Answers
Let's assume that the temperature at a point x cm from the high temperature end is T(x). We know that the temperature gradient in the rod is proportional to the rate of heat flow through the rod, which is given by Fourier's law of heat conduction:
q = -kA(dT/dx)
where q is the rate of heat flow, k is the thermal conductivity of copper, A is the cross-sectional area of the rod, and (dT/dx) is the temperature gradient.
Since the rod is in steady state, the rate of heat flow is constant throughout the rod, so we can write:
q = kA(dT/dx) = constant
Integrating both sides with respect to x, we get:
∫(dT/dx)dx = (1/kA)∫qdx
Integrating from 0 to L (where L is the length of the rod), we get:
T(L) - T(0) = (1/kA)qL
Since T(0) = 0°C and T(L) = 20°C, we can write:
20 - 0 = (1/kA)q(60)
Simplifying, we get:
q = 1/3 kA
Now, let's consider a point 20 cm from the high temperature end. We know that the rate of heat flow through the rod is constant, so we can write:
q = -kA(dT/dx)
Substituting the given values, we get:
1/3 kA = -kA (dT/dx) at x = 20
Simplifying, we get:
(dT/dx) = -1/3
Integrating both sides with respect to x, we get:
T(x) = (-1/3)x + C
where C is the constant of integration.
Using the boundary condition that T(0) = 0°C, we get:
C = 0
Therefore, the temperature at a point 20 cm from the high temperature end is:
T(20) = (-1/3)(20) + 20 = 13.3°C
So, the temperature at a point 20cm from the high temperature end is 13.3°C.
Related Questions
Two friends stand at the top of the White Cliffs of Dover in England. One throws a
stone with a velocity of 11 m/s at an angle of 30° above the horizontal off the cliff
and into the water below. The second drops the stone from rest. Both release the
stones at exactly the same time from a height of 110 m above the water. Assuming
no air resistance, how long after the first splash is the second splash?
F
0.60 s
G
1.1 s
H
3.6 s
J
4.7 s
Answers
The second splash is 1.1 s after the first splash.
What is velocity?The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction is displacement.
Given parameters:
Initial velocity of the First stone; u₁ = 11 m/s.
Initial velocity of the Second stone; u₂= 0 m/s.
Height of both cases; h = 110 m.
Acceleration due to gravity; g = 9.8 m/s².
So, If time taken by the first stone is t₁; then
h = u₁t₁ + 1/2 * gt₁²
⇒ 110 = 11 t₁ + 1/2*9.8 t₁²
⇒ 4.9 t₁² + 11 t₁ -110 = 0
So, by solving this quadratic equation we get: t₁ =3.73s.
And if time taken by the second stone is t₂; then
h = 1/2*g t₂²
⇒ t₂ = √(2h/g) = √(2×110/9.8) = 4.74 s.
Hence, the second splash happens after first splash by a time = (4.74 - 3.73) s = 1.01 s = 1.1 second ( approx.).
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A rigid body is rotating with constant angular speed 3 radians per second about a fixed axis through the points A. (4, 1, 1), B. (2, -1; 0), distances being measured in centimeters. The rotation is in the left-handed sense relative to the direction AB
1, Determine the unit vector pointing in the direction BA.
2, What is the angular velocity () of the of the body?
3, Write the position vector of point P: P .
Find the instantaneous velocity of particle P [hint v = w×r)
4, What is meant by left-handed rotation (left-handed coordinate system)?
5, Write the position vectors of points A and B The rotation axis AB has direction BA. Write the direction BA in terms of the components given above.
Answers
1.Unit vector in the direction BA: BA/|BA| = (2/3, 2/3, 1/3)
2.The angular velocity (ω) of the body is given as 3 radians per second.
3.Without the position of point P given, it is not possible to write the position vector of P.
4.Left-handed rotation refers to the direction of rotation where the rotation follows the left-hand rule.
