A boy throws a ball on a spring scales which oscillates about the equilibrium position with a period of T = 0.5 sec. The amplitude of the vibration is A = 2 cm. Assume the ball does not bounce from the scales’s surface afterwards. Assume the vibration of the scale is expressed mathematically as x(t) = Acos(t + ). Find:

Some object remains hot for a long period of time because they have low thermal conductivity and some object remain hot for a short period of time because they have high thermal conductivity.

Thermal conductivity is a property of a substance to allow heat to flow through it easily.

Thermal conductivity is a measure of how well a substance will conduct heat or not.

Objects that have high thermal conductivity gain heat easily and also lose heat easily. Hence, they get hot quickly and also get cold quickly.

Objects that have low thermal conductivity gain heat slowly and also lose heat slowly. Hence, they get hot slowly and also get cold slowly.

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Answer:

velocity

Explanation:

Answer:

Velocity

Velocity tells you the speed and the direction it's going. Speed only tells you the speed, with no direction.

Explanation:

Explanation:

We are going to use the following equation:

\(v = v_0 + at \Rightarrow t = \dfrac{v - v_0}{a}\)

\(t = \dfrac{15\:\text{m/s} - 10\:\text{m/s}}{3\:\text{m/s}^2}\)

\(\:\:\:\:=1.67\:\text{s}\)

Answer:

Current in a parallel circuit = 0.61 amps (Approx)

Explanation:

Given:

Voltage V = 6 volt

Two resistors = 17.2 , 22.4 in parallel circuit

Find:

Current in a parallel circuit

Computation:

1/R = 1/r1 + 1 / r2

1/R = 1/17.2 + 1 / 22.4

R = 9.73 ohms (Approx)

Current in a parallel circuit = V / R

Current in a parallel circuit = 6 / 9.73

Current in a parallel circuit = 0.61 amps (Approx)

Answer: .4 m/s^2

Explanation: Since there are two forces going the opposite way, you will substract them so 14 - 10 = 4, and now to find the acceleration, we will use the sum of all forces equation, f=ma.

4 = 10a

a = .4

The acceleration of the object is 0.4 m/s^2. The correct answer is B. 0.4 m/s².

Force is defined as an object which is in a state of motion then its rate of change of moment is called force.

Here,
To find the acceleration of the object, we need to use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object times its acceleration. In this case, the net force is the vector sum of the two forces acting on the object,

Net force = 14 N to the right - 10 N to the left = 4 N to the right

So, the net force acting on the object is 4 N to the right. Using Newton's second law, we can calculate the acceleration,

Net force = mass x acceleration
4 N = 10 kg x acceleration
acceleration = 4 N / 10 kg = 0.4 m/s²

Therefore, the acceleration of the object is 0.4 m/s². The correct answer is B. 0.4 m/s².

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Answer:

True

Explanation:

yes we can see that we are helping animals but we create pollution which is very bad

Weight of  jenny's book will be 10N.

The force exerted on an object by gravity is known as its weight. Weight is the result of multiplying the mass by the acceleration that is acting on it. The pound (lb), which is the most often used unit of weight, is equivalent to 1 kilogram meter per second squared (N), the SI unit of weight. The impact of gravity (or another acceleration) on an object is quantified by its weight. At various points on the Earth, two causes alter weight. Weight reduces as altitude rises. Latitude also affects weight.

Area=200cm²

p=0.05N/cm²

weight=thrust=Force

p=F/A

0.05×200=F

F=10N

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The average velocity for completing three rounds of the basketball court would be zero as initial and final position would be zero and the average speed would be 3.28 m/s.

Average velocity is defined as the total displacement divided by the total time take to compete the total displacement.

Average speed is defined as the total distance divided by the total time take to compete the total distance.

Given:

Side of the baseball court = 100 meter

Total time taken to complete three rounds of the basketball court = 375 seconds

Total distance traveled by the player can be measured using the given side of the basketball court.

First we will find the parameter of the court,

Parameter of the court = 4 times the side of basketball court

Parameter of the basketball court = 4 × 100

Parameter of the basketball court = 400 metre

The player goes for 3 rounds of the basketball court which makes the total distance three times the parameter of the basketball court.

Total distance traveled by the basketball player = 3 × 400

Total distance traveled by the basketball player = 1200 metre

Average velocity is displacement divided by time taken.

Total displacement = 0 metre

As the player reaches the same position from where he started so the total displacement is zero.

Therefore, average velocity = 0/365

average velocity = 0 m/s

Average speed = 1200/365

Average speed = 3.28 m/s

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The mass of Car B is -6000 kg.

To solve this problem, we can apply the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.

Therefore, we can write the equation for the conservation of momentum as:

(mass of Car A * velocity of Car A) + (mass of Car B * velocity of Car B) = (mass of Car A + mass of Car B) * velocity after collision

Let's substitute the given values into the equation:

(2000 kg * 10 m/s) + (mass of Car B * 0 m/s) = (2000 kg + mass of Car B) * (-5 m/s)

Simplifying the equation:

20000 kg*m/s = -5 m/s * (2000 kg + mass of Car B)

Dividing both sides by -5 m/s:

-4000 kg = 2000 kg + mass of Car B

Subtracting 2000 kg from both sides:

mass of Car B = -4000 kg - 2000 kg

mass of Car B = -6000 kg

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Answer:

which on a is the question

Here are five potential-kinetic energy conversions that could be shown in the construction of a device: Pendulum, Roller Coaster, Wind-up Toy, Elastic Slingshot, Windmill.

Pendulum: A pendulum consists of a weight attached to a string or rod, suspended from a fixed point. When the weight is lifted to a certain height, it possesses gravitational potential energy.

As the weight is released, it swings back and forth, converting the potential energy into kinetic energy. At the highest point of each swing, the weight briefly comes to a stop and has maximum potential energy, which is then converted back to kinetic energy as it swings downward.

Roller Coaster: In a roller coaster, potential-kinetic energy conversions occur throughout the ride. When the coaster is pulled up to the top of the first hill, it gains gravitational potential energy.

As the coaster descends, the potential energy is converted into kinetic energy, resulting in a thrilling and high-speed ride. Subsequent hills and loops continue to convert potential energy into kinetic energy and vice versa as the coaster moves along the track.

Wind-up Toy: Wind-up toys typically have a spring mechanism inside. When the toy is wound up, potential energy is stored in the wound-up spring. As the spring unwinds, it transfers its potential energy into kinetic energy, causing the toy to move or perform actions. The kinetic energy gradually decreases as the spring fully unwinds.

Elastic Slingshot: With an elastic slingshot, potential-kinetic energy conversions are evident when the slingshot is stretched. As the user pulls back on the elastic band, potential energy is stored.

Windmill: Windmills harness the kinetic energy of the wind and convert it into other forms of energy. As the wind blows, it imparts kinetic energy to the blades of the windmill. The rotating blades then transfer this kinetic energy into mechanical energy, which can be used for various purposes such as grinding grains or generating electricity.

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Answer:

A. 450 N

B. 3240 J

C. 0.77 KW

Explanation:

From the question given above, the following data were obtained:

Height of one step = 20 cm

Number of steps = 36

Mass of runner = 45 kg

Time taken = 4.2 s

Next, we shall convert 20 cm to metre (m). This can be obtained as follow:

100 cm = 1 m

Therefore,

20 cm = 20 cm × 1 m /100 cm

20 cm = 0.2 m

Next, we shall determine the total height. This can be obtained as follow:

Height of one step = 0.2 m

Number of steps = 36

Total height =?

Total height = 36 × 0.2

Total height = 7.2 m

A. Determination of the runner's weight.

Mass of runner (m) = 45 kg

Acceleration due to gravity (g) = 10 m/s²

Weight (W) =?

W = m × g

W = 45 × 10

W = 450 N

B. Determination of the increase in the potential energy.

At the ground level, the potential energy (PE₁) is 0 J.

Next, we shall determine the potential energy at 7.2 m. This can be obtained as follow:

Mass of runner (m) = 45 kg

Acceleration due to gravity (g) = 10 m/s²

Total height (h) = 7.2 m

Potential energy at height 7.2 m (PE₂) = ?

PE₂ = mgh

PE₂ = 45 × 10 × 7.2

PE₂ = 3240 J

Final, we shall determine the increase in potential energy. This can be obtained as follow:

Potential energy at ground (PE₁) = 0 J

Potential energy at height 7.2 m (PE₂) = 3240 J

Increase in potential energy =?

Increase in potential energy = PE₂ – PE₁

Increase in potential energy = 3240 – 0

Increase in potential energy = 3240 J

C. Determination of the power.

Energy (E) = 3240 J

Time (t) = 4.2 s

Power (P) =?

P = E/t

P = 3240 / 4.2

P = 771.43 W

Finally, we shall convert 771.43 W to kilowatt (KW). This can be obtained as follow:

1000 W = 1 KW

Therefore,

771.43 W = 771.43 W × 1 KW / 1000 W

771.43 W = 0.77 KW

Therefore, her power is 0.77 KW

The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J

First, we shall list out the given parameters from the question. This is shown below:

The quantity of heat energy that must be transferred can be obtained as follow:

Q = MCΔT

= 2.25 × 394 × 220

= 195030 J

Thus, we can conclude quantity of heat energy that must be transferred is 195030 J

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1. A complete fitness and exercise program should incorporate three basic components: Endurance (Aerobic), Flexibility, and Strength. Each of these components has specific guidelines, which govern their effectiveness

The compressive force that would be enough to produce a fracture is 4000 N.

We know that the femur is one of the most important bones that we have in the human body. In this case, we have been told that In the human femur, bone tissue is strongest in resisting compressive force, approximately half as strong in resisting tensile force, and only about one- fifth as strong in resisting shear force.

Then we know that;

Tensile force = 8000

The compressive force would be half of this magnitude as such;

Compressive force = 4000 N

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Answer:

3.91m/s

Explanation:

We can use the equation h=16t^2 to find the height in feet for a free-falling object. The height from the bridge to the water is h=16(0.4)^2=16(0.16)=2.56 ft

Next, we use the equation v=sqrt(2gh) to determine velocity from vertical height. First we must convert feet to meters as velocity is measured in m/s. 2.56ft is about 0.78 meters. Since h=0.78m from the previous equation and g=9.81m/s^2, then your velocity is v=sqrt(2*9.81*0.78)=sqrt(15.3036)=3.911981595

So, your speed/velocity is approximately 3.91m/s

Answer:

Choice a. \(70\; \rm N\), assuming that the skating rink is level.

Explanation:

There are two horizontal forces acting on the boy:

The boy should be moving in the direction of the pull of his friend. The frictions on this boy should oppose that motion. Therefore, the frictions on the boy would be in the opposite direction of the pull of his friend.

The net force in the horizontal direction should then be the difference between the pull of the friend, and the friction on this boy.

\(\text{Net force, horizontal} = 75\; \rm N - 5\; \rm N = 70\; \rm N\).

The net force on this boy should be zero in the vertical direction. Consider Newton's Second Law of motion. The net force on an object is proportional to its acceleration. In this question, the net force on this boy in the vertical direction should be proportional to the vertical acceleration of this boy.

However, because (by assumption) the ice rink is level, the boy has no motion in the vertical direction. His vertical acceleration will be zero. As a result, the net force on him should also be zero in the vertical direction.

Therefore, the (combined) net force on this boy would be:

\(\sqrt{(70\; \rm N)^2 + (0\; \rm N)^2} = 70\; \rm N\).

At height h, on the left side of a loop, a stone is let free from its resting position. h = v^2/(2 x g) + r must the stone be at in order to stay on the track at the top of the loop.

For a stone to not fall off the track at the top of a loop, it must be traveling fast enough to follow the track's curvature. This means that the stone must have a certain minimum speed at the top of the loop in order to complete it from resting position. The minimum speed required for the stone to complete the loop can be calculated using the equation v = sqrt(gr), where v is the minimum speed, g is the acceleration due to gravity, and r is the radius of the loop. Therefore, the minimum height h for which the stone will not fall off the track at the top of the loop can be calculated using the equation h = v^2/(2*g) + r, where h is the minimum height, v is the minimum speed, g is the acceleration due to gravity, and r is the radius of the loop.

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The example provided is most closely related to option C: Performance accomplishments.

Setting a mileage goal each week and becoming more confident about finishing the race indicates that Tina is actively working towards her goal of running a 5k race. By gradually increasing her mileage and gaining confidence, she is achieving performance accomplishments, which involve personal achievements and successful experiences.

Physiological states refer to the influence of one's physical and emotional condition on their confidence and motivation. Verbal persuasion involves receiving encouragement or positive feedback from others. Vicarious experience entails gaining confidence by observing and learning from others' successes.

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Answer:

a)A-B =(1,0,-3) +(2,-5,-1) =(3, -5, -4);    

b)B-C =(-2-3, 5-1, 1-1) = (-5,4,0);  

c)-A +(B –C) = (-1,0,3) +(-5,4,0) =(-6,4,3);  

d) =(3,0,-9) –(6,2,2) = (-3, -2, -11);  

e) = (-2,0,6) +(-6,15,3) +(-3,-1,-1) =

d) = (2,0,-6) –(-5*3, 4*3, 0) =  

Explanation:

1)C=k*A = (k*a1, k*a2, k*a3);

2)C=-A = -1*A;

3)C= A+B = (a1+b1, a2+b2, c2+c2);

4)C=A-B =A +(-B);  

5)A+B=B+A;  

6)A+B+C =(A+B)+C =A+(B+C

Given the speed of the driver and the time elapsed, distance traveled during his inattentive period is 0.037 kilometers.

Speed is simply referred to as distance traveled per unit time.

Mathematically, Speed = Distance ÷ time.

Given the data in the question;

First, convert 1.7 seconds to hours.

Time = 1.7s = (1.7 / (60×60)hr = 1.7/3600 hrs

Now, find the distance traveled during the inattentive period.

80 km/h = Distance ÷ 1.7/3600 hrs

Distance = 80 km/h × 1.7/3600 hrs

Distance = 136/3600 km

Distance = 0.037 km.

Given the speed of the driver and the time elapsed, distance traveled during his inattentive period is 0.037 kilometers.

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Pressure builds under the surface of Earth, causing mountains to form.The correct answer is option D.

Uplift refers to the geological process that elevates the Earth's surface, resulting in the formation of mountains. This process is primarily driven by tectonic forces, including the movement and collision of Earth's lithospheric plates.

When two plates converge, immense pressure builds up beneath the surface, causing the crust to buckle and fold. This deformation leads to the formation of mountains, as rocks are pushed upward and displaced vertically.

As the uplift process continues over millions of years, mountains gradually take shape. Erosion and weathering play significant roles in shaping their features, but it is the initial uplift that initiates the formation of mountains.

As the Earth's surface is elevated, a wide range of landforms can emerge, including rugged peaks, deep valleys, and steep slopes.

Uplift has a profound impact on the Earth's surface and ecosystems. Mountains alter local climates, influencing precipitation patterns and creating variations in temperature and wind patterns.

Therefore, uplift plays a crucial role in shaping the Earth's surface and influencing various geological, biological, and climatic processes.

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The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.

The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.

Initially, the capacitor is uncharged, so the second term is zero.

Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.

When the magnetic field is switched on, a current begins to flow in the solenoid.

This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.

Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.

The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.

Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.

This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.

The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)

The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)

The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)

This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.

The solution is t = 1.74 ms.

The units are in seconds.

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(a) The work done by the 150 N force is 877.5 Joules.

(b) The coefficient of kinetic friction between the crate and the surface is approximately 0.437.

To answer this problem, we must take into account the work done by the applied force as well as the work done by friction.

(a) The applied force's work may be estimated using the following formula:

Work = Force * Distance * cos(theta)

where the force is 150 N and the distance is 5.85 m. Since the force is applied horizontally and the displacement is also horizontal, the angle theta between them is 0 degrees, and the cosine of 0 degrees is 1.

As a result, the applied force's work is:

Work = 150 N * 5.85 m * cos(0) = 877.5 J

So, the work done by the 150 N force is 877.5 Joules.

(b) Frictional work is equal to the force of friction multiplied by the distance. The work done by friction is identical in amount but opposite in direction to the work done by the applied force since the crate travels at a constant speed.

The frictional work may be estimated using the following formula:

Work = Force of Friction * Distance * cos(theta)

The net force applied on the crate is zero since it is travelling at a constant pace. As a result, the friction force must be equal to the applied force, which is 150 N.

Thus, the work done by friction is:

Work = 150 N * 5.85 m * cos(180) = -877.5 J

Since the work done by friction is negative, it indicates that the direction of the frictional force is opposite to the direction of motion.

The coefficient of kinetic friction may be calculated using the following equation:

Friction Force = Kinetic Friction Coefficient * Normal Force

The normal force equals the crate's weight, which may be computed as:

Normal Force = mass * gravity

where the mass is 35.0 kg and the acceleration due to gravity is approximately 9.8 m/s^2.

Normal Force = 35.0 kg * 9.8 m/s^2 = 343 N

Now, we can rearrange the equation for the force of friction to solve for the coefficient of kinetic friction:

Force of Friction = coefficient of kinetic friction * Normal Force

150 N = coefficient of kinetic friction * 343 N

coefficient of kinetic friction = 150 N / 343 N ≈ 0.437

As a result, the kinetic friction coefficient between the container and the surface is roughly 0.437.

In summary, the work done by the 150 N force is 877.5 Joules, and the coefficient of kinetic friction between the crate and the surface is approximately 0.437.

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Answer:

Below

Explanation:

Change in v = 5-2 = 3 m/s

Change in momentum =  m * change in v = 1 * 3 = 3  kg m/s

Answer:

(B)False is the answer.

Explanation:

The right answer is A). The wavelength of the wave likewise reduces when the frequency of the light wave falls as it moves from a rarer to a denser medium because the frequency of light waves remains constant in all media.

Light is bent as it passes through a different medium because of the speed difference. Light waves are bent at different angles because they are slowed down at varying rates.

If light is initially absorbed by electrons in a substance to elevate their energy level, this can affect the wavelength of the light.

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(1a) The potential energy of the body is 980 J

(1b) The kinetic energy of the body halfway down is 490 J and

(1c) The kinetic energy just before impact is 9807 J.

(2) The work done by the trailer on the car is 15,750,000 J.

(3)The initial speed of the vehicle was 10.6 m/s and the work required to stop the car is 269.9 kJ.

Problem 1:

The potential energy of the body is given by the formula:

potential energy = mass x gravity x height

where mass = 50 kg, gravity = 9.8 m/s², and height = 2 m

So, potential energy = 50 x 9.8 x 2 = 980 J

When the body is halfway down, its height above the ground is 1 m. At this point, the potential energy is:

potential energy = mass x gravity x height

potential energy = 50 x 9.8 x 1 = 490 J

The total energy of the body (at any point) is the sum of its potential energy and kinetic energy.

Therefore, the kinetic energy of the body halfway down is:

kinetic energy = total energy - potential energy

kinetic energy = (50 x 9.8 x 2) - (50 x 9.8 x 1) = 490 J

Just before impact with the floor, the height of the body above the ground is zero, so the potential energy is also zero.

At this point, the total energy of the body is equal to its kinetic energy:

kinetic energy = (1/2) x mass x velocity²

where mass = 50 kg, and velocity = ?

To find the velocity, we can use the conservation of energy principle:

total energy at the top = total energy just before impact

potential energy at the top = kinetic energy just before impact

potential energy at the top = 50 x 9.8 x 2 = 980 J

kinetic energy just before impact = 980 J

So, (1/2) x 50 x velocity^2 = 980 J

Solving for velocity, we get:

velocity = √(2 x 980 / 50) = 19.8 m/s

Therefore, the kinetic energy just before impact is:

kinetic energy = (1/2) x 50 x (19.8)^2 = 9,807 J

Problem 2:

The work done by the trailer on the car is given by the formula:

work = force x distance

where force = 900 N, and distance = (70 km/h) x (15/60) h = 17.5 km

Converting km to meters, we get:

distance = 17.5 km x 1000 m/km = 17,500 m

So, work = 900 x 17,500 = 15,750,000 J

Problem 3:

The work done by the brakes is equal to the change in kinetic energy of the vehicle:

work done by brakes = change in kinetic energy

Let the initial speed of the vehicle be v m/s. Then, the initial kinetic energy of the vehicle is:

kinetic energy = (1/2) x 1600 x v²

After the brakes are applied, the final kinetic energy of the vehicle is zero (since the vehicle comes to a stop).

Therefore, the work done by the brakes is equal to the initial kinetic energy:

work done by brakes = (1/2) x 1600 x v²

Given that the work done by the brakes is 90 kJ, we can solve for the initial speed:

90,000 J = (1/2) x 1600 x v²

v² = 112.5

v = √(112.5) = 10.6 m/s

So, the initial speed of the vehicle was 10.6 m/s.

The work required to stop the car:

W = ¹/₂(1600)(15² + 10.6²)

W = 269,888 J = 269.9 kJ

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Answer:

I believe it would be C ? my apologies if I'm wrong.

Answer:

According to Newton's third law of motion, for every action, there is an equal and opposite reaction. When the man jumps from a boat, he applies force on the boat due to which boat moves backward. An equal force is exerted by the boat on the man which helps the man to jump out of the boat.