(a) a certain lens has a focal length of 79.0 cm in air and a refractive index of 1.55. find its focal length in water.

Answers

Answer 1

The focal length of lens in water is  23.75cm if focal length of same lens in air is 79cm and refractive index is 1.55

Delineation of the frequency and refraction points. The refractive file decides how much the way of light is bowed, or refracted, while entering a material. This is depicted by Snell's law of refraction, n1 sin θ₁ = n2 sin θ₂, where θ1 and θ2 are the point of frequency and point of refraction, separately, of a beam crossing the connection point between two media with refractive records n1 and n2.

The refractive records likewise decide how much light that is reflected while arriving at the point of interaction, as well as the basic plot for all out inward reflection, their power (Fresnel's conditions) and Brewster's angle.

According to lens maker's formula, we know that

1/f=(μ-1)(1/R₁-1/R₂)

where f is the focal length of lens and μ is refractive index ,and R₁,R₂ are the radius of given lens.

For focal length in air

=>1/f₁=(1.55-1)(1/R₁-1/R₂)-----eq1

Now, for focal length in water

=>1/f₂=(1.55/1.33-1)(1/R₁-1/R₂)------eq2

On dividing eq2 by eq1,we get

=>f₁/f₂ = [(1.55-1)×1.33] / (1.55-1.33)]

=>79 / f₂ =[(0.55)×1.33] / (0.22)]

=> f₂ =79 / [(0.7315/0.22)]

=> f₂ =   79/3.325

=>f₂ =23.75cm

Hence, focal length in water is 23.75cm.

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Related Questions

What is the force on a charge of +4. 0 μC which is 150 cm away from a charge of +5. 0 μC?

Answers

293N is the force on a charge of +4. 0 μC which is 150 cm away from a charge of +5. 0 μC.

The force between two charges can be calculated using Coulomb's law. Given the charges of +4.0 μC and +5.0 μC, and the distance of 150 cm between them, we can determine the force acting on the +4.0 μC charge. Coulomb's law states that the force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

Let's convert the charges to coulombs: +4.0 μC = 4.0 x 10⁻⁶ C and +5.0 μC = 5.0 x 10⁻⁶ C.

The distance between the charges is 150 cm = 1.5 m.

Applying Coulomb's law, the force (F) between the charges is given by:

\(F = (k * q1 * q2) / r^2\)

where k is the electrostatic constant (k = 9 x 10⁹ Nm²/C²), q1 and q2 are the charges, and r is the distance between them.

Plugging in the values, we have:

F = (9 x 10⁹ Nm²/C²) * (4.0 x 10⁻⁶ C) * (5.0 x 10⁻⁶ C) / (1.5² m)²

Simplifying the expression, we can calculate the force on the +4.0 μC charge.

F=293N

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Pls give full explanation!

Pls give full explanation!

Answers

1. The part that shows the body is accelerating is the first 2 hours (ABE). The acceleration is 20 Km/h²

2. The part that shows the body is coming to rest the last 2 hours (CDF)

3. The distance travelled in the first 2 hours is 40 Km

1. How to determine the accelerated motion

Acceleration is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

a is the acceleration v is the final velocity u is the initial velocity t is the time

From the diagram (ABE), we can see that the body starts from rest and attain a final velocity (40 Km/h) within the first 2 hours. This clearly indicates that the body is accelerating.

The acceleration can be obtained as followed:

Initial velocity (u) = 0 Km/hFinal velocity (v) = 40 Km/hTime (t) = 2 hoursAcceleration (a) = ?

a = (v – u) / t

a = (40 – 0) / 2

a = 20 Km/h²

2. How to determine the part showing the body is coming to rest

From the diagram (CDF), we can see that the object velocity changes from 40 to 0 within the last 2 hours. This clearly indicates that the object caming to rest.

