Explanation:
A 13.68 g sample of iron is reacted in presence of excess fluorine and an iron fluoride with a mass of 27.64 g is formed.
We have to find the empirical formula of our compound. This compound has two elements: Fe and F. We can express it like:
metal fluoride = FeₐFₓ
Where a is the subscript of Fe and x is the subscript for F.
First we have to find the mass of F present in the compound. We know that our compound has a total mass of 27.64 g and the mass of Fe present is 13.68 g. Since it only has two elements we can find the mass of F.
mass of sample = mass of Fe + mass of F
mass of F = mass of sample - mass of Fe
mass of F = 27.64 g - 13.68 g
mass of F = 13.96 g
So we found that our sample has 13.96 g of F and 13.68 g of Fe. Now we can determine the number of moles of each element that are present in the sample by using their molar masses.
molar mass of Fe = 55.85 g/mol
molar mass of F = 19.00 g/mol
moles of Fe = 13.68 g * 1 mol/(55.85 g)
moles of Fe = 0.245 moles
moles of F = 13.96 g * 1 mol/(19 g/mol)
moles of F = 0.735 moles
By definition the empirical formula is "simplest whole number ratio of atoms present in a compound". So if we want to find the ratio between them we have to divide both of them by the smallest number.
a = subscript of Fe = 0.245/0.245 = 1
x = subscript of F = 0.735/0.245 = 3
So the empirical formula of our compound is:
empirical formula = FeₐFₓ
empirical formula = FeF₃
Answer: empirical formula = FeF₃
How many electrons would Silicon with a positive 4 charge have
Answer:
Si+4 has no. of electrons=14-4=10
Explanation:
10 electrons, Silicon have with a positive 4 charge. It belongs to the periodic table's group 14: carbon family.
What is silicon?Silicon is an atomic number 14 chemical substance with the symbol Si. It is both a tetravalent metalloid as well as semiconductor that is a strong, brittle solid substance with just a blue-grey metallic sheen.
It belongs to the periodic table's group 14: carbon is above it, whereas germanium, tin, lead, as well as flerovium are below it. It is not overly reactive. Because of its strong chemical affinity to oxygen, Jöns Jakob Berzelius was not able to manufacture and analyze it in pure form until 1823. 10 electrons, Silicon have with a positive 4 charge.
Therefore, 10 electron, Silicon have with a positive 4 charge.
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compared to a phosphorus atom, a P-3 ion has
Answer:
3 electrons more
explanation
minus sign in chemistry means more
homeworkstudycom
What is the concentration of a 22.35 L solution that contains 9.95 moles of sodium
acetate? Round your answer to the correct number of significant figures.
Answer:
0.445 M
Explanation:
Molarity = moles/Volume
M = 9.95/22.35 = 0.445 M
Please help me!!!
I’ll mark as brainliest!!
Gypsum is a naturally occurring, white powdery mineral with the chemical name calcium sulphate dihydrate (CaSO4·2H2O). Gypsum products used in dentistry are based on calcium sulphate hemihydrate (CaSO4)2·H2O.
• How many grams of sulphate dihydrate must be heated to get 10 grams of sulphate hemihydrates?
We require 0.041 moles of sulphate hemihydrate and 0.041 moles of sulphate dihydrate in equal parts.
Number of moles x Molar mass = Mass of sulphate dihydrate
Sulphate dihydrate mass equals 0.041 mol 140.18 g/mol 5.74 g
To make 10 grammes of sulphate hemihydrate, 5.74 grammes of sulphate dihydrate must be cooked.
We must take into account the molar weights and stoichiometry of the compounds in order to calculate how many grammes of sulphate dihydrate (CaSO42H2O) must be heated in order to produce 10 grammes of sulphate hemihydrate (CaSO4)2H2O.
The formula below can be used to get the molar mass of sulphate dihydrate (CaSO42H2O):
One atom of calcium (Ca) is equivalent to 40.08 g/mol.
One atom of sulphur (S) is equivalent to 32.06 g/mol.
