9. Applying Concepts Explain why it isn't
possible for an atom to have a mass number
of 10 and an atomic number of 12.

I feel like it’s a no because the number of neurons would be -2, since you subtract the mass number and the atomic number

Molar concentration of Sodium chloride (NaCl) means the number of moles of sodium chloride present in 1L of water.

Molar mass of NaCl = Molar mass of Na + Molar mass of Cl

Molar mass of NaCl = 23 + 35.5

Molar mass of NaCl = 58.5g

∴ 1L of water contains 55.55 moles of water. Hence,

Mass of ocean water = 55.55 × 18 = 999.9g

Since, 1L of ocean water has a mass of 999.9g of which 3.5% is the salt.

hence, (999.9) (0.035) = 34.99g

So, No. of moles of NaCl = Mass of NaCl / 58g NaCl per mol

No. of moles of NaCl = 34.99/58.5

No. of moles of NaCl = 0.59 moles

So, Molar concentration or Molarity would be 0.59 moles present in 1L of solution.

Hence, Molarity or Molar Concentration = Moles of NaCl/ Volume of solution (in L)

Molarity = 0.59/1L

⇒ Molarity = 0.59M

Hence, the molarity is 0.59M

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Answer: Significant figures in a measurement are all measured digits, and one estimated digit

Significant figures communicate the level of precision in measurements Significant figures are an indicator of the certainty in measurements.

Explanation:

Significant figures : The figures in a number which express the value or the magnitude of a quantity to a specific degree of accuracy or precision is known as significant digits.

The significant figures of a measured quantity are defined as all the digits known with certainty and the first uncertain or estimated digit.

Rules for significant figures:

1. Digits from 1 to 9 are always significant and have infinite number of significant figures.

2. All non-zero numbers are always significant.

3. All zero’s between integers are always significant.

4. All zero’s preceding the first integers are never significant.

5. All zero’s after the decimal point are always significant.

The true statements are

Significant figures in measurement are all measured digits, and one estimated digit

Significant figures communicate the level of precision in measurements Significant figures are an indicator of the certainty in measurements.

The following information should be considered:

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Answer:

this claim may not be accurate because the blog is produced by someone who is not an expert in the field of human psychology.

Explanation:

Answer:

this claim may not be accurate because the blog is produced by someone who is not an expert in the field of human psychology.

Explanation: give the branliest to the otherperson :)

Answer: Copper is purified by electrolysis . Electricity is passed through solutions containing copper compounds, such as copper(II) sulfate. The anode (positive electrode ) is made from impure copper and the cathode (negative electrode) is made from pure copper. Pure copper forms on the cathode.

A five-carbon un-saturated hydrocarbon molecule will have more hydrogen atoms.

Any sort of hydrocarbon that contains at least one double bond, triple bond, as well as a ring through its carbon chain has been referred to as an unsaturated hydrocarbon. As a result, these molecules would have fewer hydrogen ions than the maximum number that the carbon chain is capable of supporting.

Alkenes, alkynes, as well as aromatic hydrocarbons, may be the three different kinds of unsaturated hydrocarbons. Alkenes had a or more double bonds between carbon atoms. Alkynes feature one or more triple bonds between carbon atoms, while aromatic hydrocarbons have rings such as benzene or aromatics.

Therefore, a five-carbon un-saturated hydrocarbon molecule will have more hydrogen atoms.

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Approximately 3.72 liters of C2H2 are required to produce 8 L of CO2 at STP.

We can use stoichiometry to determine the amount of C2H2 required to produce 8 L of CO2 at STP.

According to the balanced equation, 2 moles of C2H2 react with 5 moles of O2 to produce 4 moles of CO2 and 2 moles of H2O. This means that the ratio of C2H2 to CO2 is 2:4 or 1:2.

At STP, 1 mole of any gas occupies 22.4 L. Therefore, 8 L of CO2 corresponds to 8/22.4 ≈ 0.357 moles of CO2.

Since the ratio of C2H2 to CO2 is 1:2, we need half as many moles of C2H2 as moles of CO2:

0.357 moles of CO2 × (1 mole of C2H2 / 2 moles of CO2) = 0.179 moles of C2H2

Now we can use the ideal gas law to convert moles of C2H2 to liters at STP:

PV = nRT

where P is the pressure (1 atm), V is the volume (unknown), n is the number of moles (0.179 moles), R is the gas constant (0.0821 L·atm/K·mol), and T is the temperature in Kelvin (273 K at STP).

Solving for V, we get:

V = nRT/P = (0.179 mol)(0.0821 L·atm/K·mol)(273 K)/(1 atm) ≈ 3.72 L

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Answer:

2 A): Fluorine

B): more protons, more force attraction less atomic radius

3A): Helium

B):it has small atomic radius

4 th question is not visible.....

