A marble rolls off a tabletop 1.1m high and hits the floor at a point 2.1m away from the tables edge in the horizontal direction.

A. How long (in seconds) is the marble (in m/s) in the air?

B. What is the speed of the marble (in m/s) when it leaves the tables edge?

C. What is the speed (in m/s) when it hits the floor?

Answers

Answer 1
To solve this problem, we can use the equations of motion for an object in free fall with constant acceleration due to gravity (g = 9.81 m/s^2), which are:

y = vit + (1/2)gt^2 (Equation 1)
v = vi + gt (Equation 2)

where y is the vertical displacement, vi is the initial vertical velocity (which is zero when the marble leaves the table), t is the time, and v is the final velocity.

A. To find the time the marble is in the air, we can use Equation 1 with y = 1.1 m and vi = 0:

1.1 = (1/2)gt^2

Solving for t, we get:

t = sqrt(2*1.1/g) = 0.47 seconds

Therefore, the marble is in the air for 0.47 seconds.

B. To find the speed of the marble when it leaves the table, we can use Equation 2 with vi = 0 and t = 0.47 seconds:

v = gt = 9.810.47 = 4.61 m/s

Therefore, the speed of the marble when it leaves the table is 4.61 m/s.

C. To find the speed of the marble when it hits the floor, we need to find the horizontal and vertical components of its velocity. The horizontal component is constant, since there is no horizontal acceleration. The vertical component can be found using Equation 2 with vi = 0 and t = 0.47 seconds:

vy = gt = 9.810.47 = 4.61 m/s

The horizontal component of the velocity can be found from the distance traveled in the horizontal direction (2.1 m) and the time in the air (0.47 seconds):

vx = 2.1/0.47 = 4.47 m/s

The speed of the marble when it hits the floor is the magnitude of its velocity, which can be found using the Pythagorean theorem:

v = sqrt(vx^2 + vy^2) = sqrt(4.47^2 + 4.61^2) = 6.35 m/s

Therefore, the speed of the marble when it hits the floor is 6.35 m/s.

Related Questions

What are some INDIRECT applications of centripetal force in real life?

Answers

Answer:

The circular turning of roads

Explanation:

please mark brainliest

Answer:

Explanation:

The circular turning of roads

Driving on Curves

Water flows steadily from an open tank as shown in the figure. (Figure 1)The elevation of point 1 is 10.0 m , and the elevation of points 2 and 3 is 2.00 m . The cross-sectional area at point 2 is 4.80×10−2 m2 ; at point 3, where the water is discharged, it is 1.60×10−2 m2 . The cross-sectional area of the tank is very large compared with the cross-sectional area of the pipe. What is the gauge pressure p_gauge at point 2?

Answers

The gauge pressure at point 2 is 98100 Pa or 9.81 x\(10^4\) Pa, which is equivalent to 6.97 x\(10^4\) Pa when rounded to two significant figures.

Step 1: Identification of the given data:

- Elevation at point 1 (h1) = 10.0 m

- Elevation at points 2 and 3 (h2 = h3) = 2.00 m

- Cross-sectional area at point 2 (A2) = 0.0480 \(m^2\)

- Cross-sectional area at point 3 (A3) = 0.0160 \(m^2\)

Step 2: Determination of the discharge rate:

As mentioned earlier, the discharge rate (Q) is given by Q = A2 * v2, and since the velocity at point 2 (v2) is negligible, the discharge rate will be 0.

Therefore, the discharge rate is 0 cubic meters per second.

Step 3: Determination of the gauge pressure at point 2:

To find the gauge pressure at point 2, we'll use Bernoulli's equation:

P1 + (1/2)ρ\(v1^2\) + ρgh1 = P2 + (1/2)ρ\(v2^2\) + ρgh2

Since the velocity at point 2 (v2) is negligible, the term (1/2)ρ\(v2^2\) can be ignored.

The equation simplifies to:

Patm + ρgh1 = P2 + ρgh2

We want to find the gauge pressure at point 2, so we'll subtract the atmospheric pressure (Patm) from P2:

\(P_g_a_u_g_e\) = P2 - Patm

Now let's substitute the given values into the equation:

\(P_g_a_u_g_e\) = (Patm + ρgh1) - Patm

\(P_g_a_u_g_e\) = ρgh1

Plugging in the values:

\(P_g_a_u_g_e\) = (1000 kg/m^3) * (9.81 \(m/s^2\)) * (10.0 m)

\(P_g_a_u_g_e\) = 98100 Pa

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How many significant figures are there in the measurement (4.07×10^17m)

Answer and I will give you brainiliest

please heeeelp​​

Answers

Answer:

2...................

The position of a particle is r⃗ (t)=(3.0t2iˆ+5.0jˆ−6.0tkˆ)m. (a) Determine its velocity and acceleration as functions of time. (b) What are its velocity and acceleration at time t = 0?

Answers

Explanation:

It is given that,

The position of a particle is given by :

\(r(t)=(3t^2i+5j-6tk)\ m\)

(a) Velocity of a particle is given by :

\(v=\dfrac{dr(t)}{dt}\)

Putting values,

\(v=\dfrac{d}{dt}(3t^2+5-6t)\\\\v=(6ti-6k)\ m/s\)

The acceleration of the particle is given by :

\(a=\dfrac{dv}{dt}\\\\a=\dfrac{d}{dt}(6t-6)\\\\a=6i\ m/s^2\)

(b) At t = 0,

Velocity, v = 6k m/s

Acceleration, a = 6i m/s²

A cliff diver stands at the top of a cliff and falls forward off the cliff. If the cliff is 25 m tall, how fast (in m/s) is the diver going as she enters the water below?

Answers

With the use of formula, the the diver will enters the water with the speed of 22.1 m/s

What is Speed ?

Speed is how fast an object is moving which can be defined as distance over time.

Given that a cliff diver stands at the top of a cliff and falls forward off the cliff. If the cliff is 25 m tall, to know how fast  the diver going as she enters the water below, let us make use of the equation below

v² = u² + 2gH  Where

v = ?u = 0g = 9.8 m/s²H = 25 m

Substitute all the parameters into the equation

v² = 2× 9.8 × 25

v² = 490

v = √490

v = 22.1 m/s

Therefore, the diver is going as she enters the water with the speed of 22.1 m/s

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compute the distance and displacment of the puppy using visual analysis of the diagram?​

compute the distance and displacment of the puppy using visual analysis of the diagram?

Answers

Answer:

Distance A:11km

B:10km

Explanation:

Displacement A and B is 9km

Finding polar coordinates of the point ?(-2.3,-4.1)

Answers

We have the next coordiantes (-2.3,-4.1)

First we need to calculate the resultant

\(r=\sqrt{(-2.3)^2+(-4.1)^2}\)\(r=4.7\)

Then we calculate the angle

\(\theta=tan(\frac{-4.1}{-2.3})^{-1}=-119.3\)

Therefore the polar coordinate is

\(4.7\angle-119.3\)

A sample of The halflife of the substance is 21 minutes the number of atoms remaining underway. radioactive Substances has 812X1020 atom Determine the number of atoms remaining

Answers

After 42 minutes, there are 203 x \(10^{20\) atoms remaining of the radioactive substance.

To determine the number of atoms remaining after a certain amount of time has passed, we can use the formula for radioactive decay:

N(t) = N0 * \((1/2)^{(t / T)\),

where:

N(t) = number of atoms remaining at time t,

N0 = initial number of atoms (812 x  \(10^{20\) atoms),

T = half-life of the substance (21 minutes), and

t = time that has passed.

Let's calculate the number of atoms remaining after a given time.

Suppose the time passed is t = 42 minutes (twice the half-life).

N(t) = 812 x  \(10^{20\) * \((1/2)^{(42 / 21)\)

N(t) = 812 x  \(10^{20\) * \((1/2)^2\)

N(t) = 812 x  \(10^{20\) * 1/4

N(t) = 203 x  \(10^{20\) atoms.

So, after 42 minutes, there are approximately 203 x \(10^{20\) atoms remaining of the radioactive substance.

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What does flowing electrical charge produce?

Lightning.
Unusable energy.
Useable energy, electricity.
Global warming.

Answers

Answer:

Useable energy, electricity

Calculate the work done by applying a force of 830 N on a 3000 kg car to displace it 25 m.A. 20750 JB. 2490000 JC. 75000 J

Answers

The work done by a force can be calculated with the formula below:

\(W=F\cdot d\)

Where W is the work in Joules, F is the force in Newtons and d is the displacement in meters.

So, for a force of 830 N and a displacement of 25 meters, the work is:

\(\begin{gathered} W=830\cdot25 \\ W=20750\text{ J} \end{gathered}\)

Therefore the correct option is A.

what is a literature review?

Answers

Answer: A literature review consists of an overview, a summary, and an evaluation (“critique”) of the current state of knowledge about a specific area of research.

Explanation:

The lowest pressure ever obtained in a laboratory setting is 4.0×10−11 Pa. At this pressure, how many molecules of air would there be in a 50 Celsius experimental chamber with a volume of 0.060 m3?

Answers

There would be  5.38 × 10¹⁹ number of molecules of air at that condition.

What is ideal gas?

A theoretical gas known as an ideal gas is made up of several randomly moving point particles with no interparticle interactions.

Because it abides by the ideal gas law, a condensed equation of state, and is amenable to statistical mechanics analysis, the ideal gas concept is helpful.

The amount of air = PV/RT

= (4.0 × 10 ⁻¹¹× 0.060)/ 8.314 ×(273 + 50) mole

= 8.93714 × 10⁻⁵ moles.

molecules of air would there be =  8.93714 v × 6.023 × 10²³ = 5.38 × 10¹⁹

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Define average atomic mass and explain how it is calculated

Answers

Answer:

The average atomic mass of an element is the sum of masses of it's isotopes

Each are multiplied by it's natural abundance

Explanation:

The average atomic mass of an element is the sum of masses of it's isotopes

Each are multiplied by it's natural abundance

what is a U.S state you can visit a desert in

Answers

California (the High Desert); and parts of western Arizona, southern Nevada, and a small portion of Utah.

What potencial difference (volt) is required to cause 4.00 A to flow though a resistance of 330 ohms?

A) 334V
B) 12,1V
C) 82,5V
D) 1320V

Answers

Voltage = (current) x (resistance)

Voltage = (4.00 A) x (330 Ω)

Voltage = 1,320 V  (D)

The 10/90 principle can help you take control of your situation in taking responsibility of what you can change rather than in being victim of what you cannot change. Give an example of a situation that can change for you in applying this principle.

Answers

The 10/90 principle can be a powerful tool for taking control of your situation and improving your life. By taking responsibility for what you can change and focusing on your reaction to the situation, you can make positive changes in your life and become the master of your own destiny.

The 10/90 principle refers to the idea that life is made up of 10% of what happens to you and 90% of how you respond to it. In other words, you may not be able to control what happens to you, but you can control your reaction to it. By taking responsibility for what you can change rather than being a victim of what you cannot change, you can take control of your situation and improve your life.One example of a situation where the 10/90 principle could be applied is losing a job. Losing a job can be a devastating experience, and it can be easy to feel like a victim in this situation. However, by applying the 10/90 principle, you can take control of your situation and make positive changes in your life.The first step in applying the 10/90 principle in this situation would be to take responsibility for what you can change. This could mean updating your resume, networking with others in your field, and applying for new jobs. By taking action and doing what you can to find a new job, you are taking control of your situation and improving your chances of finding a new job.
The second step would be to focus on your reaction to the situation. Instead of dwelling on the negative aspects of losing your job, try to focus on the positive aspects. This could mean using the extra time to pursue a new hobby or spend more time with family and friends. By focusing on the positive aspects of the situation, you are taking control of your reaction and improving your overall well-being.
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If the coefficient of kinetic friction between a 24-kg crate and the floor is 0.25 what horizontal force is required to move the crate at a steady speed across the floor?

Answers

The horizontal force required to move the crate at a steady speed across the floor will be 58.86 N.

What is the friction force?

It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N).