3. How to determine the distance travelled in the first 2 hours Initial velocity (u) = 0 Km/hFinal velocity (v) = 40 Km/hTime (t) = 2 hoursAcceleration (a) = 20 Km/h²Distance (s) = ?

v² = u² + 2as

v² = 2as

s = v² / 2a

s = 40² / (2 × 20)

s = 40 Km

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a body of mass 5 kg undergoes a change in speed from 20 m/s to 0.20m/s. find the momentum

Answers

Answer:

99kg m/s

Explanation:

\(p=m\Delta v \\\\\Delta v=20-0.20=19.8m/s \\\\p=5(19.8)=99\)

Hope this helps!

Answer:

99 kg m/s

Solution,

Initial speed(u)=20 m/s

final speed(v)=0.20 m/s

change in momentum∆P=m(v-u)

P=5(0.20-20)

P=5*19.8

P=99 kg m/s

Momentum of the body is decreased by 99 kg m/s

hope this helps...

Good luck on your assignment...

2. A bar magnet is divided in two pieces . Which of the following statements is true about the force between the broken pieces if they face each other with a small separation ? A. There is an electric repulsive force between the broken pieces B. There is an electric attractive force between the broken pieces C. There is a magnetic repulsive force between the broken pieces D. There is a magnetic attractive force between the broken pieces .

Answers

D. There is a magnetic attractive force between the broken pieces .​

Race car engineers are looking to determine the point of application of ground reaction force vector for the drivers foot against the pedals. What parameter do they need to examine?

Answers

The pedal geometry refers to the physical characteristics of the pedals such as their size, shape, and position relative to the driver's foot.

In order to determine the point of application of ground reaction force vector for the driver's foot against the pedals, race car engineers need to examine the pedal geometry. By examining the pedal geometry, engineers can determine the exact point where the driver's foot makes contact with the pedal and therefore where the ground reaction force vector is applied. This position relative  information is critical for optimizing the driver's ability to control the car and achieve maximum performance. Additionally, engineers may also need to consider other parameters such as the driver's weight, foot size, and position within the car to ensure that the pedals are properly positioned and optimized for each individual driver. Overall, examining the pedal geometry is a crucial parameter for race car engineers to consider in determining the point of application of ground reaction force vector for the driver's foot against the pedals.

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What is the relationship between an object’s mass and its gravitational potential energy?.

Answers

Answer:

If we’re talking about objects on the Earth, the gravitational potential energy is given by:

Explanation:

PEg=mgh

so the energy is proportional to the mass ( m ), but also to the strength of the gravitational field ( g ), and the height ( h ) to which the mass is lifted.

What is the relationship between the number of resistors ,the effective resistance of the circuit and the total current in parallel

Answers

Answer:

As more and more resistors are added in parallel to a circuit, the equivalent resistance of the circuit decreases and the total current of the circuit increases. Adding more resistors in parallel is equivalent to providing more branches through which charge can flow.

It takes an average car 130-140 feet to stop if they are going 55 mph. how many feet does it take for a tractor-trailer or a truck to stop going the same speed?

Answers

It will take 130-140 feet for a tractor-trailer or a truck to stop when going at the same speed.

The stopping distance of a body moving with constant acceleration can be calculated by using the following equation,

v^2 - u^2 = 2as

As the body has stopped, v will be zero.

v^2 - u^2 = 2as

The stopping distance comes out to be

s = u^2/2a

As the stopping distance is proportional to the square of the initial velocity of the body, the mass of the body does not have any effect on the stopping distance.

So, both a car and a tractor-trailer will have the same stopping distance when moving at the same speed.

Therefore, it will take 130-140 feet for a tractor-trailer or a truck to stop when going at the same speed.

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It will take 130-140 feet for a tractor-trailer or a truck to stop when going at the same speed.

The stopping distance of a body moving with constant acceleration can be calculated by using the following equation,

v^2 - u^2 = 2as

As the body has stopped, v will be zero.

v^2 - u^2 = 2as

The stopping distance comes out to be

s = u^2/2a

As the stopping distance is proportional to the square of the initial velocity of the body, the mass of the body does not have any effect on the stopping distance.

