A golf ball is thrown straight up in the air at a velocity of 8.3 . Determine the maximum height of the golf ball.


(b) How long will it take the ball to reach its maximum height?


(c) How long will it take the ball to fall from its maximum height to the height from which it was initially launched?

The energy of the high energy neutron is 940.51 MeV.

Speed is nothing but the distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity with the SI unit meter/second.

We know that mass of the neutron m₀ = 939.6 MeV/c²

A high energy neutron is travelling at a speed of 18 million m/s.

Given that, v = 1.8 * 10⁷ m/s

The energy of neutron is calculated with the formula, m₀* c²/√(1 - v²/c²)

⇒ 939.6 * (3* 10⁸)²/√[1 - (1.8 * 10⁷)²/(3* 10⁸)²]

⇒ 940.51 MeV

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Answer:e all of the above

Explanation:

Answer:

240N

Explanation:

The formula for force is F=mass×acceleration.

Therefore, Force= 120×2= 240N

If a variety of force are applied to an object such that the net force does positive work on that object, then speed of the object is increasing.

If the net force on an object is positive, we can infer that the object's speed is increasing, and the rate of increase in speed will depend on the force and object mass.

Positive work is done on an object when the force applied on the object is in the same direction as the displacement of the object. This means that the forces acting on the object are causing it to move in the direction of the net force. As a result, the object gains kinetic energy and its speed increases.

According to Newton's Second Law, the acceleration of an object is directly proportional to the net force applied on it. If the net force is positive, it means that the object is experiencing a positive acceleration, which further implies that the speed of the object is increasing.

It's worth noting that the rate of increase in speed will depend on the magnitude of the net force applied and the mass of the object. The larger the net force applied or the smaller the mass of the object, the greater the increase in speed.

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The frequency of a car horn, f₀ is observed by the observer, v₀ at rest. Let v be the velocity of the wind toward the observer. In this case, the frequency of the horn that is observed by the observer, v₀ is given by the formula:

f = f₀ (v + v₀) / (v + vS)The frequency that is observed is f, the frequency of the horn that is observed in the presence of a wind.

Consequently, the frequency that is observed when both the car and the observer are at rest, but a wind blows toward the observer is given by:f = f₀ (v + v₀) / (v + vS).

When both the car and the observer are at rest, but a wind blows toward the observer, the frequency that is observed is given by f = f₀ (v + v₀) / (v + vS).

The formula indicates that the observed frequency depends on the velocity of the wind and the velocity of the observer.To gain insight into how this happens, consider a situation where a car horn that has a frequency, f₀ = 440 Hz is observed by a stationary observer.

In this case, the frequency that the observer hears is 440 Hz.However, if a wind starts to blow toward the observer, the frequency that the observer hears changes. If the wind velocity is 10 m/s, the frequency heard by the observer is given by the formula:

f = f₀ (v + v₀) / (v + vS)f = (440 Hz)(10 m/s + 0 m/s) / (10 m/s + 343 m/s)f = 5.44 Hz.

The result shows that the frequency of the car horn that is observed by the observer is 5.44 Hz when a wind velocity of 10 m/s is present. This frequency is very different from the frequency that is heard when there is no wind, which is 440 Hz.

Therefore, the frequency that is observed when both the car and the observer are at rest, but a wind blows toward the observer is given by f = f₀ (v + v₀) / (v + vS).

The formula indicates that the frequency that is heard by the observer depends on the velocity of the observer and the velocity of the wind.

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Answer:

912 Hz

Explanation:

Third harmonic multiplies the frequency by 3. Harmonics are waves that operate at a frequency that is an integer (whole-number) multiple of the fundamental frequency.

At greater temperatures, the energy of the air molecules increases, causing them to vibrate more rapidly.

Since the sound waves are accelerated by the collisions of the molecules, this enables them to move more quickly.

Heat causes air molecules to travel more quickly, making them better equipped to convey a pressure wave than ones that move more slowly. As a result, heat also causes sound to travel more quickly.

Heat is a type of kinetic energy, just like sound. Higher temperatures give molecules more energy and allow them to vibrate more quickly.

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A medical linear accelerator accelerates electrons to create high-energy beams, with energy levels fluctuating between 200 and 210 MeV, which is used to destroy tumors while preserving healthy tissue. The beam energy fluctuations could be represented using a cumulative distribution function in statistics.

A medical linear accelerator is a device used in cancer treatment. It utilizes electromagnetic fields to accelerate electrons to high speeds, creating a beam of high energy. This energy, typically oscillating or fluctuating between 200 and 210 MeV (mega-electron volts), targets cancerous tumors, destroying them with minimal damage to surrounding healthy tissues. In statistics, the cumulative distribution function could be utilized to understand or describe the probability associated with these energy fluctuations of the electron beam.

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Answer:

Option A. Decrease the charge of one Particles.

Option B. Increase the distance between the particles.

Explanation:

The electric force between two charged particles is related by the following equation:

F = Kq₁q₂ / r²

F is the force.

K is the electrical constant

q₁ and q₂ are the charges of the particles

r is the distance apart.

From the above formula, we can say that the force (F) is directly proportional to the product of the two charges and inversely proportional to their distance apart. This implies that as the charge of the particle increase, the force will also increase and as the charge of the particle disease, the force will also decrease.

On the other hand, if their distance apart is increased, the force will decrease and if their distance apart is decreased, the force will increase.

Note: if one of the charge disease, the force will also decrease and if one of charge increase, the force will also increase.

Explanation:

here's the answer, shouldn't be too hard to get the rest now!

4. f

5. t

6. t

7. t

8. f

9. t

10. f

Answer:

\(\frac{0.0125m}{s}\)

Explanation:

In order to solve this question we need to know that  \(speed = \frac{distance}{time}\). Then we need to convert 4 minutes into seconds and cm into m. We can do that by multiplying the number of minutes by 60 (because there is 60 seconds in one minute) and dividing the number of cm by 100 (because there is 100 cm in one m). So.......

4min = 4 x 60s = 240s

300cm = 300/100 m = 3m

Now we know that distance = 300m, and that the time = 4min = 240s ⇒

⇒ \(speed=\frac{distance}{time} = \frac{3m}{240s} = \frac{0.0125m}{s}\)

Answer:

ezrfdjhsetnhtjhsksdjghbksfneunaifghejbcifkikjayhr

Explanation:

The correct tight asymptotic bound for T(n) in 1, 2, 3 where T(1)=c is Θ(n log n).

To find the tight asymptotic bound of T(n), we will use the Master Theorem. So, let's take a look at each recurrence relation:

1. T(n) = 10T(n/10)+100nApplying the Master Theorem: a = 10, b = 10, f(n) = 100nlogb a = log10 10 = 1 Since f(n) = Θ(n) = Θ(n1), Case 2 of the Master Theorem applies. The solution, therefore, is Θ(n log n).

2. T(n) = T(n/10)+100n Here, a = 1, b = 10, f(n) = 100nlogb a = log10 1 = 0 Since f(n) = Θ(n0) = Θ(1), Case 1 of the Master Theorem applies. The solution, therefore, is Θ(n).

3. T(n) = T(n/10)+100 Here, a = 1, b = 10, f(n) = 100logb a = log10 1 = 0 Since f(n) = Θ(1) = Θ(n0), Case 2 of the Master Theorem applies. The solution, therefore, is Θ(log n).Therefore, the correct tight asymptotic bound for T(n) in 1, 2, 3 where T(1)=c is Θ(n log n).

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Let's use the Master Theorem to find the asymptotic tight bound for each of the three recurrence relations given in the problem statement.

1. T(n) = 10T(n/10) + 100n Here, a = 10, b = 10, and f(n) = 100n. We can calculate the value of logb a as follows: log10 10 = 1 Since f(n) = Θ(n1), we can apply Case 2 of the Master Theorem and get: T(n) = Θ(n log n)Therefore, the correct tight asymptotic bound for T(n) in the first case is Θ(n log n).

2. T(n) = T(n/10) + 100n Here, a = 1, b = 10, and f(n) = 100n. We can calculate the value of logb a as follows: log10 1 = 0 Since f(n) = Θ(n1), we can apply Case 1 of the Master Theorem and get: T(n) = Θ(n)Therefore, the correct tight asymptotic bound for T(n) in the second case is Θ(n).

3. T(n) = T(n/10) + 100 Here, a = 1, b = 10, and f(n) = 100. We can calculate the value of logb a as follows: log10 1 = 0 Since f(n) = Θ(1), we can apply Case 2 of the Master Theorem and get: T(n) = Θ(log n) Therefore, the correct tight asymptotic bound for T(n) in the third case is Θ(log n). Hence, the three asymptotic tight bounds for T(n) are Θ(n log n), Θ(n), and Θ(log n), respectively.

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The given statement is true .

The sign of momentum is indeed always in the direction of travel.
Momentum is defined as the product of an object's mass and its velocity. Mathematically, it can be expressed as:
Momentum (p) = mass (m) × velocity (v)

Since velocity is a vector quantity that has both magnitude and direction, the sign of momentum will also depend on the direction of the object's motion. If an object is moving in a positive direction (e.g., to the right or upward), its momentum will have a positive sign. Conversely, if an object is moving in a negative direction (e.g., to the left or downward), its momentum will have a negative sign.

In summary, the sign of momentum is always in the direction of travel because it is directly influenced by the object's velocity, which is a vector quantity with both magnitude and direction.

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Answer:

D.

Explanation:

Force and distance are inversely related, so a greater distance results in a weaker force.

Answer:

radio waves

Explanation:

Answer:

the answer is A radio waves

Answer:

0.12A

Explanation:

v=ir

I=v÷r

6÷50=0.12A

Answer:

Vector, scalar, scalar, vector

Explanation:

When you see a measurement followed by a direction ( up, down, north, east, etc.), it is usually a vector quantities

When you see a plain measurement such as 4.2s, 6 ft, it is usually a scalar one.

A 25.5 kg video cart is rolled down a hallway. It is accelerated at 0.12 m/s2. If a force of 30 N is applied to move the cart . The wheels have 26.4 N  force of friction against the floor

Force of friction is that force  that resists the sliding or rolling of one solid object over another

F(applied) - friction = F net

30 - fr = mass * acceleration

30 - fr  = 25.5  *  0.12  

fr = 30 - 3.06

  = 26.4 N

The wheels have 26.4 N  force of friction against the floor

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If the Moon was twice as far from the Earth as it is now, its gravitational pull on the Earth would reduced to a quarter of what it is now.

Gravitational force is proportional to the mass of the two objects and inversely proportional to the square of the distance between them.

This is expressed mathematically by the equation F = G (m1m2/r²), where F is the gravitational force, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them.

The formula shows that the gravitational attraction between two objects varies with the distance between them.

Thus, if the distance between the Moon and Earth doubles, the force of gravity between them will decrease to a quarter of what it was before.

This implies that the Moon's gravitational attraction to the Earth would reduce, which means that the tides would be much less significant than they are now.

Tidal waves would be less severe, and tidal currents would be less vigorous.

The reduced gravitational pull on Earth could also cause the planet's rotation to speed up since the Moon slows it down through tidal friction.

Therefore, if the Moon were twice as distant from the Earth as it presently is, its gravitational attraction to Earth would be reduced to a quarter of what it is now.

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a scientific LAW is the answer

Explanation:

a scientific law is the rule that nature runs by.

The force of friction of the cart of mass 16.4 kg is 159.18 N.

Friction is the force that opposes the motion of two bodies in contact.

To calculate the force of friction acting on the cart, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the force of friction is 159.18 N.

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Complete Question:

A long distance runner running a 5.0km track is pacing himself by running 4.5km at 9.0km/hr and the rest at 12.5km/hr. What is the average speed?​

Answer:

Average speed = 9.7333 km/h

Explanation:

Given the following data;

To find the average speed;

First of all, we would determine the time taken to cover distance A in speed A by using the formula;

\( Time \ A = \frac {Distance \; A}{Speed \; A} \)

Substituting the values into the formula, we have;

\( Time \ A = \frac {4.5}{9.5} \)

Time A = 0.4737 hours

Total distance = distance A + distance B

5 = 4.5 + distance B

Distance B = 5 - 4.5

Distance B = 0.5 Km

Next, we would determine the time to cover distance B in speed B;

\( Time \ B = \frac {0.5}{12.5} \)

Time A = 0.04 hours

Total time = time A + time B

Total time = 0.4737 + 0.04

Total time = 0.5137 hours

Now, we would solve for the average speed;

Mathematically, the average speed of an object is given by the formula;

\( Average \; speed = \frac {total \; distance}{total \; time} \)

\( Average \; speed = \frac {5}{0.5137} \)

Average speed = 9.7333 km/h

Answer:

Revolutions made before attaining angular velocity of 30 rad/s:

θ = 3.92 revolutions

Explanation:

Given that:

L(final) = 10.7 kgm²/s

L(initial) = 0

time = 8s

Torque is the rate of change of angular momentum:

\(T = \frac{L(final)-L(initial)}{t}\\T = \frac{10.7-0}{8}\\T=1.34 Nm\)

We know that

T = Iα

α = T/I

where I = moment of inertia = 2.2kgm²

α = 1.34/2.2

α = 0.61 rad/s²

We know that angular equation of motion is:

ω²(final) = ω²(initial) +2αθ

(30 rad/s)² = 0 + 2(0.61 rad/s²)θ

θ = (30 rad/s)²/ 2(0.61 rad/s²)

θ = 24.6 radians

Convert it into revolutions:

θ = 24.6/ 2π

θ = 3.92 revolutions

In the same period of time, the horses on the outside of the carousel must travel farther than the ones on the inside. Accordingly, the horses outside move at a faster linear speed than the horses at the hub.

Every point on the surface of the merry-go-round revolves at exactly the same angular speed because it rotates as a single solid entity.

Which horse travels faster along a rail, one near the inside or one on the outside of a merry-go-round? neither because their linear speeds are equal.

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The thrust of the jet engine is 59804 N and the delivered power is 1.388 MW.

Thrust is defined as the amount of effort required to move an airplane through air that is resisting its passage called drag. Newton's Second and Third Laws could be used to quantitatively explain the reaction force of thrust.

Given

Speed = 232 m/s

Air intake =117 kg/s

Fuel burn rate = 4.8 kg/s

Speed of exhaust gas = 723 m/s

Rate of mass change = 117 kg/s + 4.8 kg/s

                                   = 121.8 kg/s

Thrust T = 121.8 x 723 - 121.8 x 232

Thrust T = 88061.4 - 28257.6

Thrust T = 59804 N

Delivery power = 232 x 59804

Delivery power = 1.388 MW

Thus, the thrust of the jet engine is 59804 N and the delivered power is 1.388 MW.

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We consider only heating the green crystal sample to 110 °c to dehydrate is we want the 3 molecules of water to evaporate.

Furthermore, we need the oxalate to evaporate with the water . this type of condition only occurs when we heat the green crystal at  110 °c  due to the rise of boiling point in water being 100°c.

Oxalate refers to an anion that occurs naturally and is added to some foods for instance sodium oxalate and several esters like dimethyl oxalate. It is considered  a conjugate of oxalic acid.

The formula for oxalate is C₂O₄⁻²

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Answer:

1000m=1km

simple :) . . .

Explanation:

CON EL TEOREMA DE PITÁGORAS

v = \(\sqrt{(12 km/h)^{2} + (25 km/h)^{2}}\) = 27.7 km/h

The initial maxima speed for light with a 500 nm wavelength is 5 mm/s.

Hence, given the distance to a screen, the breadth of the slit, and the wavelength of the light, we can apply the equation y = L l / a to pinpoint the location of the initial diffraction minimum with in single slit diffraction pattern.

Its Type III dispersion is intended for applications such general carparks and streets where a larger illumination area is required. Type III lighting must be placed to one side of the area in order for it to illuminate the entire area. As a result, there's a filling light flow.

Distance between slits and screenD=3m

Distance between slits d=10 mm

Speed v=4 m/s

v β =5×10 −3 m/s

= 5 mm/s

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