A battery charges a parallel-plate capacitor fully and then is removed. The plates are then slowly pulled apart. What happens to the potential difference between the plates as they are being separated?

Current in solenoid produces astronger magnetic field inside thesolenoid than outside. The field lines in this region are parallel and closely spaced showing the field is highly uniform in strength and direction. ... Strength of the magnetic field can be increased by: increasing the current in the coil.

\(hope \: it \: will \: ....\)

Answer:

See below

Explanation:

Here are a couple of options..... one where the object slows to a rest and the other where the object stops to a rest instantaneously

Answer:

The moon does not stay at the same distance of the earth because the ortbit of the moon is slightly elliptical. If earth is not tilted at an angle of 66.5°, there will be no change in the season and the earth will have equal length of days and night.

Explanation:

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Answer:

a.  10 ohms.

Explanation:

Given;

first electrical resistance, r₁ = 20 ohms

let the first current through the circuit = I₁

let the second current through the circuit, I₂ = 2I₁ (since it is doubled)

then, the new value of the resistance after doubling the current = r₂

the current intensity is given as;

\(\frac{dI}{dt} = I = \frac{v}{r} \\\\I_1r_1 = I_2r_2\\\\r_2 = \frac{I_1r_1}{I_2} \\\\r_2 = \frac{I_1 \times 20}{2I_1 } \\\\r_2 = 10 \ ohms\)

Therefore, the new value of the resistance is 10 ohms.

Answer:

a model would be very benaficial to a scientest because they need them

Explanation:

1 model for eachscientest

The statement that says "Psychological disorders can be very difficult to diagnose" is true about diagnosing psychological disorders.

Psychological disorders are those mental, behavioral, emotional and thinking conditions that interfere with the normal performance of the individual in society.

Therefore, we can conclude that a psychological disorder is an alteration in the mental balance of a person that requires specialized attention adapted to the characteristics of the dysfunction.

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If enough experimental data supports a hypothesis, it is considered a well-supported scientific theory, but it is not considered to be 100% true or proven. Scientific theories are always open to further investigation and revision based on new evidence. Therefore, option C ("Is proven 100% true") is incorrect.

Option A ("Is accepted as true until proven false") is also incorrect because scientists do not accept a hypothesis as true until it has been rigorously tested and supported by a large body of evidence. Even then, scientists recognize that any scientific theory is subject to revision or falsification if new data or evidence emerges that contradicts it.

Option B ("Becomes an Observational Law") is also incorrect because scientific laws are typically descriptive, rather than explanatory. They describe what happens in a given set of circumstances, but they do not explain why it happens. Hypotheses and theories, on the other hand, attempt to explain why certain phenomena occur, and they are supported by experimental evidence.

Therefore, none of the options are completely accurate, but the most appropriate answer is that the hypothesis becomes a well-supported scientific theory.

Magnitude of electrostatic force on the charge q is 1.376 N, and the direction is 82.6 degrees clockwise from the positive x-axis.

Attractive and repulsive force caused by the electric charge particles is known as electrostatic force.

F₁₂ = (k * q₁ * q₂) / r₁²

k is the Coulomb constant (9 × 10⁹ N·m²/C²), q₁ and q₂ are charges, and r₁₂ is  distance between them.

F₁₂ = (9 × 10⁹ N·m²/C²) * (4.78 nC) * (6.00 nC) / (0.260 m)²

F₁₂ = 0.158 N

Direction of this force is along the x-axis, towards positive x-direction.

The distance between q and the -3.00 nC charge is the y-coordinate of the -3.00 nC charge, which is 0.100 m. The magnitude of the electrostatic force between them can be calculated using Coulomb's law:

F₁₃ = (k * q₁ * q₃) / r₁₃²

q₃ is charge of -3.00 nC charge and r₁₃ is distance between q and -3.00 nC charge.

F₁₃ = (9 × 10⁹ ) * (4.78 ) * (-3.00 ) / (0.100)

F₁₃ = -1.364 N

Direction of this force is along negative y-axis, towards negative y-direction.

|F| = √(F12² + F₁₃²)

|F| = √((0.158 N)² + (-1.364 N)²)

|F| = 1.376 N

Ф = arctan(F₁₃ / F₁₂)

= arctan(-1.364 N / 0.158 N)

Ф = -82.6 degrees

Therefore, magnitude of the electrostatic force on charge q is 1.376 N, and direction is 82.6 degrees clockwise from positive x-axis.

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Answer:

D

Explanation:

trust me bro

The instantaneous current at the same moment in the RL circuit can be expressed as I = Imaxsin(150), where Imax represents the maximum current.

1. Given that the instantaneous voltage at a specific moment in the RL circuit is V = Vmaxsin(150).

2. We can express the current at the same moment using Ohm's Law, which states that V = IR, where V is voltage, I is current, and R is resistance.

3. In an RL circuit, the resistance is represented by the symbol R, and it is typically associated with the resistance of the wire or any resistors in the circuit.

4. However, the given equation does not explicitly mention resistance.

5. Since we are considering an RL circuit, it suggests the presence of inductance (L) along with resistance (R).

6. In an RL circuit, the voltage across the inductor (VL) can be expressed as VL = L(di/dt), where L is the inductance and di/dt represents the rate of change of current.

7. At any given instant, the total voltage across the circuit (V) can be expressed as the sum of the voltage across the resistor (VR) and the voltage across the inductor (VL).

8. Therefore, V = VR + VL.

9. Since the given equation represents the instantaneous voltage (V), we can deduce that V = VR.

10. By comparing V = VR with Ohm's Law (V = IR), we can conclude that I = Imaxsin(150), where Imax represents the maximum current.

The specific values of Vmax, Imax, and the phase angle have not been provided in the question, so we are working with the general expression.

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Answer:

We're no strangers to love

You know the rules and so do I

A full commitment's what I'm thinking of

You wouldn't get this from any other guy

I just wanna tell you how I'm feeling

Gotta make you understand

Never gonna give you up

Never gonna let you down

Never gonna run around and desert you

Never gonna make you cry

Never gonna say goodbye

Never gonna tell a lie and hurt you

We've known each other for so long

Your heart's been aching but you're too shy to say it

Inside we both know what's been going on

We know the game and we're gonna play it

And if you ask me how I'm feeling

Don't tell me you're too blind to see

Never gonna give you up

Never gonna let you down

Never gonna run around and desert you

Never gonna make you cry

Never gonna say goodbye

Never gonna tell a lie and hurt you

No, I'm never gonna give you up

No, I'm never gonna let you down

No, I'll never run around and hurt you

Never, ever desert you

We've known each other for so long

Your heart's been aching but

Never gonna give you up

Never gonna let you down

Never gonna run around and desert you

Never gonna make you cry

Never gonna say goodbye

Never gonna tell a lie and hurt you

No, I'm never gonna give you up

No, I'm never gonna let you down

No, I'll never run around and hurt you

I'll never, ever desert you

Explanation:

RICK ROLLED

Answer:

The right answer for this question is 85%.

(I had the same question.)

Answer:

Below

Explanation:

Fn = mg cos(angle )    <======just plug in the values given

Fn = 43 * 9.81 * cos 35 = ~ 346 N

Answer:

e

Explanation:

Answer:

strength

Explanation:

Answer:

Potential energy

Explanation:

Since the boy is holding is, it is not moving. So, it has potential energy. Also, since it is in the air, it has gravitational potential energy.

A rope pulls a Tesla out of mud. The guy pulls a force F⊥ of 300N, and theta = 4.2°. The tension force T is 298.44__ Newton.

The problem describes a Tesla that is stuck in the mud and needs to be pulled out using a rope. the guy pulls a force F⊥ of 300N and that the angle between the rope and the horizontal plane is θ = 4.2°. The goal is to find the tension force T exerted by the rope.To solve for T, we'll need to use trigonometry. We can break the force vector into its horizontal and vertical components as follows:

Fx = F⊥ cosθ and Fy = F⊥ sinθ.

Since the rope is pulling the Tesla horizontally, the horizontal component of the force will be the tension force T. So we have:

T = Fx = F⊥ cosθ = (300 N) cos(4.2°) ≈ 298.44 N

Taking the cosine of the angle is necessary since it's the adjacent side that we're interested in, which is the horizontal component of the force. Therefore, the tension force exerted by the rope is approximately 298.44 N.

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The abnormalities in the genetic code must be found and corrected on time as it could lead to inherited disorders which could be life-threatening.

Genetic abnormalities are the conditions which are caused by changes to the genes or chromosomes. Genetic disorders are also known as inherited disorders which are caused by mutations in the genetic code. Genetic disorders include disorders such as cystic fibrosis, sickle cell disease, and Tay-Sachs disease.

Cells become diseased because certain genes work incorrectly or does not work at all. Replacing the defective genes in the diseased organisms may help treat certain diseases. For instance, a gene called p53 prevents tumor growth. Several types of cancer which have been linked to problems with the p53 gene.

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Answer:

The horizontal acceleration of the block is 4.05 m/s².

Explanation:

The horizontal acceleration can be found as follows:

\( F = m \cdot a \)

\( Fcos(\theta) - \mu_{k}N = m\cdot a \)

\( Fcos(\theta) - \mu_{k}[mg - Fsen(\theta)] = m\cdot a \)  

\( a = \frac{Fcos(\theta) - \mu_{k}[mg - Fsen(\theta)]}{m} \)

Where:

a: is the acceleration

F: is the force exerted by the rope = 28.2 N

θ: is the angle = 30°

\(\mu_{k}\): is the kinetic coefficient = 0.12

m: is the mass = 5 kg

g: is the gravity = 9.81 m/s²

\( a = \frac{28.2 N*cos(30) - 0.12[5 kg*9.81 m/s^{2} - 28.2 N*sen(30)]}{5 kg} = 4.05 m/s^{2} \)

Therefore, the horizontal acceleration of the block is 4.05 m/s².

