A car travels 500 km at an average speed of 120 m/s. How long will the trip take in hours?
Answers
Explanation:
120 m/s × (1 km / 1000 m) × (3600 s / hr) = 432 km/hr
t = (500 km) / (432 km/hr) = 1.16 hr
Related Questions
which of the following objects has the largest momentum? (a) a bullet fired from a rifle (b) a football quarterback running at top speed (c) a horse walking at about 2 miles/hour (d) an elephant standing still
Answers
Of the four objects listed, the bullet fired from a rifle will have the largest momentum. This is because the bullet has a relatively small mass but a very high velocity, which gives it a large amount of momentum.
What is momentum?Momentum is a physical quantity that describes the motion of an object. It is a measure of an object's resistance to changes in its velocity and is related to the mass of the object and its velocity. Momentum is a vector quantity, meaning it has both magnitude and direction, and is defined as the product of an object's mass and velocity.
Explanation & Formula:The object with the largest momentum depends on the mass of the object and its velocity. Momentum is defined as the product of an object's mass and velocity, and is denoted by the symbol "p". Mathematically, it can be expressed as:
p = m * v
where
p = momentum
m = mass of the object
v = velocity of the object
Of the four objects listed, the bullet fired from a rifle will have the largest momentum. This is because the bullet has a relatively small mass but a very high velocity, which gives it a large amount of momentum. The other objects, such as the football quarterback running at top speed, the horse walking at 2 miles/hour, and the elephant standing still, will have lower velocities and therefore lower momenta.
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Two people push on a shopping cart from opposite sides. In which situation
will the motion of the shopping cart stay the same?
A. The two people push with different amounts of force.
B. One of the people stops applying a force.
C. One of the people applies twice as much force.
D. The two people push with a balanced
face
Answers
Two people push on a shopping cart from opposite sides. Situation will the motion of the shopping cart stay the same, the correct option is (D) The two people push with a balanced face.
In this situation, the net force on the shopping cart will be zero, since the two forces are equal in magnitude and opposite in direction. If the forces are balanced, the shopping cart will not accelerate and will stay in the same state of motion (at rest or moving at a constant velocity). In scenario A and C, the forces are not balanced and therefore will cause acceleration. In scenario B, the net force will be non-zero and the acceleration will cause the shopping cart to change its velocity and direction.
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FIRST RESPONSE WILL GET BRAINLIEST IF THEY RESPOND TO THE PROMPT CORRECTLY!
i need to write an abstract for a science project, 250 words minimum. the project is regarding the frequency of guitar strings. here is other information if needed:
There are many components that make up a guitar. At the top, is the head and the peghead. Below that is the nut which leads into the neck and the fretboard of the instrument. The frequency of a guitar string depends on the length, the tension, and the mass of the string.The longer, looser, or heavier the string, the lower the lower the frequency. Ultimately, the slower the string vibrates and the longer it takes the sound to carry through the string, the lower the pitch will be and vice versa. You can increase the frequency of a string on guitar by shortening, tightening or reducing the weight of it. The strings of a guitar are supported at two points when they are not being played. The nut, at the top, and the saddle, which rests on the bridge. When you fret on a guitar, that fret starts to act as the nut, becoming the starting point of the string and therefore raising the frequency. You can raise the pitch an octave by fretting between the 11th and 12th frets.
Question: What is the relationship between the length of a string and the wavelength of the fundamental tone it produces when plucked?
Hypothesis: If the string is shorter, then it will produce a fundamentally higher tone.
Materials:
guitar (acoustic or electric)
guitar pick
electronic tuner to tell you what note you’ve played
sewing tape measure
lab notebook
pen or pencil
Procedure:
Measure the length of the string and the distance between the saddle and each fret using a sewing tape measure.
Tune your guitar and set up a tuner software or chromatic tuner to record the notes.
Play the open high E string and write down the frequency.
Fret the string just behind the first fret and play it again. Write down the frequency.
Repeat step 4 for frets 2-5 and all the other strings.
Organize your data in a table.
conclusion:
The fundamental tone produced by each string was higher when the string became shorter and thinner.
Answers
The abstract for a science project regarding the frequency of guitar strings is given below
What is the abstract?This science project is one that seeks to explores the relationship between the length of a guitar string and the wavelength of the elemental tone it produces when culled.
The recurrence of a guitar string is seen as part on its length, pressure, and mass. This extend tells that shorter strings will create a on a very basic level higher tone.
Hence An electronic tuner was said to be utilized to record the recurrence of each note played. The comes about appeared that the elemental tone delivered by each string was higher when the string got to be shorter and more slender.
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1. Make a chart comparing the composition of the intracellular
fluid and extracellular fluid.
2. Explain the importance of protein channels in the movement of
solutes
Answers
protein channels play a critical role in the movement of solutes across cell membranes. Their specific composition and function allow for the selective movement of certain molecules or ions, which is necessary for proper cellular function.
1. Chart comparing the composition of the intracellular fluid and extracellular fluid Intracellular Fluid Extracellular Fluid Water Water Protein ions (K+, Mg2+, Na+, Ca2+, Cl-)Protein ions (K+, Mg2+, Na+, Ca2+, Cl-) Glucose Glucose Fatty acids Fatty acids Urea Urea Carbon dioxide Carbon dioxide Sodium, potassium, and chloride ionsSodium, potassium, and chloride ions
2. Importance of protein channels in the movement of solutesProtein channels are embedded in cell membranes, allowing for the movement of solutes across the membrane.
Protein channels are made up of proteins that are folded in a specific way, allowing them to act as tunnels that allow the movement of specific molecules or ions across the membrane.
The protein channels act as gatekeepers, ensuring that only certain molecules or ions can enter or exit the cell.There are different types of protein channels that perform different functions, such as allowing for the movement of water, ions, or larger molecules like glucose. These channels are critical to maintaining the proper balance of solutes inside and outside of cells, which is necessary for proper cellular function.
For example, the movement of sodium and potassium ions across the cell membrane is necessary for proper nerve function. If these ions are not able to move across the membrane due to a malfunctioning protein channel, it can lead to neurological disorders or diseases. Protein channels are also important in the movement of glucose, which is necessary for energy production in cells. Without proper glucose transport, cells cannot produce enough energy to carry out their functions.
In conclusion, protein channels play a critical role in the movement of solutes across cell membranes. Their specific composition and function allow for the selective movement of certain molecules or ions, which is necessary for proper cellular function.
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5. A motorcycle stuntman accelerates from rest to a maximum velocity of 35.2 m/s at the top of the
take-off ramp, then swoops up and over 20 cars. Calculate how long it takes for him to reach his top
speed, at an acceleration of 8.8 m/s.
Answers
Answer:
I need help with my password and I don’t know how to change it will you please help me
Explanation:
the space between the parietal layer and visceral layer of the pericardium contains ______.
Answers
Answer: serous fluid
Explanation: The space between these two serous layers, the parietal and the visceral, is the pericardial cavity, which contains pericardial fluid.
If the carousel rotates at 0.10 rev/s , how long does it take the horse to go around twice?
Answers
The carousel that rotates at 0.10 rev/s, takes 125.66 s to go around twice
To solve this uniform circular motion (UCM) problem the formula and the procedure we will use is:
w= (2*π *n)/t
Where:
w = angular velocityπ = mathematical constantn = number of labst = timeInformation about the problem:
w = 0.10 rev/sπ = 3.1416n = 2t = ?Applying the angular velocity formula and isolating the time, we get:
w= (2*π *n)/t
t = (2*π *n)/w
t = (2 * 3.1416 * 2)rev / 0.10 rev/s
t = 125.66 s
What is angular velocity?When an object is in uniform circular motion, the angle described by the radius in each unit of time is known as angular velocity. It is measured in units of (rad/s) (revolutions/s).
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A train is traveling at a speed of 80\,\dfrac{\text{km}}{\text{h}}80 h km 80, start fraction, start text, k, m, end text, divided by, start text, h, end text, end fraction when the conductor applies the brakes. The train slows with a constant acceleration of magnitude 0.5\,\dfrac{\text{m}}{\text{s}^2}0.5 s 2 m 0, point, 5, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction. We want to find the distance the train travels from the time the conductor applies the brakes until the train comes to a complete stop. Which kinematic formula would be most useful to solve for the target unknown? Choose 1 answer:
Answers
Answer:
The distance the train travels before coming to a (complete) stop = 40/81 km which is approximately 493.83 meters
Explanation:
The initial speed of the train u = 80 km/h = 22 2/9 m/s = 22.\(\bar 2\) m/s
The magnitude of the constant acceleration with which the train slows, a = 0.5 m/s²
Therefore, we have the following suitable kinematic equation of motion;
v² = u² - 2 × a × s
Where;
v = The final velocity = 0 (The train comes to a stop)
s = The distance the train travels before coming to a stop
Substituting the values gives;
0² = 22.\(\bar 2\)² - 2 × 0.5 × s
2 × 0.5 × s = 22.\(\bar 2\)²
s = 22.\(\bar 2\)²/1 = 493 67/81 m = 40/81 km
The distance the train travels before coming to a (complete) stop = 40/81 km ≈ 493.83 m.
Answer:
v^2=v0^2+2aΔx
Explanation:
cuz khan academy says so
What Determines the amount of TE of an object
Answers
Answer:
To find the volume of a rectangular object, measure the length, width and height. Multiply the length times the width and multiply the result by the height. The result is the volume. Give the result in cubic units, such as cubic centimeters.
Explanation:
Answer:
Kinetic energy is the energy possessed by an object due to its motion. If an object is moving, then it has kinetic energy. The amount of kinetic energy depends on mass and speed.
Explanation:
if the ectopic impulse arises from the middle of the right atrium the p' wave is:
Answers
An ectopic heartbeat is an irregular heartbeat that happens when the heart's sinoatrial node (SA node), which is its normal heartbeat pacemaker, is disrupted. Ectopic beats originate from a location outside of the SA node, disrupting the normal heart rhythm. When it comes to the various types of ectopic beats, the most common is premature ventricular contraction (PVC).
If the ectopic impulse arises from the middle of the right atrium, the P wave will be abnormal. This occurs when the heart's ventricles experience an unexpected electrical impulse, causing them to contract prematurely. The P wave is a wave that appears on an electrocardiogram (ECG) and represents the electrical activity of the atria. The sinoatrial node generates a normal P wave, which spreads through both atria and then travels to the atrioventricular node, which slows the impulse and transmits it to the ventricles. P’ waveIf the ectopic impulse arises from the middle of the right atrium, the P' wave is abnormal.
As a result, the ECG can display the following:P waves with a single, smooth contour that are narrower than normal, P waves that have a pointed apex and are taller than normal, and P waves that merge with other waves, making them indistinguishable on the ECG.P prime waves, which are visible on an ECG, are related to supraventricular beats. They're usually seen in the early part of a supraventricular tachycardia event, which is a fast heart rate originating from the atria.
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1. When a 50,000 kg rocket blasts off there is a large force that acts on the rocket at the moment
of take off. In 0.137 seconds, the rocket suddenly has traveled 4.2 meters. What force from
the rocket engines caused the acceleration? (Hint: first find acceleration.)
Answers
Hi there!
We can begin by calculating the acceleration using the kinematic equation:
d = vit + 1/2at²
Since the rocket starts from rest, we can rewrite this as:
d = 1/2at²
Plug in given values:
4.2 = 1/2a(0.137²) ⇒ a = 447.55 m/s²
Now, we can use Newton's Second Law to find the appropriate force:
∑F = m · a
∑F = 50,000 · 447.55 = 22,377,500 N
Load Simulation For This Section The First Quarter phase occurs when half of the Moon's disk is illuminated. First Quarter refers to the fact that the Moon has completed one-quarter of its cycle of lunar phases. Question 4 Select the Moon and use the Info view to determine which of the following statements is correct. The First Quarter Moon rises close to midday and sets near to midnight. The First Quarter Moon rises close to midnight and sets near to midday. The First Quarter Moon cannot be seen in the evening sky. The First Quarter Moon rises and sets at approximately the same time as the Sun.
Answers
The correct answer is, "The First Quarter Moon rises close to midday and sets near to midnight."This question is based on the topic of load simulation and the lunar phase of the moon.
