a bacteria culture doubles every 3 minutes. if 400 bacteria started, how long will it take before there are 2000 in the culture?

Answer:

9

Step-by-step explanation:

6/(2/3)

= 9

Answer:

76.5 hours

(If you like this answer i would appreciate if u give brainliest but otherwise, i hope this helped ^^)

Step-by-step explanation:

Part 1 of 2:

(a) The equation that describes Winona's total take-home pay, P, in terms of the number of hours, x, worked at the first job and the number of hours, y, worked at the second job can be written as:

P = (10x) + (9.25y + 0.7 * 9.25y) - 0.2[(10x) + (9.25y + 0.7 * 9.25y)]

Simplifying the equation:

P = 10x + 9.25y + 0.7 * 9.25y - 0.2(10x + 9.25y + 0.7 * 9.25y)

Part 2 of 2:

(b) If Winona is committed to working 30 hours per week at the first job, let's assume x = 30. We need to find the number of hours per week, y, she would need to work at the second job to reach a biweekly take-home pay of $800.

Using the simplified equation from part (a), we substitute x = 30 and solve for y:

800 = (10 * 30) + (9.25y + 0.7 * 9.25y) - 0.2[(10 * 30) + (9.25y + 0.7 * 9.25y)]

800 = 300 + (9.25y + 0.7 * 9.25y) - 0.2(300 + (9.25y + 0.7 * 9.25y))

Now, we can solve for y:

800 = 300 + 9.25y + 0.7 * 9.25y - 0.2(300 + 9.25y + 0.7 * 9.25y)

Simplify the equation:

800 = 300 + 9.25y + 0.7 * 9.25y - 0.2 * 300 - 0.2 * 9.25y - 0.2 * 0.7 * 9.25y

Combine like terms:

800 = 300 - 60 + 9.25y - 1.85y - 0.1295y

800 = 240 + 7.32y

Subtract 240 from both sides:

560 = 7.32y

Divide both sides by 7.32:

y ≈ 76.5

Therefore, Winona would need to work approximately 76.5 hours per week at her second job to reach a biweekly take-home pay of $800.

     "Not independent" means that the situation is dependent. It is not relying on something else, or something else will not change the outcome. Independent means the situation is isolated, it is independent.

A jar contains green marbles and orange marbles. A green marble is selected followed by an orange marble, at random, without replacement.

Not independent

-> Since the marbles are not being replaced, this isn't independent

A coin is flipped three times.

Independent

A bag contains nickels and dimes. A nickel is selected followed by a dime, at random, with replacement.

Independent

-> Because there is replacement, this is independent

A number cube is rolled twice.

Independent

If the ratio of the sides of the triangles ΔABC and ΔDEF are equal then the triangles are similar triangles. Then the correct option is B.

What is the triangle?

Triangle is a polygon that has three sides and three angles. The sum of the angle of the triangle is 180 degrees.

A picture shows triangle ABC and triangle DEF.

Triangle ABC: Side AB is 3, Side BC is 5, and Side CA is 4.

Triangle DEF: Side DE is 6, Side EF is 10, and Side FD is 8.

The ratio of the sides of the triangles ΔABC and ΔDEF will be given below.

AB/DE=BC/EF=CA/FD

3/6=5/10=4/8=1/2

If the ratio of the sides of the triangles ΔABC and ΔDEF are equal then the triangles are similar triangles.

The diagram is shown below.

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Two right triangles—A B C and D E F. The triangles ΔABC and ΔDEF are comparable triangles if the ratio of their sides is the same.

Given that,

Two right triangles—A B C and D E F. Triangle A B C has a side of 3, a side of 5, and a side of 4.

Triangle D E F: sides D and E , side E and F and side F and each 6, 10, and 8.

Because the angles are not provided, making it impossible to determine whether the triangles are identical is not comparable to.

We have to find which of the two triangles' respective claims is true.

Describe the triangle.

The polygonal shape known as a triangle has three sides and three angles. The sum of the triangle's angles is 180 degrees.

