8) If the volume of the liquid in graduated cylinder B is 90 mL, then whatis the volume of the rock?AYour answer8060B100180

(a) the shell's horizontal range = 285839 m.

(b) the amount of time the shell is in motion is: 273.11 sec.

The length of the horizontal axis is a projectile's horizontal range. In addition, it would move before returning to the original vertical position.

Horizontal range is equal to Initial Speed in the horizontal direction, multiplied by the time the shell is in motion.  Therefore, both questions can be solved at the same time.

Step 1.  Find Velocity in the Horizontal direction by:  

Vx = (1.70 x 10³) × cos(52°)

Vx = 1046.6 m/sec

Step 2.  Find Velocity in the Vertical direction by:

Vy = (1.70 x 10³) × sin (52°)

Vy = 1339.6 m/sec

Step 3. Find the amount of time the shell is in motion by:  

t= (2 × Vy)/gravity

t = (2 × 1339.6) / 9.81       [ Gravity = 9.81m/s²]

t = 273.11 sec

Step 4. Find the shell's horizontal range:  

Distance = Vx × t

or, distance = (1046.6 × 273.11)

or, distance = 285839 m

Thus, (a) the shell's horizontal range = 285839 m.

(b) the amount of time the shell is in motion is: 273.11 sec.

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Voltage depends on the amount of resistance, current according to the Ohm's law, and, by definition, is the measurement of electrical pressure.

According to the Ohm's Law,  the current through a conductor between two points is directly proportional to the voltage across the two points.

Mathematically,

V ∝ I

V = IR

where, R is the resistance of the conductor and I is the current flowing in the conductor. So, the voltage depends on the amount of resistance and current.

Also, Voltage is the pressure from an electrical circuit's power source that pushes charged electrons (current) through a conducting loop, enabling them to do work such as illuminating a light.

Hence All of the above option in the given question are true.

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To solve this problem, we need to determine the frictional force acting on the block with different magnitudes of the applied force.

First, we need to find the normal force on the block, which is equal to the weight of the block. The weight of the block is given by:

W = mg = 2.5 kg x 9.8 m/s^2 = 24.5 N

Next, we need to find the force of the applied vertical force, which is given in the problem as "is". We can use trigonometry to find the vertical component of the force:

Fv = is sinθ

where θ is the angle between the force and the horizontal surface. Since the problem does not give us the value of θ, we will assume it to be 0°, which means the force is purely horizontal.

(a) If the magnitude of the applied force is 8.0 N, then the frictional force can be calculated as:

Ff = μsFn = μs(mg - Fv) = 0.40(24.5 - 0) = 9.8 N

(b) If the magnitude of the applied force is 10 N, then the frictional force can be calculated as:

Ff = μsFn = μs(mg - Fv) = 0.40(24.5 - 10) = 5.8 N

(c) If the magnitude of the applied force is 12 N, then the frictional force can be calculated as:

Ff = μkFn = μk(mg - Fv) = 0.25(24.5 - 12) = 3.1 N

Therefore, the magnitude of the frictional force acting on the block is 9.8 N, 5.8 N, and 3.1 N, for applied forces of 8.0 N, 10 N, and 12 N, respectively.

(a) When the horizontal force is 8 N the frictional force is 11.8 N.

(b) when the applied force is 10 N; the frictional force is 13.8 N.

(c) when the applied force is 12 N; the frictional force is 15.8 N.

(a) The magnitude of the frictional force on the block when the horizontal force is 8 N is calculated as;

F - Ff = ma

where;

F - μmg = ma

6 - 0.4 x 2.5 x 9.8 = 2.5 a

2.5 a = -3.8

a = -3.8/2.5

a = -1.52 m/s²

when the applied force is 8 N;

8 N - Ff = -1.52 m/s² x 2.5 kg

Ff = 11.8 N

(b) when the applied force is 10 N;

10 N - Ff = -1.52 m/s² x 2.5 kg

Ff = 13.8 N

(c) when the applied force is 12 N;

12 N - Ff = -1.52 m/s² x 2.5 kg

Ff = 15.8 N

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Answer:

kinetic energy

Explanation:

It is kinetic energy because it is an energy in motion. In order words it is an energy which the body or object moves.

The minimum horizontal velocity required for an object to orbit the earth just above the surface is 5.04 x 10¹⁰ m/s.

The orbital speed of Earth or a natural satellite is the speed at which it orbits around the center of the system.

The minimum horizontal velocity required for an object to orbit the earth just above the surface is calculated as follows;

V(min) = √GMR

where;

Substitute the given parameters and solve for the minimum orbital speed of the earth.

V(min) = √(6.67 x 10⁻¹¹ x 5.97 x 10²⁴ x 6.38 x 10⁶)

V(min) = 5.04 x 10¹⁰ m/s

Thus, the minimum horizontal velocity required for an object to orbit the earth just above the surface is 5.04 x 10¹⁰ m/s.

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Answer:

Answer number 3

Explanation:

REALLY HOPE im right:)

The mass of the girl is 30 kg  in order for the seesaw to be in equilibrium.

A particular kind of lever is a seesaw, which has a long beam coupled to a pivot known as the fulcrum.

As soon as you sit on one side of the beam and apply weight on one end, the beam falls to the ground. This is because the weight of your body is being pulled down by the force of gravity, along with the beam.

Let the  mass of the girl = m kg

In equilibrium;

40 kg × 300 cm = m × 400 cm

⇒ m = 30 kg.

Hence,  the mass of the girl is 30 kg.

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The minimum quantity of benzene, C₆H₆ needed for the reaction is 106.67 g

From the question given, the following data were obtained

Percentage yield = (Actual / Theoretical) × 100

65% = 100 / Theoretical

0.65 = Actual / Theoretical

Cross multiply

0.65 × Theoretical = 100

Divide both sides by 0.65

Theoretical = 100 / 0.65

Theoretical yield = 153.85 g

Balanced equation

C₆H₆ + Cl₂ → C₆H₅Cl + HCl

Molar mass of C₆H₆ = 78 g/mol

Mass of C₆H₆ from the balanced equation = 1 × 78 = 78 g

Molar mass of C₆H₅Cl = 112.5 g

Mass of C₆H₅Cl from the balanced equation = 1 × 112.5 = 112.5 g

SUMMARY

From the balanced equation above,

112.5 g of C₆H₅Cl were obtained from 78 g of C₆H₆

Therefore,

153.85 g of C₆H₅Cl will be produced from = (153.85 × 78) / 112.5 = 106.67 g of C₆H₆

Thus, the minimum amount of benzene, C₆H₆ needed for the reaction is 106.67 g

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The following would expect to be a strong electrolyte in solution (b) KCI is correct option.

When dissolved in water, a strong electrolyte produces a large concentration of ions in solution by totally dissociating into ions.  The following compounds are typically strong electrolytes in solution according to this definition:

These substances readily dissociate into ions in water and exhibit high electrical conductivity, making them strong electrolytes in solution.

Therefore, the correct option is (b).

The complete question is,

Which of the following would be a strong electrolyte in solution?

a) Al(OH)₃ b) KCI c) Pbl₂

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One notable athlete who has been associated with the use of performance-enhancing drugs (PEDs) is the American professional cyclist Lance Armstrong.

Armstrong gained worldwide recognition for his unprecedented seven consecutive victories in the Tour de France from 1999 to 2005. However, his remarkable achievements were tarnished when it was revealed that he had engaged in systematic doping throughout his career.

In 2012, after years of denial, Armstrong finally admitted to using banned substances, including erythropoietin (EPO), testosterone, corticosteroids, and blood transfusions, to enhance his performance. These substances boosted his endurance and oxygen-carrying capacity, providing him with an unfair advantage over his competitors. Armstrong's confession came after substantial evidence, including testimonies from teammates and extensive investigations, exposed his involvement in one of the most elaborate and sophisticated doping schemes in sports history.

Following his admission, Armstrong was stripped of his Tour de France titles and received a lifetime ban from professional cycling. The revelations surrounding his drug use had a profound impact on the sport, shaking its credibility and raising concerns about the prevalence of doping in cycling.

Armstrong's story serves as a cautionary tale, highlighting the ethical and moral dilemmas associated with doping in sports. His case underscores the importance of maintaining the integrity of athletic competition, the significance of stringent anti-doping measures, and the need for education and awareness regarding the risks and consequences of performance-enhancing substances.

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Answer:

8s

Explanation:

period of pendulum = 2π*√(l/g)

l = length of pendulum

period for 1st pendulum = 4 sec

thats 2π*√(l/g) = 4

for 2nd pendulum

length = 4 l

substitute 4l in formula

2π*√4l/g = 2*4= 8s

Given the data from the question, the period of the pendulum 2 is 8 s

The period of pendulum 2 can be obtained as illustrated below:

T²₁ / L₁ = T²₂ / L₂

4² / L = T²₂ / 4L

Cancel out L

4² = T²₂ / 4

Cross multiply

T²₂ = 4² × 4

T²₂ = 64

Take the square root of both sides

T₂ = √64

T₂ = 8 s

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Answer:

3.4 rad/sec^2

Explanation:

rotational inertia = 2.5 kg-m^2   radius = 1.1 m   force = 7.7 N

t = rotational inertia * angular acceleration    equation 1

also t = force * radius

therefore to calculate angular acceleration equation 1 becomes

f * r = inertia * angular acceleration   hence

angular acceleration = f * r / inertia = \(\frac{7.7 * 1.1 }{2.5}\)   8.47 / 2.5 = 3.388 ≈ 3.4 rad/sec^2

With 6.6 m/s velocity, the pony moving at the end of 3.3 seconds in m/s.

v0=0

v=?

a=2 m/s²

t=3.3 sc

v=v0+at

v=0+2×3.3

v=6.6 m/s

"The rate at which an item changes its location" is described by a vector number called velocity. Imagine someone walking swiftly, one step forward, one step back, and starting each step from the same location. Velocity is a vector quantity. Therefore, velocity is cognizant of direction. The direction must be taken into account when determining an object's velocity. A velocity of 55 miles per hour is not adequate information. It is necessary to account for the direction in order to accurately describe the object's velocity. Simply put, the direction of the velocity vector represents the motion of the object.

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180kg is mass of metal .

The definition of specific heat capacity

The amount of heat per unit mass needed to raise the temperature by one degree Celsius is known as the heat capacity or specific heat. The ability to distinguish between two polymeric composites using specific heat can be useful in calculating the processing temperatures and volume of heat required.

The heat capacity per unit mass of a material is known as the specific heat capacity (or simply the specific heat). The results of experiments indicate that three variables affect the amount of heat that is transferred: (1) the temperature change, (2) the mass of the system, and (3) the substance and phase of the material.

Eo is 9.9*10^6 J

ΔT is 55K

c is 1*10^3 J/kg.K

Eo = Mo. c. ΔT

Mo = Eo/ c. ΔT

Mo = 9.9*10^6/ 5 5*1*10^3

Mo = 180kg

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Answer:

search omni calculator and these problems can be solved easily:) hope this helps! 62.43

Answer:

1 g/cm3

Explanation:

just had it and this was the answer

The final velocity of the red ball is 18 m/s.

The term momentum has to do with the product of the mass and the velocity of an object We know that the momentum is always conserved in accordance with the Newton third law. Also it is clear that the momentum before collision is equal to the total momentum after collision and we are going to apply this principle here.

Then;

Mass of the blue ball =  6 kg

Mass of the red ball =  1 kg

Initial velocity of the blue ball =  4 m/s

Initial velocity of the red ball = 0 m/s

Final velocity of the red ball = ??

Final velocity of the blue ball =  1 m/s

We now have;

(6 * 4) + (1 * 0) = (1 * v) + (6 * 1)

24 = v + 6

v = 24 - 6

v = 18 m/s

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Answer:

jrirnr tn

Explanation:

and then we was just wondering what we should be talking to about to see how you are

The force that acts upon a projectile launched into the air is gravity.

Gravity is a fundamental force of nature that causes all physical objects to attract each other. It is the force that pulls objects towards each other, and it is the reason why objects with mass are attracted towards the center of the Earth.

When an object is launched into the air, it is subject to the force of gravity, which pulls the object down towards the Earth. As the object moves through the air, the force of gravity causes it to follow a curved path, known as a trajectory, until it eventually hits the ground. While other forces such as air resistance may also act upon the projectile, gravity is the primary force that determines the path of the projectile.

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The magnitude of the tension in the string marked A is 39.5 N.

The tension in A is determined thus:

The angle at A, θ = tan⁻¹(3/8) = 20.56

When extrapolated below negative x, the angle at B, α = tan⁻¹(5/4) = 51.34

When extrapolated below negative x, the angle at C, β = tan⁻¹(1/6) = 9.46

Taking the horizontal components of tension;

56.3cos(9.46) = A * cos(20.56) + B * cos(51.34)

0.6247B= 55.53 - 0.936A

B = (55.53 - 0.936A)/0.6247 ----(1)

Taking the vertical components of tension;

56.3 * sin(9.46) + A * sin(20.6) = B * sin(51.3)

9.25 + 0.35A = 0.78B  ---- (2)

substitute the value (1)  in (2)

9.25 + 0.35A = 0.78{(55.53 - 0.936A)/0.6247}

(9.25 + 0.35A) * 0.6247 = 43.31 - 0.73A

0.22A + 0.73A = 43.31 - 5.78

0.93A = 37.53

A = 39.5 N

In conclusion, the tension in A is determined by solving for the vertical and horizontal components of tension.

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Answer: A

Explanation:i took this one

Answer:

the potential energy is zero, and the kinetic energy must be maximum

    F = 0

Explanation:

In this exercise you are asked to complete the sentences of a simple harmonic movement of a mass-spring system.

In this system mechanical energy is conserved

at the most extreme point the carousel potential energy is

          K_e = ½ k x²

the kinetic energy is zero for that stopped.

At the equilibrium point

the spring elongation is x = 0 so the potential energy is zero

and the kinetic energy must be maximum since total energy of the system is conserved

the spring force is

             F =- k x

as in the equilibrium position x = 0 this implies that the force is also zero

             F = 0

In this exercise we have to use the knowledge of force to calculate the energy of a spring, in this way we find that:

The potential energy in the spring is at its \(K_e = 1/2 k x^2\). The kinetic energy of the mass is at its zero . The magnitude of net force acting on the mass is at its Zero.

In this system mechanical energy is conserved,  at the most extreme point the carousel potential energy is:

       \(K_e = 1/2 k x^2\)

The kinetic energy is zero for that stopped or when at the equilibrium point, so:

the spring force is:

          \(F =- k x\\F=0\)

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A 20-minute cycle ergometer exercise at 60% VO2max has been demonstrated to dramatically improve impact for the majority of persons.

the property of being strongly felt or having a powerful impact: The explosion was so loud that it could be heard from five kilometres distant. Measures of luminosity. [C or U] the strength of being something that may be measured, such as sunlight, sound, etc.

A measure that is produced from a randomised measure is known as an intensity measure in probability theory. Since the randomised measure of a set's expected value is the intensity measure, which is a non-random measure, it equates to the average volume that the random measure assigns.

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Answer:

Aerobics I think.

Explanation:

below the Antarctic Circle.

Answer:

calculate 1.6*7.8*3.1

Explanation:

Answer:

The vapor pressure of water is greater at 50°C than it is at 10°C.

Explanation:

At the point indicated by the dot, the electric field vector would be at an angle of 45 degrees measured clockwise from the positive x-axis, since the x and y components of the electric field are equal at that point.

Assuming that the two charges are of equal magnitude and opposite sign and that the distance between them is d, the electric field at the point indicated by the dot can be found using Coulomb's law:

\(E = kq/r^2\)

where k is Coulomb's constant (\(8.99 *10^9 N m^2/C^2\)), q is the magnitude of the charge, and r is the distance between the charges.

Since the charges are of equal magnitude, the net charge at the point indicated by the dot is zero, so we only need to consider the electric field due to one of the charges. Let's assume that we want to find the electric field due to the positive charge.

The distance between the positive charge and the point indicated by the dot is r = d/2. Therefore, the electric field at that point is:

\(E = kq/(d/2)^2 = 4kq/d^2\)

The direction of the electric field is radial, pointing away from the positive charge and toward the negative charge. At the point indicated by the dot, the electric field vector would be at an angle of 45 degrees measured clockwise from the positive x-axis, since the x and y components of the electric field are equal at that point.

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Nernst potential for K+ ions bathed in DMEM at 37°C is  55 mV. The correct option is A.

The Nernst potential for K+ ions bathed in DMEM at 37°C is a measure of the equilibrium potential for K+ ions across a cell membrane in a solution of DMEM. It is calculated using the Nernst equation, which takes into account the concentration gradient of K+ ions across the membrane, as well as the valence of K+ ions and the temperature of the solution.

The Nernst potential for an ion at a given temperature is calculated using the Nernst equation:

E = (RT/zF) * ln([ion]out/[ion]in)

Where:

E is the Nernst potential (in mV)

R is the gas constant (8.314 J/K/mol)

T is the temperature (in Kelvin)

z is the valence of the ion

F is the Faraday constant (96,485 C/mol)

[ion]out is the concentration of the ion outside the cell (in mM)

[ion]in is the concentration of the ion inside the cell (in mM)

ln is the natural logarithm function

Using the values from the table given in the question, we can calculate the Nernst potential for K+ ions bathed in DMEM at 37°C:

Plugging in the values for K in DMEM:

E = (RT/zF) * ln([K+]out/[K+]in)

E = (8.314 * 310.15)/(1 * 96485) * ln(5.3/140)
E≈ 0.055 V

E ≈ 55 mV

Therefore, The correct option is A.

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a ) The energy absorbed by the eardrum per second = 5 * \(10^{-12}\) W

b ) At this rate, it would take the eardrum 6341.96 years to receive a total energy of 1.0 J

P = I A

P = Power

I = Intensity

A = Surface area

β = 10 log I / Io

log I / Io = β / 10

I / Io = 10 ^ ( β / 10 )

I = Io * 10 ^ ( β / 10 )

A = 5 * \(10^{-5}\) m²

Io = 1 * \(10^{-12}\) W / m²

β = 50 dB

I = 1 * \(10^{-12}\) * 10 ^ ( 50 / 10 )

I = \(10^{-7}\) W / m²

P = 5 * \(10^{-5}\) * \(10^{-7}\)

P = 5 * \(10^{-12}\) W

P = W / t

W = Work done

t = Time

W = 1 J

t = W / P

t = 1 / 5 * \(10^{-12}\)

t = 0.2 * \(10^{12}\) s

t = 6341.96 years

Therefore,

a ) The energy absorbed by the eardrum per second = 5 * \(10^{-12}\) W

b ) At this rate, it would take the eardrum 6341.96 years to receive a total energy of 1.0 J

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