Answer:
Explanation:
range of projectile = u² sin2θ / g
u = 30 m /s
θ = 40°
range = 30² x sin 80 / 9.8
= 90.44 m
b )
maximum altitude H = u² sin²θ / 2 x g
= 30² sin²40 / 9.8
= 37.94 m .
An object with a mass of 7 kg accelerates 8 m/s2 when an unknown force is applied to it. What is the amount of the force?
The amount of force applied to the 7kg object that caused it to accelerate at 8m/s² is 56 newtons.
What is the force applied to the object?A force is simply a push or a pull of an object resulting from the object's interaction with another object.
From newton's second law;
Force = mass × acceleration
Given the data in the question;
Mass of the object = 7kgAcceleration = 8m/s²Applied force = ?Plug the given values into the formula to determine the applied force.
Force = mass × acceleration
Force = 7kg × 8m/s²
Force = 56kgm/s²
Force = 56 N
Therefore, the applied force is 56 newtons.
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True or False: There are exceptions to Newton's 1st and 3rd Laws.
The given statement is a false statement.
No, there are no exceptions to Newton's first and third laws.
Studying close relatives allows behavarial genetistics to determine
Behavioral geneticists can ascertain how genes affect the environment and population by examining close relatives. Additional explanation Individual variances result from variations in hereditary variables.
Gender, disorders/diseases, blood type, and other characteristics that each person possesses can be handed down to their offspring. The expansion of the human population is facilitated by these genetic variations. The carrying capacity of the ecosystem is influenced by the population. The ability of the environment to provide the resources it possesses for a creature's life within reasonable bounds is known as carrying capacity. Environmental issues will arise if the population surpasses the carrying capacity of the resources generated or made available.
These issues include a lack of available natural resources, the growth of pollution, or competition for scarce natural resources. so that initiatives to manage or control the environment, such as recycling or processing industrial waste, can be made. To lessen environmental exploitation that affects the entire human population, the study of human behavior based on the nature of genes will be helpful. Studying close relatives enables behavioral geneticists to ascertain the effect of humans from the nature of their genes on the carrying capacity of the environment and their effect on living populations. The population of quality and productive human resources will have a positive impact on the environment.
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What do we call the central ridge that divides the ocean floor into two parts?
A) It is a seamount.
B) It is a mountain ridge.
C) It is the Great Divide.
D) It is the mid-ocean ridge.
Answer:
D
Explanation:
Given a ball with a mass of 2.00 kg at a height of 12.00 m from the ground, a ball with a mass of 2.00 kg at a height of 7.00 m from the ground, and a ball with a mass of 4.00 kg with a height of 5.00 m from the ground. Which of these masses have the largest gravitational potential energy relative to the ground? A) 2.00 kg at 12.0 mB) 2.00 kg at 7.00mC) 4.00 at 5.00 mD)both the 2.00 kg have the same highest energy E) all do these masses have the same energy
U=The potential energy is given by:
\(U=mgh\)To determine which mass has the greater potential energy we calculate the energy for each of them.
Mass of 2 kg at 12 m height:
\(U=(2)(9.8)(12)=235.2\)Mass of 2 kg at 7 m height:
\(U=(2)(9.8)(7)=137.2\)Mass of 4 kg at 5 m height:
\(U=(4)(9.8)(5)=196\)From the energies we calculated we notice that the 2 kg mass at a height of 12 m has the largest potential energy, therefore the answer is A
An object is placed in material a at point P, as shown in the diagram. The light is refracted when it strikes the interface with material b. When viewed from material b, at which point will the image appear?
The semi major axis of an orbiting body is 3.01 AU. What is the period of this object's orbit?
a 6.01 years
b 5.01 years
c 4.97 years
d 5.22 years
Answer: 4.97 years
Explanation: I got the answers right
By the use of the Kepler's laws, the period of the orbit is 5.22 years. Option D
What is the period?We know that when we are dealing with the orbits that our mind would have to be turned to the Kepler's law. In the Keplers law, we see the relationship that cold be used in the attempt to connect the period of the orbit to the radius of the semi major axis of an orbiting body.
By the application of the Keplers third law;
T^2 = r^3
The statement of the law is that the square of the period of the objects orbit is equal to the cube of the length of the semi major axis.
We then know that;
T = period
r = distance
Hence;
T = r^3/2
T = (3.01 )^3/2
T = 5.22 years
The period of the object is seen to be 5.22 years from the calculation above.