5.Position vector of point A: (4, 1, 1)
Position vector of point B: (2, -1, 0)
The direction vector BA = (-2, -2, -1)
1.To determine the unit vector pointing in the direction BA, we subtract the coordinates of point B from the coordinates of point A and normalize the resulting vector.
The direction vector BA is given by:
BA = (4 - 2, 1 - (-1), 1 - 0) = (2, 2, 1)
To obtain the unit vector in the direction of BA, we divide the direction vector by its magnitude:
|BA| = √(2^2 + 2^2 + 1^2) = √(4 + 4 + 1) = √9 = 3
Unit vector in the direction BA: BA/|BA| = (2/3, 2/3, 1/3)
2.The angular velocity (ω) of the body is given as 3 radians per second.
3.Without the position of point P given, it is not possible to write the position vector of P. Please provide the position of point P to proceed with the calculation.
4.Left-handed rotation refers to the direction of rotation where the rotation follows the left-hand rule. In a left-handed coordinate system, if you curl the fingers of your left hand in the direction of rotation, your thumb will point in the direction of the rotation axis. It is the opposite direction to a right-handed rotation.
5.The position vectors of points A and B are:
Position vector of point A: (4, 1, 1)
Position vector of point B: (2, -1, 0)
The direction vector BA can be obtained by subtracting the coordinates of point A from the coordinates of point B:
BA = (2 - 4, -1 - 1, 0 - 1) = (-2, -2, -1)
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Question 7 part b: if a force of 50.0 N is continuously applied once once the box is in motion. What will be it’s acceleration
Answers
ANSWER:
STEP-BY-STEP EXPLANATION:
We know that the force is equal to the following:
\(\begin{gathered} F=m\cdot a \\ F=300\text{ N} \\ a\text{ = 9.8 m/s} \end{gathered}\)We know that the force is equal to the following:
\(undefined\)Find the vector whose magnitude is 5 and which is in the direction of the vector 4i -3j +k
Answers
The vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.
To solve this problemThe given vector can be normalized before being multiplied by the desired magnitude. This is how to locate the vector:
The vector that has been provided should be normalized by dividing each of its components by its magnitude. The Pythagorean theorem can be used to determine the magnitude of the vector 4i - 3j + k:
Magnitude = √(4² + (-3)² + 1²) = √(16 + 9 + 1) = √26
Normalize the vector by dividing each component by the magnitude:
Normalized vector = (4/√26)i + (-3/√26)j + (1/√26)k
Multiply the normalized vector by the desired magnitude:
To obtain a vector with a magnitude of 5, multiply each component of the normalized vector by 5:
Desired vector = 5 * ((4/√26)i + (-3/√26)j + (1/√26)k)
Simplifying the expression gives:
Desired vector ≈ (20/√26)i + (-15/√26)j + (5/√26)k
So, the vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.
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in a young's double-slit experiment the center of a bright fringe occurs wherever waves from the slits differ in the distance they travel by a multiple of
Answers
Answer:
The path difference will be zero.
Explanation:
Given that,
In a young's double-slit experiment the center of a bright fringe occurs wherever waves from the slits differ in the distance.
Suppose, we find the multiple of wavelength
In young's double slit experiment,
We need to calculate the multiple of wavelength
Using formula of path difference
\(\Delta x=d\sin\theta\)....(I)
\(d\sin\theta=m\lambda\)
Where, m = fringe number
\(\lambda\) = wavelength
For center of a bright fringe ,
m = 0
Put the value into the formula
\(d\sin\theta=0\times\lambda\)
\(d\sin\theta=0\)
Put the value in equation (I)
\(\Delta x=0\)
Hence, The path difference will be zero.
A fish tank is 20 inches by 12 inches by 12 inches. What is its volume in m * m ^ 3
Answers
As the fish tank is 20 inches by 12 inches by 12 inches, its volume is 47194744.32 mm³.
What is volume?The space that any three-dimensional solid occupies is known as its volume. These solids can take the form of a cube, cuboid, cone, cylinder, or sphere.
1 inch = 0.0254 meters.
20 inches = 20 × 0.0254 meters = 0.508 meters = 508 mm.
