A new bank customer with $3,500 wants to open a money market account. The bank is offering a
simple interest rate of 1.1%.
a. How much interest will the customer earn in 10 years?
b. What will the account balance be after 10 years?

Answer:

The correct answer is (C)

Step-by-step explanation:

answer on edge test

The equation showing (-10,8) being used in writing the line in the point-slope form will be y-8= -0.2(x+10) where 0.2 is the slope and (-10,8) is the point.

The equation of straight line passing through two points (x1,y1), (x2,y2) will be calculated as

(y-y1)/(x-x1)= m, where m is the slope of staright line and

m=  (y2-y1)/(x2-x1)

where (x1,y1), (x2,y2) are the coordinates of the two points passing through the line.

Here are given in the table are the points which are satisfying the linear equation.

Using two points from the table (-10,8) and (-5,7)

where x1= -10      y1=8

x2= -5       y2=7

m= (y2-y1) / (x2-x1)= (7-8) / (-5-(-10))= (-1)/(-5+10) =(-1)/5= -0.2

So now using the point of coordinate (-10,8)

(y-y1)/(x-x1)= m

⇒(y-y1)/(x-x1)= -0.2

⇒ (y-8)/(x-(-10)) =-0.2

⇒(y-8)/(x+10) =0.2

⇒y-8= -0.2(x+10)

⇒y=-0.2x-2+8

⇒y= -0.2x+6

Therefore the equation showing (-10,8) being used in writing the line in the point-slope form will be y-8= -0.2(x+10) where 0.2 is the slope and (-10,8) is the point.

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Using Naïve Bayes multinomial with alpha=1, we classify the given messages based on their content. Message 4, "Tokyo Japan Chinese," is classified as spam.

To classify the messages using Naïve Bayes multinomial, we consider the content of the messages and their corresponding classifications. We calculate the probabilities of each message belonging to the "Normal" or "Spam" classes.

3 messages are classified as "Normal."

1 message is classified as "Spam."

We calculate the probabilities as follows:

P(Class = Normal) = 3/4 = 0.75

P(Class = Spam) = 1/4 = 0.25

Next, we analyze the occurrence of words in each class:

For the "Normal" class:

The word "Chinese" appears 5 times.

The word "Beijing" appears 1 time.

The word "Shanghai" appears 1 time.

The word "Macao" appears 1 time.

For the "Spam" class:

The word "Tokyo" appears 1 time.

The word "Japan" appears 1 time.

The word "Chinese" appears 1 time.

Now, we calculate the probabilities of each word given the class using Laplace smoothing (alpha=1):

P(Chinese|Normal) = (5 + 1)/(5 + 4) = 6/9

P(Beijing|Normal) = (1 + 1)/(5 + 4) = 2/9

P(Shanghai|Normal) = (1 + 1)/(5 + 4) = 2/9

P(Macao|Normal) = (1 + 1)/(5 + 4) = 2/9

P(Tokyo|Spam) = (1 + 1)/(3 + 4) = 2/7

P(Japan|Spam) = (1 + 1)/(3 + 4) = 2/7

P(Chinese|Spam) = (1 + 1)/(3 + 4) = 2/7

To classify Message 4, "Tokyo Japan Chinese," we compute the probabilities for each class:

P(Normal|Message 4) = P(Chinese|Normal) * P(Tokyo|Normal) * P(Japan|Normal) * P(Class = Normal)

≈ (6/9) * (0/9) * (0/9) * 0.75

= 0

P(Spam|Message 4) = P(Chinese|Spam) * P(Tokyo|Spam) * P(Japan|Spam) * P(Class = Spam)

≈ (2/7) * (2/7) * (2/7) * 0.25

≈ 0.017

Since P(Spam|Message 4) > P(Normal|Message 4), we classify Message 4 as spam.

In summary, using Naïve Bayes multinomial with alpha=1, we classify Message 4, "Tokyo Japan Chinese," as spam based on its content.

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Using Naïve Bayes multinomial with alpha=1, we classify the given messages based on their content. Message 4, "Tokyo Japan Chinese," is classified as spam.

To classify the messages using Naïve Bayes multinomial, we consider the content of the messages and their corresponding classifications. We calculate the probabilities of each message belonging to the "Normal" or "Spam" classes.

3 messages are classified as "Normal."