Gasohol is a blend of gasoline and ethanol. To determine the maximum work that can be obtained by burning 1.003 mol of C2H5OH at 25°C and 1 atm, the Gibbs free energy equation can be utilized. What is Gibbs free energy equation? Gibbs free energy equation is a thermodynamic equation that quantifies the maximum quantity of work that may be obtained during a chemical reaction. T

he equation is as follows: ΔG = ΔH - TΔSThe values of ΔH and ΔS are calculated from thermodynamic tables or by calculating the enthalpy and entropy of the products and reactants, and the temperature, T, is usually specified in Kelvin. The change in Gibbs free energy, ΔG, is the maximum amount of energy that can be obtained from the reaction in the form of useful work if the reaction takes place at constant pressure and temperature. The reaction will proceed spontaneously if ΔG is negative. And if ΔG is positive, the reaction will not take place spontaneously. The solution to this problem is shown below:

First, let's figure out how much heat is produced when one mole of C2H5OH is burnt.ΔHrxn = [2(moles of CO2)(-393.5 kJ/mol) + 3(moles of H2O)(-285.8 kJ/mol)] - [(moles of C2H5OH)(-277.7 kJ/mol)]ΔHrxn = [2(2.006 mol)(-393.5 kJ/mol) + 3(3.009 mol)(-285.8 kJ/mol)] - [1.003 mol(-277.7 kJ/mol)]ΔHrxn = -2043.5 kJ/mol. Now, we'll figure out the entropy change for the reaction.ΔSrxn = [2(moles of CO2)(213.8 J/mol-K) + 3(moles of H2O)(69.9 J/mol-K)] - [(moles of C2H5OH)(160.7 J/mol-K)]ΔSrxn = [2(2.006 mol)(213.8 J/mol-K) + 3(3.009 mol)(69.9 J/mol-K)] - [1.003 mol(160.7 J/mol-K)]ΔSrxn = -104.3 J/mol-KThe temperature in Kelvin is 25°C.273 + 25 = 298 KΔG = ΔH - TΔSΔG = -2043.5 kJ/mol - (298 K)(-104.3 J/mol-K)/1000ΔG = -2032.6 kJ/mol. Therefore, the maximum work that can be obtained by burning 1.003 mol of C2H5OH is 2032.6 kJ/mol, which is the value of ΔG.

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Answer:

the escape velocity

Explanation:

To do this, your rock has to go very fast – more than 11 kilometers per second. This velocity is called the escape velocity, the speed an object must achieve in order to overcome the gravitational attraction of a celestial body (be it a planet, a star, or a galaxy) and escape into space

found it online, lol better then nothing

The First  largest prime is 37. None of the other numbers are prime number in the ten-number list 37, 3737, 373737, 37373737,., 373737373737373737 37. so no number is largest prime number.

A prime range is an entire number more than 1 whose most effective elements are 1 and itself. A component is an entire range that may be divided calmly into any other range. The first few top numbers are 2, 3, 5, 7, 11, 13, 17, 19, 23 and 29. Numbers which have extra than elements are known as composite numbers.

Number 37 is top as it would not have right elements. In different words, the most effective elements of 37 are 1 and itself. The top numbers from 1 to one hundred are: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97. To show whether or not a range of is a top range, first strive dividing it via way of means of 2, and spot in case you get an entire range. If you do, it cannot be a top range. If you do not get an entire range, subsequent strive dividing it via way of means of top numbers: 3, 5, 7, 11 (nine is divisible via way of means of 3) and so on, usually dividing via way of means of a top range.

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Answer:0.40 M

Explanation:

M = moles/L

moles = 59.0 / 74( molar mass from the Periodic table for KCl) =0.797 moles

M=0.797/2 = 0.3986 = 0.40 M

The main differences in the synthesis of purine and pyrimidine nucleotides -

What are 2 differences between purine and pyrimidine?

What are the structural differences among purines and pyrimidines in DNA and RNA?

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Answer:

B.

Explanation:

Thus we can see that the mass of protons and mass of neutrons are approximately equal.

There are 0,419 moles of glucose in a sample that weights 75.5g.

To calculate the amount in moles of glucose in 75.5g, we first need the molar mass of this compound. To calculate that I'll be using the following atomic mass values:

C: 12

H: 1

O: 16

To calculate the molar mass, we multiply the number of atoms by the respective atomic mass:

(6 * 12) + (12 * 1) + (6 * 16) = 180 g/mol

Since the molar mass is 180 g/mol, we know that each mol has 180 g of glucose:

1 mol glucose ---------- 180g glucose

x --------------------------- 75.5g glucose

Solving for x, we have x = 0.419 moles of glucose

Answer:

it is your instantaneous speed

Explanation:

There are approximately 0.000486 moles of hydrogen present in the sample.