12 inches = 12 × 0.0254 meters = 0.3048 meters = 304.8 mm.
Hence, The volume of the fish tank = length × width × height
= 508 mm × 304.8 mm × 304.8 mm.
= 47194744.32 mm³
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What precise meaning do you attach to the statement r = (24.0 ± 0.3) mm, where r is the radius of a tube.
Answers
The information provided above demonstrates that the range of the tube's radius within which we are certain is from 23.7 to 24.3.
Accurate findings are desired when any quantity is being measured. Closeness of the measurements to a particular value is referred to as accuracy (like the theoretical value). It is not insignificant that measurements can contain inaccuracies; as a result, the outcome frequently includes a margin error. The sentence above displays the radius's measured value along with its margin of error.
In other words, the aforementioned statement represents a quantity's numerical value along with its tolerance, or the only permissible (and conceivable) values to ensure that the measurement is accurate. The information provided above demonstrates that the range of the tube's radius within which we are certain is from 23.7 to 24.3.
These are all valid radius values, along with all others within this interval. By increasing the number of trials in a measurement, the value for the upper and lower bounds of the error can be decreased.
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A torque of T= 4Nm is required to rotate the intermediate cylinder at W= 30 rad/min .
Calculate the viscosity of the
oil. All cylinders are 450 mm long. Neglect the end effects.
R=0.15m, t=0.003 m.
Result: 1.258 N.s/m
Answers
The viscosity of the oil with a torque 4Nm and a rotational speed is 30 rpm is 0.2003 N.s/m.
From the given,
torque = 4Nm
rotational speed = 30 rpm = (30 × 3.14)/60 = 3.14 rad/sec
radius = 0.15 m
thickness (h) = 0.003 m
To find linear velocity,
V = R×ω
= 0.15×3.14
V =0.471 m/s
The dragging force,
F = 2μA(V/h) (V is linear velocity and h is the thickness )
Area = area of cylinder = 2πRH, R is radius and H is the height of the cylinder.
F = 2μ(2πRH) (V/h)
= 2μ(2×3.14×0.15×0.45) (0.471/0.003)
= 133.10 μ (μ is the viscosity of the oil)
F = 133.1μ
Torque (τ) = Force × radius
4 Nm = 133.1μ × 0.15
μ = 4 / (133.1×0.15)
= 0.2003 N.s/m
The viscosity of the oil is 0.2003 N.s/m.
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What do astronomers refer to as the retrograde motion of the planets? A. apparent movement of the planets eastward in a single night B. apparent movement of the planets westward in a single night C. apparent movement of the planets eastward from night to night D. apparent movement of the planets westward from night to night
Answers
Astronomers refer to as retrograde motion of the planets to an apparent movement of the planets westward from night to night.
What is a retrograde motion?The retrograde movement or the retrogradation of the planets is the apparent movement that a planet makes in the opposite direction to the other bodies that make up the system where it is.
This movement is actually an optical illusion that occurs due to the difference in speed between the different planets, looking as if one of them were moving backwards from east to west.
Therefore, we can confirm that the correct answer is option D. apparent movement of the planets westward from night to night.
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A scientist makes a model of Earth's water by drawing 100 drops of water, all the same size. How many of the 100 drops represent ocean water?
A.3
B.50
C.75
D.97
Answers
Answer:
D
Explanation:
If the water represents the oceans water then you'd would need to calculate how much of earth is water (96.5)
Which direction do longitudinal waves travel?
Answers
Answer:
If the particles of the medium vibrate in a direction parallel to the direction of propagation of the wave, it is called a longitudinal wave. In longitudinal waves, the particle movement is parallel to the direction of wave propagation.
Explanation:
A skydiver falls toward the ground at a constant velocity. Which statement best applies Newton’s laws of motion to explain the skydiver’s motion?
Answers
Answer:
A: An upward force balances the downward force of gravity on the skydiver.