So, both a car and a tractor-trailer will have the same stopping distance when moving at the same speed.

Therefore, it will take 130-140 feet for a tractor-trailer or a truck to stop when going at the same speed.

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The cross country team goes on a 10 mile run after school. They end the run outside of the locker room where they started fund the distance and displacement of runner

Answers

Distance = 10 miles

Displacement = zero

The coach must be fired and disciplined.

A 3.0-kg meatball is moving with a speed of 6.0 m/s directly toward a 2.0 kg meatball which is at rest. The two meatballs collide and stick together. What is their velocity immediately after the (inelastic) collision?

18 m/s

3.6 m/s

6 m/s

5 m/s

Answers

Answer:

Their common velocity after collision is 3.6 m/s

Explanation:

Given;

mass of the first meatball, m₁ = 3.0 kg

initial velocity of the first meatball, u₁ = 6.0 m/s

mass of the second meatball, m₂ = 2.0 kg

initial velocity of the first meatball, u₂ = 0 m/s

let their common velocity after collision = v

Apply the principle of conservation of linear momentum for inelastic collision ;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

(3 x 6) + (2 x 0) = v( 3 + 2)

18 = 5v

v = 18 / 5

v = 3.6 m/s

Therefore, their common velocity after collision is 3.6 m/s

Electric field strength of a point charge is E. What is the electric potential at a point where electric field will be E/4?

Answers

Answer:

Explanation:

We shall find first the distance where electric field is E/4 .

Let the charge be Q and distance be d where electric field is E . From the coulomb's Law

E = k Q / d²

Let distance be d₁ where field is E/4

E/4 = kQ / d₁²

Dividing the two equation

4 = d₁² / d²

d₁ = 2d

We shall have to find Potential at d₁ which is equal to 2 d .

Potential at d₁

V = k Q / 2d

= kQ d / 2d²

= E d / 2 . where d is distance of the point where field is E .

stratum corneum consists of mostly ________ and therefore can be modeled using an electrical circuit that consists of ___________________________.

Answers

The stratum corneum consists mostly of dead skin cells called corneocytes, which are rich in keratin. Therefore, it can be modeled using an electrical circuit that consists of resistors.

In an electrical circuit analogy, the resistors represent the impedance or resistance of the stratum corneum. The electrical resistance of the corneocytes can be attributed to their structure, composition, and organization. The corneocytes are tightly packed and surrounded by lipids, which provide a barrier function to the skin.

By modeling the stratum corneum as a resistor network, researchers and scientists can study the electrical properties of the skin and investigate various phenomena, such as electrical conductivity, impedance, and the transmission of electric signals through the skin. This approach is commonly used in transdermal drug delivery studies, electrodermal measurements, and other skin-related electrical research.

It is important to note that the electrical circuit model of the stratum corneum is a simplification and does not capture all the complex biological and physiological aspects of the skin. Nonetheless, it provides a useful framework for understanding and analyzing certain electrical properties of the stratum corneum.

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How do I predict the product of a nuclear reaction.

Answers

In the 1st reaction, ⁴²K undergoes beta decay. Therefore the resulting element will have 1 more proton than ⁴²K.

Therefore, the mass number of the new particle is 42.

The atomic number of potassium is 19.

Therefore the atomic number of the new element will be 19+1=20.

Therefore the new element is Calcium.

Therefore the reaction is,

\(^{42}_{19}K\rightarrow^0_{-1}e+^{42}_{20}Ca_{}^{}\)

In three to five sentences, explain how acid rain is formed and how it impacts humans.

Answers

Acid rain is formed when sulfur dioxide and/or nitrogen oxide are present in the atmosphere and it may cause respiratory diseases.

What is acid rain?

Acid rain is a type of precipitation of water containing suspended particles that make it have a pH lower than 7, which is generally due to the presence of sulfur dioxide and/or nitrogen oxide.

Acid rain is highly toxic and this type of precipitation may cause respiratory diseases by prolonged exposure.

In conclusion, acid rain is formed when sulfur dioxide and/or nitrogen oxide are present in the atmosphere and it may cause respiratory diseases.

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Determine the Relative Humidity, Dew Point, and Lifting Condensation Level: 1. The temperature is 30∘F and it contains 3.5 g/kg of water vapor. 2. The temperature is 50∘F and it contains 5.70 g/kg of water vapor. 3. The temperature is 70∘F and it contains 3.5 g/kg of water vapor. 4. The temperature is 80∘F and it contains 5.60 g/kg of water vapor. 5. The temperature is 80∘F and it contains 11.56 g/kg of water vapor. 6. The temperature is 30∘F and the mixing ratio is 3.5. 7. The temperature is 70∘F and the mixing ratio is 8.32. 8. The temperature is 70∘F and the mixing ratio is 3.66. 9. The temperature is 80∘F and the mixing ratio is 17.59. 10. The temperature is 50∘F and the mixing ratio is 6.54.

Answers

To determine the relative humidity, dew point, and lifting condensation level (LCL) for the given conditions, we can use the provided temperature and water vapor values.

Here are the calculations for each scenario:

1. Temperature: 30°F, Water Vapor: 3.5 g/kg   - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)

  - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)   - LCL: N/A (Need the temperature and dew point)

2. Temperature: 50°F, Water Vapor: 5.70 g/kg

  - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)   - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)

  - LCL: N/A (Need the temperature and dew point)

3. Temperature: 70°F, Water Vapor: 3.5 g/kg   - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)

  - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)   - LCL: N/A (Need the temperature and dew point)

4. Temperature: 80°F, Water Vapor: 5.60 g/kg

  - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)   - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)

  - LCL: N/A (Need the temperature and dew point)

5. Temperature: 80°F, Water Vapor: 11.56 g/kg   - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)

  - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)   - LCL: N/A (Need the temperature and dew point)

6. Temperature: 30°F, Mixing Ratio: 3.5

  - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)   - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)

  - LCL: N/A (Need the temperature and dew point)

7. Temperature: 70°F, Mixing Ratio: 8.32   - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)

  - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)   - LCL: N/A (Need the temperature and dew point)

8. Temperature: 70°F, Mixing Ratio: 3.66

  - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)   - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)

  - LCL: N/A (Need the temperature and dew point)

9. Temperature: 80°F, Mixing Ratio: 17.59   - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)

  - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)   - LCL: N/A (Need the temperature and dew point)

10. Temperature: 50°F, Mixing Ratio: 6.54

   - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)    - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)

   - LCL: N/A (Need the temperature and dew point)

To calculate the relative humidity, dew point, and LCL, we require

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Problem 5: Consider the circuit diagram depicted in the figure 0.5 Ω R2 2.5 Ω /2 R 1.5Ω 0.5 Ω 50% Part (a) what equation do you get when you apply the loop rule to the loop abcdergha, in terms of the variables in the figure? Grade= 100% Correct Answer Student Final Submission Feedback Correct! 012 R2+ 112 T3 R3 +32-62 0- 1-(Ti +R2) I2+(R3r2)13 2 Grade Summary Deduction for Final Submissi Deductions for Incorrect Submissions, Hints and Feedback [?] Student Grade-100-0-0-100% 0% 0% on Submission History All Date times are displayed in Central Standard Time Red submission date times indicate late work. Date Time 9:25 PM Answer Hints Feedback 1 Oct 29,2018 0- 1-(Ti +R2) I2+(R3r2)13 2 50% Part (b) If the current through the top branch is 12-0.505 A, what is the current through the bottom, 13, in amps?

Answers

Part(a) The equation for the loop is 0 −1−(R1 +R2)I2+(R3+R2)I3=0

Part(b) The current through the bottom branch 13 is 0.75 A.

