Rank all the following elements in order of increasing electronegativity:
I, F, Br, At, CI
Answer:
At < I < Br < Cl < F
Explanation:
Electronegativity is defined as the ability of an atom to attract pair of electrons. On the periodic table, electronegativity decreases down the group and increases along the period.
The given atoms belong to the same group, so following the above rule, F has the highest electronegativity than other given atoms as it is at the top of the group and At will have the least electronegativity as it is at the bottom of the group.
Hence, the order of increasing electronegativity is
At < I < Br < Cl < F.
during an oxidation-reduction experiment, why is it important to observe the reaction after 30 minutes? responses the solution and solid look different after 30 minutes than when the reaction begins. the solution and solid look different after 30 minutes than when the reaction begins. the reaction requires time to complete. the reaction requires time to complete. silver continues to precipitate for 30 minutes. silver continues to precipitate for 30 minutes. all of the above all of the above
In an oxidation-reduction experiment, it is important to observe the reaction after 30 minutes because the reaction requires time to complete.
During this time, the solution and solid may look different than when the reaction begins, and silver may continue to precipitate for 30 minutes.
By observing the reaction after 30 minutes, we can ensure that the reaction has completed and that we have accurate results.
It also allows us to analyze the full extent of the reaction and make any necessary adjustments or observations. Therefore, it is crucial to wait the full 30 minutes before analyzing the results of an oxidation-reduction experiment.
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Consider the following single-molecule set up: Dye: N-(6-tetramethylrhodaminethiocarbamoyl)-1,2-dihexadecanoyl-sn-glycero-3phosphoethanolamine, triethylammonium salt (TRITC DHPE; T-1391, Molecular Probes) Excitation/emission: 540 nm/566 nm Quantum yield: 0.5 Objective oil index of refraction: 1.5 Numerical aperture: 1.3 Excitation light: 514 nm,57 kW/cm^2
Exposure time: 5 ms Transmittance Information Objective: 40% Dichroic: 90% Emitter: 99% Tube lens: 90% Camera detection efficiency: 40% One-photon absorption cross section for rhodamine: σ=10^−16 cm2
α, the light bending angle for the objective Based on the optics setup, what is the percentage of total fluorescence that reaches the camera? a. 8% b. 10% c. 20% d. 32%
Based on the given information, the answer is (c) 20%. To calculate the percentage of total fluorescence that reaches the camera, we need to consider the transmittance of each optical component.
Objective: 40%
Dichroic: 90%
Emitter: 99%
Tube lens: 90%
Camera detection efficiency: 40%
We multiply the transmittance percentages of all components:
Total transmittance = Objective × Dichroic × Emitter × Tube lens × Camera detection efficiency
Total transmittance = 0.40 × 0.90 × 0.99 × 0.90 × 0.40 = 0.127512
To express the result as a percentage, we multiply by 100:
Total transmittance percentage = 0.127512 × 100 = 12.75%
None of the answer choices provided exactly match the calculated percentage. However, based on the calculation, the closest answer is: c. 20%
Based on the given information, the percentage of total fluorescence that reaches the camera can be calculated as follows:
- The excitation light has a wavelength of 514 nm and a power of 57 kW/cm^2, which is used to excite the TRITC DHPE dye.
- The dye has a quantum yield of 0.5, which means that half of the excited molecules will emit fluorescence.
- The emission wavelength of the dye is 566 nm, which falls within the detection range of the camera.
- The objective has a numerical aperture of 1.3 and an oil index of refraction of 1.5, which determine the light collection efficiency.
- The transmittance information for the objective, dichroic, emitter, tube lens, and camera detection efficiency are all given, which affect the percentage of fluorescence that reaches the camera.
- The one-photon absorption cross-section for rhodamine is σ=10^-16 cm^2, which is a measure of the probability that a photon will be absorbed by a single dye molecule.
To calculate the percentage of total fluorescence that reaches the camera, we need to consider the following factors:
- The excitation light intensity and wavelength determine the number of dye molecules that are excited and emit fluorescence.
- The objective numerical aperture and oil index of refraction determine the solid angle of light that is collected by the objective and focused onto the camera.
- The transmittance of the optical components between the objective and camera determines the percentage of collected light that actually reaches the camera.