The given data in the problem is;

Mass,m = 24 kg

The coefficient of kinetic friction, μ=0.25

The friction force is defined as the product of the coefficient of friction and normal reaction.

f=μN

If there is no other force, the horizontal force is equal to the friction force;

F=f

The horizontal force required to move the crate at a steady speed across the floor is found as;

F = μN

The normal reaction force is;

N=W

N=mg

F = μmg

F=0.25 ×  24-kg × 9.81 m/s²

F = 58.86 N

Hence horizontal force is required to move the crate at a steady speed across the floor will be 58.86 N.

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31. Box A of mass m sits on the floor of an elevator, with box B of mass 2 m on top of it, as shown in the figure above. The elevator is moving upward and slowing down. F_A is the magnitude of the force exerted on box A by box B, F_B is the magnitude of the force exerted on box B by box A, and F_g is the magnitude of the gravitational force exerted on box B. Which of the following ranks the forces in order of increasing magnitude?
(A) F_B=F_A=F_g
(B) (F_B=F_A) (C) F_B<(F_A=F_g)
(D) F_g

31. Box A of mass m sits on the floor of an elevator, with box B of mass 2 m on top of it, as shown in

Answers

The rank of the forces in order of increasing magnitude is Fg < FB < FA.

option D is the correct answer.

What is the net force on elevator moving upwards?

The net force on an elevator moving upwards is determined by the force of gravity acting downwards and the normal force of the elevator acting upwards.

That is, the two forces acting on a person when he is moving in an elevator are:

the force of gravity and the normal force by the elevator.

When the two forces are of equal magnitude, the elevator will be static or moving with constant velocity.

When the magnitude of the two force are unequal, then the elevator will be accelerating upward or downward.

Since the elevator is moving upwards, it implies that the normal force is greater than the force of gravity acting downwards.

the normal force = FB + FAForce of gravity = Fg

The box at the bottom will feel much heavier due to the weight of box and gravity acting downwards.

FA = FB + Fg

Thus, the force exerted on box A is the greatest, followed by the force on box B and then, the smallest is force of gravity.

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What is the angular speed and the number of revolutions per hour

What is the angular speed and the number of revolutions per hour

Answers

\(\begin{gathered} r=\frac{64ft}{2}=32ft \\ v=7\frac{mi}{hour}\cdot\frac{5280ft}{1\text{ mi}}\cdot\frac{1hour}{60\text{ minutes}}=616\text{ ft/min} \\ To\text{ find }angulat\text{ sp}eed \\ v=wr \\ \text{Solving w} \\ w=\frac{v}{r}=\frac{616\text{ ft/min}}{32ft}=19\text{ rad/min} \\ \text{The angular spe}ed\text{ is }19\text{ rad/min} \\ \\ To\text{ find revolution per hour } \\ 19\frac{rad}{\min}\cdot\frac{60\min}{1hour}\cdot\frac{1rev}{2\pi rad}=153\text{ rev/hour} \\ \text{The whe}el\text{ }makes\text{ }153\text{ rev/hour} \end{gathered}\)

A charge q1 of -6.00 × 10^-9 C, a charge a2 of -3.00 × 10^-9 C, and charge q3 of -1.10^-9 C. Q1 and a2 are separated by a distance of 60.0 cm, q2 and q3 are separated by distance 60.0 cm. What is the net charge on the q2?

Answers

The net charge on q2 is estimated at -4.00 × 10^-9 C.

How do we calculated?

We apply  Coulomb's law to solve this:

The Force is  = (k * q1 * q2) / r^2

For q1 and q2:

F1-2 = (k * q1 * q2) / r^2 = (9.0 × 10^9 N·m^2/C^2) * (-6.00 × 10^-9 C) * (-3.00 × 10^-9 C) / (0.60 m)^2 = 1.35 × 10^-3 N

For q2 and q3:

F2-3 = (k * q2 * q3) / r^2 = (9.0 × 10^9 N·m^2/C^2) * (-3.00 × 10^-9 C) * (-1.10 × 10^-9 C) / (0.60 m)^2 = 2.25 × 10^-4 N

The net force on q2 is the vector sum of the forces on q2 from q1 and q3:

Fnet = F1-2 + F2-3 = 1.35 × 10^-3 N + 2.25 × 10^-4 N = 1.58 × 10^-3 N

Fnet = (k * q2 * qtot) / r^2

qtot = the net charge on q2

qtot = (Fnet * r^2) / (k * q2) = (1.58 × 10^-3 N) * (0.60 m)^2 / (9.0 × 10^9 N·m^2/C^2) / (-3.00 × 10^-9 C) =  -4.00 × 10^-9 C

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HELPP

im not exactly sure what to put

HELPPim not exactly sure what to put

Answers

Explanation:

between 0 and 2 hours the relationship between time and distance traveled is a linear one.

that means that the velocity (= distance/time like in km/s) is constant (and not increasing).

and because between the hours 2 and 3 there is no increase in distance, this means the car stood still during that time. so, no, it was not always in motion during the voyage.

therefore,

option 2 is correct (as described, no change in distance means no motion or zero velocity).

and option 3 is correct, because also between hours 3 and 5 the function is linear and the speed ratio is therefore constant.

A train is traveling at 28 m/s. It slows to 6 m/s in 4 s. Calculate the distance the train
travels in this time.

Answers

The next step is -748 divide by -11 is 68 m (answer) the pic got cropped sorry
A train is traveling at 28 m/s. It slows to 6 m/s in 4 s. Calculate the distance the traintravels in

Explanation:

A=v-u/t

A= 6- 28/4

A= 5.5m/s2

s= ut+ 1/2 at^2

s = 28 * 4+ 1/2 * 5.5 * 4^2

s = 112 + 1/2 * 5.5 * 16

s = 112 + 5.5* 8

s= 112 + 44

s = 156m

Jeff finds a pond during a nature walk, and he has some questions based on his observations of the pond.

Which question can he answer through a scientific investigation?

Which organisms are part of the food web in the pond?
How much money should be spent to make the pond more attractive?
Which pond animals would make the best pets?
Which plants in the pond are the prettiest in summer?

Answers

Answer:

Which organisms are part of the food web in the pond?

Explanation:

A "scientific investigation" is a method of looking for an answer with the help of a scientific method. It helps a person learn more about the world around him.

Since the scientific investigation only employs "measurable" observations, then the only question he can ask is the types of organisms (which is measurable) that belonged to the pond's food web. This question is more focused on observing the pond, unlike the other questions that talked about different things like money, having a pet and summer season–these are not directly observable and measurable in the current situation.

Answer:   Which organisms are part of the food web in the pond?

Explanation:

A peak with a retention time of 407 s has a width at half-height (w1/2) of 7.6 s. A neighboring peak is eluted 17 s later with a w1/2 of 9.4 s. A compound that is known not to be retained was eluted in 2.5 s. The peaks are not baseline resolved. How many theoretical plates would be needed to achieve a resolution of 1.5?

Answers

Answer:

2.46 x 104

Explanation:

Solution

Recall that:

The retention time of a peak = 407 s

with a width at half-height of = 7.6 s

A compound is retained in 2.5 s.

resolution to be achieved = 1.5

Thus,

The number of plates (theoretical)= 16(tr2 / w2)

The R Resolution R= 0.589 Δtr / w1/2av = 0.589(17s) / 1/2(7.6s + 9.4s) = 1.18

Supposed that applied column contains 10,000 theoretical plates and the resolution of two peaks is 1.18

So if the column is replaced to obtain 1.5 resolution, the number of theoretical plates is needed is  stated below;

width at the base = 9.4 - 7.6 = 1.8; tr = 0.786

N = 5.55tr2 / w21/2 = 5.55 (0.7862/ 1.182) x 104

= 2.46 x 104

Therefore, required theoretical plates to achieve a resolution of 1.5 is 2.46 x 104

Which term is most applicable to a discussion of angular momentum in the context of black holes?
A. photon
B. curvature
C. spin
D. time

Answers

Answer:

Curvature

Explanation:

is burning trash a physical change or chemical change?

Answers

it's a chemical chemical change

In a 2X4X3 factorial design, how many levels does the second independent variable have?

Answers

Answer:

The second independent variable in a 2x4x3 factorial design has 4 levels.

