A conduit of circular cross section has 7 cables all same diameter. Inside diameter of conduit is 30cm. What is the cross sectional area of the conduit not part of the 7 cables

Answer:  The correct answer is y-intercept = -1

Step-by-step explanation:

The table provided:

   x    y

  5     4

  6     5

Find the slope:

Slope (m) = ΔY/ΔX = 1/1 = 1

The slope-intercept form for this line: y = x – 1

The graph is provided below.

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The main answer is that without specific values or elements for sets A and B, we cannot determine the result of A - B and B - A.

To find A - B, we need to subtract the elements in set B from set A. Similarly, to find B - A, we need to subtract the elements in set A from set B.

However, I need the specific values or elements of sets A and B to perform the calculations. Could you please provide the values or elements of the sets?In order to perform set subtraction, we need the specific elements or values of sets A and B. Set subtraction involves removing the common elements between the sets.

Let's say set A is {1, 2, 3} and set B is {2, 3, 4}. To find A - B, we remove the elements in set B from set A. Thus, A - B would be {1}.

To find B - A, we remove the elements in set A from set B. Therefore, B - A would be {4}.

Please provide the values or elements of sets A and B, and I will be able to calculate A - B and B - A accordingly.

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\(log_{4}(2) + log_{4}(3)+ log_{4}(5+2x)\) is the completely expanded logarithmic expression .

Logarithm, an exponent or power that must be raised to obtain a particular number. Mathematically, if bx = n then x = logb n then x is the logarithm of n to  base b. Example: 23 = 8; so 3 is the base 2 logarithm of 8, or 3 = log2 8.

The most common types of logarithms are  the base 10 common logarithm, the base 2 binary logarithm, and  the base  e ≈ 2.71828 natural logarithm.

the product rule for logarithms is

\(log_{b}(MN) = log_{b}(M) + log_{b}(N)\)  for b > 0

now ,

\(log_{4}(6(5 + 2x)) \\\\log_{4}(6) + log_{4}(5 + 2x)\\ \\ log_{4}(2.3) + log_{4}(5 + 2x) \\\\ log_{4}(2) + log_{4}(3)+ log_{4}(5 +2x)\)

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The round trip distance in miles from city 1 to city 3 is given as follows:

30 miles.

The matrix corresponding to the distances between each of the cities is given by the image presented at the end of the answer.

Looking at row 1, column 3, we have that the distance from city 1 to city 3 is of 15 miles.

For the round trip distance, we have to go back from city 3 to city 1, more 15 miles, hence the distance is given as follows:

2 x 15 = 30 miles.

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Answer:

4/9

Step-by-step explanation:

Answer:

1

Step-by-step explanation:

Anything to the 0 power is 1

Answer:

137 in.^2

Step-by-step explanation:

A = nsa/2

where

n = number of sides = 9

s = length of side = 4.7 in.

a = length of apothem = 6.5 in.

A = (9)(4.7 in.)(6.5 in.)/2

A = 137.475 in.^2

Answer: 137 in.^2

Answer:

The correct answer is B.

Approximately 200 students received a test score between 70.5 and 80.

The polynomial -8m²n - 7m²n can be factored using the common factor -m²n. The complete factored form of the polynomial is (-m²n) (8 + 7a).

To find the complete factored form of the polynomial -8m²n - 7m²n, we can factor out common terms from both the terms. The common factor in the terms -8m²n and -7m²n is -m²n. We can write the polynomial as:

-8m²n - 7m²n = (-m²n) (8 + 7a)

Therefore, the complete factored form of the polynomial -8m²n - 7m²n is (-m²n) (8 + 7a). This expression represents the original polynomial in a multiplied form. We can expand this expression using distributive law to verify that it is equivalent to the original polynomial.

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A fifth-degree polynomial with three terms in standard form would be written as a\(x^{2}\) + b\(x^{4}\)+ c\(x^{3}\). The closure property states that a set is closed under a certain operation if performing that operation on any two elements of the set produces a result that is also an element of the set.

Part A: A fifth-degree polynomial with three terms in standard form would be written as a\(x^{2}\) + b\(x^{4}\)+ c\(x^{3}\). The coefficient of the highest degree term (x^5) must be non-zero and all the terms must be written in descending order of the degree. This is the definition of standard form for polynomials.

Part B: The closure property states that a set is closed under a certain operation if performing that operation on any two elements of the set produces a result that is also an element of the set. In this case, the set is polynomials and the operation is subtraction. An example of this property can be seen by subtracting two polynomials, such as 4\(x^{2}\) + 3x - 5 and \(x^{2}\) + 2. The result of this subtraction would be 3\(x^{2}\) + 3x - 5, which is also a polynomial and therefore an element of the set, demonstrating the closure property.