Oxygen (O): 4 atoms at 16.00 g/mol equals 64.00 g/mol.
4 atoms of hydrogen (H) at 1.01 g/mol make up 4.04 g/mol.
CaSO42H2O has a total molar mass of 140.18 g/mol.
The sulphate hemihydrate's (CaSO4) molar massThe formula for 2H2O is as follows:
Calcium (Ca): 80.16 g/mol from 2 atoms at 40.08 g/mol.
Sulphur (S): 2 atoms with a 32.06 g/mol density equals 64.12 g/mol.
Oxygen (O): 6 atoms times 16.0 g/mol equals 96.0 g/mol
Hydrogen (H): 2.02 g/mol for 2 atoms, or 1.01 g/mol.
CaSO4's total molar mass2 H2O equals 242.30 g/mol.
Using the molar mass, we can now determine how many moles of sulphate hemihydrate (CaSO4)2H2O) are contained in 10 grammes:
Mass / Molar mass = number of moles
10 g divided by 242.30 g/mol yields 0.041 moles.
One mole of sulphate dihydrate (CaSO42H2O) produces one mole of sulphate hemihydrate (CaSO4)2H2O, as shown by the reaction's stoichiometry.
As a result, we require 0.041 moles of sulphate hemihydrate and 0.041 moles of sulphate dihydrate, respectively:
Number of moles x Molar mass = Mass of sulphate dihydrate
Sulphate dihydrate mass equals 0.041 mol 140.18 g/mol 5.74 g
In order to produce 10 grammes of sulphate hemihydrate, 5.74 grammes of sulphate dihydrate must be cooked.
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What happens in a reaction if it is at chemical equilibrium?
Responses
The reaction rates of making products and using reactants are equal.
All of the reactants are used up.
The amount of the product is constantly decreasing.
There are no products in the system.
The reaction can be said to be at equilibrium when the reaction rates of making products and using reactants are equal.
When is a reaction at equilibrium?When the rates of the forward and reverse reactions are equal and the concentrations of the reactants and products don't change over time, a chemical reaction is said to be in equilibrium.
When the system reaches equilibrium, it is in a state of balance, which means that the concentrations of the reactants and products have not changed significantly.
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The green light emitted by a stoplight has a wavelength of 505 nm. What is the frequency of this photon? (c = 3.00 × 10⁸ m/s).
Answer:
5.9405*10^14 Hz
Explanation:
Remember the equation c=v*λ
v=frequency
λ=wavelength
By manipulating the equation, we can get it in terms of frequency:
c/λ=v
Now convert wavelength to meters (1nm=m*10^-9)
5.05*10^-7m (2 decimal places were shifted to make the number between 1-10, hence the -7 exponent)
Use the manipulated equation:
(3.00*10^8)/(5.05*10^-7), which yields:
5.9405*10^14 Hz (or s^-1)
The frequency of the photon will be "\(5.9405\times 10^{14} \ Hz\)".
According to the question,
Wavelength,
\(\lambda = 505 \ nm\)or,
\(= 5.05\times 10^{-7} \ m\)
As we know the equation,
→ \(c = v\times \lambda\)
or,
→ \(v = \frac{c}{\lambda}\)
By putting the values, we get
\(= \frac{3.00\times 10^8}{5.05\times 10^{-7}}\)
\(= 5.9405\times 10^{14} \ Hz\)
Thus the above answer is right.
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The hydrolysis of sucrose (C12H22O11) into glucose and fructose in acidic water has a rate constant of 1.8×10−4s−1 at 25 ∘C. Assuming the reaction is first order in sucrose, determine the mass of sucrose that is hydrolyzed when 2.45 L of a 0.170 M sucrose solution is allowed to react for 195 min.
Answer:
Explanation:
k = 1.8 x 10⁻⁴ s⁻¹
no of moles initially = 2.45 x .17 = .4165 moles
initial moles a = .4165
k = (1 / t ) ln a / ( a - x )
a is initial moles , x is moles reacted .
a is initial moles , x is moles reacted .
time t = 195 min = 11700 s
1.8 x 10⁻⁴ = 1 / 11700 x ln .4165 /( .4165 - x )
2.106 = ln .4165 /( .4165 - x )
.4165 /( .4165 - x ) = e²°¹⁰⁶ = 8.215
.4165 = 3.42 - 8.215 x
8.215 x = 3.0035
x = .3656
moles of sucrose hydrolysed = .3656 moles.
The system at equilibrium below is heated.
How does the system adjust to reestablish
equilibrium?
2SO₂(g) + O₂(g) ⇒ 2SO3(g) + 198 kJ
An aqueous solution of methanol (MM = 32.04 g/mol) has a molality of 8.83 m and a density of 1.15 g/mL. What is the molarity of methanol in the solution?
We have that the the molarity of methanol in the solution is mathematically given as
Morality=7.91mol/l
Chemical ReactionQuestion Parameters:
An aqueous solution of methanol (MM = 32.04 g/mol)
A molality of 8.83 m and a density of 1.15 g/mL.
Generally the equation for the is mathematically given as
\(Morality=\frac{moles of solute }{mass of the solvent}\)
where
Mass of solution=(100+282.2)
Mass of solution=1289.9
Volume=1289.9/1.15
Volume=1.115L
Therefore
\(Morality=\frac{moles of solute }{mass of the solvent}\)
Morality=8.83/1.115
Morality=7.91mol/l
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If 10 moles of a gas are at a pressure of 3.6 atm and at a temperature of 27°C, what is the volume of the container that the gas is in.
Answer:
68.4 liters
Explanation:
PV = nR T R = gas constant = .082057 L atm / K-mole
n = 10 T = 27C = 300.15 K
3.6 V = 10 * .082057 * 300.15 solve for V = 68.4 liters
4. What is the necessary volume of H₂ in order to obtain 5.0 g of propane (C3H8)? Assume that dH2=0,09g/l
The necessary volume of H₂ gas to obtain 5.0 g of propane (C₃H₈) is approximately 12.60 liters.
To determine the necessary volume of H₂ gas to obtain 5.0 g of propane (C₃H₈), we need to use the molar ratio between H₂ and C₃H₈, as well as the density of H₂ gas.
First, let's calculate the molar mass of propane (C₃H₈):
C: 12.01 g/mol
H: 1.01 g/mol
Molar mass of C₃H₈ = (3 * C) + (8 * H) = (3 * 12.01) + (8 * 1.01) = 44.11 g/mol
Next, we can determine the number of moles of propane (C₃H₈) using its mass:
Number of moles = Mass / Molar mass
Number of moles of C₃H₈ = 5.0 g / 44.11 g/mol ≈ 0.1134 mol
Now, we can establish the molar ratio between H₂ and C₃H₈ from the balanced chemical equation:
C₃H₈ + 5H₂ → 3CH₄
According to the balanced equation, 5 moles of H₂ are required to produce 1 mole of C₃H₈.
Therefore, the number of moles of H₂ required can be calculated as:
Number of moles of H₂ = 5 * Number of moles of C₃H₈ = 5 * 0.1134 mol = 0.567 mol
Finally, we can determine the necessary volume of H₂ gas using the ideal gas law equation:
Volume = (Number of moles * Gas constant * Temperature) / Pressure
Given that the density of H₂ is 0.09 g/L, we can convert it to moles per liter:
Density = Mass / Volume
0.09 g/L = 2 g/mol / Volume (since the molar mass of H₂ is 2 g/mol)
Solving for Volume:
Volume = 2 g/mol / 0.09 g/L ≈ 22.22 L/mol
Now, we can calculate the necessary volume of H₂ gas:
Volume of H₂ = Number of moles of H₂ * Volume per mole
Volume of H₂ = 0.567 mol * 22.22 L/mol ≈ 12.60 L
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What would happen if HF were added to water?It would not ionize at allIt would completely ionizeIt would partially ionizeIt would dissolve
Hydrofluoric acid is a weak acid, which means that it is partially ionized when it is in presence of water.
This means that the correct answer is It would partially ionize.
What does +430 degrees celsius feel like?
if two magnets are placed on a table, which statement describes a situation with the most attraction between the two magnets
The north pole of one magnet is near the South pole of the other magnet.
The ends of a magnet are called its poles. One end is called the north pole, the other is called the south pole. If you line up two magnets so that the south pole of one faces the north pole of the other, the magnets will pull toward each other.
A gas has a volume of 550 mL at a temperature of -55 °C. The volume of the gas at 30 °C is
Blank 1:
mL.
The combined gas law equation is:
(P1 * V1) / (T1) = (P2 * V2) / (T2)
The volume of the gas at 30 °C is approximately 760.67 mL.
To determine the volume of the gas at 30 °C, we can use the combined gas law equation, which relates the initial and final conditions of temperature and volume for a gas.
The combined gas law equation is:
(P1 * V1) / (T1) = (P2 * V2) / (T2)
Where:
P1 and P2 are the initial and final pressures, respectively
V1 and V2 are the initial and final volumes, respectively
T1 and T2 are the initial and final temperatures in Kelvin, respectively
We need to convert the temperatures from Celsius to Kelvin by adding 273.15 to each value.
Given:
V1 = 550 mL
T1 = -55 °C = 218.15 K
T2 = 30 °C = 303.15 K
Assuming the pressure remains constant, we can rearrange the equation to solve for V2:
V2 = (P1 * V1 * T2) / (P2 * T1)
Since the pressure is not specified in the problem, we can assume it remains constant, allowing us to cancel out the pressure terms. Thus, the final equation becomes:
V2 = (V1 * T2) / T1
Plugging in the given values:
V2 = (550 mL * 303.15 K) / 218.15 K
Simplifying the calculation, we find:
V2 ≈ 760.67 mL
Therefore, the volume of the gas at 30 °C is approximately 760.67 mL.
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In each of the following reactions identify an acid (if there is one) and then specify whether it is
an acid according to the Arrhenius definitions or the Bronsted-Lowry definitions or both.
a) H2CO3 + CN- HCN + HCO3-
b) F- + HSO4- HF + SO42-
c) HSO4- + H2O H3O+ + SO42-
a) In the reaction \(H_2CO_3 + CN^- = HCN + HCO^{3-}\), \(H_2CO_3\) acts as an acid by donating a proton (\(H^+\)) to \(CN^-\).
b) In the reaction \(F^- + HSO_4^{-} = HF + SO_4^{2-}\), \(HSO_4^{-}\) acts as an acid by donating a proton (\(H^+\)) to \(F^-\).
c) In the reaction \(HSO_4^- + H_2O = H_3O^+ + SO_4^{2-\), \(HSO_4^{-}\) acts as an acid by donating a proton (\(H^+\)) to \(H_2O\).
a) The acid is both an Arrhenius acid (produces \(H^+\) ions in water) and a Bronsted-Lowry acid (donates a proton to a base).
b) The acid is both an Arrhenius acid (produces \(H^+\) ions in water) and a Bronsted-Lowry acid (donates a proton to a base).
c) The acid is a Bronsted-Lowry acid (donates a proton to a base) but not an Arrhenius acid because it does not produce \(H^+\) ions in water. However, the \(H_3O^+\) ion that is formed can be considered an Arrhenius acid because it produces \(H^+\) ions in water.
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2A + C + D + EDetermine the enthalpy(AH)in kJ of the above reaction using the reactions below:1B → C AH = 415.3 kJA + 1B →D AH = -95.7 kJ6A ->6E AH = 207.9 kJ
Explanations:
• We will follow Hess's Law of Constant Heat Summation:
(that states that if a reaction occurs in more than one route, then the the total enthalpy change for the reaction is the sum of all changes.)
For reaction :
\(\begin{gathered} B\Rightarrow C\text{ }\Delta H\text{ = 415.3 kJ }\ldots\text{.}\mathrm{}(\text{ reaction 1)} \\ A+B\text{ }\Rightarrow\text{ D }\Delta H\text{ = -95.7kJ}\ldots.(\text{ reaction 2 ) } \\ 6A\text{ }\Rightarrow6E\text{ }\Delta H\text{ = 207.9kJ }\ldots\ldots(\text{reaction 3 ) } \end{gathered}\)∆H total =( reaction 3 )/6 +reaction 2 - reaction 1this can be expressed as :
\(\begin{gathered} \Delta H_{total\text{ }}=\text{ }\frac{207.9}{6\text{ }}+(-95.7\text{ ) - 415}.3\text{ } \\ \text{ = 34.65 -95.7 -415.3} \\ \text{ =-476.35kJ} \end{gathered}\)This means that ∆H total= -476.35kJ.
why dihydrogen is not very reactive under normal conditions?
Insoluble sulfide compounds are generally black in color. Which of the following combinations could yield a black precipitate? a) Na2S(aq) + KCl(aq) b) Li2S(aq) + Pb(N03)2(aq) c) Pb(C103)2(aq) + NaNO3(aq) d) AgNo3(aq) + KCl(aq) e) K2S(aq) + Sn(N03)4(aq)
Answer:
b) Li2S(aq)+Pb(NO3)2(aq)
e) K2S(aq)+Sn(NO3)4(aq)
Explanation:
they are the only two of the options that contain a sulfide ion (S) therefore they are the only ones that could be considered in the question.
b) Li2S(aq)+Pb(NO3)2(aq)
e) K2S(aq)+Sn(NO3)4(aq)
Question 3(Multiple Choice Worth 3 points) (01.03 LC) What is potential energy? The energy of change O The energy of position or composition O The energy of mass or volume O The energy of motion
Potential energy is often referred to as the energy of position or composition. The energy that an object has due to its tension, electric charge, or relative immobility in space is known as potential energy. Potential energy is among the two basic forms of energy.
William Rankine, a Scottish engineer and physicist, coined the phrase "potential energy" in the 19th century. Potential energy comes in a variety of forms, each linked to a particular kind of force. It is the power imparted to an object by its position in relation to other objects. Learn more about potential energy in this article, which includes a definition, several categories, and examples.
The force acting on the two objects affects the formula for potential energy. The following is the formula for gravitational force:
W = m×g×h = mgh
Where,
m is the mass in kilogramsg is the acceleration due to gravityh is the height in metersPotential Energy Unit
In terms of units, kinetic energy and gravitational potential energy are equivalent: kg m2 / s2.
The unit used to measure all energy is the joule, which has the same units as kg m2 / s2 (J).
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A 25 ml solution of 0.5 M NaOH is titrated until neutralized into a 50 ml sample of HCl?
The concentration of the acid is \(0.25 M\).
Titration is a laboratory technique used to determine the concentration of a substance in a solution by reacting it with a standardized solution of known concentration.
The titration formula can be given by,
(Volume of the Base) \(\times\) (Normality of the Base) = (Volume of the Acid) \(\times\) (Normality of the Acid)
\(\Rightarrow V_1N_1=V_2N_2\)
Given, the volume of the base (\(NaOH\)), \(V_1 =25 ml\).
The concentration of the base (\(NaOH\)), \(M_1=0.5 M\).
The equivalence of the base (\(NaOH\)) is \(1\).
Hence, the normality of the base (\(NaOH\)), \(N_1=\frac{0.5}{1}N=0.5N\).
Given, the volume of the acid (\(HCl\)), \(V_2 =50 ml\).
Let us assume that the normality of the acid (\(HCl\)) \(N_2\).
Substitute the values in the given formula of titration.
\((25\times0.5)=(50 \times N_2)\\\Rightarrow 12.5=50N_2\\\Rightarrow N_2=\frac{12.5}{50} N\\\Rightarrow N_2=0.25 N\)
Hence, the normality of the acid (\(HCl\)), \(N_2=0.25 N\).
The equivalence of the acid (\(HCl\)) is \(1\).
Therefore, the concentration of the acid, \(M_1=\frac{0.25}{1}=0.25 M\).
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When you mixed sugar and water, the sugar was the
and the final mixture was the
solvent; solute; solution
solute; solvent; solution
solvent; solution; solute
solution; solvent; solute
is
___, the water was the
Answer:
sugar was solute.
water was solvent
and product was mixture
simple...
write the structural formula for 2-bromo-3-chloro-4,4-dimethylpentanal
Answer:
Br-CH2-CH(CH3)2-C(Cl)H-CH(CH3)2-CHO
Explanation:
The molecule has a total of 14 carbon atoms, 13 hydrogen atoms, and 1 bromine atom. The carbon atoms are arranged in a chain with a methyl group attached to the second carbon atom, a chlorine atom attached to the third carbon atom, and two methyl groups attached to the fourth carbon atom. The fifth carbon atom has a carbonyl group attached to it.
The molecule is an aldehyde, which means that it has a carbonyl group (C=O) at the end of the chain. The carbonyl group is polar, and the oxygen atom has a partial negative charge. The hydrogen atom has a partial positive charge. This polarity makes the aldehyde group susceptible to nucleophilic attack.
The bromine and chlorine atoms are both electrophilic, which means that they have a partial positive charge. This makes them susceptible to nucleophilic attack.
The methyl groups are non-polar and do not have any significant reactivity.
The molecule is a chiral molecule, which means that it has a mirror image that is not superimposable on itself. This is because the carbon atom with the carbonyl group is attached to four different groups.
The molecule is a liquid at room temperature and has a strong odor. It is used in a variety of products, including perfumes, flavorings, and plastics.
Please help me.
The answer is not either 100 or 10ml I don’t understand this anymore
The volume (in mL) of 0.100 M Na₂CO₃ needed to produce 1.00 g of CaCO₃ is 100 mL
How do i determine the volume of Na₂CO₃ needed?First, we shall determine the mole in 1.00 g of CaCO₃. Details below:
Mass of CaCO₃ = 1.00 g Molar mass of CaCO₃ = 100.09 g/mol Mole of CaCO₃ =?Mole = mass / molar mass
Mole of CaCO₃ = 1 / 100.09
Mole of CaCO₃ = 0.01 mole
Next, we shall obtain the mole of Na₂CO₃. Details below:
Na₂CO₃ + CaCl₂ -> 2NaCl + CaCO₃
From the balanced equation above,
1 mole of CaCO₃ were obtained from 1 mole of Na₂CO₃
Therefore,
0.01 moles of CaCO₃ will also be obtain from 0.01 mole of Na₂CO₃
Finally, we shall determine the volume of Na₂CO₃ needed. Details below:
Molarity of Na₂CO₃ = 0.10 MMole of Na₂CO₃ = 0.01 moleVolume of Na₂CO₃ =?Volume = mole / molarity
Volume of Na₂CO₃ = 0.01 / 0.1
Volume of Na₂CO₃ = 0.1 L
Multiply by 1000 to express in mL
Volume of Na₂CO₃ = 0.1 1000 =
Volume of Na₂CO₃ = 100 mL
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An early arrangement of the then known elements was proposed by a British scientist John Newlands, which he called the Law of Octaves. Like other scientists at the time, Newlands arranged the elements in order of increasing atomic mass and noted that every eighth element had similar physical/chemical properties. In the modern Periodic Table, which of the following represents the last pair of elements for which Newlands' Law of Octaves would hold true?
Show the Schematic representation of a polarimeter?
A polarimeter fundamental working principle entails the following: By passing light via a polarizer, one can produce light with a precisely prepared linear polarisation state.
What are the uses of polarimeter?Polarimeters have a wide range of uses, including determining the concentration and purity of chemicals in medications, maturation testing for agricultural products, and measuring the sugar content in beverages and candies.A polarimeter is made up of a light source, a monochromator (which reduces the light's spectrum to just one wavelength), a polarizer (which turns the beam of light into plane polarised light), a sample tube (which holds the sample being measured), a second polarizer (which determines the degree of rotation), and a light detector.By directing monochromatic light through two polarising plates, polarimeters calculate the optical activity. Sodium light is utilised because it has a high energy output and provides monochromatic light with a wavelength of 589 nm.To learn more about polarimeter refer to:
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CuBr2 percent composition
The percent composition of CuBr₂ is approximately 28.46% of Cu and 71.54% of Br.
To determine the percent composition of CuBr₂ (copper(II) bromide), we need to calculate the mass of each element in the compound and then divide it by the molar mass of the entire compound.
The molar mass of CuBr₂ can be calculated by adding up the atomic masses of copper (Cu) and bromine (Br) in the compound. The atomic masses of Cu and Br are approximately 63.55 g/mol and 79.90 g/mol, respectively.
Molar mass of CuBr₂ = (63.55 g/mol) + 2(79.90 g/mol) = 223.35 g/mol
Now, let's calculate the percent composition of each element in CuBr₂:
Percent composition of copper (Cu):
Mass of Cu = (63.55 g/mol) / 223.35 g/mol × 100% ≈ 28.46%
Percent composition of bromine (Br):
Mass of Br = 2(79.90 g/mol) / 223.35 g/mol × 100% ≈ 71.54%
Therefore, the percent composition of CuBr₂ is approximately:
- Copper (Cu): 28.46%
- Bromine (Br): 71.54%
These values represent the relative mass percentages of copper and bromine in the compound CuBr₂.
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]All organic compounds contain the element carbon but, not all compounds containing the element “carbon”are organic .Justify this statement.
The statement "All organic compounds contain the element carbon, but not all compounds containing the element 'carbon' are organic" can be justified based on the definition and characteristics of organic compounds.
Organic compounds are compounds primarily composed of carbon and hydrogen atoms, often with other elements like oxygen, nitrogen, sulfur, and phosphorus. These compounds are typically associated with living organisms and are known for their unique properties and behavior, including the ability to form complex structures, exhibit covalent bonding, and undergo organic reactions.
On the other hand, there are compounds that contain carbon but are not classified as organic. One notable example is carbon dioxide (\(CO_{2}\)), which is a simple inorganic compound composed of carbon and oxygen. Carbon dioxide does not possess the characteristic properties of organic compounds, such as the ability to form long chains or undergo organic reactions.
Additionally, there are inorganic compounds like carbonates (such as calcium carbonate) and carbides (such as calcium carbide) that contain carbon but are not considered organic. These compounds have distinct chemical and physical properties different from those of organic compounds.
In summary, while all organic compounds contain carbon, not all compounds containing carbon are organic. The classification of a compound as organic or inorganic depends on its overall molecular structure, bonding, and characteristic properties.
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Silver (1) oxide → silver + oxygen gas
Answer: come on lets link can do what i do
Arrange the following compounds in order of increasing solubility in
water and explain your sequence.
C7H15OH C6H13OH C6H6 C2H5OH
Answer:
C6H6<C7H15OH<C6H13OH<C2H5OH
Explanation:
Organic substances are ordinarily nonpolar. This means that they do not dissolve in water. However, certain homologous series of organic compounds actually dissolve in water because they possess certain functional groups that effectively interact with water via hydrogen bonding.
A typical example of this is alcohol family. All members of this homologous series contain the -OH functional group. This group can effectively interact with water via hydrogen bonding, leading to the dissolution of low molecular weight alcohols in water.
Low molecular weight alcohols are miscible with water in all proportions. This implies that they are highly soluble in water. However, as the size of the alkyl moiety in the alcohol increases, the solubility of the alcohol in water decreases due to less effective interaction of the -OH group with water via hydrogen bonding. This explains the fact that C2H5OH is the most soluble alcohol in the list.
C6H6 is insoluble in water since it is purely a hydrocarbon with no -OH group capable of interaction with water via hydrogen bonding.