Triangle ABC and triangle DEF are depicted in an image.

Triangle ABC has sides AB at 3, BC at 5, and CA at 4.

Triangle DEF has sides.

Sides DE at 6; EF at 10; and FD at 8.

The triangles ΔABC and ΔDEF side ratio will be provided below.

AB/DE=BC/EF=CA/FD

3/6=5/10=4/8=1/2

Therefore, The triangles ΔABC and ΔDEF are comparable triangles if the ratio of their sides is the same.

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If the height of a right triangular prism is 1⁵/₆ inches. The surface area of the solid formed is 598.33 in².

The surface area of a solid object is a measure of the total area that the surface of the object occupies.

A three-dimensional solid form with six faces, including rectangular bases, is called a rectangular prism. A rectangular prism also refers to a cuboid. A cuboid and a rectangular prism have the same cross-section.

First step:-

Right triangular prism=1⁵/₆ inches= 11/6 inches

Height of the base=8²/₃ inches = 26/3 inches

Second step:-

Surface area = 5(10× 10) + (0.5÷ 10 × 26/3) + 3(10× 11/6)

Surface area = 5(100) +43.33+ 3(18.33)

Surface area = 500) +43.33 + 55

Surface area = 598.33 in²

Therefore the surface area of the solid formed is about 598.33 in²

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The length of 2 sides and an angle between them is given A = ½ × b × c × sin(α) If two angles and the length between them is given A = For an isosceles right triangle A = ½ × a.

If the height (i.e. the altitude) and base of an isosceles triangle are known, the area can be easily calculated. The area of the isosceles triangle is calculated by multiplying the height by the base and dividing by two. As a result, an isosceles triangle has two equal sides and two equal angles. The name is derived from the Greek words iso (same) and skelos (skull) (leg). An equilateral triangle has all of its sides equal, whereas a scalene triangle has none of its sides equal.

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Step-by-step explanation:

simple interest formula is I = p × r × t / 100

$32 = p × 8 × 3 / 100

$32 = 24p / 100

32 × 100 = 24p

3200 / 24 = $133.33

The solution to the system is 6 and 11.

We have,

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side. It demonstrates the equality of the relationship between the expressions printed on the left and right sides. We have LHS = RHS (left hand side = right hand side) in every mathematical equation. To determine the value of an unknown variable that represents an unknown quantity, equations can be solved. A statement is not an equation if it has no "equal to" sign.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" symbol and terms on both sides must always be present when writing an equation.

Given equation:

y=2x-1 .....(1)

y=x+5....(2)

Now solving equation 1 and 2, we get

2x -1 = x + 5

2x - x= 5 +1

x = 6

and, y= 2x-1

y= 2(6)-1

y= 12 -1

y= 11

Hence, the value of x is 6 and y is 11.

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complete question:

On a piece of paper, graph the system of equations. Find the solution to the system. y=2x-1 y=x+5

The length of L'L in the dilated figure that's transformed will be A. 5 units.

It should be noted that transformation simply means the movement of a point from an initial location to a new location. It should be noted that the types of transformation include translation, rotation, reflection and dilation.

Triangle JKL was dilated by 1/3 with M as the center of dilation to form J'K'L'.

It should be noted that given that ML' = 2.5 units. Therefore,

L'L = (2.5 × 3) - 2.5 = 5 units

LL = 7.5 - 2.5 = 5 units

In conclusion, the correct option is 5 units.

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Triangle JKL was dilated using the rule D Subscript M, one-third. The image, triangle J'K'L', is the result of the dilation. Point M is the center of dilation. Triangle J K L is dilated to form smaller triangle J prime K prime L prime. The length of M L prime is 2.5. What is L'L? 5 units 7.5 units 10 units 12.5 units

Answer:

wdym R6

Step-by-step explanation:

Answer:

12

Step-by-step explanation:

6*2

Answer:

The answer is 25.

Step-by-step explanation:

All you have to do is type in the calculator 5 divided by 1/5 and it should give you the answer is 25.