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A fifth-degree polynomial with three terms in standard form would be written as a\(x^{2}\) + b\(y^{2}\)+ c. The closure property states that a set is closed under a certain operation if performing that operation on any two elements of the set produces a result that is also an element of the set.

Part A: A fifth-degree polynomial with three terms in standard form would be written as a\(x^{2}\) + b\(y^{2}\)+ c. The coefficient of the highest degree term (\(x^{5}\)) must be non-zero and all the terms must be written in descending order of the degree. This is the definition of standard form for polynomials.

Part B: The closure property states that a set is closed under a certain operation if performing that operation on any two elements of the set produces a result that is also an element of the set. In this case, the set is polynomials and the operation is subtraction. An example of this property can be seen by subtracting two polynomials, such as 4\(x^{2}\) + 3x - 5 and  + 2. The result of this subtraction would be 3\(x^{2}\) + 3x - 5, which is also a polynomial and therefore an element of the set, demonstrating the closure property.

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Answer:

The calculated value  t = 1.3788 < 2.0262 at 0.05 level of significance

the null hypothesis is accepted

There  is no significant difference between  their counterparts across the nation

Step-by-step explanation:

Step(i):-

Given that the mean of the U.S residents  = 1.65

Given that the size of the sample 'n' = 38

Mean of the sample = 1.84

Given that the standard deviation of the sample (S) = 0.85

Step(ii):-

Null hypothesis:H₀:

There  is no significant difference between  their counterparts across the nation

Alternative Hypothesis:-H₁:

There  is  a significant difference between  their counterparts across the nation

Test statistic

                \(t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }\)

               \(t = \frac{1.84-1.65}{\frac{0.85}{\sqrt{38} } }\)

              t =  1.3788

Degrees of freedom

                ν = n-1  = 38-1 = 37

t₀.₀₅ ,₃₇ =    2.0262

The calculated value  t = 1.3788 < 2.0262 at 0.05 level of significance

Null hypothesis is accepted

Final answer:-

There  is no significant difference between  their counterparts across the nation.

The probability of landing on the dark blue target is 2/5.

Probability is the ratio of required to the total possible outcomes of an event.

P(dark blue ) = 40/100

divide through by 20

P(dark blue ) = 2/5

Therefore, the probability of landing on target is 2/5

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Answer:

\(Understand \: how \: to \: work \: with \: negative \: bases \\ \: and \: negative \: exponents. \\

\bold{answer - } \\ {5}^{2} = 5 \times 5 = 25 \\ {5}^{ - 2} = \frac{1}{ {5}^{2} } = \frac{1}{25} = 0.04 \\ {( - 5)}^{2} = ( - 5) \times ( - 5) = 25 \\ - {5}^{2} = ( - 5) \times ( - 5) = 25 \\ \\ \bold \purple{hope \: it \: helps \: ♡}\)

Solution

Step 1:

Write the equation:

Step 2

Step 3:

Step 4

Substitute t = 4.5 into the height equation.

Answer: The total distance covered by the car is 331 9/16 km.

Step-by-step explanation:

We know that, speed= distance/time taken

Therefore, distance = speed x time taken

= 132 5/8 x 2 1/2

= 5/2 x 1061/8

= 5305/16

= 331 9/16 km

Therefore, total distance is 331 9/16 km.

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An order-preserving function is a function that preserves the order of its inputs. In other words, if x is less than y, then f(x) will be less than f(y).

The statement "f is order-preserving if x < y implies f(x) < f(y)" means that if x is less than y, then f(x) must be less than f(y). This is a necessary condition for a function to be order-preserving. However, it is not a sufficient condition. For example, the function f(x) = x^2 is not order-preserving, because 2 < 3, but f(2) = 4 > f(3) = 9.

In summary, order-preserving functions are useful in situations where we need to preserve the order of a set of data.

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Answer: Rhombus — A= pq/2

Rectangle — A= lw (length times the width)

Parallelogram — A = bh (base times the height)

Kite — A= pq/2

Step-by-step explanation:

Answer:

3.......................

Thus, the volume of cylinder with the given height and diameter is found as 1413 ft³.

A cylinder is three-dimensional. It's not a flat thing. There are parallel circular bases in this shape. These bases have a curved face affixed to them. A cylinder in this instance has three faces. Along both end of a curved face, which rounds back to the face's origin, are two spherical bases.

Given that-

Volume of cylinder = πr²h

Volume of cylinder = 3.14 *5²*18

Volume of cylinder = 3.14*25*18

Volume of cylinder = 1413 ft³

Thus, the volume of cylinder with the given height and diameter is found as 1413 ft³.