Lunar phases are the different appearances of the Moon that result from its orbit around the Earth. First Quarter phase occurs when half of the Moon's disk is illuminated. First Quarter refers to the fact that the Moon has completed one-quarter of its cycle of lunar phases.To determine the correct answer, select the Moon and use the Info view. According to Info View, the First Quarter Moon rises close to midday and sets near to midnight. Therefore, the correct answer is "The First Quarter Moon rises close to midday and sets near to midnight.
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do all of the planets orbit in the same direction when viewed from bove the earth's north pole
Answers
No, not all planets orbit in the same direction when viewed from above the earth's north pole.
The eight planets in the solar system orbit the sun in the same plane. All the planets orbit in the same direction as the sun, which is counterclockwise when viewed from above the solar system. This is also known as the prograde rotation or the direct orbit.However, there are a few exceptions to this rule. Two planets, Venus and Uranus, have a different rotational axis than the rest of the planets.
This means that they appear to be rotating clockwise or retrograde, when viewed from above their respective poles.Venus rotates slowly and in the opposite direction of its orbit, causing the sun to rise in the west and set in the east. Uranus, on the other hand, has an extreme axial tilt, causing it to appear to be rotating on its side, with its poles almost parallel to the plane of the solar system.In summary, not all planets orbit in the same direction when viewed from above the earth's north pole. While the majority of planets in the solar system have a prograde rotation or direct orbit, Venus and Uranus are exceptions to this rule and have a retrograde rotation.
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The particle is an electron. the field slows down the electron without deflecting it. what is the direction of the electric field? choose the best answer.
Answers
The particle is an electron. The field slows down the electron without deflecting it. The direction of the electric field is right.
In physics, the motion of electrically charged particles gives rise to a field called an electric field. It is measured in force per unit charge.
This field applies force on other charged particles.
Particles bearing opposite charges attract each other while particles having similar charges repel each other in the field.
If a positive charge is placed in the field then the field line moves in an outward direction and for a negative charge, the direction of the lines is inward.
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Explain how humans produce speech sounds
Answers
The human vocal apparatus is an incredibly complex and efficient machine. The production of speech sounds begins with the diaphragm, a large, flat muscle located at the bottom of the lungs. When the diaphragm contracts, it increases the volume of the thoracic cavity and forces air into the lungs. The air then passes through the larynx, or voice box, which contains the vocal cords. The vocal cords are two thin bands of tissue that vibrate when air passes through them. The pitch of the resulting sound is determined by the tension of the vocal cords.
The sound of the vibrating vocal cords is then amplified by the resonating cavities of the head and mouth. The shape of the mouth cavity plays a significant role in the production of speech sounds. For example, the placement of the tongue, teeth, and lips all contribute to the creation of different vowel sounds. The hard and soft palate, along with the tongue, also help to create different consonant sounds.
11. What kind of force did the levitating rings display? What does this say
about the magnetic domains of these objects? Record your evidence.
Answers
answer :
force is called the magnetic force of repulsion, and it happens when two magnets have the same poles (either both north or both south) and they push away from each other.
When all the domains in a material are aligned in the same direction, the material becomes strongly magnetized.
explanation :
magnetic domains in the rings were stable and strong enough to resist the force of gravity.
In the case of the levitating rings, the magnetic domains were aligned in such a way that they created a strong magnetic field, which allowed the rings to levitate in mid-air.
tiny regions within ferro magnetic material that have their own magnetic fields are called magnetic domains.
Magnetic domains in the rings refer to the tiny regions within the ring's ferro magnetic material that have their own magnetic fields.
A man is sitting on a chair with wheels. He grabs a 2.1 kg book from the desk and throws
the book at a speed of 7.2 m/s. His chair moves backward. The man has a mass of 70 kg and
the chair has a mass of 9.2 kg. What is the speed of the man and the chair after the book is
thrown?
Answers
The speed of the man and the chair after the book is thrown is 0.2 m/s.
The given parameters:
mass of the book, m₁ = 2.1 kgspeed of the book, u₁ = 7.2 m/smass of the man, M = 70 kgmass of the book, m = 9.2 kgThe total mass of the man and the book is calculated as follows;
m₂ = 70 kg + 9.2 kg
m₂ = 79.2 kg
The speed of the man and the chair after the book is thrown is determined by applying the principle of conservation of linear momentum;
\(m_1 u_1 = m_2u_2\\\\u_2 = \frac{m_1u_1}{m_2} \\\\u_2 = \frac{2.1 \times 7.2}{79.2} \\\\u_2 = 0.2 \ m/s\)
Thus, the speed of the man and the chair after the book is thrown is 0.2 m/s.
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An unnamed professor is walking to class when an office chair (travelling in the same direction) collides with them. The professor fails into the chair and remains in the chair after collision. The professor, with a mass of 113kg, is travelling at 1.56 m/s. The chair has a velocity of 6.5 m/s, and a mass of 10kg. After the collision, and ignoring any effects of professor falling, what would be the speed of the chair professor system
Answers
Answer: 1.96 m/s
Explanation:
Given
Mass of Professor \(m_1=113\ kg\)
Velocity of professor \(u_1=1.56\ m/s\)
mass of chair \(m_2=10\ kg\)
velocity of chair \(u_2=6.5\ m/s\)
Suppose after the collision, v is the common velocity
Conserving momentum
\(\Rightarrow m_1u_1+m_2u_2=(m_1+m_2)v\\\\\Rightarrow v=\dfrac{113\times 1.56+10\times 6.5}{113+10}=\dfrac{241.28}{123}\\\\\Rightarrow v=1.96\ m/s\)
Wavelength and ________________ are linked properties of a wave.
Answers
Answer:
Frequency
Wavelength and frequency are both properties of waves and are related to one another.
A train travels for 120 seconds (s) at a speed of 50 meter per second (m/s). What was the distance (m) that it travelled?
Answers
Answer:
2
Explanation:
50 times 2
A 3 kg ball is moving at 2.0 m/s to the right. It runs into a 1 kg ball moving at 0.5 m/s to the left. The balls bounce off each other.
Q. If the 3 kg ball moves at 1 m/s to the left after the collision, how fast must the 1 kg ball be going after the collision? Show the equation and work
Answers
Answer:
The Answer Is O.5 m/s
Explanation:
we have an equation:
m1u1 + m2u2=m1v1 + m2v2(u is for before collison and v is for after collision)
rearrange,
m1u1 + m2u2 - m1v1 ÷ m2 = v2Put values and answer will be 0.5m/s
Answer:
3.5
Explanation:
we have an equation:
m1u1+m2u2=m1v1+m2v2 where, m=mass
v=final velocity
u=intial velocity
then this means:
v2=m1u1+m2u2-m1v1÷m2
when we substitute on the equation:
v2=3×2.0+1×0.5-3×1÷1
=6+0.5-3
=6.5-3
=3.5
What generates the energy produced when small light atoms are combined into heavier ones
A. Fusion reactions
B. Chemical reactions
C. Fission reactions
D. Nuclear chain reactions
Answers
Answer:
A. Fusion Reactions
Explanation:
the electrical power output of a large nuclear reactor facility is 950 mw. it has a 32.5fficiency in converting nuclear power to electrical.(a) What is the thermal nuclear power output in megawatts? (b) How many 235 U nuclei fission each second, assuming the average fission produces 200 MeV? (c) What mass of 235 U is fissioned in one year of full-power operation?
Answers
(a) The thermal nuclear power output of the large nuclear reactor facility is 1,462.5 MW.
(b) Approximately 5.786 × 10²⁰ ²³⁵U nuclei fission each second.
(c) The mass of ²³⁵U fissional in one year of full-power operation is approximately 1,416.5 kilograms.
Determine the thermal nuclear power?(a) To calculate the thermal nuclear power output, we divide the electrical power output by the efficiency: 950 MW / 0.325 = 1,462.5 MW.
(b) To determine the number of ²³⁵U nuclei fissioned per second, we use the relationship E = Nf × Ef, where E is the electrical power output, Nf is the number of fissions per second, and Ef is the energy released per fission. Rearranging the equation, Nf = E / Ef.
Substituting the values, we get 950 MW / (200 MeV × 10⁶ eV/MW) = 4.75 × 10²² fissions/s. Since each fission involves two nuclei, the number of ²³⁵U nuclei fissioned per second is approximately half of that value: 4.75 × 10²² / 2 = 2.375 × 10²² ²³⁵U nuclei/s, which is approximately 5.786 × 10²⁰ ²³⁵U nuclei/s.
(c) To calculate the mass of ²³⁵U fissioned in one year, we multiply the number of fissions per second by the number of seconds in a year and the molar mass of ²³⁵U. The molar mass of ²³⁵U is 235 grams/mol.
Using Avogadro's number (6.022 × 10²³ atoms/mol), we convert the number of nuclei to moles and then multiply by the molar mass: (5.786 × 10²⁰ nuclei/s) × (31,536,000 s/year) × (235 g/mol) / (6.022 × 10²³ atoms/mol) ≈ 1,416.5 kg.
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a 25 ohm resistor in an electric circuit draws a current of 5 amperes a certain amount of charge through the resistor in 36 seconds calculate the voltage
Answers
Answer:
V= 125volts
Explanation:
R =25ohms
I = 5 amp
V = ?
t = 36seconds
V = IR
V = 5× 25
V= 125volts
Q = It
Q = 5×36
Q = 180 coulombs
Q is the amount of charge.
There are cars with masses 4 kg and 10 kg respectively that are at rest. A car having the mass 10 kg moves towards the east with a velocity of 5 m.s-1. Find the velocity of the car with mass 4 kg with respect to ground.
Answers
Answer:
The velocity of the car of mass 4 kg with respect to ground is 0 m/s
Explanation:
The problem initially stated that the car is at rest. at this stage, the velocity of the car relative to the ground is already = 0 m/s.
When the 10 kg car began to move, the problem did not specify at any point that the 4 kg car began to move also. Hence, the motion of the 10 kg car did not affect the 4 kg car in any way.
As a result, relative to the ground, the velocity of the 4 kg car is still 0 m/s since no motion was recorded by the car.
A duck is floating on a lake with 28 % of its volume beneath the water. What is the average density of the duck?
Answers
The average density of the duck is determined to be 0.28 times the density of water.
What is the ratio between the duck's density and the density of water?To determine the average density of the duck, we can use the principle of buoyancy. When an object floats, it displaces a volume of liquid equal to its own weight. Therefore, the weight of the duck is balanced by the weight of the liquid it displaces.
Let's assume the total volume of the duck is V. Since 28% of its volume is beneath the water, the volume of water displaced by the duck is 0.28V.
The density of water is generally close to 1 g/cm³ or 1000 kg/m³. We can use this value to calculate the average density of the duck.
The weight of the water displaced by the duck is given by:
Weight of water = Density of water × Volume of water = 1000 kg/m³ × 0.28V
Since the weight of the duck is balanced by the weight of the water, the average density of the duck can be calculated as:
Average density of the duck = Weight of the duck / Volume of the duck
Since the weight of the duck is equal to the weight of the water displaced, we have:
Average density of the duck = Weight of water / Volume of the duck = (1000 kg/m³ × 0.28V) / V = 280 kg/m³
Therefore, the average density of the duck is 280 kg/m³.
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word scrumble pe grade nine
EESSNTILOP
Answers
i dont know
Explanation:
If the wavelength is 10 m and the frequency is 5 Hz, what is the wave speed?
Answers
V = 5 x 10
V = 50m/s
What is the power of a diverging lens of focal length 0.4 m
a) 2.5
b) 3.5
c)-3.5
d)-2.5
Answers
Answer:
-2.5 is the answer to your question
A boat floats in a lake. When the boat moves the force of resistance is proportional to the velocity of the boat. Initially the boat is at rest. A person walks from the stern to the bow of the boat. What will be the position of the boat long time after the person stopped moving?
Answers
Answer: Contant.
Explanation:
You are given that When the boat moves the force of resistance is proportional to the velocity of the boat. This means that the total momentum on the boat is equal to zero. Then the boat remains at a certain position.
When a person walks from the stern to the bow of the boat, the boat will tend to move in the opposite direction with equal magnitude of momentum. The magnitude of forces will thereby cancel out.
The person will be seen moving while the boat moves in the opposite direction.
If no external force is acting on the boat, the sum of the momentum of the person and the boat will be equal to zero. And the boat will remain at rest.
The position of the boat long time after the person stopped moving will therefore remain the same.