Answer:

(2,-6)

Hey my answer could be wrong but i checked so i hope you think this is helpful!

Answer:

\(15-4\sqrt{15}\)

Step-by-step explanation:

\(\sqrt{5}\left(3\sqrt{5}-4\sqrt{3}\right)\\\\\mathrm{Apply\:the\:distributive\:law}:\\\quad \:a\left(b-c\right)=ab-ac\\\\a=\sqrt{5},\\\:b=3\sqrt{5},\:c=4\sqrt{3}\\\\=\sqrt{5}\times\:3\sqrt{5}-\sqrt{5}\times\:4\sqrt{3}\\\\=3\sqrt{5}\sqrt{5}-4\sqrt{5}\sqrt{3}\\\\Simplify\:\:\:3\sqrt{5}\sqrt{5}-4\sqrt{5}\sqrt{3} \: :15-4\sqrt{15}\\\\=15-4\sqrt{15}\)

Answer:

it's the third answer, no-m=2 and b=-2

Step-by-step explanation:

b means the y intercept, and the line touches the y axis at -2

m means the slop and the slope is 2/1, or just 2

Answer:

x = 2

Step-by-step explanation:

8 = 6x + -2x

8 = 4x

8 = 4x

4 4

2 = x

The solutions are: x = ln(2) for 2eˣ = 4,  x = ln(25)/4 for e⁴ˣ = 25, x = ln(72) for eˣ = 72 and x = ln(124)/3 for e³ˣ = 124.

To solve these equations using natural logarithm, we can use the following rules:

Using these rules, we can solve the given equations as follows:

2eˣ = 4

Divide both sides by 2 to get

eˣ = 2.

Take the natural logarithm of both sides to get

ln(eˣ) = ln(2).

Using rule 1 above, we can simplify ln(eˣ) to x, and we get

x = ln(2).

e⁴ˣ = 25

4x = ln(25).

Divide both sides by 4 to get

x = ln(25)/4.

eˣ = 72

Take the natural logarithm of both sides to get

x = ln(72).

e³ˣ = 124

Take the natural logarithm of both sides to get

3x = ln(124).

Divide both sides by 3 to get

x = ln(124)/3.

For the second set of equations, we use the same rule as above

So, we have

ln(x - 3) = 2

x - 3 = e²

x = e² + 3.

x ≈ 10.389.

Therefore, the solution is x ≈ 10.389.

ln(2t) = 4

2t = e⁴

t = 0.5 * e⁴

t ≈ 27.299.

Therefore, the solution is t ≈ 27.299.

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Answer:

a-17 is the answer for this question

(a) To compute the experimental probability of rolling a 1 or 6 from Latoya's results, we need to determine the number of times a 1 or 6 was rolled and divide it by the total number of rolls Latoya made.

Let's assume that Latoya rolled the dice 100 times and obtained 20 1's and 10 6's. The total number of successful outcomes (rolling a 1 or 6) is 20 + 10 = 30.

Therefore, the experimental probability of rolling a 1 or 6 is 30/100 = 0.3 or 30%.

(b) Assuming the cube is fair, the theoretical probability of rolling a 1 or 6 can be determined by considering the favorable outcomes (rolling a 1 or 6) divided by the total possible outcomes (rolling any number from 1 to 6).

Since there are two favorable outcomes (1 and 6) out of six possible outcomes (1, 2, 3, 4, 5, 6), the theoretical probability is 2/6 = 1/3 or approximately 0.3333.

(c) The correct statement is B. As the number of rolls increases, we expect the experimental and theoretical probabilities to become closer, though they might not be equal. This is due to the law of large numbers, which states that as more trials are conducted, the experimental probability tends to converge towards the theoretical probability. However, it is not necessary for them to be exactly equal. Random variations can cause some discrepancy, but with a larger number of rolls, the experimental probability should approach the theoretical probability more closely.

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The area is just the base times the height. In this case, the base is (x+4) and the height is (x+6), and then you just distribute to get x^2 +4x+6x+24 which is x^2+10x+24.

Answer:

number is 5

Step-by-step explanation:

let the number be n, then

30 subtracted from 14 times the number is

14n - 30

the result is 20 more than 4 times the number, that is

4n + 20

the equation is then

14n - 30 = 4n + 20 ( subtract 4n from both sides )

10n - 30 = 20 ( add 30 to both sides )

10n = 50 ( divide both sides by 10 )

n = 5

the number is then 5

Check the picture below.

Answer: 60h + 75 < 200

                               _

Step-by-step explanation: You dont want to spend more than 200 dollars and every hour (H) is multiplied to 60

well, the tax amount is simple, it was $71 and it went up to $86.45, that's a 15.45 difference, so that IS the tax amount.

now, if we take 71(origin amount) to be the 100%, what's 15.45 off of it in percentage?

\(\begin{array}{ccll} amount&\%\\ \cline{1-2} 71 & 100\\ 15.45& x \end{array} \implies \cfrac{71}{15.45}~~=~~\cfrac{100}{x} \\\\\\ 71x=1545\implies x=\cfrac{1545}{71}\implies x\approx 21.76\)

well, the interest is going to be the increase factor on both cases, so we can simply check how much each will accumulate to in those 4 years

\(~~~~~~ \stackrel{\textit{\LARGE University Bank}}{\textit{Compound Interest Earned Amount}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$4000\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four} \end{array}\dotfill &4\\ t=years\dotfill &4 \end{cases}\)

\(A = 4000\left(1+\frac{0.05}{4}\right)^{4\cdot 4} \implies A=4000(1.0125)^{16}\implies \boxed{A \approx 4879.56} \\\\[-0.35em] ~\dotfill\)

\(~~~~~~ \stackrel{\textit{\LARGE Rosemont Savings Bank}}{\textit{Compound Interest Earned Amount}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$4000\\ r=rate\to 5.5\%\to \frac{5.5}{100}\dotfill &0.055\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{semiannually, thus two} \end{array}\dotfill &2\\ t=years\dotfill &4 \end{cases}\)

\(A = 4000\left(1+\frac{0.055}{2}\right)^{2\cdot 4} \implies A=4000(1.0275)^8\implies \boxed{A \approx 4969.52} ~~ \textit{\LARGE \checkmark}\)

Answer:

9 bags

Step-by-step explanation:

2 1/4 ÷ 1/4

9/4 ÷ 1/4

9/4 x 4/1 = 9

The average rate of change of the function over the interval is 4

From the question, we have the following parameters that can be used in our computation:

y = 4x + 1

The interval is given as

[-1, 1)

The function is a linear function

This means that it has a constant average rate of change

From y = 4x + 1, we have

Rate = 4

Hence, the rate is 4

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The resultant normal force at point D along the x-direction is \(F_D_x=0\) and  the resultant shear force at point D along the y-direction is \(F_D_y=154.29N\)

Consider the equilibrium of the shaft.

Resolve the forces along the y-direction.

\(R_A_y+R_B_y=200+200+80+80R_A_y+R_B_y=560-----(1)\)

Take moments about point B and about the z-axis:

\(R_A_y*1.4=2*100*0.7+2*80*0.4\\\\R_A_y=245.71\)

Substitute the above value in equation (1).

\(245.71+R_B_y=560\\\\R_B_y=314.29N\)

Resolve the forces along the z-direction.

\(R_A_z+R_B_z=385+385R_A_z+R_B_z=770-----(2)\)

Take moments about point B and about the y-axis:

\(R_A_z*1.4=2*385*1.1\\\\R_A_z=605N\)

Substitute the above value in equation (2).

\(605+R_B_z=770\\\\R_B_z=165N\)

a) The resultant normal force at point D along the x-direction is

\(F_D_x=0\)  

b) The resultant shear force at point D along the y-direction is

\(F_D_y-R_B_y+2*80=0\\\\F_D_y-314.29+160=0\\F_D_y=154.29N\)

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