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what's up? we can find slope with rise/run. ill do the first dotted line on top.

the rise/run formula is y2 - y1/x2 - x1

1: (7,3)

2: (-8, -2)

-2 - 3

-8 - 7

-5/-15

this is the same as 1/3 which is your slope for the first answer

i will pick my own 2 points for the second question.

1: (-2, 5)

2: (0, -1)

-1 - 5

0 - -2

we can change the negatives out for positives to make

-1 - 5

0 +2

this makes -6/2, which is also -3 and that is your answer for the second question. good luck!

Answer:

about 21 students

Step-by-step explanation:

total students: 150 students enrolled

recognize all letters: 6/7 of the students

To find 1/7 of the students: divided the 150 by 7

150/7 = 21.4285           this is for 1/7th of students

since 1/7th of the students need to learn the alphabet (7/7 - 1/7 = 6/7)

OR

150/7 = 21.4285           this is for 1/7th of students

150/7 x 6 = 128.57        this is for 6/7th of students

150 - 128.57 = 21.4285

Answer:

D f(x)= e^x+ 5x + 19

Step-by-step explanation:

D f(x)= e^x+ 5x + 19

We want to see for which one of the given functions, the inverse derivate evaluated in x = 20 is equal to 1/5.

The correct option is B:  f(x) = x^3 + 5x + 20

Remember that two functions f(x) and g(x) are inverses if:

f( g(x)) = g( f(x))) = x

And for the inverse derivate of a function, we have the rule:

\(\frac{d}{dx} [f^{-1}(f(x))] = \frac{1}{f'(x)}\)

So first we need to find for what value of x each function is equal to 20, and then we need to see if the derivate of the function evaluated in that same value of x is equal to 5.

For example, for the first option we have:

A: f(x) = x + 5

We find the x-value such that the function is equal to 20.

f(15) = 15 + 5 = 20

We derivate the function.

f'(x) = 1

We evaluate the function in the x-value we got above.

f'(15) = 1

This is not the correct option, as this is not 5.

Now we need to do that for all the given options.

The only correct option will be the second one:

B: f(x) = x^3 + 5x + 20

First we find the x-value such that this is equal to 20

f(0) = 0^3 + 5*0 + 20 = 20

Then the x-value is x = 0.

Now we find the derivate of f(x).

f'(x) = 3*x^2 + 5

Now we evaluate that in the x-value we got before:

f'(0) = 3*0^2 + 5 = 5

As wanted, this is equal to 5.

Then we have:

\(\frac{d}{dx} [ f^{-1}( f(0))] = \frac{1}{f'(0)} \\\\\frac{d}{dx} [ f^{-1}(20)] = \frac{1}{5}\)

As wanted.

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Answer:

To calculate Karl Pearson's coefficient of skewness, we need to use the formula:

Skewness = 3 * (Mean - Mode) / Standard Deviation

Given the Mean = 73.19, Mode = 79.56, and Variance = 16, we need to find the Standard Deviation first.

Standard Deviation = √Variance = √16 = 4

Now we can substitute the values into the formula:

Skewness = 3 * (73.19 - 79.56) / 4

Skewness = -6.37 / 4

Skewness = -1.5925

Rounded to four decimal places, the Karl Pearson's coefficient of skewness for the given values is approximately -1.5925.

The correct value of 2f(a-1) is 2a^2 - 12a + 10.

To find the value of 2f(a-1), we need to substitute (a-1) into the function f(x) and then multiply the result by 2.

Given: f(x) = x^2 - 4x

Substituting (a-1) into the function:

f(a-1) = (a-1)^2 - 4(a-1)

Expanding and simplifying:

f(a-1) = (a^2 - 2a + 1) - (4a - 4)

f(a-1) = a^2 - 2a + 1 - 4a + 4

f(a-1) = a^2 - 6a + 5

Now, we multiply the result by 2:

2f(a-1) = 2(a^2 - 6a + 5)

Expanding:

2f(a-1) = 2a^2 - 12a + 10

Therefore, the value of 2f(a-1) is 2a^2 - 12a + 10.

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If the archaeologist found a fossil whose length is 489.44 inches, using the conversion table, the length in feet, to the nearest tenth, is 40.8 feet.

The conversion table refers to the tabulated standard units of measurement, showing temperature, length, area, volume, weight, and metric conversions

For instance, the conversion table shows that 12 inches equal 1 foot.

The length of the fossil = 489.44 inches

12 inches = 1 foot

489.44 inches = 40.8 feet (489.44 ÷ 12)

Thus, using the conversion table, which relies on multiplication or division operations using the conversion factors, the length in feet of the fossil is 40.8 feet.

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