A mass of a spring vibrates in simple harmonic motion at a frequency of 8.0 Hz and an amplitude of 3.9 cm. If a timer is started with its displacement is a maximum, what is the speed of the mass when the timer reads 3 seconds

Answers

Answer 1

Answer:

 e = 50.27 give / s

Explanation:

The expression for simple harmonic motion is

    x = A cos (wt + Ф)

in this case they give us the amplitude A = 3.9 cm and frequency f = 8.0 Hz

The angular and linФear variables are related

      e = 2π d

      e = 2π 8

      e = 50.27 give / s

let's look for the constant fi

       so let's find the time to have the maximum displacement

       v = dx / dt

       v = -A w sin (wt +Ф)

for the point of maximum displacement the speed is I think

        0 = - sin (0 + Ф)

therefore fi = 0

Let's put together the equation of motion

          x = 0.039 sin (50.27 t)

          v = 0.039 50.27 sin (50.27 3)

           v = 1.96 50 0.01355

            v = 0.0266 m / s


Related Questions

Chemical bonds are broken in which molecules? Question 1 options: C6H12O6 & H2O CO2 & O2 O2 & C6H12O6 CO2 & H2O

Answers

Answer:O2 & C6H12O6

Explanation:

C6H12O6 + 6O2-> 6CO2 + 6H2O

O2 and C6H12O6 molecules' chemical connections are disrupted.

What is chemical bond?A chemical bond, which is a powerful attraction between atoms, ions, or molecules, enables the construction of molecules. The connection could be brought on by electrostatic force.

Overview of the fundamental types of... Bonds in chemical formula solid chemical ties. Covalent or ionic bonds are two different types of chemical bonding.

A chemical bond is an attraction between two atoms or ions. To form bonds, atoms exchange or swap their valence electrons. Atoms need to form chemical bonds in order to attain a complete outer energy level, which is the most stable arrangement of electrons.

A chemical bond is the binding force that binds various constituents (atoms, ions, etc.) in diverse chemical species.

         C6H12O6 + 6O2-> 6CO2 + 6H2O

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The gauge pressure in a balloon in measured by means of an open-tube manometer that uses water (density=1.00×103 kg/m3) . What gauge pressure is indicated by a difference of 0.0171 m in the heights of the water columns?

Answers

The gauge pressure in the balloon as indicated by a difference of 0.0171 m in the heights of the water columns is 167.58 Pa.

Gauge pressure of the balloon

The gauge pressure in the balloon is the pressure inside the balloon due to the water columns relative to the atmospheric pressure.

The gauge pressure in the balloon as indicated by a difference of 0.0171 m in the heights of the water columns is calculated as follows;

P = ρgΔh

P = (1,000)(9.8)(0.0171)

P = 167.58 Pa

Thus, the gauge pressure in the balloon as indicated by a difference of 0.0171 m in the heights of the water columns is 167.58 Pa.

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If the coefficient of kinetic friction between a crate and the floor is 0.20,
how much force is needed to slide a 92 kg crate uniformly across the floor?

Answers

Answer:

0.3 newtons

Explanation:

If the coefficient of kinetic friction between a crate and the floor is 0.20, then the fore needed to slide a 92 kg crate uniformly across the floor would be 180.504 N

What is friction?

Friction is a type of force that resists or prevents the relative motion of two physical objects when their surfaces come in contact.

The friction force prevents any two surfaces of objects from easily sliding over each other or slipping across one another. It depends upon the force applied to the object.

As given in the problem If the coefficient of kinetic friction between a crate and the floor is 0.20

The force needed = μN

where μ is the coefficient of the kinetic friction

μ =0.2

N is the normal force

N = mg

N = 92×9.81 N

Force needed to slide = 0.20× 92×9.81

                                     =180.504 N

Thus, The force needed to slide a 92 kg crate uniformly across the floor would be 180.504 N

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Find the period of a pendulum that has a length of .6m and is on earth. Make sure that you show your work and prominently display the equation that you use to solve it.

Answers

Answer:

The period of this pendulum is \(T=1.55\: s\)

Explanation:

The equation of motion of a pendulum is given by:

\(\frac{d\theta^{2}}{dt^{2}}+\frac{g}{L}sin(\theta)=0\) (1)

Where:

θ is the angle of motion

g is the gravity at the earth surface (9.81 m/s²)

L is the length of the pendulum (0.6 m)

Now, using equation (1) we can find the square angular frequency (ω), it will be:

\(\omega^{2}=\frac{g}{L}\)

\(\omega=\sqrt{\frac{g}{L}}\)

Let's recall that the angular frequency is \(\omega=\frac{2\pi}{T}\), then the period will be:

\(T=\frac{2\pi}{\omega}\)  

\(T={2\pi}\sqrt{\frac{L}{g}\)

\(T=2\pi}\sqrt{\frac{0.6}{9.81}\)

Therefore, the period of this pendulum is \(T=1.55\: s\)

I hope it helps you!

what is the electric field due to a point charge of 20uC at a distance of 1 meter away from it?

Answers

The electric field due to a point charge of 20uC at a distance of 1 meter away from it is 180000 \(\frac{N}{C}\).

First, you have to know that the space surrounding a load suffers some kind of disturbance, since a load located in that space will suffer a force. The disturbance that this charge creates around it is called an electric field.

In other words, an electric field exists in a certain region of space if, when introducing a charge called witness charge or test charge, it undergoes the action of an electric force.

The electric field E created by the point charge q at any point P, located at a distance r, is defined as:

\(E=K\frac{q}{r^{2} }\)

where K is the constant of Coulomb's law.

In this case, you know:

K= 9×10⁹\(\frac{Nm^{2} }{C^{2} }\)q= 20 uC=20×10⁻⁶ Cr= 1 m

Replacing in the definition of electric field:

\(E=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{20x10^{-6} C}{(1 m)^{2} }\)

Solving:

E=180000 \(\frac{N}{C}\)

Finally, the electric field due to a point charge of 20uC at a distance of 1 meter away from it is 180000 \(\frac{N}{C}\).

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How could a change in straight line motion due to unbalanced forces be predicted from an understanding of inertia?

Answers

Answer:

If the force goes in the direction of movement, the speed must increase and if the net force goes in the opposite direction, the speed must decrease.

Explanation:

The principle of inertia or Newton's first law states that every body remains static or with constant velocity if there is no net force acting on it.

Based on this principle, if we have a net force, the velocity of the body changes by having an unbalanced force acting.

If the force goes in the direction of movement, the speed must increase and if the net force goes in the opposite direction, the speed must decrease.

QUESTION 1
The two human thighbones (femurs) each have a cross-sectional area of 10 cm and they support
the upper part of a human body of mass 40kg. Calculate the average pressure sustained by each of
the femurs. (1mk)​

Answers

Answer:

2 * 10^5 pa

Explanation:

Pressure = Force / Area

Each thigh bone has a cross sectional area of 10cm²

Both thigh bones :

2 * 10cm² = 20cm²

To m² : 20 * (0.01)²

20 * 0.0001 m² = 0.002 m²

Force = mass * acceleration due to gravity(g)

g = 10m/s² ;

Force = 40 * 10 = 400N

Pressure = 400 N / 0.002 m²

Pressure = 200,000 N/m² = 2 * 10^5 pascal

Question 17 of 25
You place a book on top of a spring and push down, compressing the spring
by 10 cm. When you let go of the book, it is pushed up by the spring. Which
statement describes what happens to the energy of the spring-book system?
A. The kinetic energy of the system decreases.
B. The elastic potential energy of the system increases.
C. The gravitational potential energy of the system decreases.
D. The total energy of the system remains constant.

Answers

When you compress the spring by 10 cm, you are doing work on the system, which increases the elastic potential energy of the spring-book system. When you let go of the book, the spring expands and releases the stored potential energy, which is converted back into kinetic energy of the book as it is pushed up. Therefore, the answer is:

B. The elastic potential energy of the system increases.

An object is traveling with a constant speed of 35 m/s. How long does it take to cover 770 m?