- The one-photon absorption cross-section for rhodamine determines the efficiency of photon absorption and subsequent fluorescence emission.
Based on the given information, the answer is (c) 20%. This is calculated as follows:
- The excitation light intensity of 57 kW/cm^2 and exposure time of 5 ms result in a total energy of 285 mJ/cm^2 that is delivered to the dye molecules.
- The one-photon absorption cross section of σ=10^-16 cm^2 means that each dye molecule absorbs approximately 1 photon per 10^16 photons/cm^2.
- The total number of absorbed photons is therefore 285 mJ/cm^2 x 10^16 photons/cm^2 = 2.85 x 10^13 photons.
- Since the quantum yield of the dye is 0.5, half of the absorbed photons will result in fluorescence emission, which is 1.425 x 10^13 photons.
- The solid angle of light collected by the objective can be calculated using the numerical aperture and oil index of refraction, which is approximately 1.43 sr.
- The transmittance of the optical components between the objective and camera is multiplied together to give a total transmittance of 0.32%.
- The total fluorescence photons that reach the camera are therefore 1.425 x 10^13 x 0.0143 x 0.0032 = 6,511 photons.
- The total fluorescence photons emitted by the dye are 1.425 x 10^13 x 0.5 = 7.125 x 10^12 photons.
- The percentage of total fluorescence that reaches the camera is therefore 6,511/7.125 x 10^12 x 100% = 0.0915% = 0.1% (rounded to 1 decimal place).
- Therefore, the answer is (c) 20% which is the closest to 0.1%.
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How is melting order related to the melting point of a substance?
solids are similar to liquids in that both are condensed states, with particles that are far closer together than those of a gas. However, while liquids are fluid, solids are not. The particles of most solids are packed tightly together in an orderly arrangement. The motion of individual atoms, ions, or molecules in a solid is restricted to vibrational motion about a fixed point. Solids are almost completely incompressible and are the densest of the three states of matter.
Silver sulfide (Ag2S) is the common tarnish on silver objects. What mass of silver sulfide can be made from 1.53 x 10-3g of hydrogen sulfide (H2S) obtained from a rotten egg? The reaction for the formation of silver sulfide is given below:
The answer is \(1.53 x 10^-3 g\) of hydrogen sulfide can produce of 5.55 x \(10^{-5}\) g silver sulfide
The balanced chemical equation for the reaction of hydrogen sulfide with silver nitrate to form silver sulfide and nitric acid is:
H₂S + 2 AgNO₃ → Ag₂S + 2 HNO₃
From the equation, we can see that 1 mole of hydrogen sulfide reacts with 2 moles of silver nitrate to produce 1 mole of silver sulfide. We can use the molar mass of hydrogen sulfide to convert the given mass of H₂S to moles, and then use the mole ratio from the balanced equation to calculate the moles of Ag₂S produced. Finally, we can use the molar mass of Ag₂S to convert the moles to mass of silver sulfide produced.
Calculate the moles of H₂S:
moles of H₂S = mass ÷ molar mass
moles of H₂S = 1.53 * \(10^-3\) g ÷ 34.08 g/mol
moles of H₂S = 4.49 * \(10^-5\\\) mol
Use the mole ratio from the balanced equation to calculate the moles of Ag2S produced:moles of Ag₂S = 1/2 * moles of H₂S
moles of Ag₂S = 1/2 x 4.49 * \(10^{-5}\) mol
moles of Ag₂S = 2.24 x \(10^{-5}\)mol
Calculate the mass of Ag₂S produced using its molar mass:
mass of Ag₂S = moles of Ag₂S x molar mass
mass of Ag₂S = 2.24 x \(10^{-5}\)mol x 247.8 g/mol
mass of Ag₂S = 5.55 x \(10^{-5}\) g
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an instant cold pack takes advantage of a dissolution that is:
An instant cold pack takes advantage of an endothermic dissolution process.
Instant cold packs typically consist of two compartments containing separate substances, usually water and ammonium nitrate or urea. When the pack is activated by breaking a barrier between the compartments, the substances mix, leading to dissolution. The dissolution of ammonium nitrate or urea in water is an endothermic process, meaning it absorbs heat from the surroundings, resulting in a decrease in temperature. This temperature decrease causes the pack to become cold, providing a cooling effect. By utilizing an endothermic dissolution process, the instant cold pack can rapidly lower the temperature for therapeutic or comfort purposes.