I hope it helps you!

There are 14025 x10^6 grains of sand in the sand box when it is full when there was present on average 55 grains in the box initially.

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Answer:

Anticlockwise directions

Please mark me Brainliest to help me

Each step of the energy released during cellular respiration is accompanied by the synthesis of ATP. Only a tiny fraction of energy is converted to heat that's why our body doesn't burn.

The process through which organisms use oxygen to break down food molecules in order to get chemical energy for cellular processes is known as cellular respiration. The cells of animals, plants, and fungi, as well as those of algae and other protists, all engage in cellular respiration.

Cells produce energy through a process called cellular respiration. Prokaryotic and eukaryotic cells both have mitochondria and cytoplasm where cellular respiration takes place.

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Answer:

r = 0.405m = 40.5cm

Explanation:

In order to calculate the length of the string between Wanda and the ball, you take into account that the tension force is equal to the centripetal force over the ball. So, you can use the following formula:

\(F_c=ma_c=m\frac{v^2}{r}\)       (1)

Fc: centripetal acceleration (tension force on the string) = 12N

m: mass of the ball = 60g = 0.06kg

r: length of the string = ?

v: linear speed of the ball = 9.0m/s

You solve for r in the equation (1) and replace the values of the other parameters:

\(r=\frac{mv^2}{F_c}=\frac{(0.06kg)(9.0m/s)^2}{12N}=0.405m\)

The length of the string between Wanda and the ball is 0.405m = 40.5cm

An electromagnet consists of a conductive wire wrapped around a magnetic core, creating a magnetic field when an electrical current is passed through it.

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Answer:

The loss in rotational kinetic energy due to the collision is 36.585 J.

Explanation:

Given;

mass of the disk, m₁ = 1.64 kg

radius of the disk, r = 0. 61 m

angular velocity of the disk, ω₁ = 17.6 rad/s

mass of the rod, m₂ = 1.51 kg

length of the rod, L = 1.79 m

angular velocity of the rod, ω₂ =  5.12 rad/s (clock-wise)

let the counter-clockwise be the positive direction

let the clock-wise be the negative direction

The common final velocity of the two systems after the collision is calculated by applying principle of conservation of angular momentum ;

m₁ω₁  + m₂ω₂ = ωf(m₁ + m₂)

where;

ωf is the common final angular velocity

1.64 x 17.6    + 1.51(-5.12) = ωf(1.64 + 1.51)

21.1328 = ωf(3.15)

ωf = 21.1328 / 3.15

ωf = 6.709 rad/s

The moment of inertia of the disk is calculated as follows;

\(I_{disk} = \frac{1}{2} mr^2\\\\I_{disk} = \frac{1}{2} (1.64)(0.61)^2\\\\I_{disk} = 0.305 \ kgm^2\)

The moment of inertia of the rod about its center is calculated as follows;

\(I_{rod} = \frac{1}{12} mL^2\\\\I_{rod} = \frac{1}{12} \times 1.51 \times 1.79^2\\\\I _{rod }= 0.4032\ kgm^2\)

The initial rotational kinetic energy of the disk and rod;

\(K.E_i = \frac{1}{2} I_{disk}\omega _1 ^2 \ \ + \ \ \frac{1}{2} I_{rod}\omega _2 ^2 \\\\K.E_i= \frac{1}{2} (0.305)(17.6) ^2 \ \ + \ \ \frac{1}{2} (0.4032)(-5.12) ^2\\\\K.E_i = 52.523 \ J\)

The final rotational kinetic energy of the disk-rod system is calculated as follows;

\(K.E_f = \frac{1}{2} I_{disk}\omega _f ^2 \ \ + \ \ \frac{1}{2} I_{rod}\omega _f ^2\\\\K.E_f = \frac{1}{2} \omega _f ^2(I_{disk} + I_{rod})\\\\K.E_f = \frac{1}{2} (6.709) ^2(0.305+ 0.4032)\\\\K.E_f = 15.938 \ J\)

The loss in rotational kinetic energy due to the collision is calculated as follows;

\(\Delta K.E = K.E_f \ - \ K.E_i\\\\\Delta K.E = 15.938 J \ - \ 52.523 J\\\\\Delta K.E = - 36.585 \ J\)

Therefore, the loss in rotational kinetic energy due to the collision is 36.585 J.

The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.

To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.

The force between two charged particles can be calculated using Coulomb's law:

F = k * |q₁ * q₂| / r²

Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.

First, let's calculate the force exerted on q₂ by q₁:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²

F₁₂ ≈ 252000 N

The force is positive because q₁ and q₂ have opposite charges.

Next, let's calculate the force exerted on q₂ by q₃:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²

F₂₃ ≈ -63000 N

The force is negative because q₂ and q₃ have the same charge.

Finally, we can find the net force on q₂ by summing the individual forces:

Net force = F₁₂ + F₂₃

Net force = 252000 N + (-63000 N)

Net force ≈ 189000 N

The net force on particle q₂ is approximately 189000 N.

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