To find the number of moles of hydrogen present in the sample, you need to use the ideal gas law equation, which is PV = nRT where P is the pressure of the gas (in atm), V is the volume of the gas (in L), n is the number of moles of gas, R is the ideal gas constant, and T is the temperature of the gas (in K). First, you need to convert the pressure from torr to atm. You can do this by dividing the pressure in torr by 760, since 1 atm is equal to 760 torr. In this case, the pressure in atm would be: P = 764.5 torr / 760 = 1.0059 atm Next, you need to convert the volume from ml to L. You can do this by dividing the volume in ml by 1000, since 1 L is equal to 1000 ml. In this case, the volume in L would be: V = 30.42 ml / 1000 = 0.03042 L Finally, you need to convert the temperature from degrees Celsius to Kelvin. You can do this by adding 273.15 to the temperature in Celsius. In this case, the temperature in K would be:T = 25.58 degrees Celsius + 273.15 = 298.73 K Now that you have all the necessary values, you can plug them into the ideal gas law equation to solve for the number of moles of hydrogen: n = (PV) / (RT) = (1.0059 atm * 0.03042 L) / (8.31 J/mol*K * 298.73 K) = 4.86 x 10^-4 mol Therefore, there are approximately 0.000486 moles of hydrogen present in the sample

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Answer:

3 significant digits

Explanation:

The first 0 don't count (that's the rule in significant digits). So 3,0,0 are left over. Count them and total will be 3 significant digits. (remember the last zero count if there is a decimal but the first zeros doesn't count even with the decimals)

To prepare 10.0 ml of a 0.25% m/v HCl solution, you will need to mix 2.5 ml of 1% m/v HCl solution with 7.5 ml of distilled water.

To make 10.0 ml of a 0.25% m/v HCl solution from 1% m/v HCl, dilute the 1% m/v HCl solution by a factor of 4.

Here's how to figure out how much 1% m/v HCl and distilled water you'll need:

Determine the concentration of HCl in the final solution:

A 0.25% m/v HCl solution contains 0.25 grams of HCl per 100 mL. 

As a result, there will be 0.25 g/100 ml x 10 ml = 0.025 g of HCl in 10 ml of solution.

Determine the quantity of 1% m/v HCl required:

1% m/v HCl implies that there is one gram of HCl in every 100 ml of solution. You will need the following to make 0.025 g of HCl:

0.025 g/1 g x 100 ml = 2.5 ml of 1% m/v HCl solution

Determine the amount of distilled water required:

To prepare the remaining 7.5 ml of solution, use the following :

10 ml - 2.5 ml = 7.5 ml of distilled water

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The given reaction is: 2 NOCl(g) → 2 NO(g) + Cl2(g)

To compare the rates of the reactants and products, we can look at the stoichiometric coefficients in the balanced equation.

According to the stoichiometry of the reaction, for every 2 moles of NOCl consumed, 2 moles of NO are produced, and 1 mole of Cl2 is produced.

Based on this information, the correct relationship that compares the rates of the reactants and products is:

A. [NOCl] / Δt = -2 [NO] / Δt = -1/2 [Cl2] / Δt

This relationship indicates that the rate of disappearance of NOCl is

twice the rate of appearance of NO and half the rate of appearance of Cl2.

Therefore, the correct option is A.

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Water-soluble chemicals can have different effects on humans compared to their impact on the environment due to several factors such as exposure pathways and metabolism.

Exposure pathways: Humans may come into contact with water-soluble chemicals through ingestion, inhalation, or dermal exposure, which can be different from the routes of exposure for organisms in the environment. The exposure route can significantly influence the level of toxicity and potential harm.

Metabolism and detoxification: Humans have metabolic processes and detoxification mechanisms that can break down or eliminate certain water-soluble chemicals, reducing their potential toxicity.

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The substance in the image above would be classified as a mixture of elements (option E).

A compound is a substance formed by chemical bonding of two or more elements in definite proportions by weight.

On the other hand, a mixture is made when two or more substances are combined, but they are not combined chemically.

According to this question, an image is shown with two different substances or elements as distinguished by coloration (white and purple). These elements are combined but not chemically bonded, hence, is a mixture.

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The role of oxygen in the functioning of the electron transport chain (ETC) is to act as the final electron acceptor.

It accepts electrons at the end of the electron transport chain, which allows the ETC to continue operating and generate ATP through oxidative phosphorylation.

During aerobic respiration, oxygen combines with electrons and protons to form water in the following reaction:

1/2 O2 + 2 H+ + 2 e- → H2O

This reaction summarizes the fate of oxygen as it accepts electrons and protons from the ETC. The oxygen molecules are reduced to form water, which is a byproduct of aerobic respiration.

This process is crucial for the efficient production of ATP in aerobic organisms. Without oxygen as the final electron acceptor, the electron transport chain would not be able to function properly, leading to a decrease in ATP production and an impairment of cellular energy metabolism.

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Answer:

The energy contained in its molecules movement and vibration

Explanation:

See above

The two ways in which humans have negatively affected groundwater are Fertilizers and pesticides.

Fertilizers were chemical substances that are applied to crops in order to boost their yield.

Pesticides are chemicals that are being used to keep pests at bay. Herbicides, insecticides, nematicides, and molluscicides are examples.

Fertilizers and pesticides applied to the land, manure from livestock as well as other animals, landfills, mining operations, even unintended releases such as chemical spills or storage tank leaks are all factors that affect groundwater quality.

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Answer:

A thermodynamic quantity equivalent to the capacity of a system to do work.

Explanation:

The by-products produced by the E1 and/or E2 processes in the reaction of 2-methyl-2-butanol with HCl include 2-methyl-2-butene and water.

During the reaction of 2-methyl-2-butanol (also known as tert-amyl alcohol) with HCl, two main processes can occur: E1 (unimolecular elimination) and E2 (bimolecular elimination). Both processes involve the removal of a proton (H+) from the alcohol and the formation of a new bond.

In the E1 process, the reaction proceeds through a carbocation intermediate. The alcohol molecule loses a proton, resulting in the formation of a carbocation. In the case of 2-methyl-2-butanol, the carbocation formed is a 2-methyl-2-butyl carbocation. This carbocation can then undergo elimination of a leaving group (such as chloride) to form an alkene. In this case, the major product formed would be 2-methyl-2-butene. The loss of a proton and the formation of water as a by-product occur simultaneously.

In the E2 process, the reaction occurs in a concerted manner, where the proton is removed by a base (in this case, the chloride ion). The base attacks the hydrogen on the beta-carbon (the carbon adjacent to the carbon bearing the hydroxyl group), leading to the formation of a double bond. Again, the major product formed in this process would be 2-methyl-2-butene. Water is also produced as a by-product in the E2 process.

In summary, the E1 and/or E2 processes in the reaction of 2-methyl-2-butanol with HCl result in the formation of 2-methyl-2-butene as the major product, along with water as a by-product.

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The concentration of ascorbic acid is given as 0.0439 M, the concentration of \(HC_{6}H_{6}O_{6-}\) will also be 0.0439 M

To calculate the concentration of \(HC_{6}H_{6}O_{6-}\) in an aqueous solution of 0.0439 M ascorbic acid \(H_{2}C_{6}H_{6}O_{6}\), we need to consider the ionization of ascorbic acid. Ascorbic acid can donate two protons (H+) to form the \(C_{6}H_{6}O_{6-}\) ion.

The balanced equation for the ionization of ascorbic acid is:

\(H_{2}C_{6}H_{6}O_{6}\) (aq) ⇌ \(HC_{6}H_{6}O_{6-}\) (aq) + H+ (aq)

From the equation, we can see that for every molecule of \(H_{2}C_{6}H_{6}O_{6}\), one molecule of \(HC_{6}H_{6}O_{6-}\) is formed.

Since the concentration of ascorbic acid is given as 0.0439 M, the concentration of \(HC_{6}H_{6}O_{6-}\) will also be 0.0439 M.

Therefore, the concentration of \(HC_{6}H_{6}O_{6-}\) in the aqueous solution of 0.0439 M ascorbic acid is also 0.0439 M.

This is because, during the ionization of ascorbic acid, all of the ascorbic acid molecules that ionize will form the \(HC_{6}H_{6}O_{6-}\) ions. As a result, the concentration of \(HC_{6}H_{6}O_{6-}\) is equal to the initial concentration of ascorbic acid.

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Carbon dioxide, when present in sufficient amounts, will bind with water to form carbonic acid (H2CO3), which is capable of dissociating into hydrogen ions (H+) and bicarbonate ions (HCO3-).

When carbon dioxide dissolves in water, it undergoes a chemical reaction to form carbonic acid. This reaction is facilitated by the presence of an enzyme called carbonic anhydrase, which speeds up the conversion of carbon dioxide and water into carbonic acid. The balanced chemical equation for this reaction is:

CO2 + H2O ⇌ H2CO3

Carbonic acid (H2CO3) can further dissociate into hydrogen ions (H+) and bicarbonate ions (HCO3-). The equilibrium between carbonic acid and its dissociation products is influenced by factors such as pH and carbon dioxide concentration. In the presence of high acidity or low carbon dioxide concentrations, the equilibrium shifts towards the formation of carbon dioxide and water, favoring the reverse reaction. On the other hand, in alkaline conditions or high carbon dioxide concentrations, the equilibrium shifts towards the formation of carbonic acid.

The reversible nature of this reaction is important in biological systems, such as in the transportation of carbon dioxide in the blood and the regulation of pH in the body.

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Answer:

the answer is the second one.