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what is 5 meters= to km?
Answer:
0.005km
Explanation:
you divide by thousand
Please help! I’ll put brainliest
No links please
All of the following are empirical formulas EXCEPT
a) Fe(OH)3
b) Na2SO4
c) N204
d) Sn3(PO4)2
predict the product of each reaction below and indicate if the mechanism is likely to be sn1, sn2, e1, e2 or e1cb. a) b) c)
To calculate the percent yield of 1-bromobutane obtained in your experiment, you need to know the actual yield (the amount of 1-bromobutane you obtained) and the theoretical yield (the maximum amount of 1-bromobutane that could be produced based on the starting materials).
The percent yield is calculated using the formula: (actual yield / theoretical yield) x 100%. Without the specific values for the actual and theoretical yields, I cannot provide the exact percent yield.
Experimental evidence that the product isolated in your synthetic experiment is 1-bromobutane can include various analytical techniques such as nuclear magnetic resonance (NMR) spectroscopy, infrared (IR) spectroscopy, or mass spectrometry (MS). These techniques can be used to analyze the chemical structure of the product and confirm its identity as 1-bromobutane based on characteristic spectral peaks or fragmentation patterns.
The compound that reacted faster in your SN1 experiment can be determined by comparing the reaction rates of 2-bromo-2-methylpropane and 2-chloro-2-methylpropane. The relative rates can be obtained by observing the rate of disappearance of the starting material or the rate of formation of the product. Without specific experimental data, I cannot provide the exact relative rates or identify which compound reacted faster.
The leaving group ability of Br- or Cl- can be assessed by considering their stability after leaving the molecule. Generally, a better leaving group is more stable and will leave more readily. In this case, the answer to question 3 would indicate whether 2-bromo-2-methylpropane or 2-chloro-2-methylpropane reacted faster. If 2-bromo-2-methylpropane reacted faster, it suggests that Br- is a better leaving group than Cl-. These results would be consistent with the relative basicities of the two ions, as Cl- is a weaker base than Br-. However, without the specific experimental data, it is not possible to provide a definitive answer or explanation.
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Which polymer are synthetic
Answer:
Examples of synthetic polymers include nylon, polyethylene, polyester, Teflon, and epoxy.
a dilute gas at a pressure of 2.0 atm and a volume of 4.0 l is taken through the following quasi-static steps: (a) an isobaric expansion to a volume of 10.0 l, (b) an isochoric change to a pressure of 0.50 atm, (c) an isobaric compression to a volume of 4.0 l, and (d) an isochoric change to a pressure of 2.0 atm.
(a) The pressure changes from 2.0 atm to 0.8 atm.
(b) The temperature increases by a factor of 4.
(c) The pressure changes from 0.8 atm to 1.25 atm.
(d) The pressure returns to the initial pressure of 2.0 atm.
To analyze the given quasi-static steps, we can use the ideal gas law, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin.
(a) In an isobaric process, the pressure remains constant. The initial pressure is 2.0 atm, and the gas expands from 4.0 L to 10.0 L. Since the pressure is constant, we can use the equation:
P₁V₁ = P₂V₂
2.0 atm × 4.0 L = P₂ × 10.0 L
P₂ = 0.8 atm
(b) In an isochoric process, the volume remains constant. The volume is 10.0 L, and the pressure changes to 0.50 atm. We can use the ideal gas law to find the final temperature:
P₁V₁/T₁ = P₂V₂/T₂
2.0 atm × 10.0 L / T₁ = 0.50 atm × 10.0 L / T₂
T₂ = 4T₁
The temperature increases by a factor of 4.
(c) In the isobaric compression, the pressure remains constant at 0.50 atm. The gas is compressed back to its initial volume of 4.0 L. Again, we can use the equation:
P₁V₁ = P₂V₂
0.50 atm × 10.0 L = P₂ × 4.0 L
P₂ = 1.25 atm
(d) Finally, in the isochoric process, the volume remains constant at 4.0 L, and the pressure returns to 2.0 atm. We don't need any calculations here since the final pressure matches the initial pressure.
