A long metal cylinder with radius a is supported on an insulating stand on the axis of a long, hollow, metal tube with radius b. The positive charge per unit length on the inner cylinder is λ, and there is an equal negative charge per unit length on the outer cylinder.A) Calculate the potential V(r) for rb.D) Show that the potential of the inner cylinder with respect to the outer is Vab=(λ/2πϵ0)ln(b/a)E) What is the potential difference between the two cylinders if the outer cylinder has no net charge?Please show all steps.

The circuit consists of a voltage source of 12V connected in series with a resistor of 10 ohms and a capacitor of 2 microfarads. At t=0, the switch opens and the circuit becomes an RC circuit. The voltage across the capacitor and the current flowing through the circuit will change with time.

At t=-0, the switch is closed and the capacitor is uncharged. Therefore, the voltage across the capacitor Vc(0) is zero and the current flowing through the circuit i(0) is V/R = 12/10 = 1.2A.

At t=0, the switch opens and the circuit becomes an RC circuit. The capacitor starts to charge through the resistor and the voltage across the capacitor Vc(t) increases exponentially towards 12V. The current flowing through the circuit i(t) decreases exponentially towards zero as the capacitor charges up. The time constant of the circuit is given by RC = 20 microseconds.

At t=∞, the capacitor is fully charged and no current flows through the circuit. Therefore, Vc(∞) = 12V and iL(∞) = 0.

Using the initial conditions Vc(0) = 0 and i(0) = 1.2A, we can determine the values of ic(0) and VL(0) at t=0. The current flowing through the capacitor ic(0) = i(0) = 1.2A and the voltage drop across the resistor VL(0) = i(0) x R = 1.2 x 10 = 12V.

To determine the values of Vc(t) and iL(t) at any time t, we can use the equations Vc(t) = 12(1-e^(-t/RC)) and iL(t) = (V/R)e^(-t/RC).

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The total energy of the body at evevry point is remained same due to the law of conservation of energy. Distance from A to B and final velocity of the ball just reach before C is 44.3 m/s.

d (distance) from A to B is = √2gh

In this case given are, g = 9.8 m/s² and h = 100m,

so here d = √(2⋅9.8⋅100) = 44.3m.

Final velocity ,v = √2gh

Here given are , v is the velocity, g is the acceleration due to gravity, and h is the height. In this case,

g = 9.8 m/s² ,h = 100m,

v = √(2⋅9.8⋅100)

= 44.3 m/s (final velocity)

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a)The aperture size of the radio telescope needs to be approximately 0.27 meters b)The aperture of a radio telescope needs to be much larger than that of an optical telescope because radio waves have much longer wavelengths compared to visible light. c)the resolving power of a telescope depends on the ratio of the wavelength of light.

a. To determine the aperture size of a radio telescope to achieve a resolution at 21 cm, we can use the Rayleigh criterion, which states that the minimum resolvable separation (δθ) is given by:

δθ = 1.22 * (λ / D)

Where λ is the wavelength of the radiation and D is the diameter of the telescope's aperture.

Given that the radio wavelength is 21 cm (or 0.21 m), and we want to achieve the same resolution as the optical telescope (1 second of arc), we can rearrange the formula to solve for D:

D = 1.22 * (λ / δθ)

D = 1.22 * (0.21 m / 1 second of arc)

Calculating the result:

D ≈ 0.27 m

Therefore, the aperture size of the radio telescope needs to be approximately 0.27 meters to achieve a resolution of 1 second of arc at a wavelength of 21 cm.

b. The Rayleigh criterion tells us that the resolution of an instrument is inversely proportional to the wavelength.

Since radio waves have longer wavelengths, the telescope's aperture needs to be larger to achieve the same resolution as an optical telescope. This is because a larger aperture collects more incoming waves and allows for finer spatial detail to be resolved.

c. The ability to resolve two objects using a telescope depends on the size of the aperture relative to the wavelength of the radiation. When it comes to resolving stars, the resolving power of a telescope depends on the ratio of the wavelength of light to the size of the telescope's aperture (λ/D).

Blue light has a shorter wavelength compared to red light. Since the resolving power is directly proportional to the wavelength, a shorter wavelength of blue light allows for better resolution.

Therefore, two predominantly blue stars can be resolved because their shorter wavelength allows for finer detail to be distinguished, while the same separation between two predominantly red stars cannot be resolved due to the longer wavelength.

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Answer:

orce or acceleration b. Ms. Sunderland finally decided to take this seriously and put both hands on the rope and applied a 1000 N force to the left, while Jared and James still struggled with their 300 N force to the right. What is ... 150 more force. 10. During 5th period Dylan resisted the forces applied by her classmates in a ...

Explanation:

Answer:

Because they don't have a telescope to magnify so close

Explanation:

Hope it works for you :)

Answer:

scientists can't see inside a atom because the atoms cant be seen by anything                      hope it help :)

Explanation:

The body goes through equilibrium position its displacement x is zero. Hence, acceleration also 0.

What is acceleration?

Acceleration rate at which velocity change with time, in terms of both speed and direction.

Sol-The restoring  force in case of simple harmonic motion is an elastic force of the spring. It could be found by the use of Hooke's law  F = - kx. Here k - the spring constant and x - deformation of the spring (change of its length from equilibrium position).

We see that this is a variables force that is  depends on the given displacement of their mass-spring system of x. Minus sign tells us that the direction of this force is opposite to that of the  displacement; as a result of  this force brings the mass of the back to the equilibrium position (this is why we called it a restoring force).

As any force, restoring force could be found using Newtons second law F = ma, where m - mass of the body and a - acceleration of the body.

Now we can write:

When the body goes through equilibrium position its displacement x is zero. Hence, acceleration also 0.

BTW, the maximum value of the acceleration we will have when the amplitude of this  mass-spring system is the maximum. At this points the direction of the mass-spring pendulum switches to the  opposite. Those points we are call inflection points.

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Resistance decreases the flow of current in a circuit.

Explanation:

The resistance of an electrical circuit is defined as the opposition to the flow of current in that particular circuit

The first gear set (12-72) provides a speed increase of 6, and the second gear set (8-64) further increases the speed by a factor of 8, resulting in an overall speed increase of 48.

To design a compounded reverted gear train as a step-up gear with a speed increase of 48 times while minimizing the gearbox size and avoiding interference problems, we need to carefully select the numbers of teeth for the gears.

The compounded reverted gear train consists of two sets of gears: the first set is the compound gear train, and the second set is the reverted gear train. The compound gear train is used to achieve a moderate speed increase, and the reverted gear train further amplifies the speed.

To determine suitable numbers of teeth, we can start by considering the speed increase ratio of 48. This ratio can be achieved by breaking it down into smaller ratios for the compound and reverted gear sets. For example, we can choose a speed increase ratio of 6 in the compound gear train and a ratio of 8 in the reverted gear train.

Next, we need to select suitable numbers of teeth for each gear to avoid interference problems and ensure smooth operation. To minimize gearbox size, we aim to keep the gears as small as possible. One approach is to use gears with a small number of teeth, which can help reduce their size.

For the compound gear train, we can select gears with, for example, 12 and 72 teeth. This gives a speed increase ratio of 6. For the reverted gear train, we can choose gears with 8 and 64 teeth, resulting in a speed increase ratio of 8.

The sketch of the designed compounded reverted gear system would show the gear positions and their numbers of teeth as follows:

     ----    12 teeth    ----

   /                              \

--- 72 teeth 8 teeth ---

\ /

      ---- 64 teeth ----

In this configuration, the first gear set (12-72) provides a speed increase of 6, and the second gear set (8-64) further increases the speed by a factor of 8, resulting in an overall speed increase of 48. By carefully selecting the numbers of teeth and the gear ratios, we can achieve the desired speed increase while minimizing the size of the gearbox and avoiding interference problems between the gear teeth.

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Answer:

Electric potential energy

Explanation:

The Electric potential energy of a system is less than that carried out by electrostatic forces during the development of the system (as long as charges are initially cut infinitely).

The change in potential energy between an initial and final configuration  is equal to minus the work done by the electrostatic forces.

When astronomers say that the groups of galaxies are distributed isotropically, they mean that the group of galaxies appears to be similar when viewed through any directions.

Isotropy of galaxies means that the arrangement of galaxies doesn't differ in any directions. That is ,the galaxies are arranged in such a way that it seems same even if viewed from different directions. The word isotropy refers to the lack of preference to the direction.

In Cosmology, the universe is also said to have isotropy and homogeneity. Homogeneity also refers to the uncertainty of location.

In astronomy, the isotropy of galaxies simply means there will be no difference in the galaxies viewed from different directions.  

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Answer:

11025 N / m²

Explanation:

Los siguientes datos se obtuvieron de la pregunta:

Área (A) = 400 cm²

Masa (m) = 45 Kg

Aceleración por gravedad (g) = 9,8 m / s²

Presión (P) =?

A continuación, determinaremos la fuerza aplicada. Esto se puede obtener de la siguiente manera:

Masa (m) = 45 Kg

Aceleración por gravedad (g) = 9,8 m / s²

Fuerza (F) =.?

F = m × g

F = 45 × 9,8

F = 441 N

A continuación, convertiremos 400 cm² a m². Esto se puede obtener de la siguiente manera:

1 cm² = 0,0001 m²

Por lo tanto,

400 cm² = 400 cm² × 0,0001 m² / 1 cm²

400 cm² = 0,04 m²

Por tanto, 400 cm² equivalen a 0,04 m².

Finalmente, determinaremos la presión ejercida de la siguiente manera:

Área (A) = 0.04 m².

Fuerza (F) = 441 N

Presión (P) =?

P = F / A

P = 441 / 0,04

P = 11025 N / m²

Por tanto, la presión ejercida es 11025 M / m²

Answer:

the number of protons.

Explanation:

the atomic number is the number of protons in the nucleus of an atom. the number of protons Define the identity of an element.

The factor that can have a significant influence on a planet’s surface temperature is its atmosphere.

The atmosphere plays a fundamental role in the Earth planet's temperature because it allows the entry and out of certain types of radiation that may increase the temperature.

The role of the atmosphere in the Earth's temperature is well documented because our temperature is thick and it increases its homeostatic temperature balance.

In conclusion, the factor that alters a planet’s surface temperature is its atmosphere.

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a) U =  0 J

k = 0.383 J

E = 0.383 J

b) U = 0.0228 J

k = 0.155 J

E = 0.383 J

c) U = 0.1104 J

k = 0.272 J

E = 0.383 J

d) U = 0.248 J

k = 0.177 J

E = 0.383 J

The equations for kinetic energy is:

k= 1/2*m*\(v^{2}\)

The equation for elastic potential energy is:

U= 1/2*ks*\(x^{2}\)

Where,

m= mass of the block

v= velocity

ks= spring constant

x= displacement of the spring

U= 1/2*ks*\(x^{2}\)

U= 1/2*552*\((0)^{2}\)

  = 0 J

Kinetic energy:

k= 1/2*m*\(v^{2}\)

k= 1/2*(1.05)*\((0.855)^{2}\)

k= 0.383 J

Mechanical energy:

E= k + U

E= 0.383+0

E= 0.383 J

There will be no work done by friction or any other dissipative force, hence this energy will be conserved, or it will remain constant (like air resistance). This indicates that only spring potential energy will be created from the kinetic energy (there is no thermal energy due to friction, for example).

(b) spring potential = ?

U= 1/2* 457 N/m*\((0.01)^{2}\)

U= 0.0228 J

Since the mechanical energy must remain constant, we may calculate the kinetic energy using the mechanical energy equation:

E= k + U

0.383= k + 0.0228

k= 0.383 - 0.228

k= 0.155

(c)spring constant when x= 0.02

U= 1/2*552*\((0.02)^{2}\)

U= 0.1104 J

Using the equation of mechanical energy:

E= k +U

0.383= k+ 0.1104

k= 0.383 - 0.1104

k= 0.272 J

(d) U= 1/2*552*\((0.03)^{2}\)

U= 0.2484 J

E= 0.383 J

k = E - U

k= 0.383- 0.206

k= 0.177

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The given statement "When light hits the boundary between two different materials, it can undergo both reflection and refraction" is true because Reflection occurs when the light bounces off the object and refraction leads  to bending and change in the direction .

The reflection defined as the bouncing back of the light when it strikes the smooth surface. The refraction defined as  the bending of the light rays when it will travels from the one medium to the another. Generally it occurs on the shinny surfaces that will only allow the rebounding of the light without permitting the penetration through it.

The reflection and the refraction both occurs when light hits the boundary between two different materials.

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It would take 6416.8 kJ of heat to vaporize 1.22 kg of helium at its boiling point.

Helium is a chemical element with the symbol He and atomic number 2.

The amount of heat needed to vaporize a substance can be calculated using the formula:

Q = m * ΔHv

Where

For helium, the heat of vaporization is 21.1 kJ/mol at its boiling point of -268.9°C. The molar mass of helium is 4.003 g/mol.

To calculate the amount of heat needed to vaporize 1.22 kg of helium, we first need to convert the mass to moles:

1.22 kg He * (1000 g / 1 kg) * (1 mol / 4.003 g) = 304.4 mol He

Then, we can use the formula to calculate the amount of heat needed:

Q = m * ΔHv = 304.4 mol * 21.1 kJ/mol = 6416.8 kJ

Therefore, it would take 6416.8 kJ of heat to vaporize 1.22 kg of helium at its boiling point.

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The maximum number of orbitals that can have each of the given designations are as follows: 6s  One orbital can have the designation 6s.Two orbitals cannot have the designation 6s. This is because there is only one 6s orbital in an atom.

Five orbitals cannot have the designation 6s. This is because there is only one 6s orbital in an atom.  Seven orbitals cannot have the designation 6s. This is because there is only one 6s orbital in an atom.  The designation 6s represents an orbital in the sixth energy level that has s symmetry. In any energy level, there is only one s orbital, which can hold up to two electrons. Therefore, there can only be one 6s orbital in an atom, and it can hold a maximum of two electrons.

The designation 6p represents an orbital in the sixth energy level that has p symmetry. In any energy level, there are three p orbitals, which can hold up to six electrons. Therefore, there can be up to three 6p orbitals in an atom, and each can hold a maximum of two electrons. 4) n =  i) One orbital can have the designation n = 2. Four orbitals cannot have the designation n = 2. This is because there are only two orbitals in the second energy level (one s orbital and one p orbital). Nine orbitals cannot have the designation n = 2. This is because there are only two orbitals in the second energy level (one s orbital and one p orbital).  The designation n = 2 represents an energy level that is the second closest to the nucleus. In this energy level, there are two orbitals: one s orbital and one p orbital. The s orbital can hold up to two electrons, while the p orbital can hold up to six electrons (in three orbitals). Therefore, there can be up to four electrons in the n = 2 energy level.

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The wall pushes on the skater while the skater pushes on the wall is the phrase that best captures the action-reaction force in the scenario.

Every action has an equal and opposite response, according to Newton's third law of motion. As a result, whenever we apply pressure to a wall, the wall responds by applying pressure of a similar magnitude but in the opposite direction.

This law unambiguously explains how an object can move by exerting force on another object, as in the motion of a rocket. In the illustrated scenario, the skater pushes the wall while the wall pushes back in the opposite way.

The question is incomplete. The complete question is 'Which statement best describes an action-reaction force pair in this situation?

A.The wall pushes on the skater when the skater pushes on the wall.

B.The wheels slow down, and the skater stops.

C.The skater exerts a force on the wall, and the wheels exert a force on the floor and begin to turn.

D.The friction of the floor decreases when the wheels roll on the floor.'

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The velocity of the sled at the bottom of the incline is 28 m/s.

To determine the velocity of the sled at the bottom of the incline, we need to use conservation of energy principles. At the top of the incline, the sled has gravitational potential energy due to its height above the ground. As the sled slides down the incline, this potential energy is converted to kinetic energy.

The first step is to calculate the gravitational potential energy of the sled at the top of the incline. We can use the formula E = mgh, where E is the potential energy, m is the mass of the sled, g is the acceleration due to gravity (\(9.8 m/s^2\)), and h is the height of the sled above the ground. The height h can be calculated using trigonometry, as h = 80 sin(30°) = 40 m. Therefore, the potential energy of the sled is E = (20 kg)(\(9.8 m/s^2\))(40 m) = 7840 J.

Next, we need to determine the work done by friction as the sled slides down the incline. The force of friction is given by f = µN, where µ is the coefficient of friction and N is the normal force. The normal force is equal to the component of the weight of the sled that is perpendicular to the incline, which can be calculated as N = mg cos(30°) = (20 kg)(\(9.8 m/s^2\)) cos(30°) = 166.4 N. Therefore, the force of friction is f = (0.2)(166.4 N) = 33.28 N.

The work done by friction is equal to the force of friction multiplied by the distance over which it acts, which is 80 m. Therefore, the work done by friction is W = f d = (33.28 N)(80 m) = 2662.4 J.

The final step is to use conservation of energy to relate the initial potential energy of the sled to its final kinetic energy at the bottom of the incline. According to the principle of conservation of energy, the total energy of the system must remain constant. Therefore, we can write:

Ei = Ef

\($mgh = \frac{1}{2}mv^2 + W$\)

where Ei is the initial energy (potential energy), Ef is the final energy (kinetic energy plus work done by friction), and v is the velocity of the sled at the bottom of the incline.

Substituting in the values we have calculated, we get:

\($(20 \textrm{ kg})(9.8 \textrm{ m/s}^2)(40 \textrm{ m}) = \frac{1}{2}(20 \textrm{ kg})v^2 + (33.28 \textrm{ N})(80 \textrm{ m})$\)

Simplifying and solving for v, we get:

\($v = \sqrt{2gh - 2\mu gd}$\)

\($v = \sqrt{2(9.8 \textrm{ m/s}^2)(40 \textrm{ m}) - 2(0.2)(9.8 \textrm{ m/s}^2)(80 \textrm{ m})}$\)

\($v = \sqrt{784}$\)

v = 28 m/s

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Complete question:

A 20 kg sled rests at the top of an incline 80 m long and 30° inclination. If µ = 0.2, what is the velocity at the bottom of the incline?

The statement 'the attractive force between two (2) objects depends on their masses and the distance between them' correctly describes  The Universal Law of Gravitation (Option 3).

The Universal Law of Gravitation is a scientific law well supported by empirical evidence which states that the force of attraction between different objects depends on the masses and distance.

The Universal Law of Gravitation is a scientific theory and it indicates that all types of particles are attracted by all objects present in the universe, and this attractive force is correlated to the length of separation between particles. This law was postulated by sir Isaac Newton, who was an English physicist and astronomer.

In conclusion, the statement 'the attractive force between two (2) objects depends on their masses and the distance between them' correctly describes  The Universal Law of Gravitation (Option 3).

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Answer:

Someone who writes software or programs for computers is called a programmer.

Explanation:

The spring will stretch 9.3 cm when a 48 N load is suspended from it, provided it doesn't reach its elastic limit.

Hooke's Law states that the force (F) is proportional to the displacement (x) of the spring, with a constant of proportionality called the spring constant (k).The spring constant (k) can be calculated using Hooke's Law: F = kx, where F is the force applied, x is the displacement, and k is the spring constant. In this case, we can solve for k by rearranging the formula: k = F/x.
Substituting the values given, we have:  
k = 36 N / 0.07 m
k = 514.3 N/m
To find out how much the spring will stretch when 48 N is suspended from it, we can use the same formula and solve for x:
x = F/k
x = 48 N / 514.3 N/m
x = 0.093 m
Therefore, the spring will stretch by 9.3 cm when 48 N is suspended from it.

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Starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², the car will travel a distance of approximately 0.2119 meters or 21.19 centimeters in 0.75 seconds.

To determine the distance traveled and the time elapsed by the car starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², we can use the equations of circular motion.

The tangential acceleration is the rate of change of tangential velocity. Since the car starts from rest, its initial tangential velocity is zero (v₀ = 0).

Using the equation:

v = v₀ + at

where v is the final tangential velocity, v₀ is the initial tangential velocity, a is the tangential acceleration, and t is the time, we can solve for v:

v = 0 + (0.75 m/s²) * t

v = 0.75t m/s

The tangential velocity is related to the angular velocity (ω) and the radius (r) of the circular track:

v = ωr

Substituting the values:

0.75t = ω * 300

Since the car starts from rest, the initial angular velocity (ω₀) is zero. So, we have:

ω = ω₀ + αt

ω = 0 + (0.75 m/s²) * t

ω = 0.75t rad/s

We can now substitute the value of ω into the equation:

0.75t = (0.75t) * 300

Simplifying the equation gives:

0.75t = 225t

t = 0.75 seconds

The time elapsed is 0.75 seconds.

To calculate the distance traveled (s), we can use the equation:

s = v₀t + (1/2)at²

Since the initial velocity (v₀) is zero, the equation becomes:

s = (1/2)at²

s = (1/2)(0.75 m/s²)(0.75 s)²

s = (1/2)(0.75 m/s²)(0.5625 s²)

s = 0.2119 meters or approximately 21.19 centimeters

Therefore, the car travels a distance of approximately 0.2119 meters or 21.19 centimeters.

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Answer:

The lever is a movable bar that pivots on a fulcrum attached to a fixed point. The lever operates by applying forces at different distances from the fulcrum, or a pivot. As the lever rotates around the fulcrum, points farther from this pivot move faster than points closer to the pivot.

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real and inverted same size

The renting car that is reported to achieve 10.1 km/L its mileage in miles/gal is: 23.75 miles/gal

To solve this problem, we have to do the conversion of units with the given information.

Information about the problem:

Converting the units from km/L to miles/gal, we get:

10.1 Km/L * (1 miles / 1.60934 km) * (3.785 L  1 gal) = 23.75 miles/gal

10.1 Km/L is equivalent to 23.75 miles/gal

It is the transformation of a value expressed in one unit of measurement into an equivalent value expressed in another unit of measurement of the same nature.

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Complete Question

Consider the heaviest box of 68 kg that you can push at constant speed across a level floor, where the coefficient of kinetic friction is 0.50, and estimate the maximum horizontal force that you can apply to the box. A box sits on a ramp that is inclined at an angle of 50.0 ∘ above the horizontal. The coefficient of kinetic friction between the box and the ramp is 0.50.If you apply the same magnitude force, now parallel to the ramp, that you applied to the box on the floor, what is the heaviest box (in pounds) that you can push up the ramp at constant speed? (In both cases assume you can give enough extra push to get the

Answer:

The force on the heaviest mass  is   \(F = 333.2 \ N\)

The mass on the inclined ramp is  \(M = 76.47 \ kg\)  

Explanation:

From the question we are told that

   The mass of the heaviest box is  \(m = 68 \ kg\)

   The coefficient of kinetic friction is  \(\mu_k = 0.50\)

     The angle at which the ramp is inclined is  \(\theta = 50^o\)

Generally at constant speed the acceleration is zero , which implies that

           \(F - F_f = 0\)

  Here  F is the horizontal  force applied to the heaviest box   and  \(F_f\) is the kinetic frictional  force which is mathematically represented as

        \(F_f = \mu_k * m * g\)

=>     \(F_f = 0.50 * 68 * 9.8\)

=>     \(F_f = 333.2 \ N\)

So

               \(F - 333.2 = 0\)

=>             \(F = 333.2 \ N\)

Considering the ramp inclined at an angle above the horizontal

         Generally apart from the force F  acting on the box in a direction parallel to the ramp the other force acting on the box parallel to the ramp is the net force due to frictional force on the object which is mathematically represented as

         \(F_f_h = \mu Mg cos (\theta )\)

and the weight of the object which is mathematically represented as

            \(F_w = Mg sin (\theta )\)

So the net force is  mathematically evaluated as

       \(F_n = F_w - F_{fh}\)

=>     \(F_n =Mg sin (\theta ) - \mu Mg cos (\theta )\)

=>     \(F_n =M [ 9.8 sin ( 50 )-0.50 * 9.8 cos (50 ) ]\)

=>     \(F_n = 4.3576M \ N\)

So the net force acting on the box parallel to the ramp is  mathematically represented as

      \(F_{net} = F - F_n\)  

=>    \(F_{net} = 333.2- 4.3575M\)  

=>    \(ma = 333.2- 4.3575M\)  

From the question we are told the velocity is  constant so the acceleration is zero  

   =>    \(333.2- 4.3575M = 0\)  

     =>    \(M = 76.47 \ kg\)  

Answer: 80 mph

Explanation: