A counter flow shell-and-tube heat exchanger is to be used to heat air from 4°C to 82°C, flowing at the rate of 21.8 tons per hour. Heating action is to be provided by the condensation of steam at 99°C in the shell. The internal diameter of the steel tubes is 2.5 inches. Find:
a) The size of the heat exchanger (surface area and tube length), assuming a mass velocity of 39 tons/hr.m2.
b) The air-side pressure drop. You may assume that the area of the heater is twice the flow area of the tubes.
Additional information
At the mean air temperature, the air tables list:
Pr = 0.71
Cp = 32.46 J/kg. °C
K = 3.214 J/m.hr. °C
U= 0.0698 kg/m.hr
Friction factor (f) is expressed as f = 0.046/(Re)0.2
Density of air at 4°C = 1.23 kg/m3 and at 82°C = 0.96 kg/m3
ke = 0.21 and kc = 0.31

Try to be as relax as possible.

Provide names of all parties involved.

Provide vehicle information and identification details.

Provide full names, address, registration numbers and insurance company details.

Explanation:

After a collision one may be confused, afraid and have no attention about the details that what happened because all the collision event happens in a short interval of time. So the first thing one should do during information exchange is to sit back and relax and be calm so that one can remind the things at some extent. After that provide all the details about injured people and the involved vehicles.

Answer: The red color on the cylinder is indicative of the material's flammability.

Explanation:

The shear plane angle is calculated as 49.4 degrees while the shear strain is given as 1.17

Shear strain is a measure of deformation resulting from an applied force that is parallel to the surface of an object. It is usually expressed as a fractional change in the length of the object. Shear strain is a measure of the displacement of the surface points of an object in the direction perpendicular to the direction of the applied force.

The shear plane angle is the angle between the plane of shear stress and the normal to the plane of shear. It is typically measured in degrees and can range from 0 to 90 degrees.

(a) Shear plane angle = tan⁻¹((0.65-0.30)/0.30) = 49.4°

(b) Shear strain = (deformed chip thickness - initial chip thickness)/initial chip thickness

Substituting the values into the formula;

Shear Strain = (0.65-0.30)/0.30 = 1.17

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The contact areas of nail tips are smoothed with a fine-grit block buffer held using a gentle and light touch.

When applying nail tips, it is important to ensure that they are properly attached to the natural nails to prevent them from lifting or breaking. This requires the contact areas of the nail tips to be smoothed and flattened so that they adhere well to the natural nails. A fine-grit block buffer is typically used for this purpose, as it is gentle on the nails and provides a smooth finish. To use the fine-grit block buffer on the contact areas of nail tips, it should be held with a gentle and light touch. The buffer should be moved in a back-and-forth motion across the contact area until it is smooth and flat. It is important to avoid applying too much pressure or buffing too aggressively, as this can damage the natural nails and cause discomfort to the client.

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Once the external shape and internal features of a part are represented by a combination of lines, further information is provided by Dimension.

In regards to geometry, the  three-dimensional shape is known to be one that can be said to be a form of solid figure or an object/shape that is of known to be made up of three dimensions which are length, width, and height.

Note that the three-dimensional shapes have height as well as thickness or depth.

Therefore, Once the external shape and internal features of a part are represented by a combination of lines, further information is provided by Dimension.

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The most popular alloying elements for aluminum are copper, zinc, magnesium, silicon, manganese, and lithium. Chromite, titanium, zirconium, lead, and bismuth were added in trace amounts.

According to the National Electrical Code, a list of aluminum alloys called AA-8000 is utilized to make wire.

Alclad is a type of aluminum sheet created by gluing extremely pure aluminum to a very strong core material.

Al-Li (lithium, occasionally mercury) (lithium, sometimes mercury)

Alnico (aluminum, nickel, copper) (aluminum, nickel, copper)

Birmabright (aluminum, magnesium) (aluminum, magnesium)

Duralumin (copper, aluminum) (copper, aluminum).

Zinc (Zn) 7xxx - The strongest heat-treatable aluminum alloys are created by combining zinc with aluminum and other elements, typically copper and magnesium. Zinc significantly boosts strength and allows precipitation to harden.