1 message is classified as "Spam."

We calculate the probabilities as follows:

P(Class = Normal) = 3/4 = 0.75

P(Class = Spam) = 1/4 = 0.25

Next, we analyze the occurrence of words in each class:

For the "Normal" class:

The word "Chinese" appears 5 times.

The word "Beijing" appears 1 time.

The word "Shanghai" appears 1 time.

The word "Macao" appears 1 time.

For the "Spam" class:

The word "Tokyo" appears 1 time.

The word "Japan" appears 1 time.

The word "Chinese" appears 1 time.

Now, we calculate the probabilities of each word given the class using Laplace smoothing (alpha=1):

P(Chinese|Normal) = (5 + 1)/(5 + 4) = 6/9

P(Beijing|Normal) = (1 + 1)/(5 + 4) = 2/9

P(Shanghai|Normal) = (1 + 1)/(5 + 4) = 2/9

P(Macao|Normal) = (1 + 1)/(5 + 4) = 2/9

P(Tokyo|Spam) = (1 + 1)/(3 + 4) = 2/7

P(Japan|Spam) = (1 + 1)/(3 + 4) = 2/7

P(Chinese|Spam) = (1 + 1)/(3 + 4) = 2/7

To classify Message 4, "Tokyo Japan Chinese," we compute the probabilities for each class:

P(Normal|Message 4) = P(Chinese|Normal) * P(Tokyo|Normal) * P(Japan|Normal) * P(Class = Normal)

≈ (6/9) * (0/9) * (0/9) * 0.75

= 0

P(Spam|Message 4) = P(Chinese|Spam) * P(Tokyo|Spam) * P(Japan|Spam) * P(Class = Spam)

≈ (2/7) * (2/7) * (2/7) * 0.25

≈ 0.017

Since P(Spam|Message 4) > P(Normal|Message 4), we classify Message 4 as spam.

In summary, using Naïve Bayes multinomial with alpha=1, we classify Message 4, "Tokyo Japan Chinese," as spam based on its content.

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Answer:

please see photo attached for detailed analysis.

Answer:

The definition of Acre is a unit of land area equal to 4,840 square yards (0.405 hectare). :)

Step-by-step explanation:

Answer:

a unit of land area equal to 4,840 square yards

Step-by-step explanation:

Problem

Solution

For this case we can do the following:

We also know that :

Using this property we got:

Now we can distirbute the terms and we got:

4+7i -8 -36 i

And distributing the terms we got:

(7-36)i +(4-8)

-29 i -4

And then our solution would be:

a= -29

b= -4

The surface area of this locker is 432 square centimeters .

The right rectangular prism shown in the figure has dimensions 8 cm (length) x 6 cm (width) x 12 cm (height).

1. The top and bottom faces are both rectangles with dimensions 8 cm (length) x 6 cm (width). The area of each face is:

A = length x width = 8 x 6 = 48 cm²

Since there are two of these faces, the total area is:

2 x 48 = 96 cm²

2. The front and back faces are also rectangles with dimensions 8 cm (length) x 12 cm (height). The area of each face is:

A = length x height = 8 x 12 = 96 cm²

the total area is:

2 x 96 = 192 cm²

3. The left and right faces are rectangles with dimensions 6 cm (width) x 12 cm (height). The area of each face is:

A = width x height = 6 x 12 = 72 cm²

the total area is:

2 x 72 = 144 cm²

4. Therefore, the total surface area of the locker is the sum of all the faces:

Total surface area = 96 + 192 + 144 = 432 cm²

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The speed of car moving towards south exists 15 mph and, speed of (as moving towards East = 25 mph.

They are referred to be intersecting lines when two or more lines in a plane cross each other. The point of intersection, which can be found on all intersecting lines, is the common point shared by the intersecting lines.

Let speed of Car 1 = x mph

Speed of car 2 = (x + 10) mph

Hence,

OA = Distance travelled by car2 in 2 hours

⇒ OA = (x + 10) × 2 = 2x + 20

And, OB = Distance travelled by Car 1 in 2 hours

⇒ OB = x × 2 = 2 x

Now, In ΔOAB, OA² + OB² = AB²

substitute the values in the above equation

⇒  (2 x+20)² + (2 x)² = \((10 \sqrt{34})^2 \\\)

⇒  4x² + 400 + 80x + 4x² = 3400

simplifying the equation

⇒ 8x² + 20x - 3000 = 0

⇒ x² + 10x - 375 = 0

⇒ x² + 25x - 15x - 375 = 0

simplifying the above equation, we get

⇒ x(x + 25) - 15(x + 25) = 0

⇒ (x + 25)(x - 15) = 0

⇒ x + 25 = 0, x - 15 = 0

⇒ x = -25, x = 15

Since speed can not be negative.

Hence, x = 15 mph

⇒ x + 10 = 15 + 10 = 25 mph.

Hence, speed of car moving towards south =15 mph.

And, speed of (as moving towards East = 25 mph.

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The speed of car moving towards south exists 15 mph and, speed of (as moving towards East = 25 mph.

When two or more lines in a plane cross one another, they are referred to as intersecting lines. The common point shared by all intersecting lines is the point of intersection, which can be found on all of them.

The distance travelled in relation to the time it took to travel that distance is how speed is defined. Since speed simply has a direction and no magnitude, it is a scalar quantity.

Let speed of Car 1 = x mph

Speed of car 2 = (x + 10) mph

Hence,

OA = Distance travelled by car2 in 2 hours

⇒ OA = (x + 10) × 2 = 2x + 20

And, OB = Distance travelled by Car 1 in 2 hours

⇒ OB = x × 2 = 2 x

Now, In ΔOAB, OA² + OB² = AB²

substitute the values in the above equation

⇒  (2 x+20)² + (2 x)² =

⇒  4x² + 400 + 80x + 4x² = 3400

simplifying the equation

⇒ 8x² + 20x - 3000 = 0

⇒ x² + 10x - 375 = 0

⇒ x² + 25x - 15x - 375 = 0

simplifying the above equation, we get

⇒ x(x + 25) - 15(x + 25) = 0

⇒ (x + 25)(x - 15) = 0

⇒ x + 25 = 0, x - 15 = 0

⇒ x = -25, x = 15

Since speed can not be negative.

Hence, x = 15 mph

⇒ x + 10 = 15 + 10 = 25 mph.

Hence, speed of car moving towards south =15 mph.

And, speed of (as moving towards East = 25 mph.

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Answer:

(0, 4)

Step-by-step explanation:

Hi there!

We are given the following systems of equations:

x=8-2y

y-x=4

And we want to solve it by substitution

When we solve an equation by substitution, we solve for one of the variables in one of the expressions, which should be an expression containing the other variable, then we substitute that expression as the variable we solved for into the other expression  to find the value of that variable, then use the value of the solved variable to find the value of the other variable.

In this case, we already have x solved in the first equation; x is equal to 8-2y.

We can substitute that as x in y-x=4 to solve for y.

y-(8-2y)=4

Subtract

y-8+2y=4
Combine like terms

3y-8=4

Add 8 to both sides
3y=12

Divide both sides by 3

y=4

Substitute 4 as y into x=8-2y to solve for x.

x=8-2(4)

x=8-8

x=0

The solution is x=0, y=4, or as a point,  (0, 4)

Hope this helps!

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The simplified version of the equation 32x + 8 - 34x is   -2x +8

Given that,

The equation is 32x + 8 - 34x

To find : The simplified version of 32x + 8 - 34x ?

Since the terms involving x are "like" terms, when the terms are joined, their coefficients are added.

= 32x -34x +8

= (32 -34)x +8 . . . . . x is factored out according to the distributive property

= -2x +8

Therefore, the simplified version of 32x + 8 - 34x is given as  -2x +8

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Answer:

well if theres 26 in all and 15 girls then there is 11 boys so the answer is

11:15

brainliest please

Step-by-step explanation:

Answer:

11:15

Step-by-step explanation:

First let us find the number of boys in the classroom:

26 total students - 15 girls = 11 boys

Now, we can write the ration:

11 (boys): 15(girls)

So, 11:15

I hope this helps! :)

Answer:

point B

Step-by-step explanation:

hope this helps.

Answer:

5,184 from my knowledge

Answer:

The answer might be d.

Answer:

1/10

Step-by-step explanation:

\(-\frac{1}{4} * -\frac{2}{5}\\\\= \frac{2}{20}\\\\=\frac{1}{10}\)

Feel free to mark this as brainliest! :D

I'm positive it's guide reflection by reflecting on (-6 -1) to LNM is then moving it to ABC making it guide reflection

Answer:

53

Step-by-step explanation:

58÷1.095= 53 is the answer

Answer:

5.03196347032

Step-by-step explanation:

We do:

.095x+x=58

1.095x=58

x=52.96

52.96 is a approximation and when you do the math and see what  9.5 of 52.96 plus 52.96 is you get 57.9912 which is super close to 8 The exact answer is x = 5.03196347032

The Trapezoidal rule (approximation of 8) and Simpson's rule (approximation of 4) indicate that f(1) is equal to 0.

Let's solve for f(1) by comparing the equations from the Trapezoidal rule and Simpson's rule.

Using the Trapezoidal rule:
8 ≈ (2-0)/2 * [f(0) + 2f(1) + f(2)]
8 ≈ 1 * [f(0) + 2f(1) + f(2)]
8 ≈ f(0) + 2f(1) + f(2)

Using Simpson's rule:
4 ≈ (2-0)/6 * [f(0) + 4f(1) + f(2)]
4 ≈ 1/3 * [f(0) + 4f(1) + f(2)]
4 ≈ f(0)/3 + 4f(1)/3 + f(2)/3

Comparing the coefficients of f(1) in both equations, we have:
2f(1) = 4f(1)/3
2f(1) - 4f(1)/3 = 0
(6/3)f(1) - (4/3)f(1) = 0
(2/3)f(1) = 0
f(1) = 0

Therefore, the value of f(1) is 0 based on the given approximations from the Trapezoidal rule and Simpson's rule.

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Answer: 24

Step-by-step explanation:

t=seconds. h=height

t=3

h=3+55t-16t^2

h=3+55(3)-16(3)^2

h=3+165-16*9

h=168-144

h=24 ft

The ball's height 3 seconds after it was kicked is 24 feet above the ground.

Given that a formula h = 3 + 55t-16t² describes a ball's height above the ground h, which has been kicked vertically upward from a height of 3 feet with an initial speed of 55 feet per second.

We need to find the height of the ball after 3 seconds.

To find the ball's height 3 seconds after it was kicked, we can use the formula provided:

h = 3 + 55t - 16t²

where h represents the height in feet and t represents the time in seconds.

To find the height after 3 seconds (t = 3), plug the value into the formula and calculate:

h = 3 + 55(3) - 16(3)²

Now, perform the calculations step by step:

h = 3 + 55(3) - 16(9)

h = 3 + 165 - 144

h = 24 feet

Hence the required height is 24 feet.

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Answer:

70 miles

Step-by-step explanation:

30 (mi) +40 (mi) =70

Sulfhuric acid, boric acid and vinegar have 7 atoms present in them

To find the compounds with equal number of atoms, we must take each individual atoms and find how many atoms are present in them.

In the first compound, we have sulfuric acid.

\(H_2SO_4 = 7 atoms\\\)

Second compound, we have phosphoric acid

\(H_3PO_4 = 8 atoms\)

Third compound, we have vinegar

\(C_2H_3O_2 = 7 atoms\)

Fourth compound, we have boric acid

\(H_3BO_3 = 7 atoms\)

From the above, only sulfuric acid, vinegar and boric acid have equal number of atoms present in them.

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Answer:

132 degrees

Step-by-step explanation:

the angles of measure 2 and 3 have to add up to 180 degrees (because that's the angle of a straight line, which 2 and 3 make together)

180-48=132

Answer:

I dont understand there is no equation to solve or any math at all

Answer:

0/6

Step-by-step explanation:

Hope this helps I'm just typing rn bc it says it needs to be longer

The number of white rabbits that are at the farm is 60

From the question, we are to determine the number of white rabbits that are at the farm

From the given information,

There are 210 rabbits at the farm

and

For every 5 gray rabbits, there are 2 white rabbits

Then, we can write that

5x + 2x = 210

Where x is the number of groups of 5 gray rabbits and 2 white rabbits

Then,

7x = 210

x = 210/7

x = 30

The number of white rabbits is 2x

∴ Number of white rabbits = 2×30

Number of white rabbits = 60

Hence, the number of white rabbits that are at the farm is 60

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Answer:

this is the answer please give brainliest