Answer:
10m/s
Explanation:
solution:
a= v-u / t
or,4= v-2 / 2
or,8= v-2
or,8+2= v
or,v = 10
The radius of a circle of area A and circumference C is doubled. find the new circumference of the circle in terms of C.
If the radius of a circle of area A and circumference C is doubled, the new circumference of the circle, in terms of C, will be equal to 2C.
The area (A) of a circle is given by:
\( A = \pi r^{2} \) (1)
And a circumference (C) is:
\( C = 2\pi r \) (2)
Where:
r: is the radius
If the radius of a circle and circumference is doubled, the new circumference of the circle is:
\( C_{2} = 2 (2 \pi r) = 2C \)
Therefore, the new circumference of the circle in terms of C is equal to 2C.
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A 40 kg surfer jumps off the front of a 20 kg surfboard moving forward. Find the surfboard’s velocity immediately after the girl jumps, assuming that the surfboard’s initial velocity is 2 m/s and the girl’s velocity when jumping off the front is 4 m/s.
According to the law of conservation of momentum,
\(m_1v_{1i}+m_2v_{2i}=m_1v_{1f}+m_2v_{2f}_{}_{}\)Where,
\(m_1=40\operatorname{kg},\text{ }m_2=20\operatorname{kg},v_{1i}=2m/s,v_{2i}=2m/s,\text{ }v_{1f}=4ms^{-1}_{}\)We need v2f
Substituting the known values in the equation,
\(40\times2+20\times2=40\times4+20\times v_{2f}\)Simplyfing,
\(120=160+20\times v_{2f}\)On rearranging the above equation we get,
\(v_{2f}=\frac{120-160}{20}=\frac{-40}{20}\)i.e.
\(v_{2f}=-2\text{ m/s}\)The negative sign indicates that the surfboard will move backward with a velocity of 2m/s after the surfer jumps off of it.
Mark and Nancy both take three measurements of the length of a pencil that is 15.1 cm. Mark records 15.0, 15.0, and 15.1 cm. Nancy records 15.1, 15.2, and 15.2 cm. Which of the following statements is true about Mark and Nancy's measurements?
A. Mark's measurement is more precise.
B. Nancy's measurement is more accurate.
C. Mark's measurement is more accurate.
D. Both sets of measurements are equally accurate and precise.
A) student applied two forces to the ring in the center of the force table F,= 300dyne at the angle of
309 with the +x-axis, and F7=: 400 dyne at the angle of 1209 with the +x-axis. Accordingly, the magnitude of equilibrant force is:
a) 430 dyne
b) 700 dyne
0) 100 dyne
d) 500 dyne
The magnitude of the equilibrant force is equal in magnitude but opposite in direction to the resultant vector R. Therefore, the magnitude of the equilibrant force is 500 dyne.
The correct answer is option D.
To find the magnitude of the equilibrant force, we need to determine the resultant of the two given forces and then find its opposite vector, which will be the equilibrant force.
Let's break down each force into its x-component and y-component:
For F1 = 300 dyne at an angle of 309° with the +x-axis:
F1x = F1 * cos(309°)
= 300 dyne * cos(309°)
= -259.8 dyne (negative because it is in the opposite direction of the positive x-axis)
F1y = F1 * sin(309°)
= 300 dyne * sin(309°)
= -150 dyne (negative because it is in the opposite direction of the positive y-axis)
For F2 = 400 dyne at an angle of 120° with the +x-axis:
F2x = F2 * cos(120°)
= 400 dyne * cos(120°)
= -200 dyne (negative because it is in the opposite direction of the positive x-axis)
F2y = F2 * sin(120°)
= 400 dyne * sin(120°)
= 346.4 dyne
Now, we can add the x-components and y-components separately:
Rx = F1x + F2x
= -259.8 dyne + (-200 dyne)
= -459.8 dyne
Ry = F1y + F2y
= -150 dyne + 346.4 dyne
= 196.4 dyne
The resultant vector R is given by:
R =\(\sqrt{(Rx^2 + Ry^2)}\)
= \(\sqrt{((-459.8 dyne)^2 + (196.4 dyne)^2)\\}\)
≈ 500 dyne
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The nuclear reaction that powers the sun involves the fusion of four protons (mp = 1.673x10-27 kg) into a helium nucleus (mHe = 6.645x10-27 kg). The process involves several steps, but the net reaction is simply: 4p He + energy. How much energy is released overall in each fusion process? Give your answer in J and MeV
Explanation:
it's 5 + 5 + 5 + 12 + 5 x 7 x 7 7+ 8 5+6+ +8 +9 + 9 5
A marble is thrown downward at a speed of 10.0 m/s from the top of a 30.0 m tall
building. 0.50 s later, a second marble is thrown downward. At what speed must the
second marble be thrown so that the two marbles reach the ground at the same time?
The speed of the second marble must be 14.8 m/s so that the two marbles reach the ground at the same time.
What is the time taken bey the first stone to reach the ground?The time taken by the first stone to reach the ground is calculated using the formula below:
h = ut + ¹/₂gt²
where:
h is the heightu is initial velocity or speedt is timeg is acceleration due to gravityFrom the data provided;
h = 30, u = 10m/s, g = 9.8 m/s
30 = 10t + 0.5 * 9.8t²
30 = 10t + 4.9t²
4.9t² + 10t - 30 = 0
t = 1.65 s
For the second marble, time taken = 1.65 - 0.50
t = 1.15 s
Initial velocity, u will be:
30 = u(1.15) + 0.5 * 9.8 * 1.15²
1.15u = 30 - 12.96
u = 14.8 m/s
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HI PLEASE HELP ON QUESTION ASAP USING AVERAGE (MEAN) TO ANSWER QUESTION! IF UR ANSWER AND EXPLAINATION IS CORRECT ILL RATE YOU FIVE STARS, A THANKS AND MAYBE EVEN BRAINLIEST. PLEASE MAKE SURE YOU ANSWER MY QUESTION USING AVERAGES.
1) a meal for 6 cost £12 per person. as it is one of the diners birthday , the other 5 decided to pay for his meal. how much do each of the five friends need to pay?
Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.
To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.
In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.
To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.
Total cost covered by the five friends = Total cost - Cost of one person's meal
= (£12 x 6) - £12
= £72 - £12
= £60
Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).
Amount each friend needs to pay = Total cost covered by the five friends / Number of friends
= £60 / 5
= £12
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What’s the potential and kinetic energy when it’s halfway down the hill?
According to the Law of Conservation of Mechanical Energy, if there are no external or non-conservative forces acting on a system (such as friction), then, the total mechanical energy of the system remains constant.
The mechanical energy of a system is the sum of its kinetic energy K and its potential energy U:
\(E=K+U\)The kinetic energy of a particle with mass m and speed v is:
\(K=\frac{1}{2}mv^2\)And the potential energy of a particle with mass m located at a height h is:
\(U=mgh\)Where g is the acceleration of gravity on the surface of Earth.
When the roller coaster car is located at the top of the 30.00-meter hill, its kinetic energy is 0 and its potential energy is:
\(U_1=(2500kg)(9.8\frac{m}{s^2})(30.00m)=735,000J\)Then, the total mechanical energy of the roller coaster car is:
\(E=U_1+K_1=735,000J+0J=735,000J\)On the other hand, the potential energy of the car when it is halfway down is:
\(U_2=(2500kg)(9.8\frac{m}{s^2})(15.00m)=367,500J\)Since the total mechanical energy is the same, we can find the kinetic energy of the car when it is halfway down using the law of conservation of mechanical energy:
\(\begin{gathered} E=U_2+K_2 \\ \\ \Rightarrow K_2=E-U_2=735,000J-367,500J=367,500J \end{gathered}\)Therefore, the potential and kinetic energy of the car when it is halfway down the hill at a height of 15.0 meters are:
\(\begin{gathered} U_2=367,500J \\ K_2=367,500J \end{gathered}\)Using PE for potential energy and KE for kinetic energy:
\(\begin{gathered} PE=367,500J \\ KE=367,500J \end{gathered}\)Therefore, the correct choice is the second option.
hich of the following is a minimal sum-of-products (SOP) equation that implements the same logic as the equation f(a, b, c) = a(b + c') + ac a. f = ab + ac b. f = ab + ac' + be c. f=a d. f = b(a + d) e. f = a(b + b)(b + c)
The minimal SOP equation that implements the same logic as the given equation is f = ab + ac.
What is SOP?The sum of product (SOP) is a type of logic circuit used to represent a logical expression. It is also known as a canonical sum of products and is a type of canonical form. An SOP expression is composed of one or more product terms. Each product term is the logical AND of one or more literals and is separated from other product terms with a plus sign. The sum of product form of a logic expression is a sum of the product terms of the expression.
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light travels approximately 982,080,000 ft/s, and one year has approximately 32,000,000 seconds. A light year is the distance light travels in one year.
Answer:
The distance traveled in 1 year is: \(3.143*10^{16}ft\)
Explanation:
Given
\(s = 982,080,000 ft/s\) --- speed
\(t = 32,000,000 s\) --- time
Required
The distance traveled
This is calculated as:
\(Speed = \frac{Distance}{Time}\)
So, we have:
\(Distance = Speed * Time\)
This gives:
\(Distance = 982,080,000 ft/s * 32,000,000 s\)
\(Distance = 982,080,000 * 32,000,000ft\)
\(Distance = 3.143*10^{16}ft\) -- approximated
the weight of a boy having a mass of 50 kg is_____ N
Answer: 490
Explanation:
this is a FRQ test for AP Physics I NEED IT DONE IN 2 HOURS: A dart with mass md
is launched toward a block of mass mb
that is suspended from a string of length L, as shown at left above. The dart is moving horizontally with speed v immediately before it strikes the block and remains embedded. The dart-block system then swings up to a point at which its center of mass reaches a maximum height H above its starting position, as shown at right above. The block’s mass mb
is greater than the dart’s mass md
.
(a) Indicate which object, the dart or the block, if either, experiences an impulse of larger magnitude during the collision. If the impulse is the same magnitude for both objects, state this explicitly. Briefly explain your reasoning.
The dart experiences an impulse of larger magnitude during the collision. This is because the dart has less mass than the block, so the same amount of momentum change will result in a larger impulse.
What is momentum ?Momentum is a physical concept that describes the tendency of an object to remain in motion with the same speed and direction unless it is acted on by an outside force. It is a measure of an object's inertia and is often expressed as the product of its mass and velocity. Momentum is a vector quantity, meaning that it has both magnitude and direction. Momentum is conserved in closed systems, meaning that the momentum before an interaction is equal to the momentum after the interaction. This is known as the law of conservation of momentum and can be used to solve many problems involving collisions and other interactions between objects.
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Consider a ball on a circular track. The ball is slowly coming to a stop which takes 15.0 seconds. At the start, the ball was moving around with 9.13 rad/s. Calculate the angular deceleration if the ball traveled across 90 radians.
The answer should be -0.42 rad/s2
I don't know how to solve it
The angular deceleration of the ball is -0.42 rad/s².
What is angular acceleration?Angular acceleration is a measure of the rate of change of angular velocity of an object rotating about an axis. When an object rotates, its angular velocity (ω) can change as a result of various factors, such as the application of an external torque or the redistribution of mass in the object.
We can use the formula for angular acceleration:
α = (ωf - ωi) / t
where
α is the angular acceleration
ωi is the initial angular velocity
ωf is the final angular velocity (which is zero in this case since the ball comes to a stop)
t is the time it takes for the ball to come to a stop
To find the initial and final angular positions, we can use the formula:
θf - θi = ωi * t + (1/2) * α * t²
where
θi is the initial angular position (0 in this case)
θf is the final angular position (90 radians in this case)
Substtuting the given values, we have:
θf - θi = ωi * t + (1/2) * α * t²
90 - 0 = (9.13 rad/s) * 15 s + (1/2) * α * (15 s)²
Simplifying and solving for α, we get:
α = -0.42 rad/s²
Therefore, the angular deceleration of the ball is -0.42 rad/s².
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physics homework helpCell phones use electromagnetic radiation with an energy of about 1.08J/mol photons. Calculate the wavelength and frequency that can be used to describe light with this energy.
The formula for calculating the energy of radiation is expressed as
E = hf
where
E is the energy
h is the planck constant = 6.626 x 10^-34
f is the frequency of the wave
From the information given,
011 10.0 points
A highway curves to the left with radius of
curvature of 45 m and is banked at 15° so
that cars can take this curve at higher speeds.
Consider a car of mass 1897 kg whose tires
have a static friction coefficient 0.87 against
the pavement.
top view
R= 45 m.
15°
rear
view
= 0.87
low fast can the car take this curve without
skidding to the outside of the curve? The
acceleration of gravity is 9.8 m/s?.
Answer in units of m/s.
Answer:
23.52(m/s) is the fastest it can go
Nowadays, the average person encounters more than a hundred advertisements a day, be it in the form of TV and radio commercials, billboards, online promotions, and print ads, among many others. From all the advertisements you encounter, which one caught your attention? Why? Looking at the root of it, what was the underlying cause of the promotion? What does it target? Whom does it target? How does it convey message to target clientele? Is the promoted product a trend or a fad? ESSAY WRITTING PLEASE HELP ME
The essence of the commercial is to draw the attention of the public to the products of a firm.
What is a commercial?Commercials are the primary ways by which companies promote their products. The essence of the commercial is to draw the attention of the public hence the commercial is designed with music graphics and other means that aid effective communication.
The commercial that got my attention is that of the United Bank for Africa owing to the beautiful blend of orchestra music used in the advertisement which appeals immediately to the mind. The advert targets the business class in the society and aims at granting soft credit to small and medium scale entrepreneurs. It conveys its message to the clientele via music. The advert can be regarded as a trend.
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How to solve conservation of momentum
Answer:
Step 1: List the mass and velocity of the object. Step 2: Convert any values into SI units (kg, m, s). Step 3: Multiply the mass and velocity of the object together to get the momentum of the object.
A pendulum built from a steel sphere with radius r cm 5 and density stl kg m S 3 7800 is attached to an aluminum bar with length l m 1 thickness t cm 0 8. and width w cm 4 and density . al kg m S 3 2820 a. Calculate the mass moment of inertia of the pendulum about its center of mass, . cm I b. Calculate the mass moment of inertia of the pendulum about its pivot point, o
Answer:
1) I_ pendulum = 2.3159 kg m² , 2) I_pendulum = 24.683 kg m²
Explanation:
In this exercise we are asked to calculate the moment of inertia of a physical pendulum, let's start by calculating the center of mass of each elements of the pendulum and then the center of mass of the pendulum
Sphere
They indicate the density of the sphere roh = 37800 kg / m³ and its radius
r = 5 cm = 0.05 m
we use the definition of density
ρ = M / V
M = ρ V
the volume of a sphere is
V = 4/3 π r³
we substitute
M = ρ 4/3 π r³
we calculate
M = 37800 4/3 π 0.05³
M = 19,792 kg
Bar
the density is ρ = 32800 kg / m³ and its dimensions are 1 m,
0.8 cm = 0.0008 m and 4cm = 0.04 m
The volume of the bar is
V = l w h
m = ρ l w h
we calculate
m = 32800 (1 0.008 0.04)
m = 10.496 kg
Now we can calculate the center of mass of the pendulum, we use that the center of mass of the sphere is its geometric center, that is, its center and the center of mass of the bar is where the diagonals intersect, in this case it is a very bar. long and narrow, whereby the center of mass is about half the length. It's mass scepter of the pendulum is
r_cm = 1 / M (M r_sphere + m r_bar)
M = 19,792 + 10,496 = 30,288 kg
r_cm = 1 / 30,288 (10,496 0.5 + 19.792 (1 + 0.05))
r_cm = 1 / 30,288 (5,248 + 20,7816)
r_cm = 0.859 m
This is the center of mass of the pendulum.
1) Now we can calculate the moment of inertia with respect to this center of mass, for this we can use the theorem of parallel axes and that the moments of inertia of the bodies are:
Sphere I = 2/5 M r2
Bar I = 1/12 m L2
parallel axes theorem
I = I_cm + m D²
where m is the mass of the body and D is the distance from the body to the axis of rotation
Sphere
m = 19,792 ka
the distance D is
D = 1.05 -0.85
D = 0.2 m
we calculate
I_sphere = 2/5 19.792 0.05 2 + 19.792 0.2 2 = 0.019792 +0.79168
I_sphere = 0.811472 kg m²
Bar
m = 10.496 kg
distance D
D = 0.85 - 0.5
D = 0.35 m
I_bar = 1/12 10.496 0.5 2 + 10.496 0.35 2 = 0.2186 + 1.28576
I_bar = 1.5044 kg m²
The moment of inertia is a scalar quantity whereby the moment of inertia of the body is the sum of the moment of the parts
I_pendulum = I_sphere + I_bar
I_pendulum = 0.811472 +1.5044
I_ pendulum = 2.3159 kg m²
this is the moment of inertia of the pendulum with respect to its center of mass located at r = 0.85 m
2) The moment is requested with respect to the pivot point at r = 0 m
Sphere
D = 1.05 m
I_sphere = 2/5 M r2 + M D2
I_sphere = 2/5 19.792 0.05 2 + 19.792 1.05 2 = 0.019792 +21.82
I_sphere = 21.84 kg m²
Bar
D = 0.5 m
I_bar = 1/12 10.496 0.5 2 + 10.496 0.5 2 = 0.21866 + 2.624
I_bar = 2,84266 kg m 2
The pendulum moment of inertia is
I_pendulum = 21.84 +2.843
I_pendulum = 24.683 kg m²
This moment of inertia is about the turning point at r = 0 m
Two forces act on an object. The first force has a magnitude of 15.0 N and is oriented 68.0° counterclockwise from the + ‑axis, whereas the second force has ‑ and y‑components (−19.0 N,18.5 N).
Express the magnitude and direction of the net force.
The magnitude of the net force is 5.11 N and its direction is 5.59° counterclockwise from the +x-axis.
What is the x-component of the net force acting on the object in the previous question?The x-component of the net force is 5.11 N, which is equal to the x-component of the first force.
To determine the magnitude and direction of the net force, we need to first add the x and y components of the two forces:
Fx = 15.0 N cos 68.0° = 5.11 N
Fy = -19.0 N + 18.5 N = -0.5 N
The net force is the vector sum of these two forces:
Fnet = sqrt[(5.11 N)^2 + (-0.5 N)^2] = 5.11 N
To find the direction of the net force, we can use trigonometry:
θ = tan^-1(Fy/Fx) = tan^-1(-0.5 N/5.11 N) = -5.59°
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A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 4.65 m/s. The car is a distance d away.
The bear is 32.4 m behind the tourist and running at 5.68 m/s. The tourist reaches the car safely. What is the maximum possible
value for d?
Answer:
146.27 m
Explanation:
From the question given above, the following data were obtained:
Velocity of tourist (vₜ) = 4.65 m/s
Distance travelled by tourist (dₜ) = d
Velocity of bear (v₆) = 5.68 m/s
Distance travelled by bear (d₆) = 32.4 + d
Value of d =?
Next, we shall determine the time taken for tourist and the bear to get to the car.
For the tourist:
Velocity of tourist (vₜ) = 4.65 m/s
Distance travelled by tourist (dₜ) = d
Time (tₜ) =?
vₜ = dₜ / tₜ
4.65 = d/tₜ
Cross multiply
4.65 × tₜ = d
Divide both side by 4.65
tₜ = d / 4.65
For the bear:
Velocity of bear (v₆) = 5.68 m/s
Distance travelled by bear (d₆) = 32.4 + d
Time (t₆) =?
v₆ = d₆ / t₆
5.68 = (32.4 + d) / t₆
Cross multiply
5.68 × t₆ = (32.4 + d)
Divide both side by 5.68
t₆ = (32.4 + d) / 5.68
NOTE: Both the tourist and the bear have the same time. Thus, to obtain the value of d, we shall equate both the time taken for the tourist and the bear together. This is illustrated below:
Time taken by tourist (tₜ) = time taken by the bear (t₆)
tₜ = d / 4.65
t₆ = (32.4 + d) / 5.68
tₜ = t₆
d / 4.65 = (32.4 + d) / 5.68
Cross multiply
d × 5.68 = 4.65 (32.4 + d)
5.68d = 150.66 + 4.65d
Collect like terms
5.68d – 4.65d = 150.66
1.03d = 150.66
Divide both side by 1.03
d = 150.66 / 1.03
d = 146.27 m
Thus, the maximum value of d is 146.27 m
what are the factors affecting center of mass in an object
A 43 kg rock is dropped from a 36 tower. How long does it take the rock to fall to the ground?
A 43-kg rock is dropped from a 36 m, experiencing a Uniformly Accelerated Motion and falling to the ground 2.7 s later.
What is a Uniformly Accelerated Motion?A Uniformly Accelerated Motion is a motion in which the acceleration of the object is constant.
A 43 kg rock is dropped from a 36 m tower. Given the only acceleration is that of gravity, we can calculate the time required to hit the ground using the following kinematic equation.
s = 1/2 × a × t²
t = √(2s / a)
t = √[2 × 36 m / (9.8 m/s²)] = 2.7 s
where,
s is the displacement.a is the acceleration.t is the time.A 43-kg rock is dropped from a 36 m, experiencing a Uniformly Accelerated Motion and falling to the ground 2.7 s later.
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When water changes from a gas in the atmosphere to a liquid droplet in a cloud, this is known as
Group of answer choices
transpiration
condensation
evaporation
precipitation
Answer:
Condensation
Explanation:
Answer:When water changes from a gas in the atmosphere to a liquid droplet in a cloud, this is known as
Group of answer choices
transpiration
condensation
evaporation
precipitation,←, that one is right
Explanation: so ur answer is precipitation
Consider a collection of charges in a given region and suppose all other charges are distant and have a negligible effect. Further, the electric potential is taken to be zero at infinity. If the electric potential at a given point in the region is zero, which of the following statements must be true?
A. The electric field is zero at that point.
B. The charges have the same sign and are symmetrically arranged around the given point.
C. The electric potential energy is a minimum at that point.
D. There is no net charge in the region.
E. Some charges in the region are positive, and some are negative.
Answer:
E. Some charges in the region are positive, and some are negative.
Explanation:
Electric potential is given as;
\(V = \frac{W}{Q}\)
where;
W is the work done in moving a charge between two points which have a difference in potential
Q is quantity of charge in the given region
If the electric potential at a given point in the region is zero, then sum of the charges in the given region must be equal to zero. For the charges to sum to zero, some will be positive while some will be negative,.
Therefore, the correct statement in the given options is "E"
E. Some charges in the region are positive, and some are negative.
If an object is placed at a distance of 12 cm from a convex lens of focal length 16 cm then calculate the image distance from the lens?
Answer:
-48cm
Explanation:
For a convex lens f is +ve and V is +ve
Using the formula 1/f=1/v+1/u
u=12cm and f=16cm
1/16-1/12=1/v
1/v=-1/48
v=-48cm
Which of the following is not related to unbalanced forces?
A. Motion
B. Being still
C. Falling over
D. Acceleration
Choose 1
Answer: D
Explanation:
Answer
B. Being stillExplanation
Hope it help you
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Hydrogen bonds create unusual properties in water. What are they?
Answer:Liquid water is denser than Ice.
Ice float on top of liquid water.
Explanation:
Just trust me
A pitcher throws a baseball from the pitcher's mound to home plate in 0.46 s. The
distance is 18.4 m. What was the average speed of the baseball?
a. 40 m/s
b. - 40 m/s
c. 0.03 m/s
d. 8.5 m/s
The average speed of the baseball is option a. 40 m/s .
To calculate the average speed of the baseball, we use the formula:
Average Speed = Distance / Time
Given:
Distance = 18.4 m
Time = 0.46 s
Plugging in the values, we have:
Average Speed = 18.4 m / 0.46 s = 40 m/s
Therefore, the average speed of the baseball is 40 m/s.
Option a, 40 m/s, is the correct answer. This means that the baseball traveled an average distance of 40 meters per second from the pitcher's mound to home plate.
Average speed is a scalar quantity that represents the total distance traveled divided by the total time taken. It gives us an idea of how fast an object is moving on average over a given distance.
In this case, the baseball covered a distance of 18.4 meters in a time of 0.46 seconds. Dividing the distance by the time gives us the average speed of 40 m/s.
It's important to note that average speed is a measure of the overall rate of motion and does not provide information about the direction of motion. Therefore, negative values such as option b (-40 m/s) or extremely small values such as option c (0.03 m/s) are not appropriate in this context.
Option d (8.5 m/s) is also incorrect as it does not match the calculated average speed of 40 m/s.
Therefore, the correct answer is option a, 40 m/s, as it accurately represents the average speed of the baseball.
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The graph shows the maximum amount of water vapor that air can hold at different temperatures.
Line graph of maximum humidity on a coordinate plane. X-axis labeled Temperature (degrees Celsius). Y-axis labeled Water Vapor Density grams per cubic meter. Line starts at (0, 2) and gradually rises through (30, 30), 35, 40), (40, 50), (45, 62).
Beth’s hygrometer is reading a temperature of 30°C and a relative humidity of 65%. The humidity in the air is
grams/cubic meter.
Beth’s hygrometer is reading a temperature of 30°C and a relative humidity of 65%. The humidity in the air is 19.5 grams/cubic meter.
What is the humidity?The actual vapor density or humidity can be determined from the relative humidity value and the saturation vapor density.
The formula that relates the actual vapor density or humidity, the relative humidity, and the saturation vapor density is given below:
relative humidity = (actual vapor density / saturation vapor density) x 100%Hence, the actual vapor density can be calculated as follows:
Actual vapor density or humidity = relative density * saturation vapor density / 100
From the graph;
saturation vapor density at 30°C = 30 g/cm³
relative humidity = 65%
Humidity = 65 * 30 / 100
Humidity = 19.5 g/cm³
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Which choice is the best description of a well-defined, testable question for a science experiment?
The scientist has created questions for people to answer after they read about the science investigation.
The question is clearly stated, the question can be tested in an experiment, and the results can be measured.
The words are all defined in a glossary and a test can be given to see what students learned.
An experiment can be completed to help define the meaning of scientific words and phrases.
The best description of a well-designed testable question is "The question is clearly stated, the question can be tested in an experiment, and the results can be measured".
What is a scientific question?This type of question is the one that focuses on facts and aims at testing a hypothesis.
What are the features of a scientific question?Some features include:
The question is clear as it lets the reader know the phenomenon being studied.The question can be tested which means it is based on a phenomenon that can be studied through exact instruments.The results can be measured, which means the question leads to evidence.Learn more about science in: https://brainly.com/question/935949
Answer:
b
Explanation: