pi d}=\frac{\mu_o}{2\pi d}(2A)=2B_1\\\\\)

Next, you use the formula for the magnetic force produced by the wires:

\(\vec{F_B}=I\vec{L}\ X \vec{B}\)

if the direction of the L vector is in +k direction, the first wire produced a magnetic field with direction +y, that is, +j and the second wire produced magnetic field with direction -y, that is, -j (this because the direction of the magnetic field is obtained by suing the right hand rule). Hence, the direction of the magnetic force on each wire, produced by the other one is:

\(\vec{F_{B1}}=I_1L\hat{k}\ X\ B_2(-\hat{j})=I_1LB_2\hat{i}=(2A^2)\frac{L\mu_o}{2\pi d}\hat{i}\\\\\vec{F_{B2}}=I_2L\hat{k}\ X\ B_2(\hat{j})=I_2LB_1\hat{i}=-(2A^2)\frac{L\mu_o}{2\pi d}\hat{i}\)

Hence, due to this result you have that:

C. The left wire attracts the right wire and exerts as much force as the right wire does.

Answer: I think the ans is A but I’m not sure.

Can someone check it and tell me I would like to know

The magnitude of the motor shaft's rotational velocity is used to describe a motor's speed.

The motor velocity of the supporting cable exists 18 ft/s.

A motor's speed is defined as the magnitude of the motor shaft's rotational velocity. The number of full rotations per unit of time for an axis rotation in a motion application depends on the motor's speed.

When given 11.1 V and a motor with a velocity constant and back EMF constant of 5,700 rpm/V, the motor will spin at a nominal speed of 63,270 rpm (= 5,700 rpm/V 11.1 V). The non-linear mechanical losses may prevent the motor from operating at this theoretical speed.

Motor velocity = Number of vertical strings × upward velocity

substitute the values in the above equation, we get

18 fp/s = 3 × 6

3 × 6 = 18 fp/s.

The motor velocity of the supporting cable exists 18 ft/s.

Therefore, the correct answer is option [D]. VP/H = 18 ft/s.

The complete question is:

If the hoist H is moving upward at 6 ft/s, determine the speed at which the motor M must draw in the supporting cable.

[A]. VP/H = 6 ft/s

[B]. VP/H = 2 ft/s

[C]. VP/H = 12 ft/s

[D]. VP/H = 18 ft/s

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D. :)

lmk if im right or wrong

Answer:

D. 5ºC

Explanation:

Not B, because 1k= -457.87 fahrenheit. That means it is also not C. Since the icicles are melting, then that means it is not A either.

5ºC=about 41ºF

Answer:

The first options is the ans(Circuit) it should have been electric circuit

Answer:

increases.

Explanation:

As a ball falls freely towards the ground, it's kinetic energy increases. If the kinetic energy increases, that means the object hasn't hit the bottom yet. If the ball continues to fall freely towards the ground, the air gives it more pressure, after that the pressure begins to increase.

Answer:

\(a_{c} = 13.46\ m/s^2\)

Explanation:

The motion of the tethered ball around the pole can be modeled as uniform circular motion. The acceleration of the objects executing uniform circular motion is due to the change in direction of their velocity. This is called centripetal acceleration. It is given by the following formula:

\(a_{c} = \frac{v^2}{r}\)

where,

ac = centripetal acceleration = ?

v = speed of ball = 3.5 m/s

r = distance of ball from center of rotation = 0.91 m

Using these values in equation, we get:

\(a_{c} = \frac{(3.5\ m/s)^2}{0.91\ m}\\\\a_{c} = 13.46\ m/s^2\)

Answer:

a) kinetic energy=0.5×mass×speed²

kinetic energy=0.5×2×10²=100 joules

Explanation:

im not sure about the rest :(

Answer:

a) 100J

b)20N

c) 100J

Explanation:

A) KE = 0.5 x mass x velocity^2

= 0.5 x 2 x 10^2

= 100 J

B) Work done = Force x distance

Since work done = energy transferred

Energy transferred = Force x Distance

Energy transferred/ Distance = Force

100/5 = 20 N

C) Let's assume that all the Kinetic energy of the subject get's transferred into heat energy

Therefore Kinetic energy = Heat energy = 100 J

Answer:

The proton has much greater mass

Explanation:

Answer:

D, a proton has a much greater mass.

Explanation:

An electron has a mass close to nothing.

Answer:

  163 N

Explanation:

The density of copper is about 8.96. The ratio of the weight in water to the weight in air is about 1-1/ρ, so is about 0.8884.

  0.8884 × 184 N ≈ 163 N

The submerged weight is about 163 N.

Answer:

yea

Explanation:

The angle I can rightly be called the angle of reflection.

The incident ray, the reflected ray, and the normal all reside on the same plane, according to the angles of reflection. This suggests that reflection may occur when two angles are in the same plane as the normal.

The angle I and depicted can appropriately be referred to as the angle of reflection in light of the aforementioned information.

Lastly, it is obvious from the image that angle I is the angle of reflection.

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Answer:

B)48°C

Explanation:

just is how it is. you know

Answer:

Current is inversely related to resistance.

Explanation:

Based on the given information, we can conclude that the relationship between current and resistance is inverse. This is because the graph is a downward curve, indicating that as resistance increases, current decreases, and vice versa.

In other words, when resistance is high, the flow of current is low, and when resistance is low, the flow of current is high. This inverse relationship between current and resistance is known as Ohm's Law, which states that the current flowing through a conductor is directly proportional to the voltage and inversely proportional to the resistance of the conductor.

Therefore, the best answer choice that describes the relationship between the two variables is:

Current is inversely related to resistance.

Answer:

B. Current is inversely related to resistance.

Explanation:

I took the physics exam

Answer:

\(T=326.928K\)

Explanation:

From the question we are told that:

Emissivity \(e=0.44\)

Absorptivity \(\alpha =0.3\)

Rate of solar Radiation \(R=0.3\)

Generally the equation for Surface absorbed energy is mathematically given by

 \(E=\alpha R\)

 \(E=0.3*950\)

 \(E=285W/m^2\)

Generally the equation for Emitted Radiation is mathematically given by

 \(\mu=e(\sigmaT^4)\)

Where

T=Temperature

 \(\sigma=5.67*10^8Wm^{-2}K_{-4}\)

Therefore

 \(\alpha*E=e \sigma T^4\)

 \(0.3*(950)=0.44(5.67*10^-8)T^4\)

 \(T=326.928K\)

The charge inside the cylinder is 15.81 N/C.

length ℓ = 10 m

radius R = 50 mm = 50 x 10^-3 m

volume charge density ρ = + 7.0 × 10^−9 C/m3.

the charge inside the cylinder Q = ρV

Where  V = Volume of the cylinder

             = πR^2 l

            = 3.1415 x (50x10^-3)^2(10)

            = 78.53 x10 -3 m^3

Therefore Q = (+ 7.0 × 10^−9 C/m^3)( 78.53 x10^-3 m^3)

               = 5.4971 x10^-10 C

The electric field magnitude at r = 40 mm, where r is the radial distance from the long central axis of the cylinder

  E = ρr/ε _{o}

Where ε _{o} = permitivity of free space = 8.85 x10^-12 C^2/Nm^2

          r = 40 mm = 40 x10^-3 m

Substitute values you get ,

 E = (7 x10^-9 )(40x10^-3 ) /[2 x8.85 x10^-12 ]

    = 15.81 N/C

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The earth-atmosphere energy balance is achieved as the energy from the Sun is the same as the energy lost by the Earth. Thus, the correct option is C.

The Earth-atmosphere energy balance refers to the balance between the energy the Earth receives from the sun and the energy the Earth radiates back into space.

The earth-atmosphere energy balance is achieved as the energy received from the Sun balances the energy lost by the Earth's surface back into space. Through this mechanism, the Earth maintains a stable average temperature and therefore also a stable climate on the planet.

Therefore, the correct option is C.

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Answer:

420J

Explanation:

The formula (useful output ÷ total output) × 100 is used. We need to find the the useful output. So:

(useful ÷ 600) × 100 = 70(%)

We rearrange the formula so that 'useful' is the subject of the equation.

useful ÷ 600 = 0.7 {70 ÷ 100}

useful = 0.7 × 600

useful = 420J

The speed of the water jet emerging from the nozzle with a water density of 1000 kg/m³ is 30.107 m/s.

Speed can be defined as the rate of change in the distance of an object. It is a scalar quantity due to only magnitude and no direction.

Height = 3.3 m

Diameter = 2.03 inch

Gauge pressure = 450.228 kPa

We need to calculate the speed of the water jet emerging from the nozzle

Using Bernoulli's equation,

1/2ρ(Vn² - Vp²) = P gauge - ρgh

(Vn² - Vp²) = (2/P) Pgauge - 2gh

Vn² - (An/ Ap)²Vn² = (2/P) Pgauge - 2gh

Vn² - (rn/ rp)⁴Vn² = (2/P) Pgauge - 2gh

Vn² = \(\sqrt{(2/P) Pgauge - 2gh/ (1- (rn/ rp)^4)}\)

Vn = \(\sqrt{[((2/1000)(450.228 X 10^3)) - 2 X 9.8 X 3.3]/ 1 - (1.01/ 1.91)^4}\)

Vn = \(\sqrt{(2 X 450.228 - 64.68)/ 1- (1.04/ 13.30)}\)

Vn = \(\sqrt{(900.45 - 64.68)/ (13.30- 1.04)/13.30}\)

Vn = \(\sqrt{(835.776)/ (12.26/ 13.30)}\)

Vn = \(\sqrt{(835.776)/ 0.922}\)

Vn = \(\sqrt{906.48}\)

Vn = 30.107 m/s

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Answer:

19 protons, 20 neutrons and 18 electrons.

Explanation:

The atomic number gives the number of protons 19

p

=

19

The atomic mass is the sum of the protons and neutrons

p

+

n

=

39

p

=

19

put p into the equation and solve for n the neutrons.

19

+

n

=

39

Subtract 19 from both sides

19

−

19

+

n

=

39

−

19

n

=

20

The number of electrons equals the number of protons in a neutral atom. The positive charge equals the negative charge. The negative charge is the number of electrons. This ion has a charge of +1. So solve for the negative charge.

−

19

+

1

=

−

18

The negative charge is -18 so

e

=

18

The buoyant force can be determined by subtracting the apparent weight of the object in water from its weight in air. In this case, the buoyant force would be 7N - 4N = 3N.

Based on the information provided, since the buoyant force (3N) is less than the weight of the object (7N), the object will not float.

Floating occurs when the buoyant force is greater than or equal to the weight of the object.

In this scenario, the object will experience a net downward force, indicating that it will sink rather than float in water.

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Answer:

They oscillates perpendicularly to one another, the oscillation of one field generates the other field.

Explanation:

In a light wave, an oscillating electric field of a light wave produces a magnetic field, and the magnetic field also oscillates to produce an electric field. The magnetic field and the electric field of a light wave both oscillates perpendicularly to one another. The resultant energy and direction of the wave generated as a result of these oscillating fields is propagated perpendicularly to both fields.

The best example of Newton's third law of motion is, When a passenger stepped from a boat to the shore, the boat moved away from the shore. Thus, option C is correct.

Sir Issac Newton gives three laws of motion. The first law states that an object remains at rest or in continuous motion unless an external force acted on it. The second law stated that the force is directly proportional to the acceleration of the object. Newton's third law states that, for every action, there is an equal and opposite reaction.

From the given, Newton's third law is applicable, When a passenger stepped from a boat to the shore, the boat moved away from the shore. This shows the action and reaction of the boat and shore.

Thus, the ideal solution is option C.

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