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Each value measured in nature has a number value, called its magnitude, and
a dimension, or
Answer here
Answer:
yassssssssssssssssssssssssssssssssssssss
Explanation:
A locust jumps at an angle of 55.0° and lands 0.750 m from where it jumped.
Aproximately 1.09 m/s was the locust's first speed.
What role do vectors have in mechanics?In engineering mechanics, vectors are used to express values with both a magnitude and a direction. For analysis, vector representations of a variety of engineering quantities—including forces, displacements, velocities, and accelerations—are required.
Δy = vsin(θ)t - 0.5gt²
0 = v*sin(55°)t - 0.5(-9.81 m/s²)*t²
t = 2vsin(55°)/g
Now, we can use the horizontal motion of the locust to find the initial velocity v. The horizontal distance traveled by the locust is given by:
Δx = v*cos(55°)*t
Substituting the expression for t that we just found:
0.750 m = vcos(55°)2vsin(55°)/g
Solving for v:
v = √(0.750 mg/(2sin(55°)*cos(55°)))
v ≈ 1.09 m/s
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Very Important, I need the answer
Answer:
A
Explanation:
A constant velocity means the position graph has a constant slope. It's a straight line sloping up.
A 0.6 kg basketball is 3.0 high calculate its potential Energy PE=mgh
What is the momentum of a tiger that has a mass of 81 kg and runs with a velocity of 5.4 m/s to the east
Given :
Mass of tiger , m = 81 kg .
Velocity of tiger , v = 5.4 m/s .
To Find :
The momentum of tiger .
Solution :
We know , momentum of a body is given by the product of its mass and velocity .
\(P=m\times v\)
Now , putting value of m and v in above equation , we get :
\(P=m\times v\\\\P=81\times 5.4 \ kg\ m/s\\\\P=437.4 \ kg\ m/s\)
Therefore , the momentum of tiger is 437.4 kg m/s .
Hence , this is the required solution .
Answer:
437.4
Explanation: did the math
An electric field is represented by the force on which particle?
O a neutron
O a dipole
O a negative test charge
O a positive test charge
Answer:
a positive test charge
Explanation:
Got it right on edge 2021
A car traveling 93 km/h is 240 m behind a truck traveling 74 km/h . How long will it take the car to reach the truck?
When the automobile arrives at the truck, the two distance functions are equal.
95t−0.210=75t
95t−75t=0.210
25t=0.210
t=0.210
25t=0.0084 hr = 0.504 min = 30.24 s
How fast does light travel in air?Light always moves in a straight line. Light in air travels at 1.0003 times the speed of light in a vacuum, slowing it from 299,792,458 metres per second to 299,702,547 metres per second.
Homepage for Einstein's Big Idea. E = mc2. It's the most famous equation in the world, "Mass multiplied by the speed of light squared equals energy." On the most fundamental level, the equation states that energy and mass (matter) are interchangeable; they are various manifestations of the same thing.
The distance a wave travels in a particular length of time, such as the number of metres per second, is referred to as its wave speed.
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Answer:
t=45.4717
Explanation:
Find the speed of the car
93km/h x 1000m/1km x 1hr/3600s =25.833
Find the speed of the truck
74km/h x 1000m/1km x 1hr/3600s=20.555
(25.833-20.555)t=240
t=45.4717
A spherical shell with a net charge of 3Q surrounds a point charge of -q at the center of the shell. The charges on the inner and outer surfaces of the shell are:
Answer:
1) The charge on the outer shell is +4·Q
2) The charge on the inner shell is +Q
Explanation:
1) The given parameters of the spherical shell are;
The net charge on the spherical shell = 3·Q
The point charge surrounded by the spherical shell = -Q
Let 'x' represent the charge on the outer shell, and let 'y', represent the charge on the inner shell, we have;
The net charge, 3·Q = -q + x
∴ x = 3·Q + Q = 4·Q
The charge on the outer shell, x = 4·Q
2) The net charge in the shell is zero, therefore, the charge on the inner shell, 'y', is given as follows;
-Q + y = 0
∴ y = +Q
The charge on the inner shell, y = +Q
Explain how heat is related to temperature and thermal energy...
PLEASE NO COPY AND PASTE DO IT IN YOUR OWN WORDS
PLEASEEEE HELP MEEEE!!
Answer:
Thermal energy is directly related to heat because thermal energy is how heat is transfered.
If you dropped a ball on the surface of Katar, what rate would it accelerate toward the ground
Acceleration describes the speed and direction changes in velocity over time. Acceleration refers to the change in speed or direction of an item or point travelling straight forward. Due to the constant change in direction, motion on a circle accelerates even while the speed is constant.
The rate at which an object's velocity changes in relation to time is known as acceleration. The vector quantity of accelerations. The direction of the net force that is acting on an object determines its acceleration.
The formula a = v/t denotes acceleration (a), which is the product of the change in velocity (v) and the change in time (t). Using metres per second squared (m/s²), you can gauge how quickly velocity varies.
Acceleration due to gravity on earth = 9.8 m/s²
Therefore, the rate at which the ball will fall on the Katar is 9.8m/s²
Gravitational acceleration is the acceleration that an object experiences as a result of the gravitational field. It has the SI unit m/s². It is a vector quantity since it has both magnitude and direction. g is a unit used to measure gravitational acceleration. 9.8 m/s² is the standard value of g at sea level on the surface of the earth.
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One atomic mass unit is defined as 1.66 x 10^-27 kg. If a proton has a mass of one atomic mass unit and a density of approximately 5.8 x 10^27 kg/m3^ . What is the diameter of a proton if we assume it is a sphere?
Answer:
The diameter is \(d = 8.18*10^{-19} \ m\)
Explanation:
From the question we are told that
The value of one atomic mass unit is \(u = 1.66 *10^{-27} \ kg\)
The density of the proton is \(\rho = 5.8 *10^{27} \ kg/m^3\)
Generally the volume of the proton (sphere)is mathematically represented as
\(V = \frac{4}{3} * \pi * r^3\)
Generally this volume can also be evaluated as
\(V = \frac{u}{\rho}\)
=> \(V = \frac{1.66 *10^{-27}}{5.8*10^{27}}\)
=> \(V = 2.862 *10^{-55} \ m^3\)
So
\(2.862 *10^{-55} = \frac{4}{3} * 3.142 * r^3\)
=> \(r^3 = 6.832 *10^{-56}\)
=> \(r = 4.088 *10^{-19} \ m\)
Now the diameter is mathematically represented as
\(d = 2 * r\)
=> \(d = 2 * 4.088 *10^{-19}\)
=> \(d = 8.18*10^{-19} \ m\)
The amount of thermal energy transferred between objects depends only on their masses and initial and final temperatures.
Question 17 options:
True
False
Answer:
False
Explanation:
The amount of energy transferred between objects not only depend on their masses, initial and final temperatures but also on their specific heat capacity.
The specific heat capacity plays an important role in ascertaining the amount of thermal energy a body can conduct.
Specific heat capacity is the amount of heat required to raise the temperature of 1kg of a substance by 1kelvin. This property is an intensive property of any matter and it determines to a large extent, how far matter are able to transfer energy.The equation;
H = m c Ф
where H is the amount of heat
m is the mass
c is the specific heat capacity
Ф is the change in temperature;
is used to find the amount of heat of a substance.
Answer:
false
Explanation:
Because the amount of energy is transferred between objects not only depend on their masses, initial and final temperatures but also on their specific heat capacity.
Hopes this helps you and it’s correct because I had this question on edgenuity
Which is the correct Lewis structure for carbon monoxide?
А. А
В. B
С. С
D. D
Answer: Choice B
There are triple bonds between the carbon (C) and oxygen (O) atoms. Then there are 2 dots on either side
==========================================================
Explanation:
When it comes to interaction and chemistry, all that matters is the valence shell or valence electrons. This is the outermost shell. This is because various elements do not interact with the inner electrons (they're locked in place so to speak and don't move to other elements).
Carbon has 6 protons, which is what uniquely makes up this element. This means there are 6 electrons. The inner shell has 2 electrons and the valence shell has 4 electrons. Two electrons are shown as the two blue dots on the left side of the C. The other two electrons form two of the lines, or the bonds, between the C and O.
-------------
Oxygen has 8 protons and 8 electrons. It has 2 electrons in the inner shell and 6 electrons in the valence shell. Two of those electrons are the red dots on the right side of the O. The other 4 electrons are shared to form the bonds with the carbon atom.
This is where things get a bit tricky. I've shown a diagram below indicating that one of the oxygen electrons (red dot) is passed to the carbon, as this carbon atom is pulling on the oxygen electron. But the oxygen atom is pulling on it as well, which forms one of the triple bonds.
So this is why diagram B is the final answer. This is something you can logically determine (remembering the rules of how each electron shell is formed), or it's something you'll need to memorize. In the real world, it's easy to forget a lot of info like this, so that's why having it handy as a lookup reference is preferable.
consider an electric dipole lying along x-axis with mid-point O as the origin of coordinate system.find the electric potential V at point P due to dipole.in addition to this,find electric potentials for special cases. when P lies on the axial line and when P lies on the equatorial line.
Answer:
axial V = 0
equatorial V = k q 2a / (x² -a²), V = k q 2x / (a² -x²)
Explanation:
A dipole is a system formed by two charges of equal magnitude, but different sign, separated by a distance 2a; let's look for the electrical potential in an axial line
V = k (q / √(a² + y²) - q /√ (a² + y²))
V = 0
the potential on the equator
we place the positive charge to the left and perform the calculation for a point outside the dipole
V = k (q / (x-a) - q / (x + a))
V = k q 2a / (x² -a²)
we perform the calculation for a point between the dipo charges
V = k (q / (a-x) - q / (a + x))
V = k q 2x / (a² -x²)
Two vectors are being added, one at an angle of 20.0 , and the other at 80.0. The only thing you know about the magnitudes is they are both positive. Will the equilibrant vector be in the:
a. first quadrant
b. second quadrant
c. third quadrant
d. fourth quadrant
e. you cannot tell which quadrant from the available information
Answer:a
Explanation: they are all positive
The equivalent vectors of both the vectors lie in the first quadrant. So, the right choice is a. first quadrant.
How the resultant of the vectors can be calculated?The resultant of the vectors can be calculated using the Parallelogram theorem of vector addition. In this theorem, a parallelogram is formed using the vectors, having the vectors as the adjacent side and the diagonal of this parallelogram is the resultant of both the vectors.
How the theorem is implemented to find out the resultant?The vectors A and B are drawn at the given angle, angles of 20° and 80° respectively. Using the vectors, A and B, the dotted parallelogram is drawn, and the vector C is the resultant.
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Water flows at a speed of 13 m/s through a pipe that has a diameter of 1.2 m. What is the
diameter of the smaller end of the pipe that the water comes out with a speed of 30 m/s?
The diameter of the smaller end of the pipe is approximately 0.78 meters.
To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.
The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity
Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2
Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2
Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30
Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30
0.36 * 13 = (diameter2/2)^2 * 30
4.68 = (diameter2/2)^2 * 30
Dividing both sides by 30:
0.156 = (diameter2/2)^2
Taking the square root of both sides:
0.39 = diameter2/2
Multiplying both sides by 2:
0.78 = diameter2
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Plz Help
A ball is dropped from the top of a building.
When does the ball have the most kinetic energy?
A. After it has hit the ground
B. Half way through the fall
C. As it is released
D. Just before it hits the ground
Answer:
D
Explanation:
Kinetic energy is the energy from movement so whenever its moving the most / longest is your answer
Answer: D. just before it hits the ground
The coefficient of static friction between a rubber tire and dry pavement is about 0.800. Assume that a car’s engine only turns the two rear wheels and that the weight of the car is uniformly distributed over all four wheels.
What limit does the coefficient of static friction place on the time min required for a car to accelerate from rest to 60.0 mph (26.8 m/s)?
The coefficient of static friction places a limit of approximately 3.42 seconds on the minimum time required for the car to accelerate from rest to 60.0 mph (26.8 m/s).
To find the limit that the coefficient of static friction places on the minimum time required for a car to accelerate from rest to 60.0 mph (26.8 m/s), we need to consider the maximum acceleration the car can achieve due to the friction between the rear tires and the pavement.
The maximum acceleration can be determined using the formula:
a_max = μs * g
where μs is the coefficient of static friction and g is the acceleration due to gravity (approximately 9.8 m/s²).
In this case, since the car's engine only turns the two rear wheels, the maximum acceleration is limited by the friction force between the rear tires and the pavement.
Now, to calculate the minimum time required to accelerate to 60.0 mph (26.8 m/s), we can use the following kinematic equation:
v = u + a * t
where v is the final velocity (26.8 m/s), u is the initial velocity (0 m/s), a is the acceleration, and t is the time.
Rearranging the equation, we have:
t = (v - u) / a
Plugging in the values, we get:
t = (26.8 m/s - 0 m/s) / a_max
t = 26.8 m/s / (μs * g)
Substituting the given value for the coefficient of static friction (μs ≈ 0.800) and the acceleration due to gravity (g ≈ 9.8 m/s²), we can solve for the minimum time required:
t = 26.8 m/s / (0.800 * 9.8 m/s²)
t ≈ 3.42 seconds
Therefore, the coefficient of static friction places a limit of approximately 3.42 seconds on the minimum time required for the car to accelerate from rest to 60.0 mph (26.8 m/s).
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Which two layers in this model represent parts of Earth that are mostly iron
and nickel?
A. A
B. D
C. B
D. C
The correct answer is Option C. and D. The Earth consists of several layers, and the two layers that represent parts of Earth that are mostly iron and nickel are layers B and C.
The Earth's structure has been divided into several layers based on the physical and chemical properties of the materials that make up each layer.
The model is made up of four main layers: the crust, mantle, outer core, and inner core.
The outer core and inner core are the two layers that are primarily made up of iron and nickel.
Layer B, the mantle, is made up of magnesium, silicon, and iron.
Layer C, the outer core, is made up of molten iron and nickel, with some lighter elements such as sulfur and oxygen.
The inner core, layer D, is mostly composed of solid iron and nickel.
The outer core is a liquid layer located between the mantle and the inner core.
This layer is approximately 2,300 km thick and is composed primarily of iron and nickel, with some lighter elements such as sulfur and oxygen.
The outer core is responsible for generating the Earth's magnetic field.
It's also responsible for producing seismic waves that help scientists learn about the interior of the
Earth. The inner core is a solid layer located at the center of the Earth, approximately 6,371 km below the Earth's surface.
It is composed mainly of iron and nickel, with trace amounts of lighter elements such as sulfur and oxygen.
The pressure at the center of the Earth is so high that the iron and nickel in the inner core are solid, despite being at a temperature of over 5,500°C.
Therefore, The correct answer is Option C. and D.
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Taylor and Savannah are doing the Period of a Pendulum Lab. They observe that a pendulum makes exactly 10 complete back and forth cycles of motion in 21.8 seconds. Determine the period of the pendulum.
Answer:
the answer is 2
Explanation:
when you solve for this equation it wont make sense but I'm making you read this because I ain't ever seen 2 best friends.
Fundamental Problem 12.28
The car is traveling along the road with a speed of v=(|l2 s) m/s, where s is in meters. (Figure 1)
Part A
Determine the magnitude of its acceleration when s=11 m.
Express your answer to three significant figures and include the appropriate units.
The acceleration of the car in three significant figures is 0.181 m/s².
What is the acceleration of the car?
The acceleration of the car is calculated by applying the following kinematic equation as shown below.
v² = u² + 2as
where;
v is the final velocity of the caru is the initial velocity of the cara is the acceleration of the cars is the distance travelled by the carThe given parameters include the following;
the final velocity of the car = 2 m/s
the distance travelled by the car = 11 m
The acceleration of the car is calculated as follows;
v² = u² + 2as
v² = 0 + 2as
a = v² / 2s
a = ( 2² ) / ( 2 x 11 )
a = 0.181 m/s²
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A boy whirls a ball on a string 1.0 m long in a horizontal circle at 50 rpm. If the mass of the ball is 0.22 kg
What is the tension in the string?
Hi there! :)
We can begin by doing a summation of forces on the ball. In the horizontal direction, we have the force of tension:
\(F_{Net} = T\)
The tension force results in a centripetal force experienced by the ball. The equation of centripetal force is equivalent to:
\(F_C = m\omega^2 r\)
\(F_C\) = Centripetal force (N)
m = mass of ball (0.22 kg)
ω = angular speed of ball(? rad/sec, must convert rpm to rad/sec)
r = radius/length of string (1.0 m)
We must begin by converting rpm to rad/sec:
\(\frac{50 rev}{min} * \frac{2\pi rad}{1 rev}* \frac{1 min}{60 sec} = 5.236 \frac{rad}{s}\)
Now, we can set tension equal to the centripetal force and solve. \(T = F_{Net} = F_C\\\\T = m\omega^2 r\\\\T = (0.22)(5.236^2)(1) = \boxed{6.031 N}\)
A woman has one damaged fallopian tube. The damage completely blocks the opening of the tube at the ovary. How will this most likely affect her fertility?
Her likelihood of conceiving will be reduced by at least 50%.
Her eggs, if fertilized, will not implant properly.
Her eggs will not mature inside the ovary.
Her chances of conceiving twins will be doubled.
Answer:Her likelihood of conceiving will be reduced by at least 50%.
Explanation:
EDGE 2020
Answer:
Her likelihood of conceiving will be reduced by at least 50%
Explanation:
took the test on edge, got it right