Answers

Answer:

22 s

Explanation:

time = distance / velocity

We know that distance = 770 m and velocity = 35 m/s.

t = d / v

t = 770 m / 35 m/s

t = 22 s

It takes 22 seconds to cover 770 m. Hope this helps, thank you !!

478 J of work must be done to compress a gas to half its initial volume at constant temperature. How much work must be done to compress the gas by a factor of 12.0, starting from its initial volume?

I was thinking of using PV = W formula. Like

478 = P(V/2)
956 = PV

W = P(V/12)
12W/V = P
956 = (12W/V)(V)
956 = 12W
W = 79.66667 J

is this correct? could someone please help?

Answers

Answer:

Explanation:

I don't think so. Think about it. To compress the volume by a factor of 2 it takes 956 Joules.

Now you come along and you want to get the pressure for 1/12 of the volume. It's going to take a huge pressure to do that.

I would suggest that you have to use a modified form of the formula.

PV = 956

You need to compress the volume by 1/6

P(V/6) = 956

6 * PV/6 = 6 * 956

PV = 5736 J

Why did I only take 1/6? Because. 956 represents the pressure needed for 1/2 the volume. You need to multiply 1/2 * 1/6 to get 1/12

An electrical circuit has a courent of 13A and 26 Ohm of resistance. What is voltage using the Ohm's law​

Answers

The voltage in the circuit is 338 Volts.

Ohm's law states that the voltage (V) in a circuit is equal to the current (I) multiplied by the resistance (R): V = I x R.

1. Identify the given values: In this problem, we are given the current (I) and resistance (R) in the circuit.

2. Recall Ohm's law:  V = I x R.

3. Substitute the given values: We can substitute the given values of current (I = 13A) and resistance (R = 26 Ohm) into Ohm's law to find the voltage (V).

4. Calculate the voltage: Using the equation V = I x R and substituting the values of current and resistance, we can calculate the voltage as V = 13A x 26 Ohm = 338 Volts.

Therefore,  The voltage in the circuit is 338 Volts.

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Mr. Bateman creates a standing wave in the front of the classroom with the spring. S nodes form. The distance from Mr. Bateman to the cabinet is 6m. If a student times the spring moving back and forth and gets 0.2s for one cycle of the spring, how fast are the
waves moving?

Answers

Answer:

The speed of a wave is equal to the wavelength divided by the period. The wavelength is the distance between two consecutive nodes, and the period is the time it takes for one complete cycle of the wave.

In this case, the wavelength is 6 m and the period is 0.2 s. Therefore, the speed of the wave is 30 m/s.

The answer is 30 m/s.

Explanation:

You are raising up a big bucket of water from a 25.9 m deep well. The combined mass of the water and the bucket is 13.9 kg. The bucket is attached to a heavy duty steel chain. The mass of the chain is 19.3 kg.
How much work do you perform during the lifting process?

8427 J is Incorrect.

If it takes 1.75 minutes for you to raise the bucket of water out of the well, then what was your average power?

80.25 W is Incorrect.

Answers

The total work done is  5980 Joules and the power expended is 57 Watts.

What is work done?

The work done is the work done in the gravitational field as the bucket is raised up Thus work required to remove the bucket Wb;

Wb = 13.9 kg * 25.9 m * 9.8 m/s^2 = 3530 Joules

Height of the center of mass of chain = 25.9 / 2 = 12.95 m  

Work done by the chain Wc;

Wc = 12.95 * 19.3 * 9.8 = 2450 Joules  

Total work = 3530 + 2450 = 5980 Joules

Power expended = W / t = 5980 J / 105 sec = 57 J/s = 57 Watts

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Which law of thermodynamics does each of the following scenarios violate (if any)?

A machine that pulls all thermal energy out of a refrigerated space
1.
The first law of thermodynamics
2.
The second law of thermodynamics
3.
The third law of thermodynamics
4.
It is allowed


A machine that can pull 1000J of heat out of a refrigerated space and into a warmer space without external work
1.
The first law of thermodynamics
2.
The second law of thermodynamics
3.
The third law of thermodynamics
4.
It is allowed

A machine that can turn 1000J of heat directly into 1000J of electricity
1.
The first law of thermodynamics
2.
The second law of thermodynamics
3.
The third law of thermodynamics
4.
It is allowed

A machine that can create 1000J of heat from 100J of electricity
1.
The first law of thermodynamics
2.
The second law of thermodynamics
3.
The third law of thermodynamics
4.
It is allowed

A machine that can pull 1000J of heat out of a refrigerated space and put 1500J of heat into a warmer space if it uses 500J of external work

1.
The first law of thermodynamics
2.
The second law of thermodynamics
3.
The third law of thermodynamics
4.
It is allowed

Answers

Below are the required answers and explanations for each of the scenarios listed.

1. A machine that pulls all thermal energy out of a refrigerated space: This violates the second law of thermodynamics. This is because the second law of thermodynamics states that no heat engine can have an efficiency of 100 percent, and no heat transfer can occur from a colder to a warmer object without external work being done.

2. A machine that can pull 1000J of heat out of a refrigerated space and into a warmer space without external work: This violates the second law of thermodynamics. The second law of thermodynamics states that no heat transfer can occur from a colder to a warmer object without external work being done.

3. A machine that can turn 1000J of heat directly into 1000J of electricity: This does not violate any of the laws of thermodynamics.

4. A machine that can create 1000J of heat from 100J of electricity: This does not violate any of the laws of thermodynamics.

5. A machine that can pull 1000J of heat out of a refrigerated space and put 1500J of heat into a warmer space if it uses 500J of external work: This does not violate any of the laws of thermodynamics.

a) Option 2 is correct answer.

b) Option  2 is correct answer.

c) Option 4 is correct answer.

d) Option 4 is correct answer

e) Option 4 is correct answer.

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Draw vectors 9 and 10. (this is the answer key i just need them drawn)

Draw vectors 9 and 10. (this is the answer key i just need them drawn)

Answers

The net force acting on the skier is 76.4 N

The net force acting on the steel beam is 10 N.

The net force acting on the treasure chest is 5 N.

a) Angle of inclination of the inclined plane, θ = 15°

Weight of the skier, W = 490 N

Normal force acting on the skier, N = 473 N

Force of friction acting on the skier, f = 50 N

The net force acting on the skier is,

F = W sinθ - f

F = (490 x sin 15°) - 50

F = (490 x 0.258) - 50

F = 126.42 - 50

F = 76.42 N

b) The upward force acting on the steel beam, F = 80 N

Weight of the steel beam, W = 70 N

The net force acting on the steel beam,

F' = F - W

F' = 80 - 70

F' = 10 N

The net force is acting upwards.

c) Force acting on the treasure chest towards north, F₁ = 10 N

Force acting towards the west, F₂ = 4 N

Force acting towards the south, F₃ = 13 N

The resultant force of F₁ and F₃ is,

F₄ = F₃ - F₁

F₄ = 13 - 10

F₄ = 3 N

Therefore, the net force acting on the treasure chest is the resultant of F₂ and F₄.

So, the net force,

F = √(F₂² + F₄²)

F = √(3² + 4²)

F = √25

F = 5 N

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How much heat is necessary to change 10 g of ice at -20°C into water at 10°C?

Answers

Answer:

Explanation:

The process can be broken down into two steps:

Heat required to raise the temperature of ice from -20°C to 0°C.

Heat required to melt ice at 0°C and raise the temperature of water from 0°C to 10°C.

Step 1:

The heat required to raise the temperature of ice can be calculated using the specific heat capacity of ice, which is 2.09 J/g°C.

Heat required = mass × specific heat capacity × change in temperature

Heat required = 10 g × 2.09 J/g°C × (0°C - (-20°C))

Heat required = 418 J

Step 2:

The heat required to melt ice and raise the temperature of water can be calculated using the heat of fusion of ice and the specific heat capacity of water.

Heat required to melt ice = mass × heat of fusion of ice

Heat required to melt ice = 10 g × 334 J/g

Heat required to melt ice = 3340 J

Heat required to raise the temperature of water can be calculated using the specific heat capacity of water, which is 4.18 J/g°C.

Heat required = mass × specific heat capacity × change in temperature

Heat required = 10 g × 4.18 J/g°C × (10°C - 0°C)

Heat required = 418 J

Total heat required = Heat required in Step 1 + Heat required to melt ice + Heat required in Step 2

Total heat required = 418 J + 3340 J + 418 J

Total heat required = 4176 J

Therefore, 4176 J of heat is required to change 10 g of ice at -20°C into water at 10°C.

Suppose a negatively charged object A is brought in contact with an uncharged object B in a closed system. What type of charge will be left on object B?

a. negative
b. positive
c. neutral
d. cannot be determined

Answers

Answer:

b. positive

Explanation:

A negatively charged object A has excess electron while uncharged object B is neutral, i.e equal number of electrons and protons.

When the negatively charged object A is brought in contact with the neutral object B, the electrons present in object B will be repelled (likes charges repel). This process will leave object B with excess protons, thus object B will positively charged.

The correct option is "B"

The change in motion (acceleration) of an object depends on
The size of the force
The mass of the object
BOTH the size of the force AND the mass of the object

Answers

Answer:

BOTH the size of the force AND the mass of the object

Explanation:

Acceleration of an object is the rate of change of its velocity.

The relation between force, mass and acceleration is given by the formula as follows :

F = ma

m is mass

a is acceleration

It would mean that the change in motion or the acceleration of an object depends on both the size of the force and the mass of the object. Hence, the correct option is (c).

A jet on an aircraft carrier can be launched from rest to 40 m/s in 2 seconds. What is the acceleration of the aircraft? Show steps please​

Answers

Answer:

\(a=20\ m/s^2\)

Explanation:

Given that,

Initial speed, u = 0

Final speed, v = 40 m/s

Time, t = 2 s

We need to find the acceleration of the aircraft. We know that, acceleration is equal to the rate of change of velocity. So,

\(a=\dfrac{v-u}{t}\\\\a=\dfrac{40-0}{2}\\\\=20\ m/s^2\)

So, the acceleration of the aircraft is \(20\ m/s^2\).

A uniform rod with a mass of m = 1.94 kg and a length of l = 2.10 m is attached to a horizontal surface with a hi=nge. The rod can rotate without friction. (See figure.)
Initially the rod is held at rest at an angle of Θ = 70.4 with respect to the horizontal surface. Then the rod is released.
What is the angular speed of the rod, when it lands on the horizontal surface?

What is the angular acceleration of the rod, just before it touches the horizontal surface?

A uniform rod with a mass of m = 1.94 kg and a length of l = 2.10 m is attached to a horizontal surface

Answers

(a) The angular speed of the rod, when it lands on the horizontal surface is 1.61 rad/s.

(b) The the angular acceleration of the rod, just before it touches the horizontal surface is 1.06 rad/s² .

Angular acceleration of the rod

The angular acceleration of the rod is calculated as follows;

Apply the principle of conservation of angular momentum;

τ = Iα

where;

τ is torqueI is moment of inertial of the rodα is the angular acceleration

τ = Fr = mg(L/2) cosθ

I = mL²/3

mg(L/2) cosθ =  mL²/3(α)

g(1/2) cosθ =  L/3(α)

(³/₂)g cosθ  = L(α)

(³/₂ L)g cosθ  = α

1.5Lg cosθ  = α

1.5(2.1) cos (70.4) = α

1.06 rad/s² = α

Angular speed of the rod

ωf² = ω₁² + 2αθ

ωf² = 0 + 2(1.06)(70.4π/180)

ωf² = 2.605

ωf = √2.605

ωf = 1.61 rad/s

Thus, the angular speed of the rod, when it lands on the horizontal surface is 1.61 rad/s.

The the angular acceleration of the rod, just before it touches the horizontal surface is 1.06 rad/s² .

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Water flows at a speed of 13 m/s through a pipe that has a diameter of 1.2 m. What is the
diameter of the smaller end of the pipe that the water comes out with a speed of 30 m/s?

Answers

The diameter of the smaller end of the pipe is approximately 0.78 meters.

To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.

The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity

Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2

Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2

Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30

Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30

0.36 * 13 = (diameter2/2)^2 * 30

4.68 = (diameter2/2)^2 * 30

Dividing both sides by 30:
0.156 = (diameter2/2)^2

Taking the square root of both sides:
0.39 = diameter2/2

Multiplying both sides by 2:
0.78 = diameter2

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Emory pushes the box with 20 Newtons of force. If the box is 4kg, how fast will the box accelerate?

Answers

F=ma
20N=4kg.a
a=5 N/kg

In a laboratory experiment, a student was exploring the stretch of a spring based on the pull of the force. The student used weights of 1 N, 2 N, 3 N, 4 N, and 5 N. The points were plotted, and the relationship was analyzed. The graph is shown.

A graph titled stretch versus force is shown with stretch on the vertical axis and force on the horizontal axis. The graph is a straight diagonal line from bottom left to top right going through points 0 comma 0, 1 comma 1.0, 2 comma 3.6, 3 comma 5.5, 4 comma 7.2, and 5 comma 9.1.
Which of the following values would be considered an interpolation?

Force = 0 N, stretch = 0 cm
Force = 3 N, stretch = 5.5 cm
Force = 4.4 N, stretch = 7.9 cm
Force = 5.2 N, stretch = 9.3 cm

Answers

Final answer:

Interpolation refers to determining a value within an established dataset. In the context of the spring stretch experiment, the value 'Force = 4.4 N, stretch = 7.9 cm' is considered an interpolated value as it falls within the used force range (0N to 5N). The other values are either used in the experiment or extrapolations.

Explanation:

In this context, interpolation refers to the process of determining a value within an existing data set or between two known values. In your given data for the spring stretch experiment, the force values used in the experiment range from 0N to 5N. As such, an interpolated value would need to fall within this range.

Given that, the value Force = 4.4 N, stretch = 7.9 cm would be considered an interpolation because it falls within the known values used in the experiment. The rest of the options are either values used in the experiment (0 N, 3 N) or extrapolation (5.2 N) as they are outside of the range of force investigated.

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Final answer:

Considering the values from the experiment, the interpolated value between the known points on the graph is 'Force = 4.4 N, stretch = 7.9 cm', since it falls within the range of given values.

Explanation:

In the context of this laboratory experiment, interpolation refers to predicting a value within a range of known values. From the given points plotted on the graph, the values of force range from 0 N to 5 N, and the corresponding stretch ranges from 0 cm to 9.1 cm. Looking at the listed options, the value Force = 4.4 N, stretch = 7.9 cm falls within these known ranges of both force and stretch, thereby qualifying as an interpolation.

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34. JAnswer this: Pure (24 carat) gold has a density of 19 g/mL. If you bought"gold" ring and found it had a volume of 0.3 ml and that it weighed 5.7 grams, is it pure gold? Show your work to support your answer.​

Answers

Explanation:

Density = mass / volume

ρ = 5.7 g / 0.3 mL

ρ = 19 g/mL

Yes, it's pure gold.

Yes, it's pure gold.

How do you calculate gold density?The mass of an object divided by its volume is the formula for determining density. This is expressed mathematically as d = m/v, where d denotes density, m denotes mass, and v denotes object volume. The common measurements are kg/m³.

What is the formula of volume?The basic formula for volume is length, breadth, and height, as opposed to length, width, and height for the area of a rectangular shape.

What is the volume of pure gold?Gold has a specific gravity of 19.3. In light of this, 19.3 grams take up 1 cubic centimeter. 31.1 grams make up a Troy ounce. As a result, we need 31.1/19.3 = 1.61 cubic centimeters to equal 1 Troy Oz.

According to the question:

Density = mass / volume.

ρ = 5.7 g / 0.3 mL.

ρ = 19 g/mL.

Hence, Yes it's pure gold.

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What is the force between two balloons with a negative charge of 1.6 × 10−10 C if the balloons are 0.05 m apart?

Answers

Considering the Coulomb's Law, the force between the two ballons is 9.216×10⁻⁸ N.

Coulomb's Law

Charged bodies experience a force of attraction or repulsion on approach.

From Coulomb's Law it is possible to predict what the electrostatic force of attraction or repulsion between two particles will be according to their electric charge and the distance between them.

From Coulomb's Law, the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them:

\(F=k\frac{Qq}{d^{2} }\)

where:

F is the electrical force of attraction or repulsion. It is measured in Newtons (N).Q and q are the values ​​of the two point charges. They are measured in Coulombs (C).d is the value of the distance that separates them. It is measured in meters (m).K is a constant of proportionality called the Coulomb's law constant. It depends on the medium in which the charges are located. Specifically for vacuum k is approximately 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\).

The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.

Force between two balloons

In this case, you know that two balloons have a negative charge of 1.6×10⁻¹⁰ C and the balloons are 0.05 m apart.

Replacing in the Coulomb's Law, you get:

\(F=9x10^{9} \frac{Nm^{2} }{C^{2} } \frac{(-1.6x10^{-10} C)x(-1.6x10^{-10} C)}{(0.05 m)^{2} }\)

Solving:

\(F=9x10^{9} \frac{Nm^{2} }{C^{2} } \frac{2.56x10^{-20} C^{2} }{(0.05 m)^{2} }\)

\(F=9x10^{9} \frac{Nm^{2} }{C^{2} } 1.024x10^{-17}\frac{ C^{2} }{m^{2} }\)

F= 9.216×10⁻⁸ N

Finally, the force between the two ballons is 9.216×10⁻⁸ N.

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please help meeeee :((((((((((

Answers

Answer:

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Explanation:

help me thisanswer

why is metal a good conductor of electricity; why do metals conduct heat; why do metals conduct electricity and heat; why do metals have high melting points; why do metals conduct electricity structure and bonding; electrical conductivity of metals; thermal conductivity of metals; electrical conductivity of iron

Answers

every atom has at least one free electron.

Because the free electrons in metals are not bound to the atoms, they are free to flow between the atoms.

Due to the size of metals' lattice structures, there are many electrostatic forces.

The size of broken is enormous.

because the delocalized electrons in them cause the metal to conduct electrical charge.

related to its temperature

Iron 9.70×10−8 1.03×107

Because at least one electron per atom is free, metals are effective heat and electricity conductors.

Free electrons that are not bound to the atoms exist in metals. These electrons are unrestricted in the metal, interacting with the metal atoms to effectively transmit heat to them. As a result, metals are superior heat conductors than the majority of other materials.

By allowing free electrons to travel between the atoms, metals conduct electricity.

Metals have high melting and boiling temperatures because they have massive lattice structures and must break a huge number of electrostatic forces.

Because of their delocalized electrons, which transmit electrical charge through the metal, metals are electrical conductors, and their structure and bonding explains these characteristics.

According to the Wiedemann-Franz law, a metal's temperature directly affects how much thermal conductivity there is compared to electrical conductivity.

These eight electrons are the reason why iron metal has a high electrical conductivity.

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Which energy transformation takes place in a generator?

Question 2 options:

mechanical to electrical


chemical to radiant


electrical to mechanical


radiant to electrical

Answers

Answer:

c.electrical to mechanical

Explanation:

Can you answer this question with explanation?

Can you answer this question with explanation?

Answers

a) The magnitude of the electric field at the center of the semicircle is given by E = Xo/(2πR).

What is electric field?

An electric field is a physical field created by the presence of electric charge. It is an invisible force that can act on any other charged particles in its vicinity. Electric fields are generated by electric charges, or by time-varying magnetic fields.

The direction of the electric field is towards the center of the semicircle. This can be seen from the fact that the electric field is generated by the line of positive charge, thus pointing inwards.
b) The total force on the particle with negative charge -q placed at the center of the semicircle is given by F = -qE. Thus, the total force on the particle is given by F = -qXo/(2πR).
c) The magnitude of the electric field at the center of the semicircle is given by E = Xo/(2πR) cose. Here, cose is the cosine of the angle between the line of charge and the position of the particle. The direction of the electric field is still towards the center of the semicircle.
Bonus: If the semicircle has a total charge Q, the magnitude of the electric field at the center of the semicircle is given by E = Q/(2πR). The direction of the electric field is still towards the center of the semicircle.


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What's the dimension of velocity gradient

Answers

Answer:

c

velocity gradient is dimensionally represented as [M^0 L^0 T^-1)

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