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what are plasmas properties?
Answer:Plasma is highest energy state of matter.It consists of electrons,protons and neutral particles.
Explanation:(1) Plasma has a very high electrical conductivity .
(2) The motion of electrons and ions in plasma produces it's own electric and magnetic field
(3)It is readily influenced by electric and magnetic fields .
(4)It produces it's on electromagnetic radiations.
Compare diamonds and graphite - Structure, bonding, properties, use
Answer:
Carbon atoms each form four strong bonds. The bonds are covalent (atoms share electrons). This gives graphite its characteristic properties such as high melting and boiling points, good electrical conductivity, and softness. Use as pencil 'lead', as a lubricant in oil, furnace linings, electrodes, neutron moderators in nuclear power stations.
Diamond atoms each form three strong covalent bonds in the same layer and one weak bond to an atom in another layer. Diamonds have a high level of hardness, thermal conductivity, and optical dispersion. It is used for jewellery, oil-well drills, abrasives and cutting tools.
Explanation:
Structure of Graphite and Diamond (attached below):
Please help me. Quickly!!!
Answer:
500
Explanation:
What can be found in the box on a periodic table?
In the box on a periodic table we can find its atomic number, symbol, average atomic mass, and (sometimes) name of the element.
By the 20th century, it was clear that atomic numbers, not atomic masses, were involved in the periodic relationship. The periodic law, a more recent formulation of this relationship, states that an element's properties are a periodic function of its atomic number.
The elements are arranged in a modern periodic table in increasing order of their atomic numbers, and atoms with comparable properties are grouped in the same vertical column (Figure below). With its atomic number, symbol, average atomic mass, and (sometimes) name, each box represents an element. The elements are grouped in 18 vertical columns called groups and seven horizontal rows known as periods or series.
Each column's header lists the names of its groups. Roman numerals and capital letters have traditionally been used on labels in the United States. The IUPAC advises using the digits 1 through 18, and these labels are more widely used. Parts of two of the rows, totaling 14 columns, are typically written below the table's main body in order for it to fit on a single page.
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2.5 * 10^4 gallons to mL
Can someone pls help I’m learning dimensional analysis and don’t understand how to do it dead fish method
Hydrogen peroxide breaks down back into water and oxygen when exposed to air and light. When purchased at a pharmacy for home use, hydrogen peroxide is sold in dark bottles labeled as having a concentration of 3% by weight.A chemistry student wants to test the concentration of hydrogen peroxide that has been poured into light and dark vials, and exposed to air for 10, 20 and 30 hours.The concentration was tested by titration with potassium permanganate, and each sample was tested twice.
Since the breakdown of hydrogen peroxide can cause a reduction in concentration and potency over time, it is a good idea to check the concentration of hydrogen peroxide that has been exposed to air and light.
The chemical student employed titration with potassium permanganate to measure the quantity of hydrogen peroxide.
Using this technique, the volume of potassium permanganate solution needed to completely react with the hydrogen peroxide sample is measured after adding a known quantity of a standard potassium permanganate solution to the hydrogen peroxide sample until the reaction is complete.
Hydrogen peroxide and potassium permanganate react in the following way: 5 H2O2 + 2 KMnO4 + 3 H2SO4 5 O2 + 2 MnSO4 + K2SO4 + 8 H2O
The amount of hydrogen peroxide in the sample may be determined from the volume and concentration of the potassium permanganate solution used in the titration because the reaction uses 5 moles of hydrogen peroxide for every 2 moles of potassium permanganate.
The chemical student should carry out the following procedures to examine the hydrogen peroxide samples in dark and light vials that have been exposed to air for 10, 20, and 30 hours:
1. Make a standard potassium permanganate solution with a known concentration.
2. Pour a known volume of each test sample of hydrogen peroxide into a flask.
3. To serve as a catalyst for the reaction, add a tiny quantity of diluted sulfuric acid to the hydrogen peroxide sample.
4. Continue titrating the hydrogen peroxide sample with the potassium permanganate standard solution until the reaction is finished, which is shown by a lingering pink hue of the potassium permanganate solution.
5. To confirm the correctness of the results, repeat the titration using the same sample.
6. Using the volume and concentration of the potassium permanganate solution used in the titration, determine the concentration of hydrogen peroxide in the sample.
The chemical student can find out if the exposure to air and light has changed the concentration of hydrogen peroxide over time by analysing the concentration of hydrogen peroxide in the light and dark vials after 10, 20, and 30 hours.
The findings may be calculated by comparing them to the original concentration of 3% by weight.
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What is the maximum number of electrons that can go into each of the following sub levels
How many moles are in 1.3 x 1012 grams NH3?
Answer:
50.6
Explanation
using the furmla
mole=mass/mole mass
1012/20=50.6
Plutonium-242 (242Pu) undergoes alpha decay to form what daughter isotope and decay particle?
Answer:
Decay. Plutonium-242 primarily decays into uranium-238 via alpha decay, before continuing along the uranium series.
Explanation:
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11. From the 3D plot results, approximate the recrystallization temperature for each %CW. Is there any %CW for which you cannot approximate the recrystallization temperature? If yes, which \% CW and explain why? (10 pts)
There is no recrystallization temperature for the 10% CW.I hope this helps.
From the 3D plot results, the recrystallization temperature for each %CW is approximated as shown in the table below:%CWApprox. recrystallization temperature (°C)30~31535~40050~46570~56590~650100~695There is a %CW for which the recrystallization temperature cannot be approximated. It is the 10% CW. The reason behind this is that there is no recrystallization temperature for that %CW. It is because the recrystallization temperature is the temperature at which the internal stresses are relieved through the process of recrystallization. But for the 10% CW, the material has not been cold worked enough to generate enough internal stresses that need to be relieved. Therefore, there is no recrystallization temperature for the 10% CW.I hope this helps.
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true or false? in apocalyptic literature, the source of suffering for god’s people is their faithfulness.
The given statement " Apocalyptic literature, the source of suffering for god’s people is their faithfulness" is true. Because, it includes texts found in religious or biblical contexts, the suffering experienced by God's people is often attributed to their faithfulness or lack thereof.
These texts typically depict a period of intense tribulation, persecution, or catastrophic events that are believed to occur as part of a divine plan or judgment.
According to the narrative structure of apocalyptic literature, the suffering endured by the faithful is seen as a test of their devotion and commitment to their beliefs. It is believed that their faithfulness will ultimately be rewarded, either through deliverance or entrance into a new divine realm.
This theme can be found in various apocalyptic texts, such as the Book of Revelation in the New Testament of the Bible, where the faithful are depicted as enduring suffering and persecution due to their unwavering allegiance to God.
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The statement “in apocalyptic literature, the source of suffering for God’s people is their faithfulness” is generally true.What is apocalyptic literature?Apocalyptic literature is a kind of literature that is heavily symbolic and depicts catastrophic events.
It was created during times of hardship and political strife, such as during the reign of the Roman Empire, which made it impossible for people to freely practice their religion and made them feel as though the end of the world was near.Suffering for God’s people in apocalyptic literature:In apocalyptic literature, the faithful are expected to suffer. As a result, the source of suffering for God’s people is their faithfulness.
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when an electron is acquired by a neutral atom, the energy change is called
Answer:
when an electron is acquired by a neutron atom, the energy change is called its electron affinity
When an electron is added to a neutral atom to create a negative ion, the energy of the atom changes (in kJ/mole). This is how electron affinity is defined. Alternatively put, the possibility of the neutral atom receiving an electron.
What is electron affinity ?The amount of energy released when an electron binds to a neutral atom or molecule in the gaseous state to produce an anion is known as the electron affinity of an atom or molecule.
Although there is a slight distinction between the two, electron gain enthalpy is occasionally also referred to as electron affinity. The amount of energy released when an electron is added to a single gaseous atom is known as the electron gain enthalpy.
The amount of energy released when an atom receives an additional electron is known as its electron affinity. The gaseous state is when electron affinities are measured. On the periodic table, electron affinities tend to shift from negative to positive as we move from left to right.
Thus, when an electron is acquired by a neutral atom, the energy change is called as electron affinity.
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For the amino acid alanine, the major species in solution at ph 7 is the zwitterionic form, which has a negatively charged carboxylic acid group and a positively charged amino group. There is a less common neutral form in which neither group is charged. The carboxylic acid group of alanine has a pka of 3. The amino group of alanine has a pka of 8. Estimate the ratio of the concentration of the neutral amino acid species to the zwitterionic species at ph 7.
The ratio between the neutral and the zwitterionic form of alanine at pH 7 is 1:100000.
Since the carboxylic group has a pKa of 3, that means that at pH 3 the ratio between its protonated and deprotonated (charged) form is 1:1. The difference between pH 7 and pH 3 is 7 - 3 = 4, which means that (because pH is a negative logarithm), pH 7 is 10000 times more basic than pH 3. This implies that the ratio between the protonated and the deprotonated form of the carboxylic group is 1:10000.
A similar calculation can be applied to the amino group. 8 - 7 = 1, so at pH 7, the ratio between its protonated (charged) and deprotonated form will be 10:1.
We then multiply these two ratios to get a ratio of neutral:zwitterionic = 1:100000.
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How many particles are present in 0.67 moles of radon?
a. 4.0x10^22 particles
b. 9.0x10^24 particles
c. 9.0x10^23 particles
d. 4.0x10^23 particles
PLEASE HELP!!!!!!!!
complete the following table for the reactions that occur when black powder is ignited
The following table for the reactions that occur when black powder is ignited.
What is black powder?
In order to maintain a reaction, black powder needs a fuel (charcoal), an oxidizer (saltpeter or niter), and a stabilizer (sulfur). Without the oxidising agent, the reaction would take a long time, similar to a wood fire. The saltpeter in gunpowder provides the oxygen that carbon in a fire needs to draw from the surrounding atmosphere.
What is reactions?
A chemical reaction occurs when one or more chemicals, also known as reactants, change into one or more new substances, also known as products. Both chemical constituents and compounds are substances.
The completion of the above table when black powder is ignited-
The name of the compound=Potassium nitrate
The formula of the compound=KNO3
The balanced chemical equation-
4K NO3 + 2K 20 + 2N2 + 302
Type of reaction-
This is a decomposition reaction.
Mole ratio of reactants to products-
reactants : products=4 : 7
The name of the compound=Charcoal
The formula of the compound=C
The balanced chemical equation,
C+02 + CO2
Type of reaction-
This is a combustion reaction.
Mole ratio of reactants to products-
reactants : products=2 : 1
The name of the compound=Sulfur
The formula of the compound=S
The balanced chemical equation,
S + 02 → SO2
Type of reaction-
This is also a combustion reaction.
Mole ratio of reactants to products-
reactants : products=2 : 1
The name of the compound=Potassium chlorate
The formula of the compound=KClO3
The balanced chemical equation,
2K CIO3 → 2KCI + 302
Type of reaction-
This is a decomposition reaction.
Mole ratio of reactants to products-
reactants : products=2 : 5
The name of the compound=Potassium perchlorate
The formula of the compound=KClO4
The balanced chemical equation,
KClO4\righteous KCl+2O2
Type of reaction-
This is a decomposition reaction.
Mole ratio of reactants to products-
reactants : products=1 : 3
Therefore, above table for the reactions that occur when black powder is ignited.
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What is the pressure of a tire at 25°C if the pressure is 1.5 m when the temperature is 15°C?
Ideal gas law is valid only for ideal gas not for vanderwaal gas. Therefore, the pressure of a tire at 25°C if the pressure is 1.5 atm when the temperature is 15°C is 1.55 atm.
What is ideal gas equation?Ideal gas equation is the mathematical expression that relates pressure volume and temperature. There is no force of attraction between the particles.
Mathematically the relation between Pressure, temperature and volume can be given as
PV=nRT
Rearranging the equation we get
P₁÷T₁=P₂÷T₂
where,
P = pressure
T =temperature
R = Gas constant = 0.0821 L.atm/K.mol
Substituting all the given values, we get
P₁÷T₁=P₂÷T₂
1.5 ÷288=P₂÷298K
P₂=1.55 atm
Therefore, the pressure of a tire at 25°C if the pressure is 1.5 atm when the temperature is 15°C is 1.55 atm.
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How many elements are in C8H3NaBr12?
Answer:
I don’t get it you have to go more into detail lol then I’ll answer
Explanation:
PLEASE HELP ME!!!!
Answers are below the sentence
Answer:
Mass
Explanation: