A boy pushes back on it, trying to slow it down. The sign of the work done by the boy on the block is. It depends on the speed of the block. О negative О positive О zero

yup they r equal as mentioned above is equal magnitude and direction! so they r totally equal.

as one vector has 2 things which is used to define it ->

so if both r equal then both vectors r equal vectors

Answer:

Not testable.

Explanation:

The temperature of coffee can change, as the coffee gains or loses heat to the surroundings or the room temperature. For example, if you put a hot coffee in a cold room, the coffee will lose heat to the surroundings/room temperature, eventually making it colder.

Answer:

Explanation:

In physics, work can be described as force multiplied by the displacement of the object (distance caused by the force acted on the object).

Work is a form of energy, therefore, it is measured in joules.

If Alex pushed on an object with 10N of force, and the object moved 2 meters, the work of Alex will be equal to:

W = Ft

W = 10N * 2m

W = 20 Joules

But, if we have John, that pushed on an object with 2N of force, but, since the object was way smaller, therefore it had way less inertia, the object moved a distance equal to 10 meters. Let's also calculate his work.

W = Ft

W = 2N * 10m

W = 20 Joules

And we got the same result.

Work can also be used to calculate power.

Power is equal to P = Work / time

It can also be written as P = delta Work / delta time

Power is measured in joules per second.

With power you can make the difference between someone that got a 2 kg object up in 2 second, and someone that got a 2 kg object up in 5 second.

The more powerful one would be the one who managed to make the same work in less time.

Hope it Helped!

Work is described as: the measure of energy transfer resulting from the application of force over a displacement.

In the field of physics, work is most accurately defined as the outcome of multiplying the force exerted on an object by the distance the object is displaced in the same direction as the force.

This calculation serves to quantify the energy transferred to or from the object. For instance, if an individual applies a 50 Newton force to push a box across a 5-meter distance in the force's direction, the work done on the box would equal 250 Joules (50 N × 5 m).

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We can use the formula for the rotational motion:

τ = Iα

The moment of inertia of the rotating platform is 0.32 kg m^2.

We can use the formula for the rotational motion:

τ = Iα

where τ is the torque, I is the moment of inertia, and α is the angular acceleration.

In this problem, we know the linear acceleration of the hanging mass, and we want to find the moment of inertia I of the rotating platform. We can relate the linear acceleration to the angular acceleration using the radius r of the platform:

a = αr

We also know the mass m and the force F acting on the hanging mass:

F = ma

The force F produces a torque τ on the platform, given by:

τ = Fr

Substituting the expressions for α and τ into the equation for rotational motion, we have:

Fr = I(a/r)

Simplifying and solving for I, we get:

I = (F/α)r^2 = (mg/α)r^2

Substituting the given values, we have:

I = (0.1 kg)(9.81 m/s^2)/(2.5 m/s^2)(0.2 m)^2

I = 0.32 kg m^2

Therefore, the moment of inertia of the rotating platform is 0.32 kg m^2.

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Answer:

v_f = -7.5 m / s

Explanation:

Let's analyze this exercise a little, two forces that act on a body for different time intervals are indicated, each force creates an impulse and since this is a vector quantity we must add in the form of vectors. The net momentum is

we assume that the direction to the right is positive

             I = I₁ + I₂

             I = F₁ Δt₁ - F₂ Δt₂

             I = 3  1.5 - 4  3

             I = -7.5   N s

now let's use the relationship between momentum and momentum, suppose the object starts from rest (vo = 0)

             I = Δp

             I = m (v_f - v₀)

             v_f = I / m

              v_f = -7.5 / m

to finish the calculation we must assume a mass m = 1 kg

              v_f = -7.5 m / s

the negative sign in the body is moving to the left

Answer: D. A bobcat fights a wolf to protect younger bobcats.

Answer:

The magnetic field strength of an electromagnet is therefore determined by the ampere-turns of the coil with the more turns of wire in the coil the greater will be the strength of the magnetic field

Explanation:

The relation of having the same color is reflexive. Therefore, the statement is true.

A reflexive relation is one in which every element maps its own component. Every component of the set reflects itself in its own image.

A reflexive relation on a set I is also represented as L = {(a, a): a ∈ I}, where I L ⊆ R and R is a relation defined on the set I.

According to the question,

if we have the same color, y

then,

(y, y) belongs to R

Therefore, color y and color y have the same color.

Hence, the relation between color y and R is reflexive. The statement is true.

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Answer:

I'm sorry I

Explanation:

I don't know I'm sorry I will tell you another answer

Answer:

\(4\:\mathrm{m}\)

Explanation:

The formula for work is given as \(W=F\Delta x\) where \(F\) is force applied and \(\Delta x\) is displacement.

Rearranging this equation, we have:

\(\Delta x=\frac{W}{F}\).

Plugging in given values, we get:

\(\Delta x=\frac{W}{F}=\frac{320}{80}=\fbox{$4\:\mathrm{m}$}\).

Answer:

The answer is 4m

Explanation:

hope this helps!

ANSWER

Q = 5303.95 kJ

EXPLANATION

We are looking for the energy needed to evaporate 2.35kg of water. Since the water is already at evaporation temperature, which is 100°C, we just have to use latent heat. Also, we just want the steam to be at 100°C, so we don't need to find the energy to change its temperature.

The energy needed to evaporate water of mass m is:

L is the latent heat of the material, in this case water. There are two latent heats, one of fusion and one of vaporization. We have to use the second one, which for water is approximately 2257 kJ/kg

Therefore, to boil 2.35 kg of water at 100°C to steam at 100°C we need:

When the velocity of a particle moving along an axis is known, the instantaneous acceleration equal to zero is given as 0.6t.

We estimate the average speed between two places in time separated by t while allowing t to decrease. The outcome is the velocity function's derivative, v. (t).

The slope of the tangent line to the graph at any given location on the graph corresponds to the instantaneous acceleration there. The instantaneous acceleration of the particle is equal to 0 when this line is horizontal and has a slope of 0. According to the plot, these times correlate to the velocity function's extrema, which can be found at t = 1.75, 2.75, 3.25, and for all t = 4.

t = 0.6 is the most likely choice.

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Answer:

\(\boxed {\boxed {\sf 5.6 \ m/s^2}}\)

Explanation:

We are asked to find the acceleration of a sports car.

Acceleration is the rate of change of velocity with respect to time. It is the change in velocity over time. Therefore, the formula for calculating acceleration is:

\(a= \frac {v_f-v_i}{t}\)

The car can accelerate from 5.0 meters per second to 30 meters per second in 4.5 seconds.

Susbtitute the values into the formula.

\(a= \frac{ 30 \ m/s - 5.0 \ m/s}{4.5 \ s}\)

Solve the numerator.

\(a= \frac{25 \ m/s}{4.5 \ s}\)

Divide.

\(a=5.55555556\)

The original measurements all have 2 significant figures, so our answer must have the same. For this number, 2 sig fig is the tenth place. The 5 in the hundredth place tells us to round the 5 in the tenth place up to a 6.

\(a \approx 5.6 \ m/s^2\)

The sports car's acceleration is approximately 5.6 meters per second squared.

The air temperature is affected by five factors: the latitude, height above sea level, distance from the sea, ocean currents and prevailing winds.

1) The latitude: The amount of solar radiation that a location receives affects its temperature. The temperature varies as a result of the latitude-dependent variation in insolation.

2) The altitude: Radiation from the earth indirectly warms the atmosphere. As a result, areas close to sea level experience warmer temperatures than areas at higher altitudes.

3)Distance from the sea: The location of a place in relation to the sea is the primary factor that affects the temperature. Compared to land, the sea both gains and loses heat gradually. Rapid warming and cooling occur on land.

4) Ocean currents : Similar to how land and sea breezes affect temperature, air masses likewise move through the ocean.

5) Air masses : Warm air masses have an impact on certain areas, which results in greater temperatures there, whereas cold air masses have an impact on other areas, which results in lower temperatures there.

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Answer:

forced convection cooling

Explanation:

Answer:

trust the process

Explanation:

quadratic formula, use synthetic division also use the p-q method for the roots and factoring.

The Q need to be to make the magnitude of the electric field 0.00264 meters away from the surface equal to 1.43 nC is 1.07 × 10⁻⁹ C.

The  magnitude of the electric field at the point near the charged surface is as :

E = Q / (4 × π × ε × A)

Q = E ( 4 × π × ε × A)

Where

E = 1.43 nC

ε = 8.85 x 10⁻¹² C²/N m²

A = 6.77 m²

Q = E ( 4 × π × ε × A)

Q  = 1.43 × 4 × 3.14 × 8.85 x 10⁻¹² × 6.77

Q = 1.07 × 10⁻⁹ C

Thus, the charge is  1.07 × 10⁻⁹ C.

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Answer:

El coeficiente de roce estático entre las dos superficies es 0.131.

Explanation:

El coeficiente de roce estático entre dos superficies (\(\mu_{s}\)), sin unidad, es igual a la fuerza de resistencia (\(F\)), en newtons, dividida por el peso del cuerpo a mover (\(W\)), en newtons.

\(\mu = \frac{F}{m\cdot g}\) (1)

Donde:

\(m\) - Masa, en kilogramos.

\(g\) - Aceleración gravitacional, en metros por segundo al cuadrado.

Si sabemos que \(F = 45\,N\), \(m = 35\,kg\) y \(g = 9.807\,\frac{m}{s^{2}}\), entonces el coeficiente de roce estático es:

\(\mu = \frac{45\,N}{(35\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}\)

\(\mu = 0.131\)

El coeficiente de roce estático entre las dos superficies es 0.131.

Answer:

Accurate at 99.9999746%

Explanation:

First of all, let's calculate how many seconds we have in a year which has 365 days.

1day = 24 × 60 × 60 seconds = 86400 s

Thus, for 365 days, we have;

86400 × 365 = 31536000 seconds

Now, since 1 year has 31536000 seconds, let's find the ratio of efficiency.

We are told that the watch manufacturer claims that its watches gain or lose no more than 8 seconds in a year. Thus, efficiency is given by;

Efficiency = (8/31536000) × 100% = 0.00002536783 %

Thus, it will be be accurate at;

100% - 0.00002536783% ≈ 99.9999746%

The momentum of the small rock at distance 2 is 1.08e+17 kg · m/s, in the -y direction.

What is momentum?

To solve this problem, we need to use the conservation of momentum. Since there are no other massive objects nearby, the total momentum of the system (rock + star) must be conserved.

At the first distance d1, the momentum of the rock can be split into two components: one in the x direction and one in the y direction. Using the angle α = 122 degrees, we can calculate the x and y components of the momentum:

p1x = p1 * cos(α) = 1.15e+17 kg · m/s * cos(122°) = -3.97e+16 kg · m/s

p1y = p1 * sin(α) = 1.15e+17 kg · m/s * sin(122°) = 1.08e+17 kg · m/s

Since there are no external forces acting on the system, the momentum in the x direction and the momentum in the y direction must be conserved separately. However, since the path of the rock is not given, we cannot assume that the momentum in the x direction is conserved. Therefore, we need to calculate the new momentum of the rock in the y direction at distance d2.

To do this, we can use the conservation of momentum in the y direction:

p1y = p2y

where p2y is the momentum of the rock in the y direction at distance d2.

We can rearrange this equation to solve for p2y:

p2y = p1y = 1.08e+17 kg · m/s

Therefore, the momentum of the small rock at distance 2 is 1.08e+17 kg · m/s, in the -y direction.

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d)A solar cell is an object that converts light into chemical energy.

It works by using sunlight to convert photons into electrons, which are then used to generate electricity. Solar cells can be used to power a variety of objects, such as calculators, phones, and other electronic devices. They can also be used to generate electricity for homes and businesses. Solar cells are made of special materials that allow them to capture light and convert it into energy. When sunlight hits the solar cell, electrons in the material become excited and move freely, creating an electric current. This current is then used to produce electricity.

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Answer:

I think 1.022 or 1

Explanation:

The temperature at the outlet of the compressor (T2) is equal to the temperature at the outlet of the turbine (T4) and is 1000 K. The net production of work is given by: Net-work = Wturbine - W compressor

a) To determine the temperature of the air at the outlet of the compressor and the turbine without using isentropic relations, we can use the efficiency of the Brayton cycle and the given minimum and maximum temperatures.