(a) This equation is found by applying the loop rule, which states that the sum of voltage drops around a loop is equal to zero. To find the equation, we start at the point, and move clockwise around the loop. At each point, we add the voltage drop of the component connected between that point and the previous point. We then substitute the component values into the equation.

For example, the voltage drop across R1 is equal to I2 * R1. In this equation, I2 and I3 are the currents through R2 and R3 respectively.

(b) To calculate this, we need to use Ohm's Law, which states that the voltage across a resistor is equal to the current through the resistor multiplied by the resistance.

First, we need to calculate the total resistance of the circuit.

       R total = R_1 + (1/2)*R_2 + R_3

                    = 0.5 + (1/2)*2.5 + 0.5

                    = 2.5 Ω

Now, we can use Ohm's Law to calculate the current through the bottom branch.

             I 13 = V/R

                     = (12-0.5)/2.5

                     = 0.75 A

Therefore, the current through the bottom branch 13 is 0.75 A.

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Why do you think that countries using the metric system prefer the Celsius scale over the Fahrenheit scale? If you decide to travel outside the United States, which one of the two temperature conversion formulas should you take?

Answers

Answer:

Celsius is a reasonable scale that assigns freezing and boiling points of with round numbers, zero and 100 making it easier .This makes it easy to calibrate instruments anywhere in the world.In Fahrenheit, those are, incomprehensibly, 32 and 212

Describe the energy changes in a mass-spring system that is oscillating horizontally. Explain how this changes if the system is vibrating vertically.​

Answers

In a mass-spring system, the energy changes between potential energy and kinetic energy as the mass oscillates back and forth.

What is mass-spring system?

Simply said, a spring-mass system is a spring system with a block hung or fastened to the free end of the spring.

The spring is stretched or compressed to its fullest extent, and the mass has the most potential energy, when the mass is at its maximum displacement from equilibrium position (either to the left or right for horizontal oscillations or up or down for vertical oscillations). The mass has no kinetic energy at this time since its velocity is zero.

As a mass-spring system oscillates horizontally or vertically, potential energy is transformed into kinetic energy when the mass swings back and forth.

Thus, this way, this changes if the system is vibrating vertically.​

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A variable is defined as a___ that can have ____than one single value.

Answers

Answer:

item/object; more

Explanation:

A variable is defined as an object or item that can have more than one single value.

A variable is defined as a quantity that can have more than one single value.

In the context of mathematics and science, a variable is a symbol or quantity that can change or vary. It represents an unknown or changing value that can take on different values in different situations or scenarios. Variables are used to describe relationships, equations, and patterns in various fields such as mathematics, physics, economics, and more.

Variables are an essential concept in scientific research and experimentation. They allow scientists to investigate how changes in one factor can affect another factor. In an experiment, variables are typically categorized into two main types: independent variables and dependent variables. The independent variable is the one that the researcher manipulates or controls to observe its effect on the dependent variable, which is the outcome being measured.

For example, in a study investigating the effects of different amounts of fertilizer on plant growth, the amount of fertilizer would be the independent variable, as it is being controlled by the researcher. The plant growth would be the dependent variable, as it depends on the different amounts of fertilizer applied.

Overall, variables are fundamental components of scientific inquiry, data analysis, and problem-solving, enabling researchers and scientists to understand and describe the relationships and patterns within various phenomena.

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Students perform an investigation using density to determine what kind of wood an oval-shaped block is made of.
One student attaches a lead cube to an oval-shaped piece of wood and submerges them in water, as shown in the
diagram. The lead cube keeps the wood from floating. When the wood is underwater, the water level reads 47
milliliters.

Answers

A student ties a lead cube to an oval-shaped block to prevent it from floating and immerses it in water density as part of a study to identify the sort of wood it is composed of.

What is the name of density?

The term "density" (also known as "volumetric mass density" or "specific mass") refers to a substance's mass per unit of volume. Although the Latin letter D may also be used, the sign most frequently used for density is (the lower case Greek letter rho).

Who discovered density?

According to legend, Archimedes shouted "Eureka!" as he rushed through the Sicilian streets. ("I've discovered it!") He had figured out what density was. Everyone has spent a significant amount of time in water during their life. The second thing Archimedes noticed was that he felt lighter floating.

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2 Fig. 2.1 shows a hammer being used to drive a nail into a piece of wood.hammer headnailwoodFig. 2.1The mass of the hammer head is 0.15 kg.The speed of the hammer head when it hits the nail is 8.0 m/s.The time for which the hammer head is in contact with the nail is 0.0015 s.The hammer head stops after hitting the nail.1.20(a) Calculate the change in momentum of the hammer head.(b) state the impulse given to nail. (c) calculate the average force between the hammer and the nail

2 Fig. 2.1 shows a hammer being used to drive a nail into a piece of wood.hammer headnailwoodFig. 2.1The

Answers

Given:

The mass of the hammerhead is m = 0.15 kg

The speed of the hammerhead is v = 8 m/s

The time for which the hammerhead is in contact with the nail is

\(\Delta t\text{ =}0.0015\text{ s}\)

To find the change in momentum

The impulse and the average force.

Explanation:

The change in momentum will be

\(\begin{gathered} \Delta p\text{ = mv} \\ =\text{ 0.15}\times8 \\ =1.2kg\text{ m/s} \end{gathered}\)

The impulse will be

\(\begin{gathered} Im\text{pulse = change in momentum} \\ =1.2kg\text{ m/s} \end{gathered}\)

The average force will be

\(\begin{gathered} F_{av}=\frac{Impulse}{\Delta t} \\ =\frac{1.2}{0.0015} \\ =800\text{ N} \end{gathered}\)

Final Answer: The change in momentum is 1.2 kg m/s

The impulse is 1.2 kg m/s.

The average force is 800 N

If a conductor is connected to "ground", then what is the charge on it?

positive

neutral

negative

determined by other nearby charges

Answers

If the conductor is connected to the ground, then it has a neutral charge.

Earth acts as a zero potential ground. So when you connect a positively charged conductor to the ground, the positive charge flows into the ground, resulting in the flow of electrons from the ground to the conductor. A ground wire acts as protection against unstable currents.

Under normal circuit conditions, no current flows through the ground wire. However, when an electrical accident such as a short circuit occurs, the ground wire removes the unstable current from the electrical system and leads it to the ground. The ground wire can be finger-safe as long as there is no electrical surge that causes current to flow through the ground wire.

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if I travel at 3m/s and it takes me 12 seconds to get from the kitchen to the bathroom how far is the bathroom from the kitchen?​

Answers

Answer:

36m would be the correct answer

A solid weighs 0.9N in air and 0.2N in a liquid of density 700kg/m^3. Calculate
i) the upthrust
ii) the volume of the solid​

Answers

The correct answer is Upthrust= 0.7N and Volume = 1.02 x 10⁻² g

Solid weighs.09 N in air.

Solid weighs less than liquid because of an upward force operating on it (solid weighs in liquid =.02 N).

A solid body experiences an upthrust when it is partially or entirely submerged in a fluid, such as water. In this case, the fluid's weight (water) equals the fluid's weight that the water has displaced.

upthrust is = to.09 -.02 N = 0.7N.

Upthrust = displaced liquid's weight

so that weight of liquid equal to volume of solid = 0.7 N

Volume of solid times mass of liquid = 0.07/9.8 = 0.00714 =  7.14 x 10⁻³ kg

Volume = Mass / density

Volume = 7.14 x 10⁻³ / 700

= 1.02 x 10⁻⁵ kg= 1.02 x 10⁻² g

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discuss the h atom emission spectra and the rydberg plot.

Answers

The hydrogen atom emission spectra provide information about the specific wavelengths or colors of light emitted when electrons transition between energy levels.

The Rydberg plot, based on the Rydberg formula, is a graphical representation of these spectral lines and helps determine the relationship between the energy levels and the observed wavelengths or frequencies.

The hydrogen atom emission spectra and the Rydberg plot are both important concepts in atomic physics that describe the behavior of the hydrogen atom and the relationship between the energy levels of its electrons.

The hydrogen atom emission spectra refers to the pattern of light emitted when the electrons in a hydrogen atom transition between different energy levels. When an electron moves from a higher energy level to a lower energy level, it releases energy in the form of photons of specific wavelengths or colors. These emitted photons create a characteristic set of spectral lines in the electromagnetic spectrum.

The spectral lines observed in the hydrogen atom emission spectra are classified into different series: the Lyman, Balmer, Paschen, Brackett, and Pfund series. Each series represents a specific range of wavelengths or energy transitions. The Balmer series, for example, includes the visible spectral lines and is commonly observed in laboratory experiments.

The Rydberg plot, named after the Swedish physicist Johannes Rydberg, is a graphical representation of the wavelengths or frequencies of the spectral lines in the hydrogen atom emission spectra. The Rydberg formula provides a mathematical relationship between the wavelengths/frequencies of the spectral lines and the energy levels of the hydrogen atom:

1/λ = \(R_H * (1/n_1^2 - 1/n_2^2)\)

where λ is the wavelength of the emitted light, R_H is the Rydberg constant for hydrogen (approximately 1.097 × \(10^7\) m⁻¹), and n1 and n2 are positive integers representing the initial and final energy levels, respectively.

By plotting the reciprocals of the observed wavelengths or frequencies against the corresponding energy level transitions, the Rydberg plot can be obtained. The Rydberg plot allows scientists to determine the Rydberg constant and study the energy structure of the hydrogen atom.

In summary, the hydrogen atom emission spectra provide information about the specific wavelengths or colors of light emitted when electrons transition between energy levels. The Rydberg plot, based on the Rydberg formula, is a graphical representation of these spectral lines and helps determine the relationship between the energy levels and the observed wavelengths or frequencies.

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What is the restoring force of a spring stretched 0. 35 meters with a spring constant of 55 newtons/meter?.

Answers

The restoring force of a spring is 19.25 Newtons

To get the restoring force, we can make use of the formula that is as follows:

F = -k x

When F represents the restoring force, x represents the displacement from equilibrium caused by the deformation, and k represents the constant that is connected to how difficult it is to distort the system, the expression reads as follows. While the minus sign denotes that the restoring force acts in the opposite direction to the displacement, the displacement itself remains constant. Using the formula, we get the following: 55 Newtons per meter multiplied by 0.35 meters.

Therefore, 19.25 Newtons would constitute the restoring force.

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Who hurt Odysseus the most on his journey home?

Answers

Answer:

Poseidon

Explanation:

Poseidon was justifiably not happy to learn that his son had suffered in this way, which made him hate Odysseus even more. After Homer invoked the muses at the beginning of the Odyssey, the poet mentioned that Poseidon had a grudge against Odysseus, which made his journey home to Ithaca difficult.

a car traveling at 15 m/s starts to decelerate steadily. it comes to a complete stop in 10 seconds. what is it's it's acceleration

Answers

Answer:

Vi=15m/s

Vf=0

t=10sec

a=?

a=Vf-vi/t

a=0-15/10

a= -15/10

a= -1.5m/s^2

Can anybody help?? If somebody can answer I'd love it!!

Can anybody help?? If somebody can answer I'd love it!!

Answers

Answer:

1.

a. T

b. F

c. T

d. F

e. T

2. Liquid, gas, solid

3. Water

4.

a. Solid

b. Gas

c. Water

5.

a. Add heat

b. Remove heat

c. Add heat

Is an object moving with a constany speed around a circular path veloctiy? why? why not?​

Answers

Answer: The motion of a body with constant speed in a circular path is said to be accelerated, because it is moving with uniform speed, but not with uniform velocity, as velocity is a vector quantity, it can be represented in magnitude as well the direction.

Explanation:

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