Explanation:
on edge! hope this helps!!~ (⌒▽⌒)☆
A flywheel having constant angular acceleration requires 4.00 ss to rotate through 164 radrad . Its angular velocity at the end of this time is 106 rad/srad/s . Find the angular velocity at the beginning of the 4.00 ss interval; the angular acceleration of the flywheel. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Rotation of a bicycle wheel.
Answers
Answer:
\(\omega '=-13.5rad/s\)
Explanation:
From the question we are told that:
Time \(t=4sec\)
Angular displacement \(\theta= 161 rad\)
Final Angular velocity \(\omega = 100 rad / s\)
Let
Angular acceleration \(\alpha\)
Generally the equation for Initial Angular velocity \(\omega '\) is mathematically given by
\(-\omega '^2=2 \alpha \theta -\omega^2\)
\(\omega '^2= \alpha 328 +11236\)
Also,Initial Angular velocity \(\omega '\) is mathematically given by
\(\omega '=\omega - \alpha t\)
Therefore substitution
\(-\omega '^2=2 \alpha \theta -\omega^2\)
\(\omega '=\omega - \alpha t\)
\((\omega - \alpha t)^2=2 \alpha \theta -\omega\)
\(-16\alpha^2+848\alpha+11236= \alpha 328 -11236\)
\(16\alpha^2-520\alpha=0\)
\(\alpha=29.875rads/s^2\)
Substitution in the 2nd equation for Initial Angular velocity \(\omega '\)
\(\omega '=106-(29.875rads/s^2*4)\)
\(\omega '=-13.5rad/s\)
A ball at the end of a string of length 2m rotates at a constant speed in a horizontal circle. It makes 7 rev/s.
What is the period of the ball’s motion? Answer in units of s.
second part
What is the frequency of the motion? Answer in units of Hz.
third part
What is the ball’s angular velocity? Answer in units of rad/s.
Answers
The time period of the ball’s motion will be 0.14 seconds
The frequency of the motion will be 7 Hz
The ball’s angular velocity will be 43.96 rad/second
given
a) frequency = 7 rev / s = 7 Hz
time period = 1 / frequency
= 1 / 7 = 0.14 seconds
The period of the ball’s motion will be 0.14 seconds
b) The frequency will be 7 Hz
c) The ball’s angular velocity = 2 * π * f
= 2 * 3.14 * 7 = 43.96 rad/second
The ball’s angular velocity will be 43.96 rad/second
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In what way dose ocean water move globally
Answers
Answer: Letter A. Along cold water currents from the poles to the equator. Apex
Explanation:
Explanation:
The great ocean conveyor moves water around the globe. ... There is constant motion in the ocean in the form of a global ocean conveyor belt. This motion is caused by a combination of thermohaline currents (thermo = temperature; haline = salinity) in the deep ocean and wind-driven currents on the surface.
Before a collision, a 25 kg object is moving at 12 m/s to the right. After a collision with stationary box, the 25 kg object moves at 8 m/s to the right. What is the resulting momentum of the box?
Answers
The initial momentum of the 25 kg object is 25 kg * 12 m/s = 300 kgm/s. After the collision, the momentum of the 25 kg object is 25 kg * 8 m/s = 200 kgm/s. According to the conservation of momentum, the momentum lost by the 25 kg object is equal to the momentum gained by the box. Therefore, the resulting momentum of the box is 300 kgm/s - 200 kgm/s = 100 kg*m/s.
3% of earth's water is?
Answers
Is earth’s freshwater
Only about 3 percent of Earth’s water is fresh water.
