80-
60
40
O
20
O
글
1
○ 2
(0, 52).
○-2
_y = -2x + 52
What is the slope of the line perpendicular to the line in the coordinate grid?
(18, 16)
(26, 0)
20- 40-
60- -80

The presence of data entry errors is not necessarily indicated by a right skew, as errors can occur in any type of data distribution.

A graph that has a right skew indicates that there are more data points with small values than data points with large values. This means that the tail of the distribution extends to the right, indicating a relatively small number of high values, also known as high outliers.

However, it is not accurate to say that it cannot have outliers or that it always has high outliers.

Outliers can occur in any type of distribution, and their position and number depend on the specific dataset.

Similarly, the presence of data entry errors is not necessarily indicated by a right skew, as errors can occur in any type of data distribution.

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Answer:

\(6x - 2 = x - 2 \\ 6x - x = 0 \\ 5x = 0 \\ x = 0\)

Answer:

D

Step-by-step explanation:

y = x² - 4x - 5 → (1)

y = x - 9 → (2)

substitute y = x² - 4x - 5 into (2)

x² - 4x - 5 = x - 9 ( subtract x - 9 from both sides )

x² - 5x + 4 = 0 ← in standard form

(x - 1)(x - 4) = 0 ← in factored form

equate each factor to zero and solve for x

x - 1 = 0 ⇒ x = 1

x - 4 = 0 ⇒ x = 4

substitute these values into (2) for corresponding values of y

x = 1 : y = 1 - 9 = - 8 ⇒ (1, - 8 )

x = 4 : y = 4 - 9 = - 5 ⇒ (4, - 5 )

Answer:

4h-1

Step-by-step explanation:

subtracted it with a scientific calculator and that was the answer

To check your work when dividing with fractions, convert the division to multiplication by using inverse operations. Multiply the dividend by the reciprocal of the divisor to find the product. Simplify and compare the quotient. If correct, the product and quotient will match.

When dividing with fractions, you can use your knowledge of whole number division to check your work. Here's how you can do it:

Identify the dividend, which is the number being divided, and the divisor, which is the number you are dividing by.

Convert the fractions into improper fractions if needed, by finding the product of the whole number and the denominator, and then adding the numerator.

Use inverse operations to change the division into multiplication. Instead of dividing by a fraction, multiply by its reciprocal (the divisor becomes the reciprocal or inverse of the fraction). This is similar to how in whole number division, you multiply by the reciprocal of the divisor.

Multiply the dividend by the reciprocal of the divisor (or the inverse fraction). This will give you the product.

Simplify the product if necessary and express it as a fraction in its simplest form.

Compare the quotient you obtained with your original division. They should be equal. If they are not, you may have made an error in your division calculation.

By using these steps and your understanding of whole number division, you can check your work when dividing with fractions. It allows you to verify that the quotient obtained through fraction division matches the result you would obtain using whole number division principles.

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Answer:

Answer is in fraction.--> 1/289.

Step-by-step explanation:

\(17^{-7} =17^{-7+5}=17^{-2} =\frac{1}{17^{2} } = \frac{1}{289}\)

Answer:

B

Step-by-step explanation:

Hope it helps and if you need explanation let it in the comments

Answer:

B

Step-by-step explanation:

The predicted number of adults in Oak City whose main source of news is newspapers or the radio is 85

To predict the number of adults in Oak City whose main source of news is newspapers or the radio, we need to add the number of adults who answered "Newspapers" to the number of adults who answered "Radio".

According to the sample data

Number of adults who answered "Newspapers": 64

Number of adults who answered "Radio": 21

Therefore, the predicted number of adults in Oak City whose main source of news is newspapers or the radio we have to use the addition

64 + 21 = 85

Rounding this answer to the nearest whole number, we get

85 ≈ 85

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The given question is incomplete, the complete question is:

There are 44,000 adults living in Oak City. In examining attitudes toward the news, a research group asked a random sample of Oak City adults "What is your main source of news?" The results are shown below. Main Source of News Newspapers Number of Adults 64 Internet 80 Television 126 Radio 21 Other 40 Based on the sample, predict the number of adults in Oak City whose main source of news is newspapers or the radio. Round your answer to the nearest whole number.

Answer: Leftmost vertex

Step-by-step explanation:

Answer:

Step-by-step explanation:

(1). Elote:

$7200.00 × 0.2 = $1440.00

$1440.00 ÷ 72 = 20 ( Elote, Cantidad vendida )

(2). Chocolate y fresas:

$7200.00 × 0.15 = $1080.00

$1080.00 ÷ 8 = $135.00 ( Precio )

(3). Frutas de temporada:

$7200.00 × 0.25 = $1800.00

$1800.00 ÷ $120 = 15 ( Cantidad vendida )

(4). Tres leches:

$7200.00 × 0.1 = $720.00

$720.00 ÷ 5 = $144.00 ( Precio )

(5). Galletas ( paquete ):

$7200.00 × 0.15 = $1080.00

$1080.00 ÷ $30.00 = 36 ( Cantidad vendida )

Answer:

Option D

Step-by-step explanation:

Option A

x² - 3x² + 2x² = 0

Therefore, the given polynomial has no roots.

Option B

x² + 2x + 8

By quadratic formula,

x = \(\frac{-2\pm \sqrt{4-32} }{2}\)

  = \(\frac{-2\pm \sqrt{-28} }{2}\)

Therefore, roots are imaginary and for a polynomial with degree 1 or more than 1, both the roots can't be imaginary.

So the polynomial can't have exactly two roots.

Option C

99x³ - 33x + 1

Since the polynomial is of degree 3, so it will have three roots.

Therefore, the polynomial will not have exactly 2 roots.

Option D

√2x - 3x² + 7√2

By quadratic formula,

x = \(\frac{-\sqrt{2}\pm\sqrt{(\sqrt{2})^2-4(-3)(7\sqrt{2} )}}{2(-3)}\)

x = \(\frac{-\sqrt{2}\pm\sqrt{2+84\sqrt{2} )}}{(-6)}\)

There are exactly two real roots.

Therefore Option D is the answer.

Option E

4x + 11x - 111

Since this polynomial is of a degree 1.

There will be only one root.

Answer:

the correct answer is x=44

x +6 = 50

x = 50-6

x = 44

Answer:

X= 50-6

=44

ALso mark me brainliest

Answer:

14.52% are unicyclists

Step-by-step explanation:

First, we can use proportions to find the number of unicyclists at the convention. Since we know that the ratio of unicyclists to aerial artists is 9:11, and there are 88 aerial artists, we can set up the following equation:

\(\frac{9}{11}=\frac{x}{88}\)

If we cross multiply, we get that 11x = (88)(9). After we divide through by 11 to isolate x, we get that x = (8)(9) = 72

Second, we have to figure out the number of mimes at the convention to figure out the total number of people there. We know that the ratio of unicyclists to mimes is 3:14, and the number of unicyclists is 72. So, we can set up the following proportion:

\(\frac{3}{14}=\frac{72}{y}\)

If we cross multiply, we get that 3y = 1008, or y = 336 mimes

The total number of people at the convention is 336 mimes + 72 unicyclists + 88 unicyclists = 496. Now we have to figure out what percent of 496 is 72 (the number of unicyclists). If we let z = the percentage, we can simply set up an equation that says that 72 is z% of 496:

\(72=0.01z*496\\0.01z=0.14516\\z=14.52\)

This means that approximately 14.52% of the performers are unicyclists.

Answer:

14.52%

Step-by-step explanation:

U/A = 9/11       and   A = 88      multiply by  8/8   ( to get A=88 as given)

9/11 * 8/8 = 72/88  = U / A       so U = 72

Then U/M = 3/14    multiply by  24/24   ( to get U = 72 as found above)

  then  U/M=    72 / 336     M = 336

U / ( A + U + M )  x  100% = 14.52 %

Answer:

x² - 1

Step-by-step explanation:

When x - 1 = 3 and x + 1 = 5 we know that x = 4 so (x - 1)(x + 1) = 4² - 1 when x = 4, 5² - 1 when x = 5 and so on. If you look carefully you will notice a pattern, the product is always x² - 1 so the answer to the blank is x² - 1.

Answer:

∠ H, ∠G, ∠F

Step-by-step explanation:

6x + 7 + 8x - 5 + 10x - 11 = 87

24x = 96

x = 96 / 24 = 4

FG = 6(4) + 7 = 31 units

GH = 8(4) - 5 = 27 units

FH = 10(4) - 11 = 29 units

FG is the longest side ⇒ ∠H is the largest angle.

GH is the shortest side ⇒ ∠F is the smallest angle

∠ H, ∠G, ∠F

Based on the relationship of angles and sides of a triangle, the angles from the largest to the smallest are: ∠H,  ∠G, ∠F

Recall:

Given ΔFGH with the following sides:

FG = 6x+7 (opposite to ∠H)

GH = 8x - 5 (opposite to ∠F)

FH = 10x - 11 (opposite to ∠G)

Perimeter of ΔFGH = 87

Find the value of x using the perimeter formula to create an equation.

Thus:

FG + GH + FH = 87

6x + 7 + 8x - 5 + 10x - 11 = 87

24x - 9 = 87

24x = 87 + 9

24x = 96

x = 4

Plug in the value of x to find the length of each side:

FG = 6x+7 = 6(4) + 7 = 31 (opposite to ∠H)

GH = 8x - 5 = 8(4) - 5 = 27 (opposite to ∠F)

FH = 10x - 11 = 10(4) - 11 = 29 (opposite to ∠G)

Therefore, based on the relationship of angles and sides, the angles from the largest to the smallest are: ∠H,  ∠G, ∠F

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Answer:

The total distance that the bicyclist traveled was 30 + 17 = <<30+17=47>>47 km.

The speed at which the bicyclist traveled for the remaining 17 km was v + 2 = 18 + 2 = <<18+2=20>>20 km/hr.

The time that the bicyclist spent on the trip can be calculated by dividing the total distance traveled by the speed at which he traveled: t = 47 km / (20 km/hr) = <<47/(20)=2.35>>2.35 hours. Answer: {2.35}.

Step-by-step explanation:

Answer:

G

Step-by-step explanation:

Answer:

i don't understand the question sorry

Answer: anything honestly

Step-by-step explanation:I don't think it costs anything you only have to pay if you want specific accessories

Answer:

It is better on an iPhone and the game is free. Also, it is really personal preference!

Step-by-step explanation:

Answer:

456748

Step-by-step explanation:

you 463uy2iuswhk then 13456

Answer:

30 students are 6th graders

Step-by-step explanation:

3/7×70= 30

Answer:18.5

Step-by-step explanation:

Okay if it's a square that means four sides.so you would take 74 divide it by four and get the final answer of 18.5

(a) A nonzero vector orthogonal to the plane through the points P, Q, and R is (9, -17, 35). (b) The area of triangle PQR is \(\sqrt\)(811) / 2.

(a) To determine a nonzero vector orthogonal to the plane through the points P, Q, and R, we can first find two vectors in the plane and then take their cross product. Taking vectors PQ and PR, we have:

PQ = Q - P = (5, 1, -2) - (-4, 0, 0) = (9, 1, -2)

PR = R - P = (6, 4, 1) - (-4, 0, 0) = (10, 4, 1)

Taking the cross product of PQ and PR, we have:

n = PQ x PR = (9, 1, -2) x (10, 4, 1)

Evaluating the cross product gives n = (9, -17, 35). Therefore, (9, -17, 35) is a nonzero vector orthogonal to the plane through points P, Q, and R.

(b) To determine the area of triangle PQR, we can use the magnitude of the cross product of vectors PQ and PR divided by 2. The magnitude of the cross product is given by:

|n| = \(\sqrt\)((9)^2 + (-17)^2 + (35)^2)

Evaluating the magnitude gives |n| = \(\sqrt\)(811).

The area of triangle PQR is then:

Area = |n| / 2 = \(\sqrt\)(811) / 2.

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Without a specific function and point, we cannot find f and a.

The limit is used to find the derivative of a function at a specific point. The standard expression for the limit is:
lim h→0 [(f(a+h)-f(a))/h]

In order to find f and a, we need to know the function and the point at which we are taking the derivative. Without this information, we cannot find f and a.

If we had a specific function and point, we could plug them into the limit expression and solve for the derivative. For example, if f(x) = x^2 and a = 2, we would plug these values into the limit expression:

lim h→0 [(f(2+h)-f(2))/h] = lim h→0 [((2+h)^2 - (2^2))/h] = lim h→0 [(4+4h+h^2-4)/h] = lim h→0 [(4h+h^2)/h] = lim h→0 [4+h] = 4

So the derivative of f(x) = x^2 at a = 2 is 4.

Without a specific function and point, we cannot find f and a.

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Answer:

If I understood what you mean properly... 0

Step-by-step explanation:

Answer:

Step-by-step explanation:

1. Find the mean

94 + 69+74+96 = 333

Divide 333 by 4 = 83.25

Subtract 83.35 from 88

Answer : 4.75

Now follow the next steps

The value of m for the given equation is 18. The solution has been obtained by solving the linear equation.

What is a linear equation?

A linear equation is the one with the highest degree of one. This demonstrates that there are no variables in a linear equation with an exponent bigger than one. On the graph, such an equation yields a straight line.

We are given an equation as 2 = m/2 - 7

On solving the equation for m, we get

⇒2 = m/2 - 7

⇒2 = (m - 14)/2

⇒2*2 = (m - 14)

⇒4 = m - 14

⇒m = 18

Hence, the value of m for the given equation is 18.

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Two pipes flowing together fill a water tank in 10 hours. The time needed for the second pipe to fill the tank is approximately 50.25 hours.

Let x be the time needed for the second pipe to fill the tank.
The first pipe can fill the same basin in x + 8 hours.
When the two pipes flow together, they fill 1/10 of the basin in 1 hour.
Thus, the first pipe can fill 1/(x+8) of the basin in 1 hour, and the second pipe can fill 1/x of the basin in 1 hour.
So, the equation is:
1/(x+8) + 1/x = 1/10
Multiplying both sides by 10x(x+8), we get:
10x + 10(x+8) = x(x+8)
Expanding and simplifying, we get:
x^2 - 52x - 80 = 0
Using the quadratic formula, we get:
x = (52 ± sqrt(52^2 + 4*80))/2
x ≈ 50.25 or x ≈ 1.51
Since x represents the time needed for the second pipe to fill the tank, we discard the smaller solution, x ≈ 1.51, and conclude that the time needed for the second pipe to fill the tank is approximately 50.25 hours.

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In graph theory, a clique is a subset of vertices where every pair of distinct vertices is connected by an edge, and an independent set is a set of vertices where no two vertices are connected by an edge. We have shown that G has two distinct independent sets of size 2.

Given that G is a graph with n ≥ 3 vertices, having a clique of size n-2 and no cliques of size n-1, we need to prove that G has two distinct independent sets of size 2. Consider the clique of size n-2 in G. Let's call this clique C. Since the graph has no cliques of size n-1, the remaining two vertices (let's call them u and v) cannot both be connected to every vertex in C. If they were, we would have a clique of size n-1, which contradicts the given condition. Now, let's analyze the connection between u and v to the vertices in C. Without loss of generality, assume that u is connected to at least one vertex in C, and let's call this vertex w. Since v cannot form a clique of size n-1, it must not be connected to w. Therefore, {v, w} forms an independent set of size 2. Similarly, if v is connected to at least one vertex in C (let's call this vertex x), then u must not be connected to x. This implies that {u, x} forms another independent set of size 2, distinct from the previous one.

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