The efficiency of the Brayton cycle (η) is given as 70%. We know that the efficiency is defined as the ratio of the net work output to the heat input. Since we don't have the heat input, we cannot directly calculate the net work output.

However, we can determine the temperature at the outlet of the compressor (T2) and the turbine (T4) by using the efficiency and the given minimum and maximum temperatures.

η = 1 - (T1/T3)

Rearranging the equation, we have:

T3 = T1 / (1 - η)

T3 = 300 K / (1 - 0.7)

T3 = 1000 K

Therefore, the temperature at the outlet of the compressor (T2) is equal to the temperature at the outlet of the turbine (T4) and is 1000 K.

b) To calculate the net production of work, we need to find the difference between the work output of the turbine (Wturbine) and the work input to the compressor (Wcompressor).

Wturbine = Cp * (T3 - T4)

Wcompressor = Cp * (T2 - T1)

Since T2 = T4 = 1000 K, we have:

Wturbine = Cp * (1000 K - 300 K)

Wcompressor = Cp * (1000 K - 300 K)

Therefore, the net production of work is given by:

Net work = Wturbine - Wcompressor

c) To calculate the thermal efficiency, we can use the equation:

η = (Net work) / (Heat input)

However, we don't have the heat input provided, so we cannot directly calculate the thermal efficiency without additional information.

In summary, without the knowledge of the heat input, we can determine the temperature at the outlet of the compressor and the turbine, but we cannot calculate the net production of work or the thermal efficiency of the Brayton cycle.

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WACC (Weighted Average Cost of Capital) is a calculation used to assess a company's cost of capital. It is computed by multiplying each source of capital (equity, debt, and preferred stock) by its relevant weight and then summing these up.

In this question, Ace Batteries is utilizing the CAPM (Capital Asset Pricing Model) to determine the cost of equity capital.Ace Batteries' WACC can be reduced if the company's beta decreases. The beta of a company is a measure of its market risk or volatility, and it is a component of the CAPM formula

As a result, a lower beta lowers the cost of equity capital, lowering the company's WACC. Consequently, option c: A decrease in the company's beta, will REDUCE Ace Batteries' WACC (weighted average cost of capital).

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Given data:

Mass of the wood m = 10 kg.

Work done to lift the mass W = 200 J.

Solution:

The wood of the height can be calculated as:

The gravity is constant and the value is

The height will be:

Hence, the height is 196 m.

Answer: Calculate GPE for different gravity of different enviornments - Earth, the Moon, ... kg, g, lb, oz ... variable in the physics equation for gravitational potential energy, when three of ... PEg or PE = gravitational potential energy; m = mass of an object ... have 147.15 Joules of potential energy, PE = 3kg * 9.81 m/s2 * 5m = 147.15 J.

The force exerted on the car by the raising mechanism is 7,100 N.

The given parameters:

The force exerted on the car by the raising mechanism is calculated as follows;

\(W = Fd\\\\F = \frac{W}{d} \\\\F = \frac{2.13 \times 10^6}{300} \\\\F = 7,100 \ N\)

Thus, the force exerted on the car by the raising mechanism is 7,100 N.

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Answer:

As its speed increases.......

The kinetic energy of an object increases as its speed increases. So, option B.

The type of energy that an object possesses as a result of its motion is called kinetic energy.

The kinetic energy of an object is described as the amount of effort required to accelerate a body of a specific mass from rest to its specified velocity.

The body keeps its kinetic energy after gaining it during acceleration, barring changes in speed.

When slowing down from its current pace to a condition of rest, the body expends the same amount of energy.

A force must be applied to an object in order to accelerate it. We must put in effort in order to apply a force. After the work is finished, energy is transferred to the item, which then moves at a new, constant speed.

The kinetic energy of the object,

KE = 1/mv²

where m is the mass and v is the speed of the object.

Since, the mass is a constant, the increase in speed can increase the kinetic energy of the object.

Hence,

The kinetic energy of an object increases as its speed increases.

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