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Following that, they may also be involved in the design of machinery, medical equipment, and vehicles whose structural integrity has an impact on their operation and safety.

Engineers construct the "bones and muscles that are generated the form and also that make the shape of man-made structures." It is necessary to comprehend structural engineering since it determines the stability, strength, stiffness, and earthquake-susceptibility of built structures for both buildings and non-building structures. In order to better integrate their structural designs with those of other designers, such architects and building services engineers, and to frequently oversee the on-site execution of projects by contractors. After that, they might also work on designing machines, medical devices, and cars.

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Answer:

the total charge which crosses into the collector is 60 nC

Explanation:

Given the data in the question;

current flowing into the collector lead of the bipolar junction transistor (BJT); i = 1 nA = 10⁻⁹ A

no charge was transferred in or out of the collector lead prior to t = 0

the current flow time t = 1 min = 60 sec

Now we write the relation between current, charge, and time;

i = dq / dt

where i is current, q is charge and t is time. { d refers to change }

Now,

\(q=\int\limits^t_{t=0} {i(t)} \, dt\)

\(q=\int\limits^{t=60}_{t=0} { (10^{-9}) } \, dt\)

\(q = ( 10^{-9}) (t)_0^{60\)

\(q = ( 10^{-9}) ( 60 - 0 )\)

q = 60 × 10⁻⁹ C

q = 60 nC

Therefore, the total charge which crosses into the collector is 60 nC

Recent developments in graphene research have made it possible to use its nanocomposites for a variety of applications in the energy and environmental sectors.

With a focus on synthesis and application, graphene-based polymer nanocomposites have recently attracted a lot of attention. Nanocomposites based on graphene exhibit astounding electrical, mechanical, chemical, and thermal properties. Covalent and non-covalent techniques, a chemical-based deposition strategy, hydrothermal growth, electrophoresis deposition, and physical deposition are all used to create graphene nanocomposites (GNCs). The most practical approach for making graphene in small amounts at low temperatures is chemical. Additionally, graphene films can be created using this method on a number of substrates. Recently, there has been a lot of interest in the use of artificial intelligence (AI) in the synthesis of nanoparticles produced by AI.

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Technician B says that integrally molded disc brake pads are molded into holes in the steel backing of the pads. Both technicians are correct.Riveted and bonded brake pads are two different types of brake pads that can be used in a vehicle.

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The 64 KiB cache, despite its larger data size, might provide slower performance than the first cache because of its slower access time. The larger the cache, the longer it takes to access the data stored in it.

This is because the cache has to search through a larger amount of data to find the requested information. Therefore, the larger data size of the 64 KiB cache can actually result in slower performance. The large cache would be slower under the condition where the data being accessed is not frequently used. In this case, the cache would have to search through a larger amount of data to find the requested information, resulting in slower performance. However, if the data being accessed is frequently used, the larger cache would provide faster performance because it can store more frequently used data and therefore reduce the number of times the cache has to search for the requested information.

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When looking at postural alignment from a lateral view, the vertical plumb line should be: Slightly anterior to the lateral malleolus.

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the maximum instantaneous power dissipated by the 3.0-hp pump is approximately 2238 watts, and the maximum current passing through the pump is approximately 9.32 A.

To find the maximum instantaneous power dissipated by the pump, we need to know the power formula for AC circuits, which is: P = Vrms x Irms x cos(θ) Where P is the power, Vrms is the root-mean-square voltage, Irms is the root-mean-square current, and θ is the phase angle between the voltage and current. Since the voltage is given as 240 Vrms and the power is 3.0 horsepower (hp), we need to convert the power to watts: 1 hp = 746 watts So, 3.0 hp = 3.0 x 746 = 2238 watts Next, we need to find the current passing through the pump. We can use the power formula to rearrange for current: Irms = P / (Vrms x cos(θ)) The power factor, cos(θ), is not given, but we can assume it is close to 1 for most practical applications. Thus, we can estimate the maximum current using the following formula: Irms = P / Vrms, Irms = 2238 watts / 240 Vrm ,Irms = 9.32 A.

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Answer:

True

Explanation:

Because a object is a smart thing to use doing them problem

Answer:

Lack of fluid oil – lack of fluid oil in your vehicle, or a fluid leakage, can lead to heavy steering. If there is a lack of fluid oil, or a leak, this can reduce the pressure in the system, meaning the steering wheel does not receive enough supply of fluid to perform freely.

Answer:

Explanation:

The situation being described completely fails in regard to the importance of metrology. This is because the main importance of metrology is making sure that all of the measurements in a process are as accurate as possible. This accuracy allows an entire process to function efficiently and without errors. In a food production plant, each individual department of the plant relies on the previous function to have completed their job with the correct and accurate instructions so that they can fulfill their functions correctly and end up with a perfect product. If the oven (like in this scenario) is a couple of degrees off it can cause the product to come out burned or undercooked, which will then get transferred to the next part of production which will also fail due to the failed input (burned or undercooked product). This will ultimately lead to an unusable product at the end of the process and money wasted. Which in a large production plant means thousands of products in a single batch are thrown away.

In terms of the necessity of metrology, the situation stated absolutely fails. This is because metrology's primary goal is to ensure that all measurements in a process are as precise as feasible. This precision allows a whole process to run smoothly and error-free. If the oven temperature is wrong by a few degrees, the product will come out charred or undercooked, and the product will be sent to the next step of the process, which will also fail owing to the failed input. This will result in a useless product and a waste of money at the end of the procedure. In a big manufacturing facility, this means thousands of goods are discarded in a single batch.

The task at hand is to write an equals method for a class foo that implements the Comparable interface. The equals method should return true if the foo parameter passed to this foo is equal to this foo, determined by using the implementation of Comparable.

To understand how to implement the equals method, let's first understand the Comparable interface. Comparable interface has only one method that needs to be implemented - compareTo(T obj). The method returns 0 if the current object is equal to the specified object, a value less than 0 if the current object is less than the specified object, and a value greater than 0 if the current object is greater than the specified object.

Now, let's move to the implementation of the equals method for the given class foo. Below is the code for the implementation:

```

public class foo {

public boolean equals(foo other) {

if (compareTo(other) == 0) {

return true;

} else {

return false;

}

}

}

```

In the above code, we first compare the two objects using the compareTo method. If it returns 0, then the two objects are equal and we return true. Otherwise, we return false.

So, that's how you can write an equals method for a class foo that implements the Comparable interface

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The maximum capillary rise and tube diameter for this maximum-rise case will be d=0.414× 10⁻⁴ m.

What do you mean by tube?

A tube, also known as tubing, is a long hollow cylinder that is used to transport fluids (liquids or gases) or to protect electrical and optical cables and wires.

Given that, P = 4 KPa

Contact angle = 6°

Surface tension = 1 N/m

Lets assume that atmospheric pressure = 100 KPa

Lets take that density of water = 1000kg/m³

So the capillarity rise h

h=ΔP/ρg

h= (100×1000-4×1000)/(1000×10)

h= 9.61 m

We know that for capillarity rise h

h=2σcosθ/rρg

r = 2σcosθ/hρg

r = (2×1cos4°)/(9.61×1000×10)

r = 0.207×10⁻⁴m

d=0.414× 10⁻⁴ m

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Answer:

Explanation:

Temperature of atmospheric air To = 25°C = 298 K

Free  stream velocity of air Vo = 25 m/s

Length and width of plate = 1m

Temperature of plate Tp = 125°C = 398 K

We know for air, Prandtl number Pr = 1

And for air, thermal conductivity K = 24.1×10?³ W/mK

Here, charectorestic dimension D = 1m

Given value of Reynolds number Re = 105

For laminar boundary layer flow over flat plate

= 3.402

Therefore, hx = 0.08199 W/m²K

So, heat transfer rate q = hx×A×(Tp – To)

                                          = 0.08199×1×(398 – 298)

Answer:

See attachment

Explanation:

The attached picture shows a problem identical to this one except the diameter of the balloon is defined. The provided problem can be solved in terms of the balloon's diameter using the same procedure.

Answer:

i think its called leggings thats wut my shop teacher told me

Explanation:

If an engine fails during rollout or just before takeoff, immediately shut both throttles and land the aircraft safely. Before reaching a safe single engine speed right away after takeoff, drop your nose to increase velocity.

Closing the throttle, turning off the fuel pump, setting the mixture control to idle cutoff, and simply cranking the engine is the most reliable hot start method I've found.

If an engine fails during rollout or just before takeoff, immediately shut both throttles and land the aircraft safely. Before reaching a safe single engine speed right away after takeoff, drop your nose to increase velocity. If you are unable to climb, close both throttles and land straight ahead.

The typical practice for the majority of aircraft would be to abandon takeoff if an engine failed during takeoff. In small aircraft, the pilot should turn the throttles down to idle, activate the speed brakes (if provided), and apply the brakes as needed if the engine fails before VR (Rotation Speed).

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If your crew is the first to arrive on the scene of a major MCL, The major aspect of your scene size-up will be to Make a sweep to determine what needs must be met. Option D. This is further explained below.

Generally, If your team is the first to arrive at the scene of a significant MCL, the most important part of your scene size-up will be to do a sweep to identify the requirements that need to be satisfied. Choose option D.

In conclusion, A medial collateral ligament (MCL) injury occurs when the ligament on the inside of the knee is stretched, partially torn, or completely ruptured. Most knee injuries are caused by an excessive amount of valgus stress on the knee, which is one of the most prevalent.

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CQ

If your crew is the first to arrive on the scene of a major​ MCI, what will be a major aspect of your scene​ size-up?

A.

Make an initial scene report to the communications center.

B.

Control​ on-scene communication as help arrives.

C.

Prevent uncoordinated or undirected activity at the scene.

D.

Make a sweep to determine what needs must be met.

Answer:

i) 796.18 N/mm^2

ii) 1111.11 N/mm^2

Explanation:

Initial diameter ( D ) = 12 mm

Gage Length = 50 mm

maximum load ( P ) = 90 KN

Fractures at =  70 KN

minimum diameter at fracture = 10mm

Calculate the engineering stress at Maximum load and the True fracture stress

i) Engineering stress at maximum load = P/ A

= P / \(\pi \frac{D^2}{4}\)  = 90 * 10^3 / ( 3.14 * 12^2 ) / 4

= 90,000 / 113.04 = 796.18 N/mm^2

ii) True Fracture stress =  P/A

= 90 * 10^3 / ( 3.24 * 10^2) / 4

= 90000 / 81  =  1111.11 N/mm^2

The term "remodel" implies making changes to the existing design rather than starting from scratch.

An optimized sintered wick heat pipe is a type of heat pipe that utilizes a sintered wick structure to enhance heat transfer. The sintered wick is typically made of porous metal or ceramic materials that promote capillary action and efficient fluid transport within the heat pipe.When remodeling the existing design, various aspects can be considered. This may involve modifying the dimensions, materials, or geometry of the heat pipe to enhance its performance.

The goal could be to improve heat transfer efficiency, increase thermal conductivity, reduce pressure drops, enhance durability, or optimize the heat pipe for specific operating conditions or applications.Remodeling the design may involve computational modeling, simulation, prototyping, and experimental testing to evaluate the performance and validate the modifications. The aim is to achieve an improved or tailored design that better meets the desired performance objectives.

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A type of loop which Jamal will need to create in order to make the backdrop to continuously keep changing is: C. forever loop.

A forever loop can be defined as a type of loop which comprises a sequence of instructions that are written to run continuously or endlessly, until the simulation is quitted by an end user.

This ultimately implies that, a forever loop should be created by Jamal to  make the backdrop to continuously keep changing.

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Answer: C

Explanation:

To any of you who are also taking Game Design, I have respect for you.

Answer:

OPTION A,Larger

HOPE IT HELPS

A. R-chart An R-chart, also known as a range chart, is used to track the variability or dispersion of a manufacturing process.

It is commonly used in statistical process control (SPC) to monitor the consistency of a process over time.

In the case of copper tubing production, an R-chart would be suitable for tracking the variability of the tubing's diameter. The chart displays the range (the difference between the largest and smallest values) of a set of samples taken from the manufacturing process. By analyzing the range values, one can assess whether the process is producing tubing with consistent diameter or if there is excessive variability.

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