Explanation:

I NEED HELP!!!! THIS IS A CER "Write a scientific explanation describing how a rabbit, which eats plants, gets energy to live and grow"
I NEED CLAIM, EVIDENCE, and REASONING

Answers

Answer:

A rabbit which needs food specifically food from plants because they are vegetarians, to help them grow. The energy that the plant holds is given to the rabbit when eaten. The plant feeds the bunny its nutrients which tells the muscles to keep going and get stronger and tells the rest of the body to grow.

Explanation:

A ball is thrown upward and reaches a maximum height of 20 meters and then returns back to where it was launched. What is the displacement of the ball?

Answers

Answer: 0

Explanation: because when it return total displacement is 0

A woman drives a car from one city to another with different constant speeds along the trip. She drives at a speed of 50.0 km/h for 15.0 min, 80.0 km/h for 25.0 min, makes a stop for 55.0 min, then continues at 40.0 km/h for 30.0 min, at which point she reaches her destination.

Required:
a. What is the total distance between her starting point and destination (in km)?
b. What is the avg speed for the entire trip in (km/h)?

Answers

Answer:

a) 65.83 km

b) 52.664 km/h

Explanation:

Different speed values :

Initial speed : 50 km/h  for 15 mins

                       80 km/h  for 25 mins

stops for 55 mins

40 km/h for 30 minutes

a) Determine total distance covered

Speed = distance covered / time

∴ Total distance = ∑speed * time

                           = ( 50 * 15/60 ) + ( 80*25/60) + ( 40 * 30/60 )

                           = 65.83 km

b) Average speed

Total distance / time taken

= 65.83 / ( 15 + 25 + 30 ) / 60

= 65.83 / ( 75/60)

= 52.664 km/h

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How many yard of ribbon doe Marcella have left?Enter your anwer a a mixed number (a) unrestricted pledges of support were received in the amount of $300,000. all of these are due within the year and it is estimated that 7% will ultimately prove to be uncollectible. (b) 600 memberships were sold to the public in the amount of $45 each. membership provides the individual with a monthly magazine and other benefits. the estimated fair value of member benefits is $20. the member year runs from july 1 to june 30. (c) a local carpenter donated supplies and labor with values of $25,000 and $30,000 (respectively) to construct a new exhibition area. fixed assets are classified as unrestricted net assets. (d) on april 1, 2020 a local businessman made a pledge payable in a future period. the pledge is restricted in purpose and has a present value of $110,000 (effective interest rate of 5%). 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Select the correct answer. matthew has recorded the amount he's saved every three months. months savings 3 $1,800 6 $3,600 9 $5,400 christopher saves $550 every month. assume that matthew and christopher both save money at constant rates. whose unit rate is higher, and by how much? a. christopher's savings per month is higher than matthew's savings per month by $50 per month. b. matthew's savings per month is higher than christopher's savings per month by $50 per month. c. christopher's savings per month is higher than matthew's savings per month by $100 per month. d. matthew's savings per month is higher than christopher's savings per month by $100 per month. e. matthew and christopher both save the same amount, $550 per month. francesca is participating in a fun run to raise money for the west side children's hospital. the run is held at francesca's high school track. the more laps francesca runs around the track, the more money she raises for the hospital. there is a proportional relationship between the number of laps francesca runs, x, and the amount of money she raises for the hospital (in dollars), y. x (laps) y (dollars) 1 $5 2 $10 3 $15 4 $20 what is the constant of proportionality? write your answer as a whole number or decimal. dollars per lap pregnant women with gestational diabetes mellitus (gdm) are at risk for long-term weight gain and subsequent development of type ii diabetes. a pilot weight loss clinical trial was conducted where women with gdm were randomized to either an active intervention using a web-based delivery or a control intervention. women were randomized at 6 weeks postpartum and then were seen at follow-up visits at 6 months and 12 months postpartum. at 12 months postpartum, women in the active group lost a mean of 0.18 lb with a standard deviation of 15.5 lbs. hint: for all parts of this problem, assume that weights can be measured exactly and no continuity correction is necessary. a button hyperlink to the salt program that reads: use salt. (a) if we assume that the change in weight from pre-pregnancy to 12 months is normally distributed, then what percent of women in the active group were at or below their pre-pregnancy weight at 12 months postpartum? (round your answer to two decimal places.) 22.36 incorrect: your answer is incorrect. % (b) at 12 months postpartum, women in the control group gained a mean of 7.8 lbs. with a standard deviation of 15.4 lbs. compared with their pre-pregnancy weight. what is the probability that a control group woman was at or below her pre-pregnancy weight at 12 months? (hint: make the same assumptions as in part (a). round your answer to four decimal places.) a seller's agent is contacted by a buyer's agent. during their conversation, the buyer's agent discloses that the buyer needs to move quickly as he is being relocated by his employer. the seller's agent encourages the seller to be inflexible during the negotiations on the listing price, believing that the buyer will pay whatever price is necessary because the buyer's time is limited. what statute was violated in this scenario? Select the correct answer from each drop-down menu. In a chemical reaction, activation energy increases the of the reactants. This outcome causes the particles to collide, which results in the of new products. a revolutionary war cannon, with a mass of 2020 kg, fires a 20 kg ball horizontally. the cannonball has a speed of 139 m/s after it has left the barrel. the cannon carriage is on a flat platform and is free to roll horizontally. what is the speed of the cannon immediately after it was fired? answer in units of m/s Review I Constants Periodic Table Part A The table below shows the normal boiling points of benzene and benzene derivatives. Which of these compounds exhibit dispersion interactions? Normal Drag the appropriate compounds to their respective bins. Point (2C) Compound Structure Reset Help C,H, (benzene) CHCI (chlorobenzene) 132 benzene phenol chlorobenzene bromobenzene c,H,Br (bromobenzene) 156 do not exhibit dispersion interactions exhibit dispersion interactions C,H,OH (phenol, or hydroxybenzene) 182 Submit Request Answer Part B Which of these compounds exhibit dipole-dipole interactions? Drag the appropriate items to their respective bins. Reset Help chlorobenzene phenol benzene bromobenzene exhibit dipole-dipole interactions do not exhibit dipole-dipole interactions Submit Request Answer Part C Which of these compounds exhibit hydrogen bonding? Drag the appropriate items to their respective bins. Reset Help bromobenzene benzene chlorobenzene phenol exhibit hydrogen bonding do not exhibit hydrogen bonding Submit Request Answer Part D Why is the boiling point of bromobenzene higher than that of chlorobenzene? Match the words in the left column to the appropriate blanks in the sentences on the right. Reset Help more Bromine is and polarizable than chlorine, so the dispersion forces in bromobenzene are than those in chlorobenzene. larger stronger smaller weaker less Submit Request Answer Part E Why is the boiling point of phenol the highest of all? Match the words in the left column to the appropriate blanks in the sentences on the right. Reset Help weakest Phenol exhibits intermolecular interaction among which is the covalent molecules. strongest van der waals forces hydrogen bonding covalent bonding ionic bonding Submit Request Answer consider a market served by a monopolist, firm a. a new firm, firm b, enters the market and, as a result, firm a lowers its price to try to drive firm b out of the market. this practice is known as question 42 options: resale price maintenance. predatory tying. tying. predatory pricing.consider a market served by a monopolist, firm a. a new firm, firm b, enters the market and, as a result, firm a lowers its price to try to drive firm b out of the market. this practice is known as question 42 options: resale price maintenance. predatory tying. tying. predatory pricing. Farrah sits in the very back of her high school classroom behind the largest boy in her class, but every time she looks up, she feels like the teacher is focusing everything on her no matter how hard she tries to draw attention away from herself. She constantly constructs elaborate scenarios about what her teacher thinks of her. Farrah is dealing with negative charge -q is distributed uniformly over the surface of a thin spherical insulating shell with radius r. calculate the force (magnitude and direction) that the shell exerts on a positive point charge q located a distance (a) r 7 r from the center of the shell (outside the shell); (b) r 6 r from the center of the shell (inside the shell). the data-mining application that identifies which prospective clients should be included in a mailing or email list to obtain the highest response rate is known as . a machine has 12 identical components which function independently. the probability that a component will fail is 0.2. the machine will stop working if more than three components fail. find the probability that the machine will be working.select all applicable choices a) 0.133 b) 0.795 c) 0.206 d) 0.927 e) none of these Which Qualys technology provides a patch download cache, to achieve a more efficient distribution of downloaded patches, to local agent host assets?