At a weightlifting competition two competitors list of the same way to the same height the second competitor accomplished to live two seconds faster than the first competitor this demonstrates that the second competitor had one more
Answers
please help me there
Answers
Answer:
when switch is off no electricity will flow and then the circuit is called an open circuit
Explanation:
Electricity will not flow in open circuit
prove that young modulus of elasticity and pressure have the same dimensions
Answers
Answer:
The dimensions of Young's Modulus, as well as material stress, are the same as pressure because stress is like pressure in a solid, except with some key differences that warrant the use of different terminology.
a car travelling at 18 km/hr accelerates uniformly at 2m per seconds square. calculate its velocity in km/hr in 5 seconds
Answers
1 km = 1000 m
1 hr = 3600 s
So, 18 km/hr = (18 * 1000) / (3600) m/s = 5 m/s
And 2 m/s^2 = 2 m/s^2
Now, we can use the formula for final velocity (v) when an object starts with an initial velocity (u) and accelerates at a constant rate (a) for a given time (t):
v = u + at
Plugging in the values, we get:
v = 5 + (2 * 5) m/s v = 15 m/s
To convert this back to km/hr, we use the inverse conversions: v = (15 * 3600) / (1000) km/hr v = 54 km/hr
Therefore, the car’s velocity in km/hr after 5 seconds is 54 km/hr.
7. A rock of mass 5 kg is pushed over the edge of a cliff which is 200 m high. a) Ignore air resistance and calculate the speed of the rock at the bottom of the cliff. In reality, air resistance cannot be ignored. The rock eventually reaches terminal velocity of 30 m.s-¹.
b) Calculate the kinetic energy of the rock at the bottom of the cliff.
c) Calculate the work done by air resistance.
d) Calculate the average force exerted by the air on the rock.
Answers
Speed of the rock at the bottom of the cliff is 44.3 m/s.
Kinetic energy of the rock at the bottom of the cliff is 4915 J.
Work done by air resistance is -2250 J
Average force exerted by the air on the rock is 11.25 N.
How to determine kinetic energy and speed?a) The speed of the rock at the bottom of the cliff can be calculated using the equation:
v = √(2gh)
where v = final velocity, g = acceleration due to gravity (9.81 m/s²), and h = height of the cliff (200 m).
Plugging in the values:
v = √(2 x 9.81 x 200) = 44.3 m/s
Therefore, the speed of the rock at the bottom of the cliff is 44.3 m/s.
b) The kinetic energy of the rock at the bottom of the cliff can be calculated using the equation:
KE = (1/2)mv²
where KE = kinetic energy, m = mass of the rock (5 kg), and v = velocity (44.3 m/s).
Plugging in the values:
KE = (1/2) x 5 x (44.3)² = 4915 J
Therefore, the kinetic energy of the rock at the bottom of the cliff is 4915 J.
c) The work done by air resistance can be calculated using the work-energy principle:
Work done by air resistance = KE_initial - KE_final
where KE_initial = initial kinetic energy of the rock, and KE_final = final kinetic energy of the rock (at terminal velocity).
Since the rock was initially at rest, its initial kinetic energy is zero. At terminal velocity, the kinetic energy of the rock is:
KE_final = (1/2)mv_terminal²
where m = mass of the rock (5 kg), and v_terminal = terminal velocity (30 m/s).
Plugging in the values:
KE_final = (1/2) x 5 x (30)² = 2250 J
Therefore, the work done by air resistance is:
Work done by air resistance = 0 - 2250 = -2250 J
The negative sign indicates that the work done by air resistance is in the opposite direction to the motion of the rock.
d) The average force exerted by the air on the rock can be calculated using the equation:
Work done by air resistance = Force x Distance
where Force = average force exerted by air on the rock, and Distance = distance travelled by the rock.
Rearrange the equation to solve for Force:
Force = Work done by air resistance / Distance
Plugging in the values:
Force = -2250 / 200 = -11.25 N
Therefore, the average force exerted by the air on the rock is 11.25 N. The negative sign indicates that the force is in the opposite direction to the motion of the rock.
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The mixing entropy formula derived in the previous problem actually applies to any ideal gas, and to some dense gases, liquids, and solids as well. For the denser systems, we have to assume that the two types of molecules are the same size and that molecules of different types interact with each other in the same way as molecules of the same type (same forces, etc.). Such a system is called an ideal mixture. Explain why, for an ideal mixture.
Answers
For an ideal mixture of two or more substances, the mixing entropy can be derived based on the same principles as for ideal gases. The reason is that ideal mixtures also have particles that are in constant random motion, and the entropy of mixing is still related to the number of possible ways the particles can be arranged.
Ideal mixture explained.
In an ideal mixture, the assumption is that the molecules of different substances are the same size and shape, and have the same intermolecular forces with each other as they do with their own kind. This means that there are no attractive or repulsive forces between particles of different types, which simplifies the calculation of the entropy of mixing.
The mixing entropy of an ideal mixture is determined by the number of possible ways the molecules of the two substances can be distributed among the available volume. Just as in the case of ideal gases, this leads to an increase in entropy when the two substances are mixed, as there are more ways to distribute the molecules than when they are separated.
Therefore, the concept of an ideal mixture allows us to apply the same principles of thermodynamics to denser systems as we do for ideal gases, which makes it a useful tool for studying a wide range of physical and chemical processes involving mixtures.
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The mixing entropy formula applies to ideal mixtures because there are no intermolecular forces between different species, there are no volume changes upon mixing, and the mixing is completely random.
What is Ideal Mixing Entropy Formula?An ideal mixture is a hypothetical mixture of gases, liquids or solids where the components are assumed to behave as an ideal gas, and where the two types of molecules are the same size and interact with each other in the same way as molecules of the same type (same forces, etc.). In an ideal mixture, the mixing entropy formula applies due to the following reasons:
No intermolecular forces between different species: In an ideal mixture, the molecules of the different components do not attract or repel each other. This means that the interactions between the different species are negligible and the enthalpy of mixing is zero.No volume changes upon mixing: In an ideal mixture, the components have the same size and shape, and the volume of the mixture is equal to the sum of the volumes of the individual components. Therefore, there are no volume changes upon mixing, and the entropy of mixing is solely dependent on the number of ways of arranging the molecules.Random mixing: The assumption of ideal mixing also implies that the mixing is completely random, with no preferential interactions between the different species. This means that the entropy of mixing is solely dependent on the number of ways the molecules can be arranged, and this is given by the mixing entropy formula.Therefore, the mixing entropy formula applies to ideal mixtures because there are no intermolecular forces between different species, there are no volume changes upon mixing, and the mixing is completely random.
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Find the displacement of a simple harmonic wave of amplitude 6.44 m at t = 0.71 s. Assume that the wave number is 2.34 m-1, the angular frequency is 2.88 rad/s, and that the wave is propagating in the +x direction at x = 1.21 m.
A) 4.55 m.
B) 1.05 m.
C) 3.54 m.
D) 2.25 m.
Answers
Answer:
Letter A. \(y=4.55 m\)
Explanation:
Let's use the wave equation:
\(y=Asin(kx-\omega t)\)
A is the amplitude (A=6.44 m)t is the time (t=0.71 s)k is the wave number (k=2.34 1/m)ω is the angular frequency (ω=2.88 rad/s)x is the propagation of the x direction (x=1.21 m)Therefore the displacement y will be:
\(y=6.44*sin(2.34*1.21-2.88*0.71)\)
\(y=4.55 m\)
The answer is letter A.
I hope it helps you!
Answer:
Explanation:
Find the displacement of a simple harmonic wave of amplitude 6.44 m at t = 0.71 s. Assume that the wave number is 2.34 m-1, the angular frequency is 2.88 rad/s, and that the wave is propagating in the +x direction at x = 1.21 m.
Amplitude (A) of the simple harmonic wave = 6.44 m
wave number (k) of the given wave = 2.34 m-1
Angular frequency (ω) of the given wave = 2.88 rad/s
Displacement x = 1.21 m and time t = 0.71 s
Then the general equation for the displacement of the given simple harmonic wave at given x and time t is given by
y = Asin(kx - ωt)
= (6.44 m)sin[(2.34 m-1)(1.21 m) - (2.88 rad/s)(0.71 s)]
Y=6.44sin(0.7866 rad)
0.7866rad*(180 degrees/pi rad) =45.1
Y=6.44sin(45.1)
Y=4.55m
A gas expands from I to F in the figure. The energy added to the gas by heat is 465 J when the gas goes from I to F along the diagonal path. What is the change in internal energy of the gas?
Answers
The gas's internal energy that expands from I to F changes by 1015 J.
How to determine internal energy?Since the gas is expanding and energy is added to it by heat, the change in internal energy of the gas can be calculated using the first law of thermodynamics, which states that:
ΔU = Q - W
where ΔU = change in internal energy,
Q = heat added to the system, 465 J and
W = work done by the system.
Assuming that the process is quasi-static use approximation known as the "staircase approximation."
By adding up the work done in each step, find that the total work done by the gas is approximately -550 J. The negative sign indicates that work is done on the gas.
Therefore, using the first law of thermodynamics, we can calculate the change in internal energy of the gas as:
ΔU = Q - W
ΔU = 465 J - (-550 J)
ΔU = 1015 J
Therefore, the change in internal energy of the gas is 1015 J.
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A woman weighs 129 lb. If she is standing on a spring scale in an elevator that is traveling downward, but slowing up, the scale will read:___________.
A) more than 129 lb
B) 129 lb
C) less than 129 lb
D) It is impossible to answer this question without knowing the acceleration of the elevator.
Answers
Answer:
C) less than 129 lb.
Explanation:
Let the elevator be slowing up with magnitude of a . That means it is accelerating downwards with magnitude a .
If R be the reaction force
For the elevator is going downwards with acceleration a
mg - R = ma
R = mg - ma
R measures its apparent weight . Spring scale will measure his apparent weight.
So its apparent weight is less than 129 lb .
a small block of mass m slides on a horizontal frictionlesssurface as it travels around the inside of a hoop of radiusr. the coefficient of friction between the block and the wallis u; therefore, the speed v of the block decreases. in termsof m, r, u, and v, find expressions for each of thefollowing.
Answers
The expressions are \(F = m g\) , \(F = \frac{m v^{2} }{r}\).
The frictional force: This force opposes motion and is created as a result of friction between two surfaces.
\(F = m g\)
where m is the object's mass and g is the acceleration brought on by gravity, is a formula for expressing the frictional force.
The centripetal force: To keep an object moving in a circular path, the centripetal force, which is directed toward the centre of the path, must be present.
\(F = \frac{m v^{2} }{r}\)
where m is the object's mass, v is its speed, and r is its circular path's radius, is a formula for the centripetal force.
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Phobos, one of the moons of Mars, orbits at a distance of 9378 km from the center of the red planet.
Part A What is the orbital period of Phobos?
Answers
The orbital period of Phobos is 7.66 hours.
What is orbital period?The orbital period also known as the revolution period is the amount of time it takes an astronomical object to complete one orbit around another. It usually refers to planets or asteroids orbiting the Sun, moons orbiting planets, exoplanets orbiting other stars, or binary stars in astronomy.
It will be calculated thus:
T^2 = (4π)^2( d^3) / ((G)(Mm))
where d is the distance in meters, 9.378 x 10^6 meters
(4π)^2 = 39.5
G = 6.67 x 10^-11 m^3 kg^-2 s^-2
Mm = the mass of Mars in kg which is 6.42 x 10^23 kg.
T^2 = 7.61 x 10^8 sec^2
Find the square root.
T = 2.76 x 10^4 sec
T = 7.66 hours
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As you brake your bicycle, your velocity changes from 20 m/s east to 10 m/s east in 5 seconds. What’s your acceleration?
Answers
Hello!
\(\large\boxed{-2m/s^{2} }\)
Find the acceleration using the formula a = (vf - vi) / t where:
vf = final velocity
vi = initial velocity
t = time
Plug in the points above:
vf = +10 m/s
vi = +20 m/s
t = 5 sec
(10 - 20) / 5 = -10 / 5 = -2 m/s²
A wave of frequency 13000Hz travel 1300m in 4.0 seconds, what is the wavelength of the wave
Answers
Explanation:
v = 1300/ 4
v = 325m/s
wavelength